pls help ill mark as brainliest :)

Q7. Pb + O2 PbO2

Is this combustion, single replacement, double replacement, synthesis, or decomposition

Answer:

Inertia in our body tends to be in the situation it is. So, we a car comes to a halt, our body wants to keep moving i.e. in motion. hope that helps love!

a 0.5222 −g sample of an unknown monoprotic acid was titrated with 9.98×10−2 . the equivalence point of the titration occurs at 23.72 ml. the molar mass of the unknown acid is 220.63 g/mol.

To find the molar mass of the unknown monoprotic acid, we can use the concept of stoichiometry and the given information from the titration.

The equivalence point of the titration occurs when the moles of acid are equal to the moles of the titrant.

First, let's calculate the number of moles of the titrant used in the titration:

moles of titrant = volume of titrant × molarity of titrant

moles of titrant = 23.72 ml × (9.98×10^(-2) mol/ml)

moles of titrant ≈ 2.3666 × 10^(-3) mol

Since the unknown acid is monoprotic, the number of moles of the acid is equal to the number of moles of the titrant.

moles of acid = 2.3666 × 10^(-3) mol

Next, we can calculate the molar mass of the unknown acid using the formula:

molar mass (g/mol) = mass of acid (g) / moles of acid

Given that the mass of the acid is 0.5222 g and the moles of acid is 2.3666 × 10^(-3) mol, we can substitute these values into the formula:

molar mass (g/mol) = 0.5222 g / (2.3666 × 10^(-3) mol)

Calculating the value:

molar mass (g/mol) ≈ 220.63 g/mol

Therefore, the molar mass of the unknown monoprotic acid is approximately 220.63 g/mol.

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Answer:

Answer:- Density of the substance is 0.7

i believe

Answer: The molarity is 0.25 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

\(Molarity=\frac{n\times 1000}{V_s}\)

where,

n = moles of solute

\(V_s\) = volume of solution in ml

moles of \(CO_2\) = \(\frac{\text {given mass}}{\text {Molar mass}}=\frac{11g}{44g/mol}=0.25mol\)

Now put all the given values in the formula of molality, we get

\(Molarity=\frac{0.25\times 1000}{1000ml}\)

\(Molarity=0.25M\)

Therefore, the molarity is 0.25 M

The pH of the solution is 1.954. The pH scale ranges from 0 to 14, with 7 being neutral.

The pH of a solution is defined as the negative logarithm (base 10) of the concentration of hydrogen ions (H+) in the solution. Since HNO3 is a strong acid, it is almost completely dissociated in water, so the concentration of H+ ions in the solution is equal to the concentration of HNO3.

We first need to determine the concentration of nitric acid (HNO3) that has formed from the reaction of NO2 with water.

The molar mass of NO2 is 46.006 g/mol, so the number of moles of NO2 dissolved in 1.00 L of water is

4.18 mg / 46.006 g/mol = 0.0910 mol.

Since the reaction between NO2 and water is:

NO2 (aq) + H2O(l) → HNO3 (aq) + NO(g)

The number of moles of HNO3 formed is equal to the number of moles of NO2 present, which is 0.0910 mol.

So, the concentration of HNO3 is 0.0910 mol / 1.00 L = 0.0910 M.

pH = -log(0.0910) =1.954

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Answer:

The answer you have selected in the screenshot is correct.

Its tendency to react with oxygen is correct.

Hope this helps.

The percent yield of H₂O, if 87.0 g of H₂O is produced by combining 95.0 g of O₂ and 11.0 g of H₂ is 87.87%.

Mass of any substance will be calculated by using their moles as:

n = W/M, where

W = given or required mass

M = molar mass

Moles of 95g of Oxygen (O₂) = 95g / 32g/mol = 2.96 moles

Moles of 11g of hydrogen (H₂) = 11g / 2g/mol = 5.5 moles

Given chemical reaction is:
2H₂ + O₂ → 2H₂O

From the stoichiometry of the reaction, it is clear that:

1 moles of O₂ = reacts with 2 moles of H₂

2.96 moles of O₂ = reacts with 2×2.96=5.92 moles of H₂

Here hydrogen is the limiting reagent as it has lower moles and formation of water depends on this only.

2 moles of H₂ = produces 2 moles of water

5.5 moles of H₂ = produces 5.5 moles of water

Mass of 5.5 moles of water will be calculated as:

W = (5.5mol)(18g/mol) = 99g

Given theoretical yield of water = 87g

% yield of water will be calculated as:
% yield = (87 / 99)×100 = 87.87%

Hence required value is 87.87%.

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Answer:

D

Explanation:

To transform an alkene bonded to a tert-butyl group and three hydrogens to a tert-butyl group bonded to CH2CH2OH, the best reagents are H2SO4 and H2O.

H2SO4 is used to protonate the double bond and form a carbocation, which can then undergo nucleophilic attack by water to form the final product. This reaction is known as hydration of alkenes.To perform the transformation, the alkene is first protonated with H2SO4 to form a carbocation intermediate.

Water acts as a nucleophile and attacks the carbocation to form the alcohol product. This reaction is shown below:Thus, the final product formed is tert-butyl group bonded to CH2CH2OH.Another way to perform this transformation is by using oxymercuration-demercuration.

In this reaction, the alkene is first treated with mercuric acetate and water to form a cyclic intermediate.

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The chemical equation provided is an example of a heterogeneous reversible reaction: 2HgO (s) ⇌ 2Hg (l) + O₂ (g)

In this reaction, solid mercury oxide (HgO) decomposes into liquid mercury (Hg) and gaseous oxygen (O₂), and this process is reversible. That is, under certain conditions, the reaction can proceed in either direction.

The reaction can be represented by an equilibrium constant (K), which is the ratio of the concentrations (or partial pressures) of the products to the reactants, raised to the stoichiometric coefficients:

K = [Hg]²[O₂]/[HgO]²

At equilibrium, the value of K determines the direction in which the reaction will proceed. If K is greater than 1, the equilibrium lies to the right, and there are more products than reactants. If K is less than 1, the equilibrium lies to the left, and there are more reactants than products. If K is equal to 1, the reaction is at equilibrium, and the concentrations (or partial pressures) of the reactants and products are equal.

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The complete question is:

Is the following equation a heterogeneous reversible reaction 2HgO (s) ⇌ 2Hg (l) + O₂ (g)

The equilibrium constant of the reaction from the calculation that has been done is 0.154

The concentrations (or partial pressures) of reactants and products in chemical equilibrium for a specific chemical reaction are related by the equilibrium constant (K), a mathematical equation. It quantifies the degree to which an equilibrium has been reached in a reaction.

We have the equation of the reaction as;

A(g) + B(g) ⇔C(g)

Thus;

Keq = 45.83/11.23 * 26.50

Keq = 0.154

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Answer:

2

Explanation:

According to the concept of valency, 2 moles of oxygen are needed to react with 100.0 grams of aluminum.

Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.

It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.

It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons. Molar mass has units of gram per mole . In case of molecules, where molar mass  in grams present in one mole  of atoms is its atomic mass.

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Answer:

1

Explanation:

As you can see by the charges, Ga goes from a charge of 0 to a charge of +1, meaning Ga has lost one electron. Ag goes from a charge of +1 to a charge of 0, meaning Ag has gained one electron. In this case, Ga gave the electron to Ag, meaning that only one electron was transferred between the two metals.

Answer:

The partial pressure of the game because it was not the first time that happened to me and I was just wondering if I could get a better idea of what I need to do to get this done and what I need to do to get this done and what I need to do to get this done and what I need to do to get this done and what I need to do to get this done and what I need to do to get this done and what I need to

: The partial pressures of all the gases present in air are added to determine the total pressure of air at sea level. At sea level, nitrogen, oxygen, and all other gases have corresponding partial pressures of 77.10 kPa, 21.23 kPa, and 3.01 kPa.

As a result, the partial pressures of all the gases present in air are added to get the total pressure of air at sea level. The following formula is used to determine the air pressure at sea level: Air pressure at sea level is equal to 77.10 kPa plus 21.23 kPa plus 3.01 kPa, or 101.34 kPa.

Consequently, the air's overall pressure at sea level is 101.34 kPa. This total pressure of air is also known as the atmospheric pressure or barometric pressure.

It is the tension.exerted by the force of the atmosphere's air. The weather and climate of a place are significantly influenced by the atmospheric pressure. It may also be used to determine the height of a rocket or an aeroplane. An aeroplane or rocket's height is determined using the atmospheric pressure since it drops as altitude rises.

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Answer:

This is because water molecules are made of atoms. Atoms may have special ends that attract to each-other magnetically, causing the water to look like it merges into 2 different drops.

Sodium from Na3PO4(aq) could be prepared by electrolysis of the aqueous solution shown. Based on the provided options, the element that could be prepared by electrolysis of the aqueous solution shown

Potassium from KCl(aq)
Here's why:
- Sodium from Na3PO4(aq) and Nitrogen from AgNO3(aq) are not possible because these ions are more stable in solution than undergoing electrolysis.
- Sulfur from K2S04(ed) is not valid as the compound should be K2SO4(aq) and even then, it would produce oxygen at the anode instead of sulfur.
- Oxygen from H2SO4(aq) can be prepared through electrolysis, but this is not an element directly obtained from the compound.
Potassium from KCl(aq) can be prepared by electrolysis. During this process, K+ ions are reduced to potassium metal at the cathode, and Cl- ions are oxidized to chlorine gas at the anode.

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Answer:

3.79 g

Explanation:

Answer: 7

Explanation: i don't know how the HECK. -3-(-8)-(-2)=7 but I searched it up soooooo also I got it right

This peptide is positively charged at physiological pH. In conclusion, SDEKAINVKWQLA and SDEKAINVKWQHA are neutral at physiological pH, SEERAINVAWQHA is negatively charged, and SDEK is positively charged.A peptide is a short chain of amino acids that are joined together with peptide bonds.

The nature of a peptide's charge depends on the overall charges of the amino acids in the sequence. At physiological pH, amino acids will either be positively charged, negatively charged, or neutral, depending on their side chains. Let's examine the peptides provided to determine their charges at physiological pH:SDEKAINVKWQLA: This peptide contains a mix of amino acids with positively charged, negatively charged, and neutral side chains. However, the positively charged amino acid (lysine) and the negatively charged amino acid (aspartic acid) are present in equal amounts.

Therefore, this peptide is considered neutral at physiological pH.SDEKAINVKWQHA: This peptide is similar to the first one but has one less amino acid (alanine instead of leucine at the end). It contains the same number of positively charged and negatively charged amino acids, and so it is also neutral at physiological pH.SEERAINVAWQHA: This peptide contains three negatively charged amino acids (aspartic acid and glutamic acid) and only one positively charged amino acid (lysine). Therefore, the peptide overall is negatively charged at physiological pH.SDEK: This peptide contains both positively charged (lysine) and negatively charged (aspartic acid) amino acids. However, there are more positively charged amino acids in the peptide than negatively charged ones.

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Answer:

A

Explanation:

DNA and RNA being nucleic acids are proteins in nature hence same theory but just modified.

Answer:

Ca(2+)

Explanation:

Sodium (Na) only have one valence electron and will lose it in order to gain a full octet. There will be an unbalance of electrons and protons where there are more protons there electrons. The correct ion formula for sodium is Na (1+).

Nitrogen has 5 valence electrons and will gain three more to gain a full octet. There will be an unbalance where there are more electrons then protons. Nitrogen will form the ion N (3-).

Calcium has two valence electrons and will lose them in order to gain a full octet. There will be an unbalance where there are more protons then electrons. Calcium will form the ion Ca 2+

Therefore, Ca2+ is the ion with the correct charge.

Answer:

I think it is more that one is correct, so sorry if I'm wrong, if it isn't, it is one of the electron bonding ones

A formula for the sensitivity dR/dM  represents the sensitivity of the body's reaction to the medication. It shows how the reaction changes with respect to the dose of the medication, M. The term M*C represents the contribution of the constant C to the sensitivity, while the term \((2M^2)/3\) represents the contribution of the dose M itself.

To find a formula for the sensitivity, dR/dM, let's differentiate the given function R(M) with respect to M.

Step 1: Start with the function \(R(M) = M^2(C/2 - M/3).\)

Step 2: Apply the power rule of differentiation to differentiate M^2. The power rule states that if

\(f(x) = x^n, then f'(x) = n*x^(n-1). \\\)

n this case, n = 2.

\(dR/dM = 2M^(2-1)*(C/2 - M/3).\)

Simplifying, we have:

\(dR/dM = 2M*(C/2 - M/3).\)

Step 3: Distribute the 2M to each term inside the parentheses:

\(dR/dM = M*C - (2M^2)/3.\)

This formula represents the sensitivity of the body's reaction to the medication, dR/dM. It shows how the reaction changes with respect to the dose of the medication, M. The term M*C represents the contribution of the constant C to the sensitivity, while the term \((2M^2)/3\) represents the contribution of the dose M itself.

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the formula for the sensitivity, or the rate of change of the reaction R with respect to the dose M, is

dR/dM = MC - M\(^2^/^3\)

We calculate the derivative of the reaction function R(M) with respect to M.

the reaction function: R(M) = M²(C/2 - M/3)

We will apply  the power rule and the constant multiple rule of differentiation,

dR/dM = d/dM [M²(C/2 - M/3)]

= 2M(C/2 - M/3) + M²(0 - (-1/3))

= 2M(C/2 - M/3) + M\(^2^/^3\)

dR/dM =\(MC - 2M^2^/^3 + M^2^/^3\)

= \(MC - M^2^/^3\)

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The decay of Pb by emitting a β− particle results in the production of Bi. β− decay is a process in which an atomic nucleus emits an electron (β− particle) and transforms into a different nucleus.

In the case of Pb, it undergoes β− decay to become Bi. The equation representing this decay process is:

\(\[^{210}\textrm{Pb} \rightarrow \,^{210}\textrm{Bi} + e^{-}\]\)

In this equation, the superscripts represent the mass numbers of the nuclides, while the subscripts represent their atomic numbers. Pb has a mass number of 210, and during the decay process, it emits a β− particle and transforms into Bi, which also has a mass number of 210. The emitted β− particle carries away excess energy and atomic charge to maintain the balance in the decay process.

Overall, when Pb undergoes β− decay, it transforms into Bi by emitting an electron (β− particle). This process helps stabilize the nucleus and leads to the formation of a new nuclide.

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Answer:

The correct option is;

Cylinder A contains a gas that has a temperature closest to absolute zero

Explanation:

From the kinetic theory of gases, the average speed of a gaseous molecule is found from the following equation;

\(v_{rms} = \sqrt{\frac{3\cdot R \cdot T}{MW} }\)

Where:

\(v_{rms}\) = rms speed which is the square root of the average of the velocities of the gas molecules squared which is used in place of the average of the gas molecules as the sum of the velocities of all the gas molecules in the cylinder is zero

R = Universal gas constant = 8.3145 J/(mol·K)

MW = Molecular weight of the gas

Hence where we have;

\(v_{rmsA}\) = Average velocity of gas A = 0.0000001 m/s

\(v_{rmsB}\) = Average velocity of gas B = 0.3 m/s

Since, R and MW are constant for the gas in cylinder A constant, therefore, as \(v_{rmsA}\) ≈ 0 m/s, the temperature, \(T_A\), of gas A is closest to absolute zero.

The element is Neon
The protons is the same as the atomic number (10 protons)
The electrons are the same as the number of protons in a neutral atom (10 electrons)
The neutrons can be found by subtracting the protons from the atomic mass (22-10=12 neutrons)

Answer:

no.

Explanation: