Please complete the blank in the following sentence
Within the
a thick lining
develops once per menstrual cycle.
I
SEASE
IDONT IONOW
Plz help it’s hard

Answer:

10

Step-by-step explanation:

9x10=90 then add the shipping and get 100

Answer:

THERE IS NO DARN SHAPE MAN

Step-by-step explanation:

The Reflexive property of congruence can be used to prove

ΔPQR≅ΔPSR .

Given:

∠QPR≅∠SPR

∠PQR≅∠PSR

What is Reflexive property of congruence ?

In geometry, the reflexive property of congruence states that an angle, line segment, or shape is always congruent to itself.

We learned that the reflexive property of equality means that anything is equal to itself. The formula for this property is a = a. This property tells us that any number is equal to itself. For example, 3 is equal to 3.

PR≅PR (Reflexive property of congruence)

If two angles and a non-included side of one triangle are equal to two angles and a non-included side of another triangle, then the triangles are congruent.(AAS theorem)

Hence, ΔPQR≅ΔPSR.

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Therefore, the Total Direct Materials cost variance is -$2,481. This indicates an unfavorable variance, meaning that the actual cost of materials was higher than the standard cost of materials.

To calculate the Total Direct Materials cost variance, we need to first calculate the Actual Direct Materials cost and the Standard Direct Materials cost.

Actual Direct Materials Cost = Actual quantity of materials used x Actual cost per yard

= 9,450 units x 4.75 yards per unit x $2.04 per yard

= $92,019

Standard Direct Materials Cost = Standard quantity of materials allowed x Standard cost per yard

= 9,450 units x 5 yards per unit x $2.00 per yard

= $94,500

Total Direct Materials cost variance = Actual Direct Materials Cost - Standard Direct Materials Cost

= $92,019 - $94,500

= -$2,481

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\(~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$3000\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ t=years\dotfill &2 \end{cases} \\\\\\ A = 3000e^{0.06\cdot 2} \implies A \approx 3382.49~\hfill \underset{interest~only}{\stackrel{3382.49~~ - ~~3000}{\approx\text{\LARGE 382.49}}}\)

First make the graph of the functions, then  if the two graphs are symmetric with respect to the line y = x (mirror images over y = x ), then they are inverse functions.

Symmetric

A figure or shape that can be divided into two equal parts by a line is called symmetric figures.

Inverse Functions

The inverse function of a function f  is a function that undoes the operation of f. The inverse of f exists if and only if f is bijective, and if it exists, is denoted by F^-1.

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The slope of the line in the given diagram is 3

From the question, we are to determine the slope of the line in the diagram.

Given a line with points (x₁, y₁) and (x₂, y₂), the slope of the line is given by

Slope = (y₂ - y₁) / (x₂ - x₁)

From the given diagram, the points on the line are (2, 4) and (5, 13)

Thus,

The slope of the line is

Slope = (13 - 4) / (5 - 2)

Slope = 9 / 3

Slope = 3

Hence, the slope is 3

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Answer:

exponential function

Step-by-step explanation:

geometric sequence

An = A1 * r^(n-1)

common ratio is 2

A1 = 1st term

nagwa

mthway

Answer:

Step-by-step explanation:

ANSWER:

Yes, it is linear, let's go with an example because we say this.

EXPLANATION:

Example:

As we can see, doubling the value of a number and dividing it by itself maintains the same pattern; that is, the increase is proportional.

We graph the previous proportions, a straight line is formed that is constant as we double the value and divide it on itself.

Answer:

25%

Step-by-step explanation:

First, locate the coordinate points given and join them.

Then, do the translation:

(x,y) = (x-9,y )

C' = (1-9 , 6 ) = (-8,6)

A'= (1-9,1) = (-8,1)

T'= (7-9 , 1 ) = ( -2,1)

Graph:

Finally reflect in x axis

(x,y )----> (x,-y)

C'' = (-8,-6)

A''= (-8,-1)

T''= (-2,-1)

Graph:

The probability that less than half of the sample will say that they support the increase is given as follows:

0.0885 = 8.85%.

The z-score of a measure X of a variable that has mean symbolized by \(\mu\) and standard deviation symbolized by \(\sigma\) is obtained by the rule presented as follows:

\(Z = \frac{X - \mu}{\sigma}\)

The parameters for this problem are given as follows:

n = 500, p = 0.53.

Hence the mean and the standard error are given as follows:

Hence the probability of less than half is the p-value of Z when X = 0.5, hence:

\(Z = \frac{X - \mu}{\sigma}\)

By the Central Limit Theorem

\(Z = \frac{X - \mu}{s}\)

Z = (0.5 - 0.53)/0.0223

Z = -1.35

Z = -1.35 has a p-value of 0.0885.

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A finite group is a group that has a finite number of elements. Now, let us define the center of a group. The center of a group, denoted by Z(G), is the set of all elements in G that commute with every element in G.

Now, we need to prove that if g is a finite group, the index of Z(g) cannot be prime. We can prove this using contradiction. Suppose the index of Z(g) is prime. Let this prime be denoted by p. This means that the number of distinct left cosets of Z(g) in g is p. Therefore, we can write:

|g/Z(g)| = p

where |g/Z(g)| represents the number of distinct left cosets of Z(g) in g.

Now, we can use the fact that the number of left cosets of a subgroup in a group is equal to the index of that subgroup in the group. Therefore, we can rewrite the above equation as:

|g|/|Z(g)| = p

Multiplying both sides by |Z(g)|, we get:

|g| = p|Z(g)|

Since p is a prime number, it can only be divided by 1 and itself. Therefore, the only possible divisors of p|Z(g)| are 1, p, and |Z(g)|.

Now, since |g| is finite, we know that |Z(g)| cannot be infinite. Therefore, the only possible values for |Z(g)| are positive integers that divide |g|. However, since p is a prime number, |Z(g)| cannot be equal to p. This means that the only possible values for |Z(g)| are 1 and |g|.

If |Z(g)| = 1, this means that Z(g) only contains the identity element. Therefore, g does not have any non-identity elements that commute with every other element in g. This is not possible since every group has at least one element that commutes with every other element in the group - the identity element.

If |Z(g)| = |g|, this means that every element in g commutes with every other element in g. This implies that g is an abelian group. However, this contradicts the fact that g is a finite group that is not abelian.

Therefore, we have reached a contradiction in both cases. This means that our assumption that the index of Z(g) is prime is false. Therefore, if g is a finite group, the index of Z(g) cannot be prime.

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The day when the sun is highest in the sky varies depending on the location within the United States. However, generally speaking, the highest point of the sun is reached on the summer solstice, which falls around June 20-21 each year.

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angles FGH and FHG

Step-by-step explanation:

Since this is a triangle, and the question states that FH=FG, you know that the triangle is an isosceles triangle. If you use an isosceles triangle, you know that the bottom two angles are the same degrees. Since the F is the same for both lines, you can determine that F is the top point of the triangle. As such, is you draw the triangle out, you will find the answer is  angles FGH and FHG

The perimeter of the regular pentagon is approximately 17.64 feet.

The area of the regular pentagon is approximately 5.708 square feet.

We have,

To find the perimeter and area of a regular polygon with 5 sides and a radius of 3 ft, we can use the formulas for regular polygons.

The perimeter of a regular polygon:

The perimeter (P) of a regular polygon is given by the formula P = ns, where n is the number of sides and s is the length of each side.

In a regular polygon, all sides have the same length.

To find the length of each side, we can use the formula for the apothem (a), which is the distance from the center of the polygon to the midpoint of any side. The apothem can be calculated as:

a = r cos (180° / n), where r is the radius and n is the number of sides.

Substituting the given values:

a = 3 ft x cos(180° / 5)

Using the cosine of 36 degrees (180° / 5 = 36°):

a ≈ 3 ft x cos(36°)

a ≈ 3 ft x 0.809

a ≈ 2.427 ft

Since a regular polygon with 5 sides is a pentagon, the perimeter can be calculated as:

P = 5s

However, we still need to find the length of each side (s).

To find s, we can use the formula s = 2 x a x tan(180° / n), where a is the apothem and n is the number of sides.

Substituting the values:

s = 2 x 2.427 ft x tan(180° / 5)

s ≈ 2 x 2.427 ft x 0.726

s ≈ 3.528 ft

Now we can calculate the perimeter:

P = 5s

P ≈ 5 x 3.528 ft

P ≈ 17.64 ft

Area of a regular polygon:

The area (A) of a regular polygon is given by the formula

A = (1/2)  x n x  s x a, where n is the number of sides, s is the length of each side, and a is the apothem.

Substituting the values:

A = (1/2) x 5 x 3.528 ft x 2.427 ft

A ≈ 5.708 ft²

Therefore,

The perimeter of the regular pentagon is approximately 17.64 feet.

The area of the regular pentagon is approximately 5.708 square feet.

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Hello!

\(\large\boxed{2x + y = 3}\)

Begin by finding the slope that would be perpendicular to the given equation.

A perpendicular line has a slope that is the opposite reciprocal of the original. Therefore:

1/2 --> -2

Find the answer choice that contains a slope of -2 when rewritten in the form y = mx + b:

Choice 1:

x + 2y = 2

Move x to the other side:

2y = -x + 2

Divide both sides by 2:

y = -1/2x + 1. This choice is incorrect.

Choice 2:

x - 2y = -12

Move x to the other side:

-2y = -x - 12

Divide both sides by -2:

y = 1/2x + 6. This choice is incorrect.

Choice 3:

2x + y = 3

Move 2x to the other side:

y = -2x + 3. This contains a slope of -2, which is correct.

Choice 4:

y - 2x = -5

Move -2x to the opposite side:

y = 2x - 5. This contains a slope of positive 2, so it is incorrect.

The correct answer is 2x + y = 3.

Answer:

D. y-2x=-5

Step-by-step explanation:

For given polynomial 1/2a^4 + 3a³ + a

1) There is no coefficient for the third term.

2) The constant term is 0.

In this question, we have been given a polynomial 1/2a^4 + 3a³ + a

We need to determine the coefficient of the third term and the constant term.

we can rewrite given polynomial as 1/2a^4 + 3a³ + 0a² + a + 0

The general form of the fourth degree polynomial is:

a_0 + a_1x + a_2x^2 + a_3x^3 + a_4x^4

where a_0 is the constant term

Comparing given polynomial with above general form.

a_0 = 0

a_1 = 1

a_2 = 0

a_3 = 3

a_4 = 1/2

So, the constant term is a_ 0 = 0

And there is no coefficient for the third term.

Therefore, for given polynomial 1/2a^4 + 3a³ + a

1) There is no coefficient for the third term.

2) The constant term is 0.

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Answer:

y = 22 2/3

x = 20

Step-by-step explanation:

y = 0, 4, 8, 12, 16, 20, 24

x = 3, 6, 9, 12, 15, 18, 21

Answer:

six times the subtraction of 5 from 7

To answer the questions about group G with order 77: (1) Show that there are normal subgroups H and K of the group with order 7 and 11, respectively.

Since the order of G is 77, by the Sylow theorems, there exist Sylow 7-subgroups and Sylow 11-subgroups in G.

Let H be a Sylow 7-subgroup of G and K be a Sylow 11-subgroup of G. Since Sylow subgroups are conjugate to each other, H and K are both normal subgroups of G.

(2) Show that HK={hk|h∈H, k∈K} is an Abelian subgroup of group G.

Since H and K are normal subgroups of G, we have that HK is a subgroup of G. To show that HK is an Abelian subgroup, we need to prove that for any elements hk and h'k' in HK, their product is commutative.

Let hk and h'k' be arbitrary elements in HK. Since H and K are normal subgroups, we have that h'khk' = kh'h. Thus, the product hk h'k' is equal to kh'h, which implies that HK is an Abelian subgroup.

(3) Show that HK=G.

To show that HK=G, we need to prove that every element g in G can be expressed as a product hk, where h∈H and k∈K.

Since H and K are normal subgroups of G, their intersection H∩K is also a normal subgroup of G. By Lagrange's theorem, the order of H∩K divides both the order of H (which is 7) and the order of K (which is 11). Since 7 and 11 are coprime, the only possible order for the intersection is 1.

Thus, H∩K={e}, where e is the identity element of G. This implies that every element g in G can be uniquely expressed as g = hk, where h∈H and k∈K. Therefore, HK=G.

(4) Show that G is a cyclic group.

Since HK=G, and HK is an Abelian subgroup, we have that G is an Abelian group. Every Abelian group of prime order is cyclic. Since the order of G is 77, which is not prime, G cannot be cyclic.

Therefore, G is not a cyclic group.

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To answer the questions about group G with order 77: (1) Show that there are normal subgroups H and K of the group with order 7 and 11, respectively.

Since the order of G is 77, by the Sylow theorems, there exist Sylow 7-subgroups and Sylow 11-subgroups in G.

Let H be a Sylow 7-subgroup of G and K be a Sylow 11-subgroup of G. Since Sylow subgroups are conjugate to each other, H and K are both normal subgroups of G.

(2) Show that HK={hk|h∈H, k∈K} is an Abelian subgroup of group G.

Since H and K are normal subgroups of G, we have that HK is a subgroup of G. To show that HK is an Abelian subgroup, we need to prove that for any elements hk and h'k' in HK, their product is commutative.

Let hk and h'k' be arbitrary elements in HK. Since H and K are normal subgroups, we have that h'khk' = kh'h. Thus, the product hk h'k' is equal to kh'h, which implies that HK is an Abelian subgroup.

(3) Show that HK=G.

To show that HK=G, we need to prove that every element g in G can be expressed as a product hk, where h∈H and k∈K.

Since H and K are normal subgroups of G, their intersection H∩K is also a normal subgroup of G. By Lagrange's theorem, the order of H∩K divides both the order of H (which is 7) and the order of K (which is 11). Since 7 and 11 are coprime, the only possible order for the intersection is 1.

Thus, H∩K={e}, where e is the identity element of G. This implies that every element g in G can be uniquely expressed as g = hk, where h∈H and k∈K. Therefore, HK=G.

(4) Show that G is a cyclic group.

Since HK=G, and HK is an Abelian subgroup, we have that G is an Abelian group. Every Abelian group of prime order is cyclic. Since the order of G is 77, which is not prime, G cannot be cyclic.

Therefore, G is not a cyclic group.

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Answer:

(p - 5)(p + 1)

Step-by-step explanation:

Given

p² - 4p - 5

Consider the factors of the constant term (- 5) which sum to give the coefficient of the x- term (- 4)

The factors are - 5 and + 1 , since

- 5 × + 1 = - 5 and - 5 + 1 = - 4, then

p² - 4p - 5 = (p - 5)(p + 1) ← in factored form

The standard form of a trinomial is

ax² + bx + c ( a ≠ 0 )

p² - 4p - 5 ← is in standard form

with a = 1, b = - 4 and c = - 5

Step-by-step explanation:

check the pic. I just sent

the answer is $1500

The originally invested price will be;

⇒ $1,500

A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

Given that;

Money is invested in a saving account at 12% simple interest.

And, After  one year there is $1680 in the account.

Now,

Let the original invested amount = x

So, We can formulate;

⇒ x + 12% of x = 1680

⇒ x + 12x/100 = 1680

⇒ 112x = 1680 × 100

⇒ 112x = 1,68,000

⇒ x = 1,68,000/112

⇒ x = $1,500

Thus, The original invested amount = $1,500

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Answer:

Therefore, The Boat is Approaching the Dock at a Rate of 2ft/sec When the point of attachment is:  14ft from the dock.

Make a plan:

Let  X be the Distance between the Boat and the Dock

Y  be the Length of the Rope

We will use the Pythagorean Theorem to relate X  and Y

Then Differentiate with respect to Time to find the Rate at which the Boat is Approaching the Dock.

1 - Write the Pythagorean Theorem equation:

X^2  + 1^2 = Y^2

2 - Differentiate Both Sides with respect to Time (t):

2x dx/dt  =  2y dy/dt

3 - Given dy/dt  =  -2ft/sec, and  y = 14ft

Solve for,  dx/dt, When  X = 14ft

2(14)dx/dt  =  2(14)( -2 )

4 - Solve For:

dx/dt

dx/dt  =  -2ft/sec

Draw the conclusion:

Therefore, The Boat is Approaching the Dock at a Rate of 2ft/sec When the point of attachment is:  14ft from the dock.

I hope this helps you!

Answer:

y = \(\frac{1}{3}\) x

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here slope m = \(\frac{1}{3}\) , then

y = \(\frac{1}{3}\) x + c ← is the partial equation

to find c substitute (- 9, - 3) , that is x = - 9, y = - 3 into the partial equation

- 3 = \(\frac{1}{3}\) (- 9) + c = - 3 + c ( add 3 to both sides )

0 = c

y = \(\frac{1}{3}\) x + 0 , that is

y = \(\frac{1}{3}\) x

Answer:

24

Step-by-step explanation:

8= 8, 16 ,24 , 32 , 40, 48, 56, 64, 72, 80

6= 6, 12, 18, 24, 30, 36, 42, 48, 54, 50

Answer:

Step-by-step explanation:

Yo come let's talk

then

Answer:

I think its 6

im not 100%sure

Step-by-step explanation:im in 7th grade tho

But can i get brainless

Answer:

6

Step-by-step explanation:

Have a good day :)

Answer:

$ 2.167

Let the cost of a pencil be x and that of a pen be y.

A pen costs twice as much as a pencil.

==> cost of a pen = 2 × cost of a pencil

==> y = 2x

Their total cost is $6.50

==> x + y = $6.50

since y = 2x, substituting y for 2x

==> x + 2x = 6.50

==> 3x = 6.50

dividing both sides by 3

==> x = 2.16

As per our assumption, x is the cost of one pencil.

Therefore, the cost of a pencil is $2.167