we will have to follow given below steps if we want to plot this inequality x is less than or equal to 2.6.
What is linear inequality and examples?A linear inequality is formed by any two real numbers or any two algebraic expressions marked by the symbols "," ">," "," or "." Ones of numerical inequality include 911 and 18>17, while algebraic examples include x+7>y, y10-x, and x y > 11
How do you identify a linear inequality?One of the inequality symbols is present in a linear inequality:. It displays non-equal data in graph style. With the inequality sign in place of the equality sign, a linear inequality appears exactly like a linear equation.
The values of x that satisfy the inequality must be determined before we may graph the inequality x = 2.6 on a number line. This can be done by changing x to a variety of values and observing which ones cause the inequality to hold true. When x is less than or equal to 2.6, we know that the inequality x = 2.6 is true. This means that the inequality will be satisfied for any value of x that is lower than or equal to 2.6. This has a range of inclusive values from -infinity to 2.6. We can use a dotted line spanning from negative infinity to 2.6 to graph the inequality on a number line. We would insert a dot for each number between negative infinity and 2.6, including 2.6 itself, since the dots on the line denote the numbers in the range. The dots on the line represent the integers in the range, which spans from negative infinity to 2.6. (i.e., all numbers less than or equal to 2.6). The open circle at 3 shows that the number is outside of the range, while the solid point at 2.6 indicates that the number is within the range.
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what is? -6 = x + 6
this is one step equation addition / subtraction
\( \: \: \: \: \: \)
x = - 12
refer to the attachment
refer to the attachmenthope it helps\(\sf \longmapsto-6 = x + 6\)
Flip the equation\(\sf \longmapsto \: x+6=−6\)
Subtract 6 from both sides\(\sf \longmapsto \: x+6−6=−6−6\)
\(\sf \longmapsto \: x=−12\)
\( \boxed{ \sf \: x=−12}\)
Can somebody please help me solve problem 16 .
Answer:
i think it`s $35
Step-by-step explanation:
Because 80 divided by 2 = 40 and the problem says to subtract 5 so I believe the answer is $35.
g a piece of wire 9 m long is cut into two pieces. one piece is bent into a square and the other is bent into an equilateral triangle. (a) how much wire should be used for the square in order to maximize the total area? correct: your answer is correct. m (b) how much wire should be used for the square in order to minimize the total area? incorrect: your answer is incorrect. m
(a) The length of wire that should be used for the square in order to maximize the total area is 9 meters.
(b) Using the same 9 meters of wire for the square will result in the minimum total area as well as the maximum total area.
(a) To maximize the total area, we need to use as much wire as possible for the square and as little as possible for the triangle. Let x be the length of wire used for the square, then the length of wire used for the triangle is 9 - x.
For the square, we have:
4s = x, where s is the side length of the square.
For the equilateral triangle, we have:
3t = 9 - x, where t is the side length of the equilateral triangle.
Solving for x in terms of s and t, we get:
x = 4s and x = 9 - 3t/2.
Substituting x = 4s into x = 9 - 3t/2, we get:
4s = 9 - 3t/2
8s = 18 - 3t
t = (18 - 8s)/3
The area of the square is given by A = s^2, and the area of the equilateral triangle is given by A = (\(\sqrt{3}\)/4)t^2.
Substituting t = (18 - 8s)/3, we get:
A = (\(\sqrt{3}\)/4)((18 - 8s)/3)^2
To maximize the total area, we need to maximize A, which is a function of s. Taking the derivative of A with respect to s, we get:
dA/ds = -4\(\sqrt{3}\)(4s-9)/27
Setting dA/ds = 0, we get:
4s - 9 = 0
Solving for s, we get:
s = 9/4
Therefore, the length of wire that should be used for the square in order to maximize the total area is:
x = 4s = 9 meters.
(b) To minimize the total area, we need to use as little wire as possible for the square and as much as possible for the triangle. Let x be the length of wire used for the square, then the length of wire used for the triangle is 9 - x.
Using the same equations as in part (a), we get:
t = (18 - 8s)/3
A = (\(\sqrt{3}\)/4)((18 - 8s)/3)^2
Taking the derivative of A with respect to s, we get:
\(dA/ds = -4\sqrt{3}(4s-9)/27\)
Setting dA/ds = 0, we get:
4s - 9 = 0
Solving for s, we get:
s = 9/4
This is the same value as in part (a), which means that using 9 meters of wire for the square will result in the minimum total area as well as the maximum total area.
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Can anyone help me with this please I really need help with this rq .
Answer:
Step-by-step explanation:
g(x) = ax - b
-76 = 27a - b
-79 = 28a - b Subtract
3 = -a Multiply both sides by -1
a = -3
g(x) = -3x - b
-85 = -3*30 - b
-85 = - 90 - b Add 90 to both sides
90-85 = - b Combine
5 = - b Multiply both sides by - 1
-5 = b
g(x) = -3x - b
g(x) = -3x - (-5)
g(x) = - 3x + 5
QUESTION 2 Using the "quarterly seasonality without trend" model in exhibit4 data, the quarter4 forecast for year 11 is 1167 1089 1001 999 Exhibit4 Quarterly sales of three years are below: Quarter Year 1 Year 2 Year 3 1 923 1,112 1,243 2 1,056 1,156 1,301 3 1,124 1,124 1,254 4 992 1,078 1,198
The "quarterly seasonality without trend" model is used to forecast quarterly sales, and the quarter 4 forecast for year 11 using this model is 1167 1089 1001 999.
The exhibit 4 quarterly sales for three years are given as follows: QuarterYear 1Year 2Year 31 9231,1121,2432 1,0561,1561,3013 1,1241,1241,2544 9921,0781,198
Solution: Given, quarterly seasonality without trend model,Quarter 1Quarter 2Quarter 3Quarter 4Sales Year 1923 1056 1124 992Sales Year 21075 1156 1124 1078Sales Year 31162 1301 1254 1198
Calculating the mean sales of each quarter across the years,Quarter 1Quarter 2Quarter 3Quarter 4Mean Sales1118.33 1174 1207.33 1089.33
For forecasting the sales in the year 11, we have to use the mean sales of each quarter and forecast the sales for each quarter.
So the quarter 4 forecast for year 11 using the quarterly seasonality without trend model is:Quarter 1Quarter 2Quarter 3Quarter 41167 1174 1001 999
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someone designed a game that attracts children. in case of the child won they will get a gift otherwise the child will lose their money. There is a box filled with n balls
• The child along with the game owner switch turns such that in each turn a player
could draw k balls at once at two conditions:
√k ∈ Z ∧ 1 ≤ k ≤ n
• The child draws first.
• The player who draws the last ball, wins
I am trying to design a recursive algorithm in Python programming language that takes
input N
output: true if the child won otherwise false
The algorithm is designed to find out whether the child wins or loses in a game where two players take turns to pick balls. The algorithm takes the number of balls remaining in the box as input and returns True if the child wins, otherwise False.
The algorithm assumes that both players play optimally. The algorithm works by recursively picking balls from the box and checking whether the child or the game owner wins the game.
This is a recursive problem where each player plays optimally. There are two players in the game. The child will pick the balls first and then the game owner takes turns. Both will pick the balls optimally in order to win.
In each turn, k balls can be picked from the box. The winner is the one who picks the last ball. If the child picks the last ball, they win otherwise the game owner wins.
The algorithm is as follows:
Algorithm - Pick Balls
1. Define a recursive function called PickBalls(n). The function takes one parameter as input, which is the number of balls remaining in the box.
2. Check if the number of balls remaining is less than or equal to k. If yes, then return True as the game has ended and the child has won.
3. If the number of balls is greater than k, then pick k balls from the box.
4. If the child picks the last ball, then return True.
5. If the child does not pick the last ball, then the game owner picks the balls recursively.
6. If the game owner picks the last ball, then return False. Otherwise, return True.
Explanation: We are designing a recursive algorithm to find out whether the child will win or lose in a game where two players take turns to pick balls. The algorithm takes the number of balls remaining in the box as input and returns True if the child wins, otherwise False. We are assuming that both players play optimally. The algorithm works as follows:
If the number of balls remaining in the box is less than or equal to k, then the child can pick all the balls and win the game. Therefore, the function returns True.
If the number of balls remaining in the box is greater than k, then the child picks k balls from the box. If the child picks the last ball, then they win the game. Therefore, the function returns True.
If the child does not pick the last ball, then the game owner picks the balls recursively. If the game owner picks the last ball, then they win the game. Therefore, the function returns False. If the game owner does not pick the last ball, then the child picks again and the process repeats itself. If the child eventually picks the last ball, then they win the game. Therefore, the function returns True.
Conclusion: The algorithm is designed to find out whether the child wins or loses in a game where two players take turns to pick balls. The algorithm takes the number of balls remaining in the box as input and returns True if the child wins, otherwise False. The algorithm assumes that both players play optimally. The algorithm works by recursively picking balls from the box and checking whether the child or the game owner wins the game.
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At the movies, tickets cost $13.50 for adults and $4.50 for kids under 12. What would
be the total cost for 10 adult tickets and 6 kids tickets? What would be the total cost
for a adult tickets and k kids tickets?
Total cost, 10 adult tickets and 6 kids tickets:
Total cost, a adult tickets and k kids tickets:
Submit Answer
attempt 2 out of 2 / problem 1 out of max 1
Answer:
adult-135
kid-27
Step-by-step explanation:
13.50*10=135
4.50*6=27
Susan had four bags of candy, each weighing 6 ounces. Isabel had one bag of candy weighing 1 pounds. Which girl has the more candy in weight? Your work will justify your answer.
Susan has more candy in weight compared to Isabel.
To compare the candy weights between Susan and Isabel, we need to ensure that both weights are in the same unit of measurement. Let's convert Isabel's candy weight to ounces for a fair comparison.
Given:
Susan: 4 bags x 6 ounces/bag = 24 ounces
Isabel: 1 bag x 16 ounces/pound = 16 ounces
Now that both weights are in ounces, we can see that Susan has 24 ounces of candy, while Isabel has 16 ounces of candy. As a result, Susan is heavier on the candy scale than Isabel.
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A firm experiences_______ if inputs are doubled and output more than doubles. diminishing marginal rate of technical substitution diminishing marginal product decreasing returns to scale increasing returns to scale
A firm experiences increasing returns to scale if inputs are doubled and output more than doubles.
When the firm's output grows at a faster rate than the growth in inputs, increasing returns to scale result. In this case, the company experiences economies of scale, which makes it more effective as it grows its production.
The firm is able to boost productivity and efficiency as it expands its scale of operations if inputs are doubled and output more than doubles.
This can be ascribed to a number of things, including specialisation, labour division, the use of capital-intensive technology, discounts for bulk purchases, and spreading fixed costs over a higher output. Lower average costs per unit of output result in higher profitability and competitiveness for the company.
The firm gains a number of benefits from growing returns to scale. First off, it lets the company to benefit from cost savings brought about by economies of scale, allowing it to manufacture goods or services for less money per unit. This may enable more competitive pricing on the market or result in larger profit margins.
Second, raising returns to scale can result in better operational effectiveness and resource utilisation. As the company grows in size, it will be able to use resources more wisely and profit from production volume-related synergies.market prices that are competitive.
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The cost of my monthly train ticket was £60 it went up by 25% what is the new price
Answer:
75 EUR
Step-by-step explanation:
1.00 (EUR 60) + .25 (EUR 15)
60 EUR * 1.25 = 75 EUR
Answer:
45
Step-by-step explanation:
\(60 \times 25 \div 100 = 15 \\ 60 - 15 = 45\)
begin{tabular}{|r|l|r|r|} \hline 3 & Below are your numerical inputs for the problem: \\ \hline 4 & Initial Cost (\$) & 390000 \\ \hline 5 & Year 1 Revenues (\$) & 192000 \\ \hline 6 & Year 1 Costs (\$) & 125000 \\ \hline 7 & Inflation & 2.75% \\ \hline 8 & Project Duration (years) & 6 \\ \hline 9 & Depreciation Method & \\ \hline 10 & Tax Rate & \\ \hline 11 & Net Working Capital (\% oft+1 Revenues) & MACRS \\ \hline 12 & Salvage Value (\$) & 28.00% \\ \hline 13 & Cost of Capital & 15.00% & 245000 \\ \hline \end{tabular} How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.
Information is needed to evaluate the project's financial viability, considering factors such as the initial investment, expected cash flows, cost of capital, and project duration.
To calculate the year 1 operating cash flows (OCF), we need to subtract the year 1 costs from the year 1 revenues:
OCF = Year 1 Revenues - Year 1 Costs
OCF = $192,000 - $125,000
OCF = $67,000
To find the depreciation expense in year 3, we need to determine the depreciation method. The provided information is incomplete regarding the depreciation method, so we cannot calculate the depreciation expense in year 3 without knowing the specific method.
The change in Net Working Capital (NWC) in year 2 can be determined by multiplying the Net Working Capital percentage (given as a percentage of t+1 revenues) by the year 1 revenues and subtracting the result from the year 2 revenues:
Change in NWC = (Year 2 Revenues - Net Working Capital percentage * Year 1 Revenues) - Year 1 Revenues
Without the specific Net Working Capital percentage or Year 2 Revenues values, we cannot calculate the exact change in NWC in year 2.
The net cash flow from salvage (ATSV) is calculated by multiplying the Salvage Value percentage by the Initial Cost:
ATSV = Salvage Value percentage * Initial Cost
ATSV = 28% * $390,000
ATSV = $109,200
To calculate the project's NPV, we need the cash flows for each year, the cost of capital, and the project duration. Unfortunately, the information provided does not include the cash flows for each year, so we cannot calculate the project's NPV.
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The complete question is:
Below are your numerical inputs for the problem: 4 & Initial Cost (\$) & 390000 5 & Year 1 Revenues (\$) & 192000 6 & Year 1 Costs (\$) & 125000 7 & Inflation & 2.75% 8 & Project Duration (years) & 6 9 & Depreciation Method & 10 & Tax Rate & 11 & Net Working Capital (\% oft+1 Revenues) & MACRS 12 & Salvage Value (\$) & 28.00% 13 & Cost of Capital & 15.00% & 245000 How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.
could someone help me with this maths question?
Answer:
x=69° ,y=69° is the answer
Step-by-step explanation:
Hope it is helpful for you
please follow me
Answer: X = 69° and Y = 111°
Step-by-step explanation: X is a z-angles which makes it the same as the given angles. Y is a corresponding angle which makes it the same as the above angle 111°.
Which two of these are continuous data?
Answer:
B and D
Step-by-step explanation:
Age of Student --> Age of student is continues
Time taken to run one mile is also continues
Answer:
B and D
Step-by-step explanation:
Earth is approximately 5 x 109 years old. For which of these ages could this be an approximation?
A 4,762,100,000 years
B 48,000,000,000 years
4.45 x 10⁹ years
4.249999999 × 10⁹ years
Answer:
The answer is around 50,000,000,000 years so its E
Step-by-step explanation:
Please help on all 5 of these as soon as you can
Answer:
1. no 2. no I think I'm not sure if this is right
how to do this question plz
Answer:
Adult Ticket: £7
Child Ticket: £2
Step-by-step explanation:
Let the cost of 1 child ticket be c, adult ticket be a.
\(2a + 3c = 20 \\ \\ a + 4c = 15 \\ a = 15 - 4c \\ \\ 2(15 - 4c) + 3c = 2 0 \\ 5c = 10 \\ c = 2 \\ \\ a = 15 - 4(2) \\ a = 7\)
solve 15 over x+2 equals 3 over 4
The solution to the expression is x= 18
How to calculate the expression ?15 over x=2 equals 3 over 4 can be written as follows
15/x+2 = 3/4
Cross multiply both sides
15×4= 3(x+2)
60= 3x +6
collect the like terms
3x= 60-6
3x= 54
divide both sides by the coefficient of x which is 3
3x/3 = 54/3
x= 18
Hence the value of x in the expression is 18
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Find the measure of the indicated angle to the nearest degree.
Answer:
37 degrees
Step-by-step explanation:
Cos x = 48/60
Cos x = 0.8
x = cos^-1 0.8
x = 36.8699
. In a soccer league, each of the n participating teams plays every other team twice during the season. If in the next season the league increases the number of teams by two, then there would be 27.5% more matches played. Find
The number of teams and matches in the soccer league illustrates permutation and combination
There are 12 teams in the soccer league in the first season
How to determine the number of teamsThe number of teams in the soccer league is given as n.
So, the total number of matches played in a season is:
Matches = n(n-1)/2
When the number of teams increases by 2, we have:
Matches = (n + 2)(n + 2 -1)/2
Also, the number of matches increases by 27.5%.
So, we have:
Matches = n(n-1)/2 * (1 + 27.5%)
Equate both equations
\(\frac{(n + 2)(n + 2 -1)}{2} = \frac{n(n-1)}{2} * (1 + 27.5\%)\)
Simplify
\(\frac{(n + 2)(n + 1)}{2} = \frac{n(n-1)}{2} * (1.275)\)
Multiply through by 2
\((n + 2)(n + 1) = n(n-1) * (1.275)\)
Expand
\(n^2 + 3n + 2 = 1.275n^2 - 1.275\)
Collect like terms
\(n^2 -1.275n^2+ 3n + 2 +1.275 = 0\)
Evaluate the like terms
\(-0.275n^2+ 3n + 3.275 = 0\)
Using a graphing calculator, we have:
n = -1 or n = 11.909
n cannot be negative.
So, we have:
n = 11.909
Approximate
n = 12
Hence, there are 12 teams in the soccer league in the first season
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Anna and Tommy each have a plant. They track the growth of their plants for four weeks. Whose plant grew at a faster rate, and what was the
rate?
Answer:
Anna
Step-by-step explanation:
Hers grew 2.5 inches each time
13.10 − Let Mn be the maximum of n independent U(0,1) random variables. a. Derive the exact expression for P(∣Mn−1∣>ε). Hint: see Section 8.4. b. Show that limn→[infinity]P(∣Mn−1∣>ε)=0. Can this be derived from Chebyshev's inequality or the law of large numbers?
This can be derived using Chebyshev's inequality, as Chebyshev's inequality and the law of large numbers are different in nature.
Let M_n be the maximum of n independent U(0, 1) random variables.
To derive the exact expression for P(|M_n − 1| > ε), we need to follow the below steps:
First, we determine P(M_n ≤ 1-ε). The probability that all of the n variables are less than 1-ε is (1-ε)^n
So, P(M_n ≤ 1-ε) = (1-ε)^n
Similarly, we determine P(M_n ≥ 1+ε), which is equal to the probability that all the n variables are greater than 1+\epsilon
Hence, P(M_n ≥ 1+ε) = (1-ε)^n
Now we can write P(|M_n-1|>ε)=1-P(M_n≤1-ε)-P(M_n≥1+ε)
P(|M_n-1|>ε) = 1 - (1-ε)^n - (1+ε)^n.
Thus we have derived the exact expression for P(|M_n − 1| > ε) as P(|M_n-1|>ε) = 1 - (1-ε)^n - (1+ε)^n
Now, to show that $lim_{n\to\∞}$ P(|M_n - 1| > ε) = 0 , we can use Chebyshev's inequality which states that P(|X-\mu|>ε)≤{Var(X)/ε^2}
Chebyshev's inequality and the law of large numbers are different in nature as Chebyshev's inequality gives the upper bound for the probability of deviation of a random variable from its expected value. On the other hand, the law of large numbers provides information about how the sample mean approaches the population mean as the sample size increases.
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Will make BRAINLIEST
Please helppppppppppp
x being any number, specifically any real number between -2 and 6
-2<x</=6
i think!?
Christina estimated 188% of 91 by performing these steps. What did she do wrong?
(90) (190 percent) = (90) (100 percent + 90 percent) = (90) (100 percent) + (90) (90 percent) = (90) (1.0) + (90) (0.9) = 90 + 18 = 108.
She rounded 188% up to 190%.
She rounded 91 down to 90.
She incorrectly broke 190% into 100 percent + 90 percent.
She incorrectly multiplied 90 and 0.9.
Answer:
D) she incorrectly multiplyed 90 and 0.9.
Step-by-step explanation:
hope this helps! i got 100 on the quiz on edge
Answer:
D
Step-by-step explanation:
Find an equation of the line with slope 3 that
contains the point (7.11).
y = mx + b
20 POINTS!!PLEASE HELP!!! At the school carnival, the sixth graders are making directional arrows, as shown
below.
6 inches 6 inches 4 inches 10 inches
Answer:
The area is 26
Step-by-step explanation:
plz give brainliest
$0.95
Muffin
$1.99
Fruit pies
$ 3.29
Keirra wants to buy 12 bagels. She uses partial products to find her total. She says $ 16.80 is close to my estimate of 12 x 1=12, so this total is reasonable. Do you agree with her? Explain your reasoning.
Answer:
$11.40, is the actual price, so no
Step-by-step explanation:
If a bagel is $0.95 cents, then multiply that by 12, that would be $11.40, so no, her total is not reasonable, even if you round $0.95 to a dollar, 12x1 would be 12, so you can't estimate that to $16.80
~Akmp10
Lowest common multiple of of 3,5,6
Answer:
30
hope it helps........
What is the equation of the cosine curve below? Include the period, horizontal shift (if any), and vertical shift (if any)
The equation of the cosine curve is y = A cos(B(x - C)) + D. Period is 2π/B. C is the horizontal shift and D is the vertical shift.
The equation of a cosine curve is given by:
y = A cos(B(x - C)) + D
where:
A is the amplitude, which represents the maximum displacement of the curve from its center.
B is the frequency, which is related to the period of the curve. The period T of the curve is given by T = 2π/B.
C is the phase shift, which represents a horizontal shift of the curve to the left or right.
D is the vertical shift, which represents a vertical displacement of the curve.
So the equation of the cosine curve in its most general form is:
y = A cos(B(x - C)) + D
where A, B, C, and D are constants that determine the characteristics of the curve.
Correct Question :
What is the equation of the cosine curve? Include the period, horizontal shift (if any), and vertical shift (if any).
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A survey was given to a random sample of 1350 residents of a town to determine whether they support a new plan to raise taxes in order to increase education spending. Of those surveyed, 64% of the people said they were in favor of the plan. At the 95% confidence level, what is the margin of error for this survey expressed as a percentage to the nearest tenth?
The margin of error for the survey, rounded to the nearest tenth, is approximately 4.0% when expressed as a percentage.
To determine the margin of error for a survey at the 95% confidence level, we need to calculate the standard error. The margin of error represents the range within which the true population proportion is likely to fall.
The formula for calculating the standard error is:
Standard Error = sqrt((p * (1 - p)) / n)
where p is the sample proportion and n is the sample size.
In this case, the sample proportion is 64% (or 0.64) since 64% of the 1350 surveyed residents support the plan.
Plugging in the values:
Standard Error = \(\sqrt{(0.64 * (1 - 0.64)) / 1350)}\)
\(= \sqrt{(0.2304 / 1350)} \\= \sqrt{(0.0001707)}\)
≈ 0.0131
Now, to find the margin of error, we multiply the standard error by the appropriate critical value for a 95% confidence level. The critical value corresponds to the z-score, which is approximately 1.96 for a 95% confidence level.
Margin of Error = z * Standard Error
= 1.96 * 0.0131
≈ 0.0257
Finally, to express the margin of error as a percentage, we divide it by the sample proportion and multiply by 100:
Margin of Error as Percentage = (Margin of Error / Sample Proportion) * 100
= (0.0257 / 0.64) * 100
≈ 4.0%
Therefore, the margin of error for this survey, expressed as a percentage to the nearest tenth, is approximately 4.0%.
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3,411-234 3. Please answer fast I need it now