please help please!!

If your argument leads to a misleading conclusion, it is probably unsound. It is also conceivable that the argument is sound but has a wrong premise.

If an argument has a faulty conclusion, either the premises are incorrect or the conclusion does not flow logically from the premises. This indicates that the reasoning is flawed.

An argument is deemed sound if all of its premises are true and it is valid (that is, the conclusion flows logically from the premises). Whether or not the conclusion is correct, the argument is flawed if any of the premises are untrue.

As a result, if your argument leads to a misleading conclusion, it is probably unsound. It is also conceivable that the argument is sound but has a wrong premise, in which case it is invalid.

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Main answer: The vector = ⟨-4,5⟩ of length 2 in the direction opposite to = ⟨1,2⟩ is: (-8/√5, 4/√5)

Supporting explanation: To find the vector of length 2 in the opposite direction of =⟨1,2⟩, we first need to find a unit vector in the same direction as =⟨1,2⟩, which can be found by dividing =⟨1,2⟩ by its magnitude:$$\begin{aligned} \left\lVert \vec{v}\right\rVert &=\sqrt{1^2+2^2} = \sqrt{5} \\ \vec{u} &= \frac{\vec{v}}{\left\lVert \vec{v}\right\rVert} = \frac{\langle 1,2 \rangle}{\sqrt{5}} = \langle \frac{1}{\sqrt{5}},\frac{2}{\sqrt{5}} \rangle \end{aligned}$$We can then multiply this unit vector by -2 to get a vector of length 2 in the opposite direction:$$\begin{aligned} \vec{u}_{opp} &= -2\vec{u} \\ &= -2\langle \frac{1}{\sqrt{5}},\frac{2}{\sqrt{5}} \rangle \\ &= \langle -\frac{2}{\sqrt{5}},-\frac{4}{\sqrt{5}} \rangle \\ &= \left(-\frac{8}{\sqrt{5}},\frac{4}{\sqrt{5}}\right) \\ &= \left(-\frac{8}{\sqrt{5}},\frac{4}{\sqrt{5}}\right) \cdot \frac{\sqrt{5}}{\sqrt{5}} \\ &= \boxed{\left(-\frac{8}{\sqrt{5}},\frac{4}{\sqrt{5}}\right)} \end{aligned}$$Therefore, the vector =⟨-4,5⟩ of length 2 in the opposite direction of =⟨1,2⟩ is (-8/√5, 4/√5).Keywords: vector, direction, unit vector, magnitude, length.

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False. if you are given a graph with two shif table lines, the correct answer will always require you to move both lines.

In a graph with two shiftable lines, the correct answer may or may not require moving both lines. It depends on the specific scenario and the desired outcome or conditions that need to be met.

When working with shiftable lines, shifting refers to changing the position of the lines on the graph by adjusting their slope or intercept. The purpose of shifting the lines is often to satisfy certain criteria or align them with specific points or patterns on the graph.

In some cases, achieving the desired outcome may only require shifting one of the lines. This can happen when one line already aligns with the desired points or pattern, and the other line can remain fixed. Moving both lines may not be necessary or could result in an undesired configuration.

However, there are also situations where both lines need to be shifted to achieve the desired result. This can occur when the relationship between the lines or the positioning of the lines relative to the graph requires adjustments to both lines.

Ultimately, the key is to carefully analyze the graph, understand the relationship between the lines, and identify the specific criteria or conditions that need to be met. This analysis will guide the decision of whether one or both lines should be shifted to obtain the correct answer.

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Given that each side of a square is increasing at a rate of 4 cm/s. At what rate is the area of the square increasing when the area of the square is 64 cm²?We are required to find the rate of increase of the area of a square when its area is 64 cm². Let us begin with what we know about the square.

Let the side of the square be s at any time. Now, when the sides of a square increase, the area of the square also increases proportionally by the square of the length of the sides. Thus, when the side is s, the area is s². Now, when the side of the square increases by ds/dt = 4 cm/s, the side becomes s + ds and the area becomes (s + ds)² or s² + 2*s*ds + (ds)². Now, we need to determine the rate at which the area of the square is increasing. Thus, we differentiate the area with respect to time, t.dA/dt = d/dt(s² + 2*s*ds + (ds)²)We know that the rate of increase of the side of the square is ds/dt = 4 cm/s. Thus, we can  the value of ds in the above equation. dA/dt = d/dt(s² + 2*s*ds + (ds)²)= d/dt(s²) + d/dt(2*s*ds) + d/dt(ds²)Let us differentiate each term separately.= 2s*ds/dt + 2s*ds/dt + 2ds/dt²= 4s*(4) + 2(4)(ds)²On substituting s = 8 and ds/dt = 4 cm/s, we get: dA/dt = 2 * 8 * 4 + 2 * 4 * 4= 64 + 32= 96 cm²/sThus, the rate at which the area of the square is increasing is 96 cm²/s when the area of the square is 64 cm².

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2.length of the rectangle

3.pi times the diameter.

4.The length of the rectangle is equal to the radius of the circle.

5. pi.

6.Area of (rectangle) = pi times the square of the radius.

The distance around a circle is known as its circumference. It is the circumference or length of the circle's whole boundaries. The circumference can be calculated by using the formula C = 2πr or C = πd, where r is the radius of the circle and d is the diameter of the circle. The value of π is a mathematical constant that is approximately equal to 3.14159.

2.The length of the rectangle approximates the length of one-half of the circumference of the circle.

3. π times the diameter equals the circumference of a circle.

4.The length of the rectangle is equal to the radius of the circle is 2.

5.The ratio of the circumference to the diameter is pi.

6.Area (circle) = Area of (rectangle) = pi times the square of the radius.

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Answer: B (The cost of a notebook is $0.75, and the cost of a folder is $0.25.)

Step-by-step explanation:

No need for explanation. i know i’m right!!

Triangle with sides AB = 8cm , CA = 5cm , BC = 7cm and AB = 7cm , BC = 10cm , CA = 8cm can construct a Triangle.

Condition : For forming the triangle, the sum of two sides must be greater than the third side.

a.  AB = 4cm, CA = 3cm, BC = 10cm

   CA+BC=AB

   3+1=4

   4=4

Therefore, it cannot form a triangle because it is not satisfying the condition.

b.  AB = 8cm , CA = 5cm , BC = 7cm

    AB+CA>BC

    AB+BC>CA

    CA+BC>AB

    Therefore, it can form a triangle because it satisfies the condition.

c.  AB = 7cm, BC = 10cm, CA = 8cm

   AB+BC>CA

   AB+CA>BC

   BC+BC>AB

  Therefore, it can form triangle because it satisfies the condition.

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y = mx + b is the equation. m is slope and b is the y-intercept.

y = (2/3)x - 1

Answer: We can start solving this problem by using a system of equations. Let x be the number of plain glazed donuts Nicole buys, and y be the number of chocolate cake donuts she buys. We know that:

x + y = 20 (The total number of boxes of donuts she buys is 20)

4x + 5y = 91 (The total amount of money she spends is $91)

We can use the first equation to solve for one variable in terms of the other. For example, we can substitute x = 20 - y into the second equation:

4(20 - y) + 5y = 91

80 - 4y + 5y = 91

-4y + 5y = 91 - 80

y = 11

So Nicole bought 11 boxes of chocolate cake donuts. We can substitute that back into the first equation to find the number of plain glazed donuts she bought:

x + 11 = 20

x = 9

So Nicole bought 9 boxes of plain glazed donuts.

We can check our answer by substituting our values of x and y back into the original equations:

x + y = 9 + 11 = 20 (This is the total number of boxes of donuts she bought, which is 20)

4x + 5y = 4(9) + 5(11) = 91 (This is the total amount of money she spent, which is $91)

Both equations are true, so our solution is correct.

Step-by-step explanation:

Answer:

Circle Equation: ( x - 3.8 )^2 + ( y - 7.8 )^2 = 25/36

Step-by-step explanation:

* Knowing a circle equation is in the format (x – h)^2 + (y – k)^2 = r^2, with the center being at the point (h, k) and the radius being "r" *

Let us substitute values into this equation; provided ( 3.8, 7.8 ) is the center:

( x - 3.8 )^2 + ( y - 7.8 )^2 = r^2,

Now substitute value of r, or rather the radius 5/6:

( x - 3.8 )^2 + ( y - 7.8 )^2 = ( 5/6 )^2 ⇒

Circle Equation: ( x - 3.8 )^2 + ( y - 7.8 )^2 = 25/36

* Sorry this wasn't answered earlier *

Answer:

5400 + 351 = 5751

Step-by-step explanation:

Answer:

6x - 3 + 4x = 13

10x - 3 = 13

10x = 16

x = 1.6

Any equation whose solution is    x=1.6   has the same solution as this one has.

Step-by-step explanation:

The Mitchells should report a total of $700 as dividend income on their joint return for Year 4.

Only the dividends received from Alert Corporation, a qualified domestic corporation, and Canadian Mines, Inc., a corporation incorporated in Canada, are taxable. The dividend from Eternal Life Mutual Insurance Company is not taxable since it is a dividend on a life insurance policy and the total dividends received on the policy do not exceed the cumulative premiums paid.

Therefore, the taxable dividends are $400 + $300 = $700.

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Answer:

92kg is about 202.8 lbs

Step-by-step explanation:

The value of 92 in kg to lbs is 202.8 lbs

What is Kilo gram ?

Kilo gram can be defined as follows , one kilo gram is equals to thousand grams or one gram is equal to reciprocal of thousand.

Given ,

to find 92 in kg to lbs

So, we know that,

1 kg = 2.204

So, here for 92 kg

we need to multiply with 2.204

we get,

92 kg = 92 * 2.204

= 202.8

So, 92 kg = 202.8 lbs.

Therefore, the value of 92 in kg to lbs is 202.8 lbs

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The probability of exactly three successes in five trials of a binomial experiment with a 90% probability of success is 0.0729 or about 7.29%.

To find the probability of exactly three successes in five trials of a binomial experiment with a 90% probability of success, we can use the binomial probability formula:

P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)

Plugging in the values, we get:

P(X = 3) = (5 choose 3) * (0.9)^3 * (1 - 0.9)^(5 - 3)

= 10 * (0.9)^3 * (0.1)^2

= 0.0729

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Answer:

r = 6

Step-by-step explanation:

The value of radius of the sphere rounded to the nearest whole number is,

⇒ r = 6 cm

We have to given that,

Volume of a sphere = 905 cm

Since, We know that,

Volume of sphere = 4/3 (πr³)

Where, 'r' is radius of sphere.

Now, Substitute the given value, we get;

⇒ 905 = 4/3 (πr³)

⇒ 905 × 3 = 4 × 3.14 × r³

⇒ 2,715 = 12.56 × r³

⇒ r³ = 216.16

⇒ r = ∛216.16

⇒ r = 6 cm

Thus, The value of radius of the sphere rounded to the nearest whole number is,

⇒ r = 6 cm

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Answer:

y = (1/4)x + 0

or

y = (1/4)x

the (1/4) is supposed to be a fraction of 1 in the numerator and 4 in the denominator

Step-by-step explanation:

Answer:

y=1/4x

Step-by-step explanation:

the y-intercept is 0 because when x is 0 y is also 0

the slope is 1/4 because rise/run so if you increase y by 1, x increases by 4

Let x represent the number of winter olympics held in North America.

Let y represent the number of winter olympics held in Europe.

Let z represent the number of winter olympics held in North Asia.

The Winter Olympics have been held a total of 21 times on the continents of North America, Europe, and Asia.

This means that

x + y + z = 21

The number of European sites is 5 more than the total number of sites in North America and Asia.

This means that

y = x + z + 5

There are 4 more sites in North American than in Asia.

This means that

x = z + 4

These are the equations. We would solve simultaneously

The olympics was held 2 times in North America, 13 times in Europe and 6 times in Asia

Answer:

D because that the only that make sense

Step-by-step explanation:

Answer:

45

Step-by-step explanation:

1800 total

35 dollars per bike

75 bucks to sell bike

75-35= 40

40 bucks per bike

1800 divided by 40 = 45 so 45 bikes

Answer:

The answer is 47

Step-by-step explanation:

Subtract 73 from 26.

Answer:

I would say 180 subtracted by 81 would equal

Value of D= 99

A significance level of 0.10, we have enough evidence to conclude that the new copy machines have a significantly faster mean repair time compared to the older model.

To test if the new copy machines are faster to repair, we can set up the following null and alternative hypotheses:

Null Hypothesis (H₀): The mean repair time for the new copy machines is the same as the mean repair time for the older model.

Alternative Hypothesis (H₁): The mean repair time for the new copy machines is less than the mean repair time for the older model.

Let's perform a one-sample t-test to test these hypotheses. The test statistic is calculated as:

t = (sample mean - population mean) / (sample standard deviation / √(sample size))

Given:

Population mean (μ) = 93 minutes

Sample mean (\(\bar x\)) = 86.8 minutes

Sample standard deviation (s) = 14.6 minutes

Sample size (n) = 18

Significance level (α) = 0.10

Calculating the test statistic:

t = (86.8 - 93) / (14.6 / sqrt(18))

t = -6.2 / (14.6 / 4.24264)

t ≈ -2.677

The degrees of freedom for this test is n - 1 = 18 - 1 = 17.

Now, we need to determine the critical value for the t-distribution with 17 degrees of freedom and a one-tailed test at a significance level of 0.10. Consulting a t-table or using statistical software, the critical value is approximately -1.333.

Since the test statistic (t = -2.677) is less than the critical value (-1.333), we reject the null hypothesis.

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A random sample is a sample that is drawn from a population in such a way that each member of the population has an equal chance of being selected. The mean is a measure of central tendency that represents the average value of a set of data.

In this scenario, a simple random sample of size n was drawn from a population that is normally distributed. The sample mean, X, was found to be 112, and the sample standard deviation, s, was found to be 10.

(a) To construct an 80% confidence interval about us if the sample size, n, is 13, we can use the formula:

CI = X ± t(α/2, n-1) * s/√n

where t(α/2, n-1) is the critical value for the t-distribution with (n-1) degrees of freedom and α is the level of significance. For an 80% confidence interval, α = 0.2 and t(α/2, n-1) = 1.340. Thus, the confidence interval is:

CI = 112 ± 1.340 * 10/√13
CI = (103.76, 120.24)

(b) To construct an 80% confidence interval about p if the sample size, n, is 24, we can use the formula:

CI = p ± z(α/2) * √(p(1-p)/n)

where z(α/2) is the critical value for the standard normal distribution and p is the sample proportion. Since the population is normally distributed, we can assume that the sample proportion is also normally distributed. For an 80% confidence interval, α = 0.2 and z(α/2) = 1.282. Thus, the confidence interval is:

CI = 112/24 ± 1.282 * √(112/24 * (1-112/24)/24)
CI = (0.38, 0.68)

(c) To construct a 95% confidence interval about p if the sample size, n, is 13, we can use the same formula as in (b), but with α = 0.05 and z(α/2) = 1.96. Thus, the confidence interval is:

CI = 112/13 ± 1.96 * √(112/13 * (1-112/13)/13)
CI = (0.38, 0.78)

(d) Yes, we could have computed the confidence intervals using the formulas provided, as long as the assumptions of normality and independence were met. However, if the sample size was small or the population was not normally distributed, we would need to use different methods, such as the t-distribution or non-parametric tests.

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Answer:

Yes

NEED EXPLINATION PLEASE COMMENT BELLOW

Answer:

yes 4/3 is equivalent to 8/6

Step-by-step explanation:

8/6 divided both the numerator and the denominator by 2 you get 4/3.thus 8/6 is equivalent to 4/3

Answer:

-4(5m) = -20m

-4(-3) = 12

-20m + 12

Step-by-step explanation:

Answer: 11c^2

Step-by-step explanation:

(3c^2 - 8c^1 + 5) + (1c^2 - 8c^1 - 6)
5c^1 + 5 = 10c^1 + 1c^2 - 8c^1
-7c^1   -   6
K      C    C

7+ -6 = -1c^1

10c^1 + 1c^1= 11c^2

Answer:

The final expression is:

\(4c^{2}-16c-1\)

So, the option (B) is the correct one.

Step-by-step explanation:

The expression is as such:

\((3c^{2}-8c+5)+(c^{2}-8c-6)\)

Step 1: Remove the brackets:

\((3c^{2}-8c+5)+(c^{2}-8c-6)\\=3c^{2}-8c+5+c^{2}-8c-6\)

Step 2: Collect the like terms together:

\(3c^{2}-8c+5+c^{2}-8c-6\\=3c^{2}+c^{2}-8c-8c+5-6\)

Step 3: Take the common variable as a factor, and add accordingly:

\(3c^{2}+c^{2}-8c-8c+5-6\\\\\text{Take}~c^{2}~\text{as the factor between the first two terms:}\\(3+1)c^{2}-8c-8c+5-6\\\\\text{Take}~c~\text{as the factor between the third and fourth terms:}\\(3+1)c^{2}+(-8-8)c+5-6\\\\\text{Since the last two terms are integers, we can just add them normally}\\\\\text{Add the like terms and the integers now:}\\(3+1)c^{2}+(-8-8)c+5-6\\=(4)c^{2}+(-16)c-1\\\\\text{Remove the brackets:}\\4c^{2}-16c-1\)

The statements that are true about the given algorithms are: I. Algorithm 1 does not work on lists where the smallest value is at the start of the list or the largest value is at the end of the list.  II. Algorithm 2 does not work on lists that contain all negative numbers or all numbers over 1000.

Algorithm 1's reliance on initializing minVal to the first value and maxVal to the last value can lead to incorrect results if the smallest or largest value is not properly updated during the iteration. Similarly, Algorithm 2's fixed initial values for minVal and maxVal can result in incorrect differences when dealing with lists containing all negative numbers or all numbers over 1000.

It is important to consider these limitations and potential failure cases when choosing and implementing an algorithm for calculating the difference between the smallest and largest values in a list.

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Answer:

\(q=70\)

Step-by-step explanation:

The total angle measure of supplementary angles (straight angles like this one) will always equal \(180\)°, so the following equation can be used:

\(180-52-58=q→180-110=q→70=q\)

Answer:

not a real number

Step-by-step explanation:

any negative number under a square root sign, except for 0, isn't real

On evaluating the given roots,

(a) \($-(\sqrt[3]{8}) = -2$\)

(b) \($\sqrt[4]{-81}$\) is not a real number

(a) \($-(\sqrt[3]{8})$\):

The cube root of 8 is the number that, when raised to the power of 3, equals 8. In this case, the cube root of 8 is 2, because \(2^3 = 8\).

Since we have a negative sign in front of the cube root, the result will be the negative value of the cube root of 8.

Therefore, \($-(\sqrt[3]{8}) = -2$\).

(b) \($\sqrt[4]{-81}$\):

The fourth root of a number is the number that, when raised to the power of 4, equals the given number.

In this case, we are looking for the fourth root of -81.

However, the fourth root of a negative number is not a real number. This is because raising a positive number to an even power (in this case, 4) will always result in a positive value, and there is no real number that, when raised to the power of 4, gives a negative result.

Therefore, the fourth root of -81 is not a real number.

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If a function f is differentiable at a point a and f(a) is not equal to zero, then the absolute value function |f| is also differentiable at that point.

The proof involves considering two cases based on the sign of f(a) and showing that the limit of the difference quotient exists for |f| at point a in both cases. However, it is important to note that |f| is not differentiable at the point where f(a) equals zero.

To prove that if f is differentiable at a, then |f| is also differentiable at a, provided that f(a) ≠ 0, we need to show that the limit of the difference quotient exists for |f| at point a.

Let's consider the function g(x) = |x|. The absolute value function is defined as follows:

g(x) = {

x if x ≥ 0,

-x if x < 0.

Since f(a) ≠ 0, we can conclude that f(a) is either positive or negative. Let's consider two cases:

Case 1: f(a) > 0

In this case, we have g(f(a)) = f(a). Since f is differentiable at a, the limit of the difference quotient exists for f at point a:

lim (x→a) [(f(x) - f(a)) / (x - a)] = f'(a).

Taking the absolute value of both sides, we have:

lim (x→a) |(f(x) - f(a)) / (x - a)| = |f'(a)|.

Since |g(f(x)) - g(f(a))| / |x - a| = |(f(x) - f(a)) / (x - a)| for f(a) > 0, the limit on the left-hand side is equal to the limit on the right-hand side, which means |f| is differentiable at a when f(a) > 0.

Case 2: f(a) < 0

In this case, we have g(f(a)) = -f(a). Similarly, we can use the same reasoning as in Case 1 and conclude that |f| is differentiable at a when f(a) < 0.

Since we have covered both cases, we can conclude that if f is differentiable at a and f(a) ≠ 0, then |f| is also differentiable at a.

Note: It's worth mentioning that at the point where f(a) = 0, |f| is not differentiable. The proof above is valid when f(a) ≠ 0.

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