Please please with a cherry on top
if your dont like cherries then maybe a Oreo on top
and if you dont like Oreo's maybe then a Waffle on top
I dont know you choose but can you please help me answer this question
(Find X & Happy Thanksgiving)

To evaluate the expression S = ∫(a²)du, we can break it down into smaller components. In this case, a² represents the square of a variable a, and a represents the value of the variable itself. Similarly, u² represents the square of a variable u, and u represents the value of the variable itself. Evaluating du involves finding the differential of u. Finally, integrating the expression ∫(a²)du results in a new function that represents the antiderivative of a² with respect to u.



1. The term a² represents the square of a variable a. It implies that a is being multiplied by itself, resulting in a².

2. To determine the value of a, we would need additional information or context. Without a specific value or equation involving a, we cannot calculate its numerical value.

3. Similarly, u² represents the square of a variable u. It implies that u is being multiplied by itself, resulting in u².

4. Like a, the value of u cannot be determined without further information or context. It depends on the specific problem or equation involving u.

5. du represents the differential of u, which signifies a small change or infinitesimal increment in the value of u. It is used in the process of integration to indicate the variable of integration.

6. The result of evaluating ∫(a²)du would be a function that represents the antiderivative of a² with respect to u. Since there is no specific function or limits of integration provided in the expression, we cannot determine the exact result of the integration without additional information.

In summary, without specific values for a, u, or the limits of integration, we can only describe the properties and meaning of the components in the expression S = ∫(a²)du.

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Answer:

33.3%

Step-by-step explanation:

$2 on nachos and $2 on candy will get you $4 spent on them both.

You then have a fraction (4/12)which is 1/3.

1/3=33.3%

Answer:

See below

Step-by-step explanation:

As per the graph we have:

Slope formula is:

Slope of JL:

Slope of MP:

Answer:c

Step-by-step explanation:

Answer:

$2,245.

Step-by-step explanation:

Your interest will have grown to  $2,245 dollars and you will have earned $1,545.

Hope this helped

The difference in the proportion of males and the proportion of females that smoke is 0.08

In a sample of 61 males, 15 smoke, while in a sample of 48 females, 8 smoke.

The given parameters are:

                             Male           Female

Sample                  61                  48

Smokers               15                   8

The proportion is calculated using:

p = Smoker/Sample

So, we have:

Male = 15/61 = 0.25

Female = 8/48 = 0.17

The difference is then calculated as:

Difference = 0.25 - 0.17

Evaluate

Difference = 0.08

Hence, the difference in the proportion of males and the proportion of females that smoke is 0.08

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Answer:

Use tan trig ratio:

\(\sf tan(\theta)=\dfrac{O}{A}\)

where \(\theta\) is the angle, O is the side opposite the angle, and A is the side adjacent the angle

Given:

Substituting these values into the formula:

\(\implies \tan(39)=\dfrac{10}{x}\)

Multiplying both sides by \(x\):

\(\implies x\tan(39)=10\)

Dividing both sides by \(\tan(39)\) :

\(\implies x=\dfrac{10}{\tan(39)}\)

\(\implies x=12.34897157...\)

\(\implies x=12.3 \ \textsf{(nearest tenth)}\)

\(\\ \rm\rightarrowtail tan\theta=\dfrac{Perpendicular}{Base}\)

\(\\ \rm\rightarrowtail tan51=\dfrac{x}{10}\)

\(\\ \rm\rightarrowtail x=10tan51\)

\(\\ \rm\rightarrowtail x=10(1.2348971565350)\)

\(\\ \rm\rightarrowtail x=12.348971565350\)

Answer:

To determine the general solution for the differential equation dy/dt = (ty - 2t + 4y - 8)/(ty + 3t - y - 3), we can rewrite it in the form dy/dt = (t - 2)/(t - 1).By separating variables and integrating, we find the general solution as y = t + C(t - 1), where C is an arbitrary constant.

For the initial value problem ty + t^2 dy/dt = y with y(-1) = -1, we substitute the given initial condition into the general solution to find the specific solution.

(i) To find the general solution for dy/dt = (ty - 2t + 4y - 8)/(ty + 3t - y - 3), we can simplify the right-hand side to (t - 2)/(t - 1) by factoring and canceling common terms. Next, we can separate variables by multiplying both sides by (t - 1) and dt, yielding (t - 1)dy = (t - 2)dt. Integrating both sides gives us y = t + C(t - 1), where C is an arbitrary constant.

(ii) For the initial value problem ty + t^2 dy/dt = y with y(-1) = -1, we substitute the initial condition y(-1) = -1 into the general solution. Plugging in t = -1 and y = -1 into y = t + C(t - 1), we have -1 = -1 + C(-1 - 1). Simplifying this equation gives us C = 0. Therefore, the solution to the initial value problem is y = t.

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The set that we must describe is composed of those which are at least 6.5. At least means that these values are either 6.5 or greater. Then if n is any element of this set it meets the following condition:

Then the answer is the first option.

According to the question,

6x + 90 = -42

The value of x.

6x = -42 + 90

or, x = 48/6

or, x = 8

The value of x is 8.

Answer:     9 • 10⁵

-----------------------------------------------------------------------------------------

The 3(1/√(x² + y² + z²)) is a nonzero constant, there is no value of p that makes the divergence zero.

To find the divergence of the vector field f = r/r p, we need to compute the dot product of the gradient operator (∇) with f.

The gradient operator in Cartesian coordinates is given by:

∇ = ∂/∂x i + ∂/∂y j + ∂/∂z k

And the vector field f can be written as:

f = r/r p = (xi + yj + zk)/(√(x² + y² + z²)) p

Now, let's compute the dot product:

∇ · f = (∂/∂x i + ∂/∂y j + ∂/∂z k) · [(xi + yj + zk)/(√(x² + y² + z²)) p]

Taking each component of the gradient operator and applying the dot product, we get:

∂/∂x · [(xi + yj + zk)/(√(x² + y² + z²)) p] = (∂/∂x)(x/√(x² + y² + z²)) p

= (1/√(x² + y² + z²)) p

∂/∂y · [(xi + yj + zk)/(√(x² + y² + z²)) p] = (∂/∂y)(y/√(x² + y² + z²)) p

= (1/√(x² + y² + z²)) p

∂/∂z · [(xi + yj + zk)/(√(x² + y² + z²)) p] = (∂/∂z)(z/√(x² + y² + z²)) p

= (1/√(x² + y² + z²)) p

Adding up these components, we have:

∇ · f = (1/√(x² + y² + z²)) p + (1/√(x² + y² + z²)) p + (1/√(x² + y² + z²)) p

= 3(1/√(x² + y² + z²)) p

So, the divergence of f is given by:

div f = 3(1/√(x² + y² + z²)) p

Now, we need to find if there exists a value of p for which div f = 0. Since 3(1/√(x² + y² + z²)) is a nonzero constant, there is no value of p that makes the divergence zero. Therefore, the answer is "dne" (does not exist).

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Answer: $50

Step-by-step explanation:

If sentence 6 states that ¬C is true, and sentence 7 presents a conditional statement with C as the antecedent and Q as the consequent, we can use modus ponens to infer that Q is false.

Modus ponens is a deductive reasoning rule that allows us to derive a conclusion from a conditional statement and its antecedent. Therefore, we can apply modus ponens to sentence 7 given that we know ¬C from sentence 6.
Since from sentence 6 we know ¬C, we can apply modus ponens to sentence 7. To do this, follow these steps:
1. Identify the premises: One premise is sentence 6, which states ¬C. The other premise should be a conditional statement, such as "If ¬C, then P" (replace P with the relevant proposition).
2. Apply modus ponens: Modus ponens is a rule of inference that allows us to deduce a conclusion from the given premises. If we have the premises "If ¬C, then P" and "¬C", we can conclude "P" using modus ponens.
3. State the conclusion: After applying modus ponens, we can conclude "P" based on the given premises, which include sentence 6 (¬C) and the conditional statement.

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Answer:

7776

Step-by-step explanation:

you divide 5 by 2 to get 2.5 then put 36 to the power of 2.5 to get 7,776

Part A: Width = 9.3 ft; Height = 16.5 ft; Area =  153.45 sq ft.

Part B: Width = 38.25 ft ; Height = 91 ft; Area =  3503.5 sq ft.

Part A: conversion factor: 1 in = 3 ft

Width = 3.1 in

Width = 3.1 x 3

Width = 9.3 ft

Height = 5.5 x 3 ft

Height = 16.5 ft

Area = Width x Height

Area = 9.3 ft x  16.5 ft

Area = 153.45 sq ft

Part B: conversion factor: 1 in = 6.5 ft

Width = 8.5 in

Width = 8.5 x 6.5

Width = 38.25 ft

Height = 14 x 6.5 ft

Height = 91 ft

Area = Width x Height

Area = 38.5 ft x  91 ft

Area =  3503.5 sq ft

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1. Desk: Estimate around 70 centimeters.
2. Whiteboard: Estimate around 120 centimeters.
3. Bookshelf: Estimate around 150 centimeters.

In the classroom, you can find three items that are longer than 10 centimeters and smaller than 100 centimeters.

To find three items in the classroom that fit the given criteria, you can think of common objects that are larger than 10 centimeters and smaller than 100 centimeters. Some examples include desks, whiteboards, and bookshelves. By estimating their lengths, we can approximate their sizes within the given range.

The estimates provided are just rough approximations to give you an idea of their lengths.

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The equation regarding the algebraic information that represents the total earnings is y = 22x + 125.

From the information that's given, it can be seen that the expression is:

y = 22x + 125

She earned $555 after working for 15 hours. Therefore, the equation to represent the total earnings will be:

y = 22x + 125.

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The answer will be 81.

Step-by-step explanation:

just multiple by 3

Answer:

81

Step-by-step explanation:

the people told secrion has a sequence of multiplyung by 3 if you continue the sequence you will get to 81

The height is 2 and radius is √2 of the largest right circular cylinder that can be put into a sphere of radius √3.

A cylinder whose bases are circular in shape and parallel to each other is called the right circular cylinder. It is a three-dimensional shape.

Given that the radius of a sphere R = √3

Let the radius of the cylinder is r and the height of the cylinder is h.

than.

r² = R² − h²/4

and Vc = πr²h

⇒ Vc = π(R² − h²/4)h

⇒ Vc = πR²h − πh³/4

dVc/dh = πR² − 3πh²/4  

(dVc/dh)R=√3 = 3π − 3πh²/4

For maximum or minimum volume,

dVc/dh = 0

⇒ 3π − 3πh²/4 = 0

⇒ 3πh²/4 = 3π

⇒ 3πh² = 3π*4

⇒ h² = 4

⇒ h=2

Also,  dVc/dh changes sign from positive to negative in the neighborhood of h=2. Hence, h=2 is a maximum point.

r² = R² − h²/4

⇒ r² = (√3)² - 2²/4

⇒ r² = 3 - 1

⇒ r² = 2

​⇒ r = √2

So, the height is 2 and radius is √2 of the largest right circular cylinder

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Windsor Company issued $5,770,000 face value of 14%, 20-year bonds on June 30, 2020, at a yield of 12%. The company uses the effective-interest method to amortize bond premium or discount.

The following journal entries are required to record the transactions:

(1) issuance of the bonds, (2) payment of interest and amortization of the premium on December 31, 2020, (3) payment of interest and amortization of the premium on June 30, 2021, and (4) payment of interest and amortization of the premium on December 31, 2021.

Issuance of the bonds on June 30, 2020:

Cash $6,638,160

Bonds Payable $5,770,000

Premium on Bonds $868,160

This entry records the issuance of bonds at their selling price, including the cash received, the face value of the bonds, and the premium on the bonds.

Payment of interest and amortization of the premium on December 31, 2020:

Interest Expense $344,200

Premium on Bonds $11,726

Cash $332,474

This entry records the payment of semiannual interest and the amortization of the premium using the effective-interest method. The interest expense is calculated as ($5,770,000 * 14% * 6/12), and the premium amortization is based on the difference between the interest expense and the cash paid.

Payment of interest and amortization of the premium on June 30, 2021:

Interest Expense $344,200

Premium on Bonds $9,947

Cash $334,253

This entry is similar to the previous entry and records the payment of semiannual interest and the amortization of the premium on June 30, 2021.

Payment of interest and amortization of the premium on December 31, 2021:

Interest Expense $344,200

Premium on Bonds $8,168

Cash $336,032

This entry represents the payment of semiannual interest and the amortization of the premium on December 31, 2021, using the same calculation method as before.

These journal entries accurately reflect the issuance of the bonds and the subsequent payments of interest and amortization of the premium in accordance with the effective-interest method.

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Answer:

Step-by-step explanation:

You just combine common variables.

8a^5 -4

3a^5 + a -2

11a^5 + a -6

The solution to the first is 11a^5+a-6.

The second:

3x^2 -2x + 1

-x^2 + 3x + 1

2x^2 + x + 2

2x^2+x+2

Answer:

0.03

Step-by-step explanation:

The probability of getting a false-positive result is 0.03 if Arborists use a test to detect the presence of a certain pathogen in fruit trees option (D) is correct.

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

Arborists use a test to detect the presence of a certain pathogen in fruit trees.

The probability that the tree has a disease = 96%

Or

The probability when the tree has a disease = 0.96

The probability when the tree does not have a disease = 97%

Or

The probability when the tree does not have a disease = 0.97

Probability of getting a false-positive result = 1 - 0.97

Probability of getting a false-positive result = 0.03

Thus, the probability of getting a false-positive result is 0.03 if Arborists use a test to detect the presence of a certain pathogen in fruit trees option (D) is correct.

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Answer:

22.5

Step-by-step explanation:

Brainliest plzzz

Answer:

1:2

Step-by-step explanation:

Answer:

9 Km

Step-by-step explanation:

Pythagorean theorem,

Base² + altitude² = hypotenuse²

12² + x² = 15²

144 + x² = 225

        x² = 225 - 144

       x² = 81

x = √81 = √9*9

x = 9 Km

(a) tangent line to the graph of f(x) = x^3 at the point (4,2).

(b) equation of the tangent line to the graph of f(x) = x^2 - x at the point (4,12).

(a) To find the equation of the tangent line to the graph of f(x) = x^3 at the point (4,2), we need to find the slope of the tangent line at that point. We can do this by taking the derivative of f(x) with respect to x and evaluating it at x = 4. The derivative of f(x) = x^3 is f'(x) = 3x^2. Evaluating f'(x) at x = 4 gives us the slope of the tangent line. Once we have the slope, we can use the point-slope form of a linear equation to write the equation of the tangent line.

(b) Similarly, to find the equation of the tangent line to the graph of f(x) = x^2 - x at the point (4,12), we differentiate f(x) to find the derivative f'(x). The derivative of f(x) = x^2 - x is f'(x) = 2x - 1. Evaluating f'(x) at x = 4 gives us the slope of the tangent line. Using the point-slope form, we can write the equation of the tangent line.

In both cases, the equations of the tangent lines will be in the form y = mx + b, where m is the slope and b is the y-intercept.

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Answer:

\(60+3x+5x=180\\8x=120\\x=15\)

\(\angle ABC=5x=5\times15=75\textdegree\\\angle ACB=3x=3\times15=45\textdegree\)

Answer:

X=3

Y=1

Step-by-step explanation:

Vertex A forms dilation F

Answer:

x=27

Step-by-step explanation:

Answer:

The answer would be 27

Step-by-step explanation:

Times three by nine to get the value of x.