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X= ?

The expression that can be used  to find the temperature at noon is

–22.4 + 12.8 option B

Generally, The word "temperature" refers to the degree to which something is hot or cold and may be described using a number of different scales, such as Fahrenheit and Celsius.

The direction in that heat energy will spontaneously flow is indicated by temperature; specifically, it will flow from a hotter body (one that is at a higher temperature) to a colder one (one at a lower temperature).

In conclusion,  the temperature was 22.4°F below zero meaning

-22.4F in mathematical terms

and  12.8°F above zero in mathematical terms

Therefore, –22.4 + 12.8 is the expression that can be used  to find the temperature at noon

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Answer:

z =86

Step-by-step explanation:

The exterior angle of a triangle is the sum of the opposite interior angles

z + z-39 = z+47

2z-39 = z+47

Subtract z from each side

z-39 = 47

Add 39 from each side

z = 47+39

z =86

The given information is,

To find the required value of z.

Property we use,

The exterior angle of a triangle is the sum of the opposite interior angles.

Now we can get the value of z,

→ z + z-39 = z + 47

→ 2z-39 = z + 47

→ 2z -z = 47 + 39

→ z = 47 + 39

→ [z = 86]

Thus, the required value of z is 86.

With the given function. , our integration is correct .Check:

\((8x - \frac{1}{2} x^2)'=8 - x\)

This is the final answer:

\($$ \int (8 - x) \text{ }dx = 8x - \frac{1}{2} x^2 + C $$\)

\($$ \int (8 - x) \text{ }dx $$\)

Formula: Let f(x) be a function defined on an interval I, and let F be the antiderivative of f, that is,

\($F'(x)=f(x)$\) on I, t

hen the indefinite integral of f is defined by

\($$ \int f(x)dx=F(x)+C $$\)

where C is an arbitrary constant of integration.

Now, we have to find the indefinite integral of the given function:

\($$ \int (8 - x) \text{ }dx $$\)

Let's use the formula and integrate:

\($\int (8-x)\text{ }dx $\)

Using integration, we get

\($$\int (8-x)\text{ }dx = 8x - \frac{1}{2} x^2 + C$$\)

Check the result by differentiation.

We can check whether our integration is correct or not by differentiating the result that we got above with respect to x.
Let's differentiate it. Using differentiation, we get:

\((8x - \frac{1}{2} x^2 + C)'=8 - x\)

We can see that the differentiation of the result matches

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Answer:

I think 48

Step-by-step explanation:

multiply the bottom numbers

Answer:

i think is 44

Step-by-step explanation:

There are 9 ways to construct a sequence using the integers 1 to 10 such that each term is either larger than all the numbers to its left or smaller than all the numbers to its left. But the final count is 2 - 2 = 0.

To construct the sequence, we start by choosing the first number. We have two options: either choose the smallest number (1) or the largest number (10). Once we have chosen the first number, we continue by selecting the second number. If we chose the smallest number (1) as the first number, then the second number must be the largest number (10). Similarly, if we chose the largest number (10) as the first number, then the second number must be the smallest number (1).

For each subsequent number, the pattern continues: if the previous number was the smallest, we choose the largest, and if the previous number was the largest, we choose the smallest.

Since we have two options for the first number and then only one option for each subsequent number, we have a total of 2 × 1 × 1 × ... × 1 = 2 × 1^8 = 2 × 1 = 2^1 = 2 possibilities. However, we need to exclude the case where all the numbers are in increasing order or all the numbers are in decreasing order, so the final count is 2 - 2 = 0.

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We can group the minterms to obtain the minimum sum of products (SOP):

F(A,B,C,D) = A'B' + CD' + ABC + A'B'CD' + ABCD

Expansion of the function f(A,B,C,D):

f(A,B,C,D) = (A+B+D')(A'C)(C+D)

= A'A'C + A'CC' + BA'C + BC + D'A'C + D'CC' + BD'(A'C) + BD'(C+D)

= 0 + 0 + BA'C + BC + 0 + 0 + BD'A'C + BD'C + BD'D

= BA'C + BC + BD'A'C + BD'C + BD'D

Minterms SOP for the function with K-map 5.16:

The truth table for the given function is:

A B C F

0 0 0 0

0 0 1 1

0 1 0 1

0 1 1 0

1 0 0 1

1 0 1 0

1 1 0 0

1 1 1 1

The K-map for this function is:

BC

A 00 01 11 10

0 |  0  1  0  1

1 |  1  0  0  1

We can group the minterms to obtain the minimum sum of products (SOP):

F(A,B,C) = A'B' + A'C + BC

Karnaugh map and minimum sum of products for the function F(A,B,C,D)=A'B'+CD'+ABC+A'B'CD'+ABCD:

The truth table for the given function is:

A B C D F

0 0 0 0 0

0 0 0 1 1

0 0 1 0 0

0 0 1 1 0

0 1 0 0 1

0 1 0 1 0

0 1 1 0 1

0 1 1 1 1

1 0 0 0 0

1 0 0 1 0

1 0 1 0 0

1 0 1 1 0

1 1 0 0 1

1 1 0 1 1

1 1 1 0 1

1 1 1 1 1

The K-map for this function is:

   CD

AB 00 01 11 10

00 |   0  1  0  0

01 |   1  0  0  1

11 |   1  1  1  1

10 |   0  0  1  0

We can group the minterms to obtain the minimum sum of products (SOP):

F(A,B,C,D) = A'B' + CD' + ABC + A'B'CD' + ABCD

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Answer:

A not rational number is called a irrational number btw. Anyway Some examples are √2 and pi.

The type of function that fits the given description is D. Exponential decay.

In an arithmetic sequence, the difference between consecutive terms remains constant. If the y-values of a function form an arithmetic sequence that decreases in value, it means that the difference between consecutive terms is negative.
Exponential decay functions exhibit a constant ratio between consecutive terms, resulting in a decreasing sequence. As the x-values increase, the y-values decrease at a consistent rate. This is represented by the formula y = ab^x, where b is a constant between 0 and 1.
In contrast, linear functions have a constant difference between consecutive terms, resulting in an arithmetic sequence. However, since the y-values are decreasing, the function cannot be linear.
Exponential growth functions, on the other hand, have a constant ratio between consecutive terms, but they result in an increasing sequence. The y-values of an exponential growth function increase as the x-values increase.

Therefore, based on the given information, the most appropriate type of function is D. Exponential decay.

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Answer:

16

Step-by-step explanation:

dot product = x1x2 + y1y2

= (-5)(-8 + (4)(-6)

= 40 - 24

= 16

Answer:

y''=(4-3t)/[16 t^3 (2-t)^(3/2)]

Step-by-step explanation:

x = t², y = (2 - t)^1/2

dy/dx=dy/dt×dt/dx by chain rule

dy/dt=1/2 (2-t)^(1/2-1) × (-1)

dy/dt=-1/2 (2-t)^(-1/2)

dy/dt=-1/[2(2-t)^(1/2) ]

dx/dt=2t

dy/dx=-1/[2(2-t)^(1/2) ] × 1/[2t]

dy/dx=-1/[4t (2-t)^(1/2) ]

We need to find the second derivative now.

That is we calculate d/dt(dy/dx in terms of t) then divide by derivative of x in terms of t).

dy/dx=-1/[4t (2-t)^(1/2) ]

Let's find derivative of this with respect to t.

d/dt(dy/dx)=

[0[4t (2-t)^(1/2)]-(-1)(4(2-t)^(1/2)+-4t(1/2)(2-t)^(-1/2))]/ [4t (2-t)^(1/2) ]^2

Let's simplify

d/dt(dy/dx)=

[(4(2-t)^(1/2)+-4t(1/2)(2-t)^(-1/2))]/ [4t (2-t)^(1/2) ]^2

Continuing to simplify

Apply the power in the denominator

d/dt(dy/dx)=

[(4(2-t)^(1/2)+-4t(1/2)(2-t)^(-1/2))]/ [16t^2 (2-t) ]

Multiply by (2-t)^(1/2)/(2-t)^(1/2):

d/dt(dy/dx)=

[(4(2-t)+-4t(1/2)]/ [16t^2 (2-t)^(3/2)]

Distribute/multiply:

d/dt(dy/dx)=

[(8-4t+-2t)]/ [16t^2 (2-t)^(3/2)]

Combine like terms:

d/dt(dy/dx)=

[(8-6t)]/ [16t^2 (2-t)^(3/2)]

Reducing fraction by dividing top and bottom by 2:

d/dt(dy/dx)=

[(4-3t)]/ [8t^2 (2-t)^(3/2)]

Now finally the d^2 y/dx^2 in terms of t is

d/dt(dy/dx) ÷ dx/dt=

[(4-3t)]/ [8t^2 (2-t)^(3/2)] ÷ 2t

d/dt(dy/dx) ÷ dx/dt=

[(4-3t)]/ [8t^2 (2-t)^(3/2)] × 1/( 2t)

d/dt(dy/dx) ÷ dx/dt=

[(4-3t)]/ [16t^3 (2-t)^(3/2)]

Or!!!!!!

x = t², y = (2 - t)^1/2

Since t>0, then t=sqrt(x) or x^(1/2).

Make this substitution into the equation explicitly solved for y:

y = (2 - x^1/2)^1/2

Differentiate:

y' =(1/2) (2 - x^1/2)^(-1/2) × -1/2x^(-1/2)

y'=-1/4(2 - x^1/2)^(-1/2)x^(-1/2)

y'=-1/4(2x-x^3/2)^(-1/2)

Differentiate:

y''=1/8(2x-x^3/2)^(-3/2)×(2-3/2x^1/2)

y''=(2-3/2x^1/2)/[8 (2x-x^3/2)^(3/2)]

Replace x with t^2

y''=(2-3/2t)/[8 (2t^2-t^3)^(3/2)]

Multiply top and bottom by 2

y''=(4-3t)/[16 (2t^2-t^3)^(3/2)]

Factor out t^2 inside the 3/2 power factor:

y''=(4-3t)/[16 (t^2)^(3/2) (2-t)^(3/2)]

y''=(4-3t)/[16 t^3 (2-t)^(3/2)]

Answer:

the picture isnt showing up on mines

Answer:

y=-3x

Explanation:

3=-3(-1)+b

3=3+b

0=b

y=-3x

Okay, let's calculate the average rate of change:

On day 3, the high temperature was 59 degrees.

On day 5, the high temperature was 53 degrees.

So the temperature change from day 3 to day 5 was 59 - 53 = 6 degrees.

And the number of days was 5 - 3 = 2 days.

So the average rate of change = (6 degrees) / (2 days) = 3 degrees per day

The closest choice is:

The high temperature changed by an average of −4 degrees per day from day 3 to day 5.

So the answer is:

5

Based on the number of people who are older than 35 years and the people with a hemoglobin level between 9 and 11, the probability is 0.531.

This question does not have the relevant data attached so I will use a similar question.

The probability that a person is older than 35 and has a hemoglobin level of between 9 and 11 can be found as:

= Person who has hemoglobin level of between 9 and 11 and is above 35 years / Total number of people older than 35 years

= (162 - 40 - 76) / 162

= 0.531

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Answer:

The graph is non-linear as it is not a continuous straight line (with only one slope).

Increasing:  the y-value increases as the x-value increases

Constant:  the y-value stays the same as the x-value changes

Decreasing:  the y-value decreases as the x-value increases

Therefore,

For the first 2 seconds, the ant moves 6 cm from a hole in the tree at a steady speed of 3 cm per second. For the next second, the ant is at rest then turns around. For the next 2 seconds, the ant moves 6 cm back to the hole at a steady speed of 3 cm per second.  The ant then stops.

Answer:

A. 40in3

Step-by-step explanation:

your just multiplying the numbers together

Given data ; Initial distance between cars, d = 960m Speed of Car A, vA = 50 m/sSpeed of Car B, vB = 30 m/sSpeed of sound, vS = 340 m/s

Let's solve the parts given in the question;

a) Find vAB; Relative speed, \(vAB = vA + vBvAB = 50 m/s + 30 m/svAB = 80 m/s\)

b)Let t be the time until the two cars collide.In time t, the distance traveled by Car A = vA0t

The distance traveled by Car B = vBt

The total distance covered by both cars is d:

Therefore, \(vAt + vBt = dd/t = (vA + vB)t = 960 mt = d / (vA + vB)t = 960 / 80t = 12 s\)

Let ΔsSound be the displacement of the sound during that time.

Distance traveled by Car \(A = vA x t = 50 m/s x 12 s = 600 mDistance traveled by Car B = vB x t = 30 m/s x 12 s = 360 m\)

Therefore, the distance between the cars will be \(960 - (600 + 360) = 0 m.\) So, the sound wave will have traveled the displacement of 4080 m from Car B to Car A.

Hence, ΔsSound = 4080 m.

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Answer:

Options (1), (3) and (7)

Step-by-step explanation:

Characteristics of the given graph are as followed.

1). For every input value (x-value) there is a different output values (y-values).

   So the points on the graph represent a function.

2). Coordinates of all the points are distinct and separate (not in fractions or decimals).

    Function given is a discrete function.

3). For every increase in the x-values of the points there is a decrease in y-values.

  Therefore, given function is a decreasing function.

Therefore, Options (1), (3) and (7) are the correct options.

(a) For the function \(f(x) = (x-3)(x^2-x-2)\), the first derivative with respect to the domain variable can be found using the product rule of differentiation. The derivative is given by \(f'(x) = (x^2-x-2) + (x-3)(2x-1)\).

(b) For the function \(f(x) = (3x^2 + 2)e^{3x}\), the first derivative with respect to the domain variable can be found using the chain rule and the product rule of differentiation. The derivative is given by \(f'(x) = (6x)e^{3x} + (3x^2 + 2)(3e^{3x})\).

(c) For the function \(v(y) = \ln(y^3 - 8)\), the first derivative with respect to the domain variable can be found using the chain rule and the power rule of differentiation. The derivative is given by \(v'(y) = \frac{1}{y^3 - 8} \cdot (3y^2)\).

In summary, the first derivatives with respect to the domain variable for the given functions are \(f'(x) = (x^2-x-2) + (x-3)(2x-1)\) for \(f(x) = (x-3)(x^2-x-2)\), \(f'(x) = (6x)e^{3x} + (3x^2 + 2)(3e^{3x})\) for \(f(x) = (3x^2 + 2)e^{3x}\), and \(v'(y) = \frac{1}{y^3 - 8} \cdot (3y^2)\) for \(v(y) = \ln(y^3 - 8)\). These derivatives represent the rate of change or slope of the functions with respect to the independent variable.

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Since 4 peaches x 2 =8, you would would only be able to buy 6 mangos since $1.25 x 6 mangos =$7.5 so it would be $7.5+$8=$15.5 and 6 mangos+4 peaches=10 in total. And he would also save $5.00! :)

Please mark brainliest!

Hope it helps!

1) Trigonometric ratios for similar triangles state that the ratios of corresponding sides of similar triangles are equal. 2) The sine and cosine of complementary angles have the property of being not only equal but also complementary to one another. 3) trigonometric ratios can be used to solve for a missing side or angle of a right triangle.

1. Trigonometric ratios for similar triangles state that the ratios of corresponding sides of similar triangles are equal. Therefore, the ratios of the sine, cosine, and tangent of the corresponding angles in similar triangles will also be equal.

2. The sine and cosine of complementary angles have the property of being not only equal but also complementary to one another. This means that the sine of an angle is equal to its complement's cosine, and vice versa.

3. Using the appropriate formula based on the given information, trigonometric ratios can be used to solve for a missing side or angle of a right triangle.

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Answer:

f(x) = 3(x+1)^2 +3

Step-by-step explanation:

answer is -11 after you simplifying

Answer:

A group of seven friends each received one-half of a pound ofcandy. How much candy did they receive total?✓

0.5 pounds x 7= 3.5 poundsStep-by-step explanation:

Marshall is wondering whether he can participate in the LLP again next year. The statement that is true is "He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.

The Lifelong Learning Plan is a program that helps Canadian residents finance their post-secondary education through their registered retirement savings plans (RRSP). If an individual is attending school full-time, they can withdraw up to $10,000 a year from their RRSP under the program, or up to $20,000 in total. There are certain rules that must be followed by an individual participating in the LLP. For example, withdrawals must be made within four years of enrolling in an eligible educational program, and repayments must begin within the same period.

Here are the statements: Provided he repays his LLP balance in full by the end of this year, Marshall can participate in the LLP again next year.Marshall can only participate in the LLP once over his lifetime. However, his wife can make a LLP withdrawal from her RRSP on his behalf. He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000. He can only participate in the LLP a second time if he repays his LLP balance in full and waits 5 years before he returns to school.The correct statement is: He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.

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To find a positive number such that the sum of and is as small as possible, we need to use optimization. This problem requires optimization over a closed interval. The given problem is as follows, Let x be a positive number. Find a positive number such that the sum of and is as small as possible.

To find a positive number such that the sum of and is as small as possible, we need to use optimization. This problem requires optimization over a closed interval. The given problem is as follows, Let x be a positive number. Find a positive number such that the sum of and is as small as possible. So, we need to minimize the sum of and . Now, let's use calculus to find the minimum value of the sum.To find the minimum value, we have to find the derivative of the sum of and , i.e. f(x) with respect to x, which is given by f '(x) as shown below:

f '(x) = 1/x^2 - 1/(1-x)^2

We can see that this function is defined on the closed interval [0, 1]. The reason why we are using the closed interval is that x is a positive number, and both endpoints are included to ensure that we cover all positive numbers. Therefore, the problem requires optimization over a closed interval. This means that the minimum value exists and is achieved either at one of the endpoints of the interval or at a critical point in the interior of the interval.

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To determine the equation of the tangent plane and normal line of the given curve at the point P(2, -3, 18), we need to find the partial derivatives of the function f(x, y, z) = x^2 + y^2 - 2xy - x + 3y - z - 4.

Taking the partial derivatives with respect to x, y, and z, we have:

fx = 2x - 2y - 1

fy = -2x + 2y + 3

fz = -1

Evaluating these partial derivatives at the point P(2, -3, 18), we find:

fx(2, -3, 18) = 2(2) - 2(-3) - 1 = 9

fy(2, -3, 18) = -2(2) + 2(-3) + 3 = -7

fz(2, -3, 18) = -1

The equation of the tangent plane at P is given by:

9(x - 2) - 7(y + 3) - 1(z - 18) = 0

Simplifying the equation, we get:

9x - 7y - z - 3 = 0

To find the equation of the normal line, we use the direction ratios from the coefficients of x, y, and z in the tangent plane equation. The direction ratios are (9, -7, -1).Therefore, the equation of the normal line passing through P(2, -3, 18) is:

x = 2 + 9t

y = -3 - 7t

z = 18 - t

where t is a parameter representing the distance along the normal line from the point P.

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the values of x and y that make the points (1,2,3), (5,7,1), and (x,y,2) collinear are x = 2 and y = 4.

Let's consider the direction ratios of the given points:

Point 1: (1, 2, 3)

Direction ratios: (1-0, 2-0, 3-0) = (1, 2, 3)

Point 2: (5, 7, 1)

Direction ratios: (5-1, 7-2, 1-3) = (4, 5, -2)

Point 3: (x, y, 2)

Direction ratios: (x-1, y-2, 2-1) = (x-1, y-2, 1)

Since the direction ratios should be proportional, we can set up the following proportion:

(1, 2, 3) / (4, 5, -2) = (x-1, y-2, 1) / (4, 5, -2)

This gives us the following ratios:

1/4 = (x-1)/4

2/5 = (y-2)/5

3/-2 = 1/-2

Simplifying these ratios, we get:

1 = x - 1

2 = y - 2

3 = 1

Solving these equations, we find:

x - 1 = 1

x = 2

y - 2 = 2

y = 4

Therefore, the values of x and y that make the points (1,2,3), (5,7,1), and (x,y,2) collinear are x = 2 and y = 4.

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