Project Objective
The objective of this project is to use an integrated development environment (IDE) such as NetBeans or Eclipse to develop a java program to practice various object-oriented development concepts including objects and classes, inheritance, polymorphism, interfaces, and different types of Java collection objects.
Project Methodology
✓ Students shall form groups of two (2) students to analyze the specifications of the problem statement to develop a Java program that provides a candidate solution of the presented problem.
✓ Submission of the project shall be via YU LMS no later than 19-05-2022 (late submissions are accepted with a penalty of 10% for each day after the deadline).
Problem Statement
Your team is appointed to develop a Java program that handles part of the academic tasks at Al Yamamah University, as follows:
• The program deals with students’ records in three different faculties: college of engineering and architecture (COEA), college of business administration (COBA), college of law (COL), and deanship of students’ affairs.
• COEA consists of four departments (architecture, network engineering and security, software engineering, and industrial engineering)
• COBA consists of five departments (accounting, finance, management, marketing, and management information systems).
• COBA has one graduate level program (i.e., master) in accounting.
• COL consist of two departments (public law and private law).
• COL has one graduate level program (i.e., master) in private law.
• A student record shall contain student_id: {YU0000}, student name, date of birth, address, date of admission, telephone number, email, major, list of registered courses, status: {active, on-leave} and GPA.
• The program shall provide methods to manipulate all the student’s record attributes (i.e., getters and setters, add/delete courses).
• Address shall be treated as class that contains (id, address title, postal code)
• The deanship of students’ affairs shall be able to retrieve the students records of top students (i.e., students with the highest GPA in each department). You need to think of a smart way to retrieve the top students in each department (for example, interface).
• The security department shall be able to retrieve whether a student is active or not.
• You need to create a class to hold courses that a student can register (use an appropriate class-class relationship).
• You cannot create direct instances from the faculties directly.
• You need to track the number of students at the course, department, faculty, and university levels.
• You need to test your program by creating at least three (3) instances (students) in each department.

A risk register is a log of all potential hazards, risks, and uncertainties that a project may encounter. It also has an explanation of the probability of the danger occurring and its potential impact.

A risk register's purpose is to assist in the identification, assessment, and management of risks associated with a project and is an essential part of a successful risk management strategy. As such, the risk register has six components, including the risk description, risk cause, impact, risk likelihood, risk impact, and risk ranking.The following are six potential hazards for Project A and their explanations:

1. Weather Issues: Bad weather can slow down the construction process, make it dangerous to work outside, or damage materials.

2. Availability of Materials: If materials are scarce, it can delay or halt the construction project.

3. Time Constraints: Limited time can result in project delays or cutting corners, which can impact the quality of work.

4. Cost Overruns: Unexpected or uncontrollable costs can result in the project being halted or completed poorly.

5. Inadequate or Faulty Tools: This can affect work quality, safety, and efficiency, ultimately impacting the project schedule and costs.

6. Safety Issues: Inadequate safety protocols can result in accidents that could lead to injury or death of workers on the site.In conclusion, the risk register for Project A should outline potential hazards, their causes, impact, likelihood, and ranking, as well as mitigation strategies. The risk register should be reviewed and updated regularly to ensure that new risks are identified and addressed.

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Answer:

import java.util.*;

class fibonacci

{

public static void main(String args[])

{

Scanner scanner = new Scanner(System.in);

int n1=0,n2=1,n3,i,count;

count = scanner.nextInt();  

 System.out.print(n1+" "+n2);//printing 0 and 1    

 for(i=2;i<count;++i)  

  {    

   n3=n1+n2;    

   System.out.print(" "+n3);    

   n1=n2;    

  n2=n3;    

  }    

}

}

Explanation:

When replacing a transformer in an electric heating system, the technician should always check several things to prevent the new transformer from failing like the old one.

These things include the following:1. Power Supply: Check the power supply that feeds the transformer and verify that it's the right voltage. Make sure the transformer is being supplied with the correct voltage and frequency. Also, check for any loose wiring or connections that could cause voltage drops.

If the voltage is too high or too low, it can cause the transformer to fail.2. Load: Verify the electrical load that the transformer is serving and ensure that it is within the transformer's rated capacity. If the load is too high, it can cause the transformer to overheat and fail. If the load is too low, it can cause the transformer to burn out due to insufficient cooling.3. Grounding: Check the transformer's grounding connection to ensure it is connected correctly.

If the grounding is poor, it can cause voltage surges, which can damage the transformer.4. Protection: Check the transformer's protection circuitry to make sure it is working correctly. The protection circuitry is designed to protect the transformer from overloads, overcurrents, and short circuits.

If the protection circuitry is faulty, the transformer can fail.5. Environmental factors: Verify the environmental factors that may be affecting the transformer's operation. Things like temperature, humidity, and vibration can affect the transformer's operation. If the transformer is exposed to high temperatures or vibration, it can cause the winding insulation to break down, which can cause the transformer to fail.

Therefore, when replacing a transformer in an electric heating system, the technician should always check the power supply, load, grounding, protection circuitry, and environmental factors to ensure that the new transformer does not fail like the old one.

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The demarc is located ​in the Main Distribution Frame (MDF). The correct option is D.

What is Main Distribution Frame (MDF)?

In telephony, a Main Distribution Frame (MDF) is a signal distribution frame or cable rack that connects and organizes telecommunication wiring between itself and any number of intermediate distribution frames and cabling from the telephony network it serves.

A communications facility's internal equipment is connected to wires and subscriber carrier equipment by the MDF. Each cable used to serve user telephone lines arrives at an MDF where it is distributed to local exchange equipment.

In comparison to a patch panel, an MDF can offer greater freedom when allocating telecommunications facilities at a lower cost. The most typical type of MDF is a lengthy, two-sided steel board.

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Answer:

V= 90h cm³ where h is the height of the rectangular prism.

Explanation:

The formula for volume of a rectangular prism is ;

V=l*w*h  where;

V=volume in cm³

l= length of prism=10cm

w =width of the prism = 9 cm

Assume the height of the prism as h cm then the volume will be;

V= 10* 9*h

V= 90h cm³

when the value of height of the prism is given, substitute that value with h to get the actual volume of the prism.

More cooking is done before the water actually begins to boil thanks to the raised pressure inside the cooker, which raises the boiling point of water above 1000C. In the end, food cooks more quickly.

Slow-cooked meals can be quickly prepared with pressure cookers. They are efficient in terms of electricity consumption and are excellent for tenderizing less expensive portions of meat. They are a healthy cooking method since they effectively retain nutrients and can cut cooking times by up to 50%. Water boils at 121°C (250°F) at that pressure. As a result, food may cook at considerably greater temperatures than it could under atmospheric pressure. Additionally, because cooking reactions quicken at higher temperatures, food cooks more quickly it is a good technology.

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Answer:

  0°

Explanation:

The resistor voltage has the same phase as the circuit current. There is no phase difference.

Answer:

Explanation:

6.25×10⁻¹⁸ electrons will flow through a copper wire.

Electrons can be defined as the sum of atomic particles that is the career of negative charge, they are responsible for the chemical property of an element, the electrons are present in the shell.

Use formula ( I = ne/t )

Here,

number of electron

electron =1.6 x 10¯¹9 C

We have a relation between charge and current as

Charge = Current×time i.e

Q = i×t.

Now we have current = 10 amp & time = 10sec from given data.

Therefore charge Q = 10×1 = 100 coulombs.

Again we have a relation between charge and no of electrons

I.e no of electrons= total charge / 1.6×10⁻¹⁹

So, no of electrons = ( 100C/1.6×10⁻¹⁸ )

= 6.25×10⁻¹⁸ electrons.

Therefore, 6.25×10⁻¹⁸ electrons will flow through a copper wire carrying 10 amps current for 10 sec

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With the use of a project management portal system, your team can manage all projects, exchange documents, allocate duties to other team members, and more. Internal users are able to provide more input to projects by watching their progress via the portal, which results in higher-quality work.

Similar to single sign-on (SSO) software, businesses utilize portals to build central, easily accessible platforms for everything from digital dashboards to application access points.

Therefore, The usage of portal software, a development tool, enables users to designate a starting point for accessing and navigating intranets.

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Answer:

1) ∀x [ Tiger(x) → Fast(x) ]

2) эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]

3) ∀x [ Prime(x) → Odd(x) ]

4) ∀x [ prime (x) ∧  ~Two(x) → Odd (x) ]

5) ∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]

6) ∀xэy [ I(x) → greater (y, x) ]

Explanation:

Translating the statements into first Order Logic and their negations

1)   All tigers are fast. Domain: animals.

∀x [ Tiger(x) → Fast(x) ]

2)  Some tigers are fierce and dangerous. Domain: animals

эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]

3) Every prime number is odd. Domain: positive integers

∀x [ Prime(x) → Odd(x) ]

4)  All prime numbers except two are odd. Domain: positive integers

∀x [ prime (x) ∧  ~Two(x) → Odd (x) ]

5) All fruits are either yellow or red. Domain: produce.

∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]

6) For every integer number, there exist a bigger integer. Domain: integers.

∀xэy [ I(x) → greater (y, x) ]

Answer:

Answer:

1) ∀x [ Tiger(x) → Fast(x) ]

2) эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]

3) ∀x [ Prime(x) → Odd(x) ]

4) ∀x [ prime (x) ∧  ~Two(x) → Odd (x) ]

5) ∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]

6) ∀xэy [ I(x) → greater (y, x) ]

Explanation:

Translating the statements into first Order Logic and their negations

1)   All tigers are fast. Domain: animals.

∀x [ Tiger(x) → Fast(x) ]

2)  Some tigers are fierce and dangerous. Domain: animals

эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]

3) Every prime number is odd. Domain: positive integers

∀x [ Prime(x) → Odd(x) ]

4)  All prime numbers except two are odd. Domain: positive integers

∀x [ prime (x) ∧  ~Two(x) → Odd (x) ]

5) All fruits are either yellow or red. Domain: produce.

∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]

6) For every integer number, there exist a bigger integer. Domain: integers.

∀xэy [ I(x) → greater (y, x) ]

Explanation:

Semiconductors are formed by doping pure semiconductor materials. Examples include silicon, germanium, gallium arsenide, and indium phosphide. They are used in integrated circuits, transistors, solar cells, LEDs, lasers, and sensors, among other applications.

Semiconductors are formed through a process called doping, which involves intentionally adding impurities to a pure semiconductor material. The impurities, known as dopants, can introduce extra electrons (n-type doping) or electron deficiencies called holes (p-type doping) into the semiconductor lattice structure.

Examples of semiconductor materials include:

1. Silicon (Si): Silicon is the most widely used semiconductor material. It is abundant, has a well-developed manufacturing infrastructure, and exhibits good electrical properties for various applications.

2. Germanium (Ge): Germanium was one of the first materials used as a semiconductor. It has similar properties to silicon but is less commonly used in modern applications.

3. Gallium Arsenide (GaAs): Gallium arsenide is a compound semiconductor with superior electronic properties compared to silicon. It is used in high-speed devices such as microwave amplifiers, laser diodes, and solar cells.

4. Indium Phosphide (InP): Indium phosphide is another compound semiconductor that finds applications in telecommunications, fiber-optic networks, and high-frequency electronics.

Semiconductors are used in a wide range of electronic devices and technologies, including:

- Integrated Circuits (ICs): Semiconductors form the foundation of ICs, such as microprocessors, memory chips, and sensors, which are used in computers, smartphones, and various electronic devices.

- Transistors: Transistors, which are fundamental components of electronic circuits, are made using semiconductors. They are used in amplifiers, switches, and digital logic circuits.

- Solar Cells: Semiconductors like silicon and gallium arsenide are used in photovoltaic cells to convert sunlight into electricity.

- Light-Emitting Diodes (LEDs): LEDs use semiconductors to emit light efficiently and are used in displays, lighting, and optoelectronic applications.

- Semiconductor Lasers: Semiconductor lasers are used in telecommunications, optical storage devices, laser printers, and medical equipment.

- Sensors: Semiconductors are employed in various sensors, including temperature sensors, pressure sensors, gas sensors, and image sensors.

These are just a few examples of the widespread use of semiconductors in modern technology. Their unique electrical properties make them versatile for a wide range of applications.

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A monitor is implemented as a BCPL procedure, and any associated operations are declared as additional procedures inside the monitor. Prior to the procedure declarations, condition variables, initialized in the monitor body.

While smart TVs have special technology built in to improve picture quality, a smart monitor is smaller, so picture quality will still be sharp and clear. For games and watching movies, you also have a variety of viewing angles. A monitor is especially useful when there are several people involved in the adult's life or named in the Agreement. Meeting scheduling and information exchange can be facilitated by the monitor. If there is already tension or dispute between any of the persons involved, a monitor is also crucial. Monitors display data that has been processed by the computer's video card. Output is the term used to describe the processing outcome displayed on the monitor. The output gives you immediate feedback by displaying text and graphic pictures while you work or play.

A monitor to implement

monitor bounded_stack

buffer[max] // may contain at the most, max elements

full_slots = 0; // 0 < full_slots < max

condition notempty, notfull

deposit(x) {

if (full_slots == max) notfull.wait // or discard

stack.push(x)

full_slots = full_slots + 1

notempty.signal

}

remove(x) {

if (full_slots == 0) notempty.wait

stack.pop(x)

full_slots = full_slots - 1

notfull.signal

}

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Answer:

3216.99 cm³

Explanation:

To find the formula for the volume of a cylinder, we can use A x H, with A being the area of the base and H being the height of the cylinder. We can start with finding the area of the base, using the formula πr². The radius, r, is 1/2 of the diameter.

π * (16*1/2)² = 64π cm²

We can then multiply this base area by the height of the cylinder to get the volume

64πcm² * 16cm = 1024πcm³

We can then round this to the nearest 10th, resulting in 3216.99 cm³.

Answer:

\(X_t=2.17391304*10^{-4}\)

\(X_r=2.89855072*10^{-4}\)

\(e_t=0.0026\)

\(e_r=0.0035\)

Explanation:

From the question we are told that:

Dimension \(12*12\)

Thickness \(l_t=5mm=5*10^-3\)

Normal tensile force on top side \(F_t= 15kN\)

Normal tensile force on right side  \(F_r= 20kN\)

Elastic modulus, \(E=115Gpap=>115*10^9\)

Generally the equation for Normal Strain X is mathematically given by

 \(X=\frac{Force}{Area*E}\)

Therefore

For Top

 \(X_t=\frac{Force_t}{Area*E}\)

Where

 \(Area=L*B*T\)

 \(Area=12*10^{-2}*5*10^{-3}\)

 \(Area=6*10^{-4}\)  

 \(X_t=\frac{15*10^3}{6*10^{-4}*115*10^9}\)

 \(X_t=2.17391304*10^{-4}\)

For Right side\(X_r=\frac{Force_r}{Area*E}\)

Where

Area=L*B*T

 \(Area=12*10^{-2}*5*10^{-3}\)

 \(Area=6*10^{-4}\)  

 \(X_r=2.89855072*10^{-4}\)

 \(X_r=2.89855072*10^{-4}\)

Generally the equation for elongation is mathematically given by

 \(e=strain *12\)

For top

 \(e_t=2.17391304*10^{-4}*12\)

 \(e_t=0.0026\)

For Right

 \(e_r=2.89855072*10^{-4} *12\)

 \(e_r=0.0035\)

The graph could help an economist predict that how many people will be out of work in the next year. The correct option is c.

Unemployment is the condition where people who have knowledge or eligible for doing job, but they are not getting job. Unemployment is the scarcity of jobs.

The options are attached:

a. how the government will address unemployment.

b. why workers might have a harder time finding jobs.

c. how many people will be out of work in the next year.

d. why producers might hire fewer workers in the future.

Thus, the correct option is c. how many people will be out of work in the next year.

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Answer:

b. will continue to rise.

Complete Question:

This graph shows the US unemployment rate from August 2010 to November 2011.

This graph suggests unemployment in the United States

a. will continue to fall.

b. will continue to rise.

c. will remain the same.

d. will only change a little.

b. will continue to rise.

Hope I helped!

Answer:

Use this PDF file it should help you calculate total photon flux incident on the photodiode.

Explanation:

It's a file on lecture notes that help people learn about engineering and maybe in the lecture notes it might have information about how to calculate total photon flux incident on the photodiode

Answer:

improper imput validation

Explanation:

Answer:

V = 1.5062 m/s

Explanation:

look to the photos

Answer:

I think obisidian.

Explanation:

Because it's really strong actually in real life.

The value of the destination register r1 after the instruction MOV r1, pc completes will be the address of the next instruction to be executed, which is the memory address 0x0800016A.

What is register?
In computer architecture, a register is a small, high-speed memory storage location within a CPU (Central Processing Unit) that can be used to store and quickly access data that is currently being processed by the CPU.

Registers are used to hold operands, instructions, memory addresses, and other data used by the CPU during the execution of a program. Registers are typically built into the CPU chip and can be accessed much faster than other types of memory, such as RAM.


In ARM assembly language, pc is the program counter register, which contains the address of the current instruction being executed. So, the MOV r1, pc instruction copies the current value of the program counter register to the r1 register.
Since the MOV r1, pc instruction itself occupies 4 bytes of memory, the address of the next instruction to be executed will be 4 bytes ahead of the current instruction. Therefore, the value of r1 will be 0x0800016A.

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Answer:

(The diagram of the question is given in Attachment 1)

The largest load which can be applied is:

P=67.62 kN

Explanation:

All the forces are shown in the diagram in Attachment 2.

∑ F(y)= 0 (Upwards is positive)

\(F_{BC}sin\theta-P=0\\\frac{4}{5}F_{BC} - P=0\\F_{BC}=\frac{5}{4}P\\\\F_{BC}=1.25P\)

∑ F(x)= 0 (Towards Right is positive)

\(N_{a-a} - F_{BC}cos\theta=0\\N_{a-a}-1.25P(\frac{3}{5})=0\\N_{a-a}=0.75P\)

∑ F(y)= 0 (Upwards is positive)

\(F_{BC}sin\theta- V_{a-a}= 0\\(\frac{4}{5})1.25P-V_{a-a}=0\\V_{a-a}=P\)

The cross sectional area of a-a:

\(A_{a-a}= \frac{(0.026)(0.026)}{3/5}\\A_{a-a}= 1.127\cdot10^{-3}\)

σ = N(a-a)/A(a-a)

Substitute values:

\(160\cdot10^6=\frac{0.75P}{1.127\cdot10^{-3}}\\P=240.42\cdot10^3 N\\P=240.42 kN\)

Т= V(a-a)/A(a-a)

Substitute values:

\(60\cdot10^6=\frac{P}{1.127\cdot10^{-3}}\\P=67.62\cdot10^{3}N\\P=67.62kN\)

To satisfy both the condition, we have to choose the lower value of P.

P=67.62 kN

**The self-test in Chapter 4 of the book "Electronic Devices Conventional Current Version, 9th Edition" by Thomas L. Floyd is a valuable resource for reviewing electronics engineering concepts and preparing for board exams.** It provides comprehensive coverage of bipolar junction transistors, a fundamental component in electronic circuits.

This self-test can serve as a valuable tool for assessing your understanding of key concepts related to bipolar junction transistors. By working through the questions and evaluating your answers, you can identify areas that require further study and gain confidence in your knowledge.

However, it's important to note that relying solely on this self-test may not be sufficient for thorough exam preparation. It's advisable to supplement your review with additional resources, such as textbooks, lecture notes, and practice problems from various sources. This will ensure a well-rounded understanding of the subject matter and increase your chances of success on the board exam.

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The statement that The different taste qualities (sweet, sour, bitter, salt, umami) each have their own area of the tongue that is most sensitive to them is False.

Gate Theory states that competing signals such as rubbing your elbow can make you more sensitive to pain. This theory suggests that physical signals such as massage, pressure, heat, or cold can block the transmission of pain messages through the spinal cord and prevent them from reaching the brain. Therefore, when people rub their elbows or apply pressure to the area, this stimulates the non-painful touch fibers and decreases the transmission of the painful stimuli.

As per the statement, patients who are allowed to self-administer morphine use less than when they receive injections from healthcare providers is True. Olfaction is a very important sense for humans, and they often become depressed when they lose their sense of smell (olfaction). The statement that The different taste qualities (sweet, sour, bitter, salt, umami) each have their own area of the tongue that is most sensitive to them is False.

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Answer:

well, that is a bit complicated but you can get some of the stuff on amazon or for me i used left over parts that my car guy gave me so i don't know if that is available but I'm sure that you will do great on making this desk

Explanation:

Answer:

"Physical" would be the right approach.

Explanation:

So the answer here is just the perfect one.

Answer:

The velocity at section is approximately 42.2 m/s

Explanation:

For the water flowing through the pipe, we have;

The pressure at section (1), P₁ = 300 kPa

The pressure at section (2), P₂ = 100 kPa

The diameter at section (1), D₁ = 0.1 m

The height of section (1) above section (2), D₂ = 50 m

The velocity at section (1), v₁ = 20 m/s

Let 'v₂' represent the velocity at section (2)

According to Bernoulli's equation, we have;

\(z_1 + \dfrac{P_1}{\rho \cdot g} + \dfrac{v^2_1}{2 \cdot g} = z_2 + \dfrac{P_2}{\rho \cdot g} + \dfrac{v^2_2}{2 \cdot g}\)

Where;

ρ = The density of water = 997 kg/m³

g = The acceleration due to gravity = 9.8 m/s²

z₁ = 50 m

z₂ = The reference = 0 m

By plugging in the values, we have;

\(50 \, m + \dfrac{300 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{(20 \, m/s)^2}{2 \times 9.8 \, m/s^2} = \dfrac{100 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)50 m + 30.704358 m + 20.4081633 m = 10.234786 m + \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

50 m + 30.704358 m + 20.4081633 m - 10.234786 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

90.8777353 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

v₂² = 2 × 9.8 m/s² × 90.8777353 m

v₂² = 1,781.20361 m²/s²

v₂ = √(1,781.20361 m²/s²) ≈ 42.204308 m/s

The velocity at section (2), v₂ ≈ 42.2 m/s

The problem of generation of inaccurate logs because users often share access tags when entering the building solved effectively by using by Amazon Recognition.

Amazon Recognition  will give enablement of  uptake of imagery as well as video for analysis in applications.

And then identification and distinguishing of facial features and activities will be possible.

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