A rectangular poster is 3times as long as it is wide. The perimeter is 24 inches. What are the lengths and widths?
Answer:
Length: 9 inches per side
Width: 3 inches per side
Step-by-step explanation:
Perimeter = 2*width + 2*length
Perimeter = (2 x W) + (2 x 3W) = 8W.
Since we know P = 24, it is also = 8W
With 24=8W, divide each side by 8, and W = 3.
So if W=3, the width is 3 inches, and the length is 3W, or 3x3 which is 9.
if there perimeters are the same 8x (2) = (4x+10) 14
Answer:252
Step by step explanation:
db
Lane bought 12 pencils for
$0.39 each. What was the total cost of the
pencils before sales tax was added?
Answer:
$4.68
Step-by-step explanation:
if you do 0.39 x 12 you get 4.68
Answer:
$4.68
Step-by-step explanation:
12x0.39=$4.68
The value of the _____ is used to estimate the value of the population parameter.
The value of the sample statistic is used to estimate the value of the population parameter.
What estimates the value of the population parameter?The population parameter is found by using the population statistic to predict the population estimate.
This is because the sample statistic is based on the sample produced from the population so it can therefore be used to find out more on the population.
Options for this question are:
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what are the ranges to these graphs?
please help asap
will give brainliest
a) Range of f(x) = f(x) > - 6
b) Range of f(x) = f(x) > 0
c) Range of f(x) = f(x) > 1
What is the range of graph?The range of a graph is the set of all possible values of the output (or "y") for a given function, as the input (or "x") varies over the domain of the function. In other words, it represents all the possible y-values that the graph can take.
a)The range of the graph f(x) = (1/2 * 2^x) - 6 is the set of all possible values of f(x) as x varies over the domain of the function. In other words, it's the set of all possible y values that the graph can take.
To find the range of the function, we need to consider the behavior of 2^x as x increases. As x increases, 2^x grows very quickly and becomes very large. Therefore, the expression (1/2 * 2^x) will also become very large as x increases. Subtracting 6 from this large value will still result in a large positive value.
b) The range of the graph f(x) = (1/8) * 4^(x+1) is the set of all possible values of f(x) as x varies over the domain of the function. In other words, it's the set of all possible y values that the graph can take.
To find the range of the function, we need to consider the behavior of 4^(x+1) as x increases. As x increases, 4^(x+1) grows very quickly and becomes very large. Therefore, the expression (1/8) * 4^(x+1) will also become very large as x increases.
c) The range of the graph f(x) = (4(2/3)^x) + 1 is the set of all possible values of f(x) as x varies over the domain of the function. In other words, it's the set of all possible y values that the graph can take.
To find the range of the function, we need to consider the behavior of (2/3)^x as x increases. As x increases, (2/3)^x approaches 0. Therefore, the expression 4(2/3)^x will approach 0 as well. Adding 1 to this value will result in a value that approaches 1 as x increases.
Since the value of f(x) approaches 1 as x increases, the range of the function is the interval [1, infinity).
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Suppose a 5 x 9 matrix A has five pivot columns. Is Col A= R^5? Is Nul A= R^4? Explain your answers. Is Col A = R^5? Explain your answer. Choose the correct answer and reasoning below. A. Yes, because there are five pivot columns in A. These columns form a basis in five dimensions. Any 5-dimensional basis spans R^5. B. No, Col A = R^4. The number of pivot columns is equal to the dimension of the null space. Since the sum of the dimensions of the null space and column space equals the number of columns in the matrix, the dimension of the column space must be 4. Since any 4-dimensional basis is equal to R^4, Col A= R^4. C. Yes, because the column space of a 5x9 matrix is a subspace of R^5. There is a pivot in each row, so the column space is 5-dimensional. Since any 5-dimensional subspace of RS is R^5, Col A= R^5. D. No, because a 5x9 matrix exists in Rº. If its pivot columns form a 5-dimensional basis, then Col A is isomorphic to R^5 but is not strictly equal to R^5.
Row of A = 5 and Dim. of column A = 5, has a size of 5 elements and col(A) is isomorphic to R5 but is not strictly equal to R5.
It is given to us that the order of matrix A = 5x9
Number sequence of columns = 9
also, that of the pivot element in column A = 5
therefore, with the rank-nullity theorem, we get:
Rank (A) + Dim (num (A)) = 9
Also with this we get: rank (A) = number from the pivot element = 5
therefore, rank(A) = 5
Dim. (Nul.A) = 9 - Rank(A) = 5
= 4
moreover, Row of A = 5 and Dim. of column A = 5
therefore it has a size of 5 elements
= col(A) is isomorphic to R5 but is not strictly equal to R5.
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Can I get an answer please?
9514 1404 393
Answer:
T = (4, 9)
Step-by-step explanation:
The midpoint is computed from ...
Z = (S + T)/2
Solving for T, we find ...
T = 2Z -S
Using the given coordinates, this is ...
T = 2(4, 6) -(4, 3) = (2·4-4, 2·6 -3) = (4, 9)
The location of T is (4, 9).
Answer the following questions about group G with order 77. (1) Show that there are normal subgroups H and K of the group with order 7 and 11, respectively. (2) Show that HK={hk|h=H, kEK) is an Abelian subgroup of group G. (3) Show that HK-G. (4) Show that G is a cyclic group.
To answer the questions about group G with order 77: (1) Show that there are normal subgroups H and K of the group with order 7 and 11, respectively.
Since the order of G is 77, by the Sylow theorems, there exist Sylow 7-subgroups and Sylow 11-subgroups in G.
Let H be a Sylow 7-subgroup of G and K be a Sylow 11-subgroup of G. Since Sylow subgroups are conjugate to each other, H and K are both normal subgroups of G.
(2) Show that HK={hk|h∈H, k∈K} is an Abelian subgroup of group G.
Since H and K are normal subgroups of G, we have that HK is a subgroup of G. To show that HK is an Abelian subgroup, we need to prove that for any elements hk and h'k' in HK, their product is commutative.
Let hk and h'k' be arbitrary elements in HK. Since H and K are normal subgroups, we have that h'khk' = kh'h. Thus, the product hk h'k' is equal to kh'h, which implies that HK is an Abelian subgroup.
(3) Show that HK=G.
To show that HK=G, we need to prove that every element g in G can be expressed as a product hk, where h∈H and k∈K.
Since H and K are normal subgroups of G, their intersection H∩K is also a normal subgroup of G. By Lagrange's theorem, the order of H∩K divides both the order of H (which is 7) and the order of K (which is 11). Since 7 and 11 are coprime, the only possible order for the intersection is 1.
Thus, H∩K={e}, where e is the identity element of G. This implies that every element g in G can be uniquely expressed as g = hk, where h∈H and k∈K. Therefore, HK=G.
(4) Show that G is a cyclic group.
Since HK=G, and HK is an Abelian subgroup, we have that G is an Abelian group. Every Abelian group of prime order is cyclic. Since the order of G is 77, which is not prime, G cannot be cyclic.
Therefore, G is not a cyclic group.
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To answer the questions about group G with order 77: (1) Show that there are normal subgroups H and K of the group with order 7 and 11, respectively.
Since the order of G is 77, by the Sylow theorems, there exist Sylow 7-subgroups and Sylow 11-subgroups in G.
Let H be a Sylow 7-subgroup of G and K be a Sylow 11-subgroup of G. Since Sylow subgroups are conjugate to each other, H and K are both normal subgroups of G.
(2) Show that HK={hk|h∈H, k∈K} is an Abelian subgroup of group G.
Since H and K are normal subgroups of G, we have that HK is a subgroup of G. To show that HK is an Abelian subgroup, we need to prove that for any elements hk and h'k' in HK, their product is commutative.
Let hk and h'k' be arbitrary elements in HK. Since H and K are normal subgroups, we have that h'khk' = kh'h. Thus, the product hk h'k' is equal to kh'h, which implies that HK is an Abelian subgroup.
(3) Show that HK=G.
To show that HK=G, we need to prove that every element g in G can be expressed as a product hk, where h∈H and k∈K.
Since H and K are normal subgroups of G, their intersection H∩K is also a normal subgroup of G. By Lagrange's theorem, the order of H∩K divides both the order of H (which is 7) and the order of K (which is 11). Since 7 and 11 are coprime, the only possible order for the intersection is 1.
Thus, H∩K={e}, where e is the identity element of G. This implies that every element g in G can be uniquely expressed as g = hk, where h∈H and k∈K. Therefore, HK=G.
(4) Show that G is a cyclic group.
Since HK=G, and HK is an Abelian subgroup, we have that G is an Abelian group. Every Abelian group of prime order is cyclic. Since the order of G is 77, which is not prime, G cannot be cyclic.
Therefore, G is not a cyclic group.
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a segment with endpoints a (2, 6) and c (5, 9) is partitioned by a point b such that ab and bc form a 3:1 ratio. find b. (2.33, 6.33) (3.5, 10.5) (3.66, 7.66) (4.25, 8.25)
The coordinates of point b are :
(4.25,8.25)
To find the point b, we need to use the concept of dividing a segment in a given ratio. We can use the following formula to find the coordinates of point b:
b = ( (1-r) * a + r * c ), where r is the ratio in which the segment is divided.
Here, the ratio is 3:1, which means that ab is three times smaller than bc.
So we can write :
r = 3/(3+1) = 0.75
Substituting the values in the formula, we get:
b = ( (1-0.75) * (2,6) + 0.75 * (5,9) )
b = ( 0.25 * (2,6) + 0.75 * (5,9) )
b = ( (0.5,1.5) + (3.75,6.75) )
b = (4.25,8.25)
Therefore, the coordinates of point b are (4.25,8.25).
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The point B that partitions the line segment AC with endpoints A(2,6) and C(5,9) into a 3:1 ratio is found using the formula for dividing a line segment in a specific ratio. Upon substituting the given values into the formula, we get the coordinates of point B as (3.75, 8.25).
Explanation:The subject of your question is Mathematics, specifically, it involves the concept of partitioning a line segment in a certain ratio. In this case, we are given a segment with endpoints A (2,6) and C (5,9), and a point B partitions this line into a ratio of 3:1. We can use the formula for dividing a line segment in a given ratio to find point B. The formula is:
[(m*x2 + n*x1) / (m+n), (m*y2 + n*y1) / (m+n)] where x1, y1 and x2, y2 are the coordinates of the two points and m:n is the given ratio. Let's substitute the known values into the formula: B = [(3*5 + 1*2) / (3+1) , (3*9 + 1*6) / (3+1) ] =
(3.75, 8.25) .Therefore, your answer is (3.75, 8.25).
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Mary paid back a total of $5000 on an original loan of $700 that charged a simple interest of 6%. How many years was the loan taken out? Round your answer to two decimal places.
The loan was taken out for approximately 14.29 years. To determine the number of years the loan was taken out, we can use the formula for simple interest: Interest = Principal * Rate * Time
In this case, the interest paid is $5000, the principal (initial loan amount) is $700, and the interest rate is 6% or 0.06.
5000 = 700 * 0.06 * Time
To find Time (in years), we can rearrange the equation:
Time = 5000 / (700 * 0.06)
Time ≈ 14.29 years
Therefore, the loan was taken out for approximately 14.29 years.
To find the number of years the loan was taken out, we use the formula for simple interest:
Interest = Principal * Rate * Time.
We know that the interest paid is $5000, the principal is $700, and the interest rate is 6% or 0.06.
Plugging these values into the formula, we get 5000 = 700 * 0.06 * Time.
To find the time in years, we divide both sides of the equation by (700 * 0.06) to isolate Time.
Simplifying the equation, we get Time = 5000 / (700 * 0.06), which is approximately 14.29 years.
Therefore, the loan was taken out for approximately 14.29 years.
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11. What is the center of the circle (x - 2)2 + (y + 6)2 = 25?
Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region
Answer:
Question 16 = 22
Question 17 = 20 cm²
Step-by-step explanation:
Concepts:
Area of Square = s²
s = sideArea of Triangle = bh/2
b = baseh = heightDiagonals of the square are congruent and bisect each other, which forms a right angle with 90°
Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.
Solve:
Question # 16
Step One: Find the total area of two squares
Large square: 5 × 5 = 25
Small square: 2 × 2 = 4
25 + 4 = 29
Step Two: Find the area of the blank triangle
b = 5 + 2 = 7
h = 2
A = bh / 2
A = (7) (2) / 2
A = 14 / 2
A = 7
Step Three: Subtract the area of the blank triangle from the total area
Total area = 29
Area of Square = 7
29 - 7 = 22
-----------------------------------------------------------
Question # 17
Step One: Find the length of PT
Given:
PR = 4 cmRT = 6 cmPT = PR + RT [Segment addition postulate]
PT = (4) + (6)
PT = 10 cm
Step Two: Find the length of S to PT perpendicularly
According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal
Length of Diagonal = 4 cm
4 ÷ 2 = 2 cm
Step Three: Find the area of ΔPST
b = PT = 10 cm
h = S to PT = 2 cm
A = bh / 2
A = (10)(2) / 2
A = 20 / 2
A = 10 cm²
Step Four: Find the length of Q to PT perpendicularly
Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.
Length of Diagonal = 4 cm
4 ÷ 2 = 2 cm
Step Five: Find the area of ΔPQT
b = PT = 10 cm
h = Q to PT = 2 cm
A = bh / 2
A = (10)(2) / 2
A = 20 / 2
A = 10 cm²
Step Six: Combine area of two triangles to find the total area
Area of ΔPST = 10 cm²
Area of ΔPQT = 10 cm²
10 + 10 = 20 cm²
Hope this helps!! :)
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Find the interest earned on an investment of $10,000 into a money
market account that pays a simple interest rate of 1.75% over a 39 wk
period
What is the slope of the line graphed below?
Answer:
B
Step-by-step explanation:
I think so because the rise is going downward, which means it’s a negative number. Therefore m= -1/4
Write the equation of a line, in slope-intercept form, that has an y-intercept of 4 and an
x-intercept of -2.
Answer:
y = 2x + 4
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 4) ← coordinates of intercepts
m = \(\frac{4-0}{0+2}\) = \(\frac{4}{2}\) = 2 and c = 4
y = 2x + 4 ← equation of line
can someone helpp with this
a circle in the xyx, y-plane has center (5,7)(5,7)(, 5, comma, 7, )and radius 222. which of the following is an equation of the circle?
a. (x-5)^2 + (y-7)^2 = 2
b. (x+5)^2 + (y+7)^2 = 2
c. (x+5)^2 + (y-7)^2 = 4
d. (x-5)^2 + (y-7)^2 = 4
Therefore, the correct equation of the circle is option d: (x - 5)^2 + (y - 7)^2 = 4.
The equation of a circle with center (h, k) and radius r is given by (x - h)^2 + (y - k)^2 = r^2.
In this case, the center of the circle is (5, 7) and the radius is 2.
Plugging these values into the equation, we have:
(x - 5)^2 + (y - 7)^2 = 2^2
Simplifying:
(x - 5)^2 + (y - 7)^2 = 4
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what is the sum of twice a number and five is at least half the difference of six and the same number
x= 4 is a number and five is at least half the difference of six and the same number.
What is unitary method?The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units. What can be values and units.
Let's say you go to the store to buy six apples. You are informed by the shopkeeper that he is offering 10 apples for Rs 100. In this instance, the value and the units are the price of the apples.
Recognizing the units and values is crucial when using the unitary technique to a problem.
Always write the items that need to be computed on the right side and the things that are known on the left side to simplify things. We are aware of the quantity of apples and the amount of money in the aforesaid problem.
According to our question-
We must first create an equation before solving it.Finding out what the question is asking us will help us get started on this.Let's say our number is x, the value of which we do not yet know. Therefore, two times that amount would be two times, or two.That would be divided by half, or 1/2x. We must now determine what the product of 2x and 1/2x signifies.Since addition is the definition of sum, 2 + 0.5 Equals 2.5. This amount is equivalent to 10, according to the remainder of the question. That implies:learn more about unitary method click here:
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e.) What is the surface area?and volume of sphere
√8 mm
Answer:
v=4/3 pie r ³ you would put 8 in
Step-by-step explanation:
the formal
Use the drawing tools to form the correct answers on the graph.
Consider this linear function:
y=\frac{1}{2}x+1
Plot all ordered pairs for the values in the domain.
D: {-8, -4, 0, 2, 6}
Answer:
y = 1/2+1 increasing by 1/2 (-8 -4 ) (-4 0) (2 6)
Step-by-step explanation:
increasing by 1/2 (-8 -4 ) (-4 0) (2 6) see attached as -2 0 and 0 1 has a midway point -1 and 1/2
Find the value of x in the following Question
x/5=3
\(\mathbb{ANSWER:}\)
x = 15
\(\mathbb{SOLUTION:}\)
x/5 = 3x = 5 · 3x = 15
\( \sf \frac{x}{5} = 3\)
\( \sf 5 \times \frac{x}{5} = 3\)
\( \sf \cancel{5} \times \frac{x}{\cancel{5}} = 5 \times 3\)
\(\sf x = 5 \times 3\)
\(\sf x = 15\)
(8x- 1) (11X - 25) (15y - 48)
1320xyX−4224xX−165yX−3000xy+528X+9600x+375y−12001320xyX-4224xX-165yX-3000xy+528X+9600x+375y-1200
A basketball team played five games. In those games, the team won by 7 points, lost by 3, won by 4, lost by 2, and won by 9. What was the mean difference in game scores over the five games? The mean difference in game scores over the five games was
Given:
A basketball team played five games.
In those games, the team won by 7 points, lost by 3, won by 4, lost by 2, and won by 9.
To find:
The mean difference in game scores over the five games.
Solution:
Total number of games = 5
Scores in 5 matches are 7, -3, 4, -2, 9.
Positive sign is used for winning and negative sign is used for losing the game.
We know that,
\(Mean=\dfrac{\text{Sum of observations}}{\text{Number of observations}}\)
\(Mean=\dfrac{7-3+4-2+9}{5}\)
\(Mean=\dfrac{20-5}{5}\)
\(Mean=\dfrac{15}{5}\)
\(Mean=3\)
Therefore, the mean difference in game scores over the five games was 3.
If there care 30 trucks and 7 of them are red. What fraction are the red trucks
Answer:
7/30
Step-by-step explanation:
7 out of 30 is 7/30
The following set of jobs must be processed serially through a two-step system. The times at each process are in hours. If Johnson's Rule is used to sequence the jobs then Job A would complete processing on operation 2 at Job Process 1 Process 2 A 12 9 B 8 11 C 7 6 D 10 14 E 5 8
Select one: A. hour 35. B. hour 47. C. hour 38. D. hour 21.
The total time for all the jobs is 19 + 13 + 13 + 21 + 24 = 90 hours.
Johnson's Rule is a sequencing method used to determine the order in which jobs should be processed in a two-step system. It is based on the processing times of each job in the two steps. In this case, the processing times for each job in operation 2 at Job Process 1 and Process 2 are given as follows:
Job A: Process 1 - 12 hours, Process 2 - 9 hours
Job B: Process 1 - 8 hours, Process 2 - 11 hours
Job C: Process 1 - 7 hours, Process 2 - 6 hours
Job D: Process 1 - 10 hours, Process 2 - 14 hours
Job E: Process 1 - 5 hours, Process 2 - 8 hours
To determine the order, we first need to calculate the total time for each job by adding the processing times of both steps. Then, we select the job with the shortest total time and schedule it first. Continuing this process, we schedule the jobs in the order of their total times.
Calculating the total times for each job:
Job A: 12 + 9 = 21 hours
Job B: 8 + 11 = 19 hours
Job C: 7 + 6 = 13 hours
Job D: 10 + 14 = 24 hours
Job E: 5 + 8 = 13 hours
The job with the shortest total time is Job B (19 hours), so it is scheduled first. Then, we schedule Job C (13 hours) since it has the next shortest total time. After that, we schedule Job E (13 hours) and Job A (21 hours). Finally, we schedule Job D (24 hours).
Therefore, the order in which the jobs would complete processing on operation 2 at Job Process 1 and Process 2, when using Johnson's Rule, is:
Job B, Job C, Job E, Job A, Job D
The total time for all the jobs is 19 + 13 + 13 + 21 + 24 = 90 hours.
Therefore, the correct answer is not provided in the options given.
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For all waiting lines, P0+Pw= 1. true false
True. For all waiting lines, P0+Pw= 1
The terms P0 and Pw refer to the probabilities of having 0 customers in the system and having customers waiting in line, respectively. Since every customer is either in the system or in the waiting line, the sum of these probabilities must equal 1. This is because there are only two possible outcomes: either a customer is being served (P0) or they are waiting in line (Pw). Therefore, the probability of one of these events occurring is 1, and the probability of the other event occurring is 0. Hence, P0 + Pw = 1.
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what is the solution to the question 3|x| - 1 = 8.
A. x = 3 or 9
B. x = 9 or 9
C. x = 3 or -9
D. x = -3 or 3
An experiment consists of dealing 5 cards from a standard 52-card deck. What is the probability of being dealt a 3, 4, 5, 6, 7, all in the same suit? The probability of being dealt a 3, 4, 5,6, 7, all in the same suit is Round to seven decimal places as needed.)
The probability of being dealt a 3, 4, 5, 6, 7, all in the same suit is approximately 0.0000031.
To calculate the probability of being dealt a 3, 4, 5, 6, 7, all in the same suit, we can use the following formula:
P = (number of favorable outcomes) / (total number of possible outcomes)
the order in which the cards are chosen does not matter, so we need to divide by the number of ways we can arrange 5 cards, which is 5! (5 factorial).
Therefore, the total number of possible outcomes is (52 * 51 * 50 * 49 * 48) / (5 * 4 * 3 * 2 * 1), which simplifies to 2,598,960.
Finally, we can calculate the probability of being dealt a 3, 4, 5, 6, 7, all in the same suit:
P = 8 / 2,598,960
P = 0.00000308 (rounded to seven decimal places)
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A spherical surface encloses three charges q=4q, q= 5q, q, q=-7q. A fourth charge q= -5q is placed outside the sphere. How much is the flux of the electrical field through the spherical surface worth? let c the dielectric constant of vacuum
The flux of the electric field through the spherical surface is zero.
The flux of the electric field through a closed surface is given by the Gauss's law, which states that the flux is equal to the total charge enclosed divided by the dielectric constant of vacuum (ε₀).
In this case, the spherical surface encloses charges of magnitude 4q, 5q, q, and -7q, but the net charge enclosed is zero since the charges cancel each other out. Therefore, the flux through the spherical surface is zero in this case.
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A: The set of students who are computer science majors. B: The set of students who are taking CSE 191. Express the following sets in terms of A and B. Use set operators when necessary.
The appropriate set operators (∩, ∪, -, ') when expressing these sets in terms of A and B.
How to use set operators ?The set of computer science majors who are taking CSE 191 can be represented as the intersection of A and B: A ∩ B.The set of students who are not computer science majors but are taking CSE 191 can be represented as the difference of B and A: B - A.The set of students who are either computer science majors or taking CSE 191, or both can be represented as the union of A and B: A ∪ B.The set of students who are neither computer science majors nor taking CSE 191 can be represented as the complement of the union of A and B: (A ∪ B)'.Remember to use the appropriate set operators (∩, ∪, -, ') when expressing these sets in terms of A and B.
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