£20 / 3 so £6 each
pip will get 6*2 which is £12 .
Answer:
pip gets £12
Step-by-step explanation:
gordon = x
sara = 3x (as she gets three times as much as gordon)
pip = 6x (because she gets twice as much as sara)
6x + 3x + x = 20
10x = 20
x = 20
6 * 2 = 12
Write an equation of the line that passes through (18, 2) and is parallel to the line 3y - x = -12.
Answer:
3y=x-12
y=x/3-4
m=1/3
At (18,2)
y-2=1/3(x-18)
y-2=x/3 - 6
y=x/3 - 4
Please help it’s for tmr
Leo has a number of toy soldiers between 27 and 54. If you want to group them four by four, there are none left, seven by seven, 6 remain, five by five, 3 remain. How many toy soldiers are there?
The answer is 48 but I need step by step explanation
The number of toy soldiers that Leo has is 48.
How many toy soldiers does Leo have?The first step is to determine the multiples of 4 that lie between 27 and 54. A multiple of a number is the product of an integer and that number.
Multiplies of 4 that lie between 27 and 54 = 28, 32, 36, 40, 44, 48, 52
Now divide each of the multiples by 7 :
28 / 7 = 4
32 / 7 = 4 remainder 4
36 / 7 = 5 remainder 1
40 / 7 = 5 remainder 5
44 / 7 = 6 remainder 2
48 / 7 = 6 remainder 6
52 / 7 = 7 remainder 3
It only 48 that meets this criteria. This means that the number is 48.
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If area of a rectangle is 20m^10n^4 and the length is 5m^3n what is the width
The width of the rectangle is 4*m⁷*n³
How to find the width of the rectangle?Remember that for a rectangle of length L and width W the area is given by the formula:
A = W*L
Here we know that:
A = 20*m¹⁰*n⁴
L = 5*m³*n
Then we can write:
20*m¹⁰*n⁴ = (5*m³*n)*W
Now we can solve that for W.
(20/5)*(m¹⁰/m³)*(n⁴/n) = W
4*m¹⁰⁻³*n⁴⁻¹ = W
4*m⁷*n³ = W
That is the width.
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it is a polygon with 3 sides and 3 angles
Answer:
A triangle is that polygon with three side and three Angles
Consider a random sample of size 7 from a uniform distribution, X; Uniform(0,0), 0 > 0, and let Yn = maxi si≤n X;. Find the constant c (in terms of a) such that (Yn, cYn) is a 100(1-a)% confidence interval for 0
c = ____
c = 1
What is the constant c for the confidence interval?In statistics, a confidence interval provides a range of values within which the true parameter is expected to fall with a certain level of confidence. In this case, we are considering a random sample of size 7 from a uniform distribution, X; Uniform(0,0), where 0 > 0. The variable Yn represents the maximum value observed in the sample up to the nth observation. To construct a confidence interval for 0, we need to find the constant c.
The constant c is determined based on the desired confidence level (1-a) and the properties of the uniform distribution. Since the maximum value observed in the sample is Yn, we can set up the confidence interval as (Yn, cYn). To ensure that the interval captures the true parameter 0, we need c such that cYn ≥ 0. By setting c = 1, we guarantee that the interval includes 0. Therefore, the constant c for the confidence interval is 1.
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Which is the coefficient of the expression - 3a²c-7?
-7
-3
2
3
Answer:
-3
Step-by-step explanation:
:)
Which statement is NOT true concerning a linear equation?
1. Neither x nor y can appear as an exponent or a radical
2. The variables x and y can be multipled together
3. The variables x and y must have exponent of 1
4. Neither x nor y can appear in a denominator
The statement that is false is:
"The variables x and y can be multiplied together"
Which statement is not true?
The general linear equation is given by:
y = a*x +b
Where a is the slope and b is the y-intercept.
The statement that is evidently false about the above general equation is:
"The variables x and y can be multiplied together"
y depends linearly on x, so these variables can't be multiplied together.
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what is the approximate ratio of areas for gne-a to gne-b when the gne-a concentration is 18 micrograms/ml?
The approximate ratio is 52 to 18 micrograms/ml.
Step 1:
This is a general question in which we need to analyze only the graph.
Regression of the calibration curve of GNE-A in mouse plasma is given.
Step 2:
In the given data, the ratio of area of GNE-A to GNE-B is taken in y axis and GNE - A concentration is taken in x axis. From the graph, it is clear that the concentration of GNE-A corresponding to the GNE-A to GNE-B ratio 52 is 18.
The approximate ratio of areas for gne-a to gne-b when the gne-a concentration is 18 micrograms/ml is 52 : 18.
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A rectangle's length is 12.1 more than 3 times its width. Its perimeter is 122.6. Write and solve a system of equations to find the dimensions of the rectangle.
Step-by-step explanation:
Let width of the rectangle be y
Length of rectangle = 3y + 12.1
Perimeter = 2(L + y) = 122.6
2 (4y + 12.1 ) = 122.6
8y + 24.2 = 122.6
y = 98.4 / 8
y (width) = 12.3
Length = 49
Identify all values in the five number summary and create a box plot for the data set below.
You can upload your 5 number summary and box plot in the last question or provide a link to your work in the text box.
14, 13, 16,16, 18, 20, 22, 19, 23, 24, 24, 26, 27, 28, 30, 32
Answer:
12345
Step-by-step explanation:
give me a brainliest plees
Answer:
you can create your box plot from the following answers
a) minimum = 13
b) first quartile = 17
c) median = 22.5
d) third quartile = 26.5
e) maximum = 32
e) interquartile range = 26.5 - 17 = 9.5
Step-by-step explanation:
minimum and maximum values are self-explanatory
first quartile is derived by getting the median of the lower half of data (the median will divide the data into the lower half and the upper half)
third quartile is derived by getting the median of the upper half of data
the median is sometimes referred to as the second quartile
box plots are all about quartiles so that you can see where 25% of the data reside, or 50% or 75%, etc
If correct I’ll give brainlist
the correct option is (1,0)
I need help fasttt.....
Answer:
the 3rd one I think hope this helps
Step-by-step explanation:
A delivery service charges a flat rate of $4.25 per box plus an additional
amount per ounce. Carl mailed a four-pound package at a cost of $10.65.
How much did Carl have to pay per ounce?
is 49.080 equal to lesser than or greater than 49.08
Answer:
there equal
I think but I'm not sure
Show that the following language over Σ = {0, 1} is not context-free:
{w : w is a palindrome containing the same # of 0’s as 1’s}
In all cases, pumping the string w results in a string that is not in L, which contradicts the pumping lemma. And we can conclude that L is not a context-free language.
To prove that a language is not context-free, we can use the pumping lemma for context-free languages.
Assume that the language L = {w : w is a palindrome containing the same number of 0's and 1's} is context-free. Then, by the pumping lemma for context-free languages, there exists a constant p such that any string w in L with length |w| ≥ p can be written as w = uvxyz, where:
|vy| > 0|vxy| ≤ pFor all i ≥ 0, the string \(uv^ixy^iz\) is also in L.Let's choose the string w = \(0^p1^p0^p\). This string is in L because it is a palindrome and contains the same number of 0's and 1's. By the pumping lemma, we can write w = uvxyz, where |vxy| ≤ p and |vy| > 0.
There are three cases:
vxy contains only 0's. In this case, pumping up or down will break the palindrome property because the string will no longer be a palindrome.vxy contains only 1's. In this case, pumping up or down will break the property of having the same number of 0's and 1's.vxy contains both 0's and 1's. In this case, pumping up or down will break both the palindrome property and the property of having the same number of 0's and 1's.Therefore, in all cases, pumping the string w results in a string that is not in L, which contradicts the pumping lemma. Hence, we can conclude that L is not a context-free language.
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I have the same map test lol
The girl’s hockey team won 6 games, lost 3 games, and tied 2 games. What fraction of games did they win?
Answer:
6/11 games
Step-by-step explanation:
Take the total number of wins, losses, and ties, and add them up to get the total number of games.
3+2+6=11
Then divide the wins by the number of games to get the fraction.
6/11
The line passes through the point (3,12)
and has the same slope as the line
y = 5x - 7.
Answer:
y - 12 = 5(x - 3) {the point-slope form of the equation}
y = 5x + 9 {the slope-intercept form of the equation}
5x - y = -9 {standard form of the equation}
Step-by-step explanation:
The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:
y = 5x - 7 ⇒ m = 5
(3, 12) ⇒ x₀ = 3, y₀ = 12
So, the point-slope form of the equation:
y - 12 = 5(x - 3)
Therefore:
y - 12 = 5x - 3 {add 12 to both sides}
y = 5x + 9 ← the slope-intercept form of the equation
y = 5x + 9 {subtract5x from both sides}
y - 5x = 9 {multiply both sides by (-1)}
5x - y = -9 ← the standard form of the equation
A system of equations is shown below.
y=4x
y=x-6
what is the x-value in the solution to the system?
Answer: x = -2
Step-by-step explanation:
Since both equations are in the y-slope form,
we can use substitution for y in finding x.
Hence,
4x=x-6
4x-x=x-x-6
Subtract x from both sides to get x on one side and integer on one side.
\(\frac{3x}{3} =\frac{-6}{3}\)
Divide 3 to find the value of x
x=-2
twice a number deceased by 7.translate in algebraic expressions
Twice a number (2x) decreased by 7 (- 7).
2x - 7
Two times a specfic number (x) subtracted by 7.
Multiply. Write your answer in simplest form.
SOMEONE PLS ANSWER
Consider the following system of equations.
x+2 z=-1
y-2 z=2
2 x+y+z=1
a. Represent the system of equations using the matrix equation A X=B .
The system of equations can be represented as A*X = B where A = \(\left[\begin{array}{ccc}1&0&2\\0&1&-2\\2&1&1\end{array}\right]\), X = [x; y; z], and B = \(\left[\begin{array}{ccc}-1&2&1\end{array}\right]\).
To represent the system of equations using the matrix equation A*X = B, we need to arrange the coefficients of the variables x, y, and z in a matrix form.
The coefficient matrix A is obtained by collecting the coefficients of the variables x, y, and z in the same order as they appear in the system of equations. In this case, we have:
A = \(\left[\begin{array}{ccc}1&0&2\\0&1&-2\\2&1&1\end{array}\right]\)
Here, each row of the matrix A represents the coefficients of the respective equation.
The variable matrix X is obtained by arranging the variables x, y, and z in a column matrix:
X = [x; y; z]
The constant matrix B is obtained by arranging the constants on the right-hand side of the equations in a column matrix:
B = \(\left[\begin{array}{ccc}-1&2&1\end{array}\right]\)
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Use the alternating series estimation theorem to determine how many terms should be used to estimate the sum of the entire series with an error of less than 0.001. [infinity]∑ ₙ₌₋₁ (-1)ⁿ⁺¹ 1/(n + 3√n ³
___ or more terms should be used to estimate the sum of the entire series with an error of less than 0.001.
To determine how many terms should be used to estimate the sum of the given series with an error of less than 0.001, we can apply the alternating series estimation theorem.
In the given series, the terms are alternating and decreasing in magnitude. We want the error to be less than 0.001, so we need to find the value of n where the absolute value of the (n+1)th term is less than 0.001.
To find this value, we can set up the inequality: |1/(n + 3√n)| < 0.001. Simplifying this inequality, we get: 1/(n + 3√n) < 0.001.
Solving this inequality for n will give us the minimum number of terms required. However, the given equation is incomplete and contains an incomplete expression. Please provide the correct expression for the third term of the series so that I can assist you further.
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i literally don't understand this at all.
Answer:
its just exaplining how does this exrcise work example 1^1 would be 1x1/
1^3 1x1x1x1/ 3^5 3x3x3x3x3/ 3x3=9 9x3 =27 27x3 =81 81x3=243
Step-by-step explanation:
Change a speed of 630 kilometres per hour to a speed in metres per second. Show your working
Answer:
1750 m/s
Step-by-step explanation:
1km = 1000m
1 hour = 60 minutes = 3600 seconds
( 630 * 1000 )/ (60 * 60)
= 1750 m/s
a car travel 20kph faster than a truck. the car cover 350 km in two hours less than the time it takes the truck to travel the same distance. what is the speed of the car? how about the truck?
A car travel 20kph faster than a truck. the car cover 350 km in two hours less than the time. The speed of the car is 50 km/h. The speed of truck is 70 km/h.
Define speed.You can determine an object's speed if you know how far it moves in a given amount of time. For instance, an automobile is moving at a pace of 70 miles per hour if it covers 70 miles in an hour (miles per hour).
Given,
A car travel 20kph faster than a truck. the car cover 350 km in two hours less than the time.
Let s represent the truck's speed and (s+20) represent the car's speed.
to determine each vehicle's time
Time = Speed / Distance
truck time = 350/s
Time in an automobile is 350/(s+20)
Truck time - car time = 2 hours
So,
(350/s) - [350/(s+20)] = 2
LCM is s(s+20)
[350(s+20) - 350s]/s(s+20) = 2
Cross multiplying,
350(s+20) - 350s = 2s(s+20)
Simplifying the equation,
350s + 7000 - 350s = 2s² + 40s
Now, we have quadratic equation to simplify,
2s² + 40s - 7000 = 0
Dividing the equation by 2
s² + 20s - 3500 = 0
Factorizing,
s= 50
s= -70 (impossible because of the sign)
Hence the truck's speed is s = 50 km/h.
The speed of the car is s + 20 = 70 km/h.
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3 folders cost $2.91. How much do 2 folders cost? Provide explanation.
idk anything about exponent rules can someone help me with this ?
Help me plsssssss!!!!!!!
Answer:
hello pero no hablo inglés ._.
How many integers are there between 1 and 1000 that are divisible by 3 and 5?
There are 166 integers between 1 and 1000 that are divisible by 3 and 5.
1000/3 = 333.3333
1000/5 = 200
333.3333 * 200 = 66,666.66
66,666.66 / 15 = 4444.444
4,444.444 rounded to 4,445
4,445 - 1 = 4,444
4,444 + 1 = 4,445
4,445 integers between 1 and 1000 that are divisible by 3 and 5.
There are 4,445 integers between 1 and 1000 that are divisible by both 3 and 5. The calculation to determine this is 1000 divided by 3, then 1000 divided by 5, then multiplying the two numbers together, then dividing by 15 and rounding the result to the nearest integer, then subtracting and adding 1 to the result.
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