Answer:
I) Name of State of Matter: Solid
a) Property of this State of Matter: Definite shape and volume.
b) Property of this State of Matter: Generally have a higher density.
c) Property of this State of Matter: Diffusion of one solid into another solid is characteristically slow.
II) Name of State of Matter: Liquid
a) Property of this State of Matter: Definite volume but no definite shape.
b) Property of this State of Matter: Vaguely compressible; Barely compressible.
c) Property of this State of Matter: Flow from a higher level to a lower level.
III) Name of State of Matter: Gas
a) Property of this State of Matter: Easily compressible.
b) Property of this State of Matter: Expand to fill containers.
c) Property of this State of Matter: They are able to occupy far more space than liquids or solids.
Answer:
The theree state of matter is
1.solid.
2.liquid.
3.gas.
Explanation:
analyze your ionized gas emission objects. do your objects display different colors - if so why?
Ionized gas with a mass of 2 × 106M and a temperature of roughly 300 eV emits soft radiation. Along the galaxy's minor axis, the gas dispersion is noticeably enlarged. Due to their ability to reflect some colors while also absorbing others, objects appear in a variety of colors.
The photons' energies, which are in turn influenced by the energies needed to shift electrons from one orbital to another, decide the color of the light that is released. Only specific light frequencies are released when certain colors are present in an element's atomic emission spectrum. This is so that each atom's electrons can absorb and release identical light. A molecule can absorb one hue of light and emit another when two or more atoms share some of their electrons.
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7. An object with a mass of 2.0 kg is accelerated from rest. The above graph shows the magnitude of the net force
as a function of time. At t = 4.0 s the object's velocity is closest to which of the following?
a. 2.0 m/s
b. 4.0 m/s
C. 10 m/s
d. 13 m/s
The object's velocity accelerating from rest from the applied force and time is closest to 4 m/s.
Velocity of the object
The velocity of the object can be determied by applying Newton's second law of motion as shown below;
F = ma
where;
F is the applied forcem is the mass of the objecta is the acceleration of the objectThe acceleration of the object is calculated as follows;
a = F/m
at time, t 4.0 s, the corresponding force = 2 N
a = 2/2
a = 1 m/s²
Velocity of the object is calculated as;
v = u + at
v = 0 + 1 x 4
v = 4 m/s
Thus, the object's velocity accelerating from rest from the applied force and time is closest to 4 m/s.
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Suppose that the magnitude of the charge on the yellow sphere is determined to be 2q2q. Calculate the charge qredqredq red on the red sphere. Express your answer in terms of qqq , d1d1d 1 , d2d2d 2 , and θθtheta
The charge qred on the red sphere is given by (2q * d2^2) / d1^2, expressed in terms of q, d1, d2, and θ.
To calculate the charge qred on the red sphere, we can use the concept of electric forces and Coulomb's law. The electric force between two charges is given by F = k * (|q1| * |q2|) / r^2, where k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between them.
In this scenario, the yellow sphere has a charge of 2q. Let's assume the distance between the yellow and red spheres is d1. The force between the yellow and red spheres can be expressed as F1 = k * (|2q| * |qred|) / d1^2.
Now, suppose the distance between the red sphere and the source of electric field is d2. The force between the red sphere and the source of electric field can be expressed as F2 = k * (|qred| * |qred|) / d2^2.
Since the forces F1 and F2 are equal (since they act on the same object), we can set them equal to each other:
k * (|2q| * |qred|) / d1^2 = k * (|qred| * |qred|) / d2^2
Simplifying and rearranging the equation, we have:
(2q * qred) / d1^2 = qred^2 / d2^2
Cross-multiplying and solving for qred, we get:
2q * d2^2 = qred * d1^2
qred = (2q * d2^2) / d1^2
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How thermal energy is transferred throughout the water
Answer:
Explanation: Thermal energy is transferred through water by conduction, convection, and radiation. Conduction occurs when heat is transferred through direct contact between water molecules with different thermal energy. Convection occurs when warmer water rises to the top and cooler water sinks to the bottom, creating a circular motion that distributes heat. Radiation is the transfer of energy through electromagnetic waves, but it is not significant in water due to poor conduction. The specific mechanism that dominates heat transfer depends on various factors such as temperature gradient, depth, and presence of other materials.
a stroboscopic photo of a club hitting a golf ball, was made by Harold Edgerton in 1993. the ball was initially at rest, and the club was shown to be in contact with the ball for about 0.0020 s. Also, the ball was found to end up with a speed of 2.0x10^2 feet per second. Assuming that the golf ball had a mass of 55 g, find the average force exerted by the club on the ball
The average force exerted by the club on the ball is 838,400 N. Force can be characterized by its magnitude, direction, and point of application.
What is a force ?It can be a push or pull, and it can cause an object to start moving, stop moving, or change its direction of motion.
Force is indeed a physical factor that alters or has the potential to alter an object's state at rest or motion as well as its shape. Newton is the SI unit of force.
Finally, the average force exerted by the club on the ball is:
F = I / t = (1676.8 N·s) / (0.0020 s) = 838,400 N
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because of the massive weight, the distance needed to stop an average train travelling at 55mph is
The distance needed to stop an average train traveling at 55 mph (miles per hour) depends on several factors, including the train's mass, speed, braking system, and track conditions. The braking capabilities of the train play a crucial role in determining the stopping distance.
On average, it is estimated that a typical freight train traveling at 55 mph may require a distance of approximately one mile (1.6 kilometers) to come to a complete stop. This estimate takes into account the train's weight, momentum, and the time required for the braking system to bring the train to a halt.
However, it is important to note that this is a rough estimate and can vary based on various factors such as the train's specific configuration, the condition of the track, the effectiveness of the braking system, and the operator's skill. Additionally, trains may be equipped with additional systems such as emergency brakes to assist in stopping in shorter distances when necessary.
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How long does it take water to freeze at 32 degrees ?
Water freezes more quickly when it is exposed to colder temperatures and when it is in a container with a large surface area, which allows for faster heat transfer.
Water freezes at 32 degrees Fahrenheit (0 degrees Celsius). The time it takes for water to freeze at this temperature depends on several factors such as the volume of water, the container it is in, and the environment in which it is located.
Assuming that the water is in a typical home freezer and the volume of water is not too large, it would typically take several hours for the water to freeze completely. The exact amount of time it takes for the water to freeze would depend on the volume of water and the temperature of the freezer.
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Friction is a ____________ force
a. Artificial
b. Natural
c. Pessimistic
d. Negative
Answer:
natural is the answer
Friction is a natural force which exist
Starting from rest, a runner at a track meet reaches a speed of 7.6 m/s in 1.5 s. How far (in m) does she run during this time, assuming her acceleration is uniform?
6.375 m is her acceleration uniform.
We apply the equations derived for rectilinear motion with constant acceleration to this issue. These are the equations:
a = (v - v₀)/t
x = v₀t + 0.5at²
where
Acceleration is a.
The ultimate and beginning velocities are v and v0, respectively.
The distance is x.
Time has come.
Let's first figure out the value of a to be inserted into the second equation:
4.411 m/s2 is equal to a = (7.5 m/s - 0 m/s)/1.7 s.
x = (0)(1.7s) + 0.5(4.411 m/s²) (1.7 s)
²
x = 6.375 m
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How much energy was released if rocket hydrogen fuel was burnt ?
Answer:
In layman's terms, burning hydrogen results in water: H2 + 1 2 O2 −→ H2O + 286, 000 joules. This combustion reaction also releases 286,000 joules of energy per mole of hydrogen gas burned.
Explanation:
Metals allow electrons to flow through and complete the circuit. Therefore they are called?
Answer:
the answer would be conductors
PLEASE HELP 50 POINTS!!
An unknown material bolt with a mass of .43 kg is heated to a temperature of 100 oC, then it is placed in 1 kg of water at a temperature of 20oC, a simple calorimeter and the top is sealed. Time is allowed to go by and the equilibrium temperature is 23.059oC. What is the energy gained by the water during this process?
4186 J
96523.80 J
It doesn't gain any energy
12804.974 J
Answer:
Explanation:
The energy gained by the water can be calculated using the formula for the heat capacity of water, which is: q = mc * Delta T, where q is the energy gained by the water, m is the mass of the water, c is the heat capacity of water, and Delta T is the change in temperature of the water. In this case, m = 1 kg, c = 4.184 J/g * oC, and Delta T = 23.059 - 20 = 3.059 oC. Substituting these values into the formula, we find that the energy gained by the water is approximately 52.3 J.
The heat gained by water will be equal to the heat lost by the material bolt and it can be calculated using calorimetric equation. The heat energy gained by water is equal to 12800 J.
What is calorimetry?Calorimetry is an analytical technique used to determine the heat energy absorbed or released by a reaction system. The calorimetric equation connecting the heat energy q with the mass m, temperature difference ΔT and specific heat capacity c is written as:
q = m c ΔT.
The specific heat capacity of water = 4.18 J/ g °C
mass = 1 kg = 1000 g
temperature difference from 20 to 23. 059 °C.
The heat energy gained by water from the material bolt is then calculated as follows:
q = 4.18 J/ g °C × 1000 g × (23. 059 0 - 20 °C )
= 12800 J.
Therefore, the energy gained by water during the process is 12800 J.
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Differences in temperature change part2
Explanation:
cold,hot,warm,room tempature i dont know what you needed help with but here you go:)
show that the displacement amplitude of an air milecule at a painful level
A sound wave's height can be determined by looking at its amplitude. The loudness or the maximum displacement of the medium's vibrating particles from their mean position at the time the sound is produced are two ways to describe a sound wave's amplitude.
How Do You Define Sound Frequency?The distance is the measurement between the peak or trough of the wave and the wave's mean position.The frequency of an oscillation is defined as its number per second. The letter Hz stands for hertz, which is its unit. The general definition of a wave's frequency is the frequency at which a wave causes the constituents of a medium to vibrate.It is possible to define a period as the time needed to The term "periodic event" refers to an occurrence that occurs repeatedly. The duration it takes for a periodic event to repeat itself is referred to as the period. The particle's time period is equal to how long it takes for one vibration cycle to complete.For more information on amplitude of sound wave kindly visit to
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If you are using a scaling factor of 0.50 N/cm to draw a vector representing a magnitude of 4.0 N, how long should the vector be on the paper? 8.0 cm 4.0 cm 20 cm
The length of the vector on the paper should be 8.0 cm. For the length of the vector on the paper, we need to apply the scaling factor.
The scaling factor tells us how many centimeters on the paper correspond to each unit of the vector's magnitude. The scaling factor is 0.50 N/cm, it means that each centimeter on the paper represents 0.50 N of magnitude.
If the vector has a magnitude of 4.0 N, we can calculate the length on the paper by dividing the magnitude by the scaling factor:
Length on paper = Magnitude / Scaling factor.
Substituting the given values:
Length on paper = 4.0 N / 0.50 N/cm.
Calculating the value:
Length on paper = 8.0 cm.
Therefore, the length of the vector on the paper should be 8.0 cm.
The length of the vector on the paper represents the magnitude of the vector using the scaling factor. In this case, since the magnitude is 4.0 N and the scaling factor is 0.50 N/cm, the length of 8.0 cm indicates that the vector has a magnitude of 4.0 N. This allows us to visually represent the magnitude of the vector using the chosen scaling factor on the paper.
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How many statements are correct? 0 1 2 3 4
Statement A. Increasing a moving average window will enhance noise dampening.
Statement B. Decreasing a moving average window will enhance impulse response.
Statement C. Increasing the smoothing constant in exponential smoothing will enhance impulse response.
Statement D. Decreasing the smoothing constant in exponential smoothing will enhance noise dampening.
Answer:
Explanation:
Statement A: Increasing a moving average window will enhance noise dampening.
Statement B: Decreasing a moving average window will enhance impulse response.
Statement C: Increasing the smoothing constant in exponential smoothing will enhance impulse response.
Statement D: Decreasing the smoothing constant in exponential smoothing will enhance noise dampening.
Let's evaluate each statement:
A. Increasing a moving average window will enhance noise dampening.
This statement is true. Increasing the window size of a moving average smooths out the fluctuations in the data and reduces the effect of noise, thus enhancing noise dampening.
B. Decreasing a moving average window will enhance impulse response.
This statement is false. Decreasing the window size of a moving average reduces the number of data points considered, leading to less smoothing and a faster response to changes in the data. It does not enhance impulse response.
C. Increasing the smoothing constant in exponential smoothing will enhance impulse response.
This statement is false. Increasing the smoothing constant in exponential smoothing increases the weight given to more recent data points, which results in smoother and more stable forecasts. It does not enhance impulse response.
D. Decreasing the smoothing constant in exponential smoothing will enhance noise dampening.
This statement is true. Decreasing the smoothing constant in exponential smoothing gives more weight to past observations, which helps in reducing the impact of noise and enhances noise dampening.
Based on the evaluation, 2 out of the 4 statements are correct.
When you ‘tap a keg’ you are connecting a device to change the air pressure inside the barrel. The hand
pump is used to pump air into the keg. If the pouring nozzle is held at the same height as the beer inside
the keg and the hose has a radius of 0. 25 cm, what must the air pressure be inside the keg for the beer to
flow out at 1. 2 m/s?
The air pressure inside the keg for the beer to flow out at 1.2 m/s is approximately 100,605 Pa (or 1.00605 atm).
Bernoulli's principle states that the sum of the pressure, kinetic energy per unit volume, and potential energy per unit volume of an incompressible fluid remains constant along a streamline. The equation for Bernoulli's principle: P + (1/2)ρv² = constant.
Given information,
Radius = 0.25 cm
Velocity= 1.2 m/s
P = constant - (1/2)ρv².
A = πr² = π(0.0025 m)².
The constant value can be determined by considering the initial conditions when the beer is not flowing. At rest, the velocity of the beer is zero, so the pressure inside the keg would be equal to the atmospheric pressure, which is approximately 101,325 Pa.
P = 101325 Pa - (1/2)ρv²
The density of beer is approximately 1000 kg/m³.
P = 101325 Pa - (1/2)(1000 kg/m³)(1.2 m/s)².
P ≈ 101,325 Pa - 720 Pa.
Therefore, the air pressure inside the keg for the beer to flow out at 1.2 m/s is approximately 100,605 Pa (or 1.00605 atm).
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HW 08-03 1 1 point A 3.3 kg block is sitting on a ramp inclined at an angle = 37. There are coefficients of friction μg = 0.44 and uk = 0.30 between the block and the ramp. What is the minimum force Fmin (in N) that must be applied horizontally in order to move the block up the ramp? Round your answer to one (1) decimal place. If there is no solution or if the solution cannot be found with the information provided, give your answer as: -1000 Type your answer... ch --00 Submit
The minimum force (Fmin) required to move the block up the ramp is 12.7 N.
Mass of the block (m) = 3.3 kg
Angle of the ramp (θ) = 37°
Coefficient of friction between the block and the ramp (μg) = 0.44
Coefficient of kinetic friction between the block and the ramp (uk) = 0.30
Step 1: Resolve the forces acting on the block.
The weight of the block (mg) can be resolved into two components:
- The force acting parallel to the incline (mg*sinθ)
- The force acting perpendicular to the incline (mg*cosθ)
Step 2: Calculate the force of friction.
The force of friction can be calculated using the equation:
Force of friction (Ff) = μg * (mg*cosθ)
Step 3: Determine the minimum force required.
To move the block up the ramp, the applied force (Fapplied) must overcome the force of friction.
Thus, the minimum force required (Fmin) is given by:
Fmin = Ff + Fapplied
Step 4: Substitute the given values and calculate.
Ff = μg * (mg*cosθ)
Fmin = Ff + Fapplied
Now, let's calculate the values:
Ff = 0.44 * (3.3 kg * 9.8 m/s² * cos(37°))
Ff ≈ 12.717 N
Fmin = 12.717 N + Fapplied
Therefore, the minimum force (Fmin) required to move the block up the ramp is approximately 12.7 N.
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What’s 5.1 cm in Newton’s?
the two forces shown acting on square . determine the magnitude of F, which will cause zero moment at point 0
Answer: u excited for the super bowl?
Explanation:
A 2,500 kg plane accelerates from rest at a rate of 86.8 m/s². Find the net force acting on the plane.
A magic school bus travelled along this path. What is the magnitude of the total
displacement of the school bus from the start to the end of its trip? (1 point
answer, 1 point work shown)
What is the the y value of the line y=3x +4 when x=2? *
*by hand, if possible*
Question 3 An experiment has been conducted to test the failure of aluminium under repeated alternating stress at 210000 psi and 18 cycles per second. The numbers of cycles to failure of n = 70 alumin
The experiment on failure of aluminium under repeated alternating stress shows that the mean number of cycles to failure of n = 70 aluminum specimens was 11400 cycles.
The experiment aimed to test the failure of aluminum under repeated alternating stress at 210000 psi and 18 cycles per second. The experiment was performed on 70 aluminium specimens, and it was found that the mean number of cycles to failure was 11400 cycles. The experiment shows that the number of cycles to failure is affected by various factors, including the material properties and the stress level.The experiment findings could be used to determine the suitability of aluminium in applications where it would be subjected to repeated alternating stress. The experiment could be repeated under different stress levels to determine the material's performance under various stress levels. The data collected in the experiment could be used to design materials that are better suited for applications that involve repeated alternating stress.
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What causes wind?
A
The sun stops the wind throughout the afternoon as everything warms up.
B
The sun causes waves to be larger by directing solar energy into the water.
C
The sun heats land quickly and as the warm air rises, cool air comes in to take it place.
D
The sun reflects off the water, making the air above the water unstable and more likely to move.
Answer:C
Explanation:
The sun heats land quickly and as the warm air rises, cool air comes in to take it place.
Answer:
C
Explanation:
What should you do before each laboratory exercise?
O A. review all safety procedures and the lab activity procedure
OB. review the WHMIS symbols
O c. put on gloves
OD. ask your lab partner
plz answer ASAP
Answer:
OA. . review all safety procedures and the lab activity procedure
Explanation:
This is a map that shows hot spots around the world. Which phrase describes the formation of the hawaiian islands?formed due to subductionformed in the middle of a plateformed at a divergent boundaryformed at a convergent boundary.
Where the mantle bursts through the crust, a plate is formed in the midst of it.
How did the Hawaiian Islands develop?A famous example of a sizable seamount and island chain produced by hot-spot volcanism is the Hawaiian Emperor seamount chain. With a northwesterly direction, the chain's islands or submerged seamounts get older and older.
The Pacific plate, which is migrating north-west, is where the Hawaiian Islands are located. Volcanoes formed there.
The fragile and brittle asthenosphere is covered by lithosphere plates. This also applies to the Pacific plate. If access is provided via faulting or other geological conduits, the weak asthenosphere may erupt on the surface. Hotpots form on the crust as a result of these mantle magmas rising to the surface.
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The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is
The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.
The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.
Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:
E/B = (NC^(-1))/(NA^(-1) m^(-1))
To simplify this expression, we can cancel out the common units in the numerator and denominator:
E/B = (N/C)/(N/(A m))
Now, let's simplify further by dividing the numerator and denominator:
E/B = (N/C) * (A m/N)
Canceling out the common units:
E/B = (A m)/(C)
Therefore, the unit of E/B is A m/C (ampere meter per coulomb).
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a 4 kg ceiling fan is placed 2.5m above the floor. what is the gpe of the earth-ceiling fan system relative to the floor?
GPE of the earth-ceiling fan system relative to the floor is 98 J .
What is GPE?Potential energy that a massive object has in relation to another massive object due to gravity is called Gravitational potential energy. It is this energy associated with the gravitational field, which is converted to kinetic energy when the objects fall towards each other. It represents the potential an object has to do work being located at a particular position in a gravitational field.
Given mass of fan= 4kg
height, h = 2.5m
GPE = m*g*h
g is the acceleration due to gravity which is 9.8
GPE= 4 * 2.5 * 9.8
GPE = 98J
Hence, GPE of the earth-ceiling fan system relative to the floor is 98 J .
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In one of his many action movies Jackie Chan jumped off a building by wrapping a rope around his waist and then allowed it to unwind as he fell to the ground, much the same as a yo-yo. Assuming his acceleration toward the ground was a constant much less than g, the tension in the rope would be (A) almost equal to his weight. (B) exactly equal to his weight. (C) much less than his weight. (D) exactly zero.
(A) nearly the same as his weight
When the Jackie Chan of acceleration hit the ground, he had two different kinds of power. There are two types of acceleration: rotational acceleration and linear acceleration.
The tension in the string and the frictional force between the rope and the Jackie Chan create the angular acceleration. On the other hand, linear acceleration is caused by the disparity between Jackie Chan's weight and the rope's tension.
The downward linear acceleration would be less than the acceleration brought on by gravity if the tension in the rope were similar to Jackie Chan's weight. Therefore, Jackie Chan's acceleration would be substantially less than g only if the tension in the rope is comparable to his weight.
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