Predict the shape, state the hybridization of the central atom, and give the ideal bond angle(s) and any expected deviations for:
(a) BrO³⁻

The bicarbonate buffer system is a commonly used buffer in biochemical experiments, especially in studying enzymes and proteins.

The procedure used for the preparation of bicarbonate buffer involves the addition of sodium bicarbonate to a solution of carbon dioxide in water, which results in the formation of carbonic acid. This acid can then dissociate into bicarbonate ions and hydrogen ions, forming a buffer system. While this procedure is a valid one for buffer preparation, there are some limitations. The buffer capacity of the bicarbonate buffer system is relatively low compared to other buffer systems, and it is also sensitive to changes in temperature and pH. Therefore, the use of bicarbonate buffer should be carefully considered and optimized for specific experimental conditions.

Yes, the procedure used for the bicarbonate buffer is a valid one for buffer preparation. Bicarbonate buffer systems are widely used due to their capacity to maintain pH stability. They are commonly prepared using a combination of sodium bicarbonate (NaHCO3) and sodium carbonate (Na2CO3) or a weak acid like carbonic acid (H2CO3). By adjusting the ratio of these components, the desired pH can be achieved. The bicarbonate buffer is particularly important in physiological systems, as it plays a crucial role in maintaining blood pH within the narrow range required for optimal biological function. Its effectiveness as a buffer is attributed to the equilibrium between dissolved CO2, H2CO3, and bicarbonate ions.

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Answer:

the answer is 69

Explanation:

hope this helps

have an awesome day -TJ

Answer: 1.11 g/mL is the density

Answer:

C) the number of valence electrons

Explanation:

the group shows the valence electrons in the atom

eg. Na has one valence electron hence it belongs to group(I)

(i) The initial-boundary value problem for the given scenarios are as follows:

a) Scenario a:

PDE: ∂u/∂t = k * ∂²u/∂x²

Initial condition: u(x, 0) = 100 (boiling water temperature)

Boundary conditions: u(0, t) = 10, u(L, t) = 10 (constant temperature at the ends)

b) Scenario b:

PDE: ∂u/∂t = k * ∂²u/∂x²

Initial condition: u(x, 0) = 100 (boiling water temperature)

Boundary conditions: u(0, t) = 0 (temperature at x=0), ∂u/∂x(L, t) = 0 (thermal insulation at x=L)

(iii) The solution for the temperature distribution as time approaches infinity can be found by solving the appropriate steady state equation.

(i) The initial-boundary value problem formulation states the partial differential equation (PDE) governing the temperature distribution in the aluminum bar, along with the initial condition and boundary conditions.

In scenario (a), both ends of the bar are immersed in a medium with a constant temperature of 10 degrees Celsius, while in scenario (b), the end at x=0 is immersed in a medium with temperature 0 degrees Celsius and the end at x=L is insulated.

(ii) As time approaches infinity, the temperature distribution in the bar tends to reach a steady state.

In scenario (a), the temperature throughout the bar will eventually approach a constant value of 10 degrees Celsius, since both ends are immersed in a medium with that temperature.

In scenario (b), the temperature at x=0 will approach 0 degrees Celsius, while the temperature at x=L will remain constant due to thermal insulation.

(iii) To find the solution as time approaches infinity, we need to solve the appropriate steady state equation.

In scenario (a), the steady state equation is ∂²u/∂x² = 0, which implies that the temperature gradient is zero throughout the bar, resulting in a constant temperature of 10 degrees Celsius.

In scenario (b), the steady state equation is ∂²u/∂x² = 0 with the boundary condition u(0) = 0, which implies a linear temperature distribution from 0 degrees Celsius at x=0 to a constant temperature at x=L due to insulation.

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Due to catenation property of carbon

What is catenation property ?

Carbon has the capacity to join together to form lengthy chains. In actuality, among all the other atoms present in nature, carbon atoms are distinct due to catenation. Tetravalent connections between carbon atoms are what cause carbon chains to develop today.

They create tetravalent bonds, in which one carbon atom joins forces with four additional carbon atoms. They have a repeating structure because this structure can be repeated indefinitely without affecting the stability of the bonds or the compounds created.

In actuality, chains can create branches, which in turn, create sub-branches, which create rings, and so on. Now, there are two categories of carbon compounds, the first of which is open-chain or aliphatic molecules.

C forms covalent bonds almost exclusively.

C-C bonds are relatively short and therefore strong.

C-C multiple bonds form readily and are stable.

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Answer:

because the boiling point of water is 100°C the water bath would boil before the substance

B.)because they are packet tight

Answer:

Because they are packet tight.

Explanation:

Solids maintain their volume and shape because they are packet tight.

Answer:

FeCl3 + 3NH4OH ---> Fe(OH)3 + 3NH4Cl

Explanation:

Just make sure that both sides are equal

FeCl3 + 3NH4OH ---> Fe(OH)3 + 3NH4Cl

Answer:

Explanation:

- 3 - 3

19 ml of a 5m solution of sodium borate must be added to a 200 ml solution of 50mm boric acid in order for the ph to be 9.6

Here pH=Pka-log[A]/[B]

= 9.6=9.24-log[A]/[B]

= log[A]/[B]=-0.36

Here for ml molarity formula is used

Molarity=mass/volume here mass of sodium borate is 381g/mol and volume of solution is 200ml

mass/volume=381/200=1.905/5.0×50=19ml

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Answer:

84400cg

Explanation:

100000 cg in 1kg

100000(8.44)=84400cg

The mass of the solid is  2733 g

The mole is a useful unit of measurement in chemistry because it allows scientists to easily compare the amounts of different substances in chemical reactions. By knowing the molar amounts of the reactants and products in a chemical reaction, scientists can calculate important information such as the mass of products formed, the amount of energy released or absorbed, and other key chemical properties.

We know that;

1 mole of the compound would contain 6.02 * 10^23 molecules

x moles of the compound will contain  9.62 x 10^24 molecules

x= 15.98 moles

Then;

Mass = 15.98 moles * 171 g/mol

= 2733 g

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Cosmic background radiation is Leftover radiation from the big bang.

What is Cosmic radiation?
When primary photons and particles from outside of the solar system interact with elements of the earth's atmosphere, cosmic radiation, an ionising radiation, is created. The sun's discharge of charged particles, also known as solar flares or "sun storms," is a secondary source of cosmic radiation. The environment in which we live naturally contains ionising radiation, which can be found in the soil, structures, food we eat, and even the bones in our bodies.

Nonionizing radiation, which also includes UV light, radio waves, as well as microwaves, is the other type. Natural radiation has been present in the environment where humans, animals, as well as plants have all evolved, and, with very few exceptions, it poses little danger to human health.

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Answer:

6

Explanation:

2+2+2=6 :)

Answer:

6

Explanation:

vvvffhjh DC hcf vhcnbfhbc

The molecular formula of the herbicide, molecular formula: C12H14Cl2N2, %CL= 27.6%

A molecule is a collection of two or extra atoms held collectively with the aid of appealing forces called chemical bonds; depending on the context, the term can also or may not encompass ions that fulfill this criterion.

Molecular compounds are inorganic compounds that take the shape of discrete molecules. Examples include such familiar materials as water (H2O) and carbon dioxide (CO2). these compounds are very one kind from ionic compounds like sodium chloride (NaCl).

Molecules are made up of one or greater atoms. in the event that they comprise more than one atom, the atoms can be the same (an oxygen molecule has oxygen atoms) or different (a water molecule has two hydrogen atoms and one oxygen atom).

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At -250 °C, Hydrogen is in its gaseous state. At -250 °C, Hydrogen is in its gaseous state.

The melting point of a substance is the temperature at which it transitions from a solid to a liquid state, while the boiling point is the temperature at which it transitions from a liquid to a gaseous state. Given that Hydrogen has a melting point of -259 °C and a boiling point of -253 °C, we can infer that at temperatures below its boiling point, Hydrogen remains in its gaseous state. At -250 °C, which is higher than its melting point but lower than its boiling point, Hydrogen is still below its boiling point, so it remains in the gaseous state.The density of Hydrogen in its liquid state is provided as 0.07 g/cm³, but since the temperature is below its melting point, it does not apply in this scenario. Therefore, at -250 °C, Hydrogen is in its gaseous state. The melting point of a substance is the temperature at which it transitions from a solid to a liquid state, while the boiling point is the temperature at which it transitions from a liquid to a gaseous state.

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The percent yield obtained from the stoichiometry of the reaction when the moles of the reactants and products are known.

Stochiometry gives the relationship between the mass and mole or moles and volume in a reaction.

Q1)

K2PtCl4 + 2NH3 ----> Pt(NH3)2Cl2 +2KCl

Number of moles of NH3 = 34.5 g/17 g/mol = 2.03 moles

2 moles of NH3 yields 2 moles of KCl

2.03 moles  of NH3 yields 2.03 moles  of KCl

Theoretical yield of KCl =  2.03 moles * 75 g/mol = 154 g

Again,

2moles of NH3 yields 1 mole of Pt(NH3)2Cl2

2.03 moles  of NH3 yields 2.03 moles  * 1/2 = 1.015 moles

Mass of Pt(NH3)2Cl2 = 1.015 moles * 301 g/mol = 306 g

% yield =  76.4 g/306 g * 100/1 = 25%

Q2)

H3PO4 + 3 KOH ------> K3PO4 + 3 H2O

Number of moles of H3PO4  = 49.0 g/98 g/mol = 0.5 moles

If  mole of H3PO4  yield 1 mole of K3PO4

0.5 moles of H3PO4  yield 0.5 moles of K3PO4

Mass of K3PO4  = 212 g/mol * 0.5 moles = 106 g

Percent yield = 49.0 g/106 g * 100 = 46%

Q3)

Al2(SO3)3 + 6 NaOH ------> 3 Na2SO3 + 2 Al(OH)3

Number of moles of Al2(SO3)3 = 389.4 g/294 g/mol = 1.32 moles

If 1 mole of Al2(SO3)3 yields 3 moles of  Na2SO3

1.32 moles of Al2(SO3)3 yields 1.32 moles  * 3 moles/1 mole = 3.96 moles

Mass of Na2SO3 = 3.96 moles * 126 g/mol = 498.96 g

Percent yield = 212.4 g/498.96 g * 100/1 = 43%

Q4)

Al(OH)3(s) + 3 HCl(aq) -------> AlCl3(aq) + 3 H2O(l)

Number of moles of Al(OH)3 = 50.3 g/78 g/mol = 0.64 moles

If 1 mole of Al(OH)3 yields 1 mole of AlCl3

0.64 moles of Al(OH)3 yields 0.64 moles of AlCl3

Mass of AlCl3 = 133 g/mol * 0.64 moles = 85 g

Percent yield = 39.5 g/85 g * 100 = 46%

Q5) K2CO3 + 2HCl --------> H2O + CO2 + 2KCl

Number of moles of K2CO3 = 34.5 g/138 g/mol = 0.25 moles

1 mole of K2CO3  produces 2 moles of KCl

0.25 moles of K2CO3  produces 0.25 moles * 2 moles/1 mole = 0.5 moles

Mass of KCl = 0.5 moles * 75 g/mol = 37.5 g

If 1 mole of K2CO3  yields 1 mole of H2O

0.25 moles of K2CO3  yields 0.25 moles of H2O

Mass of H2O = 0.25 moles  * 18 g/mol = 4.5 g

Percent yield = 3.4 g/4.5 g *100 = 76%

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The increase in pressure when a basketball is pumped up is caused by the change in the number of molecules (optionC).

When air is pumped into a basketball, the air molecules are forced into a smaller space, which increases the number of molecules in that space. This increase in the number of molecules leads to an increase in the pressure of the gas within the ball.To better understand why this is the case, we can use the ideal gas law, which describes the behavior of gases under various conditions. The ideal gas law is expressed as PV = nRT, where P is pressure, V is volume, n is the number of molecules, R is the gas constant, and T is temperature.
When air is pumped into a basketball, the volume of the ball remains the same (assuming the ball is rigid and does not expand), and the temperature of the air inside the ball does not change significantly. Therefore, according to the ideal gas law, the only way the pressure can increase is if the number of molecules (n) increases.
This increase in pressure is what makes the ball bouncy and allows it to be used for games and activities. It is important to note that overinflating a basketball can lead to a rupture or bursting of the ball due to the excessive pressure created by the increased number of molecules.

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1.208 m3 of nitrogen gas (N₂), also known as dinitrogen, is placed inside a sizable balloon. It has a temperature of 313.5 K and a pressure of 1.207 x 105 Pa. The mass of dinitrogen (N₂) in the balloon is approximately 1715.88 grams.

To calculate the mass of dinitrogen (N₂) in the balloon, we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure of the gas (in Pa)

V = volume of the gas (in m³)

n = number of moles of the gas

R = ideal gas constant (8.314 J/(mol·K))

T = temperature of the gas (in K)

First, we need to rearrange the equation to solve for the number of moles (n):

\(\[n = \frac{PV}{RT}\]\)

Now we can substitute the given values into the equation:

P = 1.207 x 10⁵ Pa

V = 1.208 m³

R = 8.314 J/(mol·K)

T = 313.5 K

\([n = \frac{1.207 \times 10^5 \text{ Pa}}{\cancel{\text{Pa}}} \cdot \frac{1.208 \text{ m}^3}{\cancel{\text{m}^3}} \cdot \frac{\cancel{\text{J}}}{8.314 \text{ J}/\cancel{\text{mol}\cdot\text{K}}} \cdot \frac{\cancel{\text{K}}}{313.5 \cancel{\text{K}}} = 0.500 \text{ mol}]\)

Simplifying the expression:

n ≈ 61.21 mol

Finally, to calculate the mass of dinitrogen, we need to multiply the number of moles by the molar mass of N₂, which is approximately 28 g/mol:

Mass = n * molar mass

Mass ≈ 61.21 mol * 28 g/mol

Mass ≈ 1715.88 g

Therefore, the mass of dinitrogen in the balloon is approximately 1715.88 grams.

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The molarity of the NaOH solution is 0.0754 M. Answer: 0.0754 M.

Molarity can be defined as the number of moles of solute present in per liter of solution. To calculate the molarity of the NaOH solution, we need to use the given information. Given that 35.22 mL of NaOH solution completely neutralizes a solution containing 0.544 g of KHP.We can use the formula for molarity:

Molarity = (mass of solute / molar mass of solute) / volume of solution in L

First, we need to calculate the number of moles of KHP.Number of moles of KHP = mass of KHP / molar mass of KHP

Number of moles of KHP = 0.544 / 204.22 = 0.00266 mol

Now, we can use the balanced chemical equation for the reaction between NaOH and KHP:

NaOH + KHC8H4O4 → KNaC8H4O4 + H2O

From the equation, we can see that one mole of NaOH reacts with one mole of KHP. Therefore, the number of moles of NaOH used in the reaction is also 0.00266 mol.Since the volume of the NaOH solution used is 35.22 mL, we need to convert it into liters.Volume of NaOH solution used = 35.22 mL = 0.03522 L

Now we can calculate the molarity of the NaOH solution:

Molarity = number of moles / volume of solution

Molarity = 0.00266 / 0.03522

Molarity = 0.0754 M

Therefore, the molarity of the NaOH solution is 0.0754 M. Answer: 0.0754 M.

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a. 1, 1, 1

N+H--------NH

In the above intermediate chemical equation, oxygen will appear as follows: O₂(g) as a reactant (option B).

A chemical equation in chemistry is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

According to this question, an intermediate chemical equation is presented as follows:

As observed in the above chemical equation, oxygen will react in its gaseous form i.e. as a reactant.

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PNew  = 3/2 P.

Here, PNew is the new pressure generated in the sealed container by the Ideal gas law, when the volume is doubled and the temperature is tripled. Ideal gases are the gases which follows Ideal gas properties.

According to Ideal gas law,

PV= nRT

P = nRT / V

Now,

VNew  = 2V

TNew = 3T

So, the change in pressure will be

PNew  VNew  = nRTNew

PNew (2V)=  nR(3T)

PNew  = 3/2 (nRT / V)

PNew  =3/2 P.

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ClO3-: The chlorine atom carries a single negative charge.

ClO4-: The chlorine atom carries a single negative charge.

NO3-:The nitrogen atom does not carry any charge, and the molecule as a whole carries a single negative charge.

Certainly! Here are the drawings of the molecules you requested:

1. ClO3-

   O

    |

Cl - O

    |

   O [-

2. ClO4-

   O

    |

Cl - O

    |

   O

    |

   O [-

3. NO3-

   O

    ||

N - O

    |

   O [-

4. SO3

 O

 ||

S - O

 ||

 O

Please note that for SO3, it does not carry any charge (neutral molecule), as requested.

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Answer:

6.5 octillion (that's 6,500,000,000,000,000,000,000,000,000) atoms.

Explanation:

:)

Answer:

Writing an efficient conclusion in a report involves summarizing the main findings or outcomes of the report and offering a final perspective on the subject matter. Here are some tips for writing an efficient conclusion in a report:

Remember, an efficient conclusion should be brief and to the point. It should summarize the main points of the report and provide a clear and concise perspective on the subject matter.

To calculate the molarity of a solution, you need to know the number of moles of the solute (OsF3) and the volume of the solution in liters.

First, let's calculate the number of moles of OsF3:

Molar mass of OsF3 = 247.224 g/mol

Mass of OsF3 in the beaker = 217 grams

Number of moles of OsF3 = Mass of OsF3 / Molar mass of OsF3

= 217 g / 247.224 g/mol

Next, we need to calculate the volume of the solution in liters:

Volume of the solution = 0.0673 liters

Now we can calculate the molarity:

Molarity = Number of moles of solute / Volume of solution

Substituting the values, we get:

Molarity = (217 g / 247.224 g/mol) / 0.0673 L

Calculating this expression, we find the molarity of the OsF3 solution.

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Explanation:

There are certain metals that are less reactive compared to standard hydrogen electrode.

So, such metals do not release hydrogen gas in a reaction with dilute acids.

Examples of such metals are:

copper,silver,gold,platinum,mercury.

Answer:

A burning match stick is brought

near the mouth of the test tube, but no sound is

heard. That means hydrogen gas is not released in this reaction and the metal may be a less reactive metal and it is one among the above list of metals.

Answer:

in fractional distillation we look at different boiling point of the mixture

Explanation:

argon will be separated from the mixture first because it has the lowest boiling point

The mixture of elements of gases of neon,argon, krypton and xenon can be separated using  fractional distillation as the  have difference in their boiling points.

An element is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.

Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.

The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with same atomic number are atoms of same element.

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