please help me with this​

when you carry the 2 and add the 3 its Z

It will depend on your frame of reference, assuming no energy is lost in the conversion of energy to motion.

Newton's first law asserts that an object in motion will remain in motion until acted on by a force. The car will remain in motion as long as the forces on it are balanced. However, we currently consider a motion to be moved relative to a frame of reference; depending on your perspective, the car could be traveling forward, backward, or not moving at all.

An external force is described as a change in mechanical energy, which can be either kinetic or potential energy in an item. External agents cause these forces. Friction, normal force, and air resistance are examples of external forces. Because stationery is simply a constant speed of 0. So the pace is constant.

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A. Different magmas generated in various places are isolated from one another. This assertion is untrue since magmas can interact with one another and mix.

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The physics cart is subjected to force manipulation. The Independent variable is this. The force exerted on the cart caused it to accelerate. Therefore, acceleration is a dependent variable.

When the mass of a cart is held constant, if the force applied to it rises, the cart will accelerate because, in accordance with Newton's second law, force and acceleration are directly proportional to one another.

When a person pushes a supermarket cart, an imbalanced force acts on the cart, causing it to accelerate. 2. The net force applied to an item is directly inversely proportional to its acceleration. This implies that as the object accelerates, the net force exerted on it also accelerates.

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Answer:

1 independent

2 dependent

3 mass

Explanation:

Answer:

1/2 M V^2 = .1 M g H       where 10% of PE goes into KE

V^2 = .2 g H = .2 * 9.8 * (2100 - 1600) = 980 m^2 / s^2

V = 31.1 m/s       increase in speed during descent

1 km / hr = 1000 m / 3600 sec = .278 m/s

V = 31.1 m/s / (.278 m/s / km /hr)= 112 km/hr

The ball's weight will be precisely balanced by the electric field is E = 12.25 x 10³ N/C = 12.25 KN/C

The electrostatic force caused by the electric field must be equal to the weight of the body or charge in order to balance the object's weight. Therefore,

Weight = Electrostatic Force

E q = mg

where,

Electric field = (E) =?

5 x 103 kg is the mass of the charge, or m.

g = 9.8 m/s2 is the acceleration caused by gravity.

Q equals the charge's magnitude, which is 4 C (4 x 106 C).

Therefore,

E(4 x 10⁻⁶ C) = (5 x 10⁻³ kg)(9.8 m/s²)

E = 0.049 N/4 x 10⁻⁶ C

E = 12.25 x 10³ N/C = 12.25 KN/C

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Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In other words, the larger the net force acting on an object, the greater its acceleration, and the larger the object's mass, the smaller its acceleration for a given force.

When a weight is placed over a pulley, the net force acting on it is equal to the weight of the object, and the acceleration of the object depends on its mass. However, if the weight over the pulley is not constant, the net force acting on the object changes, which affects its acceleration.

For example, if the weight over the pulley increases, the net force acting on the object also increases, and the object's acceleration increases. Conversely, if the weight over the pulley decreases, the net force acting on the object decreases, and the object's acceleration decreases.

Keeping the weight over the pulley constant ensures that the net force acting on the object remains constant, which allows for accurate and predictable calculations of the object's acceleration. This is especially important in scientific and engineering applications where precise measurements and calculations are necessary.

Therefore, it is important to keep the weight over the pulley constant to ensure that Newton's second law of motion can be applied accurately and consistently.

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Answer:

4.d 5.c

Explanation:

Answer:

The trebuchet was invented in France and was first reported to be used in 1124AD in the siege of Tyre (in present-day Lebanon) during the Crusades. As it was much more powerful than a catapult, a trebuchet became the siege weapon of choice.

Explanation:

Most people think that the trebuchet is a medieval weapon, but actually, it has its origins in ancient China. The ancient Chinese trebuchet could throw huge boulders up to 250 pounds, a distance of 200 feet. In addition, it was lightweight and mobile which was crucial as it could be moved around the battlefield with ease. The thing I love about the chinese trebuchet is that it pushes the boundaries of ancient engineering to create a ballistics revolution - a flexible, portable, killing machine.

The elevator does 24,000 Joules of work in lifting a 600 N person over a distance of 40 meters.

To calculate the work done by an elevator in lifting a person, we can use the formula:

Work = Force × Distance × cos(θ)

Where:

Force = 600 N (the weight of the person)

Distance = 40 m (the vertical distance the person is lifted)

θ = 0 degrees (cosine of 0 is 1, indicating the force and distance are in the same direction)

Plugging in the values:

Work = 600 N × 40 m × cos(0°)

= 600 N × 40 m × 1

= 24,000 N·m

= 24,000 J (Joules)

Therefore, the elevator does 24,000 Joules of work in lifting a 600 N person over a distance of 40 meters.

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Answer:

6 cm

Explanation:

When 4 cm from the mirror the image is 4 cm behind the mirror.  

When the mirror is moved 1 cm towards the man the man is now 3 cm from the mirror and his image is also 3 cm from the mirror.

Thus the distance between the man and his image is now 3+3 = 6 cm.

1. Time in the air:

When the ball is tossed upward, it reaches its maximum height and then falls back to the ground. The time it takes for the ball to reach its maximum height and fall back down is equal to the total time the ball is in the air.

To find the time in the air, we can use the equation for vertical motion:

h = u*t + (1/2)*g*t^2 ,

where:

h = height

u = initial velocity

g = acceleration due to gravity (approximately 9.8 m/s^2)

t = time

Since the ball starts from an initial height of 1.8 m and reaches the same height on its way back down, we can set the height (h) equal to 0:

0 = (21 m/s)*t + (1/2)*(9.8 m/s^2)*t^2

Rearranging the equation and solving for t using the quadratic formula, we get:

t = (-u ± sqrt(u^2 - 4*(1/2)*g*(0))) / (2*(1/2)*g)

  = (-21 ± sqrt(21^2 - 4*(1/2)*9.8*(0))) / (2*(1/2)*9.8)

 = (-21 ± sqrt(441)) / 9.8

Since we are only interested in the positive value of t, we can ignore the negative solution. Calculating t:

t = (-21 + sqrt(441)) / 9.8

 = (-21 + 21) / 9.8

 = 0 / 9.8

 = 0

Therefore, the ball is in the air for 0 seconds.

2. Maximum height:

The maximum height reached by the ball can be found using the formula:

v^2 = u^2 + 2gh ,

where:

v = final velocity (0 m/s at maximum height)

u = initial velocity (21 m/s upward)

g = acceleration due to gravity (approximately 9.8 m/s^2)

h = height

Solving for h:

0^2 = (21 m/s)^2 + 2*(-9.8 m/s^2)*h

441 = 2*(-9.8)*h

h = 441 / (-19.6)

  ≈ -22.5 m

Since the height cannot be negative in this context, we discard the negative value. Therefore, the maximum height reached by the ball is approximately 22.5 meters above the ground.

3. Velocity when it hits the ground:

When the ball hits the ground, its velocity will be downward. The final velocity can be found using the equation:

v = u + gt ,

where:

v = final velocity

u = initial velocity (21 m/s upward)

g = acceleration due to gravity (approximately 9.8 m/s^2)

t = time in the air (0 seconds)

Plugging in the values:

v = 21 m/s + (9.8 m/s^2)*(0 s)

 = 21 m/s

Therefore, the velocity that the ball hits the ground with is 21 m/s downward.

Answer:

1.63 N

Explanation:

F = GMm/r^2

  = (6.67x10^-11)(10x10^5)(3x10^5) / 3.5^2

  = 1.63 N  ( 3 sig. fig.)

The energy delivered in each pulse is 690 Joules. The average value of the magnitude of the electric field is  1.303 × 10¹¹ V/m.

A region of space surrounding an electrically charged particle or object known as an electric field is one in which an electric charge would experience force. A vector quantity called an electric field can be represented by arrows pointing in the direction of or away from charges.

Pulse emitted = 2.9 × 10(-9) s

Radius = 4.1 × 10⁻³ m

Power= 2.38 × 10¹¹ W

Energy = U=P × t

=2.9 × 10⁻⁹ ×2.38 × 10''

= 690 Joule

The electric field RMS value is given by

S= P/A = cε₀ E²(rms)

\(E_{rms}= \sqrt{\frac{P}{Ac\epsilon_{0}} } \\=\sqrt{\frac{2.38\times 10^{11}}{\pi((4.1\times10^{-3})^{2})(3\times10^{8})(8.85\times10^{-12})}\)

= 1.303 × 10¹¹ V/m

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The x-component of the acceleration of the box is given by the product of the acceleration a and the cosine of the angle theta between the force and the x-axis.

The x-component of the acceleration of the box can be found using the following formula:

a_x = F_x / m

Since the force is acting at an angle, we need to first find the x-component of the force, which can be calculated using:

F_x = F × cos(theta)

Assuming that the force F is the net force acting on the box and there are no other forces acting on it, we can use Newton's second law to find the magnitude of the force:

F = ma

where F is the net force, m is the mass of the box, and a is the acceleration of the box.

Therefore, the x-component of the acceleration of the box can be calculated as:

a_x = F_x / m

= (F × cos(theta)) / m

= [(ma) × cos(theta)] / m

= a × cos(theta)

where we have substituted the expression for the magnitude of the force from Newton's second law.

So, the x-component of the acceleration of the box is given by the product of the acceleration a and the cosine of the angle theta between the force and the x-axis.

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Answer: Δx = vxt = (85 m/s)(9s) = ? m

Explanation:

If the plane is in level flight,

Δx = vxt = (85 m/s)(9s) = ? m

Note that if Δx ≠ 0, it will not land on the car.

The values for the horizontal displacement and repositioning of the car are;

As it falls, the backpack will have a maximum horizontal displacement (away from the car) of 795 meters

The car should remain in its current position; Do not move the car

The reason the above values are correct is as follows;

The known information about the airplane, the backpack and the car are;

The speed of the airplane = 85 m/s

The time it takes the backpack to fall to the ground, t = 9 seconds

The position of the airplane when the backpack is dropped = Directly over the brand new car

Required:

Solution to the first question:

The horizontal displacement of the backpack = Horizontal velocity × Time, t

According to Newton's First Law of motion, the velocity of the backpack at the point it was dropped is the same as the velocity of the airplane

Given that the velocity of the airplane given is the horizontal velocity, we have;

The horizontal velocity of the backpack = 85 m/s

The displacement of the backpack = 85 m/s × 9 s = 795 m

Solution to the second question:

Given that the backpack will land 795 meters in front, away from the car, the car is safe if it remains in its current position

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The magnitude of the resultant force on the elliptical back will be equal to the difference between gravity and normal force.

The weight of the water and the force of gravity pressing on it determine the size of the resulting force on the elliptical tank truck. The water in the tank truck serves as a weight, creating a force of gravity proportionate to its mass. This force acts vertically downwards and is equal to the weight of the water, which can be estimated by multiplying the mass of the water by the gravity acceleration (g = 9.8 m/s^2).

When the tank truck is half full, the weight of the water may be estimated by multiplying the volume of water by its density and gravity acceleration. The volume of water may be calculated by taking the volume of the elliptical tank and dividing it by half. Water's density is constant and equal to 1000 kg/m3.

The total of the vertical components of gravity and normal force equals the size of the resulting force on the elliptical tank truck. The normal force is equal to the weight of the water and acts vertically upwards, against the force of gravity.

The amount of the resulting force on the elliptical back may be calculated by calculating the weight of the water, determining the force of gravity operating on it, and taking into account the normal force acting in the opposite direction.

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The given statement "A spring is hung from the ceiling. When a block is attached to its end, it stretches 3.0 cm before reaching its new equilibrium length. The block is then pulled down slightly and released" is True. When the block is attached to the spring, it causes the spring to stretch due to the weight of the block.

The amount of stretch is 3.0 cm, which is the difference between the new equilibrium length with the block attached and the original length of the spring without the block.

When the block is pulled down slightly and released, it will oscillate up and down around the new equilibrium length. This is because the spring has been stretched beyond its original length and now has potential energy stored in it. When the block is released, this potential energy is converted into kinetic energy, causing the block to accelerate toward the equilibrium position.

As the block reaches the equilibrium position, it will momentarily stop before continuing to move in the opposite direction. This is because the potential energy stored in the spring is now converted back into kinetic energy, causing the block to accelerate towards the other extreme position. The block will continue to oscillate back and forth until it eventually comes to a stop due to frictional forces.

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A ferris wheel having a radius of 8 m has a velocity of 8 m / s. is there a danger of the riders flying off .  No, the ferris wheel is not moving too fast.

What is a velocity?

Velocity may be a vector quantity that refers to "the rate at which an object changes its position." Imagine an individual moving rapidly - one step forward and one step back - always returning to the original starting position. While this might end in a frenzy of activity, it might result in a zero velocity.

What is the two types of velocity?

Constant velocity: is that the speed at which an object travels equal displacements in equal times. Variable velocity: it's the speed at which an object cuts different displacements at different times.

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Answer:

2. Letter C all those in the list are non living

3. Letter A a skunk is a living organism that shapes its environment

5. Letter A when talking about population it usually refers to a single type of species in that area

6. Letter B Niche (just recently heard of the word in ecology)

(a) The mechanical advantage of the ramp is determined as 2.5.

(b) The pulley provides additional advantage since it assisted the boy in pulling up the load.

The mechanical advantage of an object is the ratio of output force to input force, hence it is called force ratio.

M.A = Lp/h

where;

M.A = 10/4

M.A = 2.5

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Answer:

Option (B).

Explanation:

Given that,

Speed of Pam is 50 km/h

Force acting on an object is given by: F = ma

Pam is driving a car, and Dave is riding in the front passenger seat. Both are wearing seatbelts. As Dave's mass is 1.5 times that of Pam. It means that Dave experiences 1.5 times the force that Pam experiences.  

Hence, the correct option is (B).

Answer:

gkcfgggxg hhfdc ghgffgccvvc

bjvhgf

Explanation:

gjhghujj bhhgghj

The force applied to the box multiplied by 10m equals the work performed on the box from x = 0m to 10m.

The work done on the box from x = 0m to 10m is the product of the force applied on the box and the displacement of the box. The work done is calculated as:

Work = Force × Displacement

Therefore, the work done on the box from x = 0m to 10m is:

Work = Force Applied × (10m - 0m)

work = Force Applied × 10m

Therefore, the work done on the box from x = 0m to 10m is equal to the force applied on the box multiplied by 10m.

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We will have the following:

First, we know that the centripetal acceleration is given by:

So, the centripetal acceleration is:

The distance the spring compresses when the potatoes are dropped from a height of 15.3 m is four times greater than the distance it compresses when dropped from a height of 3.9 m.

When an object is dropped, its potential energy is converted into kinetic energy as it falls. The potential energy is given by the equation PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. As the potato sacks have the same mass, the potential energy is directly proportional to the height.

The compression of a spring is related to the potential energy transferred to it. According to Hooke's law, the force exerted by a spring is proportional to its compression. Since the potential energy is proportional to the height, and the force is proportional to the compression, we can conclude that the compression of the spring is also proportional to the height.

Therefore, when the potatoes are dropped from a height of 15.3 m compared to 3.9 m, the height increases by a factor of approximately four. Consequently, the distance the spring compresses will also increase by a factor of four.

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Answer:

FN=-Fg -> Fg=mg -> Fg = 238 kg*9.8 m/s^2 ->

Fg = -2432.4 so FN = 2432.4 -> FF = μs*FN ->

FF = 0.22*2332.4 N -> FF = 513.128 ->

Fapplied > 513.128 N

Explanation:

...

Answer:

Explanation:

The force on a charged particle moving in a magnetic field can be calculated using the formula:

F = qvBsinθ

where

F is the force on the particle

q is the charge of the particle

v is the velocity of the particle

B is the magnetic field strength

θ is the angle between the velocity and magnetic field vectors.

In this case, the charge on the particle is +3.0x10^-6C, its velocity is 300,000m/s, and the magnetic field is 1.4T. The angle between the velocity and magnetic field vectors is 90° because the particle is moving perpendicular to the magnetic field.

So, plugging in the values to the formula, we get:

F = (3.0x10^-6C)(300,000m/s)(1.4T)sin90°

F = (3.0x10^-6C)(300,000m/s)(1.4T)(1)

F = 1.26x10^-2 N

Therefore, the force on the particle is 1.26x10^-2 N to the left of the page, perpendicular to the velocity of the particle.

Answer:

Newton's first law

Explanation:

it says that an object will continue to be at rest or keep moving till any external for is applied to it to make it move or stop respectively.