Q|C A container in the shape of a cube 10.0cm on each edge contains air (with equivalent molar mass 28.9g /mol ) at atmospheric pressure and temperature 300K . Find(b) the gravitational force exerted on it.

Answers

Answer 1

The gravitational force exerted on the cube-shaped container filled with air is approximately 0.340 Newtons.

To find the gravitational force exerted on the cube-shaped container filled with air, we need to consider the weight of the air contained within the cube. The weight of an object can be calculated using the formula:

Weight = Mass * Gravity

where Mass is the mass of the object and Gravity is the acceleration due to gravity.

To determine the mass of the air inside the cube, we can use the ideal gas law, which relates the pressure, volume, temperature, and molar mass of a gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.

We are given the volume of the cube as (10.0 cm)^3 and the molar mass of air as 28.9 g/mol. To find the number of moles of air, we can rearrange the ideal gas law equation:

n = (PV) / (RT)

Substituting the values, we have:

n = (1 atm * (10.0 cm)^3) / ((0.0821 L·atm/(mol·K)) * 300 K)

n = (1 * 10^5 Pa * (10^(-2) m)^3) / ((8.314 J/(mol·K)) * 300 K)

n ≈ 1.204 mol

Next, we can calculate the mass of the air using the molar mass:

Mass = n * molar mass

Mass = 1.204 mol * 28.9 g/mol

Mass ≈ 34.78 g

Now, we can calculate the gravitational force using the weight formula:

Weight = Mass * Gravity

Since we're dealing with the force exerted on the cube, we'll use the acceleration due to gravity on Earth as the value for Gravity, which is approximately 9.8 m/s².

Converting the mass from grams to kilograms, we have:

Weight = 34.78 g * (1 kg / 1000 g) * 9.8 m/s²

Weight ≈ 0.340 N

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Related Questions

Which statement about force is incorrect

A. Some forces cause objects around us to move.
B. Some forces keep objects around us from moving
C. Force is the ability to change motion and transfer matter.
D. Force causes changes in the motion and energy of matter.​

Answers

Answer:

I don't know sorry brother/sister

Explanation:

please mark as brilliant

The most important effect in clearing the solar nebula of gas and dust was
a. impacts by planetesimals.
b. the solar wind.
c. the sun’s magnetic field.
d. the asteroid belt.
e. radiation pressure.

Answers

The most important effect in clearing the solar nebula of gas and dust was likely the solar wind.

The solar wind is a stream of charged particles that emanate from the sun's corona and travel through the solar system. As the solar wind moves through the nebula, it exerts a force on the gas and dust, causing it to move away from the sun. This process is known as solar wind sweeping. While impacts by planetesimals and radiation pressure may have played a role in clearing the nebula, the solar wind was likely the primary mechanism responsible for the removal of gas and dust.

Additionally, the sun's magnetic field may have played a role in shaping the nebula and influencing the distribution of gas and dust, but it was not the primary force behind its clearing. The asteroid belt is located outside of the nebula and therefore did not contribute to its clearing.

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Select the correct answer. a 70 kilogram mountaineer is standing on the summit of mt. everest. the distance between the mountaineer and the center of earth is 6.39 × 106 meters. what is the magnitude of the force of gravity acting on the mountaineer? (the value of g is 6.673 × 10-11 newton meter2/kilogram2. the mass of earth is 5.98 × 1024 kilograms.) a. 90.5 newtons b. 179 newtons c. 684 newtons d. 781 newtons

Answers

The magnitude of the force of gravity acting on the mountaineer is 781 N, thus the correct answer is d. 781 newtons.

The force of gravity acting on an object is given by the equation: F = G * (m1 * m2) / r^2

Where F is the force of gravity, G is the gravitational constant, m1 is the mass of the object, m2 is the mass of the other object, and r is the distance between the two objects.

Given the mass of the mountaineer is 70 kg, the mass of the Earth is 5.98 x 10^24 kg, and the distance between the mountaineer and the center of the Earth is 6.39 x 10^6 meters

F = G * (70 kg * 5.98 x 10^24 kg) / (6.39 x 10^6 m)^2

F = (6.673 x 10^-11 N m^2/kg^2) * (4.18 x 10^29 kg) / (4.08 x 10^12 m^2)

F = (6.673 x 10^-11 N m^2/kg^2) * (4.18 x 10^29 kg) / (4.08 x 10^12 m^2)

F = 781 N

So the magnitude of the force of gravity acting on the mountaineer is 781 N, thus the correct answer is d. 781 newtons.

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(ii) an object of unknown mass m is hung from a vertical spring of unknown spring constant k, and the object is observed to be at rest when the spring has extended by 14 cm. the object is then given a slight push and executes shm. determine the period t of this oscillation.

Answers

The force due to the mass of the object can be calculated as follows:

F = mg where m is the mass of the object and g is the acceleration due to gravity.

Therefore, the net force acting on the mass is given by:

Fnet = kx - mg

where x is the displacement of the spring from its equilibrium position.

Hence, the equation of motion for the mass is:

m(d²x/dt²) = -kx + mg

We can simplify this equation by dividing both sides by m. This gives us:d²x/dt² + (k/m)x = g

The solution to this differential equation is given by:x(t) = A cos(ωt + φ)where A is the amplitude of the motion, ω is the angular frequency, and φ is the phase angle.ω can be calculated as follows:ω = √(k/m)The period T of the motion is given by:

T = 2π/ω

Therefore, the period T of the oscillation is:

T = 2π/√(k/m)

The spring has extended by 14 cm or 0.14 m when the object is at rest.

m = unknownk = unknownx = 0.14 m

We can find k by using the formula for the potential energy stored in the spring:

U = (1/2)kx²

At the equilibrium position, the potential energy is zero. Therefore,

U = (1/2)kx² = 0.5k(0.14)² = 0Solving for k, we get:

k = 25 N/m

Now, we can find the period of the motion:

T = 2π/√(k/m)We know that the object is at rest when the spring has extended by 0.14 m. Therefore, the amplitude of the motion is also 0.14 m.

Hence,ω = √(k/m) = √(25/m)Also,

T = 2π/ω = 2π/√(25/m)

Therefore, the period T of the oscillation is:

T = 2π/√(k/m) = 2π/√(25/m) = 2π/√(m/25) = 0.8√(m/25) s

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Given the production rules below, is the plus operator (+) left-associative, right-associative, or neither? You need to provide a sample sentence and a parse tree of it that supports your answer.

S → T + S | T

T → 1 | 2 | 3

Answers

Given the production rules below, is the plus operator (+) left-associative, right-associative, or neither a parse tree of it is in the explanation part below.

In the provided production rules, the addition operator (+) is left-associative.

Consider the statement "1 + 2 + 3" to show this.

This sentence's parse tree is as follows:

The addition operator's left-associativity is shown in this parse tree. The operands 1 and 2 are combined by the leftmost plus operator, and the resultant total is merged with the operand 3 by another plus operator. This depicts the assessment of the statement "1 + 2 + 3" from left to right.

If the plus operator were right-associative, the parse tree would be different, with the rightmost plus operator first combining operands 2 and 3, and then combining the resultant sum with operand 1.

Thus, the parse tree is attached below as image.

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Given the production rules below, is the plus operator (+) left-associative, right-associative, or neither?

When the driver presses the brake pedal, his car stops with an acceleration of - 8.7 m/s. How far will the car travel while coming to a complete stop if its initial speed is 10 m/s? A. 10.2 m B. 13.1 m C. 9.5 m D. 5.7m

Answers

Answer:

D. 5.7 m

Explanation:

The acceleration of the car is -8.7 m/s² and the car has an initial speed (u) of 10 m/s. The car said to come to rest, that means that the final velocity (v) of the car is 0 m/s.

To find the distance traveled by the car (s) before complete stop, this equation is being used:

v² = u² + 2as

\(2as=v^2-u^2\\s=\frac{v^2-u^2}{2a}\\ Substituting:\\s=\frac{0-10^2}{2*-8.7}\\ s=\frac{-100}{17.4}\\ s=5.7\ m\)

The car traveled 5.7 m before coming to a complete stop

For an object falling at the terminal velocity, list all the forces (magnitude and direction) acting it?

Answers

Answer:

Three stages of falling

There are three stages as an object falls through a fluid:

at the start, the object accelerates downwards due to the force of gravity

as the object's speed increases, frictional forces such as air resistance or drag increase

at terminal velocity, the weight of the object due to gravity is balanced by the frictional forces, and the resultant force is zero

Explanation:

For an object falling at the terminal velocity, list all the forces (magnitude and direction) acting

An apple drops from a tree and hits the ground in 1.2s . Calculate how far it falls.

Answers

The apple falls approximately 7.07 meters before it hits the ground.

To calculate how far the apple falls, we can use the equation for the distance fallen under the influence of gravity:

Gravity is a fundamental principle of physics which states that all objects in the Universe are attracted to each other through the gravitational force
distance = 0.5 * g * t^{2}
where g is the acceleration due to gravity (approximately 9.81 m/s^{2}) and t is the time it takes for the apple to fall (1.2 s).
Step 1: Square the time (t^{2})
t^{2} = 1.2 * 1.2 = 1.44
Step 2: Multiply 0.5 * g * t^{2}
distance = 0.5 * 9.81 * 1.44
Step 3: Calculate the distance
distance ≈ 7.07 meters

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Suppose i create a two-slit interference pattern using light with some wavelength lambda and slits with some separation d. If i were to increase lambda, what would happen to the interference pattern on the wall?.

Answers

If we increase the wavelength (λ), fringe width will increase and the interference pattern on the wall will spread out.

What is two - slit interference?

The double or two-slit interference is a demonstration that light and matter can display characteristics of both classically defined waves and particles.

It  also displays the fundamentally probabilistic nature of quantum mechanical phenomena.

During a two-slit interference experiment, a beam of light is aimed at a barrier with two vertical slits.

The fringe  width is given by the relation

fringe width = λ L / D

where;

λ is wavelength of light used, L is distance of wall from the source of light and D is slit separation.

Thus, if we increase the wavelength (λ), fringe width will increase and the interference pattern on the wall will spread out.

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A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 2.00 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do?

Answers

Answer:

628 J  

Explanation:

Force of friction x distance = work

force of friction = normal force * coeff

                          =  ( 80 kg * 9.81 m/s^2) * .4 = 313.92 N

3139.2N  * 2 m  = 627.84  J  = ~ 628 J

If 100 J of work is done by lifting a box 1.5 m, then how much mass was the box?

Answers

The mass of the box is approximately 6.8 kg. To calculate the mass of the box, we need to use the formula for work: work = force x distance x cos(theta),.

where theta is the angle between the force and the displacement. In this case, we know that the work done was 100 J and the distance lifted was 1.5 m. We also know that the force required to lift the box is equal to its weight, which can be calculated using the formula weight = mass x gravity, where gravity is approximately 9.8 m/s^2.

So, we can rearrange the formula for work to solve for force: force = work / (distance x cos(theta)). Since the box was lifted vertically, the angle between the force and the displacement is 0 degrees, so cos(theta) = 1.
Therefore, force = 100 J / (1.5 m x 1) = 66.67 N. To find the mass of the box, we can use the formula weight = mass x gravity and plug in the force we just calculated:
weight = mass x gravity
66.67 N = mass x 9.8 m/s^2
mass = 6.80 kg

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help me plz Your starting fitness level is known as__________. (10 points) a starting point b beginning level c baseline d entry level

Answers

Answer:

Would it be starting point?

Explanation:

When you start a sport or something, you may not be good or bad at it. However, as time goes on you are going to improve.

Idk if this helps or not buh yeah

A tennis ball is dropped off of some stadium bleachers. If the ball was in free fall for 3
seconds, how high were the bleachers( how far did the tennis ball fall)? For acceleration
due to gravity on Earth use 10 m/s².

Answers

The height of the bleachers when a tennis ball dropped from the top and takes 3 seconds in flight is 45 m.

What is height?

Height can be defined as the vertical distance between two points.

To calculate the height of the bleachers, we use the formula below.

Formula:

H = ut+gt²/2............ Equation 1

Where:

H = Height of the bleachersu = Initial velocity of the tennis ballt = Timeg = Acceleration due to gravity

From the question,

Given:

u = 0 m/st = 3 secondsg = 10 m/s²

Substitute these values into equation 1

H = (0×3)+(10×3²)/2H = 45 m.

Hence, the height of the bleachers is 45 m.

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Newton’s second law of motion is also known as law of _____

Answers

Newton’s second law of motion can also be knows as the law of acceleration

Mateo moved the teacher's table with 50 N of force for 2 meters.. How
much work is done in pushing the table?

Answers

Statement:

Mateo moved the teacher's table with 50 N of force for 2 meters.

To find out:

The work done in pushing the table.

Solution:

Force (F) = 20 NDisplacement (s) = 2 mAngle between displacement and force (θ) = 0

We know, work is said to be done when force acting on a body produces motion in the direction of force applied.And the formula for work done isF s Cos(θ)

Therefore, the work done in pushing the table= 50 × 2 × Cos (0°) J= 100 × 1 J= 100 J

Answer:

The work done in pushing the table is 100 J.

Hope it helps.

If you have any query, feel free to ask.

A motorcycle patrolman starts from rest at A two seconds after a car, speeding at the constant rate of 120km/h, passes point A. If the patrolman accelerates at the rate of 6m/s^2 until he reaches his maximum permissible speed of 150km/h, which he maintains, calculate the distance from point A to the point at which be overtakes the car

Answers

The distance from point A to the point at which the patrolman overtakes the car is 2700 meters.

The distance from point A to the point at which the motorcycle patrolman overtakes the car is 2700 meters. Here's a step-by-step breakdown of the calculations:

Step 1:

Distance covered by the car in 2 seconds:

Distance = Speed * Time

Speed = 120 km/hr = (120/3600) m/s = (1/30) m/s

Time = 2 seconds

Distance = (1/30) m/s * 2 s = 2/30 km = (2/30) * 1000 m = 66.67 m

Step 2:

Calculating the time taken by the motorcycle patrolman to reach a speed of 150 km/h:

Using the equation v = u + at

Initial velocity (u) = 0 m/s

Final velocity (v) = 150 km/h = (150000/3600) m/s = (125/3) m/s

Acceleration (a) = 6 m/s^2

(125/3) m/s = 0 m/s + 6 m/s^2 * t

Solving for t:

t = (125/3) / 6 sec = (125/3) * (1/6) sec = 125/18 sec

Step 3:

Calculating the distance covered by the motorcycle patrolman in the first (125/18) seconds:

Using the equation s = ut + (1/2)at^2

Initial velocity (u) = 0 m/s

Acceleration (a) = 6 m/s^2

Time (t) = 125/18 sec

s = 0 * (125/18) + (1/2) * 6 * ((125/18)^2) = 1562.5/9 m

Step 4:

Calculating the time taken by the motorcycle patrolman to overtake the car:

Let the time taken be t sec

Speed of the car = 120 km/hr = (100/3) m/s

Distance covered by the car in time t = (100/3) m/s * t

Distance covered by the motorcycle patrolman in time t = Distance covered by the car in time t + Distance covered by the motorcycle patrolman in the first (125/18) sec

Time taken = (Distance to be covered) / (Speed of the motorcycle patrolman)

= (Distance covered by the motorcycle patrolman in time t - Distance covered by the motorcycle patrolman in the first (125/18) sec) / [(150000/3600) m/s]

= [(100/3) * t + 1562.5/9 - 1562.5/9] / [(150000/3600)] sec

= [(100/3) * t] / [(150000/3600)] sec

= (1/45) * t sec

The two times should be equal, so we can set up the equation:

(100/3) * t + 1562.5/9 = (1/45) * t

Solving for t:

(3200/45) * t + 1562.5/9 = t

[(3200/45) - (1/45)] * t = 1562.5/9

t = (1562.5 * 45) / (9 * 3199) sec

Step 5:

Distance from point A to the point at which the motorcycle patrolman overtakes the car:

Distance = Distance covered by the motorcycle patrolman in the first (125/18) sec + Distance covered by the motorcycle patrolman in time t

Distance = 1562.5

/9 + [(100/3) * t + 1562.5/9 - 1562.5/9] m

= 1562.5/9 + (100/3) * (1562.5 * 45) / (9 * 3199) m

= 1562.5/9 + 10425/3199 m

= [(1562.5 * 3199) + 10425] / 28791 m

= 2700 m

Therefore, the distance from point A to the point at which the motorcycle patrolman overtakes the car is 2700 meters.

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3. An earthquake measures 3 on Richterscale:
(i)Would it be recorded by a seismograph ?
(ii)ls it likely to cause much damage ?​

Answers

Answer:

Yes, it would be recorded by a seismograph. The earthquake with magnitude of 3 on Richter Scale is not likely to cause much damage

SUMMER BUTLER:
Mr. Butler and a box of Twinkies have a combined mass of 115kg. They reach a maximum speed of 5 m/s
when going down a water slide at Kings Island. The height of the water slide used is 8 meters high.
Calculate the GPE and KE of Mr. Butler and a box of Twinkies:
GPE=
KE=

Answers

The GPE of Mr. Butler and a box of Twinkies is 9016 J and KE of Mr. Butler and a box of Twinkies is 287.5 J

GPE = m g h

GPE = Gravitational potential energy

m = Mass

g = Acceleration due to gravity

h = Height

m = 115 kg

g = 9.8 m / s²

h = 8 m

GPE = 115 * 9.8 * 8

GPE = 9016 J

KE = 1 / 2 mv²

KE = Kinetic energy

v = Velocity

v = 5 m / s

KE = 1 / 2 * 115 * 5

KE = 287.5 J

Therefore,

GPE = 9016 JKE = 287.5 J

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how much energy the fission of 1 kg of coal (if possible) releases compared to combustion of 1 kg of coal? (heating value of coal is of the order of 35 mj/kg).

Answers

The fission of 1 kg of coal does not release any energy because coal does not undergo nuclear fission.

However, the combustion of 1 kg of coal releases approximately 35 MJ (megajoules) of energy based on its heating value. Combustion is a chemical reaction that involves the reaction of coal with oxygen, resulting in the release of thermal energy in the form of heat.

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* Question Completion Status: Moving to another question will save this response. Question 29 Which one of the following statements is not true? (choose all apply) O UV radiation is a type of ionizing

Answers

One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.

UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.

UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.

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A sled is pulled at a constant velocity across a horizontal snow surface. If a force of 100 N is being applied to the sled rope parallel to the ground, what is the force of friction between the sled and the snow?

Answers

Answer:

60.18 N

Explanation:

Given that:

The force applied on the sled = 100 N

Suppose, the angle between the sled rope and the ground = 53°

The horizontal force which acts  in the horizontal direction can be expressed as:

\(F_x = F \ cos \theta\)

\(F_x = 100 \ cos (53)\)

\(F_x = 60.18 \ N\)

But if the angle between the sled rope is parallel to the ground. Then, we use an angle on a straight line which is = 180°

\(F_x = F \ cos \theta\)

\(F_x = 100 \ cos (180)\)

= 100 × -1

= -100 N

a nuclear fission power plant has an actual efficiency of 39%. if 0.25 mw of power are produced by the nuclear fission, how much electric power does the power plant output?

Answers

The power output is  0.0975 MW

What is the  efficiency of a fission power plant?


The efficiency of a fission power plant refers to the percentage of the energy released during nuclear fission that is converted into usable electrical energy. The efficiency of a fission power plant depends on various factors, such as the design of the reactor, the type of fuel used, and the efficiency of the power conversion system.

Efficiency = Power output/ Power input * 100/1

39 = x/0.25 * 100

39/100 * 0.25

= 0.0975 MW

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Shown below is a 10 kg block being pushed by a horizontal force F of magnitude 200N. The coefficient of kinetic friction between the two surface is 0.50. Find the acceleration of the block.

Answers

Answer:

15.1 m/s²

Explanation:

Step 1: Calculate the force exerted by the friction

Friction exerts a force against the direction of the movement. On a horizontal plane, we can calculate the value of that force using the following expression.

Ff = μ × m × g

where,

μ: coefficient of kinetic friction

m: mass of the block

g: gravity

Ff = 0.50 × 10 kg × 9.81 m/s² = 49 N

Step 2: Calculate the resulting force

The horizontal force F and the friction force Ff are vectors that act in opposite directions. We can calculate the resulting force (R) by doing the subtraction.

R = F - Ff = R = 200 N - 49 N = 151 N

Step 3: Calculate the acceleration of the block

We will use Newton's second law of motion.

R = m × a

a = R/m

a = 151 N/10 kg = 15.1 m/s²

Directions: Answer the following questions in your own words using complete sentences. Do not copy and paste from the lesson or the internet.

1. What is the definition of a community in environmental science? Give an example of a community. What does a species first have to do in order to become a member of a community?

2. What is a habitat? Under what conditions can two or more species inhabit a habitat? Be specific and give examples.

3. Under what conditions is species diversity the greatest?

4. Explain the concepts of protocooperation, mutualism, commensalism, parasitism? Give an example of each. What is tolerance? Give an example. How do interactions among species influence what exists in a community? Give some examples of positive and negative interactions. How does predation affect a community? What happens when a keystone predator is removed from a community?

5. What causes community changes? Compare and contrast primary succession and secondary succession. Be specific and give examples.

Answers

Answer:

1. In environmental science, a community refers to a group of interacting species that live together in a particular habitat. An example of a community is a coral reef ecosystem, which includes a variety of species such as fish, algae, and invertebrates. In order to become a member of a community, a species must be able to survive and reproduce in the habitat and interact with other species.

2. A habitat is the physical environment where a particular species lives and obtains its resources, such as food, water, and shelter. Two or more species can inhabit a habitat if they are able to coexist and share resources without competition or conflict. For example, in a freshwater pond, various species of fish, frogs, and insects can coexist if they occupy different niches within the habitat.

3. Species diversity is greatest under conditions of high productivity, stable environmental conditions, and low levels of disturbance. For example, a tropical rainforest with high levels of rainfall and temperature stability will typically have greater species diversity than a desert with harsh and unpredictable environmental conditions.

4. Protocooperation refers to a mutually beneficial relationship between two species that work together, but not as closely as in mutualism. An example is the relationship between bees and flowers, where bees collect nectar from flowers for food and in the process, help pollinate the flowers. Mutualism is a relationship where both species benefit from each other. An example is the relationship between bees and flowers, where bees collect nectar for food, and in the process, transfer pollen from one flower to another, aiding in reproduction. Commensalism refers to a relationship where one species benefits while the other is neither helped nor harmed. An example is the relationship between barnacles and whales, where barnacles attach themselves to the whale's skin and gain protection and access to food, while the whale is not affected. Parasitism refers to a relationship where one species benefits while the other is harmed. An example is the relationship between ticks and deer, where the tick feeds on the deer's blood, causing harm and potentially spreading disease. Tolerance refers to a species' ability to survive and reproduce in the presence of other species. An example is the ability of some plant species to tolerate shade from other plants. Interactions among species influence what exists in a community by affecting population sizes, distribution, and resource availability. Positive interactions, such as mutualism, can promote coexistence and increase species diversity, while negative interactions, such as competition or predation, can limit population sizes and reduce species diversity.

5. Community changes can be caused by both biotic and abiotic factors, such as climate change, natural disasters, and human activities. Primary succession occurs in areas where no soil exists, such as on newly formed volcanic islands or after a glacier retreats. In this process, pioneer species such as lichens and mosses begin to colonize the area, gradually building up soil and creating conditions for other plant species to grow. Secondary succession occurs in areas where soil already exists, such as after a forest fire or clear-cutting. In this process, plant and animal species gradually recolonize the area, with some species growing more quickly than others depending on their adaptations and the availability of resources. An example of primary succession is the colonization of the volcanic island of Surtsey by pioneer species, while an example of secondary succession is the regrowth of a forest after a fire.

Explanation:

A community in environmental science is a group of different species living together and interacting in a specific area. For example, a coral reef ecosystem is a community where corals, fish, algae, and invertebrates coexist. To become a member of a community, a species needs to find a suitable habitat and establish interactions with other species.

A habitat is the specific physical environment where organisms live. It includes both living and non-living factors that affect survival and reproduction. Two or more species can inhabit a habitat when they can coexist and share resources without significant competition. For instance, a forest habitat accommodates various trees, understory plants, birds, mammals, and insects, each occupying different niches.

Species diversity is greatest under conditions of high ecological complexity, such as diverse habitats, moderate environmental disturbance, and a wide range of resources. Biodiversity is higher in tropical rainforests, coral reefs, and diverse ecosystems that provide various niches for species to thrive.

Protocooperation is a mutually beneficial interaction between different species without full dependency. An example is oxpecker birds feeding on ticks from zebras, benefiting from food while the mammals get parasite removal. Mutualism is a symbiotic relationship where both species benefit, like flowering plants providing nectar for bees while bees aid in pollination. Commensalism benefits one species without affecting the other, such as orchids growing on tree branches. Parasitism benefits the parasite at the host's expense, like ticks feeding on mammalian blood. Tolerance is the ability of species to withstand challenging conditions, such as plants tolerating extreme temperatures.

Interactions among species influence community composition, structure, and dynamics. Positive interactions like mutualism and protocooperation enhance diversity, while negative interactions like competition and predation limit certain species. Predation affects population dynamics and distribution of prey, which cascades through the community. The removal of a keystone predator disrupts the balance, leading to increased prey abundance and potential negative impacts on other species.

Community changes can result from natural disturbances, human activities, climate change, and evolutionary processes. Primary succession occurs in lifeless areas like bare rock, starting with pioneer species such as lichens. They modify the environment, enabling the establishment of other species. Secondary succession happens in disturbed areas with remnants of the previous community, beginning with fast-growing plants and eventually restoring a diverse community. Examples include the formation of a new island through volcanic activity (primary succession) and forest regeneration after a fire (secondary succession).

A 10 kg box falls off a building. The box is shown at 4 different positions along its
path.

For each position of the box, calculate the potential energy (PE). Then use the law of
conservation of energy to determine the kinetic energy (KE). Calculate the velocity of the box
at each point for extra credit.

A 10 kg box falls off a building. The box is shown at 4 different positions along itspath.For each position

Answers

Main answer-

PE=mgh

KE=E-PE

V = (2*g*h)^½

at point A

PE = 10*9.8*50=4900 J

KE = 0 J  ( because the velocity of the body is 0)

V=0

at point B

PE = 10*9.8*35=3430 J

KE = 4900-3430=1470 J

V= ( 2*9.8*15)^ ½

V=17.14 m/s

at point C

PE= 10*9.8*25=2450 J

KE=4900-2450=2450 J

V= (2*9.8*25)^ ½

V=22.135 m/s

at point D

PE=10*9.8*0=0 J

KE=4900-0=4900 J

V=(2*9.8*50)^ ½

V=31.30 m/s

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Zeb was moving his dresser. He pushed with 1000N and the resulting acceleration was 200m/s2. What was its mass?

Answers

Answer:

5

Explanation:

Formula for Mass (for this question)

\(mass=\frac{Force}{Acceleration}\)

mass= 1000N/200\(m^{2}\)=5

(pls do correct me if I have any mistakes it would rlly help others!)

three point-like objects with masses of 1 kg, and 3 kg, are located at (0 m, 0 m), (1 m, q m), and (2 m, 2 m), respectively. what is the location of the center of mass of this system?

Answers

The location of the center of mass of this system is (1 m, (3q + 2) / 5 m).



First, we can calculate the total mass of the system by adding up the individual masses:

total mass = 1 kg + 3 kg + 1 kg = 5 kg

Next, we can use the formula for the coordinates of the center of mass:

\(x_cm = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3) y_cm = (m1y1 + m2y2 + m3y3) / (m1 + m2 + m3)\)
where m1, m2, and m3 are the masses of the objects, and x1, y1, x2, y2, x3, y3 are their respective coordinates.

pluging in the values, we get:

\(x_cm = (1 kg x 0 m + 3 kg x 1 m + 1 kg x 2 m) / (5 kg) = 1 m y_cm = (1 kg x 0 m + 3 kg x q m + 1 kg x 2 m) / (5 kg) = (3q + 2) / 5 m\)

Therefore, the location of the center of mass of this system is (1 m, (3q + 2) / 5 m).

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Which item has the least thermal energy? (APEX)
Oh. 5 kg cold water
OB. 5 kgice
O C. 5 lg boiling water
O D. 5 lg hot water just below the boiling point

Answers

Answer:

5 KG of ice would have the lowest thermal energy

Answer:

its A; 5 kg of ice

Explanation:

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Answers

Answer: b

Explanation: just did it

What are the major forces that drive movements in the atmosphere?

Answers

The four driving forces within the atmosphere
a) Gravity, b) Pressure gradient force, c) Coriolis force, & d) Friction force
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