Please help me w the following or else I can’t go to my softball game tomorrow ‍♀️

The statements that are listed above that are not propositions include the following:

A proposition statement is defined as the statement that is either a true statement or false statement but can not be both.

From the given statements,the statement that is a true proposition include the following:

The statement that is a false proposition include the following:

The statement will you be my valentine? is not a proposition but a declarative question that needs to be answered.

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Answer:

32 percent

Step-by-step explanation:

We can set this up as a fraction: because there are 640 out of 2000, it becomes:

640/2000

We can simplify this to get

320/1000

32/100.

0.32

Since percentages are the decimal of the hundredths place, we get 32 percent.

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Answer:

B. Almost-equals3 × 108 meters

Step-by-step explanation:

I just did the assignment:)

Answer:

B

Step-by-step explanation:

Just took the asignment.

Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

Recall that the projection of a vector \(u\) onto \(v\) is \(\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v\).

Identify the vectors:

\(u=\langle-10,-7\rangle\)

\(v=\langle-8,4\rangle\)

Compute the dot product:

\(u\cdot v=(-10*-8)+(-7*4)=80+(-28)=52\)

Find the square of the magnitude of vector v:

\(||v||^2=\sqrt{(-8)^2+(4)^2}^2=64+16=80\)

Find the projection of vector u onto v:

\(\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v\\\\proj_vu=\biggr(\frac{52}{80}\biggr)\langle-8,4\rangle\\\\proj_vu=\biggr\langle\frac{-416}{80} ,\frac{208}{80}\biggr\rangle\\\\proj_vu=\biggr\langle\frac{-26}{5} ,\frac{13}{5}\biggr\rangle\\\\proj_vu=\langle-5.2,2.6\rangle\)

Thus, B is the correct answer

Problem 2

Treat the football and wind as vectors:

Football: \(u=\langle42\cos172^\circ,42\sin172^\circ\rangle\)

Wind: \(v=\langle13\cos345^\circ,13\sin345^\circ\rangle\)

Add the vectors: \(u+v=\langle42\cos172^\circ+13\cos345^\circ,42\sin172^\circ+13\sin345^\circ\rangle\approx\langle-29.034,2.481\rangle\)

Find the magnitude of the resultant vector:

\(||u+v||=\sqrt{(-29.034)^2+(2.481)^2}\approx29.14\)

Find the direction of the resultant vector:

\(\displaystyle \theta=tan^{-1}\biggr(\frac{2.841}{-29.034}\biggr)\approx -5^\circ\)

Because our resultant vector is in Quadrant II, the true direction angle is 6° clockwise from the negative axis. This means that our true direction angle is \(180^\circ-5^\circ=175^\circ\)

Thus, C is the correct answer

Problem 3

We identify the initial point to be \(R(-2,12)\) and the terminal point to be \(S(-7,6)\). The vector in component form can be found by subtracting the initial point from the terminal point:

\(v=\langle-7-(-2),6-12\rangle=\langle-7+2,-6\rangle=\langle-5,-6\rangle\)

Next, we find the magnitude of the vector:

\(||v||=\sqrt{(-5)^2+(-6)^2}=\sqrt{25+36}=\sqrt{61}\approx7.81\)

And finally, we find the direction of the vector:

\(\displaystyle \theta=tan^{-1}\biggr(\frac{6}{5}\biggr)\approx50.194^\circ\)

Keep in mind that since our vector is in Quadrant III, our direction angle also needs to be in Quadrant III, so the true direction angle is \(180^\circ+50.194^\circ=230.194^\circ\).

Thus, A is the correct answer

Problem 4

Add the vectors:

\(v_1+v_2=\langle-60,3\rangle+\langle4,14\rangle=\langle-60+4,3+14\rangle=\langle-56,17\rangle\)

Determine the magnitude of the vector:

\(||v_1+v_2||=\sqrt{(-56)^2+(17)^2}=\sqrt{3136+289}=\sqrt{3425}\approx58.524\)

Find the direction of the vector:

\(\displaystyle\theta=tan^{-1}\biggr(\frac{17}{-56} \biggr)\approx-17^\circ\)

Because our vector is in Quadrant II, then the direction angle we found is a reference angle, telling us the true direction angle is 17° clockwise from the negative x-axis, so the true direction angle is \(180^\circ-17^\circ=163^\circ\)

Thus, A is the correct answer

Problem 5

A vector in trigonometric form is represented as \(w=||w||(\cos\theta i+\sin\theta i)\) where \(||w||\) is the magnitude of vector \(w\) and \(\theta\) is the direction of vector \(w\).

Magnitude: \(||w||=\sqrt{(-16)^2+(-63)^2}=\sqrt{256+3969}=\sqrt{4225}=65\)

Direction: \(\displaystyle \theta=tan^{-1}\biggr(\frac{-63}{-16}\biggr)\approx75.75^\circ\)

As our vector is in Quadrant III, our true direction angle will be 75.75° counterclockwise from the negative x-axis, so our true direction angle will be \(180^\circ+75.75^\circ=255.75^\circ\).

This means that our vector in trigonometric form is \(w=65(\cos255.75^\circ i+\sin255.75^\circ j)\)

Thus, C is the correct answer

Problem 6

Write the vectors in trigonometric form:

\(u=\langle40\cos30^\circ,40\sin30^\circ\rangle\\v=\langle50\cos140^\circ,50\sin140^\circ\rangle\)

Add the vectors:

\(u+v=\langle40\cos30^\circ+50\cos140^\circ,40\sin30^\circ+50\sin140^\circ\rangle\approx\langle-3.661,52.139\rangle\)

Find the magnitude of the resultant vector:

\(||u+v||=\sqrt{3.661^2+52.139^2}\approx52.268\)

Find the direction of the resultant vector:

\(\displaystyle\theta=tan^{-1}\biggr(\frac{52.139}{-3.661} \biggr)\approx-86^\circ\)

Because our resultant vector is in Quadrant II, then our true direction angle will be 86° clockwise from the negative x-axis. So, our true direction angle is \(180^\circ-86^\circ=94^\circ\).

Thus, B is the correct answer

we conclude that the difference quotient for the function f(x), we get:

[-3*(2x + h) + 4]

For any function f(x), we define the difference quotient as:

( f(x + h) - f(x))/h

In this case, we have:

f(x) = -3x^2 + 4x + 10

Then f(x) is a quadratic function.

Now we replace that in the difference quotient formula so we get:

[ -3(x + h)^2 + 4*(x + h) + 10 - (-3x^2 + 4x + 10)]/h

Now we can simplify that:

[ -3(x + h)^2 + 4*(x + h) + 3x^2 - 4x ]/h

[ -3(x + h)^2 + 4*h + 3x^2  ]/h

[ -3(x^2 + 2xh + h^2) + 4*h + 3x^2  ]/h

[ -3(2xh + h^2) + 4*h]/h = [-3*(2x + h) + 4]

So we conclude that the difference quotient for the function f(x), we get:

[-3*(2x + h) + 4]

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Answer:

10x+276

Step-by-step explanation:

multiply length times width to get the area

12(5/6x +23)

simplify

10x +276

i hope your test is going well <3

Step-by-step explanation:

points on the line: (4, -2) & (-5, 3)

gradient of the line = -5/9

general equation for all straight lines: y = mx + c

substitute one coordinate and the gradient into the equation. 3 = (-5/9)(-5) + c

therefore, c = 2/9

so the general equation is y = (-5/9)x + 2/9

Solving the quadratic equation, it is found that:

A quadratic function is given according to the following rule:

\(y = ax^2 + bx + c\)

The solutions are:

\(x_1 = \frac{-b + \sqrt{\Delta}}{2a}\)

\(x_2 = \frac{-b - \sqrt{\Delta}}{2a}\)

In which:

\(\Delta = b^2 - 4ac\)

If a < 0, the graph, which is a parabola, is concave down, that is, it is positive only between the two roots.

In this problem, the equation is:

\(y = -16t^2 + 176t - 384\)

Then, the solution is:

\(-16t^2 + 176t - 384 = 0\)

The coefficients are \(a = -16, b = 176, c = -384\), then:

\(\Delta = (176)^2 - 4(-16)(-384) = 6400\)

\(x_1 = \frac{-176 + \sqrt{6400}}{-32} = 3\)

\(x_2 = \frac{-176 - \sqrt{6400}}{-32} = 8\)

Considering that the parabola is concave down, we have that:

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Step 1 : Given the function below

Step 2: Write the function for h(3), this is done by substituting 3 for x in the function h(x) above

Step 3: Write the corresponding value for the function g(9) and an inverse function of R⁻¹ (3) on the table.

Step 4: Substitute the g(9) and R⁻¹ (3) values in the h(3) equation and simplify

Hence, the value of h(3) is -11

The second option is the correct answer.

The shaded area represents the solution of the inequalities. Hence, points A, C, D and K are the solution of the system.

Get y first when graphing a linear inequality with two variables, such as x and y alone on one side. Then, take into account the associated equation that was created by switching the inequality sign for an equality sign. This equation has a line as its graph.

The last step is to choose a point that is not on either line (usually (0, 0) is the simplest) and determine whether or not these coordinates satisfy the inequality. If so, shade the portion of the half-plane that contains that point. If not, shade the opposite half-plane.

Create a comparable graph for each of the system's inequalities. The place where all of the system's solutions overlap is known as the system's solution.

Given that, the inequality is:

y ≤ −2x + 10 & y > 1/(2x − 2)

The given points: A(-5,4), B(4,7), C(-2,7), D(-7,1), E(4,-2), F(1,-6), G(-3,-10), H(-4,-4), I(9,3), J(7,-4) and K(2,3).

The shaded area represents the solution of the inequalities.

Hence, points A, C, D and K are the solution of the system.

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The complete question is:

Answer: $27.98

Step-by-step explanation:

22.00 × .2= 4.40

22 + 4.40 = 26.40

26.40 × .06 = 1.584

26.40 + 1.584 = 27.984

Round to the nearest hundred so the total paid by the customer would be 27.98

Answer:

Step-by-step explanation:

3(x+1) = 3·x + 3·1 = 3x + 3

Answer:

3x + 1

Step-by-step Explanation:

Just multiply or distribute 3 (outer number) to each set of the inner terms in the parenthesis which are x and 1.

The measure of angle is θ cannot determine the statements that are true about its reference angle.

There are two issues with the given statement.

First, it does not specify the measure of angle θ.

Second, the statement cos(0)=-3/10 is not related to the reference angle of θ.

The reference angle of θ is the acute angle between the terminal side of θ and the x-axis.

It is always positive and its measure is between 0 and 90 degrees or between 0 and π/2 radians.

The measure of the reference angle of θ is denoted by θ'.

To determine the reference angle of θ, we need to know the quadrant in which θ lies.

The reference angle of θ in standard position is the acute angle between the terminal side of θ and the x-axis.

If θ is in the first quadrant, then θ' = θ.

If θ is in the second quadrant, then θ' = π - θ.

If θ is in the third quadrant, then θ' = θ - π.

If θ is in the fourth quadrant, then θ' = 2π - θ.

The measure of angle θ, we can determine its reference angle using the above rules.

The statement cos(0)=-3/10 is not related to the reference angle of θ.

It is the value of the cosine function at 0 radians or 0 degrees.

This value does not correspond to any angle that has a reference angle.

The measure of angle θ cannot determine the statements that are true about its reference angle.

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Answer:

a) The 99% confidence interval of the population average of drug dosage dispensed is between 23.1 mg and 25.1 mg.

b) It means that we are 99% sure that the true mean dosage for all the population is between 23.1 mg and 25.1 mg.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

a)

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of \(1 - \frac{1 - 0.99}{2} = 0.995\). So we have T = 2.797

The margin of error is:

\(M = T\frac{s}{\sqrt{n}} = 2.797\frac{1.8}{\sqrt{25}} = 1\)

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 24.1 - 1 = 23.1 mg

The upper end of the interval is the sample mean added to M. So it is 24.1 + 1 = 25.1 mg

The 99% confidence interval of the population average of drug dosage dispensed is between 23.1 mg and 25.1 mg.

b)

The interval means that we are 99% sure that the true mean dosage for all the population is between 23.1 mg and 25.1 mg.

Answer:

  33

Step-by-step explanation:

Let n represent the number. 99 less than 4 times the number is 4n-99. That is equal to the number:

  4n -99 = n

  3n = 99  . . . . . .  add 99-n

  n = 33 . . . . . . . . . divide by 3

The number is 33.

Answer:

Sum of two polynomials:
\(3x^2 - x - 4\)        Choice C   (read explanation carefully)

Product of the two polynomials:
\(2x^4-5x^3-14x^2+30x-12\\\\\)     Choice C   (read explanation carefully)

In both cases, your answer choice copy/paste messed up the formatting. I looked at the coefficients and came up with the choices.

You should compare the actual terms with the choices I have provided to make sure they match

Step-by-step explanation:

The two polynomials are
2x² + 3x - 6

and

x² - 4x + 2

Addition

To add these two polynomials together group like terms and add their coefficients:

(2x² + 3x - 6) + (x² - 4x + 2)

= 2x² + 3x - 6 + x² - 4x + 2

= (2x² + x²) + (3x -4x) + (-6 + 2)

= 3x² - x - 4

Your answer choices have lost formatting during copy paste. You will have to compare and choose the right one. I think it is C because it has a 3x² term and the last term is - 4

Multiplication

\(\left(2x^2\:+\:3x\:-\:6\right)\cdot \left(x^2-4x\:+\:2\right)\\\\\\\)
Distribute the parentheses - multiply each term in the second polynomial by each term in the first polynomial and simplify

\(\left(2x^2\:+\:3x\:-\:6\right)\cdot \left(x^2-4x\:+\:2\right)\\\\= 2x^2x^2+2x^2\left(-4x\right)+2x^2\cdot \:2+3xx^2+3x\left(-4x\right)+3x\cdot \:2-6x^2-6\left(-4x\right)-6\cdot \:2\\\\= 2x^4-8x^3+4x^2+3x^3-12x^2+6x-6x^2+24x-12\\\\\textrm{Add similar terms}\\=2x^4 +(-8x^3+3x^3)+ (4x^2-12x^2-6x^2) + (6x+24x) -12\\\\\)

\(=2x^4-5x^3-14x^2+30x-12\\\\\)    (Answer)

Again your answer choices have lost formatting but my best guess from looking at the coefficients is that it is choice C

Answer:

Great Britain we’re colonizers

Step-by-step explanation:

Answer:

C) 0.08

Step-by-step explanation:

9514 1404 393

Answer:

  (c)  1/(36·a^4·b^10)

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

  a^-1 = 1/a

__

  \(\left(\dfrac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}\right)^{-1}=\dfrac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}=\dfrac{3^{-2}a^{-10}b^{-2}}{2^2a^{-6}b^8}=\dfrac{1}{3^22^2}a^{-10-(-6)}b^{-2-8}\\\\=\boxed{\dfrac{1}{36a^4b^{10}}}\)

Answer:

Find the measure of what?

Step-by-step explanation:

Next time please write the entire equation. Thank you!

g(x) = -2√x + 8 is the function that has the same range as f(x) = -2√(x - 3) + 8. Both functions have the range of y ≤ 8

The function that has the same range as f(x) = -2√(x - 3) + 8 is g(x) = -2√x + 8. Both functions have the range of y ≤ 8.There are a few steps involved in determining which function has the same range as f(x) = -2√(x - 3) + 8. The range of a function refers to all the possible output values that the function can produce.Let's begin by examining the original function:f(x) = -2√(x - 3) + 8The square root symbol (√) implies that x-3 must be greater than or equal to 0. If x-3 is negative, then the function would produce an imaginary result.

Let's solve for x when f(x) = 0:0 = -2√(x - 3) + 8-8 = -2√(x - 3)4 = √(x - 3)16 = x - 3x = 19This tells us that the x-value that produces an output of 0 is x = 19. To determine the range, we need to find the maximum and minimum output values. We can use a graphing calculator or sketch a graph to determine the shape of the function and the range.The shape of the function suggests that the range is y ≤ 8, which means that the maximum value of the function is 8. This tells us that any function with the same maximum output value of 8 will have the same range as f(x).

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Answer:

\(x\geq -30\)

Step-by-step explanation:

Work to isolate x on one side of the inequality:

\(3-\frac{x}{2} \leq 18\\3-18\leq \frac{x}{2} \\-15\leq \frac{x}{2}\\-30 \leq x\)

Therefore the answer is all x values larger than or equal to -30

\(x\geq -30\)

Step-by-step explanation:

The little circle between the f and g is another way of saying multiplication. So we'll multiply f(x) and g(x)

\((4 {x}^{2} + 5x)(3x + 4)\)

What we do next is distribute.

\(12 {x}^{3} + 16 {x}^{2} + 15 {x}^{2} + 20x\)

Now, we combine like terms

\(12 {x}^{3} + 31 {x}^{2} + 20x\)

Answer:

12\(x^{2}\) + 15x + 4

Step-by-step explanation:

(f ° g)(x) means a composition of functions. It can also be written as f(g(x)).

This means that you are taking g(x) and plugging it into f(x) anywhere there is an x in the equation.

f(x) = 3x + 4

f(g(x)) = 3(g(x)) + 4

= 3(4\(x^{2}\) + 5x) + 4

= 12\(x^{2}\) + 15x + 4

A salesman earns $490 as commission on his sales.

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Given that, a salesman earns 7% commission on all the merchandise that he sells.

Last month he sold $7000 worth of merchandise.

Now, the commission is 7% of 7000

7/100 ×7000

= 0.07×7000

= $490

Therefore, a salesman earns $490.

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Using the rules of indices to evaluate the expressions given, that with a value of 1 is (3² * 3⁵)/3¹⁰

1.)

\(7^{-6} \times 7^{5} = 7^{-6+5} = 7^{-1} = \frac{1}{7}\)

2.)

10³/10² = 10¹ = 10

3.)

(5⁶)²/5⁸ = 5¹²/5⁸ = 5⁴ = 625

4.)

(3² * 3⁵)/3¹⁰ = 3¹⁰/3¹⁰ = 3⁰ = 1

Therefore, the expression which has a value of 1 is the option D

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Answer:  6 * 24 = 144 ways.

Step-by-step explanation:

Solution:

Given word => DANGER.

The condition is that vowels can't occupy odd places so, we will let them occupy even places.

A total number of arrangements will be = 6 * 24 = 144 ways.

Answer: 6x24 = 144 ways.

Answer: {x ∈ ℤ ∪ {0} | x < 5}

Step-by-step explanation:

that’s it

the length of side a is 91 ft (rounded to the nearest whole foot) and the length of side b is 132 ft (rounded to the nearest whole foot). The area of the triangle is approximately 6007 sq ft.

Given: The hypotenuse of the right triangle,

c = 159 ft; angle A = 34°

We know that, in a right-angled triangle:

\($$\sin\theta=\frac{\text{opposite}}\)

\({\text{hypotenuse}}$$$$\cos\theta=\frac{\text{adjacent}}\)

\({\text{hypotenuse}}$$\)

We know the value of the hypotenuse and angle A. Using trigonometric ratios, we can find the length of sides in the right triangle.We will use the following formulas:

\($$\sin\theta=\frac{\text{opposite}}\)

\({\text{hypotenuse}}$$$$\cos\theta=\frac{\text{adjacent}}\)

\({\text{hypotenuse}}$$$$\tan\theta=\frac{\text{opposite}}\)

\({\text{adjacent}}$$\) Length of side a is:

\($$\begin{aligned} \sin A &=\frac{a}{c}\\ a &=c \sin A\\ &= 159\sin 34°\\ &= 91.4 \text{ ft} \end{aligned}$$Length of side b is:$$\begin{aligned} \cos A &=\frac{b}{c}\\ b &=c \cos A\\ &= 159\cos 34°\\ &= 131.5 \text{ ft} \end{aligned}$$\)

Now, we have the values of all sides of the right triangle. We can calculate the area of the triangle by using the formula for the area of a right triangle:

\($$\text{Area} = \frac{1}{2}ab$$\)

Putting the values of a and b:

\($$\begin{aligned} \text{Area} &=\frac{1}{2}ab\\ &=\frac{1}{2}(91.4)(131.5)\\ &= 6006.55 \approx 6007 \text{ sq ft}\end{aligned}$$\)

Therefore, the length of side a is 91 ft (rounded to the nearest whole foot) and the length of side b is 132 ft (rounded to the nearest whole foot). The area of the triangle is approximately 6007 sq ft.

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Answer:

237.5

Step-by-step explanation:

In order to do this, you can divide 38 by 0.16 to get x

38/0.16=237.5

so it would be 237.5

Answer:

x=237.5

Step-by-step explanation:

38=0.16*x

38/0.16=x

x=237.5

Answer:

$7.80

Step-by-step explanation:

Find the cost to download 1 song. Divide 6 from 4.68

4.68/6 = 0.78

Each song costs $0.78.

Find the amount 10 songs cost. Multiply 0.78 with 10:

10 x 0.78 = 7.80

$7.80 is your answer.

~

Hi

6 = 4.68

10 = X

X = 10*4.68 /6

X = 46.8/6

X = 7.8