Q2) An engineer borrowed $3000 from the bank, payable in six equal end-of-year payments at 8%. The bank agreed to reduce the interest on the loan if interest rates declined in the United States before the loan was fully repaid. At the end of 3 years, at the time of the third payment, the bank agreed to reduce the interest rate from 8% to 7% on the remaining debt. What was the amount of the equal annual end-of-year
payments for each of the first 3 years? What was the amount of the equal annual end-of-year payments for each of the last 3 years?

Answer: Aerosol Cans

Explanation: I just did the quiz

Answer:

a.) Time = 17.13 seconds

b.) 31.88 m

c.) V = 11.18 m/s

d.) V = 7.1 m/s

Explanation:

The initial velocity U of the automobile is 15.65 m/s.

 At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile with initial velocity U = 0 at a constant acceleration of 1.96 m/s². Because the police is starting from rest.

For the automobile, let us use first equation of motion

V = U - at.

Acceleration a is negative since it is decelerating with a = 3.05 m/s² . And

V = 0.

Substitute U and a into the formula

0 = 15.65 - 3.05t

15.65 = 3.05t

t = 15.65/3.05

t = 5.13 seconds

But the motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s².

The total time required for the police car to overtake the automobile will be

12 + 5.13 = 17.13 seconds.

b.) Using the third equation of motion formula for the police car at V = 11.18 m/s and a = 1.96 m/s²

V^2 = U^2 + 2aS

Where S = distance travelled.

Substitute V and a into the formula

11.18^2 = 0 + 2 × 1.96 ×S

124.99 = 3.92S

S = 124.99/3.92

S = 31.88 m

c.) The speed of the police car at the time it overtakes the automobile will be in line with the speed zone which is 11.18 m/s

d.) That will be the final velocity V of the automobile car.

We will use third equation of motion to solve that.

V^2 = U^2 + 2as

V^2 = 15.65^2 - 2 × 3.05 × 31.88

V^2 = 244.9225 - 194.468

V = sqrt( 50.4545)

V = 7.1 m/s

a) The ideal gas equation of state and the ideal gas law is utilized to calculate the volume flow rate of air at the inlet, which is 2.73 cubic meters per second. b)  The first law of thermodynamics is employed to determine how pressure, temperature, and volume change and the determined internal energy is 108,000 J.

a) The volume flow rate of air at the inlet can be determined using the ideal gas law and the ideal gas equation of state. The equation is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Using the given values, we can determine the volume flow rate (V) to be 2.73 cubic meters per second.

b) The change in pressure, temperature, and volume can be determined using the first law of thermodynamics. The equation is ΔU = Q - W, where ΔU is the change in internal energy, Q is the heat transferred, and W is the work done. Using the given values, we can determine the change in internal energy (ΔU) to be 108,000 J.

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Answer:

Used to recall the direction a standard screw

To meet the demand for component A without increasing lot sizes, 192.86 machines are required, exceeding the available 3 machines.

a. Calculation of machines required for minimum (Pessimistic) demand:

For component A, Processing (hr/unit) = 0.04

Lot Size (units/lot) = 60

Total demand required for pessimistic forecast = 15,000 machines

For pessimistic forecast, the processing time required will be: 15,000 × 0.04 = 600 hours

Setup (hr/lot) = 1.0

For 30% capacity cushion, the total operating hours will be: (600 / (1 - 0.3)) = 857.1428571428571

For expected forecast, the processing time required will be: 16,000 × 0.04 = 640 hours

For 30% capacity cushion, the total operating hours will be: (640 / (1 - 0.3)) = 914.2857142857142

For optimistic forecast, the processing time required will be: 27,000 × 0.04 = 1080 hours

For 30% capacity cushion, the total operating hours will be: (1080 / (1 - 0.3)) = 1542.857142857143

Therefore, the machines required will be:

107.14 machines for pessimistic forecast

114.29 machines for expected forecast

192.86 machines for optimistic forecast

b. Calculation of machines required if the operations manager decides to double lot sizes:

Pessimistic forecast: 120 units/lot

Expected forecast: 150 units/lot

Optimistic forecast: 200 units/lot

The calculation of the total operating hours and machines required will be the same as in part a, with the respective lot sizes.

c. Calculation of the number of machines required with 20% reduced setup time:

New setup time for component A: 0.8 hours/lot

The calculation of the new processing hours and machines required will be the same as in part a, with the reduced setup time.

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Answer:

Full wave rectification flips the negative half cycle of the sine wave to positive so the result is two positive half cycles.

Explanation:

hope it helps a lil

Answer:

D) All of the above.

To ensure that a certain part supplied by a foundry always meets or exceeds ASTM No. 20 specifications for cast iron, the hardness should be specified at 220 Brinell.

ASTM No. 20 specifications for cast iron require a minimum Brinell hardness of 220. This means that the part must be at least this hard in order to meet the standard. If the part is not hard enough, it may not be strong enough to withstand the forces that it will be subjected to in use.

The hardness of a material is a measure of its resistance to indentation. It is measured using a Brinell hardness tester, which applies a force to a small ball indenter until it makes a permanent impression in the material. The size of the impression is then used to calculate the hardness.

In this case, the part must be at least 220 Brinell hard in order to meet the ASTM No. 20 specifications for cast iron. This can be achieved by specifying the correct heat treatment process for the part.

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The maximum allowable value of P that can act on the beam can be determined by considering both the normal stress and the shear stress limits of the wood. Based on the given information, the maximum allowable values for normal stress and shear stress are Ơallow = 1.5 ksi and Tallow = 150 psi, respectively.

To determine the maximum allowable value of P, we need to consider the normal stress and shear stress acting on the beam.

Normal Stress:

The normal stress (σ) can be calculated using the formula σ = P / A, where P is the applied load and A is the cross-sectional area of the beam. In this case, the cross-sectional area is given as 2a (since the beam is rectangular with a depth of 2a).

The allowable normal stress is Ơallow = 1.5 ksi. Rearranging the formula, we can find the maximum allowable value of P:

P = Ơallow * A.

Shear Stress:

The shear stress (τ) can be calculated using the formula τ = V / A, where V is the shear force and A is the cross-sectional area of the beam. In this case, the shear force can be determined by V = P.

The allowable shear stress is Tallow = 150 psi. Rearranging the formula, we can find the maximum allowable value of P:

P = Tallow * A.

Since we need to consider both the normal stress and shear stress limits, we can calculate the maximum allowable value of P by taking the minimum of the two calculations above:

P = min(Ơallow * A, Tallow * A).

Substituting the given values, where a = 3 in and converting units to consistent values, we have:

P = min(1.5 ksi * (2 * 3 in), 150 psi * (2 * 3 in)).

P = min(9 ksi in², 900 psi in²).

Converting ksi in² to lb, 1 ksi in² = 1000 lb, we have:

P = min(9 * 1000 lb, 900 lb).

P = min(9000 lb, 900 lb).

Therefore, the maximum allowable value of P is 900 lb.

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During gait the body of a living organism is gaining speed: a. during terminal stance.

Physical fitness can be defined as a measure of both the physical and mental soundness (wellness) or ability of an individual to engage in physical exercises, sports, work and other day-to-day activities.

For instance, one of the ways in which an individual can model good physical fitness to other individuals in their neighborhood is by:

Gait can be defined as the way and manner in which an animal or individual walks or runs, thereby affecting and altering the shape of the body.

In this context, we can infer and logically deduce that during gait the body of a living organism is gaining speed, especially during terminal stance.

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Answer:

Explanation: Three-phase power is a three-wire ac power circuit with each phase ac signal 120 electrical degrees apart

In order to meet the requirements of the Online University Platform, various architectures need to be implemented. Two important architectural aspects are Technology Architecture and Application Architecture.

Technology Architecture focuses on the hardware, software, and infrastructure components necessary to support the system, while Application Architecture defines the structure and organization of the software applications that form the platform.

Technology Architecture: Technology Architecture encompasses the underlying technological components required to support the Online University Platform. This includes hardware infrastructure such as servers, network devices, and storage systems, as well as software components like operating systems, databases, and middleware. The Technology Architecture ensures that the necessary infrastructure is in place to support the application layer and its requirements. It addresses scalability, availability, performance, security, and other aspects related to the underlying technology stack.

Application Architecture: Application Architecture focuses on the design and organization of the software applications that make up the Online University Platform. It defines how the different modules or components of the system interact with each other, the data flow, and the overall structure of the applications. Application Architecture ensures that the system's functionality aligns with the requirements of the business stakeholders and user needs. It involves defining the software layers, interfaces, protocols, and frameworks used in the system, as well as the overall design patterns and principles.

In summary, Technology Architecture deals with the infrastructure and technology components required to support the Online University Platform, while Application Architecture focuses on the design and organization of the software applications that make up the platform. Both architectures are crucial for ensuring that the system meets the requirements of the project, with Technology Architecture addressing the underlying infrastructure and Application Architecture ensuring the functionality and structure of the software applications.

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To democratize space, three important things to consider are:

a) Accessibility: Making space more accessible to a wider range of people and organizations by reducing costs, simplifying launch procedures, and promoting inclusivity in the space industry.

b) Affordability: Lowering the financial barriers associated with space activities, such as satellite launches, space tourism, or scientific research, to allow more participation from various sectors and individuals.

c) Innovation: Encouraging the development of new technologies, business models, and approaches that enable a broader range of applications and opportunities in space exploration and utilization.

The frequency of rocket launches by a private company in New Zealand, or any other location, depends on various factors such as launch site availability, regulatory approvals, customer demand, and the company's capacity to manufacture and launch rockets. It could be challenging to launch rockets frequently due to logistical constraints, weather conditions, technical issues, or regulatory restrictions.

The specific manufacturing process and speed of rocket engine production can vary depending on the company and its technologies. Generally, rocket engines are manufactured using advanced manufacturing techniques and materials such as 3D printing and precision machining. These processes require careful design, rigorous testing, and quality control to ensure reliability and safety. The speed of production can depend on factors such as the complexity of the engine design, availability of resources, and production capabilities of the company.

The most significant contributor to "space junk" or orbital debris is the accumulation of defunct satellites, spent rocket stages, and fragments resulting from collisions or breakups in space. The Electron rocket, or any other launch vehicle, can help address this problem by incorporating measures to minimize the creation of debris. For example, rockets can be designed with stages that either burn up upon reentry or are deorbited into controlled areas such as oceanic splashdown zones. Additionally, rockets can be designed to deploy satellites in orbits that minimize the risk of collisions with other objects in space.

Please note that these answers are based on general knowledge and assumptions, and they may not specifically address the practices or technologies of a particular company or article you are referring to.

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Answer: None of the above

Explanation:

Business process modeling refers to the graphical representation of the business processes of a company, which is vital in the identification of potential improvements.

Business pticess modelling can be done through graphing methods, like data-flow diagram, flowchart etc. It is vital as business managers can effectively and quickly communicate their ideas.

It also enhances the customization of business processes, enhances the competitive advantage and enhances the process communication as well.

Therefore, the answer to the question will be "None of the above".

Answer:

Explanation:

The missing diagram attached to the question is shown in the attached file below:

The very first thing we need to do in other to solve this question is to determine the mass of both the tractor and the mass of the gravel

For tractor, the mass is:

\(m_1 = \dfrac{2400 \ lb }{32.2 \ ft/s^2}\)

\(m_1 = 74.53 \ lb.s^2/ft\)

For gravel, the mass is:

\(m_2 = \dfrac{900 \ lb}{32.2 \ft/s^2}\)

\(m_2 = 27.95 \ lb.s^2/ft\)

From the diagram, let's consider the force along the horizontal components and vertical components;

So,

\(\sum F_x = ma_x \\ \\ 2F = (m_1+m_2) a \\ \\ F = \dfrac{1}{2}(74.53 4 + 27.950)lb.s^2/ft(2 \ ft/s^2) \\ \\ F = 102.484 \ lb\)

\(\sum F_y = 0 \\ \\ 2N_A+2N_B - 2400 -900 = 0 \\ \\ N_A +N_B = 1650 \ lb\)

Consider the algebraic sum of moments in the plane of A, with counter-clockwise moments being positive.

\(\sum M_A = I_o \alpha + \sum ma (d) \\ \\ = -2400 (20) + 2N_B (60) -900(110) = 0 - (74.534)(2)(20) - (27.950)(2)(40)\)

\(=-48000 + 2N_B (60) -99000 = -2981.36-2236 \\ \\ = + 2N_B (60) = -2981.36-2236+48000+99000 \\ \\ = + 2N_B (60) = 141782.64 \\ \\ N_B = \dfrac{141782.64}{120} \\ \\ N_B = 1181.522 \ lb\)

Replacing the value of 1181.522 lb for \(N_B\) in equation (1)

\(N_A\) + 1181.522 lb = 1650 lb

\(N_A\) = (1650 - 1181.522)lb

\(N_A\) = 468.478 lb

The net reaction on each of the rear wheels now is:)

\(F_R = \sqrt{N_A^2 +F^2}\)

\(F_R = \sqrt{(468.478)^2 + (102.484)^2}\)

\(\mathbf{F_R =479.6 \ lb}\)

Now, we can determine the angle at the end of the rear wheels at which the resultant reaction force is being made in line with the horizontal

\(\theta = tan ^{-1}( \dfrac{468.478 }{102.484})\)

\(\theta = 77.7^0\)

Finally, the net reaction on each of the front wheels is:

\(F_B = N_B\)

\(F_B =\) 1182 lb  

(a) Hansen's assertion that the exploitation of tar sands would make it implausible to stabilize climate and avoid disastrous global climate impacts is supported by available evidence.

Tar sands development releases more greenhouse gas emissions than conventional oil extraction and processing, contributing to climate change. Additionally, transporting tar sands oil through pipelines poses a risk of spills that can harm ecosystems and communities.

(b) Morgan's assertion that exporting LNG to displace coal is a powerful way for Canada to be a leader in helping reduce global emissions is partly supported by available evidence.

While burning natural gas produces fewer emissions than burning coal, it still releases greenhouse gases. Additionally, the process of extracting and transporting natural gas can also result in methane emissions, a potent greenhouse gas.

However, replacing coal with natural gas in the short term can be a useful step in transitioning towards renewable energy sources. Ultimately, a complete shift towards renewable energy is necessary to address climate change.

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Exit lanes give drivers an ample time and space to minimize (reduce) their speed to what is posted and prepare them for the sharpness of the curve.

A speed limit is the maximum amount of speed that is legally permitted in an area for safety. Hence, this limit must be abided and strictly adhered to by all road users such as drivers of a vehicle.

As a safety precaution, Exit lanes are constructed to give drivers an ample time and space to minimize (reduce) their speed to the required  speed limit posted and prepare them for the sharpness of the curve.

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Shaded pole motors are used when very small starting and running torques are required.

Shaded pole motors are a type of single-phase induction motors commonly used in applications where low starting and running torques are sufficient. They are simple and inexpensive motors that find applications in various small appliances, such as fans, refrigerators, and small pumps.

The operation of shaded pole motors relies on the principle of induction. They have a stator with salient poles, and each pole has a portion called a shading coil that is made of a short-circuited copper or aluminum conductor. When an AC voltage is applied to the motor, a rotating magnetic field is created, but due to the presence of the shading coil, there is a phase shift in the magnetic field, resulting in an uneven distribution of magnetic flux. This imbalance creates a small starting torque, and once the motor is running, the shaded pole generates a rotating magnetic field that keeps the motor in motion. However, shaded pole motors generally have low efficiency and limited power output, which restricts their use to applications with low torque requirements.

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By using the concept of heat transfer, we need to add 0.045kg or 45g of ice to the glass of water to cool it from 20∘C to 0∘C.

The heat lost by the water is equal to the heat gained by the ice cubes. We can use the following equation to calculate the heat transfer:

Q = m_w * c_w * ΔT + m_i * L_f

where Q is the heat transfer, m_w is the mass of water, c_w is the specific heat of water, ΔT is the temperature change (20-0 = 20∘C), m_i is the mass of ice, and L_f is the latent heat of fusion of ice.

We know the values of m_w (0.45kg), c_w (4.18kJ/kg⋅∘C), ΔT (20∘C), and L_f (334kJ/kg). We can rearrange the equation to solve for m_i:

m_i = (Q - m_w * c_w * ΔT) / L_f

Substituting the values, we get:

m_i = [(0.45kg) * (4.18kJ/kg⋅∘C) * (20∘C) - 0] / (334kJ/kg

m_i = 0.045kg

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Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

Article 430 that is found in  National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .

Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.

Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

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Answer:

15psig

Explanation:

32. Lathe machine is a machine tool used for shaping various materials like wood and metal. It rotates a workpiece about an axis of rotation to perform various operations.

33. The cutting tool used in Lathe machine is a single point cutting tool.

34. The operation called as internal turning operation is boring. Omaterial-removing operation is performed on the lathe machine.

The workpiece is removed from the workpiece in the lathe machine. There are different material removing operations that can be done on the lathe machine like turning, facing, drilling, etc. Hence, option Omaterial-removing is correct. Since, lathe machine is not used for joining any metals, metal joining operation cannot be performed on it.

Therefore, option Ometal joining is incorrect.

Metal forming operation is also not performed on lathe machine. Metal forming operations include processes such as forging, rolling, etc. Therefore, option Ometal forming is incorrect. Hence, the correct option is Omaterial-removing.

Option Oboring is called as internal turning operation in lathe machine. In the boring operation, a hole is made by removing material from inside a workpiece. The tool used for boring is called a boring tool. Hence, option Oboring is correct.

Milling is an operation performed on a milling machine and it is used to remove material from a workpiece. Hence, option Omilling is incorrect.

Shaping operation is done on a shaper machine. In shaping operation, a workpiece is held in a vice and the cutting tool moves back and forth on the workpiece. Hence, option Oshaping is incorrect. Therefore, the correct option is Oboring.

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Answer:

yes

Explanation:

an idea could be a jack o lantern monster since it Halloween tomorrow  

The peak of the weighing function, w(x), which corresponds to the most likely degree of polymerization, is the M w with the highest population in the weight fraction.

The exponents of the variables are added to determine the term's degree. The degree of the term is given by 2x 4y 3 4 + 3 = 7 7. Because it has a negative exponent, 5x-2y is not a term. 8 A term's degree is zero if it is a constant term and only contains non-zero numbers.

(a) The average probability of the reactive functional group, p, can be used to calculate the probability function, P(x), as shown below:

P(x) = (1-p)^{x-1} * p

For p = 0.985, we get:

P(x) = (1-0.985)^{x-1} * 0.985

P(x) is a decreasing exponential function with x, starting from P(1) = 0.985.

(b) The weighing function, w(x), is given by:

w(x) = x * P(x)

The weighing function, w(x), is a bell-shaped curve with a maximum at some value of x. The maximum corresponds to the most probable degree of polymerization.

(c) The number-average molecular weight, M_n, can be calculated by integrating x*P(x) over all values of x:

M_n = integral [x * P(x) dx] from 1 to infinity

M_n = integral [x * (1-p)^{x-1} * p dx] from 1 to infinity

This integral can be evaluated analytically or numerically using appropriate software.

(d) The weight-average molecular weight, M_w, can be calculated by integrating x^2 * P(x) over all values of x:

M_w = integral [x^2 * P(x) dx] from 1 to infinity

M_w = integral [x^2 * (1-p)^{x-1} * p dx] from 1 to infinity

This integral can also be evaluated analytically or numerically using appropriate software.

The formula for M_n and M_w that we learn in class are:

M_n = Sum(N_i * M_i) / Sum(N_i)

M_w = Sum(w_i * M_i) / Sum(w_i)

where N_i is the number of molecules with molecular weight M_i, and w_i is the weight fraction of molecules with molecular weight M_i.

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Question:

Suppose Alice designs a one-time pad variant: the plaintext is to no longer XOR, but bite-wise multiply the one-time key that is generated uniformly at random. For example: plaintext: 001101 key: 101110 ciphertext: 001100 Is Alice's design good?

The M w with the maximum density in the weight fraction is the top of the weighting function, w(x), which correlates to the most probable degree of polymerization.

A fraction consists of two components. The numerator is the figure at the beginning of the line. It details the number of equal portions that were taken from the total or group. The denominator is the figure that appears below the line.

(a) As illustrated below, this probability function, P(x), can be calculated using the reactive hydroxyl party's average chance, p:

P(x) = (1-p)^{x-1} * p

For p = 0.985, we get:

P(x) = (1-0.985)^{x-1} * 0.985

P(x) is a decreasing exponential function with x, starting from P(1) = 0.985.

(b) The weighing function, w(x), is given by:

w(x) = x * P(x)

The bell-shaped bell curve of such weighing function, w(x), has a maximum at a certain value of x. The highest reflects the level of polymerization that is most likely to occur.

(c) The number-average molecular weight, M_n, can be calculated by integrating x*P(x) over all values of x:

M_n = integral [x * P(x) dx] from 1 to infinity

M_n = integral [x * (1-p)^{x-1} * p dx] from 1 to infinity

This integral can be evaluated analytically or numerically using appropriate software.

(d) The weight-average molecular weight, M_w, can be calculated by integrating x^2 * P(x) over all values of x:

M_w = integral [x^2 * P(x) dx] from 1 to infinity

M_w = integral [x^2 * (1-p)^{x-1} * p dx] from 1 to infinity

This integral can also be evaluated analytically or numerically using appropriate software.

The formula for M_n and M_w that we learn in class are:

M_n = Sum(N_i * M_i) / Sum(N_i)

M_w = Sum(w_i * M_i) / Sum(w_i)

where N_i is the number of molecules with molecular weight M_i, and w_i is the weight fraction of molecules with molecular weight M_i.

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Question:

Suppose Alice designs a one-time pad variant: the plaintext is to no longer XOR, but bite-wise multiply the one-time key that is generated uniformly at random. For example: plaintext: 001101 key: 101110 ciphertext: 001100 Is Alice's design good?

The most popular alloying elements for aluminum are copper, zinc, magnesium, silicon, manganese, and lithium. Chromite, titanium, zirconium, lead, and bismuth were added in trace amounts.

According to the National Electrical Code, a list of aluminum alloys called AA-8000 is utilized to make wire.

Alclad is a type of aluminum sheet created by gluing extremely pure aluminum to a very strong core material.

Al-Li (lithium, occasionally mercury) (lithium, sometimes mercury)

Alnico (aluminum, nickel, copper) (aluminum, nickel, copper)

Birmabright (aluminum, magnesium) (aluminum, magnesium)

Duralumin (copper, aluminum) (copper, aluminum).

Zinc (Zn) 7xxx - The strongest heat-treatable aluminum alloys are created by combining zinc with aluminum and other elements, typically copper and magnesium. Zinc significantly boosts strength and allows precipitation to harden.

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Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.

To determine the member's available strength, we need more information about the specific end connections and their design.

The provided description mentions a W12×79 tension member and end connections with 3/4 in. bolts at 3 in. on center, but without additional details, it is not possible to calculate the member's available strength accurately.

The available strength of a tension member depends on various factors, including the type and arrangement of the end connections, the load distribution, and the material properties. These factors need to be considered in the design and calculation of the member's strength.

If you provide more specific information about the end connections and their design, I can assist you in calculating the member's available strength.

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