Q = prod / reactants make sure to raise to the coefficients. when multiplying equations to make electrons equal...

Answer:

gang gang

Explanation:

In all it means a biologist specializing in physiology.

Only possible with alkaline earth metals

Let's see an example

\(\\ \sf\longmapsto X(OH)_2\)

The elements are

Option C is correct

\(\rule{300pt}{1000000pt}\)

The binding energy in MeV per atom for an atom of 110Sn is 309 MeV.  

The binding energy in MeV per atom for an atom of 110Sn, we need to first calculate the atomic mass of the atom, which we can do by summing the masses of all its constituent particles. The atomic mass of 110Sn can be calculated as follows:

Atomic mass = (110 atomic mass units)

110 amu = (110 x 1.6605389 x 10 kg)

110 amu = 18.9785868 kg

Next, we can use the formula for binding energy per nucleon:

Binding energy per nucleon = (atomic mass x speed of light squared) / (12 x 1.01)

Binding energy per nucleon = (18.9785868 kg x 299,792,458 m/s) / (12 x 1.01)

Binding energy per nucleon = 1.394 MeV/nucleon

Finally, we can multiply the binding energy per nucleon by the number of nucleons in the atom to get the total binding energy in MeV:

Total binding energy = (1.394 MeV/nucleon) x (110Sn x 2)

Total binding energy = (1.394 x 2) x 220

Total binding energy = 309 MeV

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The binding energy of an atom of ¹¹⁰Sn with a mass of 109.907858 amu is approximately 8.78 MeV per atom.

The binding energy of an atom is the energy required to completely separate its constituent nucleons (protons and neutrons). It represents the difference in mass between the nucleus and its individual nucleons.

To calculate the binding energy per atom, we need to determine the mass defect, which is the difference between the actual mass of the atom and the sum of the masses of its individual nucleons.

Given that the mass of ¹¹⁰Sn is 109.907858 amu, we compare it with the sum of the masses of 50 protons and 60 neutrons (since ¹¹⁰Sn has an atomic number of 50 and a mass number of 110). The mass defect is then obtained by subtracting the sum of the masses of the nucleons from the mass of the atom.

Using Einstein's mass-energy equivalence (E = mc²), where c is the speed of light, we can convert the mass defect to energy in joules (J).

Finally, we convert the energy from joules to megaelectron volts (MeV) by dividing by the conversion factor (1 MeV = 1.602 × 10⁻¹³ J).

Therefore, the binding energy per atom is approximately 8.78 MeV, representing the energy released when combining nucleons to form the nucleus of ¹¹⁰Sn.

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The average temperature is 17.0 °C.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature.

Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points and thermometric substances. The most popular scales are the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the Fahrenheit scale (°F), and the Kelvin scale (K), with the latter being mostly used for scientific purposes. One of the International System of Units' (SI) seven base units is the kelvin law of cosines.

The lowest point on the thermodynamic temperature scale is absolute zero, or zero kelvin, or 273.15 °C.

To find the average temperature, we add up the individual temperatures and divide by the total number of measurements. Let's calculate:

Average temperature = (16.9 + 17.0 + 17.1) / 3 = 51.0 / 3 = 17.0

Therefore, the average temperature is 17.0 °C.

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The coefficient for Fe(s) in the balanced chemical equation Fe(s) + O2(g) → Fe2O3(s) is 4.

In order to balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

On the left side, we have 1 Fe atom, and on the right side, we have 2 Fe atoms in Fe2O3. This means we need to multiply Fe(s) by 2 to balance the Fe atoms.

Next, we need to balance the oxygen atoms. On the left side, we have 2 O atoms in O2, and on the right side, we have 3 O atoms in Fe2O3. To balance the oxygen atoms, we need to multiply O2(g) by 3.

Therefore, the balanced chemical equation is:

4 Fe(s) + 3 O2(g) → 2 Fe2O3(s)

From the balanced equation, we can see that the coefficient for Fe(s) is 4, indicating that 4 moles of Fe(s) are required to react with 3 moles of O2(g) to form 2 moles of Fe2O3(s).

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The atom that moves at its rms velocity at 100°C with a wavelength of 2.31 * 10 m is : SULPHUR ( s )

To determine the atom we will have to determine the molar mass of the atom

Applying De Broglie equation

λ = h / mv

Vrms = \(\sqrt{\frac{3RT}{M} }\)  ---- ( 1 )

Where : λ  = 2.31 * 10⁻¹¹,  R = 8.314 J / k.mol,  T = 373 K, h = 6.626 * 10⁻³⁴ J.s

From equation ( 1 )

M = ( h² Ua ) / 3RT*λ² --- ( 2 )

where : Ua ( mass of an atom ) = 6.022 * 10²³,  h = 6.626 * 10⁻³⁴,  R = 8.314 J / k.mol, λ  = 2.31 * 10⁻¹¹,    T = 373 K

Insert values into equation ( 2 )

M ( molar mass ) = 32 g/mol

Sulphur has a molar mass of 32 g/mol therefore the atom is sulphur.

Hence we can conclude that The atom that moves at its rms velocity at 100°C with a wavelength of 2.31 * 10 m is : SULPHUR ( s ).

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Answer:

10.5

Explanation:

well we added together so thats the result

The base peak at m/z = 43 corresponds to the molecular ion of the compound CH3CH2CH2CH2CH2CH3, also known as hexane.

A mass spectrometer works by breaking apart a molecule and measuring the masses of the resulting ions. The most intense peak in the resulting mass spectrum is known as the base peak, and corresponds to the most abundant ion produced in the experiment.

In the case of hexane, the molecular ion produced is CH3CH2CH2CH2CH2CH3+, which has a mass of 43 atomic mass units, and is therefore the base peak at m/z = 43. The other compounds listed do not have a base peak at m/z = 43, as they have different molecular weights and different fragments produced upon ionization.

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Based on the available resources and profit per unit, producing 266 units of Product 1 would result in the highest total profit of BD 585.20.

To determine the maximum number of units of each product that can be produced given the available resources, we need to compare the resource requirements of the products with the available resources.

Let's calculate the resource requirements for each product:

Product 1:

- Metal sheet: 0.250 m2 per unit

- Glass sheet: 0.120 m2 per unit

- Electrical components: 3 units per unit

Product 2:

- Metal sheet: 0.150 m2 per unit

- Glass sheet: 0.050 m2 per unit

- Electrical components: 2 units per unit

Now let's compare the resource requirements with the available resources:

Metal sheets:

- Product 1 requires 0.250 m2 per unit, so the maximum number of units that can be produced using available metal sheets is 90 m2 / 0.250 m2 = 360 units.

- Product 2 requires 0.150 m2 per unit, so the maximum number of units that can be produced using available metal sheets is 90 m2 / 0.150 m2 = 600 units.

Glass sheets:

- Product 1 requires 0.120 m2 per unit, so the maximum number of units that can be produced using available glass sheets is 30 m2 / 0.120 m2 = 250 units.

- Product 2 requires 0.050 m2 per unit, so the maximum number of units that can be produced using available glass sheets is 30 m2 / 0.050 m2 = 600 units.

Electrical components:

- Product 1 requires 3 units per unit, so the maximum number of units that can be produced using available electrical components is 800 units / 3 units = 266 units.

- Product 2 requires 2 units per unit, so the maximum number of units that can be produced using available electrical components is 800 units / 2 units = 400 units.

Now let's determine the maximum number of units that can be produced for each product based on the limiting resource:

Metal sheets: The maximum number of units that can be produced is 360 units (for Product 1) since it requires a larger area of metal sheets.

Glass sheets: The maximum number of units that can be produced is 250 units (for Product 1) since it requires a larger area of glass sheets.

Electrical components: The maximum number of units that can be produced is 266 units (for Product 1) since it requires a larger number of electrical components.

Since the limiting resource for all three resources is reached with Product 1, the maximum number of units that can be produced for Product 1 is 266 units. As for Product 2, it can be produced up to a maximum of 250 units.

Now let's calculate the profit for each product:

Profit per unit for Product 1: BD 2.200

Profit per unit for Product 2: BD 1.400

Total profit for Product 1: 266 units × BD 2.200 = BD 585.20

Total profit for Product 2: 250 units × BD 1.400 = BD 350.00

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The radius of rhodium is 19.01nm

Data given;

The mass of the atom can be calculated as

\(mass of atom = \frac{atomic mass}{avogadro's number} * 4\\mass of atom = \frac{102.90}{6.023*10^2^3}*4 mass of atom = 6.837*10^-^2^2\)

using the density of the atom

\(\rho=mass/volume\\12.4 = \frac{4 * 102.90}{6.023*10^2^3*a^3}\\ a^3= 411.6/7.468*10^2^4\\a^3 = 5.503*10^-^2^3\\a = 3.803*10^-8\\\)

Let's solve for the atomic radius using this;

\(a = 2\sqrt{2} r\\r=\frac{a}{2\sqrt{2} } \\r = \frac{3.803*10^-^8}{2\sqrt{2} }\\r = 2.69*10^-8\\r = 19.01nm\)

The radius of rhodium is 19.01nm

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Answer:

7.44 grams CaCl2 will produce 10.0 grams KCl.

Explanation:

The equation is balanced:

I've repeated it here, with the elements corrected for their initial capital letter.

CaCl2( aq) K2CO3( aq) → 2KCl( aq) CaCO3( aq)

This equation tells us that 1 mole of CaCl2 will produce 2 moles of KCl.

If we want 10.0g of KCl, we need to convert that mass into moles KCl by dividing by the molar mass of KCl, which is 74.55 grams/mole.

 (10.0 grams KCl)/(74.55 grams/mole) = 0.1341 moles of KCl.

We know that we'll need half that amount of moles CaCl2, since the balanced equation says we'll get twice the moles KCl for every one mole CaCl2.

So we'll need (0.1341 moles KCl)*(1 mole CaCl2/2moles KCl) = 0.0671 moles CaCl2.

The molar mass of CaCl2 is 110.98 grams/mole.

(0.0671 moles CaCl2)*(110.98 grams/mole) = 7.44 grams CaCl2

7.44 grams CaCl2 will produce 10.0 grams KCl.

A 4.0 m solution of kno3 has a volume of 1.8 l. if the solution is diluted to 9.0 l, then the new concentration is  0.8 m

The concentration of solution of the amount of solute that has been dissolved in a given amount of solvent or solution

Here given data is

C₁ = 4.0 m

V₁ = 1.8 l

C₂ = ?

V₂ = 9.0 l

So the formula is

C₁V₁ = C₂V₂

4.0 m×1.8 l = C₂× 9.0 l

C₂ = 7.2/9.0 l

C₂ = 0.8 m

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Solvolysis is the process of reacting an organic compound with a solvent, especially one that has a high dielectric constant.

When bromomethyl cyclopentane undergoes solvolysis in methanol, a complex product mixture of the following five compounds is obtained. Here's a proposed mechanism to account for these products:

Firstly, the bromine atom present in bromomethyl cyclopentane gets replaced by a methanol molecule. As a result, a carbocation is formed in the first step.

Step 1: Bromomethyl cyclopentane + Methanol → Carbocation + Hydrogen bromide

Step 2: the carbocation undergoes attack by a methanol molecule. This attack can occur in two different positions, leading to two different products.

                  Step 2a: Carbocation + Methanol → Compound 1

                   Step 2b: Carbocation + Methanol → Compound 2

Step 3: the carbocation is attacked by a molecule of methanol to form an intermediate. The intermediate then undergoes a shift of the C-C bond, resulting in two more compounds.

                  Step 3a: Carbocation + Methanol → Intermediate → Compound 3

                  Step 3b: Carbocation + Methanol → Intermediate → Compound 4

Finally, the intermediate undergoes another methanol molecule attack, leading to the formation of the final product.

Step 4: Intermediate + Methanol → Compound 5T

Therefore, this is the mechanism proposed to account for the five products obtained from the solvolysis of bromomethyl cyclopentane in methanol.

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The mass number of the third isotope, given the data from the question is 34

The mass number of the third isotope can be obtained as illustrated below:

Relative atomic mass = [(Mass of 1st × Abundance of 1st) / 100] + [(Mass of 2nd × Abundance of 2nd) / 100] + [(Mass of 3rd × Abundance of 3rd) / 100]

32.133 = [(32 × 92.4) / 100] + [(33 × 1.9) / 100] + [(Mass of 3rd × 5.7) / 100]

32.133 = 29.568 + 0.627 + (Mass of 3rd × 0.057)

32.133 = 30.195 + (Mass of 3rd × 0.057)

Collect like term

32.133 - 30.195 = Mass of 3rd × 0.057

1.938 = Mass of 3rd × 0.057

Divide both sides by 0.057

Mass of 3rd = 1.938 / 0.057

Mass of 3rd = 34

Thus, we can conclude that the mass of the 3rd isotope is 34

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Missing part:

See attached photo

When a given amount of substance is partitioned among two immiscible liquids, the partitioning occurs at the phase boundary. Partitioning is achieved in this manner since the solute molecules diffuse from one phase to the other. Octanol is an immiscible solvent with water, and o-xylene has a greater solubility in octanol than in water.

We must first determine the molarity of the solution. We must know the volume of octanol and water in the mixture because octanol is not used to dissolve the o-xylene in water, and water does not dissolve the o-xylene in octanol. Given the water volume (V), we may calculate the octanol volume (V0) as follows:

V0 = 200 mL = 0.2 LV = 250 mL = 0.25 L

Total volume of solution = V + V0 + 0.05 L = 0.5 L. This is the volume of air present in the mixture. We must subtract it from the total volume of the solution The amount of o-xylene in the mixture is now calculated as follows:\(\frac{0.00116 mol}{L}\) × 0.5 L × 130.2 g/mol = 0.0756 g of o-xyleneSo, the total mass of o-xylene present in the flask is 0.0756 g.

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Table salt solution is neutral in nature. Lemon juice solution is more acidic in nature and soap solution is slightly basic in nature.

Any combination of one or more solutes that have been dissolved in a solvent is referred to as a solution. To create a homogenous mixture, a solute must dissolve in a solvent. To create a homogenous mixture, a solute must dissolve in a solvent.

The solution of soap is alkaline. Alkaline has a pH greater than 7. While lemon juice has an acidic pH of roughly 2, during metabolism it actually becomes alkaline and has a pH much above 7.

Sodium chloride, or table salt, is the original "salt." A neutral salt is sodium chloride, which is produced by neutralizing sodium hydroxide and hydrochloric acid.

Thus, In this way we can differentiate between table salt solution lemon juice and soap solution.

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Individuals with a strong family history of bipolar disorder: If there is a strong genetic predisposition to bipolar disorder within a family, lithium may be prescribed as a preventive measure to reduce the risk of developing the condition or to manage symptoms in its early stages.

Determining who is most likely to benefit from the use of lithium requires more context about the individuals in question. Lithium is primarily used as a medication to treat certain mental health conditions, particularly bipolar disorder. It helps stabilize mood, reduce the frequency and severity of manic and depressive episodes, and prevent relapses.Given this information, individuals who may benefit from the use of lithium include:Individuals diagnosed with bipolar disorder: Lithium is a first-line treatment for bipolar disorder and has been shown to be effective in managing mood swings associated with the condition.Individuals with a history of manic episodes: Lithium can help control and prevent future manic episodes, providing stability and reducing the risk of impulsive and risky behaviors.Individuals who have not responded well to other medications: In cases where other medications have been ineffective or have caused undesirable side effects, lithium may be considered as an alternative treatment option.It is important to note that the decision to use lithium should be made by a qualified healthcare professional based on a thorough evaluation of the individual's specific condition, symptoms, medical history, and other relevant factors.

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The mass ratio of magnesium in magnesium oxide (MgO) can be calculated by dividing the mass of magnesium (0.712 g) by the mass of magnesium oxide (1.18 g).

To find the mass ratio, we divide the mass of the element of interest (magnesium) by the mass of the compound (magnesium oxide). In this case, the mass of magnesium is given as 0.712 g and the mass of magnesium oxide is given as 1.18 g. So, the mass ratio of magnesium is calculated as follows:
Mass ratio = mass of magnesium / mass of magnesium oxide
= 0.712 g / 1.18 g
Calculating this gives us the mass ratio of 0.604.
Therefore, the mass ratio of magnesium in magnesium oxide is approximately 0.604.

The mass ratio of magnesium in magnesium oxide can be found by dividing the mass of magnesium by the mass of magnesium oxide. In this case, the mass of magnesium is given as 0.712 g and the mass of magnesium oxide is given as 1.18 g. By dividing these two values, we get a mass ratio of approximately 0.604. This means that for every gram of magnesium oxide, there are approximately 0.604 grams of magnesium. This mass ratio is useful in determining the composition of compounds and can be used in various chemical calculations.

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According to the balanced equation, 31.7 grams of nitrogen gas (N₂) reacting with excess hydrogen gas (H₂) will produce a 2.264 moles of ammonia gas (NH₃).

To determine the moles of ammonia formed, we need to convert the given mass of nitrogen gas to moles using its molar mass and the stoichiometric ratio of the balanced equation.

The molar mass of nitrogen gas (N₂) is 28.02 g/mol. To calculate the number of moles of nitrogen gas, we divide the given mass by its molar mass:

31.7 g / 28.02 g/mol = 1.132 mol

According to the stoichiometry of the balanced equation, the ratio between nitrogen gas and ammonia gas is 1:2. This means that for every 1 mole of nitrogen gas, 2 moles of ammonia gas are produced.

Therefore, using the stoichiometric ratio, we can determine the moles of ammonia formed:

1.132 mol N₂ * (2 mol NH₃ / 1 mol N₂) = 2.264 mol NH₃

Thus, upon the complete reaction of 31.7 grams of nitrogen gas with excess hydrogen gas, 2.264 moles of ammonia gas will be formed.

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Firstly, convert the volume of NaOH solution from milliliters to liters:

35 mL × 1 L / 1000 mL = 0.035 L

Now, estimate the number of moles of NaOH:

0.035 L × 0.125 M = 0.004375 moles

Finally, we can use the molar mass of sulfamic acid to determine the mass of sulfamic acid required:

Molar mass of sulfamic acid (H2NSO3H) = 97.09 g/mol

Mass of sulfamic acid = 0.004375 moles × 97.09 g/mol = 0.42 g

So, you will need approximately 0.42 g of sulfamic acid to require 35 mL of the NaOH solution.

Avogadro's number is a basic constant in physics and chemistry that relates the number of atoms or molecules in a sample to the amount of substance. It is defined as the number of entities in one mole of a substance

Avogadro's number is an important concept in chemistry as it allows us to calculate the number of entities in a sample of a substance based on its mass and vice versa. This has numerous applications in pharmacology, material science, and biochemistry, among others.

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Using number of moles, So, you will need approximately 0.42 g of sulfamic acid to require 35 mL of the NaOH solution.

Avogadro's number is a basic constant in physics and chemistry that relates the number of atoms or molecules in a sample to the amount of substance. It is defined as the number of entities in one mole of a substance

Avogadro's number is an important concept in chemistry as it allows us to calculate the number of entities in a sample of a substance based on its mass and vice versa. This has numerous applications in pharmacology, material science, and biochemistry, among others.

Firstly, convert the volume of NaOH solution from milliliters to liters:

35 mL × 1 L / 1000 mL = 0.035 L

Now, estimate the number of moles of NaOH:

0.035 L × 0.125 M = 0.004375 moles

Finally, we can use the molar mass of sulfamic acid to determine the mass of sulfamic acid required:

Molar mass of sulfamic acid (H2NSO3H) = 97.09 g/mol

Mass of sulfamic acid = 0.004375 moles × 97.09 g/mol = 0.42 g

So, you will need approximately 0.42 g of sulfamic acid to require 35 mL of the NaOH solution.

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Explanation:

Matter can be broken down in two categories by pure substance and mixtures. Pure substance are further broken down into elements and compounds. Mixtures are physical combined structures that can be separated into their original components.

Answer:

5

Explanation:

An ion has a net charge of 3+

ion has 8 protons

How many electrons does it have

A neutral atom has equal number of electrons and protons.

If a neutral atom loses electron it acquires a positive charge.

So to acquire 3+ charge the atom must have lost three electrons.

So the number of protons exceeds the number of electrons by 3.

Answer:

Using glucose to provide energy for the body

Explanation:

Answer:

D

Explanation:

Answer:

C

Explanation:

Adding and acid and base together until it is completely neutralized will give us water and a salt.

For example:

HCl + NaOH --> NaCl + H2O

HCl being the acid

NaOH being the base

The H2O is water

The NaCl is the salt

Answer & Procedure

According to the Brønsted-Lowry theory of acid-base, the conjugate base will be CN⁻

The correctly balanced chemical reaction of \(H_2SO_4\) with HI is \(H_2SO_4 + 8HI -- > H_2S + 4I_2 + 4H_2O\)

The equation of chemically balanced reactions must obey the law of conservation.

According to the law of conservation, the number of participating atoms in a reaction must be conserved. In other words, the number before must be the same as after the reaction.

However, the law opines that the forms of atoms may change after reactions.

Sulfuric acid reacts with hydrogen iodide to produce hydrogen sulfide, iodine molecules, and water according to the following equation:

\(H_2SO_4 + HI -- > H_2S + I_2 + H_2O\)

However, the equation is yet to obey the law of conservation. The correctly balanced equation of the reaction would be: \(H_2SO_4 + 8HI -- > H_2S + 4I_2 + 4H_2O\)

The above equation shows that the number of each atom in the reactants is the same as in the product.

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Which of the following shows the correctly balanced chemical reaction reacting with HI?

a. \(H_2SO_4 + 8HI -- > H_2S + 4I_2 + 4H_2O\)

b. \(H_2SO_4 + 4HI -- > H_2S + 2I_2 + 2H_2O\)

c. \(H_2SO_4 + HI -- > H_2S + I_2 + H_2O\)

Taking into account the reaction stoichiometry and limiting reagent, 9 grams of NO can be produced from 12 g of NH₃ and 12 g of O₂.

In first place, the balanced reaction is:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 68 grams of NH₃ reacts with 160 grams of O₂, 12 grams of NH₃ reacts with how much mass of O₂?

\(mass of O_{2} =\frac{12 grams of NH_{3}X160 grams of O_{2} }{68 grams of NH_{3}}\)

mass of O₂= 28.23 grams

But 28.23 grams of O₂ are not available, 12 grams are available. Since you have less mass than you need to react with 12 grams of NH₃, O₂ will be the limiting reagent.

Considering the limiting reagent, he following rule of three can be applied: if by reaction stoichiometry 160 grams of O₂ form 120 grams of NO, 12 of O₂ form how much mass of NO?

\(mass of NO=\frac{12 grams of O_{2} x120 grams of NO}{160 grams of O_{2}}\)

mass of NO= 9 grams

Then, 9 grams of NO can be produced from 12 g of NH₃ and 12 g of O₂.

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