Please help I’ll give you the BRAINLIEST!

1. How many moles are in 3.63 x 10^22 atoms of K?

2. How many moles are in 5.96g of BaCO3?

3. How many moles are in 1.50 grams of NH3?

4. How many liters are in 82.0g CSI?

Answer:

the molar mass of the gas is approximately 0.956 g/mol

Complete of row:

A mole is a unit of account for chemistry. The unit of account is used to facilitate the calculation of an object.

One mole of any substance will have the same number of particles, which is equal to 6.02 × 10²³ particles." For example, 1 mole of air contains 6.02 × 10²³ molecules of H₂O. 1 mole of oxygen gas contains 6.02 × 10²³ molecules of O.

The mole scale is needed as an indication of the amount of substance or compound, mole is the gram of substance divided by the relative molecular mass (Mr). The formula for calculating the moles of a compound is n = gram/Mr, in this case, n is the moles of the substance and gr is the mass of the substance.

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At equilibrium, the HI concentration is 2.92 mol/L.

For the process H2(g)+CO2(g)updownarrow H2O+CO. at 1660 °C, the equilibrium constant KP is 4. In a 5 liter flask, 0.8 moles each of H2 and CO2 are first injected. Reactions occur in the following order with relation to H2: 1. In experiments 1 and 2, the reaction rate doubles when the initial concentration of H2 is doubled while the initial concentration of Cl2 is held constant.

H2(g) + I2(g) ⇌ 2HI(g)

c = [HI]² / [H2][I2]

At the specified temperature, c = 53.3, hence the following can be written:

53.3 = [HI]^2 / (0.400 mol/L) × (0.400 mol/L)

or, [HI]² = 53.3 × 0.16

or, [HI]² = 8.528

or, [HI] = sqrt(8.528) mol/L

or, [HI] = 2.92 mol/L

As a result, 2.92 mol/L of HI are present at equilibrium.

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The answer for all natural hazards statements are 1. True, 2. Ture, 3. True, 4. True, 5. True, 6. True, 7. False.

Natural hazards are natural phenomena that can potentially cause harm or damage to humans, property, or the environment. These hazards are events that are caused by natural processes, such as geological, meteorological, hydrological, or biological processes. Natural hazards can range from relatively minor events, such as a small earthquake or a local flood, to catastrophic events, such as a volcanic eruption, a major earthquake, or a tsunami.

This statement is true. Natural hazards, such as earthquakes, hurricanes, floods, and wildfires, can cause a wide range of negative impacts on people and communities, including disruptions to daily life, damage to property, economic loss, and injury to people.

This statement is true. Natural hazards vary in their severity because they can occur in a range of magnitudes, from mild to extreme. The severity of a natural hazard event depends on various factors, such as the strength and duration of the event, the location and vulnerability of the affected population, and the preparedness and response capacity of the community.

This statement is true. Many natural hazards, such as earthquakes, hurricanes, and tornadoes, cause damage to property by exerting unbalanced forces on objects. These forces can cause objects to accelerate suddenly and then decelerate suddenly when they collide into objects that are at rest or that are moving in a different direction.

This statement is true. Studying the most intense and impactful natural hazard events of the past can help scientists and communities better understand the possible intensity and damages of future hazards. This information can be used to improve preparedness, response, and recovery efforts.

This statement is true. Examining the historical record of natural hazard events can help scientists and communities predict how likely it is that a similar event will occur in the future. This information can be used to assess risk and inform decision-making.

This statement is true. Patterns in the locations, frequency, and intensity of past natural hazard events can help scientists and communities forecast future events. For example, if a certain area has experienced frequent earthquakes in the past, it is more likely to experience earthquakes in the future.

This statement is false. While records of past events can provide valuable information for predicting future hazards, scientists do not assume that the conditions that created those hazards in the past will remain the same in the future. They consider a wide range of factors, such as changes in climate, land use, and population density, that may affect the occurrence and impact of natural hazards.

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Answer:

Ebenezer Scrooge's business is to take care of his own establishment and thus, refused to donate/ contribute any to the charity.

He feels this way because he thinks that it is not one's business to interfere in another's business.

Explanation:

Charles Dickens's play "A Christmas Carol," tells the story of the protagonist Ebenezer Scrooge and his 'hatred' of the Christmas festival. But it was during this time of the year that he got 'inspired' by the ghost of his late partner c um friend Marley, teaching him a life lesson that changed Scrooge for the better.

When the two gentlemen came to visit the workplace of Scrooge expecting some donation for charity, Scrooge refused to give a single penny. According to him, the suffering of the people and their need is none of his business. He exclaims "I don’t make merry myself at Christmas and I can’t afford to make idle people merry. I help to support the establishments I have mentioned—they cost enough; and those who are badly off must go there." Rather, his business is to take care of his company, which "occupies [him] constantly" and thus, it's not his business to "not to interfere with other people’s".

he felt this way because he thinks that it is "unfair" and unbecoming to get involved in someone's business.

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer: a

. dissolving it in water

Explanation:

When the unknown material is dissolved in water, it could react with the water particles and end up producing another material. For instance an alkali metal in water could form metal oxides.

Heating the material until it melts will not change it into another material because it will still be the same material only now it will be in liquid form. The same logic applies if it is burnt in a flame.

Answer:

See explaination

Explanation:

1. The addition of group 3A elements to group 4A semiconductors decreases the conductivity of the group 4A semiconductors: Wrong

The addition of 3A group elements inreases the conductivity and make them extrinsic semiconductors( p-type)

2. The conductivity of semiconductors can be increased by the doping process.: Correct

3.As the temperature increases, the conductivity of semiconductors decreases.. wrong

As the temperature increases, the conductivity of semiconductors increases.

4. The addition of group 5A elements to group 4A semiconductors increases the conductivity of the group 4A semiconductors: Correct : They will create n-type semicoductor.

5.Holes are charge carriers in p-type semiconductors: Correct

6. Electrons are charge carriers in n-type semiconductors: Correct

The molarity of a solution that contains 0.75 mol of KCI in 0.250L of the solution is 3 M

The number of moles per liter of solution is termed molarity.

M=n/V(in L)

M is the molarity

n is the number of moles

V is the volume

Substituting the values, we get

M=0.75/0.25=3

The molarity is 3 M

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When the conductivity is at a minimum, the true thing about the amount of Ba(OH)₂ is that the amount of the two reactants are the same when conductivity is low.

The ability of an aqueous solution to carry an electric current is measured by its conductivity. Ionic strength is measured by conductivity monitors. In automated chromatography systems, conductivity is the main input control parameter used to enable the generation of salt gradients or to control buffer dilution or in-line buffer preparation.

Conductivity monitors can be used to automate and monitor cleaning and equilibration procedures. It's important to remember that temperature affects measurements of conductivity and pH.

When conductivity is low, the amounts of the two reactants are equal. Between the reactants, there are no excesses. The aqueous solution cannot dissolve the precipitate BaSO₄. Since there are no ions, the conductivity is at its lowest.

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Complete question

The Ba(OH)₂ dissociates as Ba+2 + 2 OH-. H₂SO₄ dissociates as 2 H+ + SO₄-2. When the conductivity is at a minimum, what must be true about the amount of Ba(OH)₂ compared to H₂SO₄

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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The solution with correct concentration is -- 4 m: One kilogram of water contains 4 moles of H₂SO₄ (molality )

In chemistry, the abundance of a component divided by the total volume of a mixture is what is meant by the term "concentration." Quantitative descriptions can be broken down into four categories: concentrations of mass, molarity, number, and volume are all measured in these units.

The term "concentration" can be used to describe any combination of chemicals, but solutes and solvents in solutions are the most common examples. There are two types of molar concentration, also known as quantity: osmotic concentration and the standard concentration.

The "total moles of a solute contained in a kilogram of a solvent" is how molality is measured. Molal concentration is another name for molality. It is a measurement of how much solute is in a solution.

Incomplete question :

Match the solution with the correct concentration.

4 m:

4 M:

4 Molal:

4 Molar

1. 4 moles of H₂SO₄ are placed into 1 Liter of water

2. 4 moles of H₂SO₄ are placed into 1 kg of water

3.  a solution concentration where 4 moles of solute are dissolved in 1 kg of solvent

4. a solution concentration where 4 moles of solute are dissolved in 1 Liter of solvent

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Answer:

The granite block transferred 4080 joules of energy, and the mass of the water is 35.84 grams.

Explanation:

The equation needed to answer both parts of the question is:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

Part #1:

First, you need to find the energy transferred from granite block using the previous equation. You have been given the mass, specific heat, and change in temperature.

Q = ? J                            c = 0.795 J/g°C

m = 126.1 g                     ΔT = 92.6 °C - 51.9 °C = 40.7 °C

Q = mcΔT

Q = (126.1 g)(0.795 J/g°C)(40.7 )

Q = 4080

Part #2:

Secondly, using the energy calculated in Part #1, you need to calculate the mass of the water. You have calculated the energy transferred, and have been given the specific heat and change in temperature.

Q = 4080 J                     c = 4.186 J/g°C

m = ? g                            ΔT = 51.9 °C - 24.7 °C = 27.2 °C

Q = mcΔT

4080 J = m(4.186 J/g°C)(27.2 °C)

4080 J = m(113.8592)

35.84 = m

Answer: blank 1: 4,080 joules

Blank 2: 35.8 grams

Explanation:

The pH of the solution made by mixing 15.0cm³ 0.1M NaOH and 35.0 cm³ 0.2 M HCOOH would be 2.39.

The first step in solving this problem is to write the balanced chemical equation for the reaction between NaOH and HCOOH:

NaOH + HCOOH → NaCOOH + H2O

Next, we need to calculate the moles of each reactant:

moles NaOH = 0.1 mol/L x 0.015 L = 0.0015 moles

moles HCOOH = 0.2 mol/L x 0.035 L = 0.007 moles

Since NaOH and HCOOH react in a 1:1 stoichiometry, we know that 0.0015 moles of NaOH reacts with 0.0015 moles of HCOOH. This leaves 0.007 - 0.0015 = 0.0055 moles of HCOOH unreacted.

Now, we need to use the equilibrium constant (Ka) for the reaction between HCOOH and water to determine the concentration of H+ ions in the solution:

HCOOH + H2O ⇌ H3O+ + HCOO-

Ka = [H3O+][HCOO-]/[HCOOH]

We are given the value of Ka, so we can use it to find the concentration of H+ ions:

Ka = 1.82 × 10^-4 M

[H3O+] = [HCOO-] = x (let's assume that the initial concentration of HCOOH is much larger than x, so we can assume that x is negligible compared to the initial concentration of HCOOH)

[HCOOH] = 0.0055 moles / 0.05 L = 0.11 M

Ka = (x^2) / (0.11 - x)

Since x is negligible compared to the initial concentration of HCOOH, we can simplify the equation to:

Ka = (x^2) / 0.11

Solving for x, we get:

x = sqrt(Ka * [HCOOH]) = sqrt(1.82 x 10^-4 * 0.11) = 0.0041 M

Therefore, [H+] = 0.0041 M

Finally, we can use the definition of pH to calculate the pH of the solution:

pH = -log[H+] = -log(0.0041) = 2.39

Therefore, the pH of the solution is 2.39.

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Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

Answer:

F = 150 N

Explanation:

Given data:

Mass of bicycle = 15 kg

Acceleration = 10 m/s²

Force needed = ?

Solution:

Formula:

F = ma

F = force

m = mass

a = acceleration

now we will put the values in formula.

F = 15 Kg × 10 m/s²

F = 150 Kg.m/s²

      Kg.m/s² = N

F = 150 N

Answer:

apolar

Explanation:

it's the answer for this answer as I know not surley

Answer:

The percent by mass of carbon tetrachloride in the new solution is 72.6

Explanation:

Molecular weight of Carbon Tetrachloride is 154 g/mol

Molecular weight of CH3COOH is 60g/mol

Mass fraction of CCl4 is 0.5

Mass fraction of CCl4 is (0.5/154)/{(0.5/154) + (0.5/60)}

Mass fraction of CCl4 is X = 0.2803 and Y = 1-X

As per Raoul’s law

Y Pt = X * P1

Pt = X * P1 + YP2

Pt = 0.2803 * 1377 + (1-0.2803) * 519

Pt = 759.557 torr

Substituting the given values we get  

Y1 = X1P1/Pt

Y1 = 0.2803 * 1377/759.557

Y1 = 0.508

Mass fraction  

(0.508)(154)/{( (0.508)(154)) + (1-0.508)(60)}

= 0.726 = 72.6 %

The binding energy per nucleon for the ¹⁹F nucleon is equal to 7.786 MeV/nucleon.

Binding energy can be defined as the minimum quantity of energy that is required to remove the particle from the system. Nuclear binding energy can be described as the energy required to dismantle a nucleus of an atom into free neutrons and protons.

The binding energy will be determined from the mass defect. Mass defect is calculated from the difference between the mass observed and the expected combined mass.

Given the mass of the ¹⁹F = 18.9984 a.m.u.

The mass defect for the ¹⁹F can be calculated as:

Δm = \((M _n +M_p) - M_F\)

\(\triangle m =( 9\times 1.0078 + 10 \times 1.0087 )- 18.9984\)

\(\triangle m =0.1588 \;a.m.u.\)

The binding energy for the fluorine can be calculated as:

E = Δmc²

E = 0.1588 × 931.5

E = 147.92 MeV

The binding energy per nucleon of ¹⁹F can be calculated as:

B.E.N. = 147.92/18.9984 = 7.786 MeV per nucleon

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Since the heat of combustion of butane is higher than that of propane,  butane will produce more heat per gram when burned compared to propane.

The heat of combustion of a compound refers to the heat evolved when one mole of the compound is burnt under standard conditions. This heat of combustion increases from methane upwards.

Since the heat of combustion of alkanes increases according to increasing molar mass, butane will produce more heat per gram when burned compared to propane.

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The average density of three trials are 3.61 g/mL

It is given that

Density in first trial d1 = 3.5512 g/mL

Density in second trial d2 = 3.4188 g/mL

Density in first trial d3 = 3.8617 g/mL

We have to find average density

Density is a measurement that compares the amount of matter an object has to its volume. An object with much matter in a certain volume has high density. An object with little matter in the same amount of volume has a low density.

Average density = sum of all density/number of density

Average density = d1 + d2 + d3

3

Average density =

3.5512 + 3.4188 + 3.8617

3

= 3.61 g/mL

Hence, average density of three trials are 3.61 g/mL

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Answer:

less than 4.9 newtons Explanation:

The molarity of the NiSO₄ solution made by dissolving 38.81 grams of nickel (ii) sulfate, NiSO₄, in enough water to make 0.467 liters of solution is 0.535 M

First, we shall obtain the mole of 38.81 grams of nickel (ii) sulfate, NiSO₄. Details below:

Mole of NiSO₄ = mass / molar mass

= 38.81 / 154.75

= 0.25 mole

Now, we shall determine the molarity of the solution. Details below:

Molarity of solution = mole / volume

= 0.25 / 0.467

= 0.535 M

Thus, the molarity of the solution is 0.535 M

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The energy (in joules) of 1 mole of photons with this frequency is 1.99 x 10⁻¹⁴ J per photon.

Should a substance happen to have a lot of electrons in a higher level, and a lower level is mostly empty  then a photon can cause an electron to transfer from a higher state to a lower one. This change releases energy and creates a new photon, in addition to the one which caused the transfer. This photon can in turn induce more electrons to fall to a lower state.

use formula

The energy of 1 mole of photons with the given frequency can be calculated using the following equation:

Energy (J) = Avogadro's number x Plank's Constant x Frequency

Therefore,

Energy (J) = 6.02 x 10²³ x 6.626 x 10⁻³⁴ x 5.40 x 10⁴

Energy (J) = 1.99 x 10⁻¹⁴ J

Therefore, the energy of 1 mole of photons with a frequency of 5.40 x 10⁴ Hz is 1.99 x 10⁻¹⁴ J, expressed in scientific notation.

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Answer:

In a lab, a student mixes 25.0 ml of 0.115 M aluminum sulfate with 34.0 ml of 0.0975 M Lead (III) nitrate. Calculate the grams of the precipitate that is formed.

Explanation:

4.29 g, or % of the reaction's yield. Yield in synthesis reaction percent: 85%. Explanation: C2H5OH+3O22CO2+3H2O is the balanced equation.

Multiply the molal mass of water by the number of moles. 2 + 16 = 18 g/mol is the molar mass. This yields 0.834 moles H2O x 18 g/mol when multiplied by the end result. 15 grams of water equal one gram of H2. For this experiment, 15 grams of water should be produced theoretically.

The percentage and theoretical yield are multiplied together to arrive at the simple calculation for actual yield.

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An ionic compound is one that dissolves in water to produce a solution with a pH of 11, has a high melting point, conducts electricity when molten, and burns in oxygen.

Positively charged ions, which are sometimes called as cations, and negatively charged ions, also called as anions together constitute an ionic compound, which are neutral substances. The name of the cation is written first, followed by the name of the anion, in case of binary ionic compounds (ionic compounds that only contain two types of elements).

An atom can establish bonds with other atoms in two main ways: covalent and ionic. Sharing of electrons between two or more atoms is involved in case of covalent bonding. When two or more ions come together, they can form ionic bonds that are held together by charge differences.

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Atom B would form an ion that has a charge that can be designated as + 2.

An ion is an atom or molecule that has gained or lost one or more electrons, resulting in a net electric charge. Atoms typically have an equal number of electrons and protons, which gives them a neutral charge.

We can see that atom B belongs to group 2 of the periodic table and that the atoms that we find in this group are able to loose two electrons and thus they would form an ion that has a charge of + 2.

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Two substituents are taken out of the reactant molecule in an elimination reaction to create the product.

In a one- or two-step method, two substituents are eliminated from a molecule in an organic reaction known as an elimination reaction. Atoms are eliminated as molecules and compounds during an elimination reaction. Two substituents are taken out of the reactant molecule in an elimination reaction to create the product. A metal, an acid, or a base typically catalyze elimination. E1 and E2 reactions are the two primary categories of elimination processes in organic chemistry. Both E1 and E2 processes are also known as alcohol elimination reactions and alkyl halide elimination reactions, respectively. Any organic chemical reaction known as an elimination reaction in which two atoms and groups of atoms are eliminated.

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