tickets for a cinema costs £4 and £5. There were 223 customers who paid a total of £936. How many bought £4 tickets
The number of people who bought £4 tickets are 139.
How to illustrate the equation?Let £4 tickets be x
Let £5 tickets be y.
Therefore based on the information given, this will be:
x + y = 223 ..... i
4x + 5y = 936 ..... ii
From equation i
x = 213 - y
Put this into equation ii
4x + 5y = 936
4(213 - y) + 5y = 936
852 - 4y + 5y = 936
Collect like terms
y = 84
This implies that the number of £5 tickets is 84.
Recall that x + y = 223
x + 84 = 223
x = 223 - 84
x = 139
The number of £4 tickets is 139
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4 3 ​ (2 3 4 2 )=start fraction, 3, divided by, 4, end fraction, left parenthesis, 2, cubed, plus, 4, squared, right parenthesis, equals
Using PEMDAS rule , we can evaluate the provide expression . The required result is thirteen that's the value is L= 13.
PEMDAS order of operations: The order of operations is a rule that tells the correct sequence of steps for evaluating a given mathematical expression. We can remember the order using "PEMDAS" where
P --> Parentheses
E --> Exponents (2⁵ is 2 raised to the power of 5)
M------> Multiplication and
D---->Division (from left to right)
A--->Addition
S--->Subtraction (from left to right).
We have given that
3/4 ( 2³ + 4² )
let given expresion equal to L i.e
L = 3/4 ( 2³ + 4² )
Now, we have to solve it
Using "PEMDAS" rule ,
L = 3/4 ( 2³ + 4²)
= 3/4 ( 8 + 4²)
= 3/4 ( 8 + 16 )
= 3/4 ( 24)
= 3/4 ×24
= 24×3/4
= 72/4
L = 1 3
Hence, the given expresion is equal to 13 .
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A hypothesis test is to be performed for a population mean. Which of the following does the probability of a type II error not depend on?
options:
The significance level
The sample mean
The sample size
The true (population) mean
When a thesis test is being performed for a population mean, the probability of a type II error isn't dependent on the sample mean. Option B is the right answer.
A type II error occurs when a null thesis isn't rejected despite it being incorrect. It's worth noting that the threat of making a type II error is affected by several factors, including the sample size, the true population mean, the position of significance, and the variability of the data.
As a result, the larger the sample size, the lower the threat of making a type IIerror.The true population mean also has an impact on the liability of a type II error. As the difference between the true mean and the hypothecated mean grows, the threat of a type II error decreases.
The position of significance is also pivotal in determining the threat of a type II error. As the significance position increases, the threat of a type II error decreases.
So, the correct answer is B
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Addison prepares 9 cups of salsa her cookout. she divided it into 1/4 of cup servings how many servings are available.A (12 servings) B (14 servings) C (15 servings) D ( 36 servings)
Answer:
The answer is D or 36
Step-by-step explanation:
Divide the cups by servings
9/.25=36
Choose the polynomial that is in Standard Form : a) x^3-11x^2 b)2+3x+4x^2+3x^3 c)-3x+17x^4+2x^2 d)-1+3x+2x^2
a
b
c
d
Answer:
the answer would be a x^3-11x^2
Step-by-step explanation:
PLEASE HELP VERY URGENT WILL GIVE BRAINILY PLEASE I BEG YOU PLEASE
Answer: 20.5 units
Step-by-step explanation:
P=Perimeter
JI=3-(-3)
JI=3+3
JI=6
IK=7-1
IK=6
JK=(6^2+6^2)^1/2 ==> Distance Formula
JK=(36+36)^1/2
JK=(2*36)^1/2
JK=6(2)^1/2
P=JI+IK+JK
P=6+6+6(2)^1/2
P=12+6(2)^1/2
P=20.485 units
P=20.5 units
4. (4x3+3x+5) (2x +1)
Answer:
Work shown below!
Step-by-step explanation:
\((4x^{3}+3x+5)(2x+1)=8x^{4}+4x^{3}+6x^{2} +3x+10x+5= 8x^{4}+4x^{3}+6x^{2}+13x+5\)
If D is the midpoint of AB and AB = 15, what is AD?
7.5
15
22.5
30
Answer:
AD=7.5
Step-by-step explanation:
If AB=15 and D is the midpoint that means AD=DB which is half of AD,
AD=AB/2
AD=15/2
therefore AD=7.5
Five boxes of crakers cost 9 at the rate how much do 20 boxes cost
Answer:
36 dollars
Step-by-step explanation:
We can use ratios to solve
5 boxes 20 boxes
------------------ = ---------------
9 dollars x dollars
Using cross products
5x = 20*9
Divide each side by 5
5x/5 = 90*9/5
x = 36
What is the total vertical distance (both up and down) traveled by the ball when it stops bouncing? (hint: add the total distance the ball falls to the total distance it rises.)
The total vertical distance traveled by the ball when it stops bouncing is twice the sum of the distances it falls during each bounce.
The total vertical distance traveled by the ball when it stops bouncing is equal to the sum of the distance it falls and the distance it rises.
When a ball bounces, it follows a pattern where it falls vertically downward and then rebounds vertically upward, reaching a slightly lower height with each bounce until it eventually comes to a stop.
To calculate the total vertical distance traveled by the ball, we need to consider both the downward and upward movements during each bounce.
Let's assume that the ball is dropped from a certain height and bounces a total of "n" times before coming to rest.
During the first bounce, the ball falls a certain distance downward. On the subsequent bounce, it rises to a slightly lower height than the previous bounce and then falls again. This pattern repeats for each subsequent bounce until the ball eventually stops bouncing.
To find the total vertical distance traveled, we need to add up the distances traveled during each downward and upward movement for all "n" bounces.
Mathematically, the total vertical distance traveled by the ball can be expressed as:
Total Distance = Distance of First Fall + Distance of First Rise + Distance of Second Fall + Distance of Second Rise + ... + Distance of nth Fall + Distance of nth Rise
Since each downward and upward movement is equal in magnitude, we can simplify the equation:
Total Distance = 2 × (Distance of First Fall + Distance of Second Fall + ... + Distance of nth Fall)
Therefore, the total vertical distance traveled by the ball when it stops bouncing is twice the sum of the distances it falls during each bounce.
By calculating the sum of the distances the ball falls during each bounce and multiplying it by 2, we can determine the total vertical distance traveled by the ball.
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2 Which ratios are equivalent to 8:12? Select all that apply.
A 4:6
B 12:8
C 16:20
D 24:36
E 56:84
Answer:The ratios are equivalent to 8 : 12 are A 4 : 6 , D 24 : 36 and E 56 : 84.Those expressions who might look different but their simplified forms are same expressions are called equivalent expressions.What is the ratio of two quantities?Suppose that we've got two quantities with measurements as 'a' and 'b'Then, their ratio(ratio of a to b) a:bWe usually cancel out the common factors from both the numerator and the denominator of the fraction we obtained. Numerator is the upper quantity in the fraction and denominator is the lower quantity in the fraction).Suppose that we've got a = 8, and b= 12, So, the ratios are equivalent to 8 : 12A 4 : 6D 24 : 36E 56 : 84
Step-by-step explanation:
carry on learning
necesito resolver: 5+2(2x)^-1/2
Answer:
5+(2/x)^1/2 This is the correct answer!!
Step-by-step explanation:
Luis has an account at GESA Credit Union. He had a balance of $500.00 starting January 15th. He made deposits of $100, $250, and $300. He also made withdrawals of $400.32, $100, $55.55, and $62.62. What would be his ending balance after all the transactions?
SHOW THE WORK PLEASE
Answer:
the ending balance is $531.51
Step-by-step explanation:
The computation of the ending balance is shown below:
= Opening balance + all deposits - all withdrawls
= $500 + $100 + $250 + $300 - $400.32 - $100 - $55.55 - $62.62
= $531.51
hence, the ending balance is $531.51
1- In Euclidean space, the locus of points equidistant from the origin of a plane is a circle What is the locus of points equidistant (in the spacetime distance seme) from the origin of a spacetime plane? 151 2. A ruler of length L. In at rest in with its left and at the origin. O moves from left to right with speed relative to o along the length of the ruler. The two origins coincide ut time zero for both, at which time a photon is emitted toward the other end of the rulut. What are the coordinates in Olof the event at which the photon maches the other end? (10) 3. The Earth and Alpha Centauri are 43 light years apart. Ignore their relative motion Events A and B occur att on Earth and at 1 year on Alpha Centauri, respectively. (a) What is the time difference between the events according to an observer moving at B - 0.98 from Earth to Alpha Centauri? (b) What is the time difference between the events according to an observer moving at 3 = 0.98 from Alpha Centauri to Earth? (c) What is the speed of a spacecraft that makes the trip from Alpha Centauri to Earth in 2.5 years according to the spacecraft clocks? (d) What is the trip time in the Earth rest frame? [5+5+5+51 + Plane polar coordinates are related to cartesian coordinates by x=rcos and y = rsin. Describe the transformation matrix that maps cartesian coordinates to polar coordinates, and write down the polar coordinate basis vectors in terms of the basis vectors of cartesian coordinates. [51 5- suppose that we are given a basis ei, es consisting of a pair of vectors making a 45° angle with one another, such that ei hus length 2 and ez has length 1. Find the dual basis vectors for the case of covariant components of the vectors. [101
1. In the context of spacetime, the locus of points equidistant from the origin of a spacetime plane is a hyperbola.
In Euclidean space, the distance between two points is given by the Pythagorean theorem, which only considers spatial dimensions. However, in spacetime, the concept of distance is extended to include both spatial and temporal components. The spacetime distance, also known as the interval, is given by the Minkowski metric:
ds^2 = -c^2*dt^2 + dx^2 + dy^2 + dz^2,
where c is the speed of light, dt represents the temporal component, and dx, dy, dz represent the spatial components.
To determine the locus of points equidistant from the origin, we need to find the set of points where the spacetime interval from the origin is constant. Setting ds^2 equal to a constant value, say k^2, we have:
-c^2*dt^2 + dx^2 + dy^2 + dz^2 = k^2.
If we focus on a spacetime plane where dy = dz = 0, the equation simplifies to:
-c^2*dt^2 + dx^2 = k^2.
This equation represents a hyperbola in the spacetime plane. It differs from a circle in Euclidean space due to the presence of the negative sign in front of the temporal component, which introduces a difference in the geometry.
Therefore, the locus of points equidistant from the origin in a spacetime plane is a hyperbola.
(Note: The explanation provided assumes a flat spacetime geometry described by the Minkowski metric. In the case of a curved spacetime, such as that described by general relativity, the shape of the locus of equidistant points would be more complex and depend on the specific curvature of spacetime.)
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Simplify the expression:
(6x - 3) + (5x + 7) and if u can show steps
Step-by-step explanation:
Let's simplify step-by-step.
6x−3+5x+7
=6x+−3+5x+7
Combine Like Terms:
=6x+−3+5x+7
=(6x+5x)+(−3+7)
=11x+4
Answer:
11x + 4
Step-by-step explanation:
hope this helps!!!
Which of the following properly describe
"slope"? Select all that apply.
0
A)
ratio of the change in y-values
(rise) for a segment of the graph to
the corresponding change in x-
values (run)
OB) x₂-x₂
y₂-M1
C) ₂-₁
x₂-x₂
D) run/rise
☐ E) rise/run
4-1/2-1-3
What is the answer
Can the volume of a cone with the same size base as a cylinder ever have a bigger volume? Explain
Answer:
No, because if a cone and a cylinder have bases with equal areas, and both have identical heights, then the volume of the cone is one-third the volume of the cylinder.
3- Resolvé los siguientes cálculos. A- (-2)³+10= b- 21-4²= c- -5²+31= d- (-3)³+5²= e- 10²-9²= f- (-2)⁴-4²= g- (-7+2)²-10²= h- -8²+(6-9)⁴=
Answer:
A. 2
B. 5
C. 6
D. 16
E. 19
F. - 32
G. - 125
H. 17
Step-by-step explanation:
A.
\((-2)^{3}+10\\\\=- 8 + 10\\\\=2\)
B.
\(21 - 4^{2}\\\\=21-16\\\\=5\)
C.
\(-5^{2}+31\\\\=-25 + 31\\\\=6\)
D.
\(-(3)^{2}+5^2\\\\=-9 + 25 \\\\=16\)
E.
\(10^{2}-9^{2}\\\\=100 -81\\\\=19\)
F.
\(-(-2)^{4}-4^2\\\\=-16-16\\\\=-32\)
G.
\(-(-7+2)^{2}-10^2\\\\=-25-100\\\\=-125\)
H.
\(-8^{2}+(6-9)^4\\\\=-64+81\\\\=17\)
write 1875/100 in its lowest terms
Answer:
hii
Step-by-step explanation:
18.75 answer
is
correct
The equation c= 20t + 6 represents the cost c in dollars and theme park entrance tickets t. Determine whether there is a proportional relationship between c and t. Explain or show your reasoning.
'c' and 't' are not in a proportional relationship.
Given,
Equation c=20t+6.
Proportional relationship can be determined for different values of 'c' and 't', if there ratio between 'c' and 't' is same for different values
For t=1,
c=20(1)+6=26
Ratio of c:t = 26:1
For t=2.
c=20(2)+6=46
Ratio of c:t = 46:2 = 23:1
For t=3
c=20(3)+6=60+6=66
Ratio of c:t = 66:3 = 22:1
As the ratios are different for different values for c and t.
Hence, it is clear that 'c' and 't' are not in a proportional relationship.
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Please help. Look at the triangle below.
Answer:
See below.
Step-by-step explanation:
Side BC is adjacent to <B and is 11 units long.
Side BA is the hypotenuse and is x units long.
what is the square root of 96 in simplest form
Answer:
Probably the easiest number to factor out is 2 since 96 is an even number. 96/2 = 48.
Step-by-step explanation:
what is 2.161616 as a fraction and as a mixed number
Answer:
see explanation
Step-by-step explanation:
We require to create 2 equations with the repeating value placed after the decimal point.
let x = 2.1616...... → (1) Multiply both sides by 100
100x = 216.1616..... → (2)
Subtract (1) from (2) to eliminate the repeating decimal.
99x = 214 ( divide both sides by 99 )
x = \(\frac{214}{99}\) = 2 \(\frac{16}{99}\) as a mixed number
Thus
2.1616...... = \(\frac{214}{99}\) = 2 \(\frac{16}{99}\)
50 points and brainless
1. In a board game, you must roll two 6-sided number cubes. You can only start the game if you roll a 3 on at least one of the number cubes.
(a) Make a list of all the different possible outcomes when two number cubes are rolled.
(b) What fraction of the possible outcomes is favorable?
(c) Suppose you rolled the two number cubes 100 times, would you expect at least one 3 more or less than 34 times? Explain. Answer:
Answer:
The answer for (a) is
1, 1 2, 2 3, 3 4, 4 5, 5 6, 6
1, 2 2, 3 3, 4 4, 5 5, 6
1, 3 2, 4 3, 5 4, 6
1, 4 2, 5 3, 6
1, 5 2, 6
1, 6
The answer for (b) is 6/21 or 0.285714286
The answer for (c) is Less than. {its in the explanation}
===================================================================
Explanation:
(a)- Its not really hard, it just takes a bit of time.
(b)- The total number of possibilities is 21. Favorable outcomes would have a 3 as one of the dice, and only 6 of the 21 outcomes has a 3. (they are in bold)
There are only 21 possible outcomes because the prompt says "Make a list of all the different possible outcomes." For example: I have 3, 4 as an outcome, but not 4, 3 because that would be the same outcome.
(c)- Less than, because the possibility of getting an outcome with at least one 3 is only 0.285714286. If you multiply that by 100, thats only 28.5714286, or 29, still less than 34.
Shelby and her classmates placed colored blocks on a scale during a science lab. The green block weighed 9.2 pounds and the orange block weighed 0.34 pounds. How much more did the green block weigh than the orange block?
What is the value of the expression x² + y² given x = 10 and y = 2?
A. 104
B. -98
C. 89
D. -89
Answer:
A. 104Step-by-step explanation:
- 8 = 6(x - 4) What is the slope of the line described by the equation?
Answer:
the slope is undefined
Step-by-step explanation:
Write an equation in point-slope form of the line that has a slope of -3 and passes through the
point (4,-5)
A family pass to the amusement park costs $54. Using Distributive Property, write an expression that can be used to find the cost in dollars of 8 family passes. (I'm actu
The cost of 8 family passes to the amusement park is $432 when a family pass to the amusement park costs $54.
To find the cost of 8 family passes to the amusement park, we can use the Distributive Property of multiplication over addition. The Distributive Property states that a(b + c) = ab + ac, where a, b, and c are numbers. In this case, we can use the Distributive Property to write:
8 x $54 = (5 x $54) + (3 x $54)
We can see that we have broken 8 down into two smaller numbers that we can multiply by $54 individually, and then add together. The first term, 5 x $54, represents the cost of 5 family passes, while the second term, 3 x $54, represents the cost of 3 family passes. Adding these two values together, we get:
(5 x $54) + (3 x $54) = $270 + $162 = $432
Therefore, the cost of 8 family passes to the amusement park is $432.
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