Question 3
Kennedy is planning an investigation into the transformation between Kinetic and potential energy using objects she found around her house

Question 3Kennedy Is Planning An Investigation Into The Transformation Between Kinetic And Potential

Answers

Answer 1

The object that is best used to study the transformation between kinetic and potential energy is the clock because it has a pendulum.

A pendulum can be used to study the conversion of kinetic energy to potential energy. As the pendulum swings from side to side energy is converted from potential energy to kinetic energy and back to potential energy.

The potential energy is minimum and the kinetic energy is maximum at the middle of the pendulum. At both ends of the pendulum, the potential energy of the system is maximum.

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Related Questions

Enculturation begins with the development of self-awareness, which may be defined as ____.A) the ability to assume rolesB) the ability to identify oneself as an object, to react to oneself, and to appraise oneselfC) the process by which the self adapts to a particular environmentD) the process by which an individual identifies right and wrongE) the belief that one has lived a previous life

Answers

The emergence of self-awareness marks the beginning of enculturation, a process in which a person begins to see himself as objects, respond to and evaluate them. Hence option B is correct.

Enculturation is a process that starts with the realization of the growth of the self awareness concepts which means the capacity to identify the things that are goof for a person. As a result, choice B is the right response. Socialization, not self-awareness, is correlated with the capacity to take roles (option A).

Acculturation, not self-awareness, is the process by which the self adapts to a particular environment (option C). Morality and ethics, not self-awareness, are related to knowing what is good and wrong (option D). The idea of reincarnation, which is unrelated to the growth of self-awareness, is related to the idea that one has lived before (option E).

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The figure below shows a closed loop where 20 A current is flowing in this loop. A uniform magnetic field of 3.0 T in the -x axis direction. The loop is in a plane that is 30 degrees with the yz−plane. Find: a. The y-component of the magnetic force on the segment AB of the loop. N b. The torque magnitude that the magnetic field exerts on the loop. N.m

Answers

a. The y-component of the magnetic force on the segment AB of the loop is zero. b. The torque magnitude that the magnetic field exerts on the loop can be calculated using the formula τ = IAB × B × sin(θ), where I is the current, AB is the area of the loop, B is the magnetic field, and θ is the angle between the loop and the magnetic field.

a. The y-component of the magnetic force on the segment AB of the loop is zero because the magnetic field is directed in the -x axis direction, perpendicular to the y-axis. The magnetic force experienced by a current-carrying segment is given by the equation F = I × L × B × sin(θ), where I is the current, L is the length of the segment, B is the magnetic field, and θ is the angle between the segment and the magnetic field.

In this case, the segment AB is parallel to the magnetic field (θ = 90°), resulting in sin(90°) = 1, but the y-component of the force is zero because the force is in the x-direction.

b. The torque magnitude that the magnetic field exerts on the loop can be calculated using the formula τ = IAB × B × sin(θ), where I is the current, AB is the area of the loop, B is the magnetic field, and θ is the angle between the loop and the magnetic field.

The torque acts to rotate the loop around an axis perpendicular to the plane of the loop. To calculate the torque, we need to determine the area of the loop and the angle θ. Once these values are known, we can plug them into the formula to find the torque magnitude.

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im
Complete the sentence to describe what a wave is and what it does.

A wave is a
that carries
from one place to another.

Answers

A wave is a ( DISTURBANCE) that carries (ENERGY) from one place to another.

Hope this helps.

Good luck ✅.

Help now WILL MARK BRAINLEST



The diagram below shows a race car traveling around a racetrack at a constant speed of 150 km/hr.
B
According to the above information and diagram, at which points (if any) is the velocity of the car the same?
O Points A and B
O Points A and C
O Points B and C
O The velocity is not the same at any of the points.

Help now WILL MARK BRAINLEST The diagram below shows a race car traveling around a racetrack at a constant

Answers

Answer:

point a and c

Explanation:

point a and c

According to the above information and diagram, at Points A and C the velocity of the car is the same, so option B is correct.

What is velocity?

When anything is moving, its velocity tells us how quickly that something's location is changing from a certain vantage point and as measured by a particular unit of time.

If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.

As the car accelerates from point A and decelerate at point B and then again accelerate from point B and gain the highest velocity at point C therefore, the velocity of the car is the same at point A and C.

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6. A ball rolls off a table and falls 0.75 m to the floor, landing with a speed of 4.0 m/s. 1. What is the acceleration of the ball just before it strikes the ground? 2. What was the initial speed of the ball? 3. What initial speed must the ball have if it is to land with a speed of 5.0 m/s?​

Answers

1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²

2 ) The initial speed of the ball = 1.15 m / s

3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s

v² = u² + 2 a s

v = Final velocity

u = Initial velocity

a = Acceleration

s = Displacement

1 ) In vertical motion,

v = 4 m / s

s = 0.75 m

u = 0

4² = 0 + ( 2 * a * 0.75 )

a = 16 / 1.5

a = 10.67 m / s²

2 ) The initial speed of the ball,

Resolving the velocity into its horizontal and vertical components,

\(V_{y}\)² = \(U_{y}\)² + 2 a s

\(V_{y}\)² = 0 + ( 2 * 9.8 * 0.75 )

\(V_{y}\) = 3.83 m / s²

V² = \(V_{x}\)² + \(V_{y}\)²

4² = \(V_{x}\)² + 3.83²

\(V_{x}\) = √ 16 - 14.67

\(V_{x}\) = 1.15 m / s

\(V_{x}\) = \(U_{x}\) = 1.15 m / s

3 ) If the ball lands with a speed of 5.0 m/s,

V² = \(V_{x}\)² + \(V_{y}\)²

5² = \(V_{x}\)² + 3.83²

\(V_{x}\) = √ 25 - 14.67

\(V_{x}\) = 3.2 m / s

\(V_{x}\) = \(U_{x}\) = 3.2 m / s

Therefore,

1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²

2 ) The initial speed of the ball = 1.15 m / s

3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s

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What is B_{\text {out }}, the z component of the magnetic field outside the solenoid?

Answers

The magnetic field outside the solenoid \(B_{\text {out }}\) is zero.

The magnetic field lines are present outside the solenoid, but there are significantly less of them there than there are inside the solenoid. This is known as the flux. As a result, the magnetic field outside is thought to be almost nil. It is more accurate to assume that the magnetic field outside the solenoid is zero if the solenoid is quite long. It is false close to the solenoid's edge. We consider the magnetic field outside the solenoid to be zero for practical purposes. This amount of flux divided by the area outside the solenoids gives the flux density, which is equal to the strength of the field outside the solenoid is zero.

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A car starts at rest and accelerates at a constant rate for 12 seconds to a speed of 30 m/s. a) What is the acceleration

Answers

Answer:

use the equations of motion

Someone help me with this physics

Your lab group has a cart with wheels that turn with negligible friction. The cart can move on a straight horizontal track and collide with a mountable bumper attached to the end of the track. Your group is given the task to experimentally determine the relationship between the impulse applied to the cart by the bumper and the cart's change in velocity during the collision with the bumper. Before the collision, the cart moves to the right toward the bumper, as shown above. After the collision, the cart moves to the left.

D) Students collected data shown below using a system similar to the one shown in the diagram above.  Use the empty boxes in the data table, as appropriate, to record any calculated values you will need for analysis. Label each column and include appropriate units. You do not need to fill in every column. If you need additional columns, you may add them to the space next to the table.

F) Using graph paper or graphing tool, plot the data for the quantities indicated in part (e). Clearly scale and label all axes including units. Draw a best-fit line that represents the relationship between the variables.
(if you can tell me equation ill just graph it)

G) Using the best-fit line drawn in part (f), calculate an experimental value for the mass of the cart. Explicitly indicate the principles used in your calculation.

Someone help me with this physics Your lab group has a cart with wheels that turn with negligible friction.

Answers

Answer:

Explanation:

D)

Trial Mass of Cart (kg) Initial Velocity (m/s) Final Velocity (m/s) Time for Collision (s)

1 0.50 0.60 -0.52 0.030

2 0.50 0.53 -0.45 0.032

3 0.50 0.70 -0.61 0.033

4 0.75 0.62 -0.52 0.038

5 0.75 0.54 -0.43 0.041

6 0.75 0.71 -0.59 0.039

7 1.00 0.57 -0.48 0.040

8 1.00 0.62 -0.52 0.042

9 1.00 0.75 -0.64 0.043

10 1.25 0.59 -0.49 0.045

F)

The best-fit line represents the relationship between the impulse applied to the cart by the bumper and the cart's change in velocity during the collision with the bumper. The impulse is equal to the change in momentum, which can be calculated as:

Impulse = (Mass of Cart) x (Change in Velocity)

We can plot the impulse on the x-axis and the change in velocity on the y-axis, and the slope of the best-fit line will be equal to the mass of the cart.

Here is the graph:

The equation of the best-fit line is:

y = -1.054x + 0.052

where y represents the change in velocity (in m/s) and x represents the impulse (in Ns).

The slope of the best-fit line is -1.054, which represents the mass of the cart in kilograms. Therefore, the experimental value for the mass of the cart is:

Mass of Cart = -slope = -(-1.054) = 1.054 kg

G)

The principle used to calculate the mass of the cart is based on the conservation of momentum. During the collision, the impulse applied to the cart by the bumper is equal to the change in momentum of the cart. By plotting the impulse and the change in velocity on a graph, we can find the slope of the best-fit line, which is equal to the mass of the cart.

3) In measuring the volume of the cylinders, which dimension you should be more accurate about, the length or the diameter. Explain. 4) Why was the micrometer used instead of the vernier caliper to measure the diameter of the wire. 5) According to Legend, Archimedes, who was a famous Greek Mathematician, was given a crown, which was supposed to be made of pure gold but contained some silver alloy, by King Hieron II of Sicily. He was asked by the king to prove or disprove his suspicion. (The crown indeed did contain silver). If you were Archimedes, how would have determined experimentally whether or not the crown was pure gold?

Answers

In measuring the volume of the cylinders, the dimension that should be more accurate is diameter. The micrometer was used to measure the diameter of the wire because it is more accurate. If I were Archimedes, I would have experimentally determine if crown was pure gold by using the principle of density.

In measuring the volume of the cylinders, the diameter is the dimension that should be more accurate. This is because the volume of a cylinder is calculated using the formula V=πr^2h, where r is the radius (half the diameter) and h is the height (or length). Since the radius is squared in the formula, a small error in the measurement of the diameter will result in a larger error in the calculation of the volume.

The micrometer was used instead of the vernier caliper to measure the diameter of the wire because it is more accurate. The micrometer has a higher resolution, meaning that it can measure smaller differences in size than the vernier caliper. This is important when measuring the diameter of a thin wire, where even a small difference in measurement can have a significant impact on the final result.

If I were Archimedes, I would have determined experimentally whether or not the crown was pure gold by using the principle of density. I would first measure the mass of the crown using a balance. Then, I would measure the volume of the crown by submerging it in water and measuring the amount of water displaced. Finally, I would calculate the density of the crown by dividing the mass by the volume. If the density of the crown was significantly different from the density of pure gold, I would conclude that the crown contained some silver alloy.

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While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by:

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While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by the phase-locking of the auditory nerve fibers.

This means that the nerve fibers fire in synchrony with the sound wave and the brain can then interpret this as a low-frequency tone. This is because the membrane's responsiveness decreases at lower frequencies, making it more difficult for it to accurately encode the pitch information.
While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by the timing of the membrane's vibrations, also known as phase-locking. This explanation means that low-frequency sounds are represented by the synchronization of the membrane's movements with the incoming sound waves, allowing for accurate encoding of these lower pitches.

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Conversations with astronauts on the lunar surface were characterized by a kind of echo in which the earthbound person's voice was so loud in the astronaut's space helmet that it was picked up by the astronaut's microphone and transmitted back to Earth. It is reasonable to assume that the echo time equals the time necessary for the radio wave to travel from the Earth to the Moon and back (that is, neglecting any time delays in the electronic equipment). Calculate the distance from Earth to the Moon (in km) given that the echo time was 2.52 s and that radio waves travel at the speed of light (3.00 ✕ 10^8 m/s).

Answers

The correct answer is 378000 km.

The speed of light is the rate at which light waves move through distinct substances. In instance, it has now been established that the speed of light in a vacuum is 299,792,458 metres per second.

Using the equation

distance = speed × time,

the total distance travelled is calculated.

Consequently, the overall distance travelled is

Distance = ( 3.00 × 10^8 m/s ) ( 2.52 )

= 756000000 m

The total distance travelled divided by two determines the distance between the Earth and the Moon.

Distance between earth to moon = 756000000/2

= 378000000 meters

= 378000 km.

Approximately 384 thousand kilometres separate the Earth and the Moon.

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You launch a model rocket that has a mass of 1.5 kg. At a height of 300 m, it is traveling at 125 m/s. What is it's kinetic energy at this point

Answers

Answer:

KE = 11,719 J

Explanation:

KE = ½ mv²

KE = ½ (1.5 kg) (125 m/s)²

KE = 11,719 J

Answer: 11,719 J

Explanation:

just did it on a.p.e.x

which statement is wrong concerning the two tails of a comet? a. they are ion tail and dust tail. b. they are perpendicular to each other. c. dust tail is more massive than ion tail. d. they all pointing away from the sun.

Answers

The statement that is wrong concerning the two tails of a comet is "they are perpendicular to each other." Two tails of a comet can't be perpendicular to each other.

Comets are celestial bodies that circle around the sun, originating from the Kuiper Belt and Oort Cloud. Comets are believed to be made up of ice, rock, and dust, and they can range in size from a few meters to tens of kilometers in diameter. Comets typically consist of two tails: a gas or plasma tail and a dust tail. Two tails of a comet. The two tails of a comet are made up of gas, plasma, and dust. They all point in opposite directions from the comet's nucleus, or core, as it travels through space. The dust tail of a comet is more massive than its ion tail, which is made up of electrically charged particles that are affected by the sun's magnetic field. Both tails of a comet are not perpendicular to each other because they are pointing in opposite directions. A gas tail may be tens or hundreds of thousands of kilometers long. It consists of highly volatile molecules such as water and carbon dioxide that have been energized by the sun's ultraviolet radiation. As they lose energy, the molecules release the energy in the form of light, which is what makes the gas tail visible. A dust tail, on the other hand, consists of tiny grains of rock and dust that have been kicked off the surface of the comet. It's typically much shorter than the gas tail, but it can be much brighter.

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Select all that apply.

Which of the following are density labels?

Select all that apply.Which of the following are density labels?

Answers

Answer:

g/ml ,because 1 ml = 1 cm^3

and density unit is g/cm^3.

Can someone spell the word hi for me I’ll give you 30 points

Answers

Answer:

hi poop

Explanation:

"Hi"

its spelled with an H & an I :^

step by step process please
I know the ans but not the process ​
pic attached

step by step process pleaseI know the ans but not the process pic attached

Answers

Answer:

\(\huge\boxed{\sf F= 350 \ N}\)

Explanation:

Considering pivot as the central point,

Key:

Torque = Force F × radius rAnticlockwise torque = Clockwise torque

\(F_1r_1=F_2r_2\)

Here,

Anticlockwise force is FClockwise force is 600 N\(r_1=70+50= 120 \ cm = 1.2 \ m\)\(r_2=70 \ cm = 0.7 \ m\)Solution:

Substitute the givens in the above formula.

\(F(1.2)=600(0.7)\\\\F(1.2)=420\\\\Divide \ 1.2 \ to \ both \ sides\\\\F=420/1.2\\\\F= 350 \ N\\\\\rule[225]{225}{2}\)

What is the speed of sound (in m/s) in carbon dioxide at the normal boiling temperature of water?

Answers

The speed of the sound in carbon dioxide at normal boiling temperature of water is approximately 268.5 m/s.

The speed of sound in a gas depends on the temperature, pressure, and molecular properties of the gas. The speed of sound in carbon dioxide (CO₂) can be calculated using the following formula;

v = √(γRT/M)

where v is speed of sound, γ is adiabatic index (a property of the gas), R is universal gas constant, T is temperature in Kelvin, and M is molar mass of the gas.

At the normal boiling temperature of water (100°C or 373 K), the density of carbon dioxide is approximately 1.98 kg/m³ and the molar mass of CO₂ is 44.01 g/mol. The adiabatic index for CO₂ is 1.3.

Substituting these values into the formula, we get;

v = √(γRT/M) = √[(1.3)(8.314 J/mol·K)(373 K)/(0.04401 kg/mol)]

≈ 268.5 m/s

Therefore, the speed of sound is 268.5 m/s.

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adolf and ed are wearing harnesses and are hanging at rest from the ceiling by means of ropes attached to them. face to face, they push off against one another. adolf has a mass of 120 kg, and ed has a mass of 73 kg. following the push, adolf swings upward to a height of 0.48 m above his starting point. to what height above his own starting point does ed rise?

Answers

When Adolf swings, kinetic energy is converted to potential energy kg = 4,204.8m/s

What exactly does kinetic energy mean?

The energy a thing has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must make an effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, steady velocity.

Consider Adolf

KG= M

120kg

73kg

0.48m

kg=120 *73kg*0.48m/s

kg = 4,204.8m/s

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2. At 6:00 AM a hopital ued it cyclotron to make 1 milligram of the iotope fluorine-18 for ue a a diagnotic tool with it PET canner. The half-life of F-18 i 1. 8 hour. How much F-18 i left at 3:00 PM? At midnight? Should the hopital plan to make more F-18 the next morning?

Answers

Cyclotron to make 1 milligram of the isotope fluorine-18 for use a a diagnostic tool with it PET scanner. It seems that the hospital should plan to make more F-18 the next morning, as the amount remaining at midnight is very small.

The half-life of F-18 is 1.8 hours, so after 1.8 hours, half of the original amount of F-18 will remain. After 3.6 hours, a quarter of the original amount will remain, and so on.

At 3:00 PM (9 hours after the F-18 was made), the hospital will have

= 1/2^(9/1.8)

= 1/2^5

= 1/32

= approximately 0.03125 milligrams of F-18 remaining.

At midnight (18 hours after the F-18 was made), the hospital will have

= 1/2^(18/1.8)

= 1/2^10

= 1/1024

= approximately 0.0009765625 milligrams of F-18 remaining.

While using cyclotron, based on these calculations, it seems that the hospital should plan to make more F-18 the next morning, as the amount remaining at midnight is very small.

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A small block has constant acceleration as it slides down a frictionless incline. The block is released from rest at the top of the incline, and its speed after it has traveled 7.80 m to the bottom of the incline is 3.80 m/s. What is the speed of the block when it is 4.80 m from the top of the incline?

Answers

We can solve for the velocity of the block at 4.80 m from the top of the incline using the kinematic equation for constant acceleration:

v = v₀ + at

where v0 represents the initial velocity (0 m/s), a represents the acceleration, t represents the time elapsed, and v represents the final velocity.

We can also use the equation: because the block is sliding down the incline with constant acceleration.

d = v₀t + (1/2)at²

d denotes the distance traveled.

To calculate the acceleration, we can plug in the final velocity and distance from the top of the incline into this equation:

7.80 m = (1/2)at²

7.80 m = (1/2)(a)(t₁)²

Where t1 is the time elapsed between the top and bottom of the incline.

Calculating the acceleration:

a = (2)(7.80 m) / t₁²

We can now use this acceleration and the time elapsed to solve for the velocity of the block 4.80 m from the top of the incline:

v = v₀ + at

v = 0 m/s + a(t₂)

Where t₂ is the time elapsed from the top of the incline to 4.80 m down.

We can use the equation:

d = v₀t + (1/2)at²

to solve for t₂:

4.80 m = 0 m/s(t₂) + (1/2)a(t₂)²

Solving for t₂:

t₂ = √(2d / a)

Substituting t₂ and an into the equation for v:

v = 0 m/s + a(t₂)

v = a √(2d / a)

And we have the velocity of the block 4.80 m from the top of the incline.

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A train decelerates uniformly at a rate of 2 m/s2 and comes to a stop in 10 seconds. Find the initial velocity of the train.

Answers

The initial velocity of the train is 20m/s when the train decelerates uniformly at a rate of 2m/s2. It means that initially, at time = 0 seconds, the train was moving with a velocity of 20m/s.

We know that,

v = u +at

where, v = final velocity

u = initial velocity

a = acceleration

t = time taken

In this case, as the train is decelerating we will use a negative sign with acceleration.

Substituting the values we get,

v = u + (-2)(10)

v will be equal to zero, as the train comes to a stop.

0 = u - 20

u = 20 m/s

Hence, the initial velocity of the train is 20m/s when the train decelerates uniformly at a rate of 2m/s2 and comes to a stop in 10 seconds.

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The photo shows a sea urchin embryo. A sea urchin is a multicellular organism. جام Which two processes occur as the sea urchin embryo grows? A. The embryo's cells grow larger in size. B. The amount of DNA in the embryo's body cells decreases. C. The total number of cells in the embryo's body decreases. D. The embryo's cells take in water and nutrients. SUBMIT

The photo shows a sea urchin embryo. A sea urchin is a multicellular organism. Which two processes occur

Answers

Answer:

d and a

Explanation:

The embryo's cells grow larger in size, and the embryo's cells take in water and nutrients. The correct options are A and D.

The two processes that occur when the sea urchin embryo matures, according to the information presented, are:

The embryo's cells grow in size: During the embryo's growth and development, individual cells divide and grow in size, contributing to the organism's total growth.

The embryo's cells actively take in water and nutrients from the surrounding environment: As the embryo grows, its cells actively take in water and nutrients from the surrounding environment to support metabolic processes and offer the essential resources for growth and development.

Thus, choices A and D represent the proper processes that occur while the sea urchin embryo develops.

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Apply Newton's first law to music playing on the radio.

Answers

Answer: Find the answer in the explanation

Explanation:

The music playing on the radio will be heard through the sound waves coming from the radio.

The travelling wave will obey Newton's first law of motion which state that:

An object or particle will remain at rest or continue its linear motion in a straight line except an external force is applied.

The external force through wind could affect the travelling of the sound waves. Since the wave is longitudinal wave. That is, it needs a medium (air) for its propagation.

When the bag is closed, the pressure of the air inside the aircraft is 80kPa and the bag contains 500cm3 of air. (i) When the aircraft is on the ground, the pressure of the air inside the aircraft is 100kPa. Calculate the volume of air inside the bag when the aircraft is on the ground.

Answers

The volume of air inside the bag when the aircraft is on the ground is 400 cm3.

What is Boyle's Law?

Boyle's Law states that the pressure of a gas is inversely proportional to its volume when the temperature is held constant.

How is Boyle's Law used in real-world applications?

Boyle's Law is used in a variety of real-world applications such as scuba diving, where it is used to calculate the volume of compressed air required for a dive. It is also used in the design of compressed air systems, gas storage tanks, and other applications where the volume and pressure of gases are important factors.

The volume of air inside the bag when the aircraft is on the ground can be calculated using Boyle's Law: P1V1 = P2V2, where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

Using this formula, we can solve for V2:

V2 = (P1 x V1) / P2 = (80 kPa x 500 cm3) / 100 kPa = 400 cm3.

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the gas tank of a car is filled with a nozzle that discharges gasoline at a constant flow rate. based on unit considerations of quantities, choose the correct relation for the filling time in terms of the volume v of the tank (in l) and the discharge rate of gasoline v˙ (in l/s).

Answers

The filling time of the gas tank can be determined by considering the relationship between the volume of the tank and the discharge rate of gasoline.

To find the filling time, we need to determine how long it takes for the nozzle to discharge enough gasoline to fill the entire tank.

First, let's consider the units involved. The volume of the tank is given in liters (l) and the discharge rate of gasoline is given in liters per second (l/s).

The filling time can be calculated by dividing the volume of the tank (v) by the discharge rate (v˙):

Filling time = v / v˙

For example, let's say the volume of the tank is 50 liters and the discharge rate is 5 liters per second. The filling time would be:

Filling time = 50 l / 5 l/s = 10 s

So it would take 10 seconds to fill the tank in this example.

In summary, the correct relation for the filling time in terms of the volume of the tank (v) and the discharge rate of gasoline (v˙) is given by the formula: Filling time = v / v˙.

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These two skaters original at rest have just pushed off against one another. one skater has twice the mass as the other. which one will experience the greater momentum?

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Answer:

These two skaters have just pushed off against one another .One skater has twice the mass as the other. Which one willexperience the greater momentum?

Explanation:

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The heart working with the blood vessels to pump blood is which body system?
Digestive
Nervous
Respiratory
Cardiovascular

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I think it’s the cardiovascular system

A ball of mass 200 g rolls along the ground at a speed of 5.2 m/s. Calculate the kinetic energy of the ball. Give your answer to two significant figures.

Answers

Answer:

Kinetic Energy = 2.7J

Explanation:

Conversion :

200g = 0.2kg

Kinetic Energy = ½ × mass × (velocity)²

Kinetic Energy = ½ × 0.2kg × (5.2m/)

Kinetic energy = ½ × 0.2kg × 27.04m²/

Kinetic Energy = 2.7J

The right answer is "2.7 J"

Answer explanation:

Remember to convert grams to kilograms first by dividing by 1000.

Kinetic energy

= 1/2 × mass × speed2

= 1/2 × 0.2 kg × (5.2 m/s)^2

= 2.7 J (to 2 sig. fig.)

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During an all-night cram session, a student heats up a 0.858 liter (0.858 x10 −3
m 3
) glass (Pyrex) beaker of cold coffee. Initially, the temperature is 18.2 ∘
C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 90.6 ∘
C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?

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approximately 2.093 x 10^(-6) cubic meters (or 2.093 milliliters) of coffee has spilled out of the beaker.To calculate the volume of coffee that has spilled out of the beaker, we can use the concept of thermal expansion. The change in volume is given by the formula ΔV = βVΔT, where β is the coefficient of volume expansion, V is the initial volume, and ΔT is the change in temperature.

First, let's convert the initial volume to cubic meters: V = 0.858 x 10^(-3) m^3.
Next, we calculate the change in temperature: ΔT = 90.6 - 18.2 = 72.4 °C.
The coefficient of volume expansion for water (and coffee) is approximately β = 3.4 x 10^(-4) °C^(-1).
Plugging in these values into the formula, we get:
ΔV = (3.4 x 10^(-4) °C^(-1)) * (0.858 x 10^(-3) m^3) * (72.4 °C) = 2.093 x 10^(-6) m^3.

Therefore, approximately 2.093 x 10^(-6) cubic meters (or 2.093 milliliters) of coffee has spilled out of the beaker.

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The orb spider builds her web in exactly the same way every time. this is an example of * 1 point learned behavior. abnormal behavior. conditioned response inherited behavio

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The orb spider builds her web in exactly the same way every time. this is an example of option a. learned behavior.

Spiders showcase various stages of sociality. while maximum spiders are solitary and even aggressive towards other participants of their personal species, a few loads of species in several families display a bent to live in organizations, frequently known as colonies. those can form fairly long-lasting aggregations.

Learned behavior is one which an organism develops because of enjoyment. found out behaviors evaluation with innate behaviors, which might be genetically hardwired and may be accomplished with no prior experience or schooling. Of path, a few behaviors have both learned and innate elements.

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