pls what is the difference between Ac power and dc power​

Answer:  Therefore, the change in entropy when 536 g of gold are melted is 0.132 J/K.

Explanation:  To calculate the change in entropy when 536 g of gold are melted, we need to know the entropy of fusion of gold and the temperature at which it melts.

The entropy of fusion of gold is 2.35 J/g·K, and the melting point of gold is 1064 °C or 1337 K.

The change in entropy when gold is melted can be calculated using the formula:

ΔS = Q/T

where ΔS is the change in entropy, Q is the heat absorbed during the process, and T is the temperature at which the process occurs.

The heat absorbed when gold is melted can be calculated using the formula:

Q = m × ΔH_fus

where m is the mass of the gold and ΔH_fus is the enthalpy of fusion of gold, which is 64.9 kJ/mol.

Converting the mass of gold to moles:

536 g / 196.97 g/mol = 2.72 mol

The heat absorbed by the gold when it is melted is:

Q = 2.72 mol × 64.9 kJ/mol = 176.2 kJ

Finally, we can calculate the change in entropy:

ΔS = Q/T = 176.2 kJ / 1337 K = 0.132 J/K

Answer:

Explanation:

We can calculate the change in the man's center of gravity by considering the initial and final positions of the center of gravity of his arms.

Assuming the man's arms are initially hanging down by his sides, the center of gravity of his arms is located at the midpoint of the cylinder, which is at a distance of L/2 = 79/2 = 39.5 cm from the shoulder joint.

When the man raises his arms straight up, the center of gravity of his arms is located at the top of the cylinder, which is at a distance of L = 79 cm from the shoulder joint.

The change in the man's center of gravity is therefore:

Δh = h_final - h_initial

= L - L/2

= 79 cm - 39.5 cm

= 39.5 cm

Therefore, the man raises his center of gravity by 39.5 cm when he raises both his arms from hanging down to straight up.

(a) As the crate picks up speed, it friction f with the ground will increase until it equals the pull P.

(b) Constant velocity means acceleration is zero.

(c) The net force on the crate will be zero since the acceleration is zero.

Constant acceleration is defined as a change in velocity that does not vary over time.

During a constant acceleration, the change in velocity with time is constant.

For a constant velocity, that is when the change in velocity is zero, the acceleration of the object is zero.

For the friction question;

As the crate picks up speed, it friction f with the ground will increase until it equals the pull P.

Constant velocity means acceleration is zero.

The net force on the crate will be zero since the acceleration is zero.

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Answer:

The correct answer would have to be

C. Mass of the ball

Answer:

D is the answer  I think (0 w 0 )

Explanation:

The  glaciers move gradually. Hence, option (C) is correct.

A glacier is a long-lasting mass of heavy ice that is perpetually moving. When the ablation of snow is greater than the accumulation over a long period of time, frequently centuries, a glacier forms.

As it slowly flows and deforms under forces brought on by its weight, it gains distinctive features like crevasses and seracs. Cirques, moraines, and fjords are the result of the erosion of rock and debris from its substrate as it travels.

The considerably thinner sea ice and lake ice that form on the surface of bodies of water are not the same as glaciers, which form only on land and may flow into water bodies.

The huge ice sheets, commonly referred to as "continental glaciers," in the polar areas of the planet contain 99 percent of the planet's glacial ice.

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The magnitude of force F₂ is determined as 0.38 N.

The magnitude of force (F₂) is calculated by applying Newton's second law of motion as follows;

F = ma

where;

The resultant forces in the x-direction is given as

F₁cosθ₁  +  F₂cosθ₂ = maₓ

(1.5 cos35) + F₂(cos45) = 1.5 x 1

1.23 + 0.71F₂ = 1.5

0.71F₂ = 1.5 - 1.23

0.71F₂ = 0.27

F₂ = 0.27/0.71

F₂ = 0.38 N

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Answer:90

Explanation: bc i looked it up

Answer:

i don'tkniw

Explanation: ido not know

Answer:

As light waves transmit from one medium to another medium ( of different optical densities ), the speed of the light wave changes. When speed changes the direction of the wave changes hence refracted.

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The power used by the dryer to spin the drum and produce heat is 11000 Watts.

Power is simply the quantity of energy transferred per unit time.

This is expressed as;

P = v × I

Where v is voltage and I is current.

Given that;

Plug the given values into the above formula and solve for P.

P = v × I

P = 220V × 50A

P = 11000 Watts

Therefore, the power used by the dry is 11000 Watts.

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Answer:

the correct answer is up and down

The total initial mechanical energy is 590,650 J.

Work done on the projectile is 155,436 J.

Speed of the projectile is 115.4 m/s.

(a) The initial total mechanical energy of the system of the projectile and the earth can be found using the equation:

E = KE + PE

where E is the total mechanical energy, KE is the kinetic energy, and PE is the potential energy. Initially, the projectile is at a height of 116 m, so the potential energy is:

PE = mgh

PE = (54.0 kg)(9.81 m/s²)(116 m)

PE = 61,450 J

The initial speed of the projectile is 1.40 x 10² m/s, so the initial kinetic energy is:

KE = (1/2)mv²

KE = (1/2)(54.0 kg)(1.40 x 10² m/s)²

KE = 529,200 J

Therefore, the initial total mechanical energy is:

E = KE + PE

E = 529,200 J + 61,450 J

E = 590,650 J

The initial total mechanical energy of the system of the projectile and the earth is 63,014 J.

(b) At the maximum height, the potential energy of the projectile is:

PE = mgy

PE = (54.0 kg)(9.81 m/s²)(320 m)

PE = 169,517 J

At the maximum height, the kinetic energy of the projectile is:

KE = (1/2)mv²

KE = (1/2)(54.0 kg)(99.2 m/s)²

KE = 265,697 J

The total mechanical energy of the projectile at the maximum height is:

E = KE + PE

E = 169,517 J + 265,697 J

E = 435,214 J

The work done by air resistance is the difference between the initial total mechanical energy and the total mechanical energy at the maximum height:

W = Ei - Ef

W = 590,650 J - 435,214 J

W = 155,436 J

The amount of work done on the projectile by air resistance is 155,436 J.

(c) Let Wup be the work done by air resistance when the projectile is going up, and let Wdown be the work done by air resistance when the projectile is going down. According to the problem, Wdown = (3/2)Wup. Use the principle of conservation of energy to relate the speed of the projectile at its maximum height to its speed just before hitting the ground:

Ef = Ei

KEf + PEf = KEi + PEi

At the maximum height, the kinetic energy of the projectile is zero, so:

PEf = Ei - PEi

PEf = 590,650 J - (54.0 kg)(9.81 m/s²)(320 m)

PEf = 421,133 J

The total mechanical energy just before hitting the ground is the same as the total mechanical energy at the maximum height, so:

KEf + PEf = KEi + PEi

0 + 421,133 J = (1/2)mv² + 61,450 J

(1/2)(54.0 kg)v² = 359,683 J

v² = 13,321.59

v = 115.4 m/s

Therefore, the speed of the projectile immediately before it hits the ground is 115.4 m/s.

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Answer:

A, Passive Solar.

Explanation:

Answer: Pe=mgh, pe=60*10*10, pe =6000 joules

Explanation:

Answer:

15N at 116.60°

Explanation:

add the forces at an angle greater than 90°

The total energy of all the particles makes up thermal energy. This implies that larger objects with slower-moving particles at low temperatures can have more energy than smaller ones with higher temperatures.

Thermal energy is the sum of the energies of all the particles. This implies that larger objects at low temperatures can have more energy than smaller ones at higher temperatures due to slower-moving particles.

These molecules and atoms move more quickly when something is heated, providing it with more thermal energy. Compared to cold water, hot water has more thermal energy.

Therefore, molecules and atoms in colder objects move more slowly and have less thermal energy than those in warmer ones. The ability of particles to transfer energy increases with speed.

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Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

Answer:

C

Explanation:

Check for coordinates of the VT graph in C part. The information matches with the table.

We can use the following data to get the values of acceleration and the distance covered at top speed:

Maximum speed is 20 m/s (v_max).

Time (t) = 21 seconds

(d) = 270 m is the total distance travelled.

Find the acceleration (A) first:

Applying the equation v = u + at

where an is the acceleration, t is the elapsed time, u is the beginning velocity, and v is the end velocity.

Given: The bus will begin at rest with an initial velocity of 0 metres per second (u).

The formula can be rearranged as follows:

a = (v - u) / t

a = (20 m/s - 0 m/s) / 21 seconds

0.952 m/s2 a = 20 m/s / 21 sec

Therefore, the acceleration of the bus is approximately 0.952 m/s².

Next, let's find the distance traveled at maximum speed (B):

Since the bus starts from rest, it takes time to accelerate to its maximum speed and then decelerate to stop. The distance traveled at maximum speed can be found by subtracting the distances covered during acceleration and deceleration from the total distance.

Distance during acceleration = (1/2) * a * t^2

Distance during deceleration = (1/2) * a * t^2

Distance traveled at maximum speed = Total distance - (Distance during acceleration + Distance during deceleration)

B = d - (0.5 * a * t^2 + 0.5 * a * t^2)

B = 270 m - (0.5 * 0.952 m/s² * (21 sec)^2 + 0.5 * 0.952 m/s² * (21 sec)^2)

B = 270 m - (0.952 m/s² * (21 sec)^2)

B = 270 m - 220.392 m

B ≈ 49.608 m

Therefore, the distance traveled at maximum speed is approximately 49.608 m

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Force = 50N

Weight = Mass × Gravity = 25

Mass = 25 ÷ 10 = 2.5Kg

Time = 5 Seconds

we know

Force = mass × acceleration

50 = 2.5 × Velocity ÷ Time

50÷2.5 = Velocity ÷ 5

Velocity = 250 ÷ 2.5

Velocity = 100m/s.

Answer:

100m/s

Explanation:

force(f) = 50N

weight = 25N

weight = mass × gravity

25 = m × 10

25 = 10m

m = 25/10

m = 2.5kg

time(t) = 5sec

impulse formula

ft = m(∆v)

by substituting

50 × 5 = 2.5∆v

250 = 2.5∆v

∆v = 250/2.5

∆v = 100m/s

i hope this helped

Continents with high mountains might obstruct the flow of the polar jet stream. Moving continents could disrupt ocean currents, which help drive air movement.

The presence of high mountains on a continent can affect the flow of air currents, including the polar jet stream. The mountains can cause the air to rise, creating areas of high pressure, which can deflect or slow down the flow of the jet stream.

Changes in ocean currents caused by the movement of continents can also have an effect on the polar jet stream. Ocean currents help to regulate the temperature of the Earth's surface, which can in turn impact the temperature and flow of air currents, including the polar jet stream.

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A combination of colloids, clay, silt, sand, pebbles, and cobbles is positioned into the move I at factor A. The water choice B) stream II will pass all debris that might be added at point A.

Circulation speed is the velocity of the water inside the flow. units are distance in step with time (e.g., meters in keeping with second or feet in keeping with second). movement speed is best in midstream close to the surface and is slowest alongside the movement mattress and banks due to friction.

Larger particles are much more likely to fall through the upward currents to the lowest, until the flow price increases, growing the turbulence on the streambed. in addition, suspended sediment will no longer always remain suspended if the drift charge slows.

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Answer:

Efficiency = 65%

Explanation:

The formula of Efficiency applied to any circumstance is:

Efficiency = Useful Energy / Energy applied

Then replacing the values given its:

Efficiency = 25 J / 32 J

Efficiency = 0.65

0.65 written as percentage is 65%, then:

Efficiency = 65%

As you do 32 joules of work using a pair of scissors and the scissors do 25 joules of work cutting a piece of fabric, the efficiency of the scissors is 78.125%.

Efficiency is the proportion of work done by a machine or throughout a process to the overall amount of energy or heat used.

The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.

Mathematically,

efficiency of a machine = (work output/work input)×100%

Given parameters:

Input work to the pair of scissors= 32 joules.

Output work from the pair of scissors= 25 joules.

Hence,

The efficiency of a machine = (work output/work input)×100%

= ( 25 joule/32joule)×100%

= 78.125%

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Since Taylor has set this fitness goal: I will go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. The option that MOST likely TRUE about this goal is option A:It is a short-term goal.

A short-term goal is a goal that can be achieved within a relatively short period of time, usually less than a year. In this case, the goal is to go to the YMCA and lift weights for 30 minutes every other day for the entire month of January.

In this case, Taylor's goal is to go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. This goal is specific, as it clearly states what Taylor wants to accomplish, and it is measurable.

This goal can be achieved within the month of January and it's a specific, measurable and time-bound goal, which are characteristics of short-term goals.

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See full question below

Taylor has set this fitness goal: I will go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. What is MOST likely TRUE about this goal?

It is a short-term goal.

It is a long-term goal.

It is an unrealistic goal.

It is a mental health goal.

Answer:it’s a short-term goal

Explanation:

because it’s only for the month of January she will be doing this goal.

The energy released when 10 g of steam is spilled on the hand is approximately 25 kJ

The heat required to raise the temperature of 10 g of water from 33 °C to 100 °C is

Q₁ = m x c x ΔT

= 10 g * 4.2 * (100 °C - 33 °C)

= 2772 J

The heat required to vaporize 10 g of water at 100 °C is given by:

Q₂ = m x L

= 10 * 2.2

= 22,000 J

where L is the specific latent heat of vaporization of water

The total energy released

Q = Q1 + Q2

= 2772 J + 22,000 J

= 24,772 J

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Answer:

C

Explanation:

I think it C because I learnt about it in geography and my teacher approves. Maybe

In order to calculate the energy needed, we can use the formula below:

Where Q is the heat needed (in Joules), m is the mass, c is the specific heat and DeltaT is the change of temperature.

So, using the given information, we have:

Therefore the energy needed is 989325.94 Joules.