Mike bought a new shirt for $39.95. The sales tax in his city is 8.25%. What was the sales tax amount on
the shirt that Mike bought? Sales tax =
Answer:
$3.30
Step-by-step explanation:
Shirt price * city sales tax = sales tax amount on shirt. $39.95 * 0.0825 = $3.30
Look at this cube
If the side lengths are halved, then which of the following statements about its surface area will be true?
Answer:
the new surface Will be 1/4 pf the old surface
Step-by-step explanation:
because the surface with 7 in Is about 294 and with 3.5 (1/2 of 7) Is 73.5.
so 294:4 Is 73.5
excuse me for my bad English but I'm italian
To find the roots of a polynomial, it is often useful to find the ____ of the polynomial.
Answer:
factors
Step-by-step explanation:
To find the roots of a polynomial, it is often useful to find the Factors of the polynomial.
Explain why y=(x^2+7x+12)/(2x^2-7x) has a domain of all real numbers except 7/2 and 0?
Using the graphical methods [online graph calculator], the domain of (fx) = (x-3)/7x is given as All real numbers except 7/2 and 0.
(−∞,0)∪(0,7/2)∪(7/2,∞),
{x∣∣x∣≠0,7/2}
What is a domain in mathematics?A relation's domain and range are defined as the sets of all the x-coordinates and all the y-coordinates of ordered pairs, respectively.
here, we have,
y=(x^2+7x+12)/(2x^2-7x)
by solving, we get, domain as,
(−∞,0)∪(0,7/2)∪(7/2,∞),
{x∣∣x∣≠0,7/2}
Graphs may also be used to determine the domain and range of functions. The domain of a graph consists of all the input values represented on the x-axis since the domain refers to the set of potential input values. The range is the collection of potential output values represented on the y-axis.
Notice as indicated in the graph that the coordinates or ordered pairs plotted DO NOT go through the origin which is zero. Also notice that the curved lines, extend to all real numbers on the grapy to infinity.
Hence stated as a mathematical expression, the domain would be:
a domain of all real numbers except 7/2 and 0
(−∞,0)∪(0,7/2)∪(7/2,∞),
{x∣∣x∣≠0,7/2}
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in trapezoid abcd segments ab and cd are parallel. point p is the intersection of diagonals ac and bd. the area of 4p ab is 16 square units, and the area of 4p cd is 25 square units. what is the area of trapezoid abcd?
The area of trapezoid ABCD is 18.5 square units.
To find the area of trapezoid ABCD, we need to use the formula for the area of a trapezoid which is: Area = (sum of the bases/2) x height. Since AB and CD are parallel, we can consider them as the two bases of the trapezoid. Let's denote the length of AB as a and the length of CD as b.
We know that the area of 4PAB is 16 square units, which means that the height of the trapezoid from point P to AB is 4 units. Similarly, we know that the area of 4PCD is 25 square units, which means that the height of the trapezoid from point P to CD is 5 units.
Now, let's consider the diagonals AC and BD. Since P is the intersection of these diagonals, we can divide the trapezoid into two triangles: APB and CPD. The sum of the areas of these two triangles is equal to the area of the trapezoid. We can use the formula for the area of a triangle which is: Area = (base x height)/2.
The base of triangle APB is a and its height is 4. Therefore, the area of APB is (a x 4)/2 = 2a. The base of triangle CPD is b and its height is 5. Therefore, the area of CPD is (b x 5)/2 = 2.5b.
The sum of the areas of APB and CPD is 2a + 2.5b = 2(a + 1.25b). This is equal to the area of the trapezoid since the sum of the areas of the two triangles is equal to the area of the trapezoid.
Therefore, the area of trapezoid ABCD is 2(a + 1.25b). Substituting the given values, we get:
Area = 2(a + 1.25b)
Area = 2(AB + 1.25CD)
Area = 2(a + 1.25b) = 2(4 + 1.25(5)) = 18.5 square units
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8 4- 2 -8 6 -6 2 4 9 8 -2 -2 -4- -6 -8
We have 2 points in the graph (3,4) and (-3,0) so the slope is
\(m=\frac{4-0}{3--3}=\frac{4}{6}=\frac{2}{3}\)so the answer is A) 2/3
b-4/6=b/2 find the variable
please help i dont understand how to work this
Based on the given equation of b -4/6=b/2, the value of the variable b, can be found to be -2
What is the variable?The variable can be found by solving the equation through the operations of mathematics.
First, cross-multiply:
b -4/6 = b/2
b - 4 = 6b / 2
After cross-multiplying, collect like terms:
b - 4 = 3b
b - 3b = 4
-2b = 4
b = 4 / -2
b = -2
In conclusion, the variable is -2.
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A rectangle has vertices A(1,2), B(1, 9), C(7, 9), and D(7, 2). Find the perimeter of the rectangle in units.
Step-by-step explanation:
The perimeter is 26 units
a safe has a 4-digit lock code that does not include zero as a digit and no digit is repeated. What is the probability that the lock code consists of all even didgits?
Answer:
\(\dfrac1{126}\)
Step-by-step explanation:
9 all possible digits (1, 2, 3, 3, 4, 5, 6, 7, 8, 9)
4 digits and no digits repeated so
9•8•7•6 - number of all possible codes
4 even digits (2, 4, 6, 8)
4 digits and no digits repeated so
4•3•2•1 - number of all codes wich consists of all even digits
What is the probability that the lock code consists of all even didgit:
\(\dfrac{4\cdot3\cdot2\cdot1}{9\cdot8\cdot7\cdot6}=\dfrac{1\cdot1\cdot1\cdot1}{9\cdot2\cdot7\cdot1}=\dfrac1{126}\)
A bag contains 4 blue marbles and 7 red marbles. Two marbles are randomly drawn without replacement. Find the probability of the event ""the first marble is red and the second marble is blue""?
Answer:
8/11
Step-by-step explanation:
In the given scenario was cannot calculate P(B) directly. As it depends on what happened first, by itself we don’t know what was drawn first. Thus it becomes a conditional probability question:
P( B | A ) ← reads as the probability of “B” happening “given that” “A” has already happened — in this case the probability that the second marble drawn is a blue marble given that the first was a red marble.
WILL MARK BRAINLIEST!!! Evelyn loves to read and owns 8 different novels. If there is only room for 6 novels on her bookshelf, how many different ways can she arrange the books on her shelf?
A. 28 ways
B. 48 ways
C. 720 ways
D. 20,160 ways
E. 60,720 ways
Answer:
B
Step-by-step explanation:
I think the answer is b because each space of the shelf can hold 1 of 8 different books and there are 6 different spots so it would be 8x6 which equals 48. I hope this makes sence and helps.
Find the range of the function rule y=5x−2 for the domain.{−12, 14, 25}
Answer:
hmmm really interested but hard to get
and not easy
Answer:
{− 4 1/2, −3/4, 0}
Step-by-step explanation:
G E Which of the following segments is tangent to the circle ? 1) overline HL 2 ) overline DE 3 overline FG 4 ) overline AC
Answer:
DE
Step-by-step explanation:
........................
Find the distance between the two points in simplest radical form.
(−5,−4) and (−2,−6)
Answer: \(\sqrt{13}\) units
Work Shown:
\((x_1,y_1) = (-5,-4) \text{ and } (x_2, y_2) = (-2,-6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-5-(-2))^2 + (-4-(-6))^2}\\\\d = \sqrt{(-5+2)^2 + (-4+6)^2}\\\\d = \sqrt{(-3)^2 + (2)^2}\\\\d = \sqrt{9 + 4}\\\\d = \sqrt{13}\\\\d \approx 3.6056\\\\\)
I used the distance formula.
A slightly alternate method is to form a right triangle and use the pythagorean theorem. The hypotenuse will have the endpoints (-5,-4) and (-2,-6).
please help meeee! !!!
Answer:
c) $ 12.00
Step-by-step explanation:
$78.20 x 15%= 11.75
round up
Two side lengths of a triangle are $11$ and $17$. What is the longest possible integer length of the third side of the triangle
The longest possible integer length of the third side of the triangle is 6 < x < 28
The sum of any two sides must be greater than the third side for a triangle to exist
let the third side be x
x + 11 > 17 and x + 17 > 11 and 11 + 17 > x
x > 6 and x > - 6 and x < 28
The longest possible integer length of the third side of the triangle is 6 < x < 28
The length of the 3 sides of a triangle needs to always be among (however no longer the same) the sum and the difference of the opposite two sides. As an example, take the instance of two, 6, and seven. and. consequently, the third side period should be extra than 4 and less than 8.
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Answer:
27
Step-by-step explanation:
Let the third side length be s. Then, by the Triangle Inequality, we know that s satisfies the inequalities
\(s + 11 & > 17, \\ s + 17 & > 11, \\ 11 + 17 & > s.\)
\(\begin{align*} s + 11 & > 17, \\ s + 17 & > 11, \\ 11 + 17 & > s.\end{align*}\)
The first two inequalities hold as long as s > 6 and the third holds if s < 28. The largest possible integer s that satisfies all of these is 27.
Given that a = (- 8) b = 2 c = 7 and d = 11 , solve for x, y, z, and w.
[[x + y, z], [z - x, w - y]] =
[[a, b], [c, d]]
What is the value of w?
(Only type a number, nothing else)
Answer:
24
Step-by-step explanation:
Okay, let's solve this step-by-step:
1) We are given: a = -8, b = 2, c = 7, d = 11
2) We are asked to solve the matrix equation: [[x + y, z], [z - x, w - y]] = [[a, b], [c, d]]
3) Matching up the elements in the matrices:
x + y = a = -8 (1)
z = b = 2 (2)
z - x = c = 7 (3)
w - y = d = 11 (4)
4) Solving the equations:
From (1): x + y = -8 => x = -8 - y
Substitute in (3): z - (-8 - y) = 7 => z - (-8) = 7 + y => z = 15 + y
Substitute (2) into the above: 2 = 15 + y => y = 13
Substitute y = 13 into (1): -8 - 13 = -21 = x
Substitute x = -21 and y = 13 into (4): w - 13 = 11 => w = 11 + 13 = 24
Therefore, the values are:
x = -21
y = 13
z = 15
w = 24
So the final value of w is:
w = 24
Find the area of the figure. Round to the nearest tenth.
HELP ASAP!!
Answer:
A
Step-by-step explanation:
f=1/2(a+b)×h1/2(1.6+4)×22.8×25.6 since to round off 5.6 to the nearest tenth consider the hundredths' value of 5.6 which is 0. therefore the tenths value of 5.6 remains 5.6What is the value of d?
A)80
B)100
C)84
D)50
Answer:
100 degrees
Step-by-step explanation:
You can tell by just looking at the picture :)
Choose the correct simplification of 9x2(4x 2x2 − 1). 18x4 36x3 − 9x2 18x4 − 36x3 9x2 36x4 18x3 − 9x2 36x4 − 13x3 9x2
The correct simplification would be \(18x^4 - 36x^3 + 9x^2\) (option a).
To simplify the expression \(9x^2(4x - 2x^2\) - 1), we need to perform the multiplication and combine like terms.
1. Start by distributing the 9x^2 to each term inside the parentheses:
\(9x^2 * 4x = 36x^3 9x^2 * (-2x^2) = -18x^4 9x^2 * (-1) = -9x^2\)
2. Now we can combine the terms obtained from the distribution:
\(36x^3 - 18x^4 - 9x^2\)
3. Rearranging the terms in descending order of exponents:
\(-18x^4 + 36x^3 - 9x^2\)
4. However, we can simplify this expression further by factoring out a common factor of \(-9x^2\):
\(-9x^2(2x^2 - 4x + 1)\)
5. Thus, the final simplified expression is:
\(18x^4 - 36x^3 + 9x^2\)
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Let S be the quadratic surface given by 2x2+y2−2z2=10. (a) Classify S : S is a hyperboloid of two sheets. S is a hyperboloid of one sheet. S is an elliptic paraboloid. S is an ellipsoid. S is an elliptic cone. (b) Find the upward-pointing unit normal N to S at (2,2,1). (Write your solution using the standard basis vectors i,j,k. Use symbolic notation and fractions where needed.) N= (c) Find an equation of the tangent plane P to S at the point (2,2,1) An equation for P is given by
To classify the quadratic surface S, we need to analyze its equation.
The equation of S is given by 2x^2 + y^2 - 2z^2 = 10.
(a) To classify S:
We observe that the coefficients of x^2, y^2, and z^2 have different signs.
This indicates that S is a hyperboloid of two sheets.
(b) To find the upward-pointing unit normal N to S at (2, 2, 1):
To determine the unit normal vector at a point on the surface, we take the gradient of the equation of S and normalize it.
The gradient of S is given by ∇S = (∂S/∂x)i + (∂S/∂y)j + (∂S/∂z)k.
Taking partial derivatives of S with respect to each variable, we have:
∂S/∂x = 4x
∂S/∂y = 2y
∂S/∂z = -4z
At the point (2, 2, 1), the gradient becomes:
∇S = (4(2))i + (2(2))j + (-4(1))k
= 8i + 4j - 4k
To obtain the unit normal, we normalize ∇S:
N = (∇S) / ||∇S||
Calculating the magnitude of ∇S:
||∇S|| = √(8^2 + 4^2 + (-4)^2)
= √(64 + 16 + 16)
= √96
= 4√6
Dividing ∇S by ||∇S||, we get:
N = (8i + 4j - 4k) / (4√6)
= (2i + j - k) / √6
Therefore, the upward-pointing unit normal N to S at (2, 2, 1) is (2i + j - k) / √6.
(c) To find an equation of the tangent plane P to S at the point (2, 2, 1):
The equation of a plane can be given in the form Ax + By + Cz + D = 0, where (A, B, C) is the normal vector to the plane.
We already have the normal vector N = (2i + j - k) / √6 from part (b). Now, to find D, we substitute the coordinates (2, 2, 1) into the plane equation:
A(2) + B(2) + C(1) + D = 0
Substituting the components of N, we get:
(2)(2) + (1)(2) + (-1)(1) + D = 0
4 + 2 - 1 + D = 0
D = -5
Therefore, an equation for the tangent plane P to S at the point (2, 2, 1) is:
2x + y - z - 5 = 0.
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AYUDAAA PORFAVOOOOOOR!!
Answer:
4
Step-by-step explanation:
Answer:
La respuesta seria 3 espero que esto ayude
Step-by-step explanation:
simplify the expression: 3a+4a
Answer: 7a
Step-by-step explanation:
Step-by-step explanation:
do sum of 3a and 4a your answer will be 7a
Lorah is considering cutting down a tall tree in her front yard, but she is worried it might be tall enough to fallon the house when coming down. She knows that the base of the tree is 50 feet from her house. Equipped with onlya 12 inch ruler, she stands at the edge of her house, holding the ruler I foot from her eye. She lines the bottom ofthe ruler up with the base of the tree, and sees that the top of the tree lines up with a point 9 inches high on theraier. Wher house be far enough away from the falling tree?
She has to find if the tree is tall enough to fall into her house.
She is using a 12-inches ruler to find proportions. We can draw this as:
The triangle that can be drawn using as vertices the base of the tree, the top of the tree and the house is similar to the triangle formed by the rule and the the distance of 1 ft.
We can see that as the height of the ruler that indicates the top of the tree is smaller than the foot, we know that the height H of the tree is smaller than the distance D from the house to the tree, in the same proportion.
We can calculate the height of the tree using the following proportion:
\(\begin{gathered} \frac{H}{D}=\frac{9\text{ in}}{1\text{ ft}} \\ \frac{H}{50\text{ ft}}=\frac{9\text{ in}}{12\text{ in}}=\frac{3}{4} \\ H=50\text{ ft}\cdot\frac{3}{4} \\ H=37.5\text{ ft} \end{gathered}\)Answer: The house is far enough, as the height of the tree is less than 50 ft (it is 37.5 ft)
Arrivals to a bank automated teller machine (ATM) are distributed according to a Poisson distribution with a mean equal to four per 15 minutes. Complete parts a and b below.a. Determine the probability that in a given 15-minute segment, three customers will arrive at the ATM The probability is .1954. (Round to four decimal places as needed.) b. What is the probability that fewer than four customers will arrive in a 30-minute segment? The probability is 0002. (Round to four decimal places as needed.)
The probability that fewer than four customers will arrive in a 30-minute segment is 0.0483, rounded to four decimal places.
Based on the given information, we know that the arrivals to the ATM follow a Poisson distribution with a mean of 4 per 15 minutes.
a. To determine the probability that three customers will arrive in a given 15-minute segment, we can use the Poisson probability formula:
P(X = 3) = (e^-4) * (4^3) / 3!
Where X is the number of arrivals, e is the mathematical constant approximately equal to 2.71828, and 3! means 3 factorial, which is 3 * 2 * 1 = 6.
Plugging in the values, we get:
P(X = 3) = (e^-4) * (4^3) / 3! = 0.1954
So the probability that three customers will arrive in a given 15-minute segment is 0.1954, rounded to four decimal places.
b. To find the probability that fewer than four customers will arrive in a 30-minute segment, we need to use the Poisson distribution again, but this time with a mean of 8 (since there are two 15-minute segments in 30 minutes, and the mean for one segment is 4).
We want to find P(X < 4) or P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3).
Using the Poisson probability formula with a mean of 8:
P(X = 0) = e^-8 * (8^0) / 0! = 0.0003
P(X = 1) = e^-8 * (8^1) / 1! = 0.0030
P(X = 2) = e^-8 * (8^2) / 2! = 0.0122
P(X = 3) = e^-8 * (8^3) / 3! = 0.0328
Adding up these probabilities, we get:
P(X < 4) = 0.0003 + 0.0030 + 0.0122 + 0.0328 = 0.0483
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(3x — 3), (4y+4)°/60° Solve for y.
Find a common prime factor in each of these pairs of numbers.
a) 21 and 411
b) 77 and 242
c) 56 and 63
Answer:
See below.
Step-by-step explanation:
A) 3
B) 11
C) 7
-hope it helps
Answer:
a) 3
b) 11
c) 7
Step-by-step explanation:
The factors of 21 are: 1, 3, 7, 21
The factors of 411 are: 1, 3, 137, 411
A common prime factor is 3.
The factors of 77 are: 1, 7, 11, 77
The factors of 242 are: 1, 2, 11, 22, 121, 242
A common prime factor is 11.
The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56
The factors of 63 are: 1, 3, 7, 9, 21, 63
A common prime factor is 7.
FIRST to answer and get it CORRECT will get brainliest, 13 points , and a thanks:) pls leave an explanation on how u got ur answer if possible :)
Answer:
Yes, john did make his scale factor the right way, because
Step-by-step explanation:
3 x 2.5 = 7.5, Seen on the right figure/shape/parallelogram
2 x 2.5 = 5, Seen on the right figure/shape/parallelogram
Edit:
Brainliest? :)
Answer:
Yes he did it correctly
Step-by-step explanation:
The scale factor is the number you get after you divide the values of the corresponding sides of both shapesFor this example the 2 side is similar to the 5 side and the 3 side is similar to the 7.5 side. So we make ratios from the first figure to the second figureThat will 2 from the first to 5 five from the second so 2 : 5Then 3 from the first to 7.5 from the second so 3 : 7.5The scale factor must be same for every ratio, or else the transformation is incorrectCheck the ratios, does \(2:5=3:7.5\) ?\(2:5=\frac{2}{5} =0.4\) \(3:7.5=\frac{3}{7.5} =0.4\) yes, so it is a correct transformationPlease help me respond this
Option 2 is correct that is 1.79
What is third quartile ?When presented in ascending order, the value that 75% of data points fall within is known as the higher quartile, or third quartile (Q3).
The quartiles formula is as follows:
Upper Quartile (Q3) = 3/4(N+1)
Lower Quartile (Q1) = (N+1) * 1/3
Middle Quartile (Q2) = (N+1) * 2/3
Interquartile Range = Q3 -Q1,
1.74, 0.24, 1.56, 2.79, 0.89, 1.16, 0.20, and 1.84 are available.
Sort the data as follows: 0.20, 0.24, 0.89, 1.16, 1.56, 1.74, 1.84, 2.79 in ascending order of magnitude.
The data set has 8 values.
hence, n = 8; third quartile: 3/4 (n+1)th term
Q3 =3/4 of a term (9) term
Q3 =27/4 th term
Q3 = 1.74 + 1.84 / 2 (average of the sixth and seventh terms)
equals 1.76
Thus Q3 is 1.76 that is option 2
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David is doing an investigation about factors that affect plant growth, so he plants two young elm trees near each other in his garden. He gives the first elm tree a gallon of water every week, and he gives the second elm tree fertilizer once a month. He plans on measuring the trees' heights and trunk girths every week for the next year. How can David best improve his investigation
David can best improve his investigation by including a control group. A control group is a group that does not receive any treatment or intervention and is used as a benchmark to compare the results of the experimental group. In this case, the control group would be a third young elm tree that is planted near the other two but does not receive any water or fertilizer. David can measure the height and trunk girth of the control tree every week for a year as well.
In scientific research, it is important to include a control group to ensure that the results of the experimental group are due to the treatment or intervention and not due to other factors. In this case, David is investigating the factors that affect plant growth, and he is manipulating the amount of water and fertilizer that the two elm trees receive. However, there could be other factors that affect plant growth, such as soil quality, sunlight exposure, temperature, and pests. If David only measures the height and trunk girth of the two elm trees that receive water and fertilizer, he cannot be sure if any changes in their growth are due to the treatment or due to other factors.
To improve his investigation, David can plant a third young elm tree near the other two and not give it any water or fertilizer. This third tree will serve as the control group, and David can measure its height and trunk girth every week for a year as well. By comparing the growth of the experimental group (the two elm trees that receive water and fertilizer) to the growth of the control group (the third elm tree that receives nothing), David can be more confident that any changes in the growth of the experimental group are due to the treatment and not due to other factors.
David can best improve his investigation by including a control group, which will serve as a benchmark to compare the results of the experimental group. The control group should be a third young elm tree that is planted near the other two but does not receive any water or fertilizer. David can measure the height and trunk girth of the control tree every week for a year as well. By comparing the growth of the experimental group (the two elm trees that receive water and fertilizer) to the growth of the control group (the third elm tree that receives nothing), David can be more confident that any changes in the growth of the experimental group are due to the treatment and not due to other factors.
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