Answer:
c
Explanation:
Answer:
C. Element
I HAVE HELPED!!!!!!!!!
How many sodium atoms are
present in one formula unit of
sodium chromate?
1
4
7
2
The number of sodium atoms in a formula unit of the sodium chromate is 2.
How many sodium atoms are present?We know that the formula of a compound is the way that we can be able to know the atoms that we can find in the compound. The chemical formula shows the number of atoms of each of the elements that is present.
Now let us look at the formula unit of of sodium chromate as we have shown in the image that is attached to this answer. It shows us the number of the oxygen, sodium and the chromium atoms that we have in a formula unit of the sodium chromate.
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What mass of water can be heated from 15.0° C to 43.1° C by the addition of 1282 J?
The mass of water that can be heated from 15.0° C to 43.1° C by the addition of 1282J is 10.9grams.
How to calculate mass?The mass of water can be calculated using the following expression;
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperatureAccording to this question, a sample of water can be heated from 15.0° C to 43.1° C by the addition of 1282J. The mass of the substance can be calculated as follows;
1282 = m × 4.184 × (43.1 - 15)
1282 = 117.57m
m = 10.9grams
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How many grams of ice at -29.4 ∘C can be completely converted to liquid at 27.1 ∘C if the available heat for this process is 5.75×103 kJ ? For ice, use a specific heat of 2.01 J/(g⋅∘C) and ΔHfus=6.01kJ/mol .
1.135 grams of ice at -29.4 ∘C can be completely converted to liquid at 27.1 ∘C if the available heat for this process is 5.75×103 kJ.
What is specific heat ?The term specific heat is defined as the quantity of heat required to increase the temperature of one gram of a substance by one Celsius degree.
Let mass of ice is 1g
q = mcT
= 1 × 2.01 ×(0-(-11)
= 2.01 × -29.4
= 59.09 joules
q = m × ΔHfus
= 1 × 334 = 334J
q = mcT
= 1 × 4.18(27.1-0)
= 113.27 J
total heat = 59.9 + 334 + 113.27
= 506.368 joules
= 0.506368 Kj/g
actual heat = 5.75×10³ Kj
mass of ice = 5.75×10³ / 0. 506368
= 1.135 g
Thus, 1.135 g of ice at -29.4 ∘C can be completely converted to liquid at 27.1 ∘C.
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Someone please help me
Answer:
D - synapse
Explanation:
Synapse, also called neuronal junction, the site of transmission of electric nerve impulses between two nerve cells (neurons) or between a neuron and a gland or muscle cell (effector). A synaptic connection between a neuron and a muscle cell is called a neuromuscular junction.
2.60 moles CO and 2.60 moles H2O are placed in a 2.00L container at 690 °C (Keg=10.0).Calculate all equilibrium concentrations in the following reaction:
Answer:
considering the information given, the concentrations at equilbrium are:
CO(g) = 1.30 M
H2O(g) = 1.30 M
CO2(g) = 4.11 M
H2(g) = 4.11 M
Explanation:
The question requires us to calculate the concentration of CO, H2O, CO2 and H2, given the following information:
- number of moles of CO = 2.60 mol
- number of moles of H2O = 2.60 mol
- volume of container = 2.00 L
- temperature = 690°C
- equilibrium constant = 10.0
- balanced chemical equation:
\(CO_{(g)}+H_2O_{(g)}\rightleftarrows CO_{2(g)}+H_{2(g)}\)Since the number of moles of CO and H2O were provided, as well as the volume of the container, we can calculate the concentration of this gases in moles per liter:
\(\begin{gathered} [CO\rbrack=\frac{2.60mol}{2.00L}=1.30mol/L=1.30M \\ \\ [H_2O\rbrack=\frac{2.60mol}{2.00L}=1.30M \end{gathered}\)Also, since we have the equilibrium constant for this reaction and the concetrations of CO2 and H2 at equilibrium will be the same (they have the same stoichiometric coefficient), we can calculate the concentration of the products using the expression for Keq.
First, let's write the Keq expression for this reaction:
\(K_{eq}=\frac{[CO_2\rbrack\times[H_2\rbrack}{[CO\rbrack\times[H_2O\rbrack}\)Considering,
[CO2] = [H2] = x
and rearranging this equation to calculate x:
\(K_{eq}\times[CO\rbrack\times[H_2O\rbrack=x^2\rightarrow x=\sqrt[2]{K_{eq}\times[CO\rbrack\times[H_2O\rbrack}\)Now, applying the value of Keq given by the question, and the values of concentration calculated previously, we'll have:
\(x=\sqrt[2]{10.0\times1.30M\times1.30M}\rightarrow x=4.11M^\)Therefore, considering the information given, the concentrations at equilbrium are:
CO(g) = 1.30 M
H2O(g) = 1.30 M
CO2(g) = 4.11 M
H2(g) = 4.11 M
can u identify a chemical equation for the saponification of olive oil as per your experiment?
I
name all the planets in the solar system
Answer:
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptun
explain the statement potash alum is a double salt using the chemical formula of alum
Potash alum, represented by the chemical formula KAl(SO4)2·12H2O, is a double salt because it consists of two different salts, potassium sulfate (K2SO4) and aluminum sulfate (Al2(SO4)3), combined together. It forms a unique crystalline structure with 12 water molecules incorporated in its composition.
Potash alum is a type of alum that is commonly used in dyeing and water purification applications. The chemical formula for alum is KAl(SO4)2·12H2O.
The term "double salt" refers to the fact that the compound is made up of two different types of ions that are combined together.
In the case of potash alum, the two different types of ions are potassium ions (K+) and aluminum ions (Al3+). These two ions are combined together in a 1:1 ratio to form a complex ion, KAl(SO4)2, which is then combined with 12 water molecules to form the final compound, KAl(SO4)2·12H2O.
The term "double salt" is used to describe this type of compound because it contains two different types of cations (positive ions) that are combined together to form a single crystal lattice structure.
The two different cations are held together by ionic bonds, which are relatively strong and help to give the compound its characteristic properties.
Potash alum is a particularly useful compound because it has a number of important properties that make it useful in a variety of applications.
For example, it is highly soluble in water, which makes it a good choice for use in water purification applications.
It is also relatively stable and non-toxic, which makes it safe to use in a variety of different settings.
Finally, it has a number of useful physical properties, such as its ability to form crystals that are highly reflective and have a characteristic octahedral shape.
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Calculate the number of CO2
molecules ( NCO2
) in 0.0734 mol
of CO2
Answer:
4.42 x 10^22 molecules
Explanation:
1 mole of CO2 has 6.022 x 10^23 molecules
=> 0.0734 x 6.022 x 10^23 = 4.420148 x 10^22 or 4.42 x 10^22
Predict the product for the following reaction sequence.3,4-dimethyl-7-nonanol 3,4-dimethyl-7-nonanone 6,7-dimethyl-3-nonanone 6,7-dimethyl-3-nonanal 6,7-dimethyl-3-nonanol
Answer:
Hello your question is incomplete attached below is the complete question
answer : 6,7-dimethyl-3-nonanone ( B )
Explanation:
The product for the following reaction sequence as attached below is
6,7-dimethyl-3-nonanone
The following reaction sequence can be categorized under Carbon Nucleophiles.
Carbon Nucleophiles which can be used to convert aldehydes and ketones into carboxylic acids or alkenes.
The product for the given reaction sequence is 6,7-dimethyl-3-nonanone.
IUPAC (International Union of Pure and Applied Chemistry) naming is a systematic method used to name chemical compounds according to a set of rules established by the IUPAC.
The purpose of IUPAC naming is to provide a consistent and unambiguous way to communicate the structure of a compound through its name.
The outcome of the subsequent chain of reactions, which is appended below, is 6,7-dimethyl-3-nonanone
Under the heading of Carbon Nucleophiles, the following reaction chain can be categorised.
Aldehydes and ketones can be transformed into carboxylic acids or alkenes using carbon nucleophiles.
Thus, the answer is 6,7-dimethyl-3-nonanone.
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Your question seems incomplete, the probable complete question is:
What is an orbital? This is the question.
Answer:
A atomic orbital is a mathematical function describing the location and wave-like behavior of an electron in an atom.
Explanation:
Have a great day :)
Chemistry Lab Determination of the Universal Gas Constant (R)
SHOW ALL WORK
Given:
Initial mass of butane lighter: 54.24g
Final Mass of Butane Lighter: 54.01g
Temperature of water: 23.0°C
Volume of gas collected: 100.0mL
FIND:
Barometric pressure of room: 766.86 mmHg CONVERTED TO atm
Vapor pressure of water at room temperature(PH2O) (IN atm)
FIND:
Mass difference if butane lighter in grams
Moles of Butane gas collected in moles of C4H10
Partial pressure if butane gas in atm
Converted temperature of water in Kelvin
Converted volume of gas collected in Liters
Experimental value of R in Latm/molk
Accepted value of R in Latm/molk
Percent error in experimental value of R in %
CONCLUSION QUESTIONS:
1. List at least 3 factors that either did it could contribute to the percent error
2. Should the value of R go up or down if the gas had not been corrected for the partial pressure of water. Why?
3. How could this experiment be repeated to increase the accuracy, or in other words, decrease the percent error?
NOTE: LET ME KNOW IF YOU WANT A PICTURE OF THE LAB INSTRUCTIONS TO HELP SOLVE
ALSO SHOW ALL WORK PLS
To determine the universal gas constant (R), we can use the ideal gas law equation: PV = nRT, where P is the total pressure, V is the volume of gas, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.
Barometric pressure of the room: To find the barometric pressure in atm, we convert 766.86 mmHg to atm by dividing it by 760 mmHg/atm, giving us 1.0089 atm.Vapor pressure of water at room temperature (PH2O).The vapor pressure of water at 23.0°C is 0.0313 atm.
Mass difference of butane lighter:The mass difference is calculated by subtracting the initial mass (54.24 g) from the final mass (54.01 g), resulting in a difference of 0.23 g.
Moles of butane gas collected:To find the moles of butane gas, we can use the equation n = m/M, where n is the number of moles, m is the mass, and M is the molar mass of butane (58.12 g/mol). Thus, n = 0.23 g / 58.12 g/mol = 0.003959 mol.
Partial pressure of butane gas:The partial pressure of butane gas is calculated by multiplying the moles of butane gas (0.003959 mol) by the ideal gas constant (R) and the converted temperature (23.0°C + 273.15 K). Let's assume the converted temperature is 296.15 K.
Converted volume of gas collected:The volume of gas collected is given as 100.0 mL, which needs to be converted to liters by dividing it by 1000, resulting in 0.1 L.
Experimental value of R:The experimental value of R can be determined by rearranging the ideal gas law equation to solve for R: R = (P - PH2O) * V / (n * T).
Accepted value of R:The accepted value of R is 0.0821 Latm/molK.
The percent error can be calculated using the formula: (|Experimental value - Accepted value| / Accepted value) * 100.
Factors contributing to percent error could include experimental error in mass measurements, inaccurate temperature measurements, and loss of gas during collection or transfer.
If the gas had not been corrected for the partial pressure of water, the value of R would be lower because the partial pressure of water would contribute to the total pressure, resulting in a smaller value for P in the ideal gas law equation.
To increase accuracy and decrease percent error, the experiment could be repeated multiple times to obtain an average value, use more precise measuring instruments, conduct the experiment in a controlled environment, and ensure accurate calibration of equipment.
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Suppose that 0.95 g of water condenses on a 75.0 g block of iron that is initially at 22 °C. If the heat released during condensation goes only to warming the iron block, what is the final tempera- ture (in Celsius) of the iron block? (Assume a constant enthalpy ofvaporizationforwaterof44.0kJmol-1.)
Answer:
The temperature of the iron block is 68.5°C.
Explanation:
The heat released during condensation of water is used to warm the iron block:
q = m_H2O * ΔH_vap = m_fe * c_fe * ΔT
where q is the heat released, m_H2O is the mass of water condensed, ΔH_vap is the enthalpy of vaporization for water, m_fe is the mass of iron, c_fe is the specific heat capacity of iron, and ΔT is the change in temperature of the iron block.
Rearranging the equation gives:
ΔT = (m_H2O * ΔH_vap) / (m_fe * c_fe)
Substituting the given values gives:
ΔT = (0.95 g * 44.0 kJ/mol) / (75.0 g * 0.449 J/(g°C))
ΔT = 46.5°C
Therefore, the final temperature of the iron block is:
T_f = T_i + ΔT = 22°C + 46.5°C = 68.5°C.
The final temperature of the iron block is 68.5°C.
Which statement is correct abound chemical bonding in BF3 molecule O The molecule is not stable and hardly exist since the number of valence electrons around a central atom in a molecule are less than 8 O The molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8 The molecule is not stable and hardly exist since the number of valence electrons around an atom in a molecule are more than 8 and covalent bonding is not possible None of the above is correct
The molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.
Is BF3 molecule stable or not?BF3 molecule is a stable molecule because all the electrons present in the outermost shell of boron are covalently bonded with fluorine. Boron in BF3, three bonds is the maximum possible because boron only has 3 electrons to share.
So we can conclude that the molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.
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Question 1 (5 points)
What is a
phospholipid?
A.) the molecules that make up the cell membrane
B.) the molecules that provide structure to plant cells
C.) the smaller pieces that make up proteins
D.) the waxy layer on plant leaves
Answer:
A.) the molecules that make up the cell membrane
Explanation:
Phospholipids are the molecules that makes up the cell membrane. They are lipid layers which gives support and regulates the movement of materials in and out of the cell.
The phospholipid is very important for the building of membrane round a cell. They are made up of rich lipid layer which is made up of phosphoric acids, nitrogen base, alcohol and fatty acids.
With these molecules, they are able to stabilize and regulate the movement of materials in and outside of the cell.
When zinc reacts with copper sulfate solution, zinc sulfate solution and copper are formed.(i) An experiment was carried out to measure the temperature change when zinc powder reactswith copper sulfate solution.initial temperature of copper sulfate solution = 20 °Cfinal temperature of mixture after the reaction = 46 °CExplain what the temperature readings show about the type of heat change that occurs duringthis reaction.
The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.
In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.
The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.
During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.
The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.
The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.
In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.
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Which of the following is an incorrect representation for a neutral atom?
36Li
613C
3063Cu
1530P
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li
To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.
Let's analyze the given representations:
36Li:
This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.
613C:
This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.
3063Cu:
This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.
1530P:
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.
Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.
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How many grams of C›H, are needed if 14.38 moles of Oz are used up?(C2H4+302-> 2 CO2+ 2 H20)
Answer:
\(134.21g\text{ of C}_2H_4\text{ is needed}\)Explanation:
Here, we want to calculate the mass of ethene needed
From the balanced equation of reaction:
1 mole of ethene needed 3 moles of oxygen
x moles of ethene will need 14.38 moles of oxygen
To get the value of x, we have it that:
\(\begin{gathered} 1\times14.38\text{ = 3}\times x \\ x\text{ = }\frac{14.38}{3} \\ \\ x\text{ =4.793 moles} \end{gathered}\)To get the mass needed, we have to multiply the number of moles by the molar mass of ethene
The molar mass of ethene is 28 g/mol
Thus, we have the needed mass as:
\(\begin{gathered} Mass\text{ = number of moles }\times\text{ molar mass} \\ Mass\text{ = 4.793 }\times\text{ 28 = 134.21 g} \end{gathered}\)How are tadpoles and larvae similer
Answer: Tadpole, also called polliwog, aquatic larval stage of frogs and toads. Compared with the larvae of salamanders, tadpoles have short, oval bodies, with broad tails, small mouths, and no external gills. The internal gills are concealed by a covering known as an operculum.
Explanation:
1)Fluorine-21 has a half life of approximately 5 seconds. If you start with 100g, how much
would remain after 10 seconds?
What’s the answr
Answer:
25 g
Explanation:
The following data were obtained from the question:
Half life (t½) = 5 s
Original amount (N₀) = 100 g
Time (t) = 10 s
Amount remaining (N) =..?
Next, we shall determine the decay constant for the disintegration. This can be obtained as follow:
Half life (t½) = 5 s
Decay constant (K) =.?
K = 0.693 / t½
K = 0.693 / 5
K = 0.1386 s¯¹
Finally, we shall determine the amount of the isotope that remained after 10 s as follow:
Original amount (N₀) = 100 g
Time (t) = 10 s
Decay (K) = 0.1386 s¯¹
Amount remaining (N) =..?
Log (N₀/N) = kt /2.303
Log (100/N) = (0.1386 × 10) / 2.303
Log (100/N) = 1.386 / 2.303
Log (100/N) = 0.6018
Take the anti log of 0.6018
100/N = antilog (0.6018)
100/N = 4
Cross multiply
100 = N × 4
Divide both side by 4
N = 100/4
N = 25 g
Therefore, the amount remaining after 10 s is 25 g
The histograms show the number of cell phone sales during the store's operating hours for three days. Drag each statement to the box next to the histogram that it describes.
We can help explain how to analyze histograms and interpret the information related to cell phone sales.
To analyze histograms, follow these steps:
1. Identify the horizontal axis (x-axis), which should represent the store's operating hours.
2. Identify the vertical axis (y-axis), which should represent the number of cell phone sales.
3. Observe the height of the bars in the histogram. Each bar represents the number of cell phone sales within a specific time interval during the store's operating hours.
To match the statements to the histograms, you should consider the following:
- Look for any patterns or trends in the data, such as higher sales during certain time periods.
- Compare the histograms to determine if there are noticeable differences between the three days.
- Identify any outlier data points or unusually high or low sales during specific time intervals.
Once you have analyzed the histograms, you can match the statements to the appropriate histogram by considering the trends and patterns you've observed.
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19.If the chemical equation below is balanced using only whole numbers, what is the smallest whole-number coefficient for water?__ Fe2O3 + __ H2 ---> __ Fe + __ H2OSelect one:a. 1b. 2c. 3d. 4
Answer:
c. 3
Explanation:
To find the coefficient for water, we have to balance the chemical reaction:
\(Fe_2O_3+3H_2\rightarrow2Fe+3H_2O\)So, the smallest coefficient for water is 3.
a cube of iron pyrite is 0.31 cm on each side and has a mass of 0.040g. what is the density of the sample?
The density of the iron pyrite cube is 1.343 g/cm³.
Given,
Side of iron pyrite cube = 0.31 cm
Mass of iron pyrite = 0.040 g
The volume of iron pyrite cube = s³ cm³
Or, volume = 0.029791 cm³
We have to find the density of the sample.
Density is defined as the mass per unit volume. Or, it is the ratio of mass to the volume of the substance.
Using the formula for density, we get,
Density = mass/volume
Or, density = 0.40/0.029791
Or, density = 1.343 g/cm³
Hence, the density of the iron pyrite cube is 1.343 g/cm³.
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Based on the ideal gas law, there is a simple equivalency that exists between the amount of gas and the volume it occupies. At standard temperature and pressure (STP; 273.15 K and 1 atm , respectively), one mole of gas occupies 22.4 L of volume. What mass of methanol ( CH3OH ) could you form if you reacted 7.82 L of a gas mixture (at STP) that contains an equal number of carbon monoxide ( CO ) and hydrogen gas ( H2 ) molecules?
You could form approximately 5.8 grams of methanol (CH3OH) from the given gas mixture at STP.
What is the mass?
Using the Ideal gas equation;
n = PV / RT
n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)
From the question;
nCO = n / 2
nH2 = n / 2
Then;
n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)
n = 0.362 mol
nCO = n / 2 = 0.362 mol / 2 = 0.181 mol
nH2 = n / 2 = 0.362 mol / 2 = 0.181 mol
By stoichiometry;
methanol= nCO = 0.181 mol
Mass of methanol = 0.181 mol * 32.04 g/mol
= 5.8 g
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which is the graph of the function g(x) = f(-x)
To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.
What is a graph of the function g(x) = f(-x)?To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.
If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).
However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.
In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.
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1. what is an atom
2. what is a chemical process
3. WHat is a chemical reaction
Answer:
1.An atom is the defining structure of an element, which cannot be broken by any chemical means. A typical atom consists of a nucleus of positively-charged protons and electrically neutral neutrons with negatively-charged electrons orbiting this nucleus.
2.a chemical process is a method or means of somehow changing one or more chemicals or chemical compounds.
3. a process that involves rearrangement of the molecular or ionic structure of a substance, as opposed to a change in physical form or a nuclear reaction.
This graph shows the displacements and times for the winner of
a horse race.
What was the average speed of the horse that won the race?
O 0.05 m/s
O 20 m/s
O 45 m/s
Assignment Your Unde a professor in a University has Sent you an touration 6 his Inaugural lectore wate a letter to him, showing appreciation for him on halind gesture and Congratulating! his achievements So far
In this letter, express gratitude to your uncle, a university professor, for his invitation and congratulate him on his achievements.
Here are the steps to be followed:
By following these steps, you can write a thoughtful and appreciative letter to your uncle, expressing your gratitude for his invitation and congratulating him on his achievements.
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6. Give the balanced full reaction and calculate the E° for galvanic cells based on the
following reactions. Draw diagrams indicating; the anode, cathode, flow of electrons,
salt bridge
(a) Zn^2 (aq) + 2e- = Zn(s)
Pb²(aq) + 2e- → Pb(s)
(b) Cr2O7 + 14H + 6e- 2Cr³+ 7H₂O
H₂O2 + 2H+ + 2e- →2H₂O
Electrochemical cell is one in which energy is released by a chemical action.
What is an electrochemical cell?An electrochemical cell is one in which energy is released by a chemical action.
Now we have the reaction;
Zn^2 (aq) + 2e- = Zn(s)
Pb²(aq) + 2e- → Pb(s)
and
Cr2O7 + 14H + 6e- 2Cr³+ 7H₂O
H₂O2 + 2H+ + 2e- →2H₂O
In the first case, the Ecell is obtained from;
(-0.13 V) - (-0.76 V)
= 0.63 V
In the second case;
1.78 V - 1.33 V
= 0.45 V
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How would you dinstinguish adaptations and variations for a younger student ?
Answer:
just be smart and learn you gotta learn it first