please help me ASAP!!!

The y-intercept of the linear function means that her initial distance from the finish line is of 10 kilometers.

The slope-intercept equation for a linear function is presented as follows:

y = mx + b

In which:

The graph crosses the y-axis at y = 10, hence the intercept b is given as follows:

b = 10.

The y-values represent the distance in the context of this problem, hence the initial distance is of 10 km.

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Answer:

606.6 and 233.3 respectively

Step-by-step explanation:

Let the speed of plane in still air be x and the speed of wind be y.

ATQ, (x+y)*9=7560 and (x-y)*9=3360. Solving it, we get x=606.6 and y=233.3

Answer:

\(h = \frac{V}{\pi r^{2}}\)

h = 4 cm

Step-by-step explanation:

Given the formula for the volume (V) of a cylinder: V = πr ²h, and the following values for volume and radius:

V = 36π cm³

r = 3 cm

First, solve for h:

V = πr ²h

Divide both sides by πr ²:

\(\frac{V}{\pi r^{2} } = \frac{\pi r^{2}h}{\pi r^{2} }\)

\(h = \frac{V}{\pi r^{2}}\)

Next, solve for the height of the cylinder by substituting the given values for volume and radius into the formula:

\(h = \frac{V}{\pi r^{2}}\)

\(h = \frac{36\pi }{\pi (3^{2})}\) → π cancels out.

\(h = \frac{36}{9}\)

h = 4 cm

Answer:

The original price for 80% off of 96 is $480.

Answer: x=3\(\sqrt{2\). y=3\(\sqrt{2\)

Step-by-step explanation: This is a 45-45-90 triangle. Both of the legs, x and y, are congruent. To find the length of the legs, divide 6, the hypotenuse, by \(\sqrt{2\). 6/\(\sqrt{2\)=3\(\sqrt{2\).

Answer:

The next two numbers following:

431

141311

1114111321

311431131211

are:

132114132113111221

AND

11131221141113122113312211

Step-by-step explanation:

I shall explain the pattern below:

431 (just the digits 4, 3, and 1)

141311 (one 4 becomes 14, one 3 becomes 13, one 1 becomes 11 -> looking at each digit of the previous number, 431)

1114111321 (one 1 becomes 11, one 4 becomes 14, one 1 becomes 11, one three becomes 13, two consecutive 1s becomes 21 -> looking at each digit of the previous number, 141311)

311431131211 (three consecutive 1s becomes 31, one 4 becomes 14, 3 more consecutive 1s becomes 31, one 3 becomes 13, one 2 becomes 12, and one 1 becomes 11 -> looking at each digit of the previous number, 1114111321)

NEXT TWO NUMBERS:

one 3 (13), two consecutive 1s (21), one 4 (14), one 3 (13), two consecutive 1s (21), one 3 (13), one 1 (11), one 2 (12), two consecutive 1s (21)

that makes: 132114132113111221

one 1 (11), one 3 (13), one 2 (12), two consecutive 1s (21), one 4 (14), one 1 (11), one 3 (13), one 2 (12), two consecutive 1s (21), one 3 (13), three consecutive 1s (31), two consecutive 2s (22), one 1 (11)

that makes: 11131221141113122113312211

The rule is that the next number is essentially the previous number with the number of times each digit appears consecutively before each digit of the previous number. I know that sounds convoluted. Hopefully it makes enough sense. Let me know if I should explain more fully.

1. 0.625

2. 0.22222222222

3. 0.43243243243

4. -0.11111

5. 0.54

6. -0.75

22. −2 21/50

23. -4/25

24. -13/20

25. 0.62

26. 7/15

Answer:

Step-by-step explanation:

the dot would either (1,4) or (4,1)

a squared+ b squared= c squared

the length of the sides are 3

3 squared + 3 squared= c squared

9+9 =c squared

18= c squared

square root of 18 rounded to the nearest tenth is 4.2

Answer:

q=8/3

Step-by-step explanation:

First, add 5/6 to both sides to get rid of -5/6 to get q=16/6 then simplify to q=8/3.

Answer:

\(q=2\frac{2}{3}\)

Step-by-step explanation:

The given equation consists of a fraction and a mixed number.

First, convert the mixed number into an improper fraction by multiplying the whole number by the denominator of the fraction, adding this to the numerator of the fraction, and placing the answer over the denominator:

\(q-\dfrac{5}{6}=1 \frac{5}{6}\)

\(q-\dfrac{5}{6}=\dfrac{1 \cdot 6+5}{6}\)

\(q-\dfrac{5}{6}=\dfrac{11}{6}\)

Now, add 5/6 to both sides of the equation to isolate q:

\(q-\dfrac{5}{6}+\dfrac{5}{6}=\dfrac{11}{6}+\dfrac{5}{6}\)

\(q=\dfrac{11}{6}+\dfrac{5}{6}\)

As the fractions have the same denominator, we can carry out the addition by simply adding the numerators:

\(q=\dfrac{11+5}{6}\)

\(q=\dfrac{16}{6}\)

Reduce the improper fraction to its simplest form by dividing the numerator and denominator by the greatest common factor (GCF).  

The GCF of 16 and 6 is 2, therefore:

\(q=\dfrac{16\div 2}{6 \div 2}\)

\(q=\dfrac{8}{3}\)

Finally, convert the improper fraction into a mixed number by dividing the numerator by the denominator:

\(q=2 \; \textsf{remainder}\;2\)

The mixed number answer is the whole number and the remainder divided by the denominator:

\(q=2\frac{2}{3}\)

Given:

Solve the equation for g,

Answer:

Answer:

No Solution

Step-by-step explanation:

if one side is 4, another side -8z and +8z cancels, left -7

4 ≠ -7

Answer:

statement is false

Step-by-step explanation:

See image below:)

the first derivative of the given function is:

f'(x) = (2x²- 12x - 2)/( 2x² - 2)²

The quotient rule says that, if f(x) = g(x)/h(x), then:

f'(x) = ( g'(x)*h(x) - g(x)*h'(x) )/h(x)²

In this case we know that:

g(x) = x² + x - 2

h(x) = 2x² - 2

The derivatives are:

g'(x) = 2x + 1

h'(x) = 4x

Replacing that we get:

f'(x) = ( g'(x)*h(x) - g(x)*h'(x) )/h(x)²

      = ( (2x + 1)*(2x² - 2) - ( x² + x - 2)*(4x) )/( 2x² - 2)²

Expanding the denominator we get:

f'(x) = ( 4x³ - 4x + 2x² - 2 - 4x³ + 4x² - 8x)/( 2x² - 2)²

f'(x) = (2x²- 12x - 2)/( 2x² - 2)²

That is the first derivative of the given function.

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Answer:1.2872686 x 10^10

Step-by-step explanation:

46 x 23^4 x 1000

46 x 23 x 23 x 23 x 23 x 1000

1.2872686 x 10^10

The number of revolutions made by the wheel is 5.24 ≅ 5.  

One complete revolution is equal to 360 degrees, so to find the number of complete revolutions the wheel has made, we can divide the total number of degrees rotated by 360.    

Here we have

A wheel rotated by 1888°  

As we know One complete revolution is equal to 360 degrees

Hence, the angle can be rotated by the wheel in 1 rotate = 360°  

Let the wheel make 'x' revolution to make 1888°  

=> 360(x) = 1888

=> x = 1888/360

=> x = 5.24

Therefore,

The number of revolutions made by the wheel is 5.24 ≅ 5.    

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I will put it in standard form,

5a + 2r = 12

It becomes

5a + 2r - 12 = 0

The conditional probability value rounded to 4 decimal places is : 0.2500

The relation can be used to find the conditional probability of events given :

P(HH | Atleast 1 head) = P(HHn(Atleast 1 H)) / P(Atleast 1 H)

P(Atleast 1 H) = P(HT + TH + HH)

P(Atleast 1 H) = P(HT + TH + HH) = 3(0.25) = 0.75

P(HHn(Atleast 1 H)) = P(HH) × P(Atleast 1 H) = 0.25 × 0.75 = 0.1875

Therefore, the conditional probability can be expressed as :

Therefore, P(HH | Atleast 1 head) is 0.25

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Answer:

Attached is an example of a circle with a radius of 5 and a diameter of 10.

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Have a GREAT day!!!

Answer:

\(\frac{6^2-3^2}{2} =\frac{27}{2}\)

(the third answer in your list of options)

Step-by-step explanation:

The area of the region between y = x, and the x axis, between x= 3 and x=6 is the area of the trapezoid shown in the attached image.

It therefore can be calculated via the area of a trapezoid:

\((B+b)\,H/2=(6+3)*3/2=27/2\)

or doing the integral (which it seems is what they want you to do):

\(\int\limits^6_3 {x} \, dx =\frac{x^2}{2} ]\limits^6_3=\frac{6^2-3^2}{2} =\frac{27}{2}\)

The amount of your tax refund is $1,414

To find the tax refund, we need to subtract the amount of federal taxes owed after deductions from the amount of federal taxes already paid.

Tax refund = Federal taxes paid - Federal taxes owed after deductions

Tax refund = $12,042 - $10,628

Tax refund = $1,414

Rounding to the nearest cent, the tax refund is $1,414.00.

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Answer:

9

Step-by-step explanation:

4 * 2 + 3 - 2 =

= 8 + 1 =

= 9

The fastest time in the obstacle course is 260 seconds.

In statistics, a quartile is a type of quantile that divides a data set into four equal parts, or quarters, each representing 25% of the dataset. The first quartile (Q1) marks the 25th percentile, the second quartile (Q2) marks the 50th percentile, and the third quartile (Q3) marks the 75th percentile. The difference between the third and first quartiles is called the interquartile range (IQR), which is used to measure the spread of the data.

Here,

According to the box plot.

The minimum value = 260 sec

The maximum value = 360 sec

The quartile = 300 sec and 340 sec

The median = 330 sec

The fastest time in the obstacle course = 260 sec

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Answer:

Just calculate

3×2×4 ÷ (2×5)

24÷10

=2.4

Answer:

4/5

Step-by-step explanation:

Step-by-step explanation:

This is a simple system of equations problem, with our equation being:

\(\frac{4}{7}x+9=x\)

We know this as her dogs (x) is equal to 4/7 of her dogs (x) plus 9. Now all we must do is solve for x:

\(\frac{4}{7}x+9=x\\\\\frac{4}{7}x=x-9\\\\\frac{4}{7}x=\frac{7}{7}x-9\\\\\frac{-3}{7}x=-9\\\\x=21\)

The linear functions that define their distances are given as follows:

The number of hours after noon in which they will be the same distance away from the stadium is of:

8 hours.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

In which the parameters are given as follows:

In the context of this problem, the meaning of each parameter is:

They will be the same distance away at the point of intersection of the graph given at the end of the answer, which is of 8 hours.

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Answer:

y= -33/32

Step-by-step explanation:

or, 2y/3-3/3=2y+5/8

or, 2y/3-2y=5/8+3/4

or, (2y-3*2y)/3=(5+3*2)/8

or, (2y-6y)/3 = (5+6)/8

or, (-4y)/3 = 11/8

or, 8*(-4y) = 11*3

or, -32y =33

or, -y =33/32

or, y= -33/32

The statistical analysis of the data using a two-sample t-test indicates;

(a) B. Yes, the Meters On data appears to have higher speeds

A. No, there does not appear to be any outlier

(b) H₀; \(\mu_{on}\) = \(\mu_{off}\)

H₁; \(\mu_{on}\) > \(\mu_{off}\)

The P-value for the test is about 0.037

A two-sample t-test is used to determine if there is a difference between the means of two independent groups of data.

(a) The average of the data values are;

Ramp meters on;

\(\mu_{on}\) = (29+47+55+38+32+25+42+47+51+36+55+41+43+25+47)/15 ≈ 40.87

\(\mu_{off}\) = (25+25+43+35+36+31+48+37+19+29+22+40+36+50+40)/15 ≈ 34.4

The higher average value for the speed with the Ramp meters on indicates;

B. Yes, the Meters On data appears to have higher speeds

The five number summary are;

Ramp Meters On

Min = 25, Max = 55, Q₁ = 32, Q₂ = 42, Q₃ = 47

IQR = 47 - 32 = 15

Outlier = 47 + 1.5 × 15 = 69.5

32 - 1.5 × 15 = 9.5

Therefore, there are no outliers for the Ramp Meters On

Ramp Meters Off

Min = 19, Max = 50, Q₁ = 25, Q₂ = 36, Q₃ = 40

IQR = 40 - 25 = 15

Outlier = 40 + 1.5 × 15 = 62.5

25 - 1.5 × 15 = 2.5

Therefore, there are no outliers for the Ramp Meters Off data

(b) The null hypothesis is; H₀; \(\mu_{on}\) = \(\mu_{off}\)

The alternative hypothesis is; H₁; \(\mu_{on}\) > \(\mu_{off}\)

(c) The two sample t-test, can be obtained using the formula;

\(t_{cal} = \frac{(\bar{x}_1 - \bar{x}_2)}{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2} ) } }\)

Where; \(\bar{x}_1\) = 40.87

\(\bar{x}_2\) = 34.40

s₁ = 9.91

s₂ = 9.20

n₁ = n₂ = 15

Therefore; \(t_{cal}\) = 1.8516. The degrees of 15 + 15 - 2 = 28, and the one-tailed hypothesis, indicates, using an online tool;

The p-value is less than 0.05, therefore, the result is significant.

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Answer:

$57

Since $71.25 was paid for working 7.5 hours.

That means he was being paid $9.5 per hour.

Which is 71.25÷7.5.

And on tuesday that's 9.5×6 which is $57