PLSS HELP I GIVE BRAINLIEST

The saturated vapor pressure of methanol in the vessel is 125.9 mmHg (rounded off to 3 significant figures). The volume percent concentration of methanol in the vapor is 73.2% (rounded off to 3 significant figures).

a. Saturated vapor pressure of methanol in the vessel in mmHg: The vapor pressure of methanol (MeOH) in the vessel can be determined using Dalton's law of partial pressures. MetOH psat = MetOH Pabs

Here, MetOH Pabs is the pressure exerted by the vapor of methanol in the vessel. It is equal to the total pressure in the vessel minus the partial pressure of the inert gas (nitrogen). Pabs = 2 inch of water gauge = 2 x 25.4 mm of water gauge / 1 inch of water gauge = 50.8 mm of water gauge

Total pressure in mmHg = Pabs x 760 mmHg / 406.8 inch of water gauge = 94.8 mmHg

Partial pressure of nitrogen = 2 inch of water gauge = 50.8 mm of water gauge

Partial pressure of methanol = MetOH Pabs MetOH psat = 126 mmHg (at 25°C)

Therefore, the saturated vapor pressure of methanol in the vessel is 125.9 mmHg (rounded off to 3 significant figures).

b. Volume percent concentration of methanol in the vapor: The volume percent concentration of methanol in the vapor can be determined using the ideal gas law and the Dalton's law of partial pressures. V = nRT / PV = volume of the vapor (L)n = number of moles of methanol gas R = gas constant T = temperature (K)P = pressure (atm)

Let's assume that the total volume of the vapor in the vessel is 1 L and the temperature is 25°C (298 K).

The number of moles of nitrogen gas (N2) in the vapor can be determined using the Dalton's law of partial pressures. N2 Pabs = Pabs - MetOH PabsN2 Pabs = 50.8 mm of water gaugeN2 Pabs = 50.8 mm of water gauge x 1 atm / 760 mmHg = 0.067 atmN2 V = nRT / PN2N2 V = (0.067 atm x 1 L) / (0.082 L atm/K mol x 298 K)N2 V = 0.0022 mol

The number of moles of methanol gas (MeOH) in the vapor can be determined using the ideal gas law. MetOH Pabs = MetOH psatMetOH Pabs = 125.9 mm Hg MetOH Pabs = 125.9 mmHg x 1 atm / 760 mmHg = 0.165 atmMetOH V = nRT / PMetOH V = (0.165 atm x 1 L) / (0.082 L atm/K mol x 298 K)MetOH V = 0.006 mol

The volume percent concentration of methanol in the vapor can be determined using the following equation.

Volume percent concentration of MeOH = MetOH V / (N2 V + MetOH V) x 100%

Volume percent concentration of MeOH = 0.006 mol / (0.0022 mol + 0.006 mol) x 100%

Therefore, the volume percent concentration of methanol in the vapor is 73.2% (rounded off to 3 significant figures).

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According to the concept of diffusion the water will move from 5% salt solution to 15%salt solution.

Diffusion is defined as the process of movement of molecules which takes place under concentration gradient. It helps in movement of substances in and out from the cell.The molecules move from lower concentration region to a higher concentration region till the concentration becomes equal.

There are 2 main types of diffusion:

1) simple diffusion-process in which substances move through a semi-permeable membrane without the aid of transport proteins.

2) facilitated diffusion- It is a passive movement of molecules across cell membrane from higher concentration region to lower concentration.

There are 2 types of facilitated diffusion one is osmosis and dialysis.

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Hello. You did not say what is the experiment to which this question refers, which makes it impossible for it to be answered accurately.

However, advice that should be given to anyone who should start an experiment is: establish a control treatment, provide all treatments with the same variables and the same resources, write down everything that happened in the experiment from implementation to data collection and results, make measurements and analyzes on the same date in all treatments and keep the steaks in the same environment.

Answer:

Which Lab are you doing?

Answer: D. negative

Explanation:

The net ionic reaction that occurs upon the addition of HNO₃ to a solution which contains methylamine (CH₃NH₂) and methylammonium chloride (CH₃NH₃Cl) is:

CH₃NH₂+ HNO₃ → CH₃NH₃+ + NO₂₋


When HNO₃ is added to the solution, it reacts with the methylamine to form methylammonium ion (CH₃NH₊) and nitrous oxide (NO₂₋) as the products. This is an acid-base reaction in which HNO₃ acts as an acid and donates a proton (H+) to the lone pair of electrons on the nitrogen atom of methylamine, which acts as a base. The resulting methylammonium ion (CH₃NH₃₊) is positively charged and forms an ionic bond with the negatively charged chloride ion (Cl-) to form methylammonium chloride (CH₃NH₃Cl), which remains in solution.

The net ionic reaction only shows the species that are directly involved in the reaction, and excludes the spectator ions (Cl- and H+) which do not participate in the reaction.

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Upon addition of HNO3 to the solution containing methylamine and methylammonium chloride, a neutralization reaction occurs between H+ ions of HNO3 and the base (CH3NH2) resulting in the formation of CH3NH3+. The net ionic reaction is CH3NH2 + H+ → CH3NH3+.


When HNO3 is added to the solution containing methylamine (CH3NH2) and methylammonium chloride (CH3NH3Cl), a neutralization reaction occurs between the H+ ions of HNO3 and the base (CH3NH2) resulting in the formation of CH3NH3+.
The reaction can be represented as follows:
CH3NH2 + HNO3 → CH3NH3+ + NO3-
However, since methylammonium chloride (CH3NH3Cl) is a salt and dissociates into ions in the solution, we need to write the net ionic reaction.
The net ionic reaction is:
CH3NH2 + H+ → CH3NH3+
This shows that only the CH3NH2 molecule and H+ ion are involved in the reaction to form CH3NH3+.

Summary:
Upon addition of HNO3 to the solution containing methylamine and methylammonium chloride, a neutralization reaction occurs between H+ ions of HNO3 and the base (CH3NH2) resulting in the formation of CH3NH3+. The net ionic reaction is CH3NH2 + H+ → CH3NH3+.

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Answer:

B

Explanation:

It is a gas and therefore according to particle model of matter it has large spaces between them and does not have a definite shape

Among the following properties, Helium would fills entire container. Hence Option (B) is correct.

A “state of matter” is a way to describe the behaviour of atoms and molecules in a substance.

There are three common states of matter: Solids – relatively rigid, definite volume and shape. In a solid, the atoms and molecules are attached to each other. They vibrate in place but don't move around.

Helium is a gas in nature and thus fills entire container.

Therefore, Among the following properties, Helium would fills entire container. Hence Option (B) is correct.

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Explanation:

a)phenotype= 100% big

b) genotype=1:2:1 (FF-25%, Ff-50%, ff-25%)

phenotype=3:1 (big=75%, small= 25%)

Explanation:

An ecosystem includes the environment, living and non-living things and how they interact with each other.

For example, in a Reef ecosystem there

are marine plants and animals that depend on each other and their surrounding to survive.

Answer:

you need my help come over

Explanation:

Answer: I believe the answer is surface tension :)

Answer:

Distilation because they have different boiling points

The 3 isomers of pentane and their normal boiling points are:-

pentane, b.p approx. 36.C

iso pentane, b.p approx. 28.C

neo pentane, b.p approx. 10.C

Those differences in their boiling points make possible them to separate by Distilation.

Hope this will help....

a) The required pH is 3.20.

b) The required pH is 9.95.

(a) The equation for the reaction of HF (a weak acid) with NaF (a salt of a weak acid) is:HF (aq) + F− (aq) ⇌ HFn−1 (aq) + H2O (l)Therefore, HF acts as an acid and F− acts as a base. We can set up an ICE table (Initial, Change, Equilibrium) for the reaction above: We can ignore x when compared to 0.27 (assumption).

Since the solution is slightly acidic, we need to use the quadratic equation. So: Therefore, the pH is 3.20.

(b) The equation for the reaction of C2H5NH2 (a weak base) with C2H5NH3+ (a conjugate acid) is:C2H5NH2 (aq) + H2O (l) ⇌ C2H5NH3+ (aq) + OH− (aq)Therefore, C2H5NH2 acts as a base and C2H5NH3+ acts as an acid. We can set up an ICE table (Initial, Change, Equilibrium) for the reaction above: Therefore, the pH is 9.95.

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Answer:

your should probably be warming the acid

Explanation:

because when you are it is disappearing

Answer:

Warming the acid

Explanation:

This is because when the acid is heated, the particle of the acid gain more energy (kinetic to be more precise) causing more collisions to occur, colliding even more with the particles of the magnesium ribbon. This increases the rate of disappearance of the magnesium ribbon.

Answer:

The new volume is 5.0L

Explanation:

Given:

Initial pressure (P₁) = 1.4 atm

Initial volume (V₁) = 2.3 L

Final pressure (P₂) = 0.65 atm

We'll use Boyle's Law:

P₁V₁ = P₂V₂

Substituting the given values:

(1.4 atm)(2.3 L) = (0.65 atm)(V₂)

Now, let's solve for V₂:

V₂ = (1.4 atm * 2.3 L) / 0.65 atm

Calculating this expression step-by-step:

V₂ = (3.22 atm·L) / 0.65 atm

V₂ ≈ 4.953 L

Rounded to one decimal place, the new volume is approximately 5.0 L.

The reaction of hydrogen (H2) and propene (C3H6) using a platinum catalyst is an example of a hydrogenation reaction.

Hydrogenation involves the addition of hydrogen to a molecule, resulting in the formation of a saturated compound.

In this case, the unsaturated propene molecule (containing a double bond between two carbon atoms) reacts with hydrogen in the presence of a platinum catalyst to form propane (C3H8), which is a saturated compound.

The platinum catalyst facilitates the reaction by providing an active surface for the reactants to adsorb onto, promoting the breaking of the double bond and the addition of hydrogen atoms.

Hydrogenation reactions are commonly employed in various industrial processes, such as the production of margarine or the hydrogenation of vegetable oils to form solid fats.

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Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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Answer:

I would say A but I'm not sure

When tin metal is placed into a solution of nickel (II) iodide then nothing will occur.

Reactivity series of the metals tells about the increasing or decreasing orders of the reactivity of the metals.

According to the reactivity series, reactivity of nickel metal is more than the tin metal. So, if we add tin metal in the solution of nickel (II) iodide then no reaction occurs. Because the reactivity of tin is less as compare to nickel metal so it is not possible for tin to replace the nickel metal and get dissolve.

Hence, option (C) is correct i.e. nothing.

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Explanation:

We are given: Ka = 4.83*10^-8

We use Ka to find pKa:

We know: pKa + pKb = 14

Answer:

pKb = 6.68

Answer:

The acid will absolutely remove the hard water deposits that are trapping the stains. The longer it soaks, the less you have to scrub. It works for hard water stains, limescale, and rust!

Explanation:

hope this helped you out.

Answer:

For example, 0.9% NaCl contains 0.9 g NaCl per 100 ml of solution or 9 g NaCl/l. This can be converted to molarity by dividing by molecular weight: 0.9% NaCl = (9g/l)/(58.5g/mole) = 0.15 M NaCl.

The order from most soluble to least soluble is CH3CH2CH2OH > CH3CH2OCH3 > CH3CH2CH3.

The solubility of a compound depends on the nature of the solute and the solvent. If the nature of both is the same (either both polar or both nonpolar) the salute will be soluble in that solvent.

The solubility of an organic compound in water depends on the following factor:

Hydrogen bonding: If the solute is capable to form hydrogen bonding with water, it will be soluble in the water.

Polarity: As the polarity of the solvent increases the water solubility also increases.

The most soluble compound in water is alcohol. The alcohol is the highest polar molecule from the given molecules. It also forms hydrogen bonding with the water as follows:

The second most soluble compound in water is ether, CH3CH2OCH3. Ether is less polar than alcohol and forms fewer hydrogen bonds with water.

The least soluble compound in water is propane, CH3CH2CH3. Propane is a nonpolar compound and it is insoluble in a polar solvent, water.

Therefore the order is as follows:

CH3CH2CH2OH>CH3CH2OCH3>CH3CH2CH3

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The chemical formula you provided is a representation of the molecule hexanethiol (C6H14S), which contains a chain of six carbon atoms with an SH group attached to the fifth carbon atom and two CH2CH3 groups attached to the second and sixth carbon atoms.

Hexanethiol is a colorless liquid with a strong, unpleasant odor and is commonly used as a reagent in organic chemistry.

It seems like you're describing a molecule with a specific structure. Based on the information provided, the molecule can be represented as follows:
CH3CH2C(CH2CH3)C(SH)CH(CH2CH3)CH2CH3

This molecule has a main carbon chain of 7 carbons (heptane) with two CH2CH3 (ethyl) groups and an SH (thiol) group attached to different carbon atoms along the chain.

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There are 2.19 × 10²⁴ ethanol molecules present in 212 mL of ethanol.

To calculate the number of molecules of ethanol (C2H5OH) present in 212 mL of ethanol, we need to use Avogadro's number concept.

Let's first calculate the number of moles of ethanol present in 212 mL of ethanol:1. The molar mass of ethanol (C2H5OH) = 46.07 g/mol2.

The density of ethanol (C2H5OH) = 0.789 g/mL (given)Mass of ethanol in 212 mL = 0.789 g/mL × 212 mL = 167.1

moles of ethanol = Mass of ethanol/Molar mass of ethanol= 167.1 g/46.07 g/mol= 3.63 moles

Now we can calculate the number of ethanol molecules present in 3.63 moles using Avogadro's number:1 mole of ethanol contains 6.022 × 1023 ethanol moleculesTherefore, 3.63 moles of ethanol contain:3.63 moles × (6.022 × 10²³ ethanol molecules/mole) = 2.19 × 10²⁴ ethanol moleculesTherefore, there are 2.19 × 10²⁴ ethanol molecules present in 212 mL of ethanol.

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Given :

There are 0.090 moles of sugar (C₁₂H₂₂O₁₁) in the average can of soda.

To Find :

How many sugar molecules would this be ?

Solution :

We know, in 1 mole of any compound their are \(6.022\times 10^{23}\) molecules of that compound.

So, number of molecules in 0.090 moles of compound is :

\(n = 0.090 \times 6.022 \times 10^{23}\\\\n = 5.42\times 10^{22}\)

Therefore, number of molecules in 0.090 moles of compound is \(5.42 \times 10^{22}\) .

B) The plum-pudding model was proven correct in experiments by Ernest Rutherford is the false statement.

The plum-pudding model of the atom was proposed by J.J. Thomson in 1904. According to this model, the atom consists of a positively charged sphere with negatively charged electrons dispersed within it like plums in a pudding. However, in 1911, Ernest Rutherford's gold foil experiment disproved the plum-pudding model and suggested the existence of a nucleus at the center of the atom. The alpha particles in Rutherford's experiment were scattered in unexpected directions, indicating that the positive charge of the atom was concentrated in a small, dense nucleus at the center, rather than being spread uniformly throughout the atom as in the plum-pudding model.

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Answer:

The part of the atom that is involved in bonding is Valence electrons.

Answer: Atoms contain tiny, negatively charged electrons

Explanation: Thomson's experiments with cathode ray tubes helped him to discover the electron (which Dalton did not know about). Dalton thought that atoms were indivisible particles, and Thomson's discovery of the electron proved the existence of subatomic particles.

Answer: The universe consists of all the energy made by the Sun and stars. The universe consists of all physical objects on Earth and in space. The universe consists of all matter and energy. The universe consists of solar systems which contain galaxies.

Explanation:  That's because the Universe does consists of all the energy made by the Sun and Stars. That is how we get our energy is from the Sun and Stars, and the Solar System contains Galaxies.

The carbon skeletons of amino acids can be converted into seven key molecules. These seven molecules play crucial roles in metabolism, energy production, biosynthesis of other essential compounds.

1. Pyruvate: This is generated from alanine, cysteine, glycine, serine, and threonine.
2. Acetyl-CoA: Derived from isoleucine, leucine, and tryptophan, it is an important molecule involved in energy production and synthesis of other compounds.
3. Acetoacetyl-CoA: Ketogenic amino acids like leucine and lysine produce this molecule, which can be used for ketone body synthesis or further converted to acetyl-CoA.
4. Alpha-ketoglutarate: Aspartate and glutamate yield this intermediate, which is involved in the citric acid cycle.
5. Succinyl-CoA: This molecule, produced from methionine, threonine, isoleucine, and valine, is another citric acid cycle intermediate.
6. Fumarate: Phenylalanine, tyrosine, and aspartate generate fumarate, which is converted to malate in the citric acid cycle.
7. Oxaloacetate: Asparagine and aspartate produce this molecule, which is essential for gluconeogenesis and the citric acid cycle.

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