Answer:
3. DC ≅ CA
4. Vertical Angles Theorem
6. CPCTC
Step-by-step explanation:
I hope this helps :)
Which function is the inverse of f(x)= -x^3 -9?
Answer:
B. \(\sqrt[3]{-x-9}\)
Step-by-step explanation:
Switch x and y, and then solve for y.
\(y = -x^3-9\\x=-y^3-9\\x+9=-y^3\\-x-9=y^3\\\sqrt[3]{-x-9} =y\)
PLEASE HELP FAST!!♡
For f(x) = -x+2 and g(x) = x + 4, find f(x) = g(x).
Answer: x=-1
Step-by-step explanation:
There is a pair of parallel sides in the following
shape.
24
3
units²
10
25
What is the area of the shape?
The parallel sides are 24 units and 25 units, and the distance between them is 10 units (the height of the trapezoid) the area of the shape is 245 square units.
what is trapezoid?
A trapezoid is a geometric shape with four sides, where two of the sides are parallel to each other, but the other two sides are not. The parallel sides are called the bases of the trapezoid, and the other two sides are called the legs. The height of the trapezoid is the perpendicular distance between the two bases.
The shape in the image is a trapezoid, which has a formula for its area:
Area = (1/2) x (sum of parallel sides) x (distance between parallel sides)
In this case, the parallel sides are 24 units and 25 units, and the distance between them is 10 units (the height of the trapezoid).
Plugging these values into the formula, we get:
Area = (1/2) x (24 + 25) x 10
Area = (1/2) x 49 x 10
Area = 245 units²
Therefore, the area of the shape is 245 square units.
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Answer:the answer is wrong I did this and i got it wrong
Step-by-step explanation:
at most, how many references in this line could be null and might cause the nullpointerexception to be thrown?
None. There are no references in this line. This line does not contain any references, so no references can be null. Therefore, no NullPointerException can be thrown.
This line does not contain any references, so no references can be null. Therefore, no NullPointerException can be thrown.
This line of code does not contain any references at all. Therefore, it is not possible for any references to be null, and it is impossible for a NullPointerException to be thrown in response to this line. NullPointerExceptions are only thrown when a program attempts to use a reference that is null, but this line does not contain any references, so such an exception is not possible. Consequently, no references can be null in this line and no NullPointerException can be thrown.
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Im not sure what the solution is-
Answer: it’s -0,6 which is C
Step-by-step explanation:
The table shows the amounts A (in billions of dollars) budgeted for national defense for the years 1998 to 2004. (Source: U.S. Office of Management and Budget)
(a) Use a graphing utility to create a scatter plot of the data. Let t represent the year, with t = 8 corresponding to 1998.
(b) Use the regression feature of a graphing utility to find a quadratic model for the data.
(c) Use a graphing utility to graph the quadratic model with the scatter plot from part (a). Is the quadratic model a good fit for the data?
(d) Use the model to estimate the amounts budgeted for the years 2005 and 2010.
(e) Do you believe the model is useful for predicting the national defense budgets for years beyond 2004?
(a) A scatter plot of the data is shown below.
(b) A quadratic model for the data is y = 5.58x² - 85.53x + 601.96.
(c) Yes, the quadratic model is a good fit for the data.
(d) An estimate of the amounts budgeted for the years 2005 and 2010 are $575 billion and $1123 billion respectively.
(e) Yes, I believe the model is useful for predicting the national defense budgets for years beyond 2004.
How to construct and plot the data in a scatter plot?In this exercise, we would plot the years on the x-axis of a scatter plot while the defense budget would be plotted on the y-axis of the scatter plot through the use of Microsoft Excel.
Part b.
On the Microsoft Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display a quadratic model of the line of best fit (trend line) on the scatter plot;
y = 5.58x² - 85.53x + 601.96
Part c.
Based on the equation of the line of best fit and the trend line above, we can reasonably infer and logically deduce that the quadratic model a good fit for the data.
Part d.
Based on the equation of the line of best fit above, the amounts budgeted for the year 2005 is given by:
Years, x = 1998 to 2005 = 15 years.
y = 5.58(15)² - 85.53(15) + 601.96
y = 574.51 ≈ $575 billion
Years, x = 1998 to 2010 = 20 years.
y = 5.58(20)² - 85.53(20) + 601.96
y = 1123.36 ≈ $1123 billion
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
4. The term containing the highest power of x in the polynomial f(x) is 4x^4. Given that f(x) = 0
has 2 roots -2 and 3, and that 2x² + 3x + 2 is a quadratic factor of f(x),
(a) express f(x) as a polynomial in descending powers of x,
We're given \(f(x) = 0\) when \(x=-2\) and \(x=3\), so both \(x+2\) and \(x-3\) divide \(f(x)\)
We're also told \(2x^2+3x+2\) divides \(f(x)\). This quadratic does not have roots at -2 or 3, so we can factorize \(f(x)\) as
\(f(x) = 2 (x + 2) (x - 3) (2x^2 + 3x + 2)\)
where the leading coefficient is 2 because the full expansion should have a leading term of \(4x^4\).
Now just expand \(f(x)\) :
\(f(x) = 2 (x + 2) (x - 3) (2x^2 + 3x + 2)\)
\(f(x) = 2 (x^2 - x - 6) (2x^2 + 3x + 2)\)
\(f(x) = 2 (2x^4 + x^3 - 13x^2 - 20x - 12)\)
\(f(x) = \boxed{4x^4 + 2x^3 - 26x^2 - 40x - 24}\)
Ramon received a $100 bill as a graduation gift. He bought a game online for $24. 95. Then he bought a backpack for $39. 75 at a variety store. How much money did he have left after making the purchases?
Answer:
$35.30
Step-by-step explanation:
24.95+39.75 because this is the money he has spent.
This, in total, will be 64.7
Lastly, the problem states that Ramon has $100 in total, so you subtract.
$100-64.7=35.3
He has $35 and 30 cents left.
use traces to sketch and identify the surface 4x^2-16y^2 z^2=16
The surface given by the equation \(4x^2 - 16y^2 + z^2 = 16\) is a hyperboloid of two sheets. It consists of two distinct surfaces that intersect along the z-axis and open upwards and downwards.
To identify the surface defined by the equation \(4x^2 - 16y^2 + z^2 = 16,\) we can analyze the equation and determine its geometric properties.
First, let's rewrite the equation in a standard form:
\(4x^2 - 16y^2 + z^2 = 16\)
By rearranging terms, we have:
\((x^2/4) - (y^2/1) + (z^2/16) = 1\)
Comparing this equation to the standard form of a hyperboloid, we can see that the x and z terms have positive coefficients, while the y term has a negative coefficient. This indicates that the surface is a hyperboloid of two sheets.
The trace of the surface can be obtained by setting one variable constant and examining the resulting equation. Let's consider the traces in the xz-plane (setting y = 0) and the xy-plane (setting z = 0).
When y = 0, the equation becomes:
\(4x^2 + z^2 = 16\)
This represents an ellipse in the xz-plane centered at the origin, with the major axis along the x-axis and the minor axis along the z-axis.
When z = 0, the equation becomes:
\(4x^2 - 16y^2 = 16\)
This represents a hyperbola in the xy-plane centered at the origin, with the branches opening along the x-axis and the y-axis.
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identify the surface from the following equation \(4x^2-16y^2 z^2=16\)
A presidential candidate plans to begin her campaign by visiting the capitals in 3 of 47 states. What is the probability that she selects the route of three specific capitals? P(she selects the route of three specific capitals) 97290 (Type an integer or a simplified fraction:)
The probability that she selects the route of three specific capitals is 97290/1.
The probability that she selects the route of three specific capitals can be calculated by taking the total number of possible routes and dividing it by the total number of routes that involve the three specific capitals. To calculate the total number of possible routes, multiply the number of states (47) by the number of routes that could be selected from each state (2). This gives 94 total possible routes.
47 x 46 x 45 ways = 97290 ways
= 1/97290
Now, calculate the number of routes that involve the three specific capitals. Since the president is selecting three states, the total number of routes will be 3. Therefore, the probability that she selects the route of three specific capitals is 3/94, which can be simplified to 97290/1.
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Draw a function of dy/dx for the graphical below (image). Please help!
Step-by-step explanation:
Remember that
\( \frac{dy}{dx} \)
is the gradient or slope function.
So we need to analyze the slope of each graph over given time.l and how it changes.
For the 1st graph, we have a linear function.
Remember the special properties for all linear functions:
The slope at any two points on the line is the same.
So this means our slope here must be constant.
And since our slope is negative, our dy/dx, function must be a constant function that is negative. So
The answer for the first graph is draw a horizontal line underneath the x axis.
For the 2nd graph, we have a slope that is decreasing, reaches 0 at the minimum, then increases even more.
We can draw a linear function that is increasing forever for our dy/dx.
For the 3rd graph, we are increasing , till we hit 0, then decrease until we hit 0, then forever increases.
Our dy/dx will be a parabola that passes through the x axis twice at two different points, facing upwards.
The first , second, and third graph is the dy/dx graphs shown respectively.
All these are examples of possible graphs. If you need more clarification, let me know
simplify the expression
Answer:
24/64..........................
Step-by-step explanation:
hope this helped
Use the distributive properly to remove the parentheses. -(4w-y-3)
help for brainetest pls
Answer:
9 554/603
Step-by-step explanation:
If you add 2/6 and 8/9 you get 554/603. You could try simplifying this answer just to check but I don't think you can simplify it.
Answer:
10 2/9
Step-by-step explanation:
Solve the following proportion. x−2=57 x=?
Answer:
x = 59
Step-by-step explanation:
x−2=57
Add 2 to each side
x−2+2=57+2
x = 59
Answer:
X=59
Step-by-step explanation:
x−2=57
to isolate X you would have to add 2 to each side. x-2(+2)=x and 57(+2)=59
Which equation gives the number of 1/4 centimetre that are in 7/8 centimetres
Answer:
2/8
Step-by-step explanation:
4 - 3
0
4
-2
2
6
If A=
31 and B=
5
2.
0
find A-B.
-4
- 2
2
0
4
-4
5 01
9
3
4 3
00N
1
- 6
1
0
-6 11
12 0
20
2 0-11
-1 4 3
-6-1
4
-80
-1
Answer:
4
Step-by-step explanation:
the company has been a long term solution to the point that 666666
suppose a clothing store wants to determine the current percentage of customers who are over the age of forty. how many customers should the company survey in order to be 98% confident that the estimated (sample) proportion is within 2 percentage points of the true population proportion of customers who are over the age of forty?
The company survey 307 customers in order to get 98% confidence.
Sample proportion (p) = 0.5 (as no estimate is given)
α = 1 - 92% = 0.08. Therefore, α/2 = 0.08/2 = 0.04
Z(α/2) = Z(0.04) = 1.751
Estimate = 5% = 0.05
Now, E = Z(α/2) * sqrt (p(1-p)/n)
n = (1.751/0.05)2 * 0.5 * (1-0.5)
n = 307
Hence, the company should survey 307 customers in order to be 98% confident that the estimated (sample) proportion is within 2 percentage points of the true population proportion of customers who are over the age of forty.
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how many degrees of freedom are there for the numerator and denominator of an f test if there are three groups with ten participants in each? g
For an F-test with three groups, the degrees of freedom for the numerator would be 2 (number of groups - 1), and the degrees of freedom for the denominator would be 27 (total number of participants - number of groups). In an F-test, the degrees of freedom for the numerator and denominator are determined by the number of groups and the total number of participants.
Degrees of freedom for the numerator (between-groups):
This is calculated by subtracting 1 from the number of groups.
In this case, you have 3 groups, so the numerator degrees of freedom = 3 - 1 = 2.
Degrees of freedom for the denominator (within-groups):
This is calculated by subtracting the number of groups from the total number of participants.
In this case, you have 3 groups with 10 participants each, so there are a total of 3 x 10 = 30 participants. The denominator degrees of freedom = 30 - 3 = 27.
So, for this F-test, there are 2 degrees of freedom for the numerator and 27 degrees of freedom for the denominator.
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NEED HELP ASAP!!! PLSSSSSSSSSSSSSSSSSSSS
Answer:
p(x) = 6x - 15
Step-by-step explanation:
So, first you subtract the cost of the necklace from the revenue, equating to 6x. Then, you take your constant, 15, and plug it into the equation for profit, giving you the finished equation of p(x) = 6x - 15. Hope this helps! (:
Answer: p(x) = 6x - 15 Answer is B
Step-by-step explanation:
They are wanting to know p(x)
Given:
r(x) = 10x
c(x) = 4x +15
p(x) = r(x) - c(x) >substitute r(x) and c(x)
p(x) = 10x - (4x + 15) >Distribute -
p(x) = 10x - 4x - 15 >combine like terms
p(x) = 6x - 15 Answer is B
Identify the area of the circle. Use 22/7 for π
Answer:
The area of the given circle is,
\(A = 5819/350 cm^2 = 16.6257 cm^2\)
Step-by-step explanation:
Here, 4.6 cm is the diameter, d =4.6 cm
so, since the radius is d/2, we have,
r = 4.6/2 = 2.3
r = 2.3 cm
Now, the formula for area of a circle is,
A = π(r)^2 = π(r)(r)
Using 2.3 cm for r and 22/7 for π, we get,
\(A = \pi r^2\\A = (22/7)(2.3)^2\\\\A = 5819/350 cm^2 = 16.6257 cm^2\)
Hence we have found the area
In parts (a)-(e), involve the theorems of Fermat, Euler, Wilson, and the Euler Phi-function. (a) Show (4(29) + 5!) = 0 mod 31 (b) Prove a21 = a mod 15 for all integers a (e) If p,q are distinct primes and ged(a,p) = ged(a,q) = 1, prove ap-1)(-1) = 1 mod pa (d) Prove 394+5 = -2 mod 49 for all integers k
Using the theorem of Fermat, that if p is a prime number and gcd(a,p) = 1, then a^(p-1) = 1 mod p. Since 31 is a prime number, 4^30 = 1 mod 31 and 5! = 5 x 4 x 3 x 2 x 1 = 120 = 4 x 30 + 1. Therefore, 4(29) + 5! = 4^30 x 4(29) x 120 = 1 x 4(29) x 120 = 0 mod 31.
To prove a^21 = a mod 15 for all integers a, we use the Euler Phi-function which is defined as phi(n) = the number of positive integers less than or equal to n that are relatively prime to n. For any prime number p, phi(p) = p-1. Since 15 = 3 x 5, phi(15) = phi(3)phi(5) = 2 x 4 = 8. Therefore, a^8 = 1 mod 15 for all a such that gcd(a,15) = 1. Hence, a^21 = a^2 x a^8 x a^8 x a^2 x a = a mod 15 for all integers a.(e) Using the theorem of Wilson which states that (p-1)! = -1 mod p if and only if p is a prime number, we can prove that ap-1)(-1) = 1 mod pa if p and q are distinct primes and gcd(a,p) = gcd(a,q) = 1. Since gcd(a,p) = 1 and p is a prime number, we have (a^(p-1))q-1 = 1 mod p. Similarly, (a^(q-1))p-1 = 1 mod q. Multiplying these two equations together, we get a^(p-1)(q-1) = 1 mod pq. Hence, apq-1 = a^(p-1)(q-1) x a = a mod pq. Using the theorem of Euler, we know that a^(phi(pa)) = a^(p-1)(p-1) = 1 mod pa if gcd(a,pa) = 1. Since phi(pa) = (p-1)p^(k-1) for any prime number p and any positive integer k, we have ap(p-1)(p^(k-1)-1) = 1 mod pa. Thus, ap-1)(p^(k-1)-1) = -1 mod pa and ap-1)(-1) = 1 mod pa.(d) We can prove that 394+5 = -2 mod 49 for all integers k using the theorem of Euler which states that if gcd(a,n) = 1, then a^(phi(n)) = 1 mod n. Since 49 is a prime number, phi(49) = 49-1 = 48. Therefore, 5^48 = 1 mod 49. Hence, (394+5)^(48k+1) = (5+394)^(48k+1) = 5^(48k+1) + 394^(48k+1) = 5 x 394^(48k) + 394 mod 49 = 5 x (-1)^k + (-2) mod 49. Therefore, 394+5 = -2 mod 49 for all integers k.:The theorem of Fermat states that if p is a prime number and gcd(a,p) = 1, then a^(p-1) = 1 mod p. The theorem of Euler states that if gcd(a,n) = 1, then a^(phi(n)) = 1 mod n where phi(n) is the Euler Phi-function which is defined as phi(n) = the number of positive integers less than or equal to n that are relatively prime to n. The theorem of Wilson states that (p-1)! = -1 mod p if and only if p is a prime number. The problem is to use these theorems to solve the following problems.(a) Show (4(29) + 5!) = 0 mod 31Using the theorem of Fermat, we get 4^30 = 1 mod 31 and 5! = 120 = 4 x 30 + 1. Therefore, 4(29) + 5! = 4^30 x 4(29) x 120 = 1 x 4(29) x 120 = 0 mod 31.(b) Prove a^21 = a mod 15 for all integers aUsing the Euler Phi-function, we get phi(15) = phi(3)phi(5) = 2 x 4 = 8. Therefore, a^8 = 1 mod 15 for all a such that gcd(a,15) = 1. Hence, a^21 = a^2 x a^8 x a^8 x a^2 x a = a mod 15 for all integers a.(e) If p,q are distinct primes and gcd(a,p) = gcd(a,q) = 1, prove ap-1)(-1) = 1 mod paUsing the theorem of Wilson, we get (p-1)! = -1 mod p if and only if p is a prime number. Using the theorem of Euler, we get a^(p-1) = 1 mod p and a^(q-1) = 1 mod q. Multiplying these two equations together, we get a^(p-1)(q-1) = 1 mod pq. Hence, apq-1 = a^(p-1)(q-1) x a = a mod pq. Using the theorem of Euler, we get ap-1)(p^(k-1)-1) = -1 mod pa and ap-1)(-1) = 1 mod pa.(d) Prove 394+5 = -2 mod 49 for all integers kUsing the theorem of Euler, we get 5^48 = 1 mod 49. Hence, (394+5)^(48k+1) = 5 x 394^(48k) + 394 mod 49 = 5 x (-1)^k + (-2) mod 49. Therefore, 394+5 = -2 mod 49 for all integers k.
The theorems of Fermat, Euler, Wilson, and the Euler Phi-function are very useful in solving problems in number theory. These theorems are often used to prove various results in algebraic number theory, analytic number theory, and arithmetic geometry.
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Please help me ^^ This is due tomorrow
how to rewrite 3/4 with a denominator of 12
Answer:
it would be 9/12
Step-by-step explanation:
if you want to get a denominator of 12 you would have to multiply by 3 from both and you should get 9/12. 3*3=9 and 4*3=12.
Answer:
9/12
Step-by-step explanation:
4x3=12
because we are multiplying the denominator we also have to multiply the numerator by the same number
3x3=9
A car rental company charges a daily rate of $ 24 plus $ 0.10 per mile for a certain car. Suppose that you rent that car for a day and your bill (before taxes) is $ 37.00. How many miles did you drive?
_________miles
the fruity tooty company claims that the population proportion for each of its five flavors is exactly 20%. jane counts 92 red candies in a 400-count sample.z equals fraction numerator p with hat on top minus p over denominator square root of begin display style fraction numerator p q over denominator n end fraction end style end root end fraction using the formula and data provided, what is the value of the z-test statistic? answer choices are rounded to the hundredths place.
Value of the z-test statistic is 1.20.
How to find the value of the z-test statistic?To find the value of the z-test statistic, we need to calculate the sample proportion and the standard error of the proportion.
The sample proportion is:
p⁻ = 92/400 = 0.23
The standard error of the proportion is:
SE = √[(pq)/n] = √[(0.20.8)/400] = 0.025
where p = 0.2 and q = 0.8.
Now we can calculate the z-test statistic:
z = (p⁻ - p)/SE = (0.23 - 0.2)/0.025 = 1.2
Therefore, the value of the z-test statistic is 1.20.
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4x + 12% - 6 = 4 (4x + 1)
Solve
Answer:
x=-247/300 (there's a negative sign btw, its just kinda small)
Step-by-step explanation:
Answer:
x = -3
I don't know if this is right. It's probably not, but a great way to figure out math problems like these is this cite called math way it's basically a more advanced calculator. :D
The temperature in Ottawa starts at -4°C, rises 14°C, and then falls 8°C. What is the final temperature?
Answer:
2 degrees celsius
The final temperature in Ottawa is 2°C.
We have,
Given:
Initial temperature = -4°C
Temperature rise = 14°C
Temperature fall = -8°C
The formula to calculate the final temperature.
Final temperature = Initial temperature + Temperature rise + Temperature fall
Final temperature = -4°C + 14°C + (-8°C)
Simplify
Final temperature = -4°C + 14°C - 8°C
Final temperature = 2°C
Therefore,
The final temperature in Ottawa is 2°C.
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What's -2.505 as a fraction
Answer:
501/200
It told me I need more characters so here’s some random letters hehehajajjajaja
What is the relation between the sine and cosine values of angles in each quadrant? How would you use the 60° angle to find sine and cosine of 120°, 240°, and 300°? What angles could we find sine and cosine for using information for π/4 and π/6?
The angles, 60°, \(\displaystyle \frac{\pi}{4}\) and \(\displaystyle \frac{\pi}{6}\) are special angles that have known trigonometric ratio values.
First part;
The sine and cosine gives the coordinates of the tip of the radius of a unit circle as it rotates P(cos(θ), sin(θ))Second part;
With the knowledge of the sine and cosine of 60°, we have; sin(60°) = sin(120°), sin(240°) = -sin(60°), sin(300°) = -sin(60°)cos(120°) = -cos(60°), cos(240°) = -cos(60°), cos(300°) = cos(60°)Third part;
\(\displaystyle \frac{\pi}{4}\) can be used to find the sine and cosine of \(\displaystyle \frac{3 \cdot \pi}{4}\), \(\displaystyle \frac{5 \cdot \pi}{4}\), and \(\displaystyle \frac{7 \cdot \pi}{4}\) \(\displaystyle \frac{\pi}{6}\), can be used to find the sine and cosine of \(\displaystyle \frac{5 \cdot \pi}{6}\), \(\displaystyle \frac{7 \cdot \pi}{6}\), and \(\displaystyle \frac{11 \cdot \pi}{6}\)Reasons:
First Part;
Considering a unit circle with the center at the origin of the graph, we have;
The sine of the angle, θ, rotated by the radius is the vertical distance of a point P on the circle which is the location of the radius, from the horizontal axis.
The cosine of the angle, θ, is the horizontal distance of P from the vertical axis, such that we have;
The coordinates of point P = (cos(θ), sin(θ))
In the four quadrant, we have;
First Quadrant; All trigonometric ratios are positive
Second Quadrant; sine is positive
Third Quadrant; Tan is positive
Fourth Quadrant; Cosine is positive
Second part;
We have; At 120°, the point P is the same elevation from the horizontal axis, therefore;
sin(60°) = sin(120°) = 0.5·√3
However, the x-coordinate of the point P is in the negative direction, therefore, we get;
cos(120°) = -cos(60°) = -0.5
Similarly from the quadrant relationship, we have;
240° is in the third quadrant, and it is 60° below the negative horizontal line, therefore;
sin(240°) = -sin(60°) = -0.5·√3
cos(240°) = -cos(60°) = -0.5
300° is in the fourth quadrant, and it is 60° below the positive x-axis, therefore;
sin(300°) is negative and cos(300°) is positive
Which gives;
sin(300°) = -sin(60°) = -0.5·√3
cos(300°) = cos(60°) = 0.5
Third part;
\(\displaystyle \frac{\pi}{4} =45^{\circ}\)
\(\displaystyle \frac{\pi}{6} =30^{\circ}\)
The sine and cosine of 45° can be used to find the sine and cosine of (180° + 45°) = 225°, (360° - 45°) = 315°
Also, due to the mid location of the angle 45° on the quadrant, we have;
Another angles is the sines and cosine of (90° + 45°) = 135°
Therefore, \(\displaystyle \frac{\pi}{4}\), can be used to find the sine and cosine of 135°, 225°, and 315°
\(\displaystyle 135^{\circ} = \mathbf{\frac{3 \cdot \pi}{4}}\), \(\displaystyle 225^{\circ} = \frac{5 \cdot \pi}{4}\), \(\displaystyle 315^{\circ} = \frac{7 \cdot \pi}{4}\)
Therefore,
\(\displaystyle \frac{\pi}{4}\) can be used to find the sine and cosine of \(\displaystyle \mathbf{\frac{3 \cdot \pi}{4}}\), \(\displaystyle \mathbf{\frac{5 \cdot \pi}{4}}\), and \(\displaystyle \mathbf{ \frac{7 \cdot \pi}{4}}\)
Similarly, the sine and cosine of, \(\displaystyle \frac{\pi}{6}\) = 30° can be used to find the sine and cosine of 150°, 210°, and 330°.
\(\displaystyle 150^{\circ} = \frac{5 \cdot \pi}{6}\), \(\displaystyle 210^{\circ} = \frac{7 \cdot \pi}{6}\), and \(\displaystyle 330^{\circ} = \frac{11 \cdot \pi}{6}\)
\(\displaystyle \frac{\pi}{6}\), can be used to find the sine and cosine of \(\displaystyle \mathbf{ \frac{5 \cdot \pi}{6}}\), \(\displaystyle \mathbf{ \frac{7 \cdot \pi}{6}}\), and \(\displaystyle \mathbf{\frac{11 \cdot \pi}{6}}\)
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Answer:
Step-by-step explanation:
The cosine value of an angle is the x coordinate of the point the angle corresponds to on the unit circle, and the sine value of an angle is the y coordinate of that point. 120, 240, and 300 all form 60 degree reference angles which in turn forms 30-60-90 triangles which help to find the sine and cosine of these corresponding angles. Pi/4 radians converts to 45 degrees which forms a 45-45-90 special triangle on the unit circle which has its own known trigonometric ratio. Pi/6 radians converts to 30 degrees which forms a 30-60-90 triangle on the unit circle which also has a known trigonometric ratio. These ratios help find the sine and cosine of the angles on the unit circle which corresponds to a point on the coordinate plane.