Please help me if u don’t I will get a bad grade‼️

4931870234e-238+9273.

Answer:

76$

Step-by-step explanation:

114=.6y; y= original price

y=190, original price

190-114=76

Answer

6/15, 4/6

Step-by-step explanation:

Answer:

The answer is A

Step-by-step explanation:

Add up

After considering the given data we conclude that the clockwise rotational path of the line segment is a rotation of -59.04 degrees about the point (-6, -1).

We have to evaluate the center and angle of rotation to explain the clockwise rotation of the line segment.

So in the first step, we can evaluate the midpoint of the line segment JK and the midpoint of the line segment J'K'. we can calculate the vector connecting the midpoint of JK to the midpoint of J'K'. This vector is (4-1, 1-(-4) = (3,5)

The center of rotation is the point that is equidistant from the midpoints of JK and J'K'. We can evaluate this point by finding the perpendicular bisector of the line segment connecting the midpoints.

The slope of this line is the negative reciprocal of the slope of the vector we just found, which is -3/5. We can apply the midpoint formula and the point-slope formula to evaluate the equation of the perpendicular bisector:

Midpoint of JK: (1, -4)

Midpoint of J'K': (4, 1)

The slope of the vector: 3/5

(x₁ + x₂)/2, (y₁ + y₂) /2

Point-slope formula: y - y₁ = m(x - x₁)

Perpendicular bisector: y - (-4) = (- 3/5)(x - 1)

Applying simplification , we get: y = (- 3/5)x - 1.2

To evaluate the center of rotation, we need to find the intersection point of the perpendicular bisector and the line passing through the midpoints of JK and J'K'. This line has slope ( 3 - (4)) /(4 - 1) = 7/3 and passes through the point (4, 1). Applying the point-slope formula, we can evaluate its equation:

y - 1 = (7/3)( x - 4)

Apply simplification , we get: y = (7/3)x - 17/3

To evaluate the intersection point, we can solve the system of equations:

y =(- 3/5)x - 1.2 = (7/3)x - 17/3

Evaluating for x and y, we get x = -6 and y = -1.

Therefore, the center of rotation is (-6, -1).

√( 4 - 1)² + ( 1 - ( - 4))²) = 5√(2)

Distance between image points and center of rotation

√( ( 6 - (-6))² + ( 3 - (-1))² = 13

The ratio of these distances gives us the scale factor of the transformation, which is 13/√2).

The angle of rotation is negative as the image moves clockwise direction. We can apply the inverse tangent function to find the angle of the vector connecting the midpoint of JK to the midpoint of J'K':

Angle of vector: arctan(5/3) = 59.04 degrees

Therefore, the clockwise rotational path of the line segment is a rotation of -59.04 degrees about the point (-6, -1).

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The central angle is approximately 2.357 radians.

To find the central angle, we can use the formula:

Central angle (θ) = arc length ÷ radius

Given:

Arc length (mXY) = 18 in

Radius (ZY) = 7.64 in

Plugging in the values:

Central angle (θ) = 18 in ÷ 7.64 in

Calculating the division:

θ ≈ 2.357 radians

Therefore, the central angle is approximately 2.357 radians.

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The investment growth is an illustration of an exponential function.

It will take 78.3 years for the investment to reach £29437.2

The given parameters are:

An exponential function is represented as:

\(y = a(1 + r)^t\)

Where:

So, we have:

\(y = 645.3(1.05)^t\)

When the investment becomes 29437.2, the equation becomes

\(29437.2 = 645.3(1.05)^t\)

Divide both sides by 645.3

\(45.6=1.05^t\)

Take the logarithm of both sides

\(\log(45.6)=\log(1.05)^t\)

This gives

\(\log(45.6)=t\log(1.05)\)

Make t the subject

\(t = \frac{\log(45.6)}{\log(1.05)}\)

\(t = 78.3\)

Hence, it will take 78.3 years for the investment to reach £29437.2

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Answer:

-8

Step-by-step explanation:

substitute

x=4

       into -3x+2(y-1):

x=3

-3x4+2x(3-1)

-12+2x(3-1)

-12+2x2

-12+4

= -8

Answer:

first question ans is 16 and second is 13

Step-by-step explanation:

Given

x=4 and y=3

3x+2(y-1)

3×4+2(3-1)

3×4+2×2

12+4

16Ans

Second question is

x+y×y

4+3×3

4+9

13 Ans

Answer:

Correct answer is B, 69.3 feet

Step-by-step explanation:

Since we have a 30°-60°-90° right triangle, the length of the longer leg is √3 times the length of the shorter leg, so the length of the shorter leg is 1/√3, or √3/3 times the length of the longer leg.

\(120( \frac{ \sqrt{3} }{3}) = 40 \sqrt{3} = 69.3\)

Answer:

Both of there acceleration was about the same.

I think the man had more frictional force because he was heavier than the boy

Step-by-step explanation:

Answer:

Answer:

Both of there acceleration was about the same.

I think the man had more frictional force because he was heavier than the boy

Step-by-step explanation:

Answer:

D. 12h + 6k

Step-by-step explanation:

in order to find the equivalent expression, you have to simplify it (at least in this case)

when simplifying the expression, you use the distributive property (multiplying 3 to both 4h AND 2k). 3(4h) = 12h, and 3(2k) = 6k, so it is 12h + 6k

The triangle's area is listed as: 70.50cm2.A shape's surface area is measured by its area.

A shape's surface area is measured by its area.By multiplying the length and breadth of a rectangle or square, you can get its area.Area A is equal to x times y.

Square measurements, such as square inches, square feet, or square meters, are used to describe area.Multiplying a rectangle's length and breadth will reveal its area.A is the area, L is the length, W is the width, and * denotes multiply in the formula.

Area of the darkened area is equal to the sector's area minus the triangle's area.This is displayed as:π r² (∅/360) - 1/2 x b x h

= π x 14² x (46/360) - (1/2) x 14 x 10.0708

= 78.6794 - 70.4956

= 8.1838 cm²

Consequently, the triangle's area is equal to (1/2) x 14 x 10.0708.

= 70.4956 cm²

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Answer:

it is b

Step-by-step explanation: hope help

Answer:

the equation: 2x+3+2x+3+2x= 36

x=5

the length of the congruent sides

15

the length of the third side

10

Step-by-step explanation:

i'll add this later hold on

Answer:

1 yard

Step-by-step explanation:

in a yard there is 36 inches

Answer:

\(\tex\huge\boxed{67}\)

Step-by-step explanation:

In order to solve this problem, we should set it up in an algebraic equation. Doing so will make it easier to make sense of the problem. To do this, we can represent each part of the statement with an expression.

For the purposes of this, let's call our unknown number \(n\).

Altogether, we get \(n+98=3n-36\). We can now solve for \(n\).

Therefore, the answer here is 67.

Hope this helped!

Answer:

True

Step-by-step explanation:

Answer:

(i) The name of the part of the circle, OQ is a radius

(ii) The radius of the sector QOR is 21 cm

Step-by-step explanation:

The given figure is a sector of the circle O

∵ Any sector of a circle formed from 2 radii and an arc

∴ OQ is a radius

(i) The name of the part of the circle, OQ is a radius

The rule of the length of an arc of a circle is L = \(\frac{\alpha }{360}\) × 2 π r, where

∵ The length of the arc QR is 22 cm

∴ L = 22

∵ The measure of the angle of the arc is 60°

∴ α = 60°

∵ π = \(\frac{22}{7}\)

→ Substitute them in the rule above

∵ 22 = \(\frac{60}{360}\) × 2 × \(\frac{22}{7}\) × r

∴ 22 = \(\frac{22}{21}\) r

→ Divide both sides by  \(\frac{22}{21}\)

∴ 21 = r

(ii) The radius of the sector QOR is 21 cm

Answer:

2×100= 200

1349×10=13490

A2+B2=C2

We are given that there are a total of 78 students. If we set the following variables:

Then, the sum of all of these must be 78, that is:

Since there are 15 in chemistry and physics and 47 in chemistry, we may replace that into the equation and we get:

Simplifying:

Now we solve for P by subtracting 62 on both sides:

Therefore, there are 16 students in physics

Answer:

It is, 6

Step-by-step explanation:

Good luck! Have a good day!! <33

Act like you have 2 fingers up and then add 4 more.

It is difficult to make a general statement about whether tennis coaches generally get paid more than football coaches in Jacksonville or elsewhere, as the salaries of coaches are influenced by a Wide range of factors

As an AI language model, I do not have access to up-to-date information about salaries of coaches in Jacksonville. However, in general, the salaries of coaches vary widely depending on a number of factors, such as the type of sport, the level of competition, the location, the success of the team, and the budget of the institution.

In terms of tennis and football, football is generally considered to be a more popular and high-profile sport than tennis in the United States, which could result in higher salaries for football coaches at the collegiate level. Football also typically generates more revenue and has larger budgets for athletic programs, which could also influence the salaries of coaches.

However, there are also factors that could affect the salaries of tennis coaches. For example, if a tennis program has a particularly successful season or has produced successful players, the coach may negotiate a higher salary. Additionally, some colleges may place a greater emphasis on tennis or have larger budgets for tennis programs, which could also impact the salaries of coaches.

Overall, it is difficult to make a general statement about whether tennis coaches generally get paid more than football coaches in Jacksonville or elsewhere, as the salaries of coaches are influenced by a wide range of factors. It is also important to note that salaries can vary widely between individual institutions, even within the same sport, and that negotiations between coaches and their institutions can play a significant role in determining salaries.

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Answer:

True

Step-by-step explanation:

If a is negative then the shape of the graph is an upside down U, which intersects the x-axis. If a is positive it will never cross the X axis.

It is true that f(x)=\(a^{x}\)+4 will never cross the x axis if a is positive.

Function is relationship between two or more that are variables expressed in equal to form. In a function each value of x must have a corresponding value of y.

We have been given that f(x)=\(a^{x} +4\) and we have to find whether it will cross x axis or not.

when a line crosses the x axis the value of y becomes negative. We have to first check at y=0.

\(a^{x}+4\)=0

\(a^{x}\)=-4

taking log both sides,

log \(a^{x}\)=log(-4)

x log a=0.602059991+1.3437635i

x=(0.602059991+1.3437635i)/log a

when we put the value of x in f(x) the value of f(x) cannot be negative so it cannot crosses the x axis.

Hence it is true that f(x)=\(a^{x}\)+4 will never cross the x axis if a is positive.

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Answer:

133 m^2

Step-by-step explanation:

to find are of a circle it’s r^2 times pi

6^2 x pi

36 pi

113 m^2

Hopes this helps please mark brainliest

Answer:

Answer C is correct

Step-by-step explanation:

The formula to find the area of a circle is:

A = πr²

Here,

r => radius = 6m

Let us find the area of the circle.

A = πr²

A = 3.14 × 6 × 6

A = 113.04 m²

Approx. = 113m²

The width of the top of the bookcase should be approximately 12.2 inches to give Bria's soap carving collection an area of 300 square inches.

Simply multiply the length and width measurements to get the area of your square or rectangular area in square inches.

Assume the bookcase's top is rectangular, with length "L" and width "b". Because the area of a rectangle is the product of its length and width, we get:

L * b = 300

To find "b," we can rearrange the equation as follows:

b = 300 / L

We don't have enough information to directly solve for "L," but we can make an educated guess based on the figure provided. Based on the illustration, the bookcase appears to be roughly twice as long as it is wide. So let us suppose:

L ≈ 2b

When we plug this into the equation above, we get:

b = 300 / (2b) (2b)

To simplify, we have:

b^2 = 150

When we take the square root of both sides, we get:

b ≈ 12.2

We have, rounded to the nearest tenth of an inch:

b ≈ 12.2 inches

As a result, the width of the top of the bookcase should be approximately 12.2 inches in order to give Bria's soap carving collection a 300-square-inch area.

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Answer:

Your answer is

\(2 (\frac{2}{5} x + 2) = \frac{4}{5} x + 4\)

The value of the function F(3) will be 1/125. It is obtained by putting the value 3 in the place of x.

A connection between independent variables and the dependent variable is defined by the function. Functions help to represent graphs and equations.

A function is represented by the two variables one is dependent and another one is an independent function. The relation between them is shown as y if dependent and x is the independent variable.

F(x)=(1/5)ˣ

F(3)=(1/5)³

F(3)=1/125

Hence, the value of the function F(3) will be 1/125.

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so the idea being, we have a system of equations of two variables and 4 equations, each one rendering a line, for this case these aren't equations per se, they're INEquations, so pretty much the function will be the same for an equation but we'll use > or < instead of =, but fairly the function is basically the same, the behaviour differs a bit.

we have a line passing through (-6,0) and (0,8), side one

we have a line passing through the x-axis and -6, namely (-6,0) and the y-axis and -4, namely (0,-4), side two

we have a line passing through (0,-4) and (6,4), side three

now, side four is simply the line connecting one and three.

the intersection of all four lines looks like the one in the picture below, so what are those lines with their shading producing that quadrilateral?

well, we have two points for all four, and that's all we need to get the equation of a line, once we get the equation, with its shading like that in the picture, we'll make it an inequality.

\((\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{8 -0}{0 +6} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = \cfrac{4}{3} ( x +6) \\\\\\ y=\cfrac{4}{3}x+8\hspace{5em}\stackrel{\textit{side one} }{\boxed{y < \cfrac{4}{3}x+8}}\)

\(\rule{34em}{0.25pt}\\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-4}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{-4 -0}{0 +6} \implies \cfrac{ -4 }{ 6 } \implies - \cfrac{2}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = - \cfrac{2}{3} ( x +6) \\\\\\ y=-\cfrac{2}{3}x-4\hspace{5em}\stackrel{\textit{side two} }{\boxed{y > -\cfrac{2}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\(\stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{(-4)}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{0}}} \implies \cfrac{4 +4}{6 -0} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{0}) \implies y +4 = \cfrac{4}{3} ( x -0) \\\\\\ y=\cfrac{4}{3}x-4\hspace{5em}\stackrel{ \textit{side three} }{\boxed{y > \cfrac{4}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\((\stackrel{x_1}{6}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) ~\hfill~ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{6}}} \implies \cfrac{ 4 }{ -6 } \implies - \cfrac{2}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{6}) \\\\\\ y=-\cfrac{2}{3}x+8\hspace{5em}\stackrel{ \textit{side four} }{\boxed{y < -\cfrac{2}{3}x+8}}\)

now, we can make that quadrilateral a trapezoid by simply moving one point for "side four", say we change the point (0 , 8) and in essence slide it down over the line to  (-3 , 4).  Notice, all we did was slide it down the line of side one, that means the equation for side one never changed and thus its inequality is the same function.

now, with the new points for side for of (-3,4) and (6,4), let's rewrite its inequality

\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{(-3)}}} \implies \cfrac{4 -4}{6 +3} \implies \cfrac{ 0 }{ 9 } \implies 0\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{ 0}(x-\stackrel{x_1}{(-3)}) \implies y -4 = 0 ( x +3) \\\\\\ y=4\hspace{5em}\stackrel{ \textit{side four changed} }{\boxed{y < 4}}\)

Given that Line a is parallel to Line b (Line a ║ Line b), the triangle that is similar to ΔJKH is 1. ΔMKN

Similar triangles are triangles that have congruent corresponding angles, and in which all three corresponding sides are proportional.

The given parameter is Line a is parallel to Line b, which gives: a║b

Two triangles are similar if they satisfy the following conditions:

According to alternate angles theorem, the angles ∠JHK in ΔJKH is congruent to the ∠KNM in triangle ΔMKN

Similarly, the angle ∠HJK in ΔJKH is congruent to the ∠KMN in ΔMKN

Therefore, ΔJKH is similar to ΔMKN by Angle-Angle, AA similarity postulate.

The correct option for the triangle similar to ΔJKH is option 1. ΔMKN

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