Point I is on line segment HJ. Given HI = x, IJ = 2x + 9, and H J = 4x,
determine the numerical length of IJ.

The formula for computing the line integral of the scalar function is given as: Sc f(x, y) dsWhere, Sc represents the line integral of the scalar function f(x, y) over the curve C and ds represents an infinitesimal segment of the curve C.

Let us evaluate the given line integral of the scalar function f(x, y) over the curve \(y = x³ for 0 ≤ x ≤ 9.\)Substituting the given values in the formula, we get\(:Sc f(x, y) ds= ∫ f(x, y) ds ...(1)\)The curve C can be represented parametrically as x = t and y = t³, for 0 ≤ t ≤ 9. Therefore, we have ds = √(1 + (dy/dx)²) dx, where dy/dx = 3t².Hence, substituting the values of f(x, y) and ds in equation (1), we have\(:Sc f(x, y) ds= ∫₀⁹ √(1 + (dy/dx)²) f(x, y) dx= ∫₀⁹ √(1 + 9t⁴) √√/1+9t⁴ dt= ∫₀⁹ dt= [t]₀⁹\)= 9Hence, the value of the line integral of the scalar function\(f(x, y) = √√/1+9xy over the curve y = x³ for 0≤x≤ 9 is 9.\)

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The properties of the quadratic equation y=-3x^2+6x+17 is Axis of symmetry - x=1, Vertex (maximum) - (1,20), Parabola opens downwards and the end behaviour is x→∞,y→-∞, x→-∞, y→-∞.

What is a quadratic equation?

An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax^2 + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.

The quadratic equation in the general form can be written as -

y=-3x^2+6x+17

Here, a=-3

b=6

c=17

An imaginary straight line known as the axis of symmetry divides a shape into two identical sections, making one part the mirror image of the other.

Here, the axis of symmetry is x=1.

The vertex of the equation is at the maximum or the lowest point of the parabola.

So, after plotting the graph the maximum point is (1,20).

The leading coefficient of the equation is -3, which is less than zero.

So, the parabola formed by the quadratic equation opens downwards and forms a upside-down U shaped parabola.

According to the equation has an even degree and the graph of  the parabola is leading towards negative infinity.

Therefore, it can be denoted as x→∞,y→-∞, (right end down) and as x→-∞, y→-∞ (left end down).

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The x-intercept of f(x) is 4

The y-intercept of f(x) is -8.

A function is a relationship between inputs where each input is related to exactly one output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

f(x) = x³ - 7x² + 14x - 8

One of the factors of f(x) is (x - 4).

This means,

x = 4

Now,

The x-intercept is when y = 0.

The y-intercept is when x = 0.

When y = 0 we get the x value.

x = 4 is a factor.

The x-intercept is x = 4.

Now,

Put x = 0,

f(x) = y

y = x³ - 7x² + 14x - 8

y = 0 - 0 + 0 - 8

y = -8

Thus,

The x-intercept of f(x) is 4

The y-intercept of f(x) is -8.

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Answer:

108/9 = 12

Step-by-step explanation:

if you simplify 108/9 it equals 12

convert to a decimal it also equals 12

im not exactly sure what you wanted to do with the problem but i hope this helped, let me know if im incorrect or if i can help more.

Answer:

They travel 5/18 in one hour

Step-by-step explanation:

Answer:

In an hour the car can cover 5/18 of the distance

Answer:

9/12 or simplified as 3/4

Step-by-step explanation:

We are given 3 fractions that we have to add because the question says "What fraction of the can did she use in all?​"

First: Write down \(\frac{1}{3} + \frac{1}{4} +\frac{1}{6}\)

Then: We can't just add up all these fractions, we need a LCM. The LCM (Least Common Multiple) We need all the denominators (3, 4, and 6) to be the same. To do that we need to find a number that they can multiply to get. Let's find out all the multiples of each number: (just write the first 5 down because most of the time we can find it easily from this list)

3: 3, 6, 9, 12, 15

4: 4, 8, 12, 16, 20

6: 6, 12, 18, 24, 30

After: just change all the fractions one at a time by whatever you multiply the bottom number to get 12, do it to the top:

\(\frac{1}{3} -- > \frac{4}{12}\)

\(\frac{1}{4} -- > \frac{3}{12}\)

\(\frac{1}{6} -- > \frac{2}{12}\)

Finally we get to add everything up to get:

\(\frac{4}{12} +\frac{3}{12} +\frac{2}{12} =\frac{9}{12}\)

(simplified as 3/4)

Answer:

Amen Sister!

A whole lot of people who are against the word are gonna delete this

*cough* *cough* Karens *cough*

Step-by-step explanation:

How do I properly repent?

Plz mark B R A I N L I E S T

There is a positive nonlinear association from the scatter plot shown. Option D

A link between two variables in a scatter plot is said to have a positive correlation if their values tend to rise together.

It implies that the value of the other variable tends to increase as the value of the first variable does. On the other hand, as one variable falls, the other tends to fall as well.

In a scatter plot with a positive correlation, the data points generally form an upward trend or pattern as you move from left to right on the plot as shown above.

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Answer:

There is a positive nonlinear association.

Step-by-step explanation: to all the flvs people good job for making it this far in math and I hope you finish your exams and get a good and get a good grade ! <3

Answer:

Point (5, -1) is located in Quadrant IV of a coordinate plane.

Explanation:

Point (-2,-7) is located in Quadrant III of a coordinate plane, not Quadrant I.

Point (3,-9) is located in Quadrant IV of a coordinate plane, not Quadrant II.

Point (-4, 8) is located in Quadrant Il of a coordinate plane, not Quadrant III.

Answer:

Step-by-step explanation:

Answer:

6.3 x 106 ÷ 7 x 10-5 = 0.9 x 1011 or 9 x 1010

Step-by-step explanation:

Answer:

-3/4

Step-by-step explanation:

change them to improper fractions

-5/2 - (-7/4)

now multiply -5/2 by two so the denominators are the same

-10/4 - (-7/4)

subtracting a negative number is the same as adding a positive number

-10/4 + 7/4

= -3/4

We can replace the ellipsis with -49a4 to get: (7/4)a 10 - 2 = -49a4 - b 4, missing monomial is -49a4.

To find the missing monomial, we need to use the distributive property to expand the left side of the equation:

(... - b 4)(64 + ....) = 121a 10 – 68

Expanding the left side gives:

64(... - b 4) + ....(... - b 4) = 121a 10 – 68

Now we need to find a monomial to replace the ellipsis that will make the left side of the equation equal to the right side of the equation, no matter what value is substituted for a and b.

Looking at the constants in the equation, we can see that 121 and 68 have a common factor of 17. Therefore, we can divide both sides of the equation by 17 to simplify the coefficients:

7a 10 - 4 = 4(... - b 4) + 4

Simplifying further, we get:

7a 10 - 8 = 4(... - b 4)

Dividing both sides by 4, we get:

(7/4)a 10 - 2 = ... - b 4

Now we need to find a monomial to replace the ellipsis that will make the left side of the equation equal to the right side of the equation, no matter what value is substituted for a and b.

Since we want the left side of the equation to have a degree of 4 (because the right side has a term of -b4), we need to choose a monomial of degree 4 that will cancel out the terms of degree 10 on the left side. One possible monomial is:

-49a4

Therefore, we can replace the ellipsis with -49a4 to get: (7/4)a 10 - 2 = -49a4 - b 4

So the missing monomial is -49a4.

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Answer:

10 in³

Step-by-step explanation:

Length = 10/3 inches

Width = 8/4 inches = 2 inches

Height = 3/2 inches

Volume = Length * width * height

Volume = 10/3 * 2/1 * 3/2

Volume = (10*2*3) / (3*1*2)

Volume = 60/6

Volume = 10 in³

We must find the length of one side of the new square.

Step one

The area of the square is 64. We know that the is of a rectangle is given by n x n, so:

The value of n is a number that multiplied by itself gives us 64, that number is 8, so we have:

Step two

The length of one side of the new square is obtained by multiplying the original length 8 by the scale factor 3/2, which gives us:

Answer

Answer:

THANK YOU?

Step-by-step explanation:

DNSNJSMSNNFJD

Please, give me brainliest

If the column vectors of matrix A are linearly dependent and vector b is in the column space of A, then the linear system Ax = b will have infinitely many solutions.

In a linear system Ax = b, where A is an m x n matrix, x is an n x 1 vector of variables, and b is an m x 1 vector, the column space of A represents all possible linear combinations of the column vectors of A.

If the column vectors of A are linearly dependent, it means that at least one column vector can be expressed as a linear combination of the other column vectors.

In other words, there exists a non-zero solution to the equation Ax = 0.

Now, if b is in the column space of A, it means that b can be expressed as a linear combination of the column vectors of A.

Since the column vectors of A are linearly dependent, we can find a non-zero solution to the equation Ax = b.

This means that there exists more than one solution to the linear system.

To see why there are infinitely many solutions, consider the equation Ax = b with a non-zero solution x₀.

Since the column vectors of A are linearly dependent, we can add a multiple of any column vector to another column vector without changing the column space of A.

Therefore, if x is a solution to the equation Ax = b, then x + kx₀ (where k is any scalar) will also be a solution.

This implies that there are infinitely many solutions to the linear system.

In conclusion, if the column vectors of matrix A are linearly dependent and vector b is in the column space of A, the linear system Ax = b will have infinitely many solutions.

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Answer:

what´s the question????

Step-by-step explanation:

Answer:

The line AB, with A(Ax, Ay), B(Bx, By) and midpoint M(Mx, My) satisfying:

Ax + Bx = 2Mx

Ay + By = 2My

=>

2 + Bx = 2*1

5 + By = 2*2

=> Bx = 0

=> By = -1

=> B(0, -1)

Hope this helps!

:)

Answer:

B(3, 8 )

Step-by-step explanation:

Using the midpoint formula

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then midpoint is

[ \(\frac{1}{2}\)(x₁ + x₂ ), \(\frac{1}{2}\)(y₁ + y₂ ) ]

let the coordinates of B = (x, y ), then

\(\frac{1}{2}\)(1 + x) = 2 ( multiply both sides by 2 )

1 + x = 4 ( subtract 1 from both sides )

x = 3

and

\(\frac{1}{2}\) (2 + y) = 5 ( multiply both sides by 2 )

2 + y = 10 ( subtract 2 from both sides )

y = 8

Thus

coordinates of B = (3, 8 )

Answer:

(6, 1 )

Step-by-step explanation:

To determine which ordered pair is a solution

Substitute the x and y values into the left side of the equation and if equal to the right side then it is a solution.

(6, 1 )

3(6) + 9(1) = 18 + 9 = 27 ← Solution

(1, 8 )

3(1) + 9(8) = 3 + 72 = 75 ≠ 27

(1, 11 )

3(1) + 9(11) = 3 + 99 = 102 ≠ 27

(8, 1 )

3(8) + 9(1) = 24 + 9 = 33 ≠ 27

Then (6, 1 ) is a solution to the equation

Answer:

Just put it in the middle of the square. and since this is a half, it should be in the middle of the square top right of the center point. or (0, 0)

Step-by-step explanation:

Since half on a graph is literally half of the square its the same for both Y and X cords. so it should be in the center if its half and half.

The linear regression model for the weekly cost data is given by C(z) = ma + k, where z is the independent variable representing the weekly demand.



The values of m and k are determined through the regression analysis. Using this model, we can estimate the total weekly cost for a given weekly demand and calculate the per unit variable cost and weekly fixed cost.To find the linear regression model, we need to perform a regression analysis on the given weekly cost data. This analysis will determine the values of m and k in the equation C(z) = ma + k, where C(z) represents the weekly cost and z represents the weekly demand.

Once the values of m and k are obtained, we can use the model to estimate the total weekly cost when the weekly demand is 210. By plugging in z = 210 into the equation C(z) = ma + k, we can calculate the total weekly cost rounded to the nearest dollar.The per unit variable cost can be determined by the value of m in the model. It represents the change in cost per unit change in demand. By rounding m to one decimal place, we can obtain the per unit variable cost rounded to one decimal place.

The weekly fixed cost can be determined by the value of k in the model. It represents the cost that does not depend on the weekly demand. By rounding k to the nearest integer, we can obtain the weekly fixed cost rounded to the nearest dollar.Overall, by applying the linear regression model to the given data, we can estimate the total weekly cost, calculate the per unit variable cost, and determine the weekly fixed cost of producing sleeping bags.

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Answer:

D

Step-by-step explanation:

f(x) =2x - 10

(f(x) + 10)/2 =h(X)

x/2 + 5 = h(x)

Answer: 16 units

Step-by-step explanation:

Given that in triangle ABC, m∠C=90,

it means m∠A +∠B= m∠BAC + m∠ABC = 90

m∠ABC = 90 - m∠BAC

Also given that;m∠BAC = 2m∠ABC

So,

m∠BAC = 2(90 - m∠BAC) = 180 - 2m∠BAC

m∠BAC +2m∠BAC = 180

3m∠BAC = 180

m∠BAC=180/3 = 60

m∠ABC = 60/3 = 30

thus,ΔBAC is a 30-60-90 right triangle, in which the ratio of the side lengths is 1:√3:2AC:BC=1:√3, AC=BC/√3BC=24, So,

AC=24/√3=8√3AL bisects angle A =>m∠LAC=30

ΔALC is a 30-60-90 right triangle, in which the ratio of the side lengths is 1:√3:2AC:AL=√3:2AL=2AC/√3=2x8√3/√3=16

Answer:

\(-2,\,\{0^\circ < A < 90^\circ\}\)

Step-by-step explanation:

\(\displaystyle \frac{\sqrt{1-\cos^22A}}{\cos(-A)\cos(90^\circ+A)}\\\\=\frac{\sqrt{\sin^22A}}{\cos(-A)\cos(90^\circ+A)}\\\\=\frac{\sin2A}{\cos(-A)\sin(-A)}\\\\=\frac{2\sin A\cos A}{-\cos(-A)\sin(A)}\\\\=\frac{2\cos A}{-\cos(A)}\\\\=-2\)

Note that by the co-function identity, \(\cos(90^\circ+A)=\sin(-A)\), and that \(\cos(-A)=\cos(A)\) and \(\sin(-A)=-\sin(A)\).

An English teacher, gives pop quizzes to her students every marking period. (D. Fixed interval schedule of reinforcement.)

The other options listed are not applicable in this scenario:

A. Variable interval schedule of reinforcement: This schedule involves providing reinforcement after varying time intervals. Mrs. Jackson's quizzes occur at fixed intervals, not varying intervals.

B. Variable ratio schedule of reinforcement: This schedule involves providing reinforcement after a varying number of responses. The pop quizzes are not contingent on the number of responses from the students.

C. Fixed ratio schedule of reinforcement: This schedule involves providing reinforcement after a fixed number of responses. The pop quizzes are not contingent on the number of responses from the students.

D. Fixed interval schedule of reinforcement :fixed interval schedule of reinforcement involves providing reinforcement  at a fixed time interval. Mrs. Jackson gives the pop quizzes every marking period, which is a predetermined fixed interval of time. This schedule of reinforcement is characterized by a steady rate of response from the students, with an increase in responding closer to the time when the reinforcement is expected.

E. Interval ratio schedule of reinforcement: This is not a recognized schedule of reinforcement. The correct term would be fixed interval or variable interval schedule of reinforcement.

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