Please help with this. 40 points

Answer:

E is (1, 2) and M is (-3,-2),

Step-by-step explanation:

G and O are diagonally opposite points.

E is the image of O in the x axis and M is the image of G in the x axis.

E which is adjacent to M and  will have y-coordinate of 2 and x -coordinate 1.

M  will have x coordinate same as G which is -3 and y coordinate is -2.

The coordinates of E are (1, 2) and coordinates of M are (-3,-2),

The coordinates of a point are referred as (x, y), where x represents the position of the point with reference to the x-axis, and y represents the position of the point with reference to the y-axis.

Here, G and O are diagonally opposite points.

E is the image of O in the x-axis and M is the image of G in the x axis.

E which is adjacent to M and  will have y-coordinate of 2 and x -coordinate 1.

M  will have x coordinate same as G which is -3 and y coordinate is -2.

Thus, the coordinates of E are (1, 2) and coordinates of M are (-3,-2),

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The two positive numbers that satisfy the given requirements are 4.12 and 34

To find two positive numbers that satisfy the given requirements, we can use the concept of quadratic equations. Let's call the first number "x" and the second number "y".

From the given information, we have the equation:

x² + y = 51

To find the maximum product, we can use the formula for finding the maximum point of a quadratic function. In this case, the function is:

f(x) = xy

We can rewrite this function as:

f(x) = x(51 - x² )

To find the maximum point of this function, we need to take its derivative and set it equal to zero:

f'(x) = 51 - 3x²

0 = 51 - 3x²

3x² = 51

x² = 17

So the first number, x, is the square root of 17.

To find the second number, we can substitute x into the original equation:

x² + y = 51

17 + y = 51

y = 34

So the two positive numbers that satisfy the given requirements are approximately 4.12 and 34, with a product of approximately 140.6.

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The final answer is (1 + 21√2)/(21√2). The process of rationalization involves changing the form of an expression to eliminate radicals from its Denominator, or to eliminate denominators from a radical expression.

To rationalize the denominator 1/7 + 3√2,

A rational number is a number that can be expressed as a ratio of two integers, with the denominator not equal to zero. The fraction 4/5, for example, is a rational number since it can be expressed as 4 divided by 5.

Step-by-Step SolutionTo rationalizes the denominator 1/7 + 3√2, we'll need to follow these steps.

Step 1: First, we need to create a common denominator for the two terms. The common denominator is 7. Thus, we can convert the expression to the following form:(1/7) + (3√2 × 7)/(7 × 3√2).

Step 2: Simplify the denominator to 7. (1/7) + (21√2)/(21 × 3√2).

Step 3: The numerator and denominator can now be simplified. (1 + 21√2)/(7 × 3√2).Step 4: Simplify further. (1 + 21√2)/(21√2).We have successfully rationalized the denominator!

The final answer is (1 + 21√2)/(21√2).

The final answer is (1 + 21√2)/(21√2). The process of rationalization involves changing the form of an expression to eliminate radicals from its denominator, or to eliminate denominators from a radical expression.

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To solve for the diameter and radius of a cone with a volume of 8 and a height of 6, we need to use the formulas for the volume and surface area of a cone.

The volume of a cone is given by the formula:

V = 1/3 * π * r^2 * h

where V is the volume, r is the radius, h is the height, and π is the mathematical constant pi (approximately 3.14).

We know that the volume is 8 and the height is 6, so we can plug these values into the formula and solve for the radius:

8 = 1/3 * π * r^2 * 6

r^2 = 8/(π*6/3)

r^2 = 4/π

r = √(4/π)

r ≈ 0.798

The radius is approximately 0.798.

To find the diameter, we simply multiply the radius by 2:

d = 2 * r

d ≈ 1.596

Therefore, the diameter is approximately 1.596 and the radius is approximately 0.798.

Answer: a's value is (6,8) B is (-3,7), and C is (-7,-2)

The equation of line tangent is y-35x+30=0.

What is tangent of a line?

A tangent line to a circle is a line that touches the circle exactly one time in Euclidean plane geometry and never enters the interior of the circle. Tangent lines to circles are the focus of various theorems and are crucial to numerous geometric structures and mathematical arguments.

Given equation y=2x+33x-2

                       =>y=35x-2

General slope intercept form is y=mx+b

Comparing and we get m = 35

The equation of tangent is y-5=35 (x-1)

=> y-5=35x-35

=> y=35x-35+5

=>y-35x+30=0

Therefore, the equation of line tangent is y-35x+30=0.

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The final value of x when (x = 1 ; x<10; x ),in this case will be 9.

This is because the initial value of x is set to 1, and the condition for the loop is that x must be less than 10.

Therefore, the loop will continue to execute as long as x is less than 10, and will stop when x is equal to 10. However, since the final value of x is not included in the loop, the final value of x will be one less than the stopping value, or 9.

Steps include:-
1. Set the initial value of x to 1: x = 1
2. Check if x is less than 10: x<10
3. If x is less than 10, execute the loop and increase the value of x by 1: x++
4. Repeat steps 2 and 3 until x is no longer less than 10
5. The final value of x will be one less than the stopping value, or 9.

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When you trim a video, the start and end markers of the timeline indicate the portion of the video that will play during the slide; the trimmed portion indicates the portion that is removed or excluded from the final playback.

When editing a video, you may want to remove certain parts or shorten its duration. Trimming allows you to specify the exact portion of the video that will be included in the final version. The timeline represents the entire duration of the video, and the start and end markers on the timeline serve as reference points for indicating the selected segment. By adjusting the position of these markers, you can define the beginning and end points of the desired portion. The section of the timeline between the start and end markers represents the portion of the video that will play during the slide or be included in the final output. The remaining parts of the video outside of this selected segment are considered the trimmed portion, which will be excluded from the playback or final edited version of the video.

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a. The magnitude of a vector, ||v|| is \(\sqrt{41}\), ||w|| is sqrt(\(\sqrt{Z^2+i^2+t^2+u^2+s^2}\)), b. the dot product of two vectors is 4Z+(-5)u, C. the angle in degrees between V and D. W is \(cos^-1\) \((v.W/(||v|| ||w||))\) and the unit vector is \((1/||v||)v\).

Given vector v = 4;-5j, and vector w = Zitus, we need to find the following:

a. ||v||, ||w||

To find the magnitude of a vector, we use the formula:

\(||v|| = \sqrt(v1^2+v2^2+....+vn^2)\)

Here, v = 4;-5j,

so ||v|| = \(\sqrt(4^2+(-5)^2)\)

          = \(\sqrt{41}\)

Similarly, \(||w|| = \sqrt{Z^2+i^2+t^2+u^2+s^2}\)

b. v.W

To calculate the dot product of two vectors, we use the formula:

v.W=v1w1+v2w2+....+vnwn

Here, v=4;-5j and w=Zitus, so v.W=4Z+(-5)u.

c. The angle in degrees between V and We know that the dot product of two vectors is given by

\(v.W=||v|| ||w|| cos (theta).\)

We can solve for cos(theta) to get the angle between the vectors.

cos(theta) = \(v.W/(||v|| ||w||)\)

So, theta = \(cos^-1 (v.W/(||v|| ||w||))\)

Using the value of v.W from part (b) and ||v|| from part (a), we can solve for theta.

d. The unit vector in the direction of V

We can get the unit vector in the direction of V by dividing it by its magnitude.

unit vector = \((1/||v||)v\)

Using the value of ||v|| from part (a), we can solve for the unit vector.

Here, v=4;-5j, so unit vector=(\(1/sqrt(41))(4;-5).\)

I decompose V into two vectors V. V.

Where v, is parallel to W and V₂ is Ortragonal to W,

We can decompose vector V into two vectors, V1 and V2 such that V1 is parallel to W and V2 is orthogonal to W.

Let's find V1 and V2.

V1 = \(((v.W)/(||w||^2))w\)

    = \(((4Z-5u)/((Z^2+i^2+t^2+u^2+s^2)^2))(Zitus)\)

This gives us V1.

Now, V2 = V-V1 = 4;

\(-5j-((4Z-5u)/((Z^2+i^2+t^2+u^2+s^2)^2))(Zitus)\)

This gives us V2.

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There are 853,818,600 ways to award first, second, and third prizes in a contest with 950 contestants, assuming there are no ties.

To determine the number of ways to award first, second, and third prizes in a contest with 950 contestants, we can use the permutation formula:

P(n, r) = n! / (n - r)!

where n is the total number of contestants and r is the number of prizes to be awarded (in this case, 3).

Using this formula, we get:

P(950, 3) = 950! / (950 - 3)!

= 950! / 947!

= 950 × 949 × 948

= 853,818,600

Therefore, there are 853,818,600 ways to award first, second, and third prizes in a contest with 950 contestants, assuming there are no ties.

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The median of X is 1;  P(X > 2) = 0; P(one observation < 2 and the other > 2) = P(X < 2) * P(X > 2) = 0 * 0 = 0; Var(X) is approximately 0.33; E(X) is 1 and  the value of q such that P(X < q) = 0.95 is 1.9.

(a) To find the median of X, we need to find the value of x for which the cumulative distribution function (CDF) equals 0.5.

Since the PDF is given as f(x) = 1/2 for 0 < x < 2 and 0 otherwise, the CDF is the integral of the PDF from 0 to x.

For 0 < x < 2, the CDF is:

F(x) = ∫(0 to x) f(t) dt = ∫(0 to x) 1/2 dt = (1/2) * (t) | (0 to x) = (1/2) * x

Setting (1/2) * x = 0.5 and solving for x:

(1/2) * x = 0.5;  x = 1

Therefore, the median of X is 1.

(b) To find P(X > x), we need to calculate the integral of the PDF from x to infinity.

For x > 2, the PDF is 0, so P(X > x) = 0.

Therefore, P(X > 2) = 0.

(c) To find the probability that one observation is less than 2 and the other is greater than 2, we need to consider the possibilities of the first observation being less than 2 and the second observation being greater than 2, and vice versa.

P(one observation < 2 and the other > 2) = P(X < 2 and X > 2)

Since X follows a continuous uniform distribution from 0 to 2, the probability of X being exactly 2 is 0.

Therefore, P(one observation < 2 and the other > 2) = P(X < 2) * P(X > 2) = 0 * 0 = 0.

(d) The variance of X can be calculated using the formula:

Var(X) = E(X²) - [E(X)]²

To find E(X²), we need to calculate the integral of x² * f(x) from 0 to 2:

E(X²) = ∫(0 to 2) x² * (1/2) dx = (1/2) * (x³/3) | (0 to 2) = (1/2) * (8/3) = 4/3

To find E(X), we need to calculate the integral of x * f(x) from 0 to 2:

E(X) = ∫(0 to 2) x * (1/2) dx = (1/2) * (x²/2) | (0 to 2) = (1/2) * 2 = 1

Now we can calculate the variance:

Var(X) = E(X²) - [E(X)]² = 4/3 - (1)² = 4/3 - 1 = 1/3 ≈ 0.33

Therefore, Var(X) is approximately 0.33.

(e) The expected value of X, E(X), is given by:

E(X) = ∫(0 to 2) x * f(x) dx = ∫(0 to 2) x * (1/2) dx = (1/2) * (x²/2) | (0 to 2) = (1/2) * 2 = 1

Therefore, E(X) is 1.

(f) The value of q such that P(X < q) = 0.95 can be found by solving the following equation:

∫(0 to q) f(x) dx = 0.95

Since the PDF is constant at 1/2 for 0 < x < 2, we have:

(1/2) * (x) | (0 to q) = 0.95

(1/2) * q = 0.95

q = 0.95 * 2 = 1.9

Therefore, the value of q such that P(X < q) = 0.95 is 1.9.

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The triple integral is Simplifying this is 16 times the negative number 4 over 3, which is the negative number 64 over 3.

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Every rectangle with four congruent sides is a square -> True

Every rhombus is a quadrilateral -> True

Every square is a parallelogram -> True

Every quadrilateral is a square -> False.

A square is a regular quadrilateral, which means that it has four equal sides and four equal angles. It can also be defined as a rectangle with two equal-length adjacent sides.

here, we have,

we know that,

Every rectangle with four congruent sides is a square -> True

Every rhombus is a quadrilateral -> True

Every square is a parallelogram -> True

Every quadrilateral is a square -> False.

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Answer: 15

Step-by-step explanation:

first you would subtract -69 by positive 420 to get 15

Answer:

i am sorry i am no se

peack englis

Answer:

65 mph

Step-by-step explanation:

520/8 is 65

The operation * in the expression  a*b = ab/4 + a + b is associative.

∗ is association if (a∗b)∗c = a∗(b∗c)

(a∗b)*c =  (ab/4*c)/4 = abc /16

​a∗(b*c) =  (a x (bc/4))/4 = abc /16

​Since (a∗b)∗c=a∗(b∗c)∀a,b,cϵQ

∗ is an associative binary operation.

Since addition is also associative.

So here a*b = ab/4 + a + b is also associative.

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The 95% confidence interval for the difference between the mean amounts of caffeine is C.I = (-1.36, 7.36) and the p-value for this test is  0.169.

In statistics, a confidence interval describes the likelihood that a population parameter would fall between a set of values for a given percentage of the time. Confidence ranges that include 95% or 99% of anticipated observations are frequently used by analysts.

Therefore, it can be concluded that there is a 95% probability that the true value falls within that range if a point estimate of 10.00 is produced from a statistical model with a 95% confidence interval of 9.50 - 10.50.

a) We will set up the null hypothesis that

\(H_{0}: \mu_{1} = \mu_{2}\)          Vs

Ha

Under the null hypothesis the test statistics is.

(T1-T2) 7t 7t

Where  (nl+ n2- 2)

Also we are given that

 T1 80  ,  12 77 , 721 15  ,     n2- 12   ,  5    and    \(S_{2}\) = 6

\(\therefore S^2=\frac{(15-1)5^2+(12-1)6^2}{(15+12-2)}=5.4626\)

n1 n2

\(C.I=(15-12)\pm 2.060*5.4626\sqrt{\frac{1}{15}+\frac{1}{12}}\)

C.I = (-1.36, 7.36)

b) Also under null hypothesis

\(t=\frac{(\bar{x }_{1}-\bar{x }_{2})-(\mu _{1}-\mu _{2})}{S^{2}\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}}\)

\(t=\frac{(15-12)-0}{5.4626\sqrt{\frac{1}{15}+\frac{1}{12}}}\)

t=1.42

Also corresponding   P-Value = 0.169

Since calculated P-Value = 0.169 which is greater then 0.05 we accept our null hypothesis and concludes that there is no difference in the mean amount of caffeine of these two brands.

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Answer:

Here is the result:

(2, 3)      ↔      (2, 2)                     ∵ x = 2 is duplicated

(-5, 2)     ↔      (-5, 1)                     ∵ x = -5 is duplicated

(6, -5)     ↔      (6, 5)                     ∵ x = 6 is duplicated

(-1, 0)      ↔      (-1, 6)                     ∵ x = -1 is duplicated

Here, each matching pair has duplicated input values, so neither of them represents the function.

Step-by-step explanation:

We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.

In other words, we can not have duplicated inputs as there should be only 1 output for each input.

We are given that we need to match the ordered pairs so that the relation defined by the set of ordered pairs does not represent a function.

Therefore, all we need is to match the ordered pairs which have the same input value as it would violate the relation to be function.

Here is the result:

(2, 3)      ↔      (2, 2)                     ∵ x = 2 is duplicated

(-5, 2)     ↔      (-5, 1)                     ∵ x = -5 is duplicated

(6, -5)     ↔      (6, 5)                     ∵ x = 6 is duplicated

(-1, 0)      ↔      (-1, 6)                     ∵ x = -1 is duplicated

Here, each matching pair has duplicated input values, so neither of them represents the function.

Answer:

$50.91

Step-by-step explanation:

Let T represent the total cost of goods purchased.

Sale tax = 8.25% of total cost of good purchased.

Sales tax = 8.25% of T

Total cost T of goods mike purchased is;

a sweater for 49.95 = $49.95

and two pair of slacksfor 68.59 each = 2 × $68.59

and a suit for 429.99 = $429.99

T = 49.95 + 2(68.59) + 429.99

T = $617.12

And since;

Sales tax = 8.25% of T

Substituting T;

Sale tax = 8.25% of 617.12

Sales tax = 8.25/100 × $617.12

Sales tax = $50.91

Step-by-step explanation:

See below

Answer:

\( \frac{5}{n + 3} \)

Step-by-step explanation:

\(1. \: 5 \times \frac{1}{n + 3} \\ 2. \: \frac{5}{n + 3} \)

ANSWER

EXPLANATION

The problem represents a geometric progression.

The general form of a geometric sequence is:

where a = first term

r = common ratio

The first term from the table is the first price (for the first month). That is $80.00

To find the common ratio, we divide a term by its preceeding term.

Let us divide the price of the second month from the first.

We have:

The price after the 8th month is the value of a(n) when n = 8

So, we have that:

A flashlight has six batteries, two of which are defective. if two are selected at random without replacement, then the probability that both selected batteries are defective is 1/15.

To find the probability that both selected batteries are defective, we need to calculate the probability of selecting a defective battery on the first draw, and then the probability of selecting another defective battery on the second draw.

There are a total of 6 batteries, and 2 of them are defective. So, the probability of selecting a defective battery on the first draw is 2/6.

After the first draw, there will be 5 batteries remaining, and 1 defective battery remaining. So, the probability of selecting another defective battery on the second draw, without replacement, is 1/5.

To find the probability of both events occurring, we multiply the probabilities:

P(both defective) = P(defective on first draw) * P(defective on second draw)

= (2/6) * (1/5)

= 1/15

Therefore, the probability that both selected batteries are defective is 1/15.

The question should be:

A flashlight has six batteries, two of which are defective. If two are selected at random without replacement, find the probability that both are defective.

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The better buy is given by the following brand:

Brand A.

The better buy is obtained applying the proportions in the context of the problem.

A proportion is applied as the cost per ounce is given dividing the total cost by the number of ounces.

Then the better buy is given by the option with the lowest cost per ounce.

The cost per ounce for each brand is given as follows:

$8 per ounce is a lesser cost than $9.3 per ounce, hence the better buy is given by Brand A.

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Answer:

.54788732

Step-by-step explanation:

win / total = 6 /9

For 15 games:

x / 15

Where x is the number of wins in 15 games.

Cross multiply:

Divide both sides by 9

They will win 10 games.

Answer:

A) The equation for the height of the rocket is h = a(t)^2 + b(t) + c, where h is height in feet and t is time in seconds. Since the rocket is launched with an initial vertical velocity of 100 ft, the value of a is 1/2*(-16) = -8. The rocket is launched from a 5-foot platform, so the initial height of the rocket is 5 feet. Therefore, the value of c is 5. To find the value of b, we need to use the initial velocity of the rocket. At t=0, the initial height is 5 feet and the initial velocity is 100 feet per second. Thus, b = 100t + 5.

B) To find the time when the rocket reaches maximum height, we need to find the vertex of the parabolic equation. The vertex of the parabola is given by the formula t = -b/2a. Plugging in the values of a and b, we get t = -100/-16 = 6.25 seconds. To find the maximum height, we need to plug in this value of t into the equation for h: h = -8(6.25)^2 + 100(6.25) + 5 = 320.3125 feet.

C) To find the time when the rocket hits the ground, we need to find the time when h = 0. Setting h to 0 in the equation, we get: 0 = -8t^2 + 100t + 5. Using the quadratic formula, we get t = (-100 +/- sqrt(100^2 - 4*(-8)5))/(2(-8)) = 12.81 seconds. Therefore, the rocket hits the ground after 12.81 seconds.

D) The equation for the height of the rocket after the parachute opens is y = -5x + b. We want the entire trip to take 9 seconds, so the rocket will be descending for (9-6.25) = 2.75 seconds. During this time, the rocket will descend a total of 2.75*5 = 13.75 feet. Since the rocket was at a height of 320.3125 feet when the parachute opened, it needs to descend a further 13.75 feet to reach the ground. Therefore, the value of b in the equation for y is 320.3125 + 13.75 = 334.0625. To find the time when the parachute should open, we need to solve the equation h = -5t + 334.0625 for t, where h is the height of the rocket. Setting h to 100 feet (the height at which the parachute should open), we get: 100 = -5t + 334.0625. Solving for t, we get t = 46.8125 seconds. Therefore, the parachute should open after 46.8125 - 6.25 = 40.5625 seconds.

Answer:

2

Step-by-step explanation:

Logarithm base 6 of 36 is 2 .

Answer:

9. 89

Step-by-step explanation:

A squared + B squared = C squared

7 squared + 7 squared = 98 squared

Find the square root of 98 (I recommend using a calculator)

You should get 9.89 as an answer.

80+x+45=180 (sum of angles on a straight line)

x=180-80-45

x=55.