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To solve the question we must know about the System of equations.

A system of equations to have no real solution, the lines of the equations must be parallel to each other.

A system of the equation to be Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.

A system of the equation to be Independent Consistent System the system must have one unique solution for which the lines of the equation must intersect at a particular.

The value of k should be 17 so that the system of equations gives infinite number of solutions.

Given to us

As we know that for a system of equations to give an infinite number of solutions. the equations of the system must be either same or in ratio.

\(35x + 14y = 119,\)

dividing both the sides of the equation by 7,

\(\dfrac{35x + 14y}{7} = \dfrac{119}{7}\\\\ \dfrac{35x}{7}+\dfrac{14y}{7} = \dfrac{119}{7}\\ 5x+2y = 17\)

As already discussed the system of equations to give infinite number of solutions, the equations must be the same. therefore, comparing both the equations we see that the value of k should be 17.

Hence, the value of k should be 17, so that the system of equations gives infinite number of solutions.

As we can see in the below image on equating the value of k as 17, the line of the system of equations coincides, therefore, the system will have infinite number of solutions.

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Answer:

answer is c

Step-by-step explanation:

i took the test on edge and i passed it. good luck

Answer:

0.135

Step-by-step explanation:

first, find the total kids in the group

14 + 69 + 21 = 104

14 students / 104 total

14/104 = 0.13461...

rounded to the nearest thousandth is 0.135

The needed 3rd-degree polynomial function with real coefficients matching the specified constraints will be y=-5x³+10x²-45x+90.

A polynomial is a mathematical statement made up of indeterminates and coefficients that solely includes the operations of addition, subtraction, multiplication, and positive-integer powers of variables. x2 4x + 7 is an example of a polynomial with a single indeterminate x. Polynomials are sums of k-x^n terms, where k can be any number and n can be any positive integer. 3x+2x-5, for example, is a polynomial. Polynomials are introduced. This video defines words such as degree, standard form, monomial, binomial, and trinomial.

Here,

y=-5(x-2)(x-3i)(x+3i)

y=-5(x-2)(x²+9)

y=-5(x³-2x²+9x-18)

y=-5x³+10x²-45x+90

The required 3rd-degree polynomial function with real coefficients satisfying the given conditions will be y=-5x³+10x²-45x+90.

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Answer:

\(\Large \boxed{\mathrm{Option \ B}}\)

Step-by-step explanation:

The equation is in the form ax² + bx + c = 0.

x² - c = 0

1x² + 0x + -c = 0

Where : a = 1, b = 0, and c = -c

c > 0

The quadratic equation can always be factored if c is a square number

c can be a square number and the quadratic equation can be solved by using the difference of two squares formula.

x is squared so it can be solved by isolating x on one side by adding c to both sides and using the square root property.

Answer:

\(\huge\boxed{Option \ B}\)

Step-by-step explanation:

\(x^2 - c = 0\)

This equation is in a quadratic form since:

=> It has the highest power of x as 2. Those equations are quadratic equations in which the highest power of x is 2.

=> However, Those quadratic equation in which b = 0 , and they are like either \(ax^2 + c = 0 \ OR \ ax^2-c = 0\), They are called pure quadratic equation.

So, \(x^2 - c = 0\) is a quadratic equation.

a. F(G(p)) = 4p^2 + 12p + 2, b. F(G(H(p))) = 4|p|^2 + 12|p| + 2, c. G(F(1)) = 5  To find the compositions of the given functions, let's substitute the functions into each other as follows:

a. F(G(p)):

F(G(p)) = F(2p + 1)

        = (2p + 1)^2 + 4(2p + 1) - 3

        = 4p^2 + 4p + 1 + 8p + 4 - 3

        = 4p^2 + 12p + 2

b. F(G(H(p))):

F(G(H(p))) = F(G(|p|))

           = F(2|p| + 1)

           = (2|p| + 1)^2 + 4(2|p| + 1) - 3

           = 4|p|^2 + 4|p| + 1 + 8|p| + 4 - 3

           = 4|p|^2 + 12|p| + 2

c. G(F(1)):

G(F(1)) = G(1^2 + 4(1) - 3)

        = G(2)

        = 2(2) + 1

        = 4 + 1

        = 5

In mathematics, function composition is an operation that combines two functions to create a new function. Given two functions f and g, the composition of f and g, denoted as f(g(x)), is a new function that applies g to an input value x and then applies f to the result.

In simpler terms, function composition allows you to plug one function into another, where the output of the inner function becomes the input of the outer function.

For example, let's say we have two functions:

f(x) = 2x + 1

g(x) = x^2

To find the composition f(g(x)), we substitute g(x) into f:

f(g(x)) = 2(g(x)) + 1

        = 2(x^2) + 1

        = 2x^2 + 1

Function composition is a way to combine and transform functions to create new functions that may exhibit different behaviors or properties. It is a fundamental concept in mathematics and is used in various branches such as calculus, algebra, and analysis.

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Answer:

The LCM of 100 and 120 is 600.

The LCM of 5 and 120 is 120.

LCM of 5 and 100 is 100.

Step-by-step explanation:

I think this is the answer . If it is not sorry .

Answer:

Area = 10 in

Step-by-step explanation:

Base=4 in , Height=2 in , Other Side = 3 in.

Height x Other Side + Base

2 x 3 + 4

2 x 3 = 6 + 4 = 10

The function that models the number of bacteria ttt seconds since the medicine was introduced is N(t) = 45000 (0.75)t/14.

The function that models the number of bacteria ttt seconds since the medicine was introduced, where the bacterial culture loses 25% of its size every 1414 seconds is given by the formula

N(t) = 45000 (0.75)t/14

Here, N(t) = The number of bacteria at time ttt seconds after the medicine is introduced.

45000 = The initial number of bacteria (before the medicine was introduced).

t = time in seconds since the medicine was introduced.0.75 = The rate of decay (since 25% of the bacteria dies every 14 seconds).

The formula is obtained by applying exponential decay: N(t) = N0ekt, where N0 is the initial number of bacteria, k is the decay constant, and t is time in seconds.

The decay constant is related to the rate of decay (r) and the time taken for the culture to lose 25% of its size (T), by the formula k = ln(1 - r)/(-T).

Substituting r = 0.25 and T = 14 into the formula, we get

k = ln(0.75)/(-14)k = -0.049226Logarithmic functions are used to solve problems in which a quantity grows or decays at a constant percentage rate over time.

The formula for the number of bacteria N(t) at time ttt after the medicine is introduced is:

N(t) = N0 ekt

Here, N0 is the initial number of bacteria, and k is the decay constant.

Given that the bacterial culture loses 25% of its size every 14 seconds, the decay constant k can be calculated as follows:

k = ln(0.75)/(-14)k

= -0.049226

Substituting N0 = 45000 and k = -0.049226 into the formula, we get:

N(t) = 45000 e-0.049226t/14N(t)

= 45000 (0.75)t/14

Hence, the function that models the number of bacteria ttt seconds since the medicine was introduced is N(t) = 45000 (0.75)t/14.

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Once the protection period for a new invention expires, the invention is said to be in the public domain.

The invention without permission from the original inventor, and the inventor cannot prevent others from doing so.

In other words, the invention becomes freely available for anyone to use or benefit from, without any legal restrictions.

The length of time for which an invention is protected depends on the type of intellectual property protection granted, such as patents or trademarks, and the laws of the country or region where the protection is sought.

The creator cannot restrict others from using, manufacturing, or selling the innovation without the consent of the original inventor.

In other words, there are no longer any constraints on who can utilise or benefit from the idea.

The kind of intellectual property protection granted, such as patents or trademarks, as well as the legal framework of the nation or region where the protection is sought, determine the duration of an invention's protection.

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Answer:

The error is at (-4, 0) where 0 should be changed to 1

Step-by-step explanation:

The error was made at (-4, 0). The point should be (-4, 1) instead, because the y values should be increasing by 3 each time.

Answer:

108.9

Step-by-step explanation:

180-(30.3+40.8)

180-71.1

108.9

Answer:

Below

Step-by-step explanation:

Cross multiply the fractions to get

3 (x+4 ) = 4(x+3)

3x + 12  = 4x + 12     subtract 12 from both sides

3x = 4x      <======obviously , this can only happen when x = 0  

ONE SOLUTION

The situation given that can be represented by a graph with a y-intercept of -8 is A. Hal bought $8 worth of supplies, then sold x buttons for $3 each. His profit is y dollars.

The y-intercept is a figure in the linear equation that shows the original number of units before the value of x either started to increase or to decrease and therefore cause a change in x.

The situation where Hal bought $8 worth of supplies would be represented by the y-intercept of -8 because the $8 that Hal bought represents his total profit before he sells anything. That total profit is -8 because Hal has spent -$8 but has not sold anything.

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Answer:

100mi

Step-by-step explanation:

No, (−5, −4) is not a solution of the system. The ordered pair (−5, −4) is a point in the Cartesian plane, but it is not necessarily a solution of any system of equations.

To determine whether an ordered pair is a solution of a system of equations, we must substitute the values of the ordered pair into the equations in the system and determine whether the equations are true.

For example, consider the following system of equations:

3x − 5y = 20

2x + 4y = 10

To determine whether (−5, −4) is a solution of this system, we must substitute the values of x and y into the equations and determine whether the equations are true.

For the first equation:

3x − 5y = 20

3(-5) − 5(-4) = 20

15 + 20 = 20

35 ≠ 20

For the second equation:

2x + 4y = 10

2(-5) + 4(-4) = 10

-10 - 16 = 10

-26 ≠ 10

Since neither equation is true when the values of (−5, −4) are substituted into the equations, we can conclude that (−5, −4) is not a solution of the system.

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Answer:

$6.25

Step-by-step explanation:

The type of circuit that is represented above is a closed circuit that allows electrons to flow. That is option B

A circuit is defined as the electrical or electronic pathway that allows the flow of an electrical current.

There are two types of circuit that include the following;

The closed circuit is defined as the type of circuit that is complete and allow the flow of current

The open circuit is the type of circuit that is incomplete and that cannot allow complete flow of electrons.

The circuit shown above is a complete circuit that allows the build to turn on.

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Answer:

y=5/2x-1

Step-by-step explanation:

For three fair six-sided dice, the possible sum of the faces rolled can be any digit from 3 to 18.the number of sums will be greater than 16 and the minimum number greater than 16 is 17.

For instance the minimum sum occurs when all three dices shows 1 (i.e. 1 + 1 + 1 = 3) and the maximum sum occurs when all three dces shows 6 (i.e. 6 + 6 + 6 = 18).

Thus, there are 16 possible sums when three six-sided dice are rolled.

Therefore, from the pigeonhole principle, the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice is 16 + 1 = 17 times.

The pigeonhole principle states that if n items are put into m containers, with n > m > 0, then at least one container must contain more than one item.

That is for our case, given that there are 16 possible sums when three six-sided dice is rolled, for there to be two same sums, the number of sums will be greater than 16 and the minimum number greater than 16 is 17.

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Answer:

cool

Step-by-step explanation:

O m g r e a l l y ?

Never knewww

The maximum time that can be spent packing PDAs and still be profitable is 5 hours.

The maximum time that can be spent packing PDAs and still be profitable will depend on a variety of factors, such as the cost of producing the PDAs, the cost of labor for packing, and the selling price of the PDAs. In order to determine the maximum time that can be spent packing and still be profitable, you would need to consider these factors and calculate the break-even point, which is where the total cost of production equals the total revenue from sales.

For example, if the cost of producing one PDA is $50, the cost of labor for packing is $10 per hour, and the selling price of the PDA is $100, then the break-even point would be at 5 hours of packing time. This means that the maximum time that could be spent packing the PDAs and still be profitable would be 5 hours.

In general, the maximum time that can be spent packing and still be profitable will be determined by the formula:

Maximum time = (Selling price - Cost of production) / Cost of labor for packing

So, in this case:

Maximum time = ($100 - $50) / $10 = 5 hours

Therefore, the maximum time that can be spent packing PDAs and still be profitable is 5 hours.

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Answer:

225

Step-by-step explanation:

(- 15)² = - 15 × - 15 = 225

Answer:

1.    -30x     2. 12x    3.   x         4.  2x

Step-by-step explanation:

i believe the way your learning is that you have to add or subtract both numbers and then add the letter next to the answer.  number 3 is just x because -1- 4x = 0 and just add the x.

Answer:

D) Angle angle angle

Answer:

here you go

Step-by-step explanation:

If person A and person B have equal positive amounts of goods X and Y and person A values good X more than good Y and person B values good Y more than good X, there are mutually beneficial trades available.

Mutually beneficial trades are the kind of trades that benefit both parties in a trade agreement. A mutually beneficial trade occurs when two countries or individuals trade and both benefit from the transaction. In the case where person A and person B have equal positive amounts of goods X and Y and person A values good X more than good Y and person B values good Y more than good X, there are mutually beneficial trades available. This is because person A would be more willing to trade his good Y for Person B’s good X since person A values good X more than good Y and person B would be more willing to trade his good X for person A’s good Y since person B values good Y more than good X. In this way, both parties would benefit from the transaction because they would be trading the goods they value less for the ones they value more.

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Problem 1

U = {2,3,8} is the entire universe. It's all of the numbers that exist in this framework. We ignore anything else.

A = {2,3,8} simply copies the universe and lists all the values we care about.

The complement of set A is any number not in set A. But because set A lists everything we care about, there's nothing left.

Therefore, the complementary set is empty.

We can write the empty set as { } which is a pair of curly braces with nothing between them. Not even 0 is part of this set.

=============================================================

Problem 2

U = {whole numbers} = {0,1,2,3,4,...}

This time the universal set is a bit more interesting, or at the very least, it's much bigger.

Set A is the set of odd whole numbers, so A = {1,3,5,7,9,...}. Notice how anything inside set A is also in set U. We can say set A is a subset of set U.

The complement of set A would be the set of even whole numbers {0,2,4,6,...}. This is the list of stuff not found in set A, but it's in the universal set.

Combing the evens and odds together will help form the set of all whole numbers.

=============================================================

Problem 3

set of whole numbers = {0,1,2,3,4,...}

Because h is a whole number, this means h must be selected from that set of values above and nowhere else.

We're then told that h < -2, but there is no such whole number that fits the description. Something like 4 < -2 is false. If we wanted negative values like this, then we'd have to expand to the set of integers.

Therefore, the set being described has nothing in it.