PLS HELP WILL GIVE BRAINLIEST
Harry needs wood pieces to complete a project in woodshop class. He needs three pieces of wood that have a length of two and three fourths feet and six pieces of wood that are one and one third feet. What is the total amount of wood that Harry will need for the project?

four and one twelfth feet
sixteen and one fourth feet
three and four sevenths feet
six and one third feet

Answer:

-82

Step-by-step explanation:

84/21=4

-25x4=-100

-3x-6=18

-100+18=-82

option B. $19.72 took the quiz and got 100%

Answer:

option B

Step-by-step explanation:

I took the test and got 100 on it

edge2020

Distance is increasing with a speed of 0.2 Miles/Min

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Time in Minutes      Distance in Miles

0                              0.0

2                              0.4

4                              0.8

6                              1.2

8                              1.6

Here, Myra’s distance is increasing as time increase with a constant Speed.

Now, In every 2 mins distance traveled = 0.4 Miles

Hence, In every 1 min Distance traveled = 0.4/2 = 0.2 Miles/Min

Thus, Distance is increasing with a speed of 0.2 Miles/Min.

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In the Clausius-Clapeyron equation, the variables related to the measured values that would typically be graphed on the x and y axes depend on the specific application.

Generally, the natural logarithm of the vapor pressure (ln P) is plotted on the y-axis, while the reciprocal of the absolute temperature (1/T) is plotted on the x-axis. The slope (m) and y-intercept (b) of the resulting linear graph have specific interpretations in the context of the equation.

The Clausius-Clapeyron equation relates the vapor pressure of a substance to its temperature. It is expressed as ln(P) = -ΔHvap/R * (1/T) + C, where P is the vapor pressure, ΔHvap is the enthalpy of vaporization, R is the gas constant, T is the temperature, and C is a constant. When graphing this equation, we often plot ln(P) on the y-axis and 1/T on the x-axis.

The graph obtained from plotting these variables follows a linear relationship. The slope of the resulting line, denoted as m, is equal to -ΔHvap/R. This slope provides valuable information about the enthalpy of vaporization, which is a measure of the energy required to convert a substance from its liquid phase to its gas phase. The y-intercept, denoted as b, represents the constant C in the equation, which accounts for any initial conditions or deviations from the ideal gas behavior.

By plotting ln(P) against 1/T, we can determine the slope and y-intercept of the linear graph. These parameters have specific physical interpretations and can provide insights into the thermodynamic properties of the substance under investigation. Analyzing the slope and y-intercept values can help in quantifying the enthalpy of vaporization and understanding the behavior of the substance as its temperature changes.

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The intervals are nested, each subsequent interval is contained within the previous one. Mathematically, this means I₁ ⊇ I₂ ⊇ ... In ⊇ ... . Therefore, we have:

1. I₁ ⊇ I₂ implies [a₁; b₁] ⊇ [a₂; b₂], which means a₁ ≤ a₂ and b₁ ≥ b₂.
2. I₂ ⊇ I₃ implies [a₂; b₂] ⊇ [a₃; b₃], which means a₂ ≤ a₃ and b₂ ≥ b₃.

To show that a1 ≤ a2 ≤ ... ≤ an ≤ ..., we need to use the fact that the sequence of intervals is nested, meaning that each interval is contained within the next one.

First, we know that I1 contains I2, so every point in I2 is also in I1. That means that a1 ≤ a2 and b1 ≥ b2.

Now consider I2 and I3. Again, every point in I3 is also in I2, so a2 ≤ a3 and b2 ≥ b3.

We can continue this process for all the intervals in the sequence, until we reach In. So we have:

a1 ≤ a2 ≤ ... ≤ an-1 ≤ an

and

b1 ≥ b2 ≥ ... ≥ bn-1 ≥ bn

This shows that the endpoints of the intervals are ordered in the same way.

Given that I₁ ⊇ I₂ ⊇ ... In ⊇ ... is a nested sequence of intervals and In = [an; bn], we can show that a₁ ≤ a₂ ≤ ... ≤ an ≤ ... and b₁ ≥ b₂ ≥ ... ≥ bn ≥ ... as follows:

Since the intervals are nested, each subsequent interval is contained within the previous one. Mathematically, this means I₁ ⊇ I₂ ⊇ ... In ⊇ ... . Therefore, we have:

1. I₁ ⊇ I₂ implies [a₁; b₁] ⊇ [a₂; b₂], which means a₁ ≤ a₂ and b₁ ≥ b₂.
2. I₂ ⊇ I₃ implies [a₂; b₂] ⊇ [a₃; b₃], which means a₂ ≤ a₃ and b₂ ≥ b₃.

Continuing this pattern for all intervals in the sequence, we can conclude that a₁ ≤ a₂ ≤ ... ≤ an ≤ ... and b₁ ≥ b₂ ≥ ... ≥ bn ≥ ... .

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Answer:

Step-by-step explanation:

5.8(20−3x)

=(5.8)(20+−3x)

=(5.8)(20)+(5.8)(−3x)

=116−17.4x

=−17.4x+116

Answer:

51

Step-by-step explanation:

4(9+4)-6(9+2)

9(13)-6(11)

117-66

51

Answer:

the answer for 4(9 + 4) – 6(9+2) is 54

The equation of the line with slope m and y-intercept b is given by:

In this case the slope is 5 and the y-intercept is -2; then we have that the equation of the line is:

Now that we have the equation of the line we can use it to find points on the line, we do that by given values to x (whichever values we want) and use the equation to determine its corresponding y value.

If x=0, then we have:

Hence, the line passes through the point (0,-2).

If x=1, then we have:

Hence, the line passes through the point (1,3).

Now that we have two points on the line we graph them on the plane:

Finally, we join the points with a straight line. Therefore, the graph of the line is:

Answer:

x=44

Step-by-step explanation:

Pretty straightforward!

4-x/5 +x+2/3=6

3(4-x) + 5(x+2) = 90  (Multiply both sides of the equation by 15, a multiple of              both 5 and 3)

12-3x+5x+10=90 (Use Distributive property to multiply across parentheses)

-3x+5x=90-12+10 (Bring like terms together/Signs change when moved to the other side)

2x=88

x=44

Thank you for your time!

Answer: x=44

Step-by-step explanation: Pretty straightforward!

4-x/5 +x+2/3=6

3(4-x) + 5(x+2) = 90  (Multiply both sides of the equation by 15, a multiple of              both 5 and 3)

12-3x+5x+10=90 (Use Distributive property to multiply across parentheses)

-3x+5x=90-12+10 (Bring like terms together/Signs change when moved to the other side)

2x=88

x=44

Thank you for your time!

it may be permissible to proceed with a hypothesis test even if the assumption of random participant selection is violated, under the conditions of known and accounted for non-random selection or random assignment to treatment groups

Random participant selection is an important assumption in hypothesis testing, as it helps ensure the generalizability of the results to the target population. However, in some situations, it may be impractical or impossible to achieve perfect random selection. In such cases, there are a few conditions under which it may still be permissible to proceed with a hypothesis test despite the violation of this assumption:

Non-random selection is known and accounted for: If the non-random selection process is well-documented and understood, researchers can adjust their analysis or statistical methods to account for potential biases introduced by the non-random selection.

Random assignment to treatment groups: Even if participants are not randomly selected, random assignment to different treatment groups can help mitigate the impact of non-random selection. By randomly assigning participants to treatment groups, the effects of non-random selection are distributed evenly across the groups, allowing for valid comparisons and hypothesis testing.

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Answer:

x = 1

Step-by-step explanation:

When there is an equation in absolute form like this |3x - 2| that means that there are no negative numbers or subtraction signs. Instead, such things are reversed, so the simplified equation is

3x + 2 = 5

So then we proceed as normal

3(1) + 2 = 5

3 + 2 = 5

5 = 5

The solution to the inequality is x > -3 or x < -13

The inequality is given as:

9|x + 8| > 45

Divide through  by 5

|x + 8| > 5

Split the inequality

x + 8 > 5 or x + 8 < -5

Solve for x

x > -3 or x < -13

Hence, the solution to the inequality is x > -3 or x < -13

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Answer:

If the account paid a monthly interest instead of annual, the answer would be $162.12

Step-by-step explanation:

Original value is $5350.00

Percentage increase(interest gained) is 1%

Total value after 1st month is equal to the Original Value + The interest

$5350.00 x 0.01 (0.01 = 1/100 = 1%) = $53.50

Do not try and do this altogether as you will get the answer wrong. Instead calculate month by month.

At the end of the first month, he has ($5350.00 + $53.50) = $5403.50

Original Value is $5403.50

Percentage increase(interest gained) is still 1%

Total value after the 2nd month is equal to the Original Value+The interest

$5403.50 x 0.01 = $54.035

ALWAYS round off to the nearest cent before continuing.

At the end of the second month, he has ($5403.50 + $54.04) = $5457.54

Original Value is $5457.54

Percentage increase(interest gained) is 1%

Total value after the 3rd month is equal to the Original Value + The interest

$5457.54 x 0.01 = $54.5754 = $54.58

When rounding off, if the number is 5 or higher, add 1 to the digit before it.

At the end of the third month, he has ($5457.54 + $54.58) = $5512.12

The question asks, how much interest did his money earn. If you calculated like how I did above, picking the interest should be easy.

Simply add, the first month's interest, to the second month's interest, to the third month's interest.

$53.50 + $54.04 + $54.58 =  $162.12

Answer:

p(x) = (x-a)(x-b)(x-7) - a and b can be whatever you want, any real numbers

Step-by-step explanation:

If you plug in 7, you need to multiply the other two numbers by 0, which will result in 0. There are 3 factors since it must be a 3rd degree polynomial

Hope this helps! Please give brainliest!

Answer: D.) 2x + 22 = 50

Step-by-step explanation:

P=2(l+w)

2x+22=50 is correct because

2 times x is 2 times the unknown length

11 times 2 is 22 so, you add that to the 2x

50 is the perimeter

The length of one side of the square room of Rhett for his movie and music collection is (2x+7) feet.

Area of square is the square of its sides length. It can be given as,

\(A=a^2\)

Here, \(a\) is the length of the side of the square

Rhett decides to build a square room for his movie and music collection. The area of the room is given by the polynomial equation as,

\(A=(4x^2 +28x +49)\rm ft^2\)

Find the factors of the above equation using the split the middle term method as,

\(A=4x^2 +28x +49\\A=4x^2 +14x+14x +49A=x(2x+7)+7(2x+7)\\A=(2x+7)(2x+7)\\A=(2x+7)^2\rm ft^2\)

Compare it with the area of the square we get,

\(a=(2x+7)\rm ft\)

Hence, the length of the square room of Rhett for his movie and music collection is (2x+7) feet.

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Answer:

130=monthly charge

119=one time installation fee

Step-by-step explanation:

119 is the y-intercept and in problems like these, it is always the one time fee. 130 is the monthly payment because it has an x, which could account for the number of months. For example , say six months passed, you could multiply 130 * 6 to get the monthly fee for six months. I hope that makes sense!

The gradient of the function \(\(f\)\) at the point \(\((-1, -3)\)\) is:

\(\[\nabla f(-1, -3) = \left(-3e^{-3} \sin(12), 4e^{-3} \cos(12)\right)\]\)

To find the gradient of the function \(\( f(x, y) = e^{3x} \sin(4y) \)\) at the point \(\((-1, -3)\)\), we need to compute the partial derivatives with respect to \(\(x\) and \(y\)\) and evaluate them at that point.

The gradient of a function is given by:

\(\[\nabla f(x, y) = \left(\frac{{\partial f}}{{\partial x}}, \frac{{\partial f}}{{\partial y}}\right)\]\)

Let's calculate the partial derivatives:

\(\[\frac{{\partial f}}{{\partial x}} = \frac{{\partial}}{{\partial x}}\left(e^{3x} \sin(4y)\right) = 3e^{3x} \sin(4y)\]\)

\(\[\frac{{\partial f}}{{\partial y}} = \frac{{\partial}}{{\partial y}}\left(e^{3x} \sin(4y)\right) = 4e^{3x} \cos(4y)\]\)

Now, we can evaluate these derivatives at the point \(\((-1, -3)\):\)

\(\[\frac{{\partial f}}{{\partial x}}\Bigr|_{(-1, -3)} = 3e^{3(-1)} \sin(4(-3)) = 3e^{-3} \sin(-12)\]\)

\(\[\frac{{\partial f}}{{\partial y}}\Bigr|_{(-1, -3)} = 4e^{3(-1)} \cos(4(-3)) = 4e^{-3} \cos(-12)\]\)

Simplifying further:

\(\[\frac{{\partial f}}{{\partial x}}\Bigr|_{(-1, -3)} = 3e^{-3} \sin(-12) = -3e^{-3} \sin(12)\]\)

\(\[\frac{{\partial f}}{{\partial y}}\Bigr|_{(-1, -3)} = 4e^{-3} \cos(-12) = 4e^{-3} \cos(12)\]\)

Therefore, the gradient of the function \(\(f\)\) at the point \(\((-1, -3)\)\) is:

\(\[\nabla f(-1, -3) = \left(-3e^{-3} \sin(12), 4e^{-3} \cos(12)\right)\]\)

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When solving the following system of equations,  the x in the first equation would be the easiest to solve for.

Systems of equations can be solved using one of three techniques: graphing, substitution, or elimination. Simply plot the provided equations on a graph and locate the point(s) where they all cross to solve a problem by graphing. You may find the values of the variables you are working for by finding the location of this point.

The result of the first equation is

x + 6y = 25

we can easily solve for x by subtracting 6y from both sides we have  

x + 6y - 6y = 25 - 6y

x - 25 - 6y

So, the first equation's x term can be simply solved.

When solving the following system of equations,  the x in the first equation would be the easiest to solve for.

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Answer:

3

Step-by-step explanation:

3/4 = 0.75

0.75 x 4 = 3

0.75 + 0.75 + 0.75 + 0.75 = 3

Step-by-step explanation:

\( = \frac{3}{4} + \frac{3}{4} + \frac{3}{4} + \frac{3}{4} \\ \)

\( = \frac{3 + 3 + 3 + 3}{4} \\ \)

\( = \frac{12}{4} \\ \)

change into lowest term

\( = \frac{6}{2} \\ \)

\( = \frac{3}{1} \\ \)

hope it helped !!!

If the model is true, there would be around 1689 students sick during the 12th week of classes.

The number of students getting sick was growing exponentially with a growth factor of ‘1.6.

Week 1 : (6)

Week 2 : (10)

Week 3 : (15).

To find the number of students sick on the 12th week of school, we can use the formula for exponential growth:

y = a bˣ

Where:

y is the number of students sick on the x th week

a is the number of students sick on the first week (6 in this case)

b is the growth factor (1.6 in this case)

x is the number of weeks that have passed (12 in this case)

Plugging in the values, we get:

y = 6 · 1.6¹²

Solving for y, we get:

y = 6 · 281.47

y = 1688.8 ≈ 1689

Therefore, there would be approximately 1689 students sick on the 12th week of school if the model is correct.

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Step-by-step explanation:

whatever amount if brown sugar you use is the same amount if sugar you use. so if you use 1/2cup of brown sugar you use 1/2cup of sugar. sorry can't see the number you have written before the word cup

V+W and V+2W are linearly independent. To prove that V+W and V+2W form a basis for V, we need to show two things:

1. V+W and V+2W span V.

2. V+W and V+2W are linearly independent.

To show that V+W and V+2W span V, we need to demonstrate that any vector v in V can be expressed as a linear combination of vectors in V+W and V+2W.

Let's take an arbitrary vector v in V. Since V and W form a basis for V, we can write v as a linear combination of vectors in V and W:

v = aV + bW, where a and b are scalars.

Now, we can rewrite this expression using V+W and V+2W:

v = a(V+W) + (b/2)(V+2W).

We have expressed v as a linear combination of vectors in V+W and V+2W. Therefore, V+W and V+2W span V.

To show that V+W and V+2W are linearly independent, we need to demonstrate that the only solution to the equation c(V+W) + d(V+2W) = 0, where c and d are scalars, is c = d = 0.

Expanding the equation, we get:

(c+d)V + (c+2d)W = 0.

Since V and W are linearly independent, the coefficients (c+d) and (c+2d) must be zero. Solving these equations, we find c = d = 0.

Therefore, V+W and V+2W are linearly independent.

Since V+W and V+2W both span V and are linearly independent, they form a basis for V.

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The distance between the buildings is approximately 49.76 meters.

To find the distance between the buildings, we can use the Law of Cosines. Let's denote the distance between the buildings as "d." We have one side of the triangle as 20 meters, another side as 25 meters, and the angle between these sides as 40 degrees.

Using the Law of Cosines: d² = 20² + 25² - 2(20)(25)cos(40°)

Calculating this equation gives us d² = 400 + 625 - 1000cos(40°)

Using a calculator, we find that cos(40°) ≈ 0.766

Substituting the values, we get d² = 400 + 625 - 1000(0.766)

Simplifying, we get d² ≈ 49.76

Taking the square root, we find that d ≈ 7.06 meters.

Therefore, the distance between the buildings is approximately 7.06 meters, which is not one of the given answer choices.

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The nth term of the sequence is aₙ = 26 - 4n.

A sequence is defined as an arrangement of numbers in a particular order.

The sequence is an arithmetic sequence. Therefore, the nth term of the sequence can be found as follows:

aₙ = a + (n - 1)d

where

Therefore,

a = 22

d = 18 - 22 = -4

n = number of terms

Hence,

aₙ = 22 + (n - 1)-4

aₙ = 22  - 4n + 4

aₙ = 22 + 4 - 4n

aₙ = 26 - 4n

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Answer:

0.44444444444

Step-by-step explanation:

The original recurrence relation T(n) = T(n - 1) + n into a closed-form expression T(n) = T(n - 1) + n(n + 1)/2.

Recurrence relations are mathematical equations that define a sequence based on its previous terms. Solving recurrence relations is an important topic in computer science and mathematics. One technique used to solve such recurrences is called unrolling. In this explanation, we will use the unrolling technique to solve the given recurrence relation.

To solve the recurrence relation T(n) = T(n - 1) + n, with T(1) = 0, we will apply the unrolling technique. Unrolling involves expanding the recurrence relation by repeatedly substituting the recurrence equation into itself until we reach a base case.

Let's start by expanding the recurrence relation for a few terms:

T(n) = T(n - 1) + n

      = T(n - 2) + (n - 1) + n

      = T(n - 3) + (n - 2) + (n - 1) + n

We can observe a pattern here. Each time we expand the recurrence, we add the next term in the sequence, starting from n and going down to 1.

Continuing this process, we can express T(n) as the sum of all the terms from n to 1:

T(n) = T(n - 1) + T(n - 2) + T(n - 3) + ... + T(2) + T(1) + n + (n - 1) + (n - 2) + ... + 2 + 1

We can simplify this expression by grouping the terms:

T(n) = [T(n - 1) + T(n - 2) + T(n - 3) + ... + T(2) + T(1)] + [n + (n - 1) + (n - 2) + ... + 2 + 1]

The first part in square brackets represents the sum of the previous terms in the recurrence relation, which we denote as S(n-1):

T(n) = S(n - 1) + [n + (n - 1) + (n - 2) + ... + 2 + 1]

The second part in square brackets represents the sum of the integers from 1 to n, which is a well-known formula and can be written as n(n + 1)/2:

T(n) = S(n - 1) + n(n + 1)/2

Now, we need to find a closed-form expression for S(n-1). To do that, we can apply the same unrolling technique to the sum of the previous terms:

S(n - 1) = S(n - 2) + S(n - 3) + ... + S(2) + S(1)

We can notice that S(n-1) is essentially the same recurrence relation as T(n), but with a different initial condition. Therefore, we can rewrite S(n-1) as T(n-1) with a new initial condition:

S(n - 1) = T(n - 1) - T(1)

Substituting this back into the expression for T(n), we get:

T(n) = T(n - 1) - T(1) + n(n + 1)/2

We know that T(1) = 0, so we can simplify further:

T(n) = T(n - 1) + n(n + 1)/2

This is the final closed-form expression for the given recurrence relation. To calculate the value of T(n), you can either use this formula directly or implement it recursively or iteratively in a programming language.

Using the unrolling technique, we have transformed the original recurrence relation T(n) = T(n - 1) + n into a closed-form expression T(n) = T(n - 1) + n(n + 1)/2, which provides a more direct way to calculate the value of T(n) for any given n.

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Answer:

116 remainder 1

116 1/3

116.333

Step-by-step explanation:

Answer:

116 with a remainder of 1

Step-by-step explanation:

Picture below shows step by step work

Hopefully this helps!

Brainliest please?

For different types of triangle, The circumcenter has different properties. The properties varies for acute, obtuse and right angle triangles.

A polygon with three edges and three vertices is called a triangle. It is one of the fundamental geometric shapes.

The spot where the three perpendicular bisectors of a triangle's sides meet and which is equally spaced from the triangle's three vertices.

Properties of circumcenter of triangle are:

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