Plz help i am timed
Find the missing exponent: 36 = 67.
A.-2
B.2
C.-1/2
D.1/2

Answer:

Step-by-step explanation:4

Step-by-step explanation:

We do the ones that are in parenthesis first. Find out the exponent. 2 to the power of two is 4. 3-4=-1. Then we would add 5. 5+-1 would result of 4.

The function is undefined for those values of x where the denominator is zero.

The reciprocal identity for sine, cosine, and tangent states that:

sin(x) = 1/csc(x)

cos(x) = 1/sec(x)

tan(x) = 1/cot(x)

It is important to note that csc, sec, and cot are only defined for values of x where the denominator is not equal to zero.

For example, csc(x) is defined as 1/sin(x), so it is undefined for x = kπ where k is any integer and sin(x) = 0.

Similarly, sec(x) is defined as 1/cos(x) and is undefined for x = (k+1/2)π where k is any integer and cos(x) = 0. Finally, cot(x) is defined as 1/tan(x) and is undefined for x = kπ where k is any integer and tan(x) = 0.

Therefore, the reciprocal identity for sine, cosine, and tangent is only defined for certain input values, and it is undefined for those values of x where the denominator is zero.

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Answer:

4250 m

Step-by-step explanation:

1 day = 850

5 days = 850×5

= 4250

The transformation that produces a similar figure that is not congruent to the orginal figure would be: A. dilation.

We know that Dilation is a formm of transformation which involves the enlargement or reduction of an image to create a new image that is similar to the original image.

By implication, the new image has becomes different size but the same shape with the original image.

However Dilation produces a figure that is similar but not congruent to the original figure.

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Answer:

4√5 cm

Step-by-step explanation:

Connect the two points at which the chord touches the circle to the center - these are radii.

We know that the chord is 4cm from the center of the circle.

So we now have an isosceles triangle with height of 4cm and congruent side lengths of 6cm (see attached diagram for visual representation). An isosceles triangle is made up of 2 congruent right triangles.

To find the length of the chord, all we have to do is calculate the shorter leg of one of the right triangles and multiply it by 2.

Use Pythagoras' Theorem:  a² + b² = c²

(where a and b are the legs and c is the hypotenuse of a right triangle).

Therefore, a² + 4² = 6²

                 a² + 16 = 36

                        a² = 36 - 16 = 20

                          a = √20 = 2√5

So the length of the chord = 2 x 2√5 = 4√5 cm

Answer: 1/6 of the paint went to each container

Step-by-step explanation: Since we know he had 2/3 of a gallon of paint and they were divided into 4 containers, we have to divide 2/3 by 4 and when you do that you get 0.16666 continuous but in fraction for you arrive at 1/6 of a gallon of paint

An expression that can be used to find the cost of an n-minute long distance call, where n is at least 5 minutes is (0.55 + (n - 5) x 0.07) dollars.

Given:

Long Distance Rates Time (minutes) Cost5 $0.556 $0.627 $0.698 $0.769 $0.8310 $0.90We need to find an expression that can be used to find the cost of an n-minute long-distance call, where n is at least 5 minutes.

The cost of making a long-distance call is given for 5 minutes, 6 minutes, 7 minutes, 8 minutes, 9 minutes, and 10 minutes.

We can observe from the above table that for every increase of 1 minute, the cost increases by $0.07.

We can conclude that the cost of n minutes long-distance call is given by: (0.55 + (n - 5) x 0.07) dollars when n is at least 5 minutes.

Therefore, the required expression is: (0.55 + (n - 5) x 0.07) dollars when n is at least 5 minutes. The above expression is based on the pattern in the table provided for long-distance call rates. We can use this expression for values of n greater than or equal to 5.

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Answer:

A.) Students who do not play sport are more likely to play a musical instrument than students who do play sport.

Step-by-step explanation:

Student who do not play sport and play musical instruments = 7

Student who do play sport and play musical instrument = 6

7 > 6 ; Hence, statement A is true

Answer:A

Step-by-step explanation:

I got it right on khan academy

Answer:

y = 7(1 + x/5)

Step-by-step explanation:

7x - 5y = -35

-5y = -35 - 7x

5y = 35 + 7x

y = (35 + 7x) / 5

y = 7 + 7x/5

y = 7(1 + x/5)

The solution to the equation -2(x + 3) = -6 is x = 0.

To simplify the expression 5t + 7 + 8b, we can combine like terms.

There are two like terms in the expression: 5t and 8b.

Combining the like terms gives us:

5t + 8b + 7

Therefore, the simplified form of the expression 5t + 7 + 8b is 5t + 8b + 7.

Regarding the equation -2(x + 3) = -6:

To solve this equation, we can follow these steps:

Distribute the -2 to the terms inside the parentheses:

-2 * x + (-2) * 3 = -6

This simplifies to:

-2x - 6 = -6

Move the constant term to the right side by adding 6 to both sides of the equation:

-2x = 0

Divide both sides of the equation by -2 to isolate the variable x:

x = 0 / -2

Simplifying the right side of the equation gives us:

x = 0

The solution to the equation -2(x + 3) = -6 is x = 0.

The simplified expression 5t + 7 + 8b remains as 5t + 8b + 7, and the solution to the equation -2(x + 3) = -6 is x = 0.

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Step-by-step explanation:

f[g(X)]

=f(X+5)

=(x+3)+5

=x+8

Ans: fg(x)=x+8

Step-by-step explanation:

If you know how to solve this, Please answer it. Thank You

The first one to answer the question right, will get Brainlist!

I PROMISE!!!!!

Based on the limited information provided, it is not possible to definitively determine the type of economy in Country A. More specific details and factors would be necessary to make a conclusive determination.

To find the Fourier cosine series of the function f(x), we first need to find the Fourier coefficients of f(x).

The Fourier coefficients of f(x) are given by:

a0 = (2/L) * integral of f(x) from x=0 to x=L

an = (2/L) * integral of f(x) * cos(npix/L) from x=0 to x=L

bn = (2/L) * integral of f(x) * sin(npix/L) from x=0 to x=L

Using the result from part a) and the fact that the series can be integrated term by term, we can find the Fourier cosine series of f(x) as follows:

F(x) = a0/2 + sum from n=1 to infinity of an * cos(npix/L)

Therefore, the Fourier cosine series of the function f(x) is:

F(x) = (1/L) * integral of f(x) from x=0 to x=L + sum from n=1 to infinity of (2/L) * integral of f(x) * cos(npix/L) from x=0 to x=L

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Answer:

100 2/3

Step-by-step explanation:

50+50=100

1/3+1/3=2/3

100+2/3= 100 2/3

Answer:

Hey there! :)

Step-by-step explanation:

~Answer would be 100 2/3

(There is 3 steps for solving this question, the steps are provided below!)

Here is two ways you can solve this problem!:

Steps in order to solve this problem:

~ 1.Make both of the mixed number into a improper fraction.

151/3 + 151/3

~ 2.Now, when you add ‘151/3 + 151/3’ you will get 302/3.

~ 3.Finally you divide 302 and 3 which will give you 100 2/3

……………………………………………………………………………………………………

Another way to solve the question:

~1.Break up the mixed number:

50 1/3 = 50 + 1/3

50 1/3 = 50 + 1/3

~2.So this is the question you asked 50 1/3 + 50 1/3

Add 50+50 which gives you 100.

We solved for the whole number and now we have to solve for the fractions part.

1/3 + 1/3 = 2/3

~3.We got 100 as the whole and 2/3 as the fraction.

So now you just combine them both.

100 + 2/3 = 100 2/3

Therefore the answer is 100 2/3

Hope this helps!! I would be glad to help you with anything you don’t understand about this question! :D

Good luck!

Answer:

3.33 is the unit price

Step-by-step explanation:

The value of angle RPQ in the circle is 115 degrees.

The intersecting chords theorem, also known as the chord theorem, is an elementary geometry statement that describes a relationship between the four line segments formed by two intersecting chords within a circle.

If two chords intersect inside a circle, then the measure of the angle formed is one-half the sum of the measure of the arcs intercepted by the angle and its vertical angle.

Therefore,

∠RPQ = 1  / 2 (arc angle RQ + arc angle SA)

arc angle RQ = 175 degrees

arc angle SA = 55 degrees

Hence,

∠RPQ  = 1 / 2 (175 + 55)

∠RPQ  = 1 / 2 (230)

∠RPQ  = 115 degrees.

The angle is 115°.

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Answer:

wgqrgrregvqewbv

Step-by-step explanation:

Answer:

it’s SAA

Step-by-step explanation:

ur wlcm, i am sure of my answer

brainliest please?

The graph of the function y = -2x + 1/3 is added as an attachment

From the question, we have the following parameters that can be used in our computation:

y = -2x + 1/3

The above function is a linear function that has been transformed as follows

Next, we plot the graph using a graphing tool by taking not of the above transformations rules

The graph of the function is added as an attachment

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The inequality that represents the value of x is (b)  x > 80

from the question, we have the following parameters that can be used in our computation:

The figure

The general rule is that

The larger the side length, the larger the angle opposite it

using the above as a guide, we have the following:

1/8x > 10

So, we have

x > 80

Hence, the inequality is x > 80

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Answer: negative one third

Answer:

-1/3

Explanation:

There's a formula that I'll use to find the slope - it's called the slope formula.

\(\sf{m=\dfrac{y_2-y_1}{x_2-x_1}}\)

Plug in the data:

\(\sf{m=\dfrac{8-4}{-4-8}}\\\\\sf{m=\dfrac{4}{-12}\)

Simplify:

\(\sf{m=-\dfrac{4}{12}}\)

\(\sf{m=-\dfrac{1}{3}}\)

Hence, the slope is negative one-third.

The x-coordinate of Q if  the x-coordinate of R is -1 and the x-coordinate of P is -3 is 5

Here, we have,

given that,

Point R divides PQ in the ratio 1 : 3. If the x-coordinate of R is -1 and the x-coordinate of P is -3,

Midpoint of a line

The formula for calculating the midpoint of a line divided in the ratio m:n is expressed as:

M(x,y) =  (mx₂ + nx₁) / (m + n) , (my₂ + ny₁) / (m + n)

For the x-coordinate

X = (nx₁+mx₂/m+n)

let, the x-coordinate of Q = a

Substitute the given parameters

-1 = 3(-3) + 1(a) / 1+3

or, -1 = -9 + a/4

or, -4 = -9 + a

or, a = 5

Hence the x-coordinate of Q if  the x-coordinate of R is -1 and the x-coordinate of P is -3 is 5

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The three quadratic equation with different maximum and/or minimum values are y = (x-4)² – 1, y = -(x-4)² + 1, and y = -3(x-4)² + 3.

Quadratic equation:

In math, quadratic equation is the algebraic equation of the second degree in x.

The general form of quadratic equation is

ax² + bx + c = 0,

where a and b are the coefficients, x is the variable, and c is the constant term. The first condition for an equation to be a quadratic equation is the coefficient of x² is a non-zero term(a ≠ 0).

Given,

Here we need to find the three equations for quadratics in vertex form that have roots at 3 and 5 but have different maximum and/or minimum values.

As per the definition of quadratic equation, here we have to write the quadratic equation, that have the roots of 3 and 5,

Here the problem was going to call for two equations but then we have realized that it could be as simply as multiplying the a and c values by -1. Therefore, the equation are,

=> y = (x-4)² – 1,

=> y = -(x-4)² + 1,

=> y = -3(x-4)² + 3.

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The equation of the line in slope-intercept form is y = (3/4)x.

To write the equation of a line in slope-intercept form, we need to use the slope-intercept form equation: y = mx + b,

where m is the slope and b is the y-intercept.

Given that the line passes through the point (-8, 5) and has a slope of 3/4, we can substitute the values into the equation to find the y-intercept (b).

First, let's find the value of b using the point-slope form equation: y - y1 = m(x - x1), where (x1, y1) is a point on the line.

Using (-8, 5) as the point and 3/4 as the slope, we have:

5 - 5 = (3/4)(-8 - x)

0 = (3/4)(-8 - x)

0 = (-3/4)(8 + x)

0 = -6 - (3/4)x

Next, we can solve for x:

(3/4)x = -6

x = -6 \(\times\) (4/3)

x = -8

Now that we have the value of x, we can substitute it back into the equation to find the value of b:

0 = -6 - (3/4)(-8)

0 = -6 + 6

0 = 0

So, the value of b is 0.

Finally, we can write the equation of the line in slope-intercept form:

y = (3/4)x + 0

y = (3/4)x.

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A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(x^{4}\)+ c\(x^{3}\). The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set.

Part A: A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(x^{4}\)+ c\(x^{3}\). The coefficient of the highest degree term (x^5) must be non-zero and all the terms must be written in descending order of the degree. This is the definition of standard form for polynomials.

Part B: The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set. In this case, the set is polynomials and the operation is subtraction. An example of this property can be seen by subtracting two polynomials, such as 4\(x^{2}\) + 3x - 5 and \(x^{2}\) + 2. The result of this subtraction would be 3\(x^{2}\) + 3x - 5, which is also a polynomial and therefore an element of the set, demonstrating the closure property.

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A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(y^{2}\)+ c. The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set.

Part A: A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(y^{2}\)+ c. The coefficient of the highest degree term (\(x^{5}\)) must be non-zero and all the terms must be written in descending order of the degree. This is the definition of standard form for polynomials.

Part B: The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set. In this case, the set is polynomials and the operation is subtraction. An example of this property can be seen by subtracting two polynomials, such as 4\(x^{2}\) + 3x - 5 and  + 2. The result of this subtraction would be 3\(x^{2}\) + 3x - 5, which is also a polynomial and therefore an element of the set, demonstrating the closure property.

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