Question 1 (2 points)


2. 5 L of a gas is heated from 200 K to 300 K. What is the final volume of the gas?

When determining whether a chemical reaction has taken place, you observe and look that heat is given off for several indicators.

What is an exothermic reaction?

When new bonds form in the products, less energy is produced during an exothermic reaction than is required to break bonds in the reactants. Energy is continuously released during an exothermic process, frequently in the form of heat. Exothermic reactions characterize all combustion processes.

According to the given question:

Complete question is given below.

Because melting is a physical change, A cannot be the solution. There was no chemical reaction.

The answer is B since it is an EXOTHERMIC REACTION and heat will be produced.

C is not the correct response since dissolving essentially involves atoms changing into ions rather than a chemical process in which one reactant combines with another to produce a different reactant.

D is not a valid response. same justification as why answer A is incorrect.

Hence, B is the correct option.

The question is When determining whether a chemical reaction has taken place, you observe and look for several indicators. Which would be considered an indication that a chemical reaction or chemical change has taken place? A) Solid melts. B) Heat is given off. C) Substance dissolves D) Substance changes shape.

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Answer:

One mole of H2O corresponds to 18 g .

The molecular formula of the compound would be C2HCl having empirical formula ch.

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Answer:Gravity and inertia

After 9 million years, only 12.5% of the original isotope will remain.

The half-life of a radioactive isotope is the amount of time it takes for half of the atoms in a sample to decay. In this case, the half-life of the isotope is 3 million years, which means that after 3 million years, half of the isotope will have decayed, and half will remain. After another 3 million years (for a total of 6 million years), half of the remaining isotope will have decayed, leaving 25% of the original amount.

After another 3 million years (for a total of 9 million years), another half of the remaining isotope will have decayed, leaving 12.5% of the original amount.

To find out what percent of the isotope is left after 9 million years, we can use the formula:

Percent remaining =\((0.5)^{(t/h)\) x 100

Where t is the time elapsed and h is the half-life of the isotope. Plugging in the values, we get:

Percent remaining = \((0.5)^{(9/3)\) x 100
Percent remaining = \((0.5)^3\) x 100
Percent remaining = 12.5%

Therefore, after 9 million years, only 12.5% of the original isotope will remain. The isotope has undergone three half-lives, each time reducing its quantity by half, resulting in a significant decrease in the overall amount present.

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Answer:

3.213J/mol

Explanation:

first specific heat capacity of water = 4200J/Kg K

Q=mass×temperature difference×specific heat capacity

Q=1.53×(24.3-20)×4200

Q=25.704 J

heat of solution= quantity of heat ÷ amount of substance

heat of solution= 25.704÷8

heat of solution= 3.213J/mol

Answer:

Eat healthy food  and exercise daily also undertake good healthcare

There are some special exercises that help to increase brain strength you can do them

D. CsF would require the least amount of energy to separate into ions.

The substance for which the least energy is expected to change over one mole of the strong into independent particles is (d) CsF, cesium fluoride. This is due to the fact that of the available options, CsF has the highest ionic character.

The difference in electronegativity between the components of the compound is what determines the ionic character. The larger electronegativity difference between Cs and F results in a stronger ionic bond. The higher the ionic person, the more vulnerable the connection between the particles, requiring less energy to break and separate them into particles.

Consequently, of the aforementioned substances, CsF would require the least amount of energy to separate into ions.

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Which is the best reason to carry out scientific research on climate change?

A. To help people prepare for the future

C. To elect better-informed politicians

D. To win political debates

Answer:

to create jobs for scientists

First of all, Z is unknown. I hope it is a mistake.

        Now, it is given that the element X has nineteen electrons. This proves that X is actually Potassium.

        As per the periodic table, both Potassium and Lithium belongs to group 1 as their valency is 1 because of the presence of only one electron in the outermost shell of electrons i.e., they lose an electron during a chemical reaction to form a stable compound. Furthermore, both are metallic.

        Magnesium belongs to group 2 and hence its valency is two, which is different from potassium though it is metallic. Similiarly, bromine belongs to group 17 and gains one electron during a reaction in contrast to potassium.

( No internal links available for reference. For clarification, check the periodic table).

a. Consistency is a term that matches the description: The agreement between several measurements of the same quantity.

b. Density matches the description: Ratio between the mass and volume of a substance.

c. Outlier matches the description: In a series of measurements of the same quantity, one that is significantly different from the others.

d. Mean matches the description: Mathematical value reported when a quantity is measured multiple times.e. Immiscible is a term describing two liquids that do not mix together.

Definition: Immiscibility is the property of not being miscible. When two or more liquids are not able to form a homogeneous solution when combined, they are immiscible. The term "miscible" refers to the property of being mixed. Therefore, immiscible liquids cannot be mixed together or dissolved in one another.

Limiting reagent (also known as limiting reactant) is a chemical reaction term that refers to the substance that limits the quantity of product that can be formed in a chemical reaction. It is the substance that is entirely consumed first, preventing the other reactants from reacting further. The amount of product generated is determined by the quantity of the limiting reagent. In a chemical reaction, the quantity of the product produced is determined by the limiting reactant, and the rest of the excess reagents will remain unchanged.

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Answer:

I presume you are talking about Nitric Oxide so the molar mass of NO is 30g/mol 30 g / m o l.

Then you should substitute the respective values from the formula above.

Doing that the mass of NO formed is 4.413 g or just 4.4 grams.

Answer:

c

Explanation:

formation is an igneous rock

The ending is changed to -ide. This is the way by which the name of the second element in a covalent molecule changed. Therefore, the correct option is option A.

When more than two nonmetals unite, covalent bonds are created. For instance, water is created when two nonmetals, hydrogen and oxygen, interact through the formation of covalent bonds. Molecular compounds are those that contain just non-metals or semi-metals combined with non-metals and exhibit covalent bonding.

Ionic bonding will typically be present in compounds where a metal is bound to either another substance or a semi-metal. Because sodium and chlorine are ionic (a metal plus a non-metal), the chemical they create will be ionic. The ending is changed to -ide. This is the way by which the name of the second element in a covalent molecule changed.

Therefore, the correct option is option A.

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Answer:

A and D

Explanation:

It might seem like B and D but I took the test and it's A and D.

Answer:

Whether the particles of the solute and solvent are charged

Temperatures of the solvent and solute

Explanation:

A. Whether the particles of the solute and solvent are charged

B. Pressure acting and solute

C. Length of time spent stirring

D. Temperatures of the solvent and solute

Based on the analysis, the lesson that the Egyptians did not learn from the Hyksos invasion is option e) The reliance on isolationism.

To identify the lesson that the Egyptians did not learn from the Hyksos invasion, we need to understand the historical context of the event and the subsequent actions taken by the Egyptians. The Hyksos invasion occurred during the Second Intermediate Period of ancient Egypt (17th century BCE) when a Semitic-speaking people from the Levant conquered Lower Egypt.

Step 1: Identify the lessons learned from the Hyksos invasion:

a) The importance of military strength: The Egyptians learned the significance of a powerful military to protect their borders and maintain stability.

b) The adoption of new military technologies: The Hyksos introduced horse-drawn chariots, composite bows, and other military advancements. The Egyptians learned the value of incorporating such technologies into their own military.

Step 2: Analyze the options:

c) The importance of diplomacy and alliances: The Hyksos invasion highlighted the need for Egypt to forge alliances with other regional powers. This lesson was likely learned by the Egyptians.

d) The significance of cultural assimilation: The Hyksos introduced aspects of their own culture to Egypt, including the worship of foreign deities. The Egyptians likely learned the importance of cultural assimilation to prevent social unrest.

Step 3: Determine the answer:

Based on the analysis, the lesson that the Egyptians did not learn from the Hyksos invasion is option e) The reliance on isolationism. The Egyptians recognized the importance of engaging with the outside world, forming alliances, and adopting new military technologies. Isolationism would have hindered their ability to defend against future invasions and integrate beneficial influences from other cultures.

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The option that was not a ""lesson"" that the Egyptians learned from the hyksos invasion is X bronze metallurgy the best defense

According to legend, a mystery tribe of alien invaders known as the Hyksos took control of the Nile Delta around 1638 B.C.However, there are few documented accounts of the dynasty, and modern archaeologists have uncovered little physical remnants of the historic military operation.

An invasion is when an army enters a territory, typically as part of a hostile attack during a war or other conflict. The world's history is replete with accounts of invasions.

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missing options;

Security depended upon the maintenance of ma'at.

X bronze metallurgy the best defense

Answer:

32kg/j correct me if I am wrong

Answer:

1.38 kJ/g

Explanation:

it is answer

The student did not get any crystals to collect because copper (II) nitrate is a soluble salt, meaning it readily dissolves in water. Unlike copper (II) sulphate, which is insoluble and can crystallize out of solution, copper (II) nitrate remains in solution even after evaporation of the water.

When the student added copper (II) carbonate to dilute nitric acid, a reaction occurred to produce copper (II) nitrate and carbon dioxide gas. However, since copper (II) nitrate is soluble, it remained dissolved in the solution. The student then warmed the solution to drive off some water, but this step did not cause the copper (II) nitrate to crystallize because it remains soluble in the remaining water.

Leaving the solution to crystallize for several days did not result in the formation of copper (II) nitrate crystals because there was no solid salt to crystallize out. The water gradually evaporated, but the dissolved copper (II) nitrate simply became more concentrated in the remaining solution.

To obtain copper (II) nitrate crystals, the student would need to use a different method. One possible approach is to use a more concentrated nitric acid solution or to try different solvents that can selectively precipitate the copper (II) nitrate from the solution. It's important to note that working with chemicals and performing experiments should always be done with proper safety precautions and under the supervision of a qualified individual.

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The maintenance of the proper pH of the body fluids may be the result of the control of respiratory ventilation. Option A

We know that the pH has to do with the degree of acidity of alkalinity. The body is a complex system and there are several chemical processes that are taking place. In the case of all of these systems there is the need that a balance of the pH of the solutions must be maintained.

Now, we know that during the process of respiration, there is the intake of oxygen  and there is also the removal of carbon dioxide. This is very important as it does take place in the cells. In the cells, there is the breakdown of the complex sugars and there is the release of carbon dioxide of oxygen.

The carbon dioxide that is produced does contribute to the concentration of the bicarbonate that is present in the body of the organism.

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Starting with a 1.35 m HCl stock solution, five standard solutions are prepared by sequentially diluting 5.00 ml of each solution to 100.0 ml. The concentration of the final solution after 5 dilutions is \(\rm 4.22 \times 10^{-7} M\).

Dilution in chemistry is the process of lowering a solute's concentration in a solution by incorporating more solvent. Dilution is the process of lowering the solute concentration per unit volume while maintaining a constant solute concentration overall. As a result, the fluid becomes less concentrated or more diluted.

Volume of Stock Solution = 5 mL

                                          = (5 mL)(1 L/1000 mL)

                                           = 0.005 L

Moles of HCl = (1.35 mol/L)(0.005 L)

                     = \(\rm 6.75 \times 10^{-3}\) mol

Dilution 1:-

Volume of Solution = 100 mL

                                = (100 mL)(1 L/1000 mL)

                                = 0.100 L

Molarity After 1st Dilution = (\(\rm 6.75 \times 10^{-3}\) mol)/(0.100 L)

                                         = \(\rm 6.75 \times 10^{-2}\) mol/L

Volume of Solution Taken = 5 mL

                                          = (5 mL)(1 L/1000 mL)

                                          = 0.005 L

Moles of HCl = (\(\rm 6.75 \times 10^{-4 }\)mol/L)(0.005 L)

                    =\(\rm 3.375 \times 10^{-4}\) mol

Dilution 2:-

Volume of Solution = 100 mL

                                = (100 mL)(1 L/1000 mL)

                                = 0.100 L

Molarity After 2nd Dilution = (\(\rm 3.375 \times 10^{-4 }\)mol)/(0.100 L)

                                            =\(\rm 3.375 \times 10^{-3}\) mol/L

Volume of Solution Taken = 5 mL

                                            = (5 mL)(1 L/1000 mL)

                                          = 0.005 L

Moles of HCl = (\(\rm 3.375 \times 10^{-3}\) mol/L)(0.005 L)

                     = \(\rm 1.6875 \times 10-5\) mol

Dilution 3:-

Volume of Solution = 100 mL

                                = (100 mL)(1 L/1000 mL)

                               = 0.100 L

Molarity After 3rd Dilution = (\(\rm1.6875 \times 10^{-5 }\)mol)/(0.100 L)

                                           = \(\rm 1.6875 \times 10^{-4}\) mol/L

Volume of Solution Taken = 5 mL

                                           = (5 mL)(1 L/1000 mL)

                                           = 0.005 L

Moles of HCl = (\(\rm 1.6875 \times 10^{-4}\) mol/L)(0.005 L)

                      = \(\rm 8.4375 \times 10^{-7}\) mol

Dilution 4:-

Volume of Solution = 100 mL

                               = (100 mL)(1 L/1000 mL)

                               = 0.100 L

Molarity After 4th Dilution = (\(\rm 8.4375 \times 10^{-7 }\)mol)/(0.100 L)

                                          =\(\rm 8.4375 \times 10^{-6}\) mol/L

Volume of Solution Taken = 5 mL

                                            = (5 mL)(1 L/1000 mL)

                                            = 0.005 L

Moles of HCl = (\(\rm 8.4375 \times 10^{-6 }\)mol/L)(0.005 L)

                      = \(\rm 4.21875 \times 10^{-8}\) mol

Dilution 5:-

Volume of Solution = 100 mL

                                 = (100 mL)(1 L/1000 mL)

                                = 0.100 L

Molarity After 5th Dilution = (\(\rm 4.21875 \times 10^{-8}\) mol)/(0.100 L)

                                           =\(\rm 4.21875 \times 10^{-7}\) mol/L

                                          = \(\rm 4.22 \times 10^{-7}\) mol/L

                                          =\(\rm 4.22 \times 10^{-7}\) M

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Answer:

A CH 3−CH 2−CH 2−COOC 2H 5 B C 6H 5COOC 2H 5 C C 6H 11−CH 2−COOC 2H 5 D C 6H 5−CH 2COOC 2H 5 H

Answer:

I cannot give you all the answer but I can help you to solve those.

Explanation:

The first question:

How many grams are there in 7.5×\(10^{23}\) molecules of \(H_{2} SO_{4}\)?

So we need to find the molecular mass first, use your periodic table,

And then we can find out 2+32+16×4=98 g/mol

Then, we need to find how many moles, by using Avogadro's constant:

Avogadro's constant: 1 mole = 6.02×\(10^{23}\)

∴\(\frac{7.5*10^{23} }{6.02*10^{23}}\)=1.25 mol(2d.p.)

Lastly, find the grams using the formula \(M= \frac{m}{n}\)

m=Mn

m=1.25*98

m=122.5g

-------------------------------------------------------------------------------------------------------------

In conclusion, use those formula to help you:

\(M= \frac{m}{n}\) (which M = molecular mass(atomic mass) m=mass of the substance and n = moles)

Avogadro's constant: \(\frac {molecular mass} {6.02*10^{23}} = moles\)

Answer:

There is no hydrogen in the first half reaction

Answer:

4 the number of figures

Explanation:

answers above

Answer:

uuuhm???? sonar??? and???? idk??? gooogle it

Answer:

Explanation:

7) A block of wood

has a length of 10.2

cm, a width of 6 cm

and a height of 4.1

cm. The wood has

a total mass of 179

grams. What is the

volume of the

wood and what is

the density of the

wood?

volume = L XW XH=10.2 X 6 X4.1 =250.92cm^3

DENSITY = M/V = 179gm/250.92 cm^3

=0.713 gm/cm^3

The value of Kc for the given reaction is approximately 0.109 .

To calculate the value of Kc for the reaction X(g) + 2Y(g) ⇌ 2Z(g) with Kp = 2.13 × 10^(-2) at a temperature of 127°C, follow these steps:

Step 1: Write down the given information:
Kp = 2.13 × 10^(-2)
T = 127°C = 400.15 K (convert from Celsius to Kelvin by adding 273.15)

Step 2: Use the relationship between Kp and Kc, which is:
Kp = Kc(RT)^(Δn)
where R is the ideal gas constant (0.0821 L atm/mol K), T is the temperature in Kelvin, and Δn is the change in moles of gas in the balanced equation.

Step 3: Calculate Δn:
Δn = (moles of product gas) - (moles of reactant gas) = (2 - 1 - 2) = -1

Step 4: Rearrange the equation to solve for Kc:
Kc = Kp / (RT)^(Δn)

Step 5: Plug in the given values and calculate Kc:
Kc = (2.13 × 10^(-2)) / ((0.0821)(400.15))^(-1)
Kc ≈ 0.109

So, the value of Kc for the given reaction is approximately 0.109.

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a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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