please help me with this problem

The independent set in a graph is a set of vertices that contain no edges. So, no neighboring vertices are included. The max independent set problem is to get an independent set of maximum size in graph G.

The solution for this question is discussed below:

a) The integer linear program for the max independent set problem is as follows:

maximize ∑x_i Subject to: x_i+x_j ≤ 1 {i,j} ∈ E;x_i ∈ {0, 1} ∀i. The variable x_i can represent whether the ith vertex is in the independent set. It can take on two values, either 0 or 1.

b) The LP relaxation for the max independent set problem is as follows:

Maximize ∑x_iSubject to:

xi+xj ≤ 1 ∀ {i, j} ∈ E;xi ≥ 0 ∀i. The variable xi can take on fractional values in the LP relaxation.

c) The family of graphs is as follows:

Consider a family of graphs G = (V, E) defined as follows. The vertex set V has n = 2^k vertices, where k is a positive integer. The set of edges E is defined as {uv:u, v ∈ {0, 1}^k and u≠v and u, v differ in precisely one coordinate}. It can be shown that the size of the max independent set is n/2. Using LP, the value can be determined. LP provides a value of approximately n/4. Therefore, the ratio LP-OPT/OPT is at least c/4. Therefore, the ratio is in for a constant c>0.

d) The size of a max-independent set is equivalent to the number of vertices minus the minimum vertex cover size.

e) The 2-approximation algorithm for vertex cover implies a 2-approximation algorithm for the max independent set.

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Answer:

0.6666666666666666666666

Step-by-step explanation:

The Taylor polynomials T, for n = 0, 1, 2, and 3 generated by f are;  6(x - 1), 6(x - 1) - 3(x - 1)², and 6(x - 1) - 3(x - 1)² + 2(x - 1)³.

The Taylor polynomial of order 1, denoted by P1(x), is a linear polynomial that approximates f(x) near the point a. To find this polynomial, we first need to find the first derivative of f(x), which is f'(x) = 6/x.

Evaluating this derivative at the point a, we have f'(1) = 6, so the equation of the tangent line to the graph of f(x) at the point x = 1 is y = 6(x - 1) + 0. Simplifying this expression, we get

M 1(x) = 6(x - 1).

The Taylor polynomial of order 2, M 2(x), is a quadratic polynomial that approximates f(x) near the point a.

we first need to find the second derivative of f(x), which is;

f''(x) = -6/x².

Evaluating this derivative at the point a, we have f''(1) = -6,

Thus the equation of the quadratic polynomial that f(x) near the point x = 1 is

y = 6(x - 1) + (-6/2)(x - 1)².

Simplifying this expression, we get

 M 2(x) = 6(x - 1) - 3(x - 1)².

Finally, the Taylor polynomial of order 3, M 3(x), is a cubic polynomial that approximates f(x) near the point a.

To find this polynomial, we first need to find the third derivative of f(x), which is f'''(x) = 12/x³.

y = 6(x - 1) - 3(x - 1)² + (12/3!)(x - 1)³.

Simplifying this expression, we get;

M 3(x) = 6(x - 1) - 3(x - 1)² + 2(x - 1)³.

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Answer:

96,470,000

Step-by-step explanation:

10^7=10,000,000

10,000,000 * 9.647= 96,470,000

Hope this helps!

There is a potential outlier in this data set is True statement.

The data in ascending order:

-46, -1, 4, 7, 15, 19, 23, 24, 27, 31, 34, 35, 41, 48, 60, 65

The 5-number summary consists of the minimum (Min), the first quartile (Q1), the median (Q2 or the second quartile), the third quartile (Q3), and the maximum (Max) of the data set.

Min: -46

\(Q_1\): 7

\(Q_2\)(Median): 24

\(Q_3\) : 41

Max: 65

The interquartile range (IQR) is

IQR = Q3 - Q1

      = 41 - 7

       = 34

Now, Lower limit: Q1 - 1.5 x IQR

                            = 7 - 1.5 x 34

                             = 7 - 51

                             = -44

Upper limit: Q3 + 1.5 x IQR

                  = 41 + 1.5 x 34

                  = 41 + 51

                  = 92

Since we have a value of -46, which falls below the lower limit of -44, there is a potential outlier in this data set.

Therefore, the statement "There is a potential outlier in this data set" is true.

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Answer: 2/3

Step-by-step explanation: 50/75

25 can go into both.

50 divided by 25 = 2

75 divided by 25 = 3

Answer:

8

Step-by-step explanation:

12 ÷ 3 = 4

4 × 2 = 8

:) hope this helps

Answer:

The answer is is 8 inches.

Answer:

it changed to f(x)+7 because it has an asymptote of 7

Answer:

73384 kilotons

Step-by-step explanation:

=> Total amount the 1st year = 90,000

=> Since after the 1st yr, there was a reduction of 4%, so 100% - 4% = 96% or 0.96

=> Total time = 6

We know that the formula of a geometric sequence is;

aₙ = a₁ * r⁽ⁿ⁻¹⁾

In which;

Therefore we can finally say;

=> aₙ = a₁ * r⁽ⁿ⁻¹⁾

=> a₆ = 90,000 * 0.96⁶⁻¹

=> a₆ = 90,000 * 0.96⁵

=> a₆ = 73383.54

=> a₆ = 73384 (Rounded to the nearest whole number)

Therefore, rounding the answer to the nearest whole number, the answer would be; 73384 kilotons

Hope this helps! (Btw big shout out to jcherry99 for helping me figure this out!!)

Given:

There are given that the triangle ABC.

Where,

Explanation:

According to the question:

We need to find the value for BC:

So,

To find the value of BC, we need to use the cosine rule:

From the cosine rule:

Then,

Put the all values into the given formula:

Then,

Then,

Final answer:

Hence, the value of BC is 6.016 km.

Answer:

right triangle

Step-by-step explanation:

because 15 would be the base so 11 and 12 would be the sides and fot the triangle to be acute or obtuse the total of the sides (11+12) has to be lass than the base (15), but it is more 23 so it has to be a right triangle.

Determine the domain and range of the given function:

y = –x4 + 4

This is just a garden-variety polynomial. There are no denominators (so no division-by-zero problems) and no radicals (so no square-root-of-a-negative problems). There are no problems with a polynomial. There are no values that I can't plug in for x. When I have a polynomial, the answer for the domain is always:

the domain is "all x".

The range will vary from polynomial to polynomial, and they probably won't even ask, but when they do, I look at the picture:

graph

The graph goes only as high as y = 4, but it will go as low as I like. Then:

The range is "all y ≤ 4".

Answer:

{x,y} ={0,-7}

Step-by-step explanation:

[1]  3 x - 2 y = 14

[2] 5 x 6 y =42

the derivative dy/dx is equal to 1/3 based on the given information. It's important to note that this calculation assumes that the partial derivatives (∂F/∂x) and (∂F/∂y) are not zero at the given point (z.y.a).

n the given problem, we have an implicit equation ln(x+y+z) = x+2y+3z that defines z as a function of x and y. We are given the values dy = (-1, 5, -3).

To find the derivative dy/dx, we can use the total derivative formula and apply it to the implicit equation. The total derivative is given by dy/dx = - (∂F/∂x)/(∂F/∂y), where F = ln(x+y+z) - x - 2y - 3z.

Differentiating F partially with respect to x and y, we have (∂F/∂x) = 1/(x+y+z) - 1 and (∂F/∂y) = 1/(x+y+z) - 2.

Plugging in the given values of dy = (-1, 5, -3), we can calculate dy/dx = - (∂F/∂x)/(∂F/∂y) = -(-1)/(5-2) = 1/3.

Therefore, the derivative dy/dx is equal to 1/3 based on the given information. It's important to note that this calculation assumes that the partial derivatives (∂F/∂x) and (∂F/∂y) are not zero at the given point (z.y.a).

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switch the variables

x = -y + 6

x - 6 = -y

-x + 6 = y

Answer:

11/5 x^2 + 5/2 xy + 3/2 y.

Step-by-step explanation:

2x . (x+y) + 1/5 x.x + 1/2 y . (x + 3)

= 2x^2 + 2xy + 1/5 x^2 + 1/2xy + 3/2 y

= 11/5 x^2 + 5/2 xy + 3/2 y.

To solve the equation \(6sin^2(x)\) + 6sin(x) + 1 = 0, we can use algebraic methods and the unit circle to determine the values of x that satisfy the equation.

1. Start by rearranging the equation to a quadratic form: \(6sin^2(x)\) + 6sin(x) + 1 = 0.

2. Notice that the equation resembles a quadratic equation in terms of sin(x). Let's substitute sin(x) with a variable, such as u: \(6u^2\) + 6u + 1 = 0.

3. Solve this quadratic equation for u. You can use the quadratic formula or factorization methods to find the values of u. The solutions are u = (-3 ± √3) / 6.

4. Since sin(x) = u, substitute back the values of u into sin(x) to obtain the values for sin(x): sin(x) = (-3 ± √3) / 6.

5. To find the values of x, we can use the inverse sine function. Take the inverse sine of both sides: x = arcsin[(-3 ± √3) / 6].

6. The arcsin function has a range of [-π/2, π/2], so the values of x lie within that range. Use a calculator to find the approximate values of x based on the values obtained in step 5.

7. Plot the obtained x-values on the graph to show the solutions of the equation \(6sin^2(x)\) + 6sin(x) + 1 = 0. The graph will illustrate the points where the curve intersects the x-axis.

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Answer:

50%

Step-by-step explanation:

\(\frac{26}{52}\) x 100 = 50

Answer: 9 - 6 = 3

Step-by-step explanation:

Answer:

(3,4)

Step-by-step explanation:

Step-by-step explanation:

6x-2y=10

y+2x=10

2y+4x=20

6x-2y+2y+4x=10+20

10x. =30

X=3

y+2x=10

y+6=10

y=4

Answer:

The 18th term of the sequence is -117.

Step-by-step explanation:

The given sequence is 2,-5,-12,-19

From this AP,

First term, a = 2

Common difference, d = -5-2 = -7

It is required to find the 18th term of the sequence. The nth term of an AP is given by :

\(a_n=a+(n-a)d\\\\a_{18}=a+17d\\\\a_{18}=2+17\times (-7)\\\\a_{18}=-117\)

So, the 18th term of the sequence is -117.

Answer: X is do it yourself and y is do it yourself X is do it yourself and y is do it yourself

Step-by-step explanation:

Lolol

Step-by-step explanation:

the average rate of change is

(f(x2) - f(x1)) / (x2 - x1)

so, for x = 1 and 2

(4×3² - 4×3¹) / (2 - 1) = 36 - 12 = 24

for x = 3 and 4

(4×3⁴ - 4×3³) / (4 - 3) = 324 - 108 = 216

so the second rate is 216/24 = 9 times greater than the first rate.

The trapezoidal rule is a numerical integration method that uses trapezoids to estimate the area under a curve. The trapezoidal rule can be used for both definite and indefinite integrals. The trapezoidal rule approximation, Tn, to the integral sin r dz is given by:

Tn = (b-a)/2n[f(a) + 2f(a+h) + 2f(a+2h) + ... + 2f(b-h) + f(b)]where h = (b-a)/n. To determine how large n should be so that Tn is accurate to within 0.00001, we can use the error bound given in Section 5.9 of the course text. According to the error bound, the error, E, in the trapezoidal rule approximation is given by:E ≤ ((b-a)³/12n²)max|f''(x)|where f''(x) is the second derivative of f(x). For the integral sin r dz, the second derivative is f''(r) = -sin r. Since the absolute value of sin r is less than or equal to 1, we have:max|f''(r)| = 1.

Substituting this value into the error bound equation gives:E ≤ ((b-a)³/12n²)So we want to choose n so that E ≤ 0.00001. Substituting E and the given values into the inequality gives:((b-a)³/12n²) ≤ 0.00001Simplifying this expression gives:n² ≥ ((b-a)³/(0.00001)(12))n² ≥ (b-a)³/0.00012n ≥ √(b-a)³/0.00012Now we just need to substitute the values of a and b into this expression. Since we don't know the upper limit of integration, we can use the fact that sin r is bounded by -1 and 1 to get an upper bound for the integral.

For example, we could use the interval [0, pi/2], which contains one full period of sin r. Then we have:a = 0b = pi/2Plugging in these values gives:n ≥ √(pi/2)³/0.00012n ≥ 5073.31Since n must be an integer, we round up to the nearest integer to get:n = 5074Therefore, we should choose n to be 5074 so that the trapezoidal rule approximation, Tn, to the integral sin r dz is accurate to within 0.00001.

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The quadratic formula multiplied by π divided by x is: π(-b ± √(b² - 4ac)) / (2ax).

The quadratic formula is used to solve quadratic equations, and is given by: x = (-b ± √(b² - 4ac)) / 2a.

Pi otherwise denoted by the symbol π in real terms is a mathematical constant that represents the ratio of the circumference of a circle to its diameter. It is approximately equal to 3.14159, although its decimal representation goes on infinitely without repeating.

Since the rational objective of every mathematical expression or problem is to simplify, we  will leave Pi in it's symbolic form - π.

Thus, multiplying quadratic formula by π and dividing by x, we get:

π(-b ± √(b² - 4ac)) / (2ax)

Therefore, the quadratic formula multiplied by π divided by x is:

π(-b ± √(b² - 4ac)) / (2ax).


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Answer:  π(-b ± √(b² - 4ac)) / (2ax)

Step-by-step explanation:

take the standard quadratic formula and plug in pi and x and you get you answer hope this helps

A sample size of 76 would be required to estimate the population mean with a margin of error of 4 and a 98% level of confidence.

To determine the sample size required to estimate the population mean with a specific margin of error and level of confidence, we can use the formula:

n = (Z * σ / E)²

where

n = required sample size

Z = Z-score corresponding to the desired level of confidence

σ = standard deviation of the population

E = desired margin of error

here, we have that

the standard deviation (σ) is given as 15,

the margin of error (E) is 4 and

the level of confidence is 98% and For a 98% confidence level, the Z-score is approximately 2.33.

Plugging the values into the formula:

n = (2.33 * 15 / 4)²

n = (8.7375)²

n ≈ 76.34

n = 76

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