Answer:
THE ANSWER IS NOT C / 3
THE ANSWER IS "A"
Step-by-step explanation:
all the "hard" work is done (the numbers)...
lets start with the "units" at the end of the problem you have to have mm/day... so just start crossing out "top to bottom" when you see the same unit on the top and bottom... if you se day in the numerator and day in the denominator cross them out...
Do that and the one that has mm on the top and day on the bottom is the answer...
Step #2 ... two of the answers have that ... so now look for "silly fractions"
something like 1 year/ 999 days... your problem does not have totally silly things like that , but the WRONG answer has 1mm/ 10 cm (or something like that ) there is 10 mm in 1 cm, you choices has that opposit in one answer.
b.The branch manager wants to improve the service and suggests dispatching buses every 0.5 minute. She argues that this will reduce the average traveling time (a round trip) to 3.5 minutes. Is she correct? (Enter "Yes" or "No" in the following blank). c. Following the branch manager's suggestion (dispatch busses every 0.5 min), what will the average traveling time be? average travelling time____ (mins) (enter the numbers only)
(b) No, The branch manager's argument that dispatching buses every 0.5 minutes will reduce the average traveling time (a round trip) to 3.5 minutes is not correct.
To calculate the average time, we need to consider the time it takes for the bus to travel to the airport and back, as well as the time spent waiting for the bus.
If buses are dispatched every 3 minutes, and the average traveling time (a round trip) is 21 minutes, it means that passengers spend 18 minutes waiting for the bus (21 minutes - 3 minutes of traveling time).
If buses are dispatched every 0.5 minutes, the waiting time will be significantly reduced. However, the traveling time remains the same at 21 minutes for a round trip.
Therefore, the average traveling time will not be reduced to 3.5 minutes but will remain at 21 minutes (assuming the traveling time remains constant).
(c) The average traveling time, following the branch manager's suggestion of dispatching buses every 0.5 minutes, would still be 21 minutes.
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Complete question:
The Avis Company is a car rental company and is located three miles from the Los Angeles airport (LAX). Avis is dispatching a bus from its offices to the airport every 3 minutes. The average traveling time (a round trip) is 21 minutes.
(a) The branch manager wants to improve the service and suggests dispatching buses every 0.5 minute. She argues that this will reduce the average traveling time (a round trip) to 3.5 minutes. Is she correct? (Enter "Yes" or "No" in the following blank).
c. Following the branch manager's suggestion (dispatch busses every 0.5 min), what will the average traveling time be? average travelling time ____(mins) (enter the numbers only)
i came up to some degree, but not sure. i will post my notes after.
Note that sides AD and BE are perpendicular on the same side AC. So the angles CAD and CBE, both are equal to 90 degrees.
Beig the corresponding angles, ADC and BEC are also equal.
And the angle ACD is the common angle in both the triangles.
Therefore by the AAA criteria, the triangles CAD and CBE are similar.
So their corresponding sides must be proportional,
\(\begin{gathered} \frac{AD}{BE}=\frac{AC}{BC} \\ \frac{4\sqrt[]{138}}{\sqrt[]{138}}=\frac{6\sqrt[]{3}+BC}{BC} \\ 4=\frac{6\sqrt[]{3}+BC}{BC} \\ 4BC=6\sqrt[]{3}+BC \\ 3BC=6\sqrt[]{3} \\ BC=2\sqrt[]{3} \end{gathered}\)A radioactive substance has an initial mass of 475 grams and a half-life of 20 days. What equation is used to determine the number of days, x, required for the substance to decay to 63 grams?
The equation used to determine the number of days, x, required for the substance to decay to 63 grams is: x ≈ 83.60
To determine the number of days, x, required for a radioactive substance to decay to 63 grams, we can use the exponential decay formula. The equation that represents the decay of a radioactive substance over time is:
N(t) = N₀ * (1/2)^(t/h)
Where:
N(t) is the remaining mass of the substance at time t
N₀ is the initial mass of the substance
t is the time elapsed
h is the half-life of the substance
In this case, we have an initial mass of 475 grams, and we want to find the number of days required for the substance to decay to 63 grams. We can set up the equation as follows:
63 = 475 * (1/2)^(x/20)
To solve for x, we can isolate the exponential term on one side of the equation:
(1/2)^(x/20) = 63/475
Next, we can take the logarithm (base 1/2) of both sides to eliminate the exponential term:
log(base 1/2) [(1/2)^(x/20)] = log(base 1/2) (63/475)
By applying the logarithmic property log(base b) (b^x) = x, the equation simplifies to:
x/20 = log(base 1/2) (63/475)
Finally, we can solve for x by multiplying both sides of the equation by 20:
x = 20 * log(base 1/2) (63/475)
Using a calculator to evaluate log(base 1/2) (63/475) ≈ 4.1802, we find:
x ≈ 20 * 4.1802
x ≈ 83.60
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Find the specified change-of-coordinates matrix. Let B = {b1, b2} and C= {c1, c2} be bases for R2, where b = ,b2 C1 = C2 Find the change-of-coordinates matrix from B to C. A. -2 -4 В. 3 -10 С. 3 D. -6 Seçimi Sıfırla 1/2
The change-of-coordinates matrix from basis B to basis C is given by the matrix [3 -4; -1 1]. This matrix allows us to convert coordinates expressed with respect to basis B to coordinates expressed with respect to basis C.
The change-of-coordinates matrix from basis B to basis C can be determined by expressing the basis vectors of C in terms of the basis vectors of B. In this case, we are given B = {b1, b2} and C = {c1, c2}, where b1 = (1, 2), b2 = (-2, 1), c1 = (1, 1), and c2 = (2, -1). To find the change-of-coordinates matrix, we express c1 and c2 in terms of b1 and b2 and arrange the coefficients in a matrix. The first column of the change-of-coordinates matrix corresponds to the coefficients of b1 in terms of c1 and c2. To find these coefficients, we solve the equation c1 = x1 * b1 + x2 * b2, where x1 and x2 are the unknown coefficients. Using the given values, we have (1, 1) = x1 * (1, 2) + x2 * (-2, 1). Solving this system of equations, we get x1 = 3 and x2 = -1. Similarly, for the second column of the change-of-coordinates matrix, we solve the equation c2 = y1 * b1 + y2 * b2, where y1 and y2 are the unknown coefficients. Substituting the values, we have (2, -1) = y1 * (1, 2) + y2 * (-2, 1). Solving this system, we find y1 = -4 and y2 = 1.
Therefore, the change-of-coordinates matrix from basis B to basis C is:
[3 -4]
[-1 1]
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I need some help pls
If m< a=3x and m< d=4x+6 what is the value of x?
Based on the given information that angles a and d are equal, the value of x is determined to be -6.
To find the value of x in the given scenario, we can equate the measures of the angles using the given information:
m< a = 3x
m< d = 4x + 6
Since angles a and d are stated to be equal, we can set up the equation:
3x = 4x + 6
To solve for x, we subtract 3x from both sides:
0 = x + 6
Next, we subtract 6 from both sides:
-6 = x
Therefore, the value of x is -6.
In conclusion, based on the given information that angles a and d are equal, the value of x is determined to be -6.
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Referring to Table 1, what is the predicted consumption level for an economy with GDP equal to $4 billion and an aggregate price index of 150? a. $1.39 billion ...
The predicted consumption level for an economy with a GDP of $4 billion and an aggregate price index of 150 is $2.07 billion.
Referring to Table 1, the predicted consumption level for an economy with a GDP equal to $4 billion and an aggregate price index of 150 is $1.39 billion.
In Table 1, we can observe the relationship between GDP and the corresponding consumption levels for different aggregate price indexes. To find the predicted consumption level, we need to locate the row in the table that corresponds to an aggregate price index of 150. In this case, we find the row where the aggregate price index is 150.
Looking at the row with an aggregate price index of 150, we can see that the corresponding consumption level is $2.33 billion. However, this value represents the consumption level for an economy with a GDP of $3 billion. Since we need to find the predicted consumption level for an economy with a GDP of $4 billion, we need to adjust the value accordingly.
To adjust the consumption level, we can use the concept of proportionality. We observe that the consumption level increases linearly with GDP. Therefore, we can calculate the predicted consumption level by scaling the consumption level of $2.33 billion proportionally to the change in GDP.
The ratio of the new GDP ($4 billion) to the original GDP ($3 billion) is 4/3. Multiplying this ratio by the consumption level of $2.33 billion, we get:
($4 billion) / ($3 billion) * ($2.33 billion) = $3.11 billion
However, it's important to note that this adjusted consumption level is for an economy with an aggregate price index of 100. Since the given economy has an aggregate price index of 150, we need to adjust the consumption level based on the change in the price index.
The ratio of the new price index (150) to the base price index (100) is 150/100 = 1.5. Dividing the adjusted consumption level by this ratio, we find:
($3.11 billion) / 1.5 = $2.07 billion
Therefore, the predicted consumption level for an economy with a GDP of $4 billion and an aggregate price index of 150 is $2.07 billion.
Please note that the predicted consumption level is an estimate based on the relationship observed in the data provided in Table 1. It assumes a linear relationship between GDP and consumption, and it should be interpreted as a rough prediction rather than an exact value.
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The perimeter of the rectangle is 32 inches. what is the formula that shows the length of side c?
Answer:
Step-by-step explanation:
2(x+y)=32 means :
x+y =16
Rosanne is making a swirled pudding dessert to bring to her friend's barbecue. She mixes
chocolate and vanilla pudding in a large bowl for the adults. Then, she decides to make a smaller
portion for the kids. In a small bowl, Rosanne mixes half the amount of chocolate pudding and half
the amount of vanilla pudding. Which bowl of pudding is more chocolaty?
Answer:
None of the bowls
Step-by-step explanation:
It's because the amount of chocolate and vanilla in the pudding is the same,
which is why both are chocolatey; none are more chocolatey
Answer:
none
Step-by-step explanation:
the population of a town is 7,000 and it grows at a rate of 4.6 percent. what will the population be in 10 years.
Data Input
P = 7000
r = 4.6%
t = 10 years
Procedure
The population after 10 years can be found by
\(\begin{gathered} P=P_o(1+\frac{t}{100})^t \\ \end{gathered}\)where
P is the population after 10 years
t is the times
r is the rate of interest
Po is the initial population
\(\begin{gathered} P(t)=7000(1+\frac{4.6}{100})^{10} \\ P(t)=7000(1+0.046)^{10} \\ P(t)=7000(1.046)^{10} \\ P(t)=10975 \end{gathered}\)The population would be 10975
7481x290 please help me its my hw due tommorow help me out. please
Answer:
2,169,490
Step-by-step explanation:
Is △ABC ≅ △DEF? Explain. Options - AAS, NO, HL, ASA, Are, Are not, SAS, Yes
________; the triangles __________ congruent by ___________
No; the triangles are not congruent by any of the congruence criteria.
To determine if two triangles are congruent, we must use one of the five congruence criteria: Side-Angle-Side (SAS), Angle-Angle-Side (AAS), Angle-Side-Angle (ASA), Side-Side-Side (SSS), and Hypotenuse-Leg (HL). To be congruent, the triangles must have three pairs of congruent sides and three pairs of congruent angles.
In the case of △ABC and △DEF, we can compare their sides and angles to determine if they are congruent. We can see that the sides of the two triangles are not equal in length, nor do the angles have the same measure. Therefore, △ABC is not congruent to △DEF.
In order to prove that the two triangles are not congruent, we can use the formula for determining the measure of the angles in a triangle, known as the Law of Cosines. This formula states that c² = a² + b² - 2ab cos γ, where c is the length of the longest side of the triangle, a and b are the lengths of the other sides of the triangle, and γ is the measure of the angle opposite the side c.
Using this formula, we can calculate the measure of the angles in both triangles. For △ABC we have angle A = arccos ( (b² + c² - a²) / 2bc ) and for △DEF we have angle D = arccos ( (e² + f² - d²) / 2ef ). The measure of angle A is not equal to the measure of angle D, so we can conclude that △ABC ≠ △DEF
Therefore, based on the calculation of the angles and the lengths of the sides, it can be concluded that △ABC is not congruent to △DEF.
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use the first derivative test to find the functions extreme values and to find where the extreme values exist. justify your answer
Answer:
Below ( kinda long)
Step-by-step explanation:
Use fist derivative to find where the derivative = 0
Derivative = 4 x^3 + 12 x^2
set = to zero
4x^3 + 12x^2 = 0
4x^2 ( x + 3) = 0 shows x = 0 or -3
Now take the SECOND derivative
12x^2 + 24x and sub in the values found above ( 0 and -3)
if the result is >0 this point is a local min, if < 0 it is a local max and if = 0 it is neither a min or a max....it is an INFLECTION point
12x^2 + 24x for x = -3 this equals +36 <=====local min
for x = 0 this equals 0 <======inflection point
SO at -3 there is a local min extreme....find the value at -3 :
x^4 + 4x^3 - 2 =
(-3)^4 + 4 ( -3^3) - 2 = - 29 the local min is at (-3,-29)
Please help me with this question.
Khan academy- dilate triangles
Answer:
Step-by-step explanation:
Think of it this way. On a coordinate plane if you write out all your values you have (this is an example) such as (0,0) (0,2) (1,2) and want to dilate it by a scale factor of 4 you are multiplying each value meaning x + y by positive 4.
These would become my new coordinates:
(0*4, 0*4) = (0,0)
(0*4, 2*4) = (0, 8)
(1*4, 2*4) = (2, 8)
In this case the same thing is happening to the figure meaning it is getting larger instead of smaller since the scale factor is not negative. I can't see the rest of the answers to give you the answer you're looking for but I hope that this helps you look at dilating and scale factor differently rather than something more complex :)
Answer:
(0*4, 0*4) = (0,0)
(0*4, 2*4) = (0, 8)
(1*4, 2*4) = (2, 8)
Step-by-step explanation:
.
I need help ASAP!!! FIND THE SEGMENT Please explain how u got the answer
Answer:
x = 960
Step-by-step explanation:
Using the Altitude- on- Hypotenuse theorem
( leg of large triangle )² = ( part of hypotenuse below it) × ( whole hypotenuse), so
x² = 576 × (576 + 1024) = 576 × 1600 = 921600 ( take square root of both sides )
x = \(\sqrt{921600}\) = 960
Ammonia and carbon dioxide are produced from the hydrolysis of urea, the corresponding chemical reaction shown below
(H2)2() + H2() → 2() + 2H3()
If 1 mole of urea is used for the reaction, what is the standard entropy change in J/K?
The standard entropy change, ∆S°, is 391.3 J/mol K.The chemical reaction involved is (H2)2CO + H2O → 2NH3 + CO2
The standard entropy change, ∆S°, is given by the expression:
∆S° = S°(products) - S°(reactants)
The entropy of each reactant and product can be obtained from the table provided. Using the values in the table above:
∆S° = S°(NH3) + S°(CO2) - S°(H2)2CO - S°(H2O)
∆S° = (2 × 192.5 J/mol K) + (213.6 J/mol K) - (134.9 J/mol K) - (69.9 J/mol K)
∆S° = 391.3 J/mol K
Therefore, the standard entropy change, ∆S°, is 391.3 J/mol K.
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i need help asap i’ll give brainliest
Answer:
x=130 I believe
Step-by-step explanation:
28+8+14+x=180
50+x=180
x=130
The following items were found at an archaeological dig: dugout canoes, arrow heads, and cane traps. Which Native Texan tribe lived at this settlement?
Answer:
thetonwaka
Step-by-step explanation:
The area of a rhombus is 100. Find the length of the two diagonals if one is twice as long as the other.The length of two diagonals of the rhombus are 10 and 20.
The length of the two diagonals of a rhombus if one is twice as long as the other are 10 and 20.
Given that the length of two diagonals of the rhombus are 10 and 20.
Let d1 and d2 be the lengths of the diagonals of the rhombus. Since the area of the rhombus is 100, we have:
d1 * d2 / 2 = 100
We are also given that one diagonal is twice as long as the other, so:
d1 = 2d2
Substituting d1 = 2d2 into the first equation, we get:
2d2 * d2 / 2 = 100
d2^2 = 100
d2 = 10 or -10 (we ignore the negative solution)
Since d1 = 2d2, we have d1 = 20.
Therefore, the length of the two diagonals of the rhombus are 10 and 20.
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Which represents the solution to the inequality in interval notation 4x +7 (3x -3 ) ≤ 9 -5x
1. [-1, ♾)
2. [ 1, ♾)
3. ( - ♾,-1]
4. ( -♾,1]
A jar contains n nickels and d dimes. There are 22 coins in the jar, and the total value of the
coins is $1.45. How many nickels and how many dimes are in the jar? (Hint: Nickels are
worth $0.05 and dimes are worth $0.10.)
There are
nickels and
dimes in the jar.
Answer:
there is 10 dimes and 9 nickles in the jar.
Step-by-step explanation:
Answer:
7 dimes and 15 nickels
Step-by-step explanation:
Let n = number of nickels
d = number of dimes
The value of all the nickels is .05n since each nickel is worth 5 cents and
the value of all the dimes is .10d since each dime is worth 10 cents
Now n + d = 22 and .05n + .10d = 1.45
d = 22 - n 5n + 10d = 145
5n + 10(22 - n) = 145
5n + 220 - 10n = 145
-5n = -75
n = 15 nickels
d = 22 - 15 = 7 dimes
Check: All the nickels are worth 75 cents and all the dimes are worth 70 cents. 75 + 70 = 145 cents or $1.45
e^(iπ) = ?
e^(iπ) + 1 = ?
Rafael can type 24 words in 6 minutes. What is his rate in words per minute
Answer:
24/6= 4
4 words per minute
Step-by-step explanation:
Answer:
4 words per minute
Step-by-step explanation:
Rafael can type 24 words in 6 minutes, so we divide 24 and 6 to get 4 words per minute.
Find the binomial distribution for flipping a coin 3 times, where "heads" is a success. P(k successes) = nCk pk(1 – p)n – k P(0 successes) = 3C0(0.5)0(0.5)3
Answer:
0.125, 0.375, 0.375, 0.125
Step-by-step explanation:
For a binomial distribution :
nCk * p^k * (1 – p)^(n – k)
P(0 successes) = 0 head, k = 0
n = 3 = number of flips
P(success) = 0.5
3C0 * 0.5^0 * 0.5^3
1 * 0.5^0 * 0.5^3 = 0.125
P( 1 success) = 1 head, k = 1
n = 3 = number of flips
P(success) = 0.5
3C1 * 0.5^1 * 0.5^2
3 * 0.5^1 * 0.5^2 = 0.375
P(2 successes) = 2 head, k = 2
n = 3 = number of flips
P(success) = 0.5
3C2 * 0.5^2 * 0.5^1
3 * 0.5^2 * 0.5^1 = 0.375
P(3 successes) = 3 head, k = 3
n = 3 = number of flips
P(success) = 0.5
3C3 * 0.5^3 * 0.5^0
1 * 0.5^3 * 0.5^0 = 0.125
Answer:
0.125, 0.375, 0.375, 0.125
second part is 0.5
Step-by-step explanation:
achel rolls two number cubes, each with sides that are labeled 1 to 6. What is the probability that onennumber cube lands on a 1 and the other lands on an even?
Answer:
immma send you the link friend me on here
Step-by-step explanation:
1. Find the sum of \sum_(n=1)^(14) 5n+3.
2. A supermarket display consists of boxes of cereal. The bottom row has 63 boxes. Each row has seven fewer boxes than the row below it. The display has six rows.
Write and use a function to determine how many boxes are in the top row. Show your work.
Use the appropriate formula to determine the number of boxes in the entire display.
3. The number of visitors to a website in the first week is 418. The number of visitors each week is quadruple the number of visitors the previous week. What is the total number of visitors to the website in the first 6 weeks? Show the formula with correct values plugged in along with your answer.
I am so confused. Need help ASAP. (Math is getting tougher lol. Please show your work for each question so i can understand better)
The total number of visitors to the website in the first 6 weeks are 12510.
What is the number?
A number is a mathematical object used to represent a quantity or value. Numbers can be positive, negative, or zero, and can be represented in various ways such as decimals, fractions, or percentages.
To find the sum of the expression \(\sum_{(n=1)} (14) 5n+3\), we can use the formula for the sum of an arithmetic sequence:
Sₙ = n/2 * [2a + (n-1)d]
where Sₙ is the sum of the first n terms of the sequence, a is the first term, d is the common difference, and n is the number of terms.
In this case, a = 5(1) + 3 = 8 (the first term of the sequence), d = 5 (the common difference), and n = 14 (the number of terms we want to sum). Plugging these values into the formula, we get:
S₁₄ = 14/2 * [2(8) + (14-1)(5)]
= 7 * [16 + 65]
= 7 * 81
= 567
Therefore, the sum of the expression \(\sum_{(n=1)} (14) 5n+3\) is 567.
We can write a function in Python to determine the number of boxes in the top row:
python boxes_in_top_row(num_rows, bottom_row):
"""
Returns the number of boxes in the top row of a supermarket display, given the number of rows
and the number of boxes in the bottom row.
"""
total_diff = (num_rows - 1) * 7 # total difference in boxes between top row and bottom row
top_row = bottom_row - total_diff # number of boxes in top row
return top_row
Using this function, we can find the number of boxes in the top row of a display with six rows and a bottom row of 63:
boxes in top row(6, 63)
21
Therefore, there are 21 boxes in the top row.
To find the total number of boxes in the display, we can use the formula for the sum of an arithmetic series:
Sₙ = n/2 * [2a + (n-1)d]
where Sₙ is the sum of the first n terms of the sequence, a is the first term, d is the common difference, and n is the number of terms.
In this case, a = 21 (the number of boxes in the top row), d = -7 (the common difference between rows), and n = 6 (the number of rows). Plugging these values into the formula, we get:
S₆ = 6/2 * [2(21) + (6-1)(-7)]
= 3 * [42 - 35]
= 3 * 7
= 21
Therefore, the total number of boxes in the display is 21 + 28 + 35 + 42 + 49 + 56 = 231.
To find the total number of visitors to the website in the first 6 weeks, we can use a geometric sequence:
a = 418 (the number of visitors in the first week)
r = 4 (the common ratio between weeks)
n = 6 (the number of weeks we want to consider)
The formula for the sum of a geometric sequence is:
S_n = a(1 - rⁿ) / (1 - r)
Plugging in the values we have, we get:
S₆ = 418(1 - 4⁶) / (1 - 4)
= 418(1 - 4096) / (-3)
= 12510
Therefore, the total number of visitors to the website in the first 6 weeks are 12510.
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the arithmetic progressions{2,5,8,11, . . .}and{3,10,17,24, . . .}have some common values. what is the largest value less than 500 that they have in common?
The largest value less than 500 that the arithmetic progressions have in common = 479
In this question, we have been the arithmetic progressions {2,5,8,11, . . .} and {3,10,17,24, . . .}
We need to find the largest value less than 500 that they have in common.
We know that the formula for the n-th term of arithmetic progression is: an = a + (n – 1)d
For arithmetic progression {2,5,8,11, . . .}
a_m = 2 + (m - 1)3
For arithmetic progression {3,10,17,24, . . .}
a_n = 3 + (n - 1)7
if we solve for m, n then m =160 and n =69
2 + (160 -1)*3 = 479 which is the 160th term in the arithmetic progression {2,5,8,11, . . .}
3 + (69 - 1)*7 =479 which is the 69th term in the arithmetic progression {3,10,17,24, . . .}
Therefore, the value which less than 500 that both the progressions have in common = 479
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For every 2 males birds in a birdcage, there are 5 females. What is the ratio of
males to females? *
Answer:
2:5
Step-by-step explanation:
The structure of a ratio is x:y.
So all you have to do is place the former as the first digit and the latter as the second and separate them by a colon.
if p(x)=2x cubed-3x+5 what is the remainder p(x) divided by (x-5)
Step-by-step explanation:
Hello
p(x) = quotient × (x-5) + remainder
From above equation remainder is obtained by putting x= 5 (can you see why?)
Thus remainder is p(5) which you can evaluate using a calculator.
a good way to get a small standard error is to use a ________.
Answer: A good way to get a small standard error is to use a large sample.
Step-by-step explanation:
In order to find the small standard error, there is always need of a complete set which is called the large sample.
If tried to do a small or repeating sample, you will most likely not get an error and you could get a repetition. If you do a population sample, you wont get accurate results at all.
Therefore, a good way to get a small standard error is to use a large sample. Hope this helps!
-From a 5th Grade Honors Student