Pls help need to get this done asap

Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

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The simplest definition of a black hole is an object that is so dense that not even light can escape its surface. If we squished the Earth's mass into a sphere with a radius of 9 mm, the escape velocity would be the speed of light. Just a wee-bit smaller, and the escape velocity is greater than the speed of light.

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Bluetooth works through radio waves in the ISM band, that is, they work by radio frequency. For that use the wireless networks of personal area (WPAN).

Bluetooth is a form of communication that works through radio waves by which there can be a transfer of data such as music, documents, images, etc. It works at a short distance so the devices must be close for the data transfer to occur correctly

Therefore, we can confirm that Bluetooth works through radio waves in the ISM band, that is, they work by radio frequency. For that use the wireless networks of personal area (WPAN).

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1,401.88 N is the required weight of the man using the given conversion factor.

To calculate the weight of a typical NFL lineman in Newtons, we need to first convert the weight from pounds to kilograms using the conversion factor of 1 kg = 2.2 pounds:

314 pounds ÷ 2.2 pounds/kg = 142.73 kg

Next, we can use the formula Weight (newtons) = mass * gravity, where gravity is approximately 9.81 m/s^2 (meters per second squared):

Weight (newtons) = 142.73 kg * 9.81 m/s^2 = 1,401.88 N

The required weight in Newton of the man is 1,401.88 N

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The net work done on the rocket as it accelerate upward at 2 m/s is 10796 J.

Work done is the product of force and distance.

To calculate the net work done on the rocket, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the net work done is 10796 J.

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The net work done on the rocket as it accelerates upward at 2.0 m/s through a distance of 30.0m starting from rest is 10796 J

First, we shall list out the given parameters. This is shown below:

Considering the given parameters, we can obtain the net work done on the rocket as illustrated below:

W = ½mv²

Inputting the various varables we have:

W = ½ × 5398 × 2²

W = 2699 × 4

W = 10796 J

Thus, we can conclude that the net work done on the rocket is 10796 J

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Answer:

Aerosol spray lubricants should never be sprayed toward your body

Explanation:

Aerosols are substances that are enclosed under high pressure and released by means of a fine spray propelled by a gas.

It is very dangerous to spray aerosols towards the body as some of them are capable of causing severe damage to the body and even possible death; hence the answer above.

Answer:

the object's weight changes but its mass stays the same

Answer:

the object's weight changes but its mass stays the same

Explanation:

100% correct

Answer:

movement generates energy=heat so 50c should be it

the information provided (34 and 42 seconds) does not give the necessary information to determine the speed at which the BEYBLADE is spinning in miles per hour. To calculate the speed of the BEYBLADE we need to know the distance traveled in each rotation. Also, you mentioned that the beyblade makes 1 rotation in 34 seconds and 42 seconds, which is not correct, it should be 1 rotation per second in 34 seconds, and 1 rotation per 42 seconds.

The horizontal component of the vector is determined as 6i.

The horizontal component of the vector is calculated as follows;

V = (0 i, 0 j) + (6i, 8j)

V = (6i, 8j)

where;

Thus, the horizontal component of the vector is determined as 6i.

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i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

d is the awnser

Explanation:

MABY?!??

Answer:

\( \underline{ \boxed{ yes}}\\\)

Explanation:

\(given : initial \: velocity \: (u )= 40 {ms}^{ - 1} \\ given : final \: velocity \: (u )= 0 {ms}^{ - 1} \\ given : - (acceleration) \: (a_r) = 2 {ms}^{ - 2} \\ given : distance \: (s) \: = \: ? : \\ but \: {v}^{2} = {u}^{2} + 2( a)s\\ {0}^{2} = {40}^{2} + 2( - 2)s \\ - {40}^{2} = - 4s \\ s = \frac{ - {40}^{2} }{ - 4} \\ s = \frac{1600}{4} \\s = 400 \: m\)

The human brain has the capacity to generate new neurons throughout the lifespan (option b).

The correct statement regarding the development and growth of new neurons in the human brain is option A. The human brain has the capacity to generate new neurons throughout the lifespan.

1. Neurogenesis, the process of generating new neurons, was once believed to be limited to early brain development and not to occur in adulthood. However, recent research has challenged this notion.

2. Studies conducted on adult brains have provided evidence of neurogenesis occurring in specific regions of the brain, such as the hippocampus, which is involved in learning and memory.

3. Neurogenesis in the adult brain involves the generation of new neurons from neural stem cells. These stem cells have the ability to differentiate into mature neurons and integrate into existing neural circuits.

4. The process of neurogenesis is influenced by various factors, including environmental enrichment, physical exercise, and certain medications.

5. It is important to note that while neurogenesis occurs in the adult human brain, the rate of neurogenesis is relatively low compared to early brain development.

6. In contrast to option B, there is evidence to support the idea that neurogenesis continues to occur in the human brain after birth and throughout life.

7. Option C is incorrect because while glial cells, a type of support cell in the brain, can reproduce and grow in number throughout adulthood, neurons also have the capacity to generate new neurons.

8. Option D is incorrect as several animal species, including primates, birds, and rodents, have been found to experience neurogenesis in various stages of their lives.

In conclusion, option A is the true statement regarding the development and growth of new neurons in the human brain, as neurogenesis can occur throughout the lifespan.

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Given:

The spring constant of the spring is k = 220 N/m

The compression is x = 0.175 m

The mass of the object is m = 0.75 kg

To find the speed at which an object will leave the spring.

Explanation:

According to the conservation energy, elastic potential energy is equal to kinetic energy.

The speed can be calculated by the formula

On substituting the values, the speed will be

Thus, the speed is 2.997 m/s

The given problem can be exemplified in the following diagram:

We are given that a ladder is against a wall. According to the diagram, the ladder, the wall, and the floor form a right triangle, therefore, if "T" is the distance from the top to the floor and "B" is the distance from the bottom to the wall we can apply the Pythagorean theorem and we get:

Now, since we want to know the speed, we will derivate implicitly with respect to time on both sides of the equation:

Now we solve for the value of the speed of the top of the ladder, this is dT/dt:

The 2 cancels out:

Now we divide both sides by "T":

Now, since we determine the value of "T" from the Pythagorean theorem, we get:

Subtracting B squared from both sides:

Taking the square root:

Now we replace these values in the formula for the velocity:

Now we have an expression for the velocity of the top of the ladder. Replacing the given values:

Solving the operations we get:

Therefore, the speed of the top of the ladder is -0.47 feet per second.

The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The fraction of a wavelength represented by the first harmonic is 1/2.

The higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

1. The first harmonic of a standing wave on a string with a loose end occurs when there is a node near the driver end and an antinode at the loose end. To measure the frequency of the first harmonic, we need to determine the fraction of a wavelength represented by this standing wave.

The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The first harmonic of a standing wave on a string with a loose end consists of a node near the driver end and an antinode at the loose end. This configuration creates the simplest standing wave pattern.

In a standing wave, a node is a point where the amplitude of the wave is always zero, representing a point of minimum displacement. An antinode, on the other hand, is a point of maximum displacement, where the amplitude is at its highest.

Since the loose end does not invert the phase of the wave upon reflection, the reflected wave and the original wave constructively interfere at the loose end, resulting in an antinode.

In the first harmonic, there is exactly half a wavelength between the node near the driver end and the antinode at the loose end.

Therefore, the fraction of a wavelength represented by the first harmonic is 1/2.

2. To predict the frequencies of higher harmonics, we can use the relationship that the frequency of each harmonic is a multiple of the frequency of the first harmonic. The higher harmonics can be calculated as follows:

Second Harmonic: The second harmonic consists of two nodes and one additional antinode compared to the first harmonic. The fraction of a wavelength for the second harmonic is 1/2 * 2 = 1. Thus, the second harmonic has a frequency that is twice that of the first harmonic.

Third Harmonic: The third harmonic consists of three nodes and two additional antinodes compared to the first harmonic. The fraction of a wavelength for the third harmonic is 1/2 * 3 = 1.5. Thus, the third harmonic has a frequency that is three times that of the first harmonic.

Fourth Harmonic: The fourth harmonic consists of four nodes and three additional antinodes compared to the first harmonic. The fraction of a wavelength for the fourth harmonic is 1/2 * 4 = 2. Thus, the fourth harmonic has a frequency that is four times that of the first harmonic.

In general, the higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

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Hence, 1344 10 3 J of heat are needed to melt the ice. From 0°C to 4°C, heating water causes it to continuously contract rather than expand.

In accordance with the U.S. Energy Statistics Administration, coal, nuclear power, and natural gas made up the majority of the country's electrical generation in 2020. Renewable energy sources like wind, hydropower, solar, biomass, and geothermal are also used to generate electricity.

Using coal and oil, nuclear energy, biomass, geothermal, & solar thermal energy, steam turbines are used to produce the majority of the world's power. Gas turbines, hydroelectric turbines, wind turbines, & solar photovoltaics are some additional significant electricity generation systems.

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To solve this problem, we need to use Newton's second law to find the net force acting on the two boxes. The net force is equal to the mass of the two boxes times the acceleration. Since the boxes are moving at a constant speed, the acceleration is zero, and the net force is also zero. This means that the sum of all the forces acting on the two boxes must be zero.The force you exert on the boxes is the force of tension in the rope, and this force is equal in magnitude and opposite in direction to the force of friction on the lower box. The magnitude of the friction force on the lower box is equal to the coefficient of kinetic friction times the normal force acting on the lower box.The normal force is the force exerted by the ramp on the lower box, and it is equal in magnitude to the weight of the lower box. The weight of the lower box is equal to the mass of the lower box times the acceleration due to gravity.The magnitude of the friction force on the upper box is equal to the coefficient of static friction times the normal force acting on the upper box. The normal force acting on the upper box is equal in magnitude to the weight of the upper box.Now that we have all the forces, we can use Newton's second law to solve for the force you need to exert. The equation is:F_tension - F_friction_lower = 0

F_tension = F_friction_lowerF_friction_lower = u_k * N_lower

F_tension = u_k * m_lower * gWhere:F_tension is the force you need to exertF_friction_lower is the force of friction on the lower boxu_k is the coefficient of kinetic friction between the ramp and the lower boxN_lower is the normal force acting on the lower boxm_lower is the mass of the lower boxg is the acceleration due to gravitySubstituting the given values, we get:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The force you need to exert is therefore:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The magnitude of the friction force on the upper box is:F_friction_upper = u_s * N_upperWhere:F_friction_upper is the force of friction on the upper boxu_s is the coefficient of static friction between the two boxesN_upper is the normal force acting on the upper boxSubstituting the given values, we get:F_friction_upper = (0.800) * (m_upper) * (9.8 m/s^2)The direction of the friction force on the upper box is opposite to the direction of motion of the upper box.

Answer:

The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.

Explanation:

Answer:

V2 = 37.5 L

Explanation:

Given the following data;

Initial volume, V1 = 25 L

Initial temperature, T1 = 20°C

Final temperature,T2 = 30°C

To find the final volume V2, we would use Charles' law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

\( \frac {V}{T} = K\)

\( \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}} \)

Making V2 as the subject formula, we have;

\( V_{2}= \frac{V_{1}}{T_{1}} * T_{2}\)

\( V_{2}= \frac{25}{20} * 30 \)

\( V_{2}= 1.25 * 30 \)

V2 = 37.5 L

In Tesla squared meters, the magnitude of the change in the magnetic flux. (ΔΦ= 2.3468T⋅m²).

The magnetic flux through the loop is given by;

Φ = B A cosθ

where B is magnetic field strength, A is area of the loop, and θ is angle between the normal to the loop and the direction of the magnetic field. Since the magnetic field is perpendicular to the plane of the loop, θ = 0 and cosθ = 1.

The magnitude of the change in the magnetic flux is given by;

ΔΦ = Φ₂ - Φ₁

where Φ₁ is the initial magnetic flux through the loop when the magnetic field strength is B₁ = 0.65 T, and Φ₂ is the final magnetic flux through the loop when the magnetic field strength is B₂ = 4.5 T.

The initial magnetic flux through the loop is;

Φ₁ = B₁ A cosθ = 0.65 × πr² × 1 = 0.1126 T⋅m²

The final magnetic flux through the loop is;

Φ₂ = B₂ A cosθ = 4.5 × πr² × 1 = 2.4594 T⋅m²

Therefore, the magnitude of the change in the magnetic flux is;

ΔΦ = Φ₂ - Φ₁ = 2.4594 - 0.1126 = 2.3468 T⋅m²

Therefore, ΔΦ = 2.3468 T⋅m².

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The net force will be equal to 4915.5 N when the elevator accelerates upward with an acceleration of 1.50 m/s².

Tension can be described as a force along the length of a flexible medium such as a cable, rope, etc. Tension is a pulling force but it can not be a pushing force.

When the elevator moves upward with acceleration (a). The net force will be equal to:

Fₙ = mg + ma

Where m is the mass of the object and 'g' is the gravitational acceleration.

Given the total mass of three people = 185 Kg

The mass of the elevator = 250 Kg

Then the total mass, m = 185 + 250 = 435 Kg

The acceleration of the elevator, a = 1.50 m/s²

The net force of the elevator will be: F = 435 × 9.8 + 435 × 1.50

F = 4915.5 N

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The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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The greatest speed of a given pitch at any point from the moment it is released until it passes home plate is represented by velocity, one of the methods used to assess pitchers most commonly.

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Answer:

A. force

Explanation:

Magnetism is a type of force.

Answer:

A. force

Hope this helps

Answer:

C

Explanation:

Option C is correct since it is the effect of Newton’s third law.