q009) what is true of the ozone hole? a.all of the possible answers are correct. b.it is a zone at the equator where ozone has been completely removed from the atmosphere. c.it is the cause of global warming. d.it is caused by the destructive reaction of chlorofluorocarbons with ozone in the atmosphere.

Answer:

All living things use cellular respiration to turn organic molecules into energy. ... This process makes energy from food molecules available for the organism to carry out life processes. Cellular respiration usually occurs in the presence of oxygen. This is called aerobic respiration.

Answer:

Grassland

Explanation:

Grasslands have too little water to support trees as it does not rain very often in more temperate Grasslands

Answer:When two lines are cut by a transversal, the pairs of angles on one side of the transversal and inside the two lines are called the consecutive interior angles . If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles formed are supplementary

Explanation:

Answer:

solid liquid and gas

Explanation:

ice is a solid then it melts to liquid and evaporates into gas

Answer:

Snow is basically water;

ice/snow is solid state

water is liquid state

vapour is gaseous state

Explanation:

Answer:

1.33%

Explanation:

In an aqueous solution, a weak acid such as acetic acid, will be in equilibrium with its conjugate base, acetate ion, thus:

CH₃CO₂H(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CH₃CO₂⁻(aq )

Where dissociation constant, ka, is defined as the ratio of concentrations of products and reactants:

Ka = 1.8x10⁻⁵ = [H₃O⁺] [CH₃CO₂⁻] / [CH₃CO₂H]

H₂O is not taken into account in the equilibrium because is a pure liquid

When a solution of acetic acid becomes to equilibrium, the original concentration of the acid decreases producing more H₃O⁺ and CH₃CO₂⁻.

The concentrations at equilibrium when a 0.100M solution of acetic acid reaches this state, is:

[CH₃CO₂H] = 0.100M - X

[H₃O⁺] = X

[CH₃CO₂⁻] = X

Where X is reaction coordinate.

Replacing in Ka expression:

1.8x10⁻⁵ = [H₃O⁺] [CH₃CO₂⁻] / [CH₃CO₂H]

1.8x10⁻⁵ = [X] [X] / [0.100M - X]

1.8x10⁻⁶ - 1.8x10⁻⁵X = X²

1.8x10⁻⁶ - 1.8x10⁻⁵X - X² = 0

Solving for X:

X = -0.00135 → False solution. There is no negative concentrations.

X = 0.00133 → Right solution.

That means concentration of acetate ion is:

[CH₃CO₂⁻] = 0.00133M.

Now, percent ionization is defined as 100 times the ratio between weak acid that is ionizated, [CH₃CO₂⁻] = 0.00133M, per initial concentration of the acid, [CH₃CO₂H] = 0.100M. Replacing:

% Ionization = 0.00133M / 0.100M × 100 =

Answer:

new substances

Explanation:

Atoms of different elements can combine to make new substances. A molecule is formed when two or more atoms join together chemically. If atoms combine that are of two or more different elements, we call that a compound. All compounds are molecules, but not all molecules are compounds.

Answer:

metric system

Explanation:

Scientists use the metric system, which uses the following base units: 1. Meter for length 2. Gram for mass 3. Liter for volume 4. Second for time Different prefixes

Answer:

3.39e+20

Explanation:

Answer:

Explanation:

The double replacement reactions among the given options are:

C. KCl + AgNO3 → AgCl + KNO3

D. Cu + Ag(NO3)₂ → Ag + Cu(NO3)₂

These reactions involve an exchange of ions between two compounds, resulting in the formation of new compounds. In a double replacement reaction, the positive ions in the reactants switch places to form new compounds.

Therefore, options C and D are the double replacement reactions.

Answer:

did not

Explanation:

ask

Answer: temperature liquefaction

Explanation: At the exact time the only used method or strategy the division of helium from natural gas is low temperature liquefaction

sorry the pic is blocked

The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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Answer: Carbon Dioxide, Methane, Nitrous Oxide and Fuorinated Gases

Explanation:Carbon dioxide (CO2): Carbon dioxide enters the atmosphere through burning fossil fuels (coal, natural gas, and oil), solid waste, trees and other biological materials, and also as a result of certain chemical reactions (e.g., manufacture of cement). Carbon dioxide is removed from the atmosphere (or "sequestered") when it is absorbed by plants as part of the biological carbon cycle.

Methane (CH4): Methane is emitted during the production and transport of coal, natural gas, and oil. Methane emissions also result from livestock and other agricultural practices and by the decay of organic waste in municipal solid waste landfills.

Nitrous oxide (N2O): Nitrous oxide is emitted during agricultural and industrial activities, combustion of fossil fuels and solid waste, as well as during treatment of wastewater.

Fluorinated gases: Hydrofluorocarbons, perfluorocarbons, sulfur hexafluoride, and nitrogen trifluoride are synthetic, powerful greenhouse gases that are emitted from a variety of industrial processes. Fluorinated gases are sometimes used as substitutes for stratospheric ozone-depleting substances (e.g., chlorofluorocarbons, hydrochlorofluorocarbons, and halons). These gases are typically emitted in smaller quantities, but because they are potent greenhouse gases, they are sometimes referred to as High Global Warming Potential gases ("High GWP gases").

Step-by-step explanation:

The number of carbon atoms present in the structure is 5

Each carbon atom carry four hydrogen atoms

The above organic structure is Pentane

Having a molecular formula of C5H12

The partition coefficient you obtained may or may not match what a chemist would expect based on our understanding of structure and solubility.

The partition coefficient is a measure of how a compound distributes itself between two immiscible solvents, typically water and an organic solvent. It depends on factors such as the polarity, size, and functional groups of the compound. A chemist would expect a compound with a higher polarity to have a higher partition coefficient in water, while a compound with lower polarity would have a higher partition coefficient in the organic solvent. If the partition coefficient you obtained aligns with the expected behavior based on the compound's structure and solubility, it would match what a chemist would expect.

Your obtained partition coefficient may match the chemist's expectation if it corresponds to the compound's structure and solubility properties, such as polarity and functional groups. However, if there is a discrepancy between the experimental results and theoretical expectations, further investigation would be needed to identify any potential sources of error or alternative explanations.

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Answer:

D is the answer

Explanation:

The difference in the means is 2.2.

given that :

original scores are = 75, 85, 90, 90, 100, 75, 80, 100, 90.

Grades after retake the exam = 85, 85, 100, 90, 100, 85,80, 100, 90.

now,

The sum of original score=  75 + 85 + 90 + 90 + 100 + 75 + 80 + 100 + 90

                                            = 785

mean = 785 / 9 = 87.2

sum of score after retake=  85 + 85 + 100 + 90 + 100 + 85 + 80 + 100 + 90

                                          =  805

mean = 805 / 9 = 89.4

the difference in mean is = 89.4 - 87.2

                                          = 2.2

Thus, The difference in the means is 2.2.

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Answer:

23.8g

Explanation :

Convert 2.0M into mol using mol= concentration x volume

2.0M x 0.1L (convert 100mL to L since the units for M is mol/L)

= 0.2 mol

We can now find grams by using the molar mass of KBr

=119.023 g/mol (Found online) webqc.org

but can be be calculated by using the molecular weight of K and Br found on the periodic table

We can now calculate the grams by using grams=mol x molar mass

119.023g/mol x 0.2mol

= 23.8046 g

=23.8g (rounded to 1decimal place)

Answer: The mole ratio of \(PCl_3\) to \(PCl_5\) is 1: 1

Explanation:

According to the balanced chemical equation ,the number of atoms of each element has to be same on reactant and product side. The stoichiometric coefficients of the species represent their number of moles.

\(PCl_3+Cl_2\rightarrow PCl_5\)

Thus in the reactants, there is 1 mole of \(PCl_3\) and 1 mole of \(Cl_2\) molecule. And thus there is 1 mole of \(PCl_5\) in the product as well.

Thus the mole ratio of \(PCl_3\) to \(PCl_5\) is 1: 1

Yes, a metal will always be produced at one electrode during electrolysis.

An electrode is an electrical conductor used to make contact with a nonmetallic part of a circuit.

An electrode can be anode or cathode. During electrolysis, that is , the decomposition of a chemical compound by electricity, a metal will be deposited at the cathode.

Thus, a metal will always be produced at one electrode during electrolysis.

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Answer: FALSE

Explanation: Often, gases rather than metals form at electrodes, especially if it involves the electrolysis of a solution.

Answer:

The stability of atoms depends on whether or not their outer-most shell is filled with electrons. If the outer shell is filled, the atom is stable. Atoms with unfilled outer shells are unstable, and will usually form chemical bonds with other atoms to achieve stability.

Explanation:

Answer:

The stability of atoms depends on whether or not their outer-most shell is filled with electrons. If the outer shell is filled, the atom is stable. Atoms with unfilled outer shells are unstable, and will usually form chemical bonds with other atoms to achieve stability.

Explanation:

A high temperature would favor the reactants in this reaction.

A high temperature would favor the reactants in this exothermic reaction. This is because, according to Le Chatelier's Principle, if a system at equilibrium is subjected to a change in temperature, pressure, or concentration of one of the components, the system will shift its equilibrium position in a way that tends to counteract the change.

In the case of an exothermic reaction, increasing the temperature will shift the equilibrium to favor the reactants in order to absorb the excess heat and return to equilibrium. Therefore, a high temperature would favor the reactants in this reaction.

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The partial pressure of He is 0.5 atm.

To find the partial pressure of He, we first need to calculate the total moles of gas in the mixture:

Total moles of gas = 0.350 moles Ne(g) + 0.250 moles He(g) + 0.400 moles CH₄(g) = 1.0 moles of gas

Next, we can use the mole fraction of He to calculate its partial pressure:

Mole fraction of He = moles of He / total moles of gas
Mole fraction of He = 0.250 moles He(g) / 1.0 moles of gas = 0.25

The partial pressure of He can be calculated using the following equation:

Partial pressure of He = mole fraction of He x total pressure
Partial pressure of He = 0.25 x 2 atm = 0.5 atm

Therefore, the partial pressure of He in the mixture is 0.5 atm.

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A chemical equation is a statement using chemical formulas expresses both the identities and the relative quantities of the reactants and products involved in a chemical or physical change. The correct answer is B.

An expression of the identities and relative quantities of the reactants and products involved in a chemical or physical transformation is called a chemical equation. Chemical equations are statements made using chemical formulas.

In chemical equations, variables like the direction of a reaction and the physical states of the reacting parties are represented by symbols. In 1615, the French chemist Jean Beguin created the first chemical equation.

Chemical equations, such as the one below, can be used to depict chemical reactions on paper (for the reaction between hydrogen gas and oxygen gas to form water).

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According to the concept of solubility, thing which dissolves is solute and in which it is dissolved is solvent , hence juice crystals are solute and water is solvent.

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.

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The new volume of the balloon when heated to 78 oC is approximately 2.89 L, assuming no change in pressure.

The volume of a gas is directly proportional to its temperature when pressure remains constant. This relationship is described by Charles's Law.

To find the new volume of the balloon after it is heated to 78 oC, we can use the formula:

(V1 / T1) = (V2 / T2)

where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Given:
Initial volume, V1 = 2.44 L
Initial temperature, T1 = 23 oC = 23 + 273.15 K = 296.15 K
Final temperature, T2 = 78 oC = 78 + 273.15 K = 351.15 K

We can plug these values into the formula and solve for V2:

(2.44 L / 296.15 K) = (V2 / 351.15 K)

Cross-multiplying:

(2.44 L) * (351.15 K) = (296.15 K) * (V2)

V2 = (2.44 L) * (351.15 K) / (296.15 K)

Calculating:

V2 ≈ 2.89 L

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The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

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