3. When a magnetic sector instrument was operated with an accelerating voltage of 4.50*103 V, a field of 0.251 T was required to focus the CH4 on the detector. a) What range of field strengths would be required to scan the mass range between 12.5 and 2.50*102 , for singly charged ion, if the accelerating voltage is held constant
Answer:
The answer is "\(4,500 - 225 \ V\)".
Explanation:
Using formula for calculating the Voltage:
\(M_1=12.5\\\\M_2=250\\\\V_1=4,500 \\\\\bold{\text{Formula: }}\\\\\to \bold{\frac{m_1}{m_2}=\frac{V_2}{V_1}}\\\\\to \frac{12.5}{250}=\frac{V_2}{4,500}\\\\\to 0.05=\frac{v_2}{4,500}\\\\\to 0.05\times 4,500= V_2\\\\\to V_2=225\\\\\)
Hence the range of accelerating in voltage is \(4,500 - 225 \ V\)
a car with a mass of 2000kg is traveling at a velocity of 50 m/s. the engine supplies a force of 1000N forward.the force of friction is 1000 N backwards. What is the velocity after 5 seconds
Answer:
no
Explanation:
ok
1. A train is moving north at 5 m/s on a straight track. The engine is causing it to accelerate northward at 2 m/s^2.
How far will it go before it is moving at 20 m/s?
A) 83
B) 43
C) 39
D) 94
E) 20
Answer:
(D) x = 93.8 m
Explanation:
v^2 = v0^2 + 2ax
(20 m/s)^2 = (5 m/s)^2 + 2(2 m/s^2)x
Solving for x,
x = 93.8 m
Mrs Turner has a scale drawing of her apartment.IN the scale drawing the lenght of her apartment is 6.25 inches and the width is 2.75 onches. If Mrs. Turner used the scale factor 1 inc/18ft, what would the area of the apartment be?
The area of Mrs. Turner's apartment is approximately 0.05304 square feet.
To find the area of Mrs. Turner's apartment, we need to convert the measurements from the scale drawing to the actual measurements in feet, using the given scale factor of 1 inch/18 feet.
Length of apartment in feet = 6.25 inches × (1 foot/18 inches) = 0.34722 feet
Width of apartment in feet = 2.75 inches × (1 foot/18 inches) = 0.15278 feet
Now, we can calculate the area of the apartment in square feet by multiplying the length and width:
Area of apartment in square feet = Length × Width = 0.34722 feet × 0.15278 feet = 0.05304 square feet
Therefore, the area of Mrs. Turner's apartment is approximately 0.05304 square feet.
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How much work is done on a 6.4N box of books that you move horizontally across a 6.1 meter room?
Answer:
39.04 J
Explanation:
Definition of work
\(W=fd\)
\(W=\) Work
\(f=\) force
\(d=\) displacement
In this case,
\(f=6.4\)
\(d=6.1\)
\(W=6.4*6.1\)
\(W=39.04\)
A 2.65 g bullet moves with a speed of 180 m/s perpendicular to the Earth's magnetic field of 5.00×10^−5 T. If the bullet possesses a net charge of 1.39×10^−8 C, by what distance will it be deflected from its path due to the Earth's magnetic field after it has traveled 1.25km?
d =
m
The distance deflected from its path due to the Earth's magnetic field after the 2.65 g bullet with a speed of 180 m/s perpendicular to the Earth's magnetic field has traveled 1.25km is 11.38 * \(10^{-10}\) m
F = q v B sin θ
F = m a
F = Magnetic force
q = Charge
v = Velocity
B = Magnetic field
θ = Angle between v and B
m = Mass
a = Acceleration
m = 2.65 g = 2.65 * \(10^{-3}\) kg
v = 180 m / s
B = 5 * \(10^{-5}\) T
q = 1.39 * \(10^{-8}\) C
d = 1.25 km
θ = 90°
F = q v B
s = ut + 1 / 2 at²
t = d / v
s = Vertical distance
d = Horizontal Distance
u = Initial velocity
t = Time
u = 0
a = F / m
s = 1 / 2 at²
s = 1 / 2 * ( F / m ) * ( d / v )²
s = 1 / 2 * ( q v B d² / m v² )
s = 1 / 2 * ( 1.39 * \(10^{-8}\) * 180 * 5 * \(10^{-5}\) * 1.25² / 2.65 * \(10^{-3}\) * 180 * 180 )
s = 1 / 2 * ( 10.86 * \(10^{-13}\) / 477 * \(10^{-3}\) )
s = 11.38 * \(10^{-10}\) m
Therefore, the distance deflected from its path due to the Earth's magnetic field is 11.38 * \(10^{-10}\) m
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Two equal and opposite charges are placed 40mm apart,if the force between them is found to be 0.5N Calculate the magnitude of the charge
5. A person on a trampoline jumps straight up. When the person is 3 m above the surface and
with upward velocity of 2.5 m/s, drops a ball. a) What is the speed of the ball at the time of
impact? b) How long before the ball impacts the surface of trampoline?
a)The speed of the ball at the time of impact will be 8.1 m/sec.
b)The time taken by the ball impacts the surface of trampoline will be 1.1 second.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. Its SI unit is m/sec.
Given data;
g( gravitational acceleration) = 9.81 m/s2
u (initial velocity of ball) = 2.5 m/s
h₁(initial height of the ball) = 3.0 m
v (speed of the ball at the time of impact ) ?
The time taken by ball for upward journey = u / g
t₁ = u / g
t₁ = (2.5 m/s) / (9.81 m/s2) =
t₁ =0.2548 s
From second equation of motion,upward vertical distance covered by ball is;
\(\rm h_2= \frac{1}{2} gt^2\\\\ h_2=\frac{1}{2} \times 9.81 \times (0.2548)^2\\\\ h_2=0.3184\)
The total distance in the downward direction travelled;
\(\rm h_3=h_1+h_2 \\\\ h_3=3.0+0.3184 \\\\ h_3=3.3184 \ m\)
The time taken for the downward motion is;
\(\rm t_2 = (\frac{2 \times h_3 }{g} )^\frac{1}{2}\\\\ t_2 = 0.825 \ m/sec\)
The speed of the ball at the time of impact is found as;
\(\rm V=gt_2 \\\\ V= 9.81 \times 0.8225 \\\\ V= 8.07 \ m/sec\)
The total time of the flight of ball is;
\(\rm t_3 = t_1+t_2 \\\\ t_3=0.2548+0.8225 \\\\ t_3=1.0774 \ sec\)
Hence,the speed of the ball at the time of impact will be 8.1 m/sec and time taken by the ball impacts the surface of trampoline will be 1.1 second.
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If a planet has an orbital eccentricity equal to 0.70, then its orbit is
Closer to a perfect circle then a straight line
Almost rectangular
A very elongated ellipse
Almost parabolic
If a planet has an orbital eccentricity equal to 0.70, then its orbit is
a very elongated ellipse.What is eccentricity?Eccentricity is a measure of how squashed an ellipse is compared to a perfect circle.
The value of eccentricity ranges from 0 to 1, where 0 represents a perfect circle and 1 represents a parabolic orbit (which is not a closed orbit).
An eccentricity of 0.70 indicates that the planet's orbit is significantly elongated and not close to a perfect circle.
Therefore, the correct answer is - A very elongated ellipse.
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we can find the current, i, in the circuit by using ohm's law (generalized for alternating currents), v
The current, i, in the circuit by using ohm's law (generalized for alternating currents), v is \(\begin{aligned}& I= \\& \quad 0.4000+0.8000 i\end{aligned}\)
What is circuit?
An electronic circuit is composed of individual electronic components, such as resistors, transistors, capacitors, inductors and diodes, connected by conductive wires or traces through which electric current can flow.
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How long does it take electrons to get from
the car battery to the starting motor? Assume
the current is 134 A and the electrons travel
through copper wire with cross sectional area
38.9 mm- and length 92.2 cm. The mass den-
sity of copper is 8960 kg/m and the molar
mass is 63.5 g/mol. Avogadro's number is
6.022 x 10 . Asume that each copper atom
contributes one conduction electron.
Answer in units of min.
We need to find the time it takes an electron to move in the given circuit.
The time taken for electrons to reach the starting motor from the battery is 60.65 minutes.
I = Current = 134 A
\(N_A\) = Avogadro's number = \(6.022\times 10^{23}\ \text{mol}^{-1}\)
A = Area = \(38.9\ \text{mm}^2\)
L = Length = 92.2 cm
\(\rho\) = Density of copper = \(8960\ \text{kg/m}^3\)
M = Molar mass of copper = 63.5 g/mol
\(n_v\) = Number of valence electrons of copper = 1
e = Charge of electron = \(1.6\times 10^{-19}\ \text{C}\)
Number of charge carriers per unit volume is given by
\(n=\dfrac{\rho N_An_v}{M}\\\Rightarrow n=\dfrac{8960\times 6.022\times 10^{23}\times 1}{63.5\times 10^{-3}}\\\Rightarrow n=8.497\times 10^{28}\ \text{m}^{-3}\)
Time taken is given by
\(t=\dfrac{LAne}{I}\\\Rightarrow t=\dfrac{92.2\times 10^{-2}\times 38.9\times 10^{-6}\times 8.497\times 10^{28}\times 1.6\times 10^{-19}}{134}=3638.83\ \text{s}\\\Rightarrow t=\dfrac{3638.83}{60}=60.65\ \text{minutes}\)
The time taken for electrons to reach the starting motor from the battery is 60.65 minutes.
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A ball is projected with an initial velocity 50m/s at an angle 30 degree from the top of a tower 55m high.calculate the total time the ball was on the air and the maximum horizontal distance
Time of flight = 1.6 s
Horizontal distance = 64 m
What is a projectile motion?Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.
For the given case,
h = vt + ¹/₂gt²
h = height of tower
v = initial velocity
t = time of flight
55 = 50sin30t + ¹/₂9.8t²
55 = 25t + 4.9t²
4.9t² + 25t - 55 = 0
t = 1.6 s
X = vₓt
X = horizontal distance
vₓ = horizontal velocity
t = time of flight
X = (50 x cos30) x 1.6
X = 64 m
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the table below showing melting points and boiling point. take room temperature as 25°C.
A melting point is -117°C and boiling point is 78°C
B melting point is 658°C and boiling point is 2467°C
C melting point is -39°C and boiling point is 357°C
D melting point is -259.14°C and boiling point is -252.87°C
E melting point is 1530°C and boiling point is 2735°C
F melting point is 0°C and boiling point is 100°C
2.1 which substance(s) is /are solids at room temperature?
2.2 which of these substance is Hydrogen?
2.3 which substances are liquid at room temperature ?
2.4 which substance are gases at room temperature?
2.5 which substance has strongest forces between the particles?
2.6 which of these substances is water?
2.1 Substance C (melting point is -39°C and boiling point is 357°C) is solid at room temperature.
2.2 Substance D (melting point is -259.14°C and boiling point is -252.87°C)is Hydrogen.
2.3 Substances A ( melting point is -117°C and boiling point is 78°C) and F (melting point is 0°C and boiling point is 100°C) are liquid at room temperature.
2.4 Substance D ( melting point is -259.14°C and boiling point is -252.87°C) is a gas at room temperature.
2.5 Substance B (melting point is 658°C and boiling point is 2467°C) has the strongest forces between the particles.
2.6 Substance F ( melting point is 0°C and boiling point is 100°C) is water.
Based on the given information:
2.1 The substance with a melting point of -39°C (Option C) is a solid at room temperature (25°C). It remains in a solid state at room temperature.
2.2 The substance with a boiling point of -252.87°C (Option D) is Hydrogen. Hydrogen has a low boiling point, which is below room temperature.
2.3 The substances that are liquid at room temperature (25°C) are:
The substance with a melting point of -117°C and a boiling point of 78°C (Option A)
The substance with a melting point of 0°C and a boiling point of 100°C (Option F)
These substances, which are water and another unknown substance, exist as liquids at room temperature.
2.4 The substance with a melting point of -259.14°C and a boiling point of -252.87°C (Option D) is a gas at room temperature. Its boiling point is below room temperature, indicating that it exists as a gas.
2.5 The substance with the highest melting point (658°C) and boiling point (2467°C) is option B. This substance has the strongest forces between its particles, as indicated by its high melting and boiling points.
2.6 Water is represented by option F, as it has a melting point of 0°C and a boiling point of 100°C, which are the characteristic values for water.
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A linear accelerator uses alternating electric fields to accelerate electrons to close to the speed of light. A small number of the electrons collide with a target, but a large majority pass through the target and impact a beam dump at the end of the accelerator. In one experiment the beam dump measured charge accumulating at a rate of -2.0 nC/s. How many electrons traveled down the accelerator during the 2.0 h run
Answer:i
9E13 ELECTRONS
Explanation:
First we find the number of charges in two hrs
Which is - 2x 7200=- 14400NC
So no of electrons is now q/e
-144x10^-7/-1.6*10^-19
= 9*10^13
A marine weather station reports waves along the shore that are 2 meters high, 8 meters long, and reach the station 8 seconds apart. Determine the speed of these waves.
One full weather station reports wave passing a spot every second is equivalent to a frequency of 1 Hz. The frequency is 48=12=0.5 Hz if 4 waves pass a spot in 8 seconds.
What is the frequency of a 30-second ocean wave that hits the shore?The number of cycles that make up a time unit is the frequency. The frequency of a wave with a 30-second period is therefore 1 30 = 0.033 cycles per second, or 0.033 Hertz (Hz).
Which of the following statements most accurately sums up how a wave crosses a border and enters a new medium?A wave's speed and wavelength vary as it crosses a border and enters a new medium, but its frequency doesn't.
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Select the correct answer from each drop-down menu. Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. Complete the passage summarizing the collision. On colliding, the truck applies a force on the stationary car, and the stationary car applies and opposite force on the truck. The front of the truck is designed to crumple in order to , which protects the well-being of the passengers.
The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.
Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.
During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.
The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.
By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.
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Which object has the most momentum?
A toy car rolling along the floor
A child peddling their bike as fast as possible
&o
A large moving truck stopped at a red light
4500 kj of work is done by a small engine in 7.2 s what power is supplied by the engine in this time interval ?
P equals 625000 watts The engine provides power during this period, enabling anything to be done or accomplished. political or governmental power
What does "force of life" actually mean?influencing oneself, others, and circumstances This kind of influence comes from personal qualities rather than institutional authority. Personal power is more of a mindset or attitude. Self-efficacy and collaboration skills are important to those with high personal power.
What is power, really?Real power is energy, and as our awareness and self-awareness expand, it grows from within. Being powerful depends on having insight. A person with true authority does not affect the world without taking the larger picture into account.
Work done by the steam engine, W=4500*10³J
Time taken to do work, t = 7.2 seconds
P=W/t
=4500*10³/7.2
=625000watt
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A bird sits on a uniform rod suspended from vertical wires P and Q.
i
x !
'
v
P a
1
not to scale
15.0 cm
2W
The rod has a weight J’ and is 15.0 & long.
The weight of the bird is 2’ and acts at a distance x from P.
What is the value of x when the tension in P is half the tension in Q?
[1 mark]
A 7.50 cm [=]
B 10.0cm [e]
Cc 13cm fe]
D 15.0cm [e]
!
a) Define the Inverse Square Law and show that the field strength, E of a single charge Q acting on a test charge Q at a distance x from it along its field is given by
(b) A circuit consists of a variable resistor R connected in series with an ammeter and a cell. A voltmeter is connected in parallel across the variable resistor R. the cell is of e.m.f E and internal resistance r. For a certain value of R, the voltmeter reads 4V and the ammeter reads 1A. When R is adjusted, the voltmeter reads 2V and the ammeter reads 2.5A. Draw the circuit diagram and calculate the values of E and r.
a. The Inverse Square Law states that the intensity or strength of a physical quantity decreases with the square of the distance from its source.
b. The values of E and r in the given circuit are: E = 4V (e.m.f. of the cell) and r = ∞
How to explain the informationa. In the context of electrostatics, the Inverse Square Law describes the relationship between the electric field strength and the distance from a charged particle.
b. For the first scenario (V = 4V and I = 1A), we have:
4V = 1A * R1,
R1 = 4Ω.
For the second scenario (V = 2V and I = 2.5A), we have:
2V = 2.5A * R2,
R2 = 0.8Ω.
Total resistance in the circuit (when ammeter reads zero current) is given by:
= R1 + R2 + r.
Since the ammeter reads zero current, we have:
E = I * R_total,
4V = 0A * R_total,
R_total = ∞ (infinity).
Therefore, we can conclude that the internal resistance r of the cell is infinite (or very high compared to the resistances in the circuit).
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Find the measure of arc CD (round to the nearest degree).
1.31 m
0.5 m
The measure of arc CD is
The measure of arc CD (round to the nearest degree) is 150 degress
How do i determine the measure of arc CD to the nearest degree?The following data were obtained from the question:
Radius (r) = 0.5 cmLength of arc CD = 1.31 mMeasure of arc CD (θ) =?Length of arc = 2πr × (θ / 360)
Inputting the given parameters, we can obtain the measure of arc CD as follow:
1.31 = (2 × 3.14 × 0.5) × (θ / 360)
1.31 = (3.14 × θ) / 360
Cross multiply
3.14 × θ = 1.31 × 360
3.14 × θ = 471.6
Divide both sides by 3.14
θ = 471.6 / 3.14
θ = 150 °
Thus, we can conclude that the measure of arc CD is 150 °
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Complete question:
See attached photo
What type of tv uses a VfL for backlighting
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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If the forces acting on an object are balanced, what must be true about the motion of this object?
A. It must be moving
B. It must be accelerating
C. It must be changing direction
D. It must have a constant velocity
Answer:
D Constant velocity
Explanation:
if it has forces moving on it it has constant velocity
How are magnetic fields like vectors?
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
If the 100 g mass is replaced by a 200 g mass, which variables in Tnet = la change, and which
remains constant? Justify your answer.
The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.
What is the changed variable in the equation?The formula for net torque acting on an object is given as;
T(net) = Ia
where;
a is the angular accelerationI is the moment of inertiaT(net) is the net torqueThe moment of inertia of an object is given as;
I ∝ MR²
where;
M is the massR is the radius of the objectSo mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.
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Using this formula Q = mcAt. A 1kg block of aluminum is increased in temperature by 75°C. how much heat energy was required? a 67,7250 b 67.728 C 65.7253 d 66.7253 Check it
Answer:
67500 J
Explanation:
Q = mcΔt.................... Equation 1
Where Q = Amount of heat, m = mass of aluminum, c = specific heat capacity of aluminium, Δt = change or increase in temperature.
From the question,
Given: m = 1 kg, Δt = 75 °C
Constant: c = 900 J/kg.K
Substitute these values into equation 1
Q = 1×900×75
Q = 67500 J
Hence the heat energy required is 67500 J
All of the following are ways in which sports psychologists help athletes except __________.
A.
staying motivated
B.
managing fear of failure
C.
improving performance
D.
enhancing memory
Please select the best answer from the choices provided
A
B
C
D
Answer:
D-Enhancing memory
Explanation:
Circuits
Calculate the total Resistance, Current, and Power in the circuits
The total resistance of the circuit is 3 ohms.
The total current in the circuit is 4 A.
The power of the circuit is 48 W.
What is the total resistance of the circuit?
The total resistance of the circuit is calculated as follows;
1 / Rt = 1/R1 + 1/R2 + 1 / R3
1/Rt = 1/6 + 1/12 + 1/12
1/Rt = 0.3333
Rt = 3 ohms
The total current in the circuit is calculated as follows;
I = V / Rt
I = ( 12 ) / ( 3 )
I = 4 A
The power of the circuit is calculated as follows;
P = IV
P = ( 4 x 12 )
P = 48 W
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which object has a weight of about 22.5 n the book the rock the box the fish
Answer: The rock
Explanation:
Betelgeuse, one of the brightest stars in the constellation of Orion, has a diameter of 7.0 x 1011 m (500 times the diameter of the sun). Consider two compact clouds with opposite charge equal to 1.0 x 105 C. If these clouds are located 7.0 x 1011 m apart, what is the magnitude of the electric force of attraction between them?
K = 8.93 ⋅ 10 9 N m 2 C 2 hope this helps.