please answer within 7 minutes !!

The union of two events A and B, denoted by A U B, does not have outcomes from both A and B is true.

Because the union of two events A and B, denoted by A U B is the possibility of occurance of either event A or event B. The crossroad of two events A and B, denoted by A ∩ B, is the event conforming of all issues that are in A and B. Two events A and B can be both mutually exclusive and independent at the same time. The union of two sets is a set containing all the rudiments from both sets. However, they're counted only formerly in the union and can't be considered in both, If there are some common rudiments in the two sets.

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The complete question is :

the union of two events A and B, denoted by A ∪ B, can not have outcomes from both A and B. State true or false.

Given:

Graph is given.

Answer:

none. he was made into a smoothie, so he is a liquid.(⌐■_■)

Step-by-step explanation:

Answer:

Since the values are not given i can only tell how to solve if the values were given,

you know that it got blended into one peice, which is 1

You take this number and multiply it by the number of peices their were which is x

so the answer of this will be x

where x is a variable that represents number of peices.

The item is an inelastic good at a price of 6 because it is negative and have a demand of -0.71.

The formula for elasticity of demand is Elasticity of demand = (% change in quantity demanded) / (% change in price)

The initial quantity demanded at a price of 6 and the quantity demanded at a slightly different price must be know.

Let say Initial quantity demanded is:

x = -0.7(6) + 10

x = 5.8

Assume price changes slightly to 6.01, which gives us a new quantity demanded of x:

= -0.7(6.01) + 10

= 5.793

The % change in quantity demanded will be:

= [(new quantity demanded - initial quantity demanded) / initial quantity demanded] x 100%

= [(5.793 - 5.8) / 5.8] x 100%

= -0.12%

As price has changed from 6 to 6.01, we can calculate the percentage change as follows:

% change in price = [(new price - initial price) / initial price] x 100%

= [(6.01 - 6) / 6] x 100%

= 0.17%

Elasticity of demand = (% change in quantity demanded) / (% change in price)

= (-0.12% / 0.17%)

= -0.71

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Answer:

Step-by-step explanation:

From the information given:

The joint density of \(y_1\)  and  \(y_2\) is given by:

\(f_{(y_1,y_2)} \left \{ {{y_1+y_2, \ \ 0\ \le \ y_1 \ \le 1 , \ \ 0 \ \ \le y_2 \ \ \le 1} \atop {0, \ \ \ elsewhere \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ } \right.\)

a)To find the marginal density of \(y_1\).

\(f_{y_1} (y_1) = \int \limits ^{\infty}_{-\infty} f_{y_1,y_2} (y_1 >y_2) \ dy_2\)

\(=\int \limits ^{1}_{0}(y_1+y_2)\ dy_2\)

\(=\int \limits ^{1}_{0} \ \ y_1dy_2+ \int \limits ^{1}_{0} \ y_2 dy_2\)

\(= y_1 \ \int \limits ^{1}_{0} dy_2+ \int \limits ^{1}_{0} \ y_2 dy_2\)

\(= y_1[y_2]^1_0 + \bigg [ \dfrac{y_2^2}{2}\bigg]^1_0\)

\(= y_1 [1] + [\dfrac{1}{2}]\)

\(= y_1 + \dfrac{1}{2}\)

i.e.

\(f_{(y_1}(y_1)}= \left \{ {{y_1+\dfrac{1}{2}, \ \ 0\ \ \le \ y_1 \ \le , \ 1} \atop {0, \ \ \ elsewhere \ \\ \ \ \ \ \ \ \ \ } \right.\)

The marginal density of \(y_2\) is:

\(f_{y_1} (y_2) = \int \limits ^{\infty}_{-\infty} fy_1y_1(y_1-y_2) dy_1\)

\(= \int \limits ^1_0 \ y_1 dy_1 + y_2 \int \limits ^1_0 dy_1\)

\(=\bigg[ \dfrac{y_1^2}{2} \bigg]^1_0 + y_2 [y_1]^1_0\)

\(= [ \dfrac{1}{2}] + y_2 [1]\)

\(= y_2 + \dfrac{1}{2}\)

i.e.

\(f_{(y_1}(y_2)}= \left \{ {{y_2+\dfrac{1}{2}, \ \ 0\ \ \le \ y_1 \ \le , \ 1} \atop {0, \ \ \ elsewhere \ \\ \ \ \ \ \ \ \ \ } \right.\)

b)

\(P\bigg[y_1 \ge \dfrac{1}{2}\bigg |y_2 \ge \dfrac{1}{2} \bigg] = \dfrac{P\bigg [y_1 \ge \dfrac{1}{2} . y_2 \ge\dfrac{1}{2} \bigg]}{P\bigg[ y_2 \ge \dfrac{1}{2}\bigg]}\)

\(= \dfrac{\int \limits ^1_{\frac{1}{2}} \int \limits ^1_{\frac{1}{2}} f_{y_1,y_1(y_1-y_2) dy_1dy_2}}{\int \limits ^1_{\frac{1}{2}} fy_1 (y_2) \ dy_2}\)

\(= \dfrac{\int \limits ^1_{\frac{1}{2}} \int \limits ^1_{\frac{1}{2}} (y_1+y_2) \ dy_1 dy_2}{\int \limits ^1_{\frac{1}{2}} (y_2 + \dfrac{1}{2}) \ dy_2}\)

\(= \dfrac{\dfrac{3}{8}}{\dfrac{5}{8}}\)

\(= \dfrac{3}{8}}\times {\dfrac{8}{5}}\)

\(= \dfrac{3}{5}}\)

= 0.6

(c) The required probability is:

\(P(y_2 \ge 0.75 \ y_1 = 0.50) = \dfrac{P(y_2 \ge 0.75 . y_1 =0.50)}{P(y_1 = 0.50)}\)

\(= \dfrac{\int \limits ^1_{0.75} (y_2 +0.50) \ dy_2}{(0.50 + \dfrac{1}{2})}\)

\(= \dfrac{0.34375}{1}\)

= 0.34375

The constant of proportionality is a crucial aspect of a proportional relationship, as it tells us how much one variable changes in relation to the other. It can be calculated from the equation of the relationship, or from the slope of the graph if it is a linear relationship.

A proportional relationship is a mathematical equation that expresses two variables that are in proportion to one another. In this type of relationship, if one variable is multiplied by a certain constant factor, then the other variable will be multiplied by the same constant factor. For example, if the cost of 3 books is $15, then the cost of 6 books will be $30. In this case, the number of books and the cost of the books are in proportion to one another.

The constant of proportionality is the constant factor by which the two variables are multiplied to obtain each other. In other words, it is the ratio between the two variables that remain constant in a proportional relationship. It can be represented by the letter k, and is calculated by dividing one variable by the other.

To find the constant of proportionality from a graph, we need to look at the slope of the line. The slope is the ratio between the change in the y-values and the change in the x-values, which is also known as the rise over run. If the graph shows a proportional relationship, then the slope will remain constant throughout the graph.

For example, if the graph shows the relationship between the number of hours worked and the amount of money earned, and the slope is 10, then the constant of proportionality is 10. This means that for every hour worked, the person earns $10. The equation for this proportional relationship can be written as y = 10x, where y represents the amount of money earned and x represents the number of hours worked.

In conclusion, the constant of proportionality is a crucial aspect of a proportional relationship, as it tells us how much one variable changes in relation to the other. It can be calculated from the equation of the relationship, or from the slope of the graph if it is a linear relationship.

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The assertion is true. Both 7√5 and √2 + 21 are irrational numbers because they cannot be expressed as fractions.

The assertion is true. Both 7√5 and √2 + 21 are irrational numbers.

An irrational number is defined as a number that cannot be expressed as a fraction of two integers and has an infinite non-repeating decimal representation.

In the case of 7√5, the square root of 5 is an irrational number because it cannot be expressed as a fraction. Multiplying it by 7 does not change its irrational nature.

Similarly, √2 is also an irrational number because the square root of 2 cannot be expressed as a fraction. Adding 21 to √2 does not alter its irrationality.

The reason provided, that every integer is a rational number, is not relevant to the given assertion. While it is true that every integer is a rational number because it can be expressed as a fraction (e.g., 3 can be written as 3/1), it does not contradict the fact that 7√5 and √2 + 21 are irrational numbers.

In conclusion, the assertion is valid, and both 7√5 and √2 + 21 are irrational numbers.

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Given:

Find-: Evaluate the expression.

Sol:

Formula:

So the value is:

value is:

So the value is 220.

Answer:

p > 34

He wrote more than 34 pages before today.

Step-by-step explanation:

Eduardo wrote 16 more pages, increasing his total number of pages above 50.

p = pages he wrote before today

p + 16 > 50

p > 50 - 16

p > 34

He wrote more than 34 pages before today.

Answer:

Choice B is the closest

Step-by-step explanation:

A-lateral = 2πrh

r = D/2 = 16.5/2 = 8.25

h = 14

A = 2π(8.25)(14) = 725.7 in²

The given system is-

We have to graph these equations. Remember that each equation represents a straight line. The image below shows both lines.

The important thing here is that the solution of the system is the common point of the lines.

As you can observe, Jake's mistake was that he confused the coordinates, he wrote down inversely.-

On the other hand, to graph a linear equation we need just two points when x = 0, and y = 1. Let's the two points for the first equation y - 2x = 0.

For x = 0

So, the first point is (0,0).

Let's find the second point when y = 1.

The second point is the same (1/2,0).

Once you have the two points of the line, you draw them on the coordinated plane then you draw a straight line across those points. The image below shows this.

Then, you do the same process to graph the second equation to have the two lines as the first image shows.

Answer:

Mary Jo bought 20 shares at $19 a share and 80 shares at $24 a share.

Step-by-step explanation:

Let's use algebra to solve the problem. Let x be the number of shares Mary Jo buys at $19 a share, and y be the number of shares she buys at $24 a share.

We know that Mary Jo spends a total of $2,300, so we can write the equation:

19x + 24y = 2300

We also know that she ends up with a total of 100 shares, so we can write the equation:

x + y = 100

Now we have two equations with two variables, which we can solve using substitution or elimination.

Let's use substitution. Solve the second equation for x:

x = 100 - y

Substitute this expression for x in the first equation:

19(100 - y) + 24y = 2300

Simplify and solve for y:

1900 - 19y + 24y = 2300

5y = 400

y = 80

So Mary Jo bought 80 shares at $24 a share.

To find the number of shares she bought at $19 a share, substitute y = 80 in the second equation:

x + 80 = 100

x = 20

Therefore, Mary Jo bought 20 shares at $19 a share.

In summary, Mary Jo bought 20 shares at $19 a share and 80 shares at $24 a share.

The ordered pair (3, - 2) is not a solution to the equation 2x - y = 4

An ordered pair is made up of the ordinate and the abscissa of the x coordinate, with two values given in parenthesis in a certain sequence.

Pair in Order = (x,y)

x is the abscissa, the distance measure of a point from the primary axis x

y is the ordinate, the distance measure of a point from the secondary axis y

Given, an equation 2x - y = 4 now if  (3, - 2) is an ordered pair then putting the numerical value of x must satisfy the y value.

when x = 3,

2(3) - y = 4.

6 - y = 4.

- y = 4 - 6.

- y = - 2.

y = 2.

So,  (3, - 2) is not a solution to an equation 2x - y = 4.

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Designing an easy do-it-yourself compost bin:

Drawing and Description:

The compost bin can be a simple structure made of wood or wire mesh. It consists of four sides, a bottom, and a removable lid. The sides and bottom are connected securely to form a rectangular shape, while the lid allows for easy access to the contents inside.

The bin can be placed directly on the ground or on a solid surface, depending on personal preference.

Materials Used:

Wood or wire mesh (depending on preference)

Nails or screws to assemble the structure

Size of the Bin:

The size of the bin can vary based on the available space and the amount of compostable materials you generate. A suitable size for a home compost bin could be approximately 3 feet wide, 3 feet deep, and 3 feet tall.

Substances Used to Fill It:

To fill the compost bin, you would need a mix of "green" and "brown" materials. "Green" materials include fruit and vegetable scraps, coffee grounds, tea leaves, grass clippings, and plant trimmings. "Brown" materials consist of dry leaves, shredded newspaper, cardboard, and small twigs.

Household Items That Can Go in It:

You can add a variety of household items to the compost bin, such as fruit and vegetable peels, eggshells, coffee grounds, tea bags, yard waste (leaves, grass clippings, plant trimmings), shredded paper, cardboard, and natural fibers (like cotton or wool scraps).

Time for Compost to Be Ready:

The time it takes for the compost to be ready varies depending on factors like temperature, moisture, and the type of materials used. Generally, it takes about 2 to 6 months for compost to fully decompose and become ready to use.

Using the Compost:

Once the compost has broken down into a dark, crumbly, and earthy material, it is ready to use. You can spread it in your garden beds or pots as a nutrient-rich soil amendment. It improves soil structure, retains moisture, and provides essential nutrients for plants' growth.

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Answer:

B  or 70 hot dogs.

Step-by-step explanation:

56 hot dogs cost 140 dollars

1 hot dog costs 140/56 = 2.50

How many hot dogs would you need to see to get 175 dollars.

x * $2.50 = $175

x = 175/2.5

x = 70

Answer:

3 (5x -2) (use the distributive property to multiply the number outside the parenthesis by everything inside of it)

15x -6 (this in the answer)

C I hope this helps :))

Step-by-step explanation:

The answer choice which must be true regarding the linear function is; The set must have a constant additive rate of change.

Since a linear function typically takes the slope-intercept form; f(x) = mx +c.

It therefore follows that the equation must have a constant slope m, which is the described additive constant rate of change.

It therefore follows that, the answer choice which is true regarding the linear function is therefore; The set must have a constant additive rate of change.

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Answer:

20 on c and 90 on d cause noth are kinda the same but different at the same time.

a) The sum of the areas of all the squares is 2 unit².

b) The sum of the perimeters of all squares is \(\frac{4\sqrt{2} }{\sqrt{2} -1}\) unit.

In Mathematics and Geometry, the area of a square can be calculated by using this mathematical equation (formula);

A = x²

Where:

Area of 1st square, A₁ = 1² unit².

Area of 2nd square, A₂ = (1/√2)² unit².

Area of 3rd square, A₃ = (1/2)² unit².

Therefore, the sum of the areas of all the squares is given by;

Sum of all areas = A₁  + A₂ + A₃ + ...... + Aₙ

Sum of all areas = 1² + (1/√2)² + (1/2)² + .....

Common ratio, r = 1/2 and the first term is 1.

Sum of all areas to infinity = 1/(1 - 1/2)

Sum of all areas to infinity = 2 unit².

Part b.

In Mathematics and Geometry, the perimeter of a square can be calculated by using the following formula;

P = 4x

Perimeter of 1st square, P₁ = 4(1) unit.

Perimeter of 2nd square, P₂ = 4(1/√2) unit.

Perimeter of 3rd square, P₃ = 4(1/2) unit.

Therefore, the sum of the perimeter of all the squares is given by;

Sum of all perimeters = 4(1) + 4(1/√2) + 4(1/2) + .....

Sum of all perimeters = 4(1 + 1/√2 + (1/√2)² + ....)

Common ratio, r = 1/√2 and the first term is 1.

Sum of all perimeters to infinity = \(4(\frac{1}{1-\frac{1}{\sqrt{2} } } )\)

Sum of all perimeters to infinity = \(\frac{4\sqrt{2} }{\sqrt{2} -1}\) unit.

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Answer:X=10

Step-by-step explanation:

Answer:

Step-by-step explanation this is a tough one but i know everything the answer is 69

6) 65 * 7200 /100 = 4680 $

7) OP=price/ (1− Discount percentage)

original price = 32.89 / (1- 0.85)

= 219.26 $

8)Let the total people in crew is x of which 8(66.2/3%) are men.

x *(66.2/3/ 100 ) =8 or

(x⋅200/3 )*(1 /100)=8 or

x=3 * (8/2)=12

there are 12 people in the crew

9) 12,800 * 15 /100 = 1920$ taken as taxes

Answer:

3

15: 1, 3, 5, 15

24: 1, 2,3,4,6,8,12,24

27:1, 3,9,27

Answer:

20

Step-by-step explanation:

Let the number of days be \(d\).

\(250=12d \\ \\ d=\frac{250}{12}=\frac{125}{6} \implies \lfloor d \rfloor=20\)

Answer:

Using z score formula:

X = z ∂ + µ

 = 157.833

Step-by-step explanation:

Solution:

Mean = µ = 1262

Standard deviation = ∂ = 117

(a) 28th percentile for the number of chocolate chip.

P( z < z) = 28%

             = 0.28

P( z<- 0.58)  = 0.28

Z = -0.58

By using z score formula:

Z = x - µ /∂

-0.58= x – 117 / 1262

X = (- 0.58)(117) + (1262)

 =  1194.14

(b) Middle 97% of bag.

P(-z < z < z) = 97%

                    = 0.97

P( z < z) – p(z < -z) = 0.97

2p(z < z) -1 = 0.97

2p (z < z) = 1 + 0.97

P(z < z) = 1.97 / 2

            = 0.99

P(z < 2.33) = 0.99

Z ± 2.33

By using z score formula:

Z = x - µ / ∂

X = z ∂ + µ

  = - 2.33 x 117 + 1262

  =989.39

Z = 2.33

X = z ∂ + µ

  =  2.33 x 117 + 1262

 =1533.61

(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate.

By using standard normal table,

The z dist’n formula:

P(z < z ) = 25%

            =0.25

P(z < -0.6745) = 0.25

Z = 0.6745

Using z score formula:

X = z∂ + µ

   = - 0.6745 x 117 + 1262

  = 1183.0835

First quartile = Q1 =1183.0835

The third quartile is:

P(z<z) = 75%

    = 0.75

P(z < 0.6745) = 0.75

Z = 0.6745

Using z score formula:

X = z ∂ + µ

  = 0.6745 x 117 + 1262

= 1340.9165

IQR = Q3 – Q1

     = 1340.9165 – 1183.0835

  = 157.833

Answer:

Cost for each pound of jelly beans:  $2.75

Cost for each pound of almonds:  $3.75

Step-by-step explanation:

Let J be the cost of one pound of jelly beans.

Let A be the cost of one pound of almonds.

Using the given information, we can create a system of equations.

Given 3 pounds of jelly beans and 5 pounds of almonds cost $27:

\(\implies 3J + 5A = 27\)

Given 9 pounds of jelly beans and 7 pounds of almonds cost $51:

\(\implies 9J + 7A = 51\)

Therefore, the system of equations is:

\(\begin{cases}3J+5A=27\\9J+7A=51\end{cases}\)

To solve the system of equations, multiply the first equation by 3 to create a third equation:

\(3J \cdot 3+5A \cdot 3=27 \cdot 3\)

\(9J+15A=81\)

Subtract the second equation from the third equation to eliminate the J term.

\(\begin{array}{crcrcl}&9J & + & 15A & = & 81\\\vphantom{\dfrac12}- & (9J & + & 7A & = & 51)\\\cline{2-6}\vphantom{\dfrac12} &&&8A&=&30\end{array}\)

Solve the equation for A by dividing both sides by 8:

\(\dfrac{8A}{8}=\dfrac{30}{8}\)

\(A=3.75\)

Therefore, the cost of one pound of almonds is $3.75.

Now that we know the cost of one pound of almonds, we can substitute this value into one of the original equations to solve for J.

Using the first equation:

\(3J+5(3.75)=27\)

\(3J+18.75=27\)

\(3J+18.75-18/75=27-18.75\)

\(3J=8.25\)

\(\dfrac{3J}{3}=\dfrac{8.25}{3}\)

\(J=2.75\)

Therefore, the cost of one pound of jelly beans is $2.75.

Answer:

\(115 \dfrac{1}{2}\:cm^3\)

Step-by-step explanation:

The volume of a rectangular prism is the product of each of the sides of the prism

Given the sides have lengths
\(3\dfrac{1}{2}, 6 \;and\; 5 \dfrac{1}{2} cm\)

the volume would be
\(3\dfrac{1}{2} \times 6 \times 5 \dfrac{1}{2}\)

To perform this multiplication, convert mixed fractions to improper fractions first

Use the rule that mixed fraction
\(a\dfrac{b}{c}=\dfrac{a\times \:c+b}{c}\)

\(3\dfrac{1}{2}=\dfrac{3\times 2+1}{2} = \dfrac{7}{2}\)

\(5\dfrac{1}{2}=\dfrac{5\times 2+1}{2}= \dfrac{11}{2}\)

Therefore
\(3\dfrac{1}{2}\times \:6\times \:5\dfrac{1}{2}\\\\= \dfrac{7}{2}\times \:6\times \dfrac{11}{2}\\\\= \dfrac{7}{2}\times \dfrac{6}{1}\times \dfrac{11}{2} \quad(6 = \dfrac{6}{1})\)

\(=\dfrac{7\times \:6\times \:11}{2\times \:1\times \:2}\\\\= \dfrac{462}{4}\\\)

Divide numerator and denominator by 2 to get
\(\dfrac{231}{2}\\\)

Convert improper fraction \(\dfrac{231}{2}\) to mixed fraction using quotient/remainder

\(\dfrac{231}{2} \\\\\rightarrow Quotient: 115\\\\\rightarrow Remainder = 231 - 115 \times 2 = 231 - 230 = 1\)

\(\dfrac{231}{2} = 115 \dfrac{1}{2}\)

Answer: "The pyramid and the cone have the same volume despite their different shapes."

Step-by-step explanation: If a pyramid and a cone are both 10 centimeters tall and have the same volume, then the statement that can be made is:

"The pyramid and the cone have the same volume despite their different shapes."

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