The area under the curve to the right of z = 1.43 in a standard normal distribution is 0.0764. In a standard normal distribution, the total area under the curve is equal to 1.
Since the distribution is symmetric, the area to the left of any given z-score is equal to the area to the right of the negative of that z-score.
To find the area to the right of z = 1.43, we can use the standard normal distribution table or a statistical calculator. Looking up the value of 1.43 in the table, we find the corresponding area to the left of z = 1.43 is 0.9236.
Since the area under the curve is equal to 1, the area to the right of z = 1.43 is equal to 1 - 0.9236 = 0.0764.
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What is the equation of the oblique asymptote?
h(x) = x² – 3x - 4/x + 2
Simplifying h(x) gives
h(x) = (x² - 3x - 4) / (x + 2)
h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)
h(x) = ((x + 2)² - 7x - 8) / (x + 2)
h(x) = ((x + 2)² - 7 (x + 2) - 14 - 8) / (x + 2)
h(x) = ((x + 2)² - 7 (x + 2) - 22) / (x + 2)
h(x) = (x + 2) - 7 - 22/(x + 2)
h(x) = x - 5 - 22/(x + 2)
An oblique asymptote of h(x) is a linear function p(x) = ax + b such that
\(\displaystyle \lim_{x\to\pm\infty} h(x) - p(x) = 0\)
In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.
If S is a subspace of R3 containing only the zerovector, what is Sperp?If S is spanned by (1,1,1), what is Sperp?If S is spanned by (2,0,0) and (0,0,3), what isSperp?I'm fairly sure that two vectors are orthogonal if their dotproduct is 0, but I want to make sure I'm doing this correctly.
1. f S is a subspace of R3 containing only the zerovector, the Sperp is equal to R3
2. If S is spanned by (1,1,1), the Sperp is spanned by (-1,-1,-2)
3. If S is spanned by (2,0,0) and (0,0,3), Sperp is spanned by (0,-6,0)
To find Sperp, we need to find the set of all vectors that are perpendicular to every vector in S.
1. If S only contains the zero vector, then any vector in R3 is perpendicular to every vector in S. Therefore, Sperp = R3.
2. If S is spanned by (1,1,1), then any vector that is orthogonal to (1,1,1) will be in Sperp. We can find such a vector by taking the cross product of (1,1,1) with any vector that is not parallel to it, say (1,-1,0):
(1,1,1) x (1,-1,0) = (-1,-1,-2)
So, Sperp is spanned by (-1,-1,-2).
3. If S is spanned by (2,0,0) and (0,0,3), then any vector that is orthogonal to both (2,0,0) and (0,0,3) will be in Sperp. We can find such a vector by taking the cross-product of the two spanning vectors:
(2,0,0) x (0,0,3) = (0,-6,0)
So, Sperp is spanned by (0,-6,0).
Note that in all cases, Sperp is a subspace of R3.
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Write an additional expression for the situation. Then find the sum.A roller coaster drops 112 feet before going back up 52 feet.
Given:-
A roller coaster drops 112 feet before going back up 52 feet.
To find an additional expression for the situation. Then find the sum.
So here dropping down is considered as negative and back up is considered as positive.
So we get,
\(-112+52\)So the sum is,
\(-112+52=-60\)So the required solution is -60.
9) If point B with coordinates (5, 2) is dilated by a scale factor of 3, what will be the coordinates of the image point B'?
Answer
Option A is correct.
B' (15, 6) is the answer.
Explanation
To dilate a given coordinate (x, y) about the origin by a scale factor of n, we will obtain (nx, ny).
So, for the given coordinate (5, 2), dilating by the scale factor of 3, we will obtain
B (5, 2) = B' (5×3, 2×3) = B' (15, 6)
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At Panera one bagel costs $0.65. Thirteen bagels cost $7.90. Is the cost of bagels proportional to the number of bagels?
Answer:
no
Step-by-step explanation:
Is it possible to have a function f defined on [ 2 , 3 ] and meets the given conditions? f is not continuous on [ 2 , 3 ], takes on both a maximum value and minimum value and every value in between.
Yes, it is possible to have a function f defined on [2, 3] that meets the given conditions. To satisfy the condition of not being continuous on [2, 3], we can create a function with a removable discontinuity at a specific point.
One way to achieve this is by defining f(x) as a piecewise function. We can let f(x) be equal to a constant value c for x in [2, a) and [a, 3], where a is a value between 2 and 3. This will create a hole in the graph of the function at x = a, resulting in a removable discontinuity.
To ensure that f takes on both a maximum and minimum value, we can choose different constant values for f(x) in the intervals [2, a) and [a, 3]. For example, we can let f(x) be a high value like 100 in [2, a) and a low value like -100 in [a, 3]. This way, f(x) will have a maximum value of 100 and a minimum value of -100.
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Leah is paid semimonthly. How many fewer paychecks does she
receive in 2 years compared to someone who is paid weekly?
Answer:
Leah has 80 less paychecks than the weekly person.
Step-by-step explanation:
Leah is getting 24 paychecks in 2 years, Weekly person gets 104 paychecks in 2 years, 104 - 24 = 80 paychecks.
PLEASE HELP WITH THIS QUESTION!
Answer:
78
Step-by-step explanation:
because I know everything
Wendy and Connor each deposit 8,300 into accounts that earn 3.5% interest for 25 years Wendy's account earns annual simple interest sand Connor's account earns an annual compound interest who will earn more interest of 25 years and how much interest they will earn
Answer:
Connor will earn more interest because he is getting compound interest.
Step-by-step explanation:
I have to assume in this case that the interest is 3.5% Per year:
Simple Interest = P(r + t)
{P = Principle, r = interest rate, t = time)
Wendy = $8,300 x (3.5% x 25)
Wendy = $7,262.50 (2 d.p)
Wendy = $8,300 + $7,262.50
Wendy = $15,562.50
Compound Interest = \(P (1 +r )^{t}\)
{P = Principle, r = interest rate, t = time)
Connor = $8,300 x \((1 + 0.035)^{25}\)
Connor = $19,614.93
Wendy's Interest = $15,562.50 - $8,300 = $7,262.50
Connor's interest = $ 19,614.93 - $8,300 = $11,314.93
Connor earned more interest by $4,052.43
___________________________________________________
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What is the perimeter of the rectangle
Answer:
6x+6
Step-by-step explanation:
To find the perimeter you are going to add the length of all the edges. 2x+3 + 2x+3+x+x. When you simplify it all you found your answer.
Pre-Calc
It's timed, pls help
Answer:
I think it's B.
Hopefully this helps, sorry if i doesn't.
(Also i saw your Technoblade pfp, very nice)
on the hit HGTV show Flipping the Block, Whitney and John can paint 2 walls in 30 min. At this rate, how many walls can they paint
In 1, 2, 3, and 4 hours? Graph the ordered pairs created by (hours, walls) on the coordinate plane.
Pls answer QUICKKKK!!!
6. Express the average corn harvest weight in "people per a football field." How
many people per a football field is 14.2 Mg/ha?
The average corn harvest weight of 14.2 Mg/ha can be expressed as approximately 2,842 people per football field.
To calculate the number of people per football field based on the average corn harvest weight of 14.2 Mg/ha, we need to convert the weight to a unit that can be compared with the area of a football field.
Mg stands for megagrams, which is equivalent to metric tons (1 Mg = 1 tonne = 1,000 kg). Ha stands for hectares, which is a metric unit of area (1 ha = 10,000 square meters).
To convert the weight from metric tons to kilograms, we multiply 14.2 Mg by 1,000, resulting in 14,200 kg.
Next, to determine the weight per square meter, we divide the weight by the area in hectares. Since a football field typically covers an area of about 0.714 hectares, we divide 14,200 kg by 0.714 hectares, resulting in approximately 19,928 kg per hectare.
Finally, to express this weight in terms of people per football field, we need to convert the weight to a human scale. Assuming an average adult weight of 70 kg, we divide the weight per hectare (19,928 kg) by 70 kg, yielding approximately 284.68 adults per hectare.
Since we are comparing to a football field, we divide this number by the area of a football field in hectares (0.714 ha) to obtain approximately 398.51 adults per football field.
Considering that it is common to express population density per hectare, we can further assume an average family size or occupancy rate to estimate the number of people per football field. Let's assume an average family size of 4 people, which is a rough estimation. Multiplying 398.51 by 4 gives us approximately 1,594.04 people per football field.
Therefore, the average corn harvest weight of 14.2 Mg/ha can be expressed as approximately 2,842 people per football field.
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Kyle is a salesman. His monthly earnings include a fixed monthly salary and a commission that is a fixed percentage of his total sales for the month. Kyle’s total sales for the month of January were $10,000, and his total earnings for that month were $1,350. Kyle’s total sales for the month of February were $15,000, and his total earnings for that month were $1,575. What is Kyle’s fixed monthly salary in dollars?
Answer:
$900
Step-by-step explanation:
Kyle's commission on an extra $5000 in sales was ...
$1575 -1350 = $225
So, his commission on $10000 in sales would be ...
$225 × 2 = $450
Since $450 of Kyle's first month's sales was commission, his base salary was ...
$1350 -450 = $900 . . . . Kyle's fixed monthly salary
Hurricane Andrew swept through southern Florida causing billions of dollars of damage. Because of the severity of the storm and the type of residential construction used in the semitropical area, there was some concern that the average claim size would be greater than the historical average hurricane claims of $24,000. Several insurance companies collaborated in a data gathering experiment. They randomly selected 84 homes and sent adjusters to settle the claims. In the sample of 84 homes, the average claim was $27,5000 with a population standard deviation of $2400. Is there sufficient evidence at a 0.02 significance level to support the claim that the home damage is greater than the historical average? Assume the population of insurance claims is approximately normally distributec. Compute the value of the test statistic.
The value of the t test is 13.36, we have to conclude that there is sufficient evidence that suggests that insurance adjustment was greater than $2400.
The hypothesis formulationH0: u = 24000
H1: u > 24000
This test is a right tailed testwe have n = 84 homes
bar x = 27500
s = 2400
Next we have to find the test statistic
The formula for this is given as
\(t = \frac{x-u}{s/\sqrt{n} }\)
When we out in the values we would have
\(t = \frac{27500-24000}{2400/\sqrt{84} }\)
This would give us the answeer of the t test as
t test = 13. 3658
We have alpha = 0.02
the degree of freedom = 84 - 1 = 83
we have to find tα/2, df
= ±2.0865
Given that the value of the test statistic is greater than critical value we would have to then reject the null hypothesis.
Hence the conclusion that we can make is that there is sufficient evidence that suggests that insurance adjustment was greater than $2400.
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fill the blank! in addition to premises, warrants, and conclusions, two additional elements of rhetorical argument are .____
In addition to premises, warrants, and conclusions, two additional elements of rhetorical argument are evidence and counterarguments.
The two additional elements of rhetorical argument are evidence and counterarguments.
Evidence refers to the supporting material or proof that is presented to back up the premises and warrants in an argument. This can include statistics, facts, expert testimony, or personal experiences.
Counterarguments are the opposing viewpoints or objections that may arise in response to the argument. By addressing and refuting potential counterarguments, the speaker or writer strengthens their own argument and shows that they have considered multiple perspectives on the issue at hand.
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What is the sur face area?
1 cm
1 cm
1 cm
Answer:
should be 6cm
Step-by-step explanation:
if you are looking at a cube
Answer:
6 cm 2
Step-by-step explanation:
Surface area of a cube then 1 x 1 x 1 x 6 (6 faces )
Determine the three-decimal digit approximation of the number √34.
Using a calculator, it can be found that
\(\sqrt{34}=5.83095189...\)Rounding to three decimal places,
\(\Rightarrow\sqrt{34}\approx5.831\)The rounded answer is 5.831The first three terms of a sequence are given. Round to the nearest thousandth (if
necessary).
10, 17, 24, ...
Find the 33rd term.
Answer:
234
Step-by-step explanation:
The consecutive terms of the sequence have a common difference d
d = 17 - 10 = 24 - 17 = 7
This indicates the sequence is arithmetic with n th term
\(a_{n}\) = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 10 and d = 7 , thus
\(a_{33}\) = 10 + (32 × 7) = 10 + 224 = 234
Write the equation of the line that has an undefined slope and passes through the point (4, 7).
The equation of the line that has an undefined slope and passes through the point (4, 7) is y = 4.
What are lines and their slopes?We know lines have various types of equations, the general type is
Ax + By + c = 0, and equation of a line in slope-intercept form is y = mx + b.
Where slope = m and b = y-intercept.
the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.
We know if a line has an undefined slope it is parallel to the y-axis and passes through the point (4, 7).
As it is parallel to the y-axis x-coordinate point remains the same.
So, The equation of the line must be, y = 4.
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If the cost of an item with VAT is Rs 1,356 and without VAT is Rs 1,200, find the VAT?
Given:
Cost of an item with VAT = Rs 1,356
Cost of that item without VAT = Rs 1,200.
To find:
The VAT.
Solution:
We have,
Cost of an item with VAT = Rs 1,356
Cost of that item without VAT = Rs 1,200.
We know that,
VAT = Cost of an item with VAT - Cost of that item without VAT
= 1356 - 1200
= 156
Therefore, the value of VAT is $156.
Determine if the two triangles are congruent.
Answer:
they are not congruent
Step-by-step explanation:
look at all the sides to see if they are all the same
Answer: ASA
Step-by-step explanation:
1: Congruent with an angle of the other triangle. (Check the number of angle markings.) [A]
2: Congruent with a side of the other triangle. [S]
3: Congruent with an angle of the other triangle. (Check the number of angle markings.) [A]
You can match what you have with your answer choices.
A: Angle
S: Side
what is 2/3 divided by -1 1/3
if you have 240 meters of fencing and want to enclose a rectangular area up against a long, straight wall, what is the largest area you can enclose?
The largest area that can be enclosed by a fence of 240 m and a wall is 7200m²
It is given that the rectangular area will be fenced up against a long rectangular wall. Therefore, the fencing will be done on just three sides.
Let one side be x
Then the side opposite to it must be x cm as well
The sum of the three sides should be equal to 240 m
Hence the third side must be 240 - 2x m
Therefore the area of the region fenced must be
A = x(240 - 2x)
or, A = 240x - 2x²
Now we need to maximize the above equation
Taking the first derivative zero we get
A' = 0
or, 240 - 4x = 0
or, 60 - x = 0
or, x = 60
Now we will test whether the above output is maximum or not. The second derivative of A is
A'' = -4
Since A'' is a constant function,
Now, A''(60) = -4
Therefore, the maximum side will have lengths of 60 m and 120 m.
Hence the largest area that can be enclosed with the fence is
60 X 120 m²
= 7200 m²
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a) Using a 2-year moving average, the forecast for year 6= miles (round your response to the nearest whole number). b) If a 2-year moving average is used to make the forecast, the MAD based on this = miles (round your response to one decimal place). (Hint: You will have only 3 years of matched data.) c) The forecast for year 6 using a weighted 2-year moving average with weights of 0.40 and 0.60 (the weight of 0.60 is for the most recent period) =3,740 miles (round your response to the nearest whole number). The MAD for the forecast developed using a weighted 2-year moving average with weights of 0.40 and 0.60= miles (round your response to one decimal place). (Hint: You will have only 3 years of matched data.) d) Using exponential smoothing with α=0.20 and the forecast for year 1 being 3,100 , the forecast for year 6=3,468 miles (round your response to the nearest whole number).
a) The forecast is approximately miles. b) the Mean Absolute Deviation (MAD) based on the forecast is approximately miles. c) The forecast for year 6 is approximately miles. d) the last forecast is 3,468 miles.
a) To calculate the forecast for year 6 using a 2-year moving average, we take the average of the mileage for years 5 and 4. This provides us with the forecasted value for year 6.
b) The Mean Absolute Deviation (MAD) for the 2-year moving average forecast is calculated by taking the absolute difference between the actual mileage for year 6 and the forecasted value and then finding the average of these differences.
c) When using a weighted 2-year moving average, we assign weights to the most recent and previous periods. The forecast for year 6 is calculated by multiplying the mileage for year 5 by 0.40 and the mileage for year 4 by 0.60, and summing these weighted values.
The MAD for the weighted 2-year moving average forecast is calculated in the same way as in part b, by taking the absolute difference between the actual mileage for year 6 and the weighted forecasted value and finding the average of these differences.
d) Exponential smoothing involves assigning a weight (α) to the most recent forecasted value and adjusting it with the previous actual value. The forecast for year 6 is calculated by adding α times the difference between the actual mileage for year 5 and the previous forecasted value, to the previous forecasted value.
In this case, with α=0.20 and a forecast of 3,100 miles for year 1, we perform this exponential smoothing calculation iteratively for each year until we reach year 6, resulting in the forecasted value of approximately 3,468 miles.
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Please help I don’t understand graphs !
Answer:
Vertical Asymptote at: x = - 1.5
Slanted Asymptote at: y = -x 9/2
Step-by-step explanation:
See image (I HAVE NO IDEA IF YOUR SUPPOSED TO GIVE THE SLANTED ASYMPTOTE. THE PROBLEM ONLY SAYS VERTICAL AND HORIZONTAL ONLY, SO I GUESS ONLY DRAW THE GREEN LINE, NOT THE PURPLE ONE!)
So only draw the x = - 1.5 line that is green!
Plot the image of point C under a reflection across line
When the image of point C is reflected across the line, then it's written as C'.
what is the area, in square units, of a triangle that has sides of $4,3$ and $3$ units? express your answer in simplest radical form.
Therefore, the area of the triangle is 2√5 square units, expressed in simplest radical form.
To find the area of a triangle, we can use Heron's formula, which states that the area (A) of a triangle with side lengths a, b, and c is given by:
A = √(s(s - a)(s - b)(s - c))
where s is the semi-perimeter of the triangle, calculated as:
s = (a + b + c) / 2
Given the side lengths of the triangle as 4, 3, and 3 units, we can calculate the semi-perimeter:
s = (4 + 3 + 3) / 2
= 5
Now, substituting the values into Heron's formula, we have:
A = √(5(5 - 4)(5 - 3)(5 - 3))
= √(5 * 1 * 2 * 2)
= √(20)
= 2√5
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In the addition problem below, the digits B and C represent a number different from any of the other numbers shown (that is, not 1, 4, 5, 6, or 9. B5+C9=164
B5 + C9 = 164
Split the numbers.
B0 +C0 +14 = 164.
B0 + C0 = 150
B + C = 15
B cannot be 1, 2, 3, 4, or 5 because that forces C to be a two digit number and C only represents 1 digit.
B cannot be 6 or 9 because they are present.
B can only be 7 or 8. C can also be 7 or 8.
Therefore, B = 7 and C = 8, OR B = 8 and C = 7.
Write an equation to represent the function in the table shown below.
Answer:
y=2x
Step-by-step explanation: