propose a solution to decrease the total amount of chemical pesticides used in britain for agriculture.

Answer:

The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure (Charles's law). The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).

Answer:

I need this too but nobody knows how :(

Explanation:

When the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

The zinc metal will ionize as shown below;

Zn²₊ + 2e⁻ → Zn

The molar mass of zinc metal is given as 65.38 g/mol

Amount of charge that will deposite the given mass of zinc is calculated as follows;

e⁻ = 96500 C

2e⁻ = 2 x 96500 C = 193,000 C

65.38 g -------> 193,000 C

7.85 g -----------> ?

= (7.85 x 193,000)/(65.38)

= 23,173 C

Thus, when the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

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Answer:

Approximately \(60.3\; \rm g\).

Explanation:

Look up the relative atomic mass of \(\rm Al\) and \(\rm Br\) on a modern periodic table:

Calculate the formula mass of \(\rm AlBr_3\) and \(\rm Br_2\):

\(\begin{aligned}& M(\mathrm{AlBr_3}) = 26.982 + 3 \times 79.904 \approx 266.694\; \rm g \cdot mol^{-1} \\ & M(\mathrm{Br_2}) = 2\times 79.904 \approx 159.808\; \rm g \cdot mol^{-1}\end{aligned}\).

Calculate the number of moles of formula units in \(67.1\; \rm g\) of \(\rm AlBr_3\):

\(\begin{aligned}n(\mathrm{AlBr_3}) &= \frac{m(\mathrm{AlBr_3})}{M(\mathrm{AlBr_3})} \\ &\approx \frac{67.1\; \rm g}{266.694\; \rm g \cdot mol^{-1}} \approx 0.2516\; \rm mol \end{aligned}\).

Refer to the balanced equation for this reaction. The ratio between the coefficients of \(\rm Br_2\) and \(\rm AlBr_3\) in that equation is three-to-two. That corresponds to the ratio:

\(\begin{aligned}\frac{n(\text{$\mathrm{Br_2}$, consumed})}{n(\text{$\mathrm{AlBr_3}$, produced})} &= \frac{3}{2}\end{aligned}\).

It is already calculated that approximately \(0.2516\; \rm mol\) of \(\rm AlBr_3\) was produced through this reaction. Apply this ratio to approximate the (minimum) number of moles of \(\rm Br_2\) that is consumed:

\(\displaystyle \frac{3}{2} \times 0.2516\; \rm mol \approx 0.3774\; \rm mol\).

Calculate the mass of that \(0.3774\; \rm mol\) of \(\rm Br_2\):

\(\begin{aligned}m(\mathrm{Br_2}) &= n(\mathrm{Br_2})\cdot M(\mathrm{Br_2}) \\ &\approx 0.3774\; \rm mol \times 159.808\; \rm g \cdot mol^{-1} \approx 60.3\; \rm g\end{aligned}\).

The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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Answer:

6.591

explanation

mass of weight is 1.092 , and mass of weight boat and sample = 7.683

mass of the solid sample= (mass of weight boat and sample) - (weight of the boat) = (1.092-7683) = 6.591 g

hence, the mass of the solid sample is 6.591 g

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

Answer:

Ionic Substance is....

Explanation:

In chemistry, an ionic compound is a chemical compound composed of ions held together by electrostatic forces termed ionic bonding. The compound is neutral overall, but consists of positively charged ions called cations and negatively charged ions called anions.

To solve such this we must know the concept of redox reaction. Therefore, the given reaction is redox reaction as one element is getting oxidized and other is getting reduced.

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

Redox reaction is a chemical reaction where oxidation and reduction takes place simultaneously. Oxidation is loss of electrons and reduction is gain of electrons. The electron transfer from oxidant to reductant.

CH\(_4\) + 2 O\(_2\) \(\rightarrow\) CO\(_2\) + 2 H\(_2\)O

The oxidation state of C in CH\(_4\) is -4 while in CO\(_2\)  it is +4. So, carbon is getting oxidized. The oxidation state of oxygen in O\(_2\) is 0 while in  H\(_2\)O it is -2, so oxygen is getting reduced. So, this reaction is a redox reaction.

Therefore, the given reaction is redox reaction.

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In the given reaction, carbon oxidizes from 0 oxidation state to +4 state whereas, oxygen reduces from 0 to -2. Hence, one species is oxidized and another species is reduced, thus, it is a redox reaction.

A redox reaction a type of reaction in which one species is oxidized and another species is reduced. In oxidation an element forms its higher oxidation state whereas in reduction it reduces to lower oxidation state.

In the given reaction, carbon is in zero oxidation state zero and the it forms +4 oxidation state in CO₂. Similarly, oxygen is in zero charge at its molecular state O₂ which is changed to -2 state in CO₂.

Therefore, both oxidation and reduction takes place in this reaction and it is a redox reaction.

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An experiment with paperclip and a ice cube was experimented several times by many scientists. The phenomenon which comes after the experiment as a result is called as 'Regulation' in science.

This well-known experiment demonstrates how ice may fuse together on its own. Although it was initially demonstrated in 1872, the exact mechanism behind the phenomena is still unknown but known as Regulation.

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Answer:

B. Gas pressure will increase

Explanation:

Since the gas container is compressing, the number of air molecules inside the container will stay the same, but now in less space. This will result in the molecules to bump into each other more often, creating more pressure as well as more heat.

Adding small amount of sodium biphosphate  to buffer will cause the pH to increase.

pH , also referred to as acidity, which  denotes "potential of hydrogen" (or "power of hydrogen").It is a scale which is  used to specify the acidity or basicity of an aqueous solution. Acidic solutions (solutions with higher concentrations of hydrogen (H+) ions) are measured to have lower pH values than basic or alkaline solutions which have higher pH of more than 7.

The pH scale is logarithmic and inversely indicates the activity of hydrogen ions  in the solution.It is also used in buffer concept.

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The term that refers to the passing of a wave through an object is "transmission."

Transmission refers to the process by which a wave passes through an object or medium. In the context of sound, transmission occurs when sound waves travel through different substances, such as air, water, or solids.

When a sound wave encounters an object, it can be transmitted through it, reflected off it, or absorbed by it, depending on the properties of the object and the medium through which the sound is traveling.

For example, when you speak into a microphone, the sound waves produced by your voice travel through the air and are transmitted to the microphone's diaphragm. The diaphragm converts the sound waves into electrical signals, which can then be amplified and reproduced as sound through speakers.

In summary, transmission is the term used to describe the passage of a wave, such as a sound wave, through an object or medium. It is an essential concept in understanding how waves interact with their surroundings and how sound propagates through different materials.

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Answer:

089

Explanation:

I have no idea

Based on the data from the calorimetry experiment, the enthalpy change, ΔH of the reaction is -286 KJ .

The enthalpy change, ΔH of a reaction is the amount of heat evolved or absorbed when reactant molecules react to form products.

From the calorimetry experiment, the determined heat of combustion of 1.01 g of H2(g) reacting with excess O2(g), qsoln = 143 kJ.

Heat is evolved in the reaction, therefore the qsoln = -143 kJ

Equation of reaction is given as:

H2(g) + ½ O2(g) → H2O (l)

Molar mass of H = 1.01 g

Mass of H2 = 1.01 g × 2 = 2.02 g

ΔH of the reaction = -143 kJ × 2.02/1.01

ΔH of the reaction = -286 KJ

Therefore, the enthalpy change, ΔH of the reaction is -286 KJ .

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Answer:

59.0764

Explanation:

Element Symbol Atomic weight Atoms

Calcium   Ca             40.078              1        

Fluorine     F             18.9984032             1  

you just multiply the atomic weight to the atom and then add :))

Answer:

oxygen = 4.7 * 10^-6

Nitrogen = = 9.7 * 10^6

Explanation:

partial pressure of oxygen = 0.20 atm

partial pressure of Nitrogen = 0.80 atm

calculate the mole fractions of oxygen and Nitrogen in water

Temp = 298k

applying henry's law

molar conc of oxygen in water ( Coxygen )

= Kp = 1.3 * 10^-3 Mol/L.atm * 0.20 atm = 2.6 * 10^-4 Mol

molar conc of Nitrogen in water ( Cnitrogen )

= Kp = 6.8 * 10^-4 Mol/L.atm * 0.80 atm = 5.4 * 10^-4

next Given that the number of moles in 1 liter of water = 55.5 mol  

therefore the mole fraction of oxygen

= 2.6 * 10^-4 / 55.5

= 4.7 * 10^-6

mole fraction of Nitrogen

= 5.4 * 10^-4  / 55.5

= 9.7 * 10^6

Table salt does not melt on the stove, it dissolves in water and does not conduct electricity.

There are several substances listed in the table Epsom salt is another one of these substances. It does not melt on a stove, it dissolves in water and also conducts electricity.

Finally, potassium chloride does not melt on the stove, it dissolves in water and it does conduct electricity. These are the experiences one can have with these common substances.

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The order of reaction is defined as the power to which the concentration of the reactants are raised in the rate equation of the reaction.

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Answer:

The amount of Mg was enough

Explanation:

In this case, we have to start with the reaction between \(Mg\) and \(CuO\), so:

\(CuO~+~Mg~->~MgO~+~Cu\)

If we check the reaction is already balanced. Now, we can do some stoichiometry to calculate the amount of Mg. The first step is the number of moles of \(CuO\). To this we have to calculate the molar mass of \(CuO\) first, so:

Cu: 63.55 g/mol and O: 16 g/mol. So, (63.55+16)= 79.55 g/mol.

Now, we can calculate the moles:

\(1.525~g~CuO\frac{1~mol~CuO}{79.55~g~CuO}=0.0192~mol~CuO\)

The molar ratio between \(Mg\) and \(CuO\) is 1:1, so:

\(0.0192~mol~CuO=0.0192~mol~Mg\).

Now we can calculate the mass of Mg if we know the atomic mass of Mg (24.305 g/mol). So:

\(0.0192~mol~Mg\frac{24.305~g~Mg}{1~mol~Mg}=0.466~g~Mg\)

With this in mind, the student added enough Mg to recover all the Cu.

Note: The HCl doesn't take a role in the reaction. The function of HCl is to dissolve the \(CuO\).

I hope it helps!

i believe its B

Explanation:

Explanation:

since 5g saturates 12.5g of water at 10°c

so......x would saturate 50g of water at 0°c

then you can cross multiply

Answer:

Heat waves

Explanation:

The electronic configuration of magnesium is:

1s² 2s² 2p⁶ 3s² = [Ne] 3s²

This means that for a magnesium atom, in order to have its outermost orbital full, the easiest way would be to lose the two outermost electrons. This is seen in its relatively low first two ionization energies. The third ionization energy is several times higher because the ion would move from a stable form to an highly unstable form. (Mg⁺² → Mg⁺³ + e⁻).

Sodium only has one electron in its outermost orbital, so its first ionization energy would be several times lower than the second.

From the reaction given, 47.4 kJ evolved when 5.91 grams of Na(s) reacted with H2O(l). The value of ΔrH for this equation is: - 23.7 kJ/mol.

Before calculating the enthalpy changes, we should know the moles of Na first:

n of Na = mass / molar mass

n = 46.4 g / 23 g/mol

n = 2 moles.

Now, the equation given is:

2Na(s) + 2H₂O(l) —> 2NaOH(aq) + H₂(g)    ΔH = - 47.4 kJ

The value of ΔrH has to state the enthalpy changes of one mol reactant. So, we need to divide the coefficient by 2:

Na(s) + H₂O(l) —> NaOH(aq) + ½ H₂(g)    ΔH = - 23.7 kJ/mol

Hence, the value of ΔrH is - 23.7 kJ/mol.

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50.97 g AgNO₃ is needed to make 500.0 mL of 0.600 mol/L AgNO3(aq)

A mole is defined as 6.02214076 × \(10^{23}\)of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Molar mass of AgNO₃ = (107.9 + 14.0 + 16.0×3) g/mol = 169.9 g/mol

Molarity = Moles of solute ÷ Volume of solution in litre

0.600 mol/L = Moles of solute ÷ 0.5 mL

Moles of solute =0.3 mol

Moles =\(\frac{mass}{molar \;mass}\)

0.3 mol =  \(\frac{mass}{169.9 g/mol}\)

Mass =50.97 g AgNO₃

Hence, 50.97 g AgNO₃ is needed to make 500.0 mL of 0.600 mol/L AgNO3(aq).

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Answer:

ΔH°f C₂H₅O₂N(s)  = -537.2kJ

Explanation:

Based on the reaction:

4 C₂H₅O₂N(s) + 9O₂(g) → 8CO₂(g) + 10H₂O(l) + 2N₂(g)

ΔHrxn = ΔH°f products - ΔH°f reactants.

As:

ΔH°fO₂(g) = 0

ΔH°fCO₂(g) = -393.5kJ/mol

ΔH°fH₂O(l) = -285.8kJ/mol

ΔH°fN₂(g) = 0

The ΔHrxn is:

ΔHrxn = (8×-393.5kJ/mol + 10×-285.8kJ/mol) - (4×ΔH°fC₂H₅O₂N(s)) = -3857kJ/mol

-6006kJ/mol - (4×ΔH°fC₂H₅O₂N(s)) = -3857kJ/mol

-4×ΔH°fC₂H₅O₂N(s) = 2149kJ/mol

ΔH°fC₂H₅O₂N(s) = 2149kJ/mol / -4

In forming the Al³⁺ ion, the Al atom loses the electrons in its outermost energy level, causing a decrease in the atomic radius, hence option A is correct.

The number of protons in the nucleus of AlandAl3+ AlandAl3+ is the same, however there are differing numbers of electrons in the final shell. Al³⁺ is smaller than Al because it has fewer electrons.

The Al atom will become an Al³⁺ ion when it loses its third electron and develops a tri-positive charge on it. In forming the Al³⁺ ion, the Al atom loses the electrons in its outermost energy level, causing a decrease in the atomic radius.

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