qbal attempts three practice papers in mathematics. The probability that he passes the first paper is 0.6. Whenever he gains a pass in a paper, his confidence increases so that the probability of him passing the next paper increases by 0.1. Whenever he fails a paper the probability of him passing the next paper is 0.6. Complete the given probability tree diagram for Iqbal's three attempts, labelling each branch with the correct probability. P P F F F 2b. [2 marks] Calculate the probability that Iqbal passes at least two of the papers he attempts. 2c. [3 marks] Find the probability that Iqbal passes his third paper, given that he passed only one previous paper.

We can say that a and b are identical in absolute value if a and b are nonzero integers such that a divides b (a | b) and b divides a (b | a). That is to say, a =± b.

The transitive property of divisibility serves as evidence for this. We know that there are numbers k and l such that b = ak and a = bl exist if a | b and b | a. We obtain a = alk by substituting the expression for b into the second equation. We can divide both sides by a to get l = 1/k because an is not zero. Given that k and l are both integers, they must both either be 1 or -1. B Equals ak if k = 1, else then b = ak = a(1) = a, and if k = -1, then b = ak = a(-1) = -a. In either case, we have shown that a = ±b.

So if a and b are nonzero integers such that a divides b and b divides a, then we can conclude that a and b have the same absolute value, but possibly opposite signs.

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Answer:

| x | = − 5

Step-by-step explanation:

Let's solve your equation step-by-step.

| x | = − 5

Solve Absolute Value.

| x | = − 5

No solutions. (Absolute value cannot be less than 0.)

No solutions.

I hope this helps :)

Answer:

| x | = -5

Step-by-step explanation:

Let's think about absolute value, the number we stick in side of these magical type "brackets" (so to speak) is always going to end up being positive because absolute value is the distance of a number from 0. Therefore, we know that because "x" cannot be negative in this scenario, the absolute value of x cannot be equal to -5 and therefore would produce a graph with no solution!

$97.056 is the total interest accrued after the first month.

A value or ratio that may be stated as a fraction of 100 is referred to as a percentage in mathematics. If we need to compute a percentage of a number, we should divide it by its whole and then multiply it by 100. The proportion, therefore, refers to a component per hundred. Per 100 is what the term percent signifies. The letter "%" stands for it.

Given, You (or your parents) purchase a new car for $19,725.00 plus 4.75% sales tax. The down payment is $2,175.00 and you (or your parents) have an average credit rating.

The cost of car = 19,725*(1.0475) = 20,661.9375

Down payment = 2,175

So balance amount, P= 20661.9375-2175 = 18,486.9375

So interest for the average rating of a new car = 6.30%

So the interest accrued in first month = 18,486.9375*0.063/12 = $ 97.056

therefore, interest accrued after the first month is $97.056.

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Answer:

NEED:

WANT:

Step-by-step explanation:

Right on Plato! <3

Have a wonderful day!

The needs listed are tuition and fees and staple foods, while the wants are a vacation, a Lamborghini, and a lavish wedding.

The listed needs and wants reflect different aspects of a person's life and priorities. "Tuition and Fees" and "Staple Foods" are necessities that are essential for a person's survival and well-being.

On the other hand, "Vacation," "Lamborghini," and "Lavish Wedding" are desires that are often seen as luxury items or experiences. While having wants is normal and human, it is important to understand that not all wants can be fulfilled, and it is equally important to prioritize needs over wants. Having a balanced approach to spending, budgeting, and financial planning can help ensure that both needs and wants can be met in a sustainable manner.

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Answer:

Step-by-step explanation:

i believe its xy

Answer:

Hi, don't stress this is very easy! So basically, since those segments are equal, you would have to equate them meaning inverse operations. So 3x-4=x+12

The answer would therefore, be x=8

Answer:

276

Step-by-step explanation:

The minus reverses the negative too a positive then you subtract

Answer:

Infinite/Many solutions

Step-by-step explanation:

If u divide 4x+6y=12 then u get 2x+3y=6 so that means there’s infinite solutions

The solutions that match the given differential equation are a)y=0 and b)y=2x.

The differential equation is a homogeneous linear differential equation with constant coefficients, which can be written in the form of y" + p(x)y' + q(x)y = 0. The general solution to this type of equation is y = c1e^(rx) + c2e^(rx) where r is the root of the characteristic equation r^2 + p(x)r + q(x) = 0.

In this case, the equation is of the form xy'' - y' = 0. By dividing both sides by x, we get y'' - (1/x)y' = 0, which is a homogeneous linear differential equation with constant coefficients. The characteristic equation is r^2 - (1/x)r = 0. The roots of this equation are r1 = 0 and r2 = 1/x.

Therefore, the general solution to this differential equation is y = c1 + c2x.

y=0 is a solution of the differential equation since it satisfies the equation when plugged in.

y=2x is also a solution of the differential equation since it also satisfies the equation when plugged in.

y=2x^2 and y=2 are not solutions of the differential equation because when plugged into the equation they don't satisfy it.

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The area of the rectangular lot with the dimension of 10 dm by 15 dm is 1,500 m2.

The area of a rectangular lot can be calculated by multiplying the length (L) and the width (W) of the lot. The formula for calculating the area of a rectangular lot is: Area = L x W. In this case, the length of the lot is 10 dm (decimeters) and the width is 15 dm, so the area is 10 dm x 15 dm = 150 dm2. To convert this to square meters (m2), we need to divide 150 dm2 by 10,000, since there are 10,000 dm2 in 1 m2. Therefore, 150 dm2 = 1,500 m2. So, the area of the rectangular lot with the dimension of 10 dm by 15 dm is 1,500 m2.

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Answer:

A

Step-by-step explanation:

These are cross angles

The sample mean, s is the sample standard deviation, n is the sample size, and t is the critical value of the t-distribution with (n - 1) degrees of freedom.

For the given case, the most appropriate confidence interval would be the t-interval for the population mean. Confidence interval: A confidence interval refers to the range of values that are likely to include the population parameter. Confidence intervals provide us with a range of values where the true mean lies with some degree of certainty. The formula to calculate a confidence interval for the mean with a known population standard deviation is as follows

\(:\[\overline{x}-z\frac{\sigma }{\sqrt{n}}\text{ }\le \text{ }\mu \text{ }\le \text{ }\overline{x}+z\frac{\sigma }{\sqrt{n}}\]Where, \[\overline{x}\]\) is the sample mean, σ is the population standard deviation, z is the critical value of the normal distribution and n is the sample size.

Now, since the population standard deviation is unknown, a t-distribution must be used instead of the normal distribution. Thus, the formula to calculate a confidence interval for the mean with an unknown population standard deviation is as follows:\(\[\overline{x}-t\frac{s}{\sqrt{n}}\text{ }\le \text{ }\mu \text{ }\le \text{ }\overline{x}+t\frac{s}{\sqrt{n}}\]\)

Where, s is the sample standard deviation, and t is the critical value of the t-distribution with n - 1 degrees of freedom. Given that the sample size is 55, the appropriate degrees of freedom to use would be (55 - 1) = 54.Since we are constructing a confidence interval for the true mean filling amount of DoubleStuf Oreos, the appropriate confidence level to use would depend on the desired level of certainty or the margin of error. Commonly used levels of confidence are 90%, 95%, and 99%. A 95% confidence level is usually preferred for most cases.

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Answer:

5/12

Step-by-step explanation:

5/12

Answer: 7,000

Step-by-step explanation: the hundred was greater than 5 so we round up any number after whatever you are doing if it’s 5 or greater you round up

The coordinates  ( 6,-8 ) are plotted by moving 6 units right and 8 units down.

The intersection of the x- and y-axes creates the two-dimensional coordinate plane known as the cartesian plane. The origin is the point at which the x- and y-axes cross perpendicularly.

here, we have,

Given coordinates (6,-8)

for  the cartesian plane, we know that the origin has points (0, 0)

and divided into four Quadrants,

the left side of the origin is a negative x-axis and the right side is a positive x-axis.

and the upside of the origin is a positive y-axis and the downside is a negative y-axis.

here coordinates of x =6 and y = -8

6 is 6 units right from the origin

and -8 is 8 units down from the origin.

Hence for the coordinates , 6 units to the right and 8 units down , is correct.

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To fit the Eiffel Tower model in a 1-foot tall box, a scale of 1:984 would be the best option.

To determine the appropriate scale for the Eiffel Tower model, we need to find the ratio between the height of the actual tower and the height of the model that can fit in a 1-foot tall box.

Given that the actual height of the Eiffel Tower is 984 feet, we want to scale it down to fit within a 1-foot space. To find the scale, we divide the actual height by the desired height of the model:

Scale = Actual height / Desired height

Scale = 984 feet / 1 foot

Scale = 984

Therefore, a scale of 1:984 would be the best option to ensure that the model of the Eiffel Tower fits within a 1-foot tall box. This means that for every 1 unit of height in the model, the actual tower has 984 units of height.

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Step-by-step explanation:

please watch reflection in the picture

The rules AAS, ASA, SSS and SAS are congruence rule of triangle  and the each rules has been explained

The rules AAS, ASA, SSS and SAS are congruence rule of triangle

SSS rule is side-side-side rule, it states that if three sides of the one triangle and three sides of the other triangles are equal, then both triangles are congruent

SAS rule is side-angle-side rule, it states that if two sides and one included angles between the sides of the one triangle is equal to  the two sides and one included angles between the sides of the other triangle, then both triangles are congruent

ASA rule is angle-side-angle rule, it states that if two angles and one included side between the angle of the one triangle is equal to the two angles and one included sides between the angles of the other triangle, then both triangles are congruent

AAS rules is angle-angle-side rule, it states that if two angles and one non included sides of the one triangle is equal to the two angles and one non included sides of the another triangle, then both triangles are congruent

Therefore, the AAS, ASA, SSS and SAS are the rules of congruence of the triangle

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Answer:

15

Step-by-step explanation:

sucks to suck

Answer:

the answer is A

Step-by-step explanation:

Decreasing the period to 1 ms helps ensure bounces will not be noticed (option c).

1. The synchsm samples the state of button A0 every 5 ms. This means that every 5 ms, it checks whether the button is pressed (1) or not pressed (0).

2. The button has a bounce duration of up to 20 ms. When the button is pressed or released, it may exhibit temporary fluctuations in its state due to mechanical factors. This is known as "button bounce."

3. To ensure that bounces are not noticed, the synchsm needs to accurately capture the true state of the button and filter out any temporary fluctuations.

4. Option (a) states that a bounce will never be noticed. However, since the button can bounce for up to 20 ms, this option is not true.

5. Option (b) suggests increasing the period to 30 ms. Increasing the period between samples would provide more time for the button to settle and reduce the chances of capturing a bounce. However, a period of 30 ms is still longer than the maximum bounce duration of 20 ms, so this option does not guarantee that bounces will not be noticed.

6. Option (c) proposes decreasing the period to 1 ms. By reducing the period, the synchsm can sample the button state more frequently, increasing the chances of capturing the true state and minimizing the impact of bounces. This option helps ensure that bounces will not be noticed.

7. Option (d) suggests eliminating the period and running the synchsm as fast as possible. However, without a period, the synchsm would continuously sample the button state, making it susceptible to capturing bounces. Therefore, this option does not help ensure that bounces will not be noticed.

Based on the above analysis, option (c) is the correct answer as decreasing the period to 1 ms helps ensure bounces will not be noticed.

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The coordinates of the point after dilation is P' = (-10, 15)

Given,

Point of P (-4,6) was dilated by a scale factor of 2.5.

To find the coordinates of P'

Dilation with Scale Factor:

The center of dilation is a fixed point in the plane. Based on the scale factor and the center of dilation, the dilation transformation is defined. If the scale factor is more than 1, then the image stretches. If the scale factor is between 0 and 1, then the image shrinks.

Now, According to the question:

Point of P is  (-4,6)

and, Scale Factor is 2.5

The coordinates of the point after dilation :

P' = -4 x 2.5 , 6 x 2.5

P' = (-10, 15)

Hence, The coordinates of the point after dilation is P' = (-10, 15)

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Answer:

5:1 is the unit rate hoping I am right

Barton should use a luggage scale to get the most accurate and appropriate measurement of his packed suitcase before he leaves to catch a flight. A luggage scale is a compact and portable device that is designed specifically to weigh luggage. Using a luggage scale is easy and convenient as it allows travelers to weigh their bags accurately, ensuring that they are within the airline's weight limit. To use a luggage scale, Barton should follow these simple steps:

Step 1: Attach the luggage strap Barton should attach the luggage strap to the handle of his suitcase.The strap should be attached in such a way that it can support the weight of the suitcase without slipping or coming off.

Step 2: Turn on the luggage scale Barton should turn on the luggage scale and wait for it to calibrate. This usually takes a few seconds. Once the scale is calibrated, it will display a zero reading.

Step 3: Lift the suitcase Barton should lift the suitcase by the luggage strap until it is off the ground. The luggage scale will display the weight of the suitcase on its digital display. This reading is the weight of the suitcase including all the contents inside.

Step 4: Check the weight If the weight of the suitcase is less than 50 pounds, Barton can go ahead and catch his flight without worrying about any extra charges. If the weight of the suitcase is more than 50 pounds, Barton will have to remove some items from the suitcase or pay the extra fee charged by the airline.

Therefore, using a luggage scale is the most accurate and appropriate method for travelers like Barton to measure their suitcase weight before boarding their flight.

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Answer:

use a standard digital bathroom scale.

Step-by-step explanation:

If you go twice as fast, your stopping distance will increase by four times (option C).

This relationship is based on the laws of physics and the principles of motion.

When an object is in motion, its stopping distance is influenced by its initial speed, reaction time, and braking capabilities. The stopping distance consists of two components: the thinking distance (the distance traveled during the reaction time) and the braking distance (the distance needed to bring the object to a complete stop).

According to the laws of physics, the braking distance is directly proportional to the square of the initial speed. This means that if you double your speed, the braking distance will increase by a factor of four. In other words, going twice as fast will require four times the distance to come to a stop.

It is important to note that this relationship assumes other factors, such as road conditions and braking efficiency, remain constant. However, in real-world scenarios, these factors may vary and can affect the stopping distance to some extent.

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