PLEASE HELP ME!!
I am smaller than Rb and bigger than Na but we are in the same family.
H
K
N
Cs
Is it easier to remove an electron from Mg or from Cl?
Mg
Cl

Answer:

Cd(s) + CuSO4(aq) = Cu(s) + CuSO4(aq)

Explanation:

cadmium metal is a solid, so it will be labeled as Cd(s)

"reacts with a" means it is adding something: so the symbol will be "+"

copper (ll) sulfate is CuSO4, and "solution of" means it is aqueous "aq"

"to produce" means it is creating something, so instead of the "=" it would be an arrow

pure copper is labeled as Cu, and it is a solid

it repeats "solution of cadmium (II) sulfate" so it becomes CuSO4(aq)

6 moles of water will be produced. after analyzing the stoichiometry of the equation, where the number of water molecules is divided by the molecular mass of water which is 18 grams.

What are Moles?

Standard scientific unit for calculating the number of atoms, molecules, or other specific particles in vast amounts. The mole designates 6.02214076 × \(10^{23}\) units, which is a very large number.

What is Stoichiometry?

To calculate the appropriate quantitative data, a chemistry concept known as stoichiometry uses relationships between the reactants and/or products of a chemical reaction. Understanding the relationships that exist between products and reactants and why they exist, which necessitates understanding how to balance reactions, is crucial before using stoichiometry to perform calculations regarding chemical reactions.

6 moles of water will be produced.

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Explanation:

a chemical nomenclature is a set of rules to generate systematic names for chemical compounds.

According to our question, we have a white powder at the end of this reaction.

The white powder responds to the baking soda (NaHCO3)

We can exclude from our options, B, D, E because they are products, not reactants.

Thus, we have A and C.

One part of our text says: "When the reaction is finished, there is white powder at the bottom". This power is the NaHCO3, and it means that when the reaction finishes, this compound remains. Therefore is the excess.

So, our limiting reactant is C.) CH3COOH (vinegar)

Answer: C.) CH3COOH (vinegar)

The term that refers to the passing of a wave through an object is "transmission."

Transmission refers to the process by which a wave passes through an object or medium. In the context of sound, transmission occurs when sound waves travel through different substances, such as air, water, or solids.

When a sound wave encounters an object, it can be transmitted through it, reflected off it, or absorbed by it, depending on the properties of the object and the medium through which the sound is traveling.

For example, when you speak into a microphone, the sound waves produced by your voice travel through the air and are transmitted to the microphone's diaphragm. The diaphragm converts the sound waves into electrical signals, which can then be amplified and reproduced as sound through speakers.

In summary, transmission is the term used to describe the passage of a wave, such as a sound wave, through an object or medium. It is an essential concept in understanding how waves interact with their surroundings and how sound propagates through different materials.

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Answer:

3000000000000009000000

The density of air at exactly 35°C and 1.00 atm (assuming that air is 80.0 percent N2 and 20.0 percent O2 is 1.1 g/L.

Density is described as the substance's mass per unit of volume.

Density of a gas d is given as  = PM/ RT

where d ⟶ Density of the gas

P ⟶ Pressure of the gas

M⟶ Molar Mass of the gas

R⟶ Universal Gas Constant

T⟶ Absolute temperature

we have that the pressure of air is P=1.00 atm, and the temperature is T=35∘C=308K.  The molar mass of air can be assumed to be the weighted average of its components.

The air is 80% nitrogen and 20% oxygen, so 1 mole of air will contain 0.80 moles of nitrogen and 0.20 moles of oxygen. So, the molar mass of air will be:

Molar Mass of air= 0.80 MN2 + 0.20MO2 = 0.80 (28.00g/mol) + 0.20 (32.00g/mol) = 28.8 g/mol

Substituting the values into the equation of d = PM/ RT, we have

density = 1.1g/L

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Answer:

c. pH=-log[H+]

Explanation:

pH=-log10[H+]

The sample of air should be heated to 252 Kelvin (K) to increase its volume by 25%.

It is possible to determine the temperature to which the sample of air should be heated by using the concept of the ideal gas law. PV = nRT is the ideal gas law, and it relates the pressure (P), volume (V), number of moles (n), temperature (T), and gas constant (R). we can focus on the relationship between volume and temperature since the number of moles and pressure are assumed to be constant.

By showing the increase in volume as a percentage (25%), we can make the equation (V+0.25V)/T = V/T, where V represents the initial volume of the air.

On making the equation simple, we find  Tfinal / Tinitial = 1.25.

To solve for Tfianal, the final temperature,

Tfinal = Tinitail / 1.25

On substituting the initial temperature value of 315K into the equation, we will be getting;

Tfinal = 315K / 1.25

Tfinal = 252K

Hence, the sample of air should be heated to 252 Kelvin (K) in order to increase its volume by 25%.

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The question is incomplete, the complete question is shown in the image attached.

The ion that is not isoelectronic with the noble gas neon is O^2+.

To be "isoelectronic" means to have the same number of electrons. When we say that a specie is isoelectronic with the noble gas neon, we mean that the specie has 10 electrons just as neon does.

All the ions listed in the options have 10 electrons except O^2+ which has six electrons.

Therefore, the ion that is not isoelectronic with the noble gas neon is O^2+.

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In this exercise we will use Maxwell botzamn's knowledge of distribution to explain what happens, like this:

The Maxwell-Boltzmann distribution describes the distribution of velocities between particles in a sample of gas at a given temperature.

Then we can analyze that the graph referring to the boltzman distribution will be:

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The number of mole of cyclopentadiene present in the solution is 0.0232 mole.

We'll begin by converting 5.8 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

5.8 mL = 5.8 / 1000

Finally, we shall determine the number of mole of cyclopentadiene present in the solution. This can be obtained as follow:

Volume = 0.0058 L

Molarity = 4 M

Mole = Molarity x Volume

Mole = 4 × 0.0058

Therefore, the number of mole of cyclopentadiene present in the solution is 0.0232 mole.

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The stoichiometric table and the rate law for the given elementary liquid phase reaction have been constructed. The rate constant and activation energy have been calculated, and the type of reaction energy has been specified as endothermic.

Stoichiometric table in terms of concentrations:

The stoichiometric table for the given reaction can be constructed as follows:

A + 2B → products

                             A                                B                                products

Feed         0.3*Cf                        0.7*Cf                                       0

Exit              (0.3-0.3X)*C             (0.7-0.7X)*C                                0

Change         -0.3XC                      -0.7XC                                     0

Where:

Cf = Total feed concentration

C = Concentration inside reactor

X = Conversion of A

Rate of reaction of A:

The rate of the reaction can be expressed as:

rA = -1/2 * dCA/dt = k*C^2

where, CA is the concentration of A and k is the rate constant.

Since the reaction is elementary, the rate law is proportional to the concentrations of the reactants raised to their stoichiometric coefficients.

The rate of disappearance of A = rate of appearance of B

rB = -dCB/dt = 2*rA

Therefore, the rate of reaction of A can be expressed as:

rA = (0.7Cf - 0.7C)/V = k*C^2

Substituting values, we get:

rA = (0.710 - 0.70.7X)/5 = k(0.3 - 0.3*X)^2

Calculation of k and E:

The rate constant k can be calculated using the Arrhenius equation:

k = A * exp(-Ea/RT)

where A is the frequency factor, Ea is the activation energy, R is the gas constant and T is the temperature in Kelvin.

Assuming the activation energy is 50 kJ/mol, we can calculate the rate constant at the given temperature of 333 K:

k = 0.00717 * exp(-50000/(8.314*333)) = 0.0001504

The reaction energy can be determined by calculating the activation energy using the rate constant at two different temperatures. Assuming the rate constant at 323 K is 0.000098, we can solve for Ea:

ln(k2/k1) = Ea/R * (1/T1 - 1/T2)

ln(0.000098/0.0001504) = Ea/8.314 * (1/323 - 1/333)

Ea = 43775 J/mol

The positive value of the activation energy indicates that the reaction is endothermic.

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Answer:

H₂O = 3.56 moles

MgCl₂ = 1.78 moles

Explanation:

The correct answer is A. The sample is not a heterogeneous mixture

Explanation:

A heterogeneous mixture includes two or more materials and these are not completely integrated. Due to this, in most cases, if a heterogeneous mixture is filtered it is possible to separate its parts. This did not occur when Ben filtered the substance, which shows it is likely the substance is not a heterogeneous mixture. Moreover, a heterogeneous mixture does not show uniformity in terms of appearance or properties, which shows this definitely not heterogenous and Ben can safely conclude this.

Answer:

true

Explanation:

because scientist are discovering new things everyday.

Answer:đúng nhé người ae

Explanation:

To convert the given number to regular notation, we have to move the decimal dot as many times as indicated by the exponent of 10. In this case, that exponent is -4, so we have to move the decimal dot 4 times to the left:

It means that the answer is 0.000875.

Answer:

Explanation:

To determine the mass of NaCl in 1.25L of 0.1035M solution, we can use the formula:

mass = concentration x volume x molar mass

where concentration is in molarity (M), volume is in liters (L), and molar mass is in grams per mole (g/mol).

The molar mass of NaCl is 58.44 g/mol.

Plugging in the given values, we get:

mass = (0.1035 M) x (1.25 L) x (58.44 g/mol)

mass = 7.3188 g

So, there is approximately 7.3188 grams of NaCl in 1.25L of 0.1035M solution.

Answer: A pencil

Explanation: The pencil has the least strength than the other objects.

Metal conductivity generally goes down or resistivity goes up with temperature goes up.

The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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Answer:

9.3×1015 atoms Pb make up 1.5×10−8mol Pb

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

Answer:

0.295 mol/L

Explanation:

Given data:

Volume of solution = 3.25 L

Mass of BaBr₂ = 285 g

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of solute:

Number of moles = mass/ molar mass

Molar mass of BaBr₂ = 297.1 g/mol

Number of moles = 285 g/ 297.1 g/mol

Number of moles= 0.959 mol

Molarity:

M = 0.959 mol / 3.25 L

M = 0.295 mol/L

Answer:

the boiling point of solution at 3 decimal point is 100.329०C Ans.

Explanation:

given data -

molality of Nacl = 0.321 m

molal boiling point elevation constant (Kb) =0.512०C/m

# formula of change of boiling point of sample =

∆ Tb =i × Kb × m

Kb = molal boiling point of elevation constant

m = molality

i = vont's hoff factor.

Nacl is strong electrolyte and its 100% dissociate so the value of i for Nacl is 2

put value in the formula

∆ Tb = 2 × 0.512 ०C/m × 0.321m

= 0.3287

= 0.329०C

∆Tb = T'b - Tb

T'b = boiling point of solution

Tb= boiling point of solvent( water)

0.329०C = T'b - 100०c ( boiling point of water = 100०C)

T'b = 0.329०C + 100०C

= 100.329०C

hope this helps

Answer:

1.E25 it is the answer the answer to mass of 1×10^25 molecules of water​

Explanation:

this is just EXPLINATION find your answer using this

first divide the number of molecules by Avogadro's number 6.022*10^25

you will

l get no. of Moles of water

multiply the no. of Moles with mass of 1 Mole of water 18g per mole

if get answer you comment

you should try on your own you will understand better

When the reaction of  Grignard reagent reacted with methanol will yield a tertiary alcohol. Therefore, Option C tertiary alcohol is correct.

Contains a carbon-metal link, Grignard reagents are chemicals used in catalysis. They generally result from the anhydrous reaction of magnesium metal with an alkyl or aryl halide. Because of their high reactivity, Grignard reagents frequently act as nucleophiles in organic reactions.

An alkyl group from a Grignard reagent binds to the oxygen atom of methanol (CH3OH) when it interacts with the methanol, breaking the carbon-metal connection. A precursor alkoxide is created as a result. The equivalent alcohol is then produced by protonating the intermediate alkoxide.

The reaction of a Grignard reagent with methanol leads to the formation of a tertiary alcohol.

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Answer:

\(m=406.26g\)

Explanation:

Hello,

In this case, since the density is defined as the degree of compactness of a substance and it mathematically defined as the ratio of the mass and volume:

\(\rho = \frac{m}{V}\)

By knowing that its density is 1.11 g/mL, the mass in 366 mL is:

\(m=\rho V=366mL*1.11\frac{g}{mL}\\ \\m=406.26g\)

Regards.

Answer:

4 millllllermeeters jb