Please someone help me with this math problem

Answer:

8397 divided by 27 in partial quotients is 311

Step-by-step explanation:

Answer:

4.3

Step-by-step explanation:

Answer:

y = 13/13

helpful??

18. An infant weighs 11 pounds which is equivalent to 4.98 kg. Using the 100/50/20 Rule, the required amount of fluid per day for an infant between 11-20 kg is 50 ml/kg/day. So, the required amount of fluid per day in ml is 4.98 kg x 50 ml/kg/day = 249 ml/day.

19. A child weighs 31lbs and 8 ozs which is equivalent to 14.21 kg. Using the 100/50/24 Rule, the required amount of fluid per day for a child over 20 kg is 20 ml/kg/day. So, the required amount of fluid per day in ml is 14.21 kg x 20 ml/kg/day = 284.2 ml/day.

If no oral fluids are consumed, the hourly IV flow rate to maintain proper hydration would be: 284.2 ml/day / 24 hours/day = 11.8 ml/hour.

The question is about fluid requirements for infants and children, and it is using the 100/50/20 Rule for Daily Fluid Requirements (DFR) to calculate the required amount of fluid per day for different weight ranges. The 100/50/20 Rule is a guideline used to determine the appropriate amount of fluid that infants and children should receive on a daily basis based on their weight. The rule states that for infants and children up to 10 kg, the recommended fluid intake is 100 ml/kg/day, for those between 11-20 kg it is 50 ml/kg/day, and for those over 20 kg it is 20 ml/kg/day.

The question also asking about the hourly IV flow rate to maintain proper hydration if no oral fluids are consumed.

This subject is part of pediatrics, more specifically in the field of fluid and electrolyte balance and management.

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Answer:

B. 3 - 5.5 + 1.5

Step-by-step explanation:

Because you start at 0 and then move positive 3 on the number line negative 5.5 and then positive 1.5 again.

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The total number of red marbles in the vase are 10.

A ratio is described as a comparison between two amounts with the same unit to determine the amount of 1 quantity is contained in the other. Ratios are divided into two sorts.

The first is a part-to-part ratio, and the second is a part-to-whole ratio. The part-to-part ratio expresses the relationship between 2 separate entities or groupings.

Now, according to the question;

Let 'x' be the red marbles in the vase.

Let 'y' be the orange marbles in the vase.

The total number of marbles in the vase are 60

x  + y = 60 (equation 1)

The ratio of red marbles to orange ones is 1:5.

Thus, x/y = 1/5

cross multiplying;

5x = y

or y = 5x

substitute the value of y in equation 1;

x  + y = 60 (equation 1)

x  + 5x = 60

6x = 60

x = 10  (red marbles)

Thus, the number of red marbles in the vase are 10.

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Answer:5^15

Step-by-step explanation: I am Smart :>

Answer:

\(5^{15}\)

Step-by-step explanation:

\(\frac{(5^3)^9}{5^{12}} \\\\\frac{5^{27}}{5^{12}} \\\\5^{15}\)

3 x 9 = 27

27 - 12 = 15

Answer:

the answer is A

Step-by-step explanation:

\((\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1})\hspace{10em} \stackrel{slope}{m} ~=~ - 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{- 4}(x-\stackrel{x_1}{(-1)}) \implies y +1= -4 (x +1) \\\\\\ y+1=-4x-4\implies {\LARGE \begin{array}{llll} y=-4x-5 \end{array}}\)

Thus, we need a sample size of at least 22 to obtain a 90 percent confidence interval for the mean protein content of meat with an estimate within 2 pounds of the true mean value.

To obtain a 90 percent confidence interval for the mean protein content of meat with an estimate within 2 pounds of the true mean value, we need to calculate the required sample size. The formula for the required sample size is:

n = (Zα/2 * σ / E)^2

where n is the required sample size, Zα/2 is the z-score for the desired confidence level (in this case 90%), σ is the standard deviation of the population (in this case 7 pounds, the square root of the variance), and E is the margin of error (in this case 2 pounds).

Plugging in the values, we get:

n = (1.645 * 7 / 2)^2
n = 21.16

Therefore, we need a sample size of at least 22 to obtain a 90 percent confidence interval for the mean protein content of meat with an estimate within 2 pounds of the true mean value. It is important to note that this assumes that the sample is drawn randomly and is representative of the population.

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To determine the spot price of one Bitcoin, we can use the concept of no-arbitrage pricing. In this case, the futures contract price can be considered as the present value of the expected future spot price, taking into account the risk-free rate.

The futures contract price of $60810 per Bitcoin represents the expected future spot price one year from October 23, 2021. We can calculate the present value of this future price by discounting it at the risk-free rate of 1%. Using the formula for present value, we have:

Present Value = Future Value / (1 + Risk-free rate)

Present Value = $60810 / (1 + 0.01) = $60208.91

Therefore, the spot price of one Bitcoin closest to the given information is approximately $60208, which corresponds to option A.

Insummary, based on the information provided, the spot price of one Bitcoin is closest to $60208 (option A).

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The Fourier transform of the signal x(t)= e^|a|t, a>0 is X(ω) = 2πδ(ω - ja) + 2πδ(ω + ja).

To find the Fourier transform of the signal x(t) = e^|a|t, where a > 0, we can use the properties of the Fourier transform and the formula for the Fourier transform of the exponential function.

The Fourier transform of the signal x(t) is denoted as X(ω), where ω represents the angular frequency.

Using the formula for the Fourier transform of the exponential function, we have:

X(ω) = 2πδ(ω - j) + 2πδ(ω + j),

where δ(ω) represents the Dirac delta function.

In this case, since a > 0, we have j = ja.

Therefore, the Fourier transform of x(t) = e^|a|t is:

X(ω) = 2πδ(ω - ja) + 2πδ(ω + ja).

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ES is 8√2 units from the given graph.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

The given two points from the graph are S(4, 4) and E(-4, -4)

We need to find ES which means the distance between two points in units.

The length along a line or line segment between two points on the line or line segment.

Distance=√(x₂-x₁)²+(y₂-y₁)²

√(-4-4)²+(-4-4)²

√(-8)²+(-8)²

√64+64

√64×2

8√2 units.

Hence, ES is 8√2 units from the given graph.

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When two tables have a one-to-many relationship, you typically need to add a foreign key to the table on the "many" side to link the records to the corresponding record in the "one" table.

In a one-to-many relationship, the table on the "one" side is usually the primary key table, and the table on the "many" side is usually the foreign key table. The foreign key is used to link the records in the "many" table to the corresponding record in the "one" table. This is done by adding a column to the "many" table that contains the primary key value from the "one" table.

When designing a database, it is important to establish relationships between tables to ensure data integrity and avoid redundant data. In a one-to-many relationship, one record in the primary key table can be associated with many records in the foreign key table. To establish a one-to-many relationship, you need to create a primary key in the "one" table and a foreign key in the "many" table. The foreign key is a column that contains the primary key value from the "one" table. For example, if you have a "customers" table and an "orders" table, the "customers" table would be the primary key table and the "orders" table would be the foreign key table. Each record in the "orders" table would have a foreign key column that contains the customer ID from the "customers" table.

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Answer:

rfgcc ft v crytrcvrcvhtfvyrfftv ffg

Step-by-step explanation:

tgfgghcg gn v v

The symbols d and sd represent:

The differences in the mean of the paired data entries in the dependent samples.

What is the standard deviation?

A measure of a set of values' variance or dispersion is called the standard deviation.

Here,

d: the difference between paired data in the dependent samples.

sd:  standard deviation.

The dependent samples' dependent samples' standard deviation for the variance between the means of the paired data items.

Hence, the differences in the mean of the paired data entries in the dependent samples.

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Answer:

Option 3 is the correct answer

Answer:

Slope of line A is 1/3

Equation of Line B is y = 2x + 4

Answer:

Subtracting 7

Step-by-step explanation:

Given:

Clara is stacking cups; she put 45 plastic cups in the first stack, 38 plastic cups in the second stack, 31 plastic cups in the third stack, and 24 plastic cups in the fourth stack.

To Find:

What kind of sequence is this?

Solve:

Let's make a table:

[1 stack]  45

[2 stack] 38

[3 stack] 31

[4 stack] 24

Now all we have to do is subtract to see what each is:

45 - 38 = 7

38 - 31 = 7

31 - 24 = 7

Thus,

[1 stack]  45 ⇒ 7

[2 stack] 38 ⇒ 7

[3 stack] 31 ⇒ 7

[4 stack] 24 ⇒ 7

Hence, each stack is going down by 7.

Kavinsky

Answer:

31

Step-by-step explanation:

2x+5+3x-9+x-2=180

or, 6x-6=180

or, 6x=180+6

or, x=186/6

or, x=31

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Answer:

B. 183

Step-by-step explanation:

m<L = (1/2)[m(arc)KN - m(arc)KM)]

35 = (1/2)(177x - 107x)

70 = 70x

x = 1

m(arc)KN = 177x = 177

m(arc)NMK = 360 - m(arc)KN

m(arc)MNK = 360 - 177

m(arc)MNK = 183

Given:

The expression is,

Simpify the expression,

Answer:

Answer:

11 quarters

Step-by-step explanation:

First, I subtract : 3.45 - .70 = 2.75

Then, divide : 2.75 by 25 ( a quarter ) = .11

Check : 11 x 25 = 2.75 -------------> 2.75 + .70 = 3.45

Hope this helps :)

Answer:

if I got quarters and nickels saved in my piggy bank and $3.45 is in my bank then I know I have 9 quarters 29 nickels

Step-by-step explanation:

The location of all the relative and absolute extrema is (0, 0) (local minimum); (1, 1) (local maximum); (3, 3) (absolute maximum)

To find the relative and absolute extrema of the function f(x) = 2x - x^2 on the domain (0,3), we first take the derivative:

f'(x) = 2 - 2x

Setting this equal to zero, we find the critical point:

2 - 2x = 0
x = 1

To determine the nature of the critical point, we need to examine the second derivative:

f''(x) = -2

Since the second derivative is negative at x = 1, this critical point is a local maximum. To find the absolute extrema, we also need to examine the endpoints of the domain, x = 0 and x = 3:

f(0) = 0
f(3) = 3

So the function has an absolute maximum at x = 3 and an absolute minimum at x = 0. Therefore, the location of all the relative and absolute extrema, from smallest to largest x, is:

(0, 0) (local minimum)
(1, 1) (local maximum)
(3, 3) (absolute maximum)

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The diameter of cylinder is 2.28 cm and area of wrapper is 60.56π cm².

A cylinder is a three-dimensional solid figure which has two identical circular bases joined by a curved surface at a particular distance from the center which is the height of the cylinder.

Here, Given area of cylinder = 25π cm²

          Height of cylinder = 11 cm.

Now, Area of Cylinder = 2πrh

                  25π = 2πr X 11

                   25 = 22r

                    r = 25 / 22

                  r = 1.14 cm

Then, diameter = 2r = 2 X 1.14 = 2.28 cm

Now area of wrapper = total surface area = 2πr(r + h)

                                    = 2π X 2.28 (2.28 + 11)

                                   = 4.56π X 13.28

                                   = 60.56π cm²

Thus, the diameter of cylinder is 2.28 cm and area of wrapper is 60.56π cm².

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Answer:

(3x - 4) (3x + 4)

Step-by-step explanation:

Area of the square paper = 9x^2 square centimeters

Area of the square corner = 16 square centimeters

The area of the square corner is removed from area of the square paper.

That is,

9x^2 - 16

Factorise by finding the square root of each term

9x^2

Square root of 9x^2 = 3x

Check:

3x * 3x = 9x^2

Square root of 16 = + or - 4

9x^2 - 16 = (3x - 4) (3x + 4)

Check:

(3x - 4) (3x + 4)

9x^2 + 12x - 12x - 16

= 9x^2 - 16

Answer:

hey guys lol its c on edg.

Step-by-step explanation:

Tracing the surface given by 2x² − 8y²z² = 8 involves fixing one variable at a time and plotting the resulting curves in space.

To sketch the surface, we will use the method of traces, which involves fixing one variable and tracing the resulting curve in space. To do this, we will hold z constant and plot the curve formed by the equation 2x² − 8y²z² = 8 in the x-y plane. We can rewrite the equation as follows:

2x²/8 = y²z²/1

x²/4 = y²z²/1

y²z² = 4x²

y² = 4x²/z²

This equation represents a family of parabolas that are symmetric about the y-axis, with their vertex at the origin (0,0).

To complete the sketch, we will also hold y constant and plot the curve formed by the equation 2x² − 8y²z² = 8 in the x-z plane. We can rewrite the equation as follows:

2x²/8 = y²z²/8y²

x²/4 = z²

z = ±x/2

This equation represents a pair of intersecting planes that pass through the origin. The planes are perpendicular to each other and intersect at a right angle along the x-axis. As we change the value of y, the planes stay fixed in space and do not change shape.

By combining the information from the two sets of curves, we can sketch the surface by imagining a grid of parabolas that intersect with a pair of perpendicular planes. The resulting shape is a hyperboloid of one sheet, which is a smooth surface that resembles a saddle or a potato chip.

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To find \(\( \frac{{dy}}{{dt}} \)\) when \(\( x = 1 \)\) and \(\( y = 0 \),\)  we can differentiate the equation \(\( \frac{{x+y}}{{x-y}} = x^2 + y^2 \)\) implicitly with respect to \(\( t \).\)

Taking the derivative of both sides with respect to \(\( t \),\) we have:

\(\[ \frac{{d}}{{dt}} \left( \frac{{x+y}}{{x-y}} \right) = \frac{{d}}{{dt}} (x^2 + y^2) \]\)

Using the quotient rule on the left side and the chain rule on the right side, we get:

\(\[ \frac{{(x-y) \frac{{d}}{{dt}}(x+y) - (x+y) \frac{{d}}{{dt}}(x-y)}}{{(x-y)^2}} = 2x \frac{{dx}}{{dt}} + 2y \frac{{dy}}{{dt}} \]\)

Substituting \(\( x = 1 \), \( y = 0 \), and \( \frac{{dx}}{{dt}} = 12 \),\) we have:

\(\[ \frac{{(1-0) \frac{{d}}{{dt}}(1+0) - (1+0) \frac{{d}}{{dt}}(1-0)}}{{(1-0)^2}} = 2(1)(12) + 2(0) \frac{{dy}}{{dt}} \]\)

Simplifying the equation gives:

\(\[ \frac{{\frac{{d}}{{dt}}(1) - \frac{{d}}{{dt}}(1)}}{{1}} = 24 \]\)

\(\[ 0 = 24 \]\)

Therefore, we cannot determine the value of \(\( \frac{{dy}}{{dt}} \)\) when \(\( x = 1 \) and \( y = 0 \)\) based on the given information.

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Answer: 12

Step-by-step explanation:

Convert both mixed numbers to improper fractions:

7 1/12= 85/12

1 3/5= 8/5

Multiply:

84 x 8 = 680

12 x 5 = 60

As a fraction:

680/60

Simplified:

11 1/3 ft. of paper needed

Answer:

£29.37

Step-by-step explanation:

Type in the question- like type it. Not a screenshot, type in part of the question into the Brainly search bar and you'll find it.

Here, x = 6 is a vertical asymptote of f, so the function approaches infinity as x approaches 6 from both sides.

Let's start by integrating f'(x) to get f(x). We have:

f'(x) = 16(x+2)(6-x)³ - 32(x+6)

Integrating both sides with respect to x:

f(x) = ∫[16(x+2)(6-x)³ - 32(x+6)] dx

Simplifying the integral, we get:

f(x) = -2(x+2)²(6-x)⁴ + 16(x+6) + C

where C is the constant of integration.

Next, we can find the critical points of f(x) by setting f'(x) = 0:

f'(x) = 16(x+2)(6-x)³ - 32(x+6) = 0

Solving for x, we get x = -2 and x = 6 as critical points.

Now, we can use the second derivative f''(x) to determine the concavity of the function. We have:

f''(x) = (6x-x)⁴ = x⁴

Since the second derivative is always positive for x > 0, the function is concave up on the interval (6, ∞).

Similarly, since the second derivative is always negative for x < 0, the function is concave down on the interval (-∞, -2).

At x = -2 and x = 6, the function has an inflection point.

Finally, we know that x = 6 is a vertical asymptote of f, so the function approaches infinity as x approaches 6 from both sides.

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