As the car is moving in a circle, the centripetal force, F acting on the car is given as F = mv² / r
The maximum force of static friction that can act on the car is given as f = μsN
where μs is the coefficient of static friction, and N is the normal force acting on the car.
Substituting the values in the formula, we get\(N = mg = 1500 kg × 9.8 m/s² = 14700 N\)
where g is the acceleration due to gravity.
Substituting the values in the formula, we get f = μsN= μs × 14700 N
The maximum value of the force of static friction is given as f = μsN.The centripetal force is given as F = mv² / r
Substituting the maximum value of the force of static friction in the formula, we getμsN = mv² / r
Substituting the values, we get
\(μs × 14700 N = 1500 kg × (23 m/s)² / 65 mμs = (1500 kg × (23 m/s)² / 65 m) / 14700 Nμs = 0.738\)
This means that the minimum coefficient of static friction required to keep the car on the curve is 0.738.
Therefore, the minimum value of the coefficient of friction which would be required to keep Justin's car on the curve is 0.738.
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how far can the center of the box be from the end of the table before the board begins to tilt?
Based on the moment of the forces, the distance the center of the box will be from the end of the table before the board begins to tilt is a distance greater than 14 cm.
What distance will the center of the box be from the end of the table before the board begins to tilt?The distance the center of the box will be from the end of the table before the board begins to tilt is calculated as follows:
The fulcrum is the edge of the table
The downward force acting on the left-hand side of the board = 3/5 x 7
The downward force acting on the left-hand side of the board = 4.2 kg. This force acts at the center of gravity = 15 cm or 0.15 m
The moment on the left side = 4.2 x .15 = 0.63 kg/m.
The moment on the right side = (2/5 x 7) x 0.1 + 2.5 x y
where;
y is the distance from the end of the table.
The moment on the left side = The moment on the right side
0.63 = 0.28 + 2.5 * y
y = 0.14 m or 14 cm
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Complete question:
A thin 2.50 kg box rests on the edge of a 6.00 kg board of length 2m that hangs over the end of a table. How far can the center of the board be from the end of the table before the board begins to tilt?
What are the 5 types of electrical incidents?
Electrical burns can occur in a variety of ways, including arc burns, low voltage burns, high voltage burns, mouth burns, flash burns, and flame burns.
What are electrical incidents?Electric shock, a serious electrical mishap, or a fatal electrical event are all considered electrical incidents.
For the purposes of reporting and analysis, incident definition types let you attribute the appropriate type to safety events. Having only the two types of incidents—Accident and Near Miss—is one strategy.
An occurrence or scenario that has a number of serious repercussions and necessitates the implementation of special measures by one or more emergency responder agencies is referred to as a big incident.
Any electrical incident that results in or has the potential to result in: death or serious bodily harm to a person; significant property damage; or a serious risk to the public safety must be reported, according to the Electrical Safety (General) Regulations of 2019.
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i literally need mental help
Answer:
WDYM?
Explanation:
Answer: Get therapy (not like actually lol but like you know...)
Explanation: Listen to calming music or your favorite music, read, draw, color, literally anything that makes you calm
which of the following is true of inertia
a) it is a property of motion
b) it is measured by weight
Answer:
it is a property of motion
A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 76.8 m/s2 for 1.99 seconds, at which point its fuel abruptly runs out. Air resistance has no effect on its flight. What maximum altitude (above the ground) will the rocket reach?
Answer:
Explanation:
Take note that when the fuel of the rocket is consumed, the acceleration would be zero. However, at this phase the rocket would still be moving up until all the forces of gravity would dominate and change the direction of the rocket. Hence, there will be a need to calculate two distances, one from the ground until the point where the fuel is consumed and from that point to the point where the gravity would change the direction.
Given:
a = 76.8 m/s^2
t = 1.99 s
Solution:
d = vi (t) + 0.5 (a) (t^2)
d = (0) (1.99) + 0.5 (76.8) (1.99)^2
d = 0+38.4×3.9601
d = 152.068m
vf = vi + at
vf = 0 + 76.8 (1.99)
vf = 152.83 m/s (velocity when the fuel is consumed completely)
Then, we calculate the time it takes until it reaches the maximum height.
vf = vi + at
0 = 152.83+(-9.8) (t)
0 = 152.83 + (-9.8) (t)
-152.83 = -9.8t
t = 152.83/9.8 s
t = 15.59s
Then, the second distance
d= vi (t) + 0.5 (a) (t^2)
d = 152.83 (15.59) + 0.5 (-9.8) (15.59^2)
d = 2382.6197- 1190.93
d = 1191.68m
Then, we determine the maximum altitude:
d1 + d2 = 152.068 m + 1191.68m = 1343.748m
6. The star nearest to our Sun is Alpha Centauri, which is 4.3 light years away. A light
year is the distance that light travels in one year. 1 light year is about
9,500,000,000,000kilometers. Again, use the unit cancelation technique:
How many astronomical units is it to Alpha Centauri? HELP
Answer:
273,000 Astronomical Units.
Explanation:
4.3 light years = 40,850,000,000,000 kilometeres, 4.3 x 9,500,000,000,000.
Convert kilometers to astronomical unit:
149,597,870 kilometers = 1 AU, convert unit.
40,850,000,000,000 divided by 149,597,870 = 273,065.385222 or approx. 273,000 AU.
I need help with this ASAP.. it was due today
Answer:
4:Hhhhghhhhhhhhhhhhhhhhhhhhhhhhhhhhh. 5:Bbbbbbbbbbbbbbbbbbbbb
5. Determine What factors affect the strength
of the gravitational force between objects?
Provide an example. SC.8.E.5.4
The two key factors that affect the strength of the gravitational force between objects are their mass and the distance between them.
The factors that affect the strength of the gravitational force between objects are:
1. Mass of the objects: The strength of the gravitational force increases with the increase in mass of the objects involved.
2. Distance between the objects: The strength of the gravitational force decreases with the increase in distance between the objects.
In summary, the strength of the gravitational force between objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. This relationship is described by Newton's law of universal gravitation.
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2. 2 "However, we need to examine our environment, and ask problematic questions such as,
"whose law?" Obviously, it's the law of the dominant class in that society (Study Guide,
p. 7)
Which class does the South African law, including the constitution, serve? Explain fully. (3)
The law in South Africa, including the constitution, serves the interests of the dominant class, which historically has been the white minority. During apartheid, the law was used to enforce segregation and discrimination against the majority black population.
While the constitution and laws have since been revised to promote equality and protect human rights, there are still systemic issues that continue to serve the interests of the wealthy and powerful.
For example, land ownership remains highly concentrated in the hands of a few, and the legal system can be slow and expensive, making it difficult for marginalized communities to access justice. Additionally, the legacy of apartheid-era policies and practices continues to impact access to education, healthcare, and economic opportunities for many black South Africans.
Overall, while progress has been made in addressing inequality and promoting social justice, the law in South Africa still reflects the interests of the dominant class and requires continued efforts to ensure that it serves the needs of all citizens.
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What is meant by the statement "Motion is relativel"?
Answer:
when an object move from its place is called an mation
To win the game, a place kicker must kick a
football from a point 37 m (40.4632 yd) from
the goal, and the ball must clear the crossbar,
which is 3.05 m high. When kicked, the ball
leaves the ground with a speed of 21 m/s at
an angle of 35.8
◦
from the horizontal.
The acceleration of gravity is 9.8 m/s
2
.
By how much vertical distance does the ball
clear the crossbar?
Answer in units of m.
We know that the vertical clearance of the crossbar by the ball is x=1.57m.
Clear the crossbar: What does that mean?From a point 36.0 m from the goal, a place kicker must kick a football. The ball must clear the 3.05 m-high crossbar as a consequence of the kick. The ball kicks off the ground with a speed of 20.0 m/s at an angle of 53° from the horizontal.
v=18cos48 m/s
Time is therefore defined as distance multiplied by speed, which equals 28/18cos48 divided by 48, or 2.324
Use s = ut + (0.5)a(t2) when resolving vertically.
Where is the unidentified distance, s? (the height above the GROUND)
initials are u (vertical) 18 divided by 48 gives a speed of -9.8 meters per second (negative since we take upwards as positive)
t = 2.3247... (what we found previously) (what we found previously)
Adding the figures to the formula gives 4.616
Subtracting the goalpost's height (3.05) results in 1.57m above the crossbar, or 1.56.
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at what minimum speed must a roller coaster be traveling when upside down at the top of a circle so that the passengers do not fall out? assume a radius of curvature of 7.1 m
The roller coaster must be traveling at a minimum speed of approximately 8.81 m/s (or 31.7 km/h) at the top of the loop to prevent passengers from falling out.
To determine the minimum speed required for a roller coaster to prevent passengers from falling out at the top of a circular loop, we can use the concept of centripetal force. At the top of the loop, the net force acting on the passengers should provide enough centripetal force to keep them moving in a circular path without falling out.
The centripetal force required is provided by the gravitational force acting on the passengers. At the top of the loop, the gravitational force and the normal force (which acts perpendicular to the surface of the track) combine to provide the centripetal force.
The gravitational force is given by the equation:
Fgravity = m * g
Where m is the mass of the passenger and g is the acceleration due to gravity (approximately 9.8 m/s²).
The normal force at the top of the loop is equal to the gravitational force plus the centripetal force
Fnormal = Fgravity + Fcentripetal
The centripetal force is given by:
Fcentripetal = (m * v²) / r
Where v is the velocity of the roller coaster and r is the radius of curvature.
At the top of the loop, the net force acting on the passengers should be zero to prevent them from falling out, so we can set the normal force equal to zero:
Fnormal = 0
Fgravity + Fcentripetal = 0
m * g + (m * v²) / r = 0
Solving for v, we get:
v² = - (r * g)
Since the velocity cannot be negative, we take the positive square root:
v = √(r * g)
Substituting the given values
v = √(7.1 m * 9.8 m/s²)
v = 8.81 m/s
Therefore, the roller coaster must be traveling at a minimum speed of approximately 8.81 m/s (or 31.7 km/h) at the top of the loop to prevent passengers from falling out.
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A particle with an initial linear momentum of 2.00 kg-m/s directed along the positive x-axis collides with asecond particle, which has an initial linear momentum of4.00 kg-m/s, directed along the positive y-axis. The finalmomentum of the first particle is 3.00 kg-m/s, directed45.0?Above the positive x-axis. Find the final momen -tum of the second particle.
Answer:
Explanation:
We shall apply conservation of momentum along x and y axis.
Let the final momentum of second particle be p₁ along x axis and p₂ along y axis.
Considering momentum along x axis
2 + 0 = 3 cos 45 + p₁
p₁ = 2-2.12 = - 0.12 kg m/s
Considering momentum along y axis
4 + 0 = 3 sin 45 + p₂
p₂ = 4-2.12 = 1.88 kg m/s
Final momentum = √ ( p₁² + p₂² )
=√ ( .12² + 1.88² )
= 1.88 approx
How many bones does the baby have and why does the baby has more bones than the older ones
Answer:
300
Explanation:
when the baby are born then they would have 300 bones but when they grow they would have 206 cause when they grow that 94 bones would convert into different kind of proton and energy I guess
A cart is loaded with a brick and pulled up a ramp. If the mass of the loaded cart is 3.0 kg and the height of the seat top is 0.45 meters, then what is the potential energy of the loaded cart on top of the ramp?
Answer:
Potential energy = 13.23 J
Explanation:
Given that,
The mass of the loaded cart, m = 3 kg
Its height of the seat top is 0.45 m
We need to find the potential energy of the loaded cart on top of the ramp. We know that, the potential energy of an object is due to its height. It can be given by the formula as follows :
\(E=mgh\\\\E=3\ kg\times 9.8\ m/s^2\times 0.45\ m\\\\E=13.23\ J\)
So, the required potential energy is 13.23 J.
The electric force between two charged balloons is 0.12 newtons. If the distance between the two balloons is halved, what will be the new force?
A.
0.03 newtons
B.
0.06 newtons
C.
0.36 newtons
D.
0.48 newtons
Answer:
d. 0.48
Explanation:
I still Cube 100 mm on a sideways 80 Newtons. We want to hold the cube in equilibrium underwater by attaching a light foam buoy to it. If the phone weighs 470 Newtons per meter cube, what is the minimum required volume of the buoy
So, the minimum required volume of the foam buoy is approximately 0.00176 cubic meters.
we'll first need to calculate the buoyancy force required to counteract the 80 Newtons force acting on the cube. Then, we'll use the density of the foam to determine the volume of the foam needed to generate that buoyancy force.
Step 1: Calculate the buoyancy force needed, The cube is acted upon by a sideways force of 80 Newtons. To hold the cube in equilibrium underwater, the buoy must provide an equal and opposite buoyancy force of 80 Newtons.
Step 2: Determine the density of the foam
The foam weighs 470 Newtons per cubic meter.
Step 3: Calculate the volume of the foam required
To find the volume (V) of the foam required, we'll use the formula for buoyancy force:
Buoyancy force = Density of foam × Volume of foam × Acceleration due to gravity (g)
We'll rearrange the formula to solve for the volume:
Volume of foam = Buoyancy force / (Density of foam × g)
We know that the buoyancy force is 80 Newtons, the density of foam is 470 N/m³, and the acceleration due to gravity (g) is approximately 9.81 m/s².
Plugging these values into the formula:
V = 80 N / (470 N/m³ × 9.81 m/s²)
V ≈ 0.00176 m³
So, the minimum required volume of the foam buoy is approximately 0.00176 cubic meters.
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The big five personality trait affects people negatively if they have to much of it? Which trait is it?
The term personality traits has to do with the essentials of a person. One of the five big personality trait that affects people negatively if they have to much of it is neuroticism.
Personality traitsThe term personality traits refers to those traits that characterize an individual. They have the capacity to affect a person positively or negatively.
One of the five big personality trait that affects people negatively if they have to much of it is neuroticism.
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temperature is a measure of the average energy of particles in a substance.
a. true
b. false
Temperature is a measure of the average energy of particles in a substance is true.
Temperature is indeed a measure of the average energy of particles in a substance. Temperature reflects the kinetic energy of the particles, which is related to their random motion. In a substance, the particles are in constant motion, and their individual energies contribute to the overall temperature of the substance. A higher temperature indicates that, on average, the particles possess greater energy and are moving more vigorously. Conversely, a lower temperature signifies lower average energy and slower particle motion. Temperature is typically measured using various scales, such as Celsius, Fahrenheit, or Kelvin, and it serves as a fundamental parameter in thermodynamics and many other scientific disciplines.
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what must be the pressure difference between the two ends of a 1.6km section of pipe, 29 cm in diameter, if it is to transport oil (p= 950 kg/m3 ,n = 0.20 Pa. s) at a rate of 650 cm3/s?
Answer:
The pressure difference required between the two ends of the 1.6 km pipe section, with a diameter of 29 cm, to transport the oil at a rate of 650 cm^3/s, is approximately 0.398 Pa.
Explanation:
To calculate the pressure difference between the two ends of a pipe, we can use the Poiseuille's Law equation, which relates flow rate, viscosity, pipe length, diameter, and pressure difference.
The formula is as follows: ΔP = (8 * n * L * Q) / (π * r^4)
Where:
ΔP is the pressure difference,
n is the viscosity of the fluid,
L is the length of the pipe section,
Q is the flow rate,
and r is the radius of the pipe (half of the diameter).
Given:
L = 1.6 km = 1600 m (convert to meters)
Diameter = 29 cm
Radius (r) = 29 cm / 2 = 14.5 cm = 0.145 m (convert to meters)
Q = 650 cm^3/s = 650 * 10^-6 m^3/s (convert to cubic meters per second)
n = 0.20 Pa.s (viscosity)
p = 950 kg/m^3 (density)
ΔP = (8 * 0.20 * 1600 * 650 * 10^-6) / (π * (0.145)^4)
ΔP ≈ 0.398 Pa
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What is a force that opposes motion through direct contact?
The force that opposes motion through direct contact is called friction. It is caused by the interaction and deformation of the roughness in the contacting surfaces.
Friction is the force that opposes the relative motion or tendency of such motion of two surfaces in contact. It is caused by the interaction and deformation of the roughness in the contacting surfaces. It is, therefore, a contact force. When an object is set in motion, it continues to move unless stopped by an external force. There are a number of factors that can alter the velocity of an object that is already in motion. One of the most important factors is friction. Friction is a force that opposes motion through direct contact between two surfaces. This means that when an object is moving along a surface, it experiences a force that tries to slow it down. The amount of friction between two surfaces depends on a number of factors. One of the most important factors is the nature of the surfaces themselves. Rougher surfaces tend to generate more friction than smoother ones. This is because the roughness of the surface creates more contact points between the two surfaces, which in turn generates more friction. Another factor that affects the amount of friction between two surfaces is the amount of force pressing the two surfaces together.
In conclusion, friction is a force that opposes motion through direct contact between two surfaces. It is caused by the interaction and deformation of the roughness in the contacting surfaces. It depends on a number of factors, including the nature of the surfaces themselves and the amount of force pressing the two surfaces together.
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a limited access zone for masonry construction should?
A limited access zone is an area next to a masonry wall that is being built and is clearly marked to restrict access by workers.
The restricted area must extend the entire length of the wall and have a height equivalent to the height of the proposed wall plus four feet. On the un-scaffolded side of the wall, a limited access zone must be formed. For a maximum wall height of 10.668 meters, the load-bearing masonry wall should be at least 304.8 mm (1 foot) thick (35 ft.). Additionally, for every additional 10.668 meters, the brick wall's thickness must be increased by 101.6 mm (4 inches) (35 ft).
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A 2.1W iPod is used for 30 minutes. How much energy does it use?
a generator supplies 80 v to a transformer's primary coil, which has 59 turns. if the secondary coil has 530 turns, what is the secondary voltage?
The primary coil of a transformer, which has 59 turns, receives 80 v from a generator. The secondary voltage will be 530 if the secondary coil has 530 turns IS 718.644 V
For an ideal transformer
Vs/Vp=Ns/Np
Given that primary voltage V =80 V
Number of turns in primary N = 59 turns
Number of turns in srcondary Ng = 530 turns
Therefore
Vs/80=530/59
Hence voltage across secondary V = 8.98*80 V
=718.644 V.
Voltage is the quantity of potential charge that exists between two points on a circuit. One idea is charge more strongly than another. Voltage refers to the difference in charge between the two points. Volt, denoted by the symbol "V," is the accepted unit of measurement for the voltage expression.
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You use a knife to cut a piece of bread. What kind of simple machine are you
using?
A. Wedge
B. Inclined plane
C. Screw
O D. Lever
Answer:
the answer is A.) Wedge
A knife to cut a piece of bread is a A. Wedge
What is a simple machine?
A simple machine, any of several devices with few or no moving parts that are used to modify motion and the magnitude of a force in order to perform work.
since , a wedge is a simple machine with two inclined planes which when put together forms a sharped edge, which forms a triangular shaped tool which can be used to separate portion of two objects .
hence , a knife to cut a piece of bread is a A. Wedge
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how fast would a(n) 73 kgkg man need to run in order to have the same kinetic energy as an 8.0 gg bullet fired at 430 m/sm/s ?
Answer:
an 85 kg person run to equal the kinetic energy of an 8.0 g bullet fired at 410 m/s? The speed is, it might be argued,
v=4.0m/s
Explanation:
Typically, the mathematical formula for kinetic energy is as follows:
KE=\(\frac{1}{2} *m*v^{2}\)
K.E= kinetic energy
M=mass
V= speed
so,
KE=1/2*0.008*(420)*420
K.E=672.4J
Therefore,
v*v=672.4/85
v*v=15.821
v=4.0m/s
Therefore
v=4.0m/s
What is Kinetic Energy?
The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity.
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What will the unknown angle 0 be
in order for the pulley system to
the right to be in static equilibrium?
Note that the 80 N weight is
attached to a free-moving pulley,
and the cable is fastened to the
wall on the left.
In the system to the right, the pulleys
2.0 m
80 N
fixed
pulley
400 N
The pulley system to the right will be in static equilibrium at an unknown angle of 90 degrees.
What circumstances must an object meet in order to be in static equilibrium?An object must satisfy two requirements of equilibrium in order to maintain static equilibrium. First, there must be no net force acting on the item. Second, there must be no net torque pulling on the object.
The 80 N weight is fastened to a freely rotating pulley in this setup.
As a result, the cable's tension is also 80 N.
The tensions' x components must be balanced against one another:
T1x = T2x
Since T1x = T1 cos(θ) and T2x = 0 (because the cable attached to the wall is vertical), we have:
T1 cos(θ) = 0
Therefore, cos(θ) = 0, which means that θ = 90 degrees.
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A dog starts running after a squirrel. Originally the dog traveled at 3m/s
North, and then he picked up speed to 9m/s. After 13s he caught the
squirrel, what is his acceleration?
0.56 m/s^2
0.46 m/s^2
0.75 m/s^2
0.35m/s^2
Answer:0.46 m/s^2.
Explanation:
The acceleration of the dog can be calculated by using the formula:
acceleration = (final velocity - initial velocity) / time
The initial velocity of the dog was 3 m/s, the final velocity was 9 m/s, and the time was 13 seconds.
acceleration = (9 m/s - 3 m/s) / 13 s = 0.46 m/s^2
Therefore, the acceleration of the dog was 0.46 m/s^2.
6.
1273
NOT TO SCALE. All coordinates in inches.
The dimension given for the hole is its diameter.
Assume uniform thickness and density.
Here is your shape drawn to scale:
This problem DOES need to be written out for your portfolio.
EXAMPLE
PartDescriptionAnswerChkHistoryA.What is the area of the object shown above?
(include units with answer)
Format Check

5 pts.50%
2% try penalty
Hints: 1,2# tries: 0B.What is the X coordinate of the center of mass the object shown above?
(include units with answer)
Format Check

7.5 pts.50%
2% try penalty
Hints: 3,1# tries: 0C.What is the Y coordinate of the center of mass the object shown above?
(include units with answer)
Format Check

7.5 pts.50%
2% try penalty
Hints: 1,1# tries: 0
A. The area of the object can be calculated by breaking it down into smaller shapes and adding their areas together. We can see that the object consists of a rectangle and a semicircle :
The dimensions of the rectangle are 6 inches by 2 inches. The diameter of the semicircle is 3 inches, so its radius is 1.5 inches. The area of the rectangle is 6 x 2 = 12 square inches. The area of the semicircle is (1/2) x π x (1.5)^2 = 3.53 square inches.Therefore, the total area of the object is 12 + 3.53 = 15.53 square inches. Answer:
15.53 square inchesB. To find the X coordinate of the center of mass, we need to find the centroid of the object. The centroid is the point where the object would balance if it were placed on a pin. The X coordinate of the centroid can be found using the formula:
Xc = (A1x1 + A2x2 + ... + Anxn) / (A1 + A2 + ... + An)Where A is the area of each shape and x is the distance from the centroid of each shape to the Y axis.
We can break the object down into a rectangle and a semicircle, and find the centroid of each shape separately.The centroid of a rectangle is at the center, which is at (3,1). The centroid of a semicircle is at (4/3, 4/3) from the center of the circle. Therefore, the X coordinate of the centroid of the semicircle is at 3 + (4/3) = 4.33. We can now use the formula to find the X coordinate of the centroid of the object: Xc = (A1x1 + A2x2) / (A1 + A2) = ((6 x 2 x 3) + (1/2 x π x 1.5^2 x 4.33)) / (12 + 3.53) = 2.9 inches.
The Answer:
2.9 inchesC. To find the Y coordinate of the center of mass, we can use a similar formula:
Yc = (A1y1 + A2y2 + ... + Anyn) / (A1 + A2 + ... + An) where y is the distance from the centroid of each shape to the X axis.The Y coordinate of the centroid of the rectangle is at 0.5, and the Y coordinate of the centroid of the semicircle is at 2/3 from the center of the circle. Therefore, the Y coordinate of the centroid of the semicircle is at 1 + (2/3) = 1.67. We can now use the formula to find the Y coordinate of the centroid of the object: Yc = (A1y1 + A2y2) / (A1 + A2) = ((6 x 2 x 0.5) + (1/2 x π x 1.5^2 x 1.67)) / (12 + 3.53) = 1.07 inches.
The Answer:
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A 1500 kg car is accelerated by a force of 2000 N for 15 s.
What is the acceleration of the car?
If the car started at rest, how fast is the car going after 15s? (1pts)
How far (∆x) would the car have traveled after the 15s? (1pts)
By Newton's second law, the car has acceleration a such that
2000 N = (1500 kg) a
a = (2000 N) / (1500 kg)
a = 4/3 m/s² ≈ 1.33 m/s²
After 15 s, the car will attain a speed of
(4/3 m/s²) (15 s) = 20 m/s
It will have traveled a distance ∆x such that
(20 m/s)² - 0² = 2 (4/3 m/s²) ∆x
∆x = (20 m/s)² / (8/3 m/s²)
∆x = 150 m