R is the midpoint of FG.

FR = 26 find RG

Answer: yes, it depends on the substance though

Explanation:

Answer:

As water freezes or evaporates, what happens to the salinity of the remaining ocean water? There is no change to salinity.

Explanation:

The pOH of this solution is 0.3 and the pH of the solution is 13.3 .

What is pH ?

The pH of a food is a direct function of the free hydrogen ions present in that food. Acids in food release free hydrogen ions. Hydrogen ions give acidic foods their characteristic sour taste. Therefore, pH can be defined as a measure of free acid. More specifically, pH is defined as the negative logarithm of hydrogen ion concentration. The pH range is 0 to 14. The pH of pure water is exactly 7, so pH 7 is neutral. Values ​​less than 7 are acidic. Values ​​above 7 are basic or basic.

Foods are generally classified as “acidic foods” (low pH, pH 4.6 or less) or “weakly acidic foods” (high pH, ​​pH 4.6 or higher). Safe food storage is determined by the pH of the food. Acidic foods such as fruit and pickles can be safely canned in a tin can with a hot water bath. A combination of acid and hot water (212°F) destroys perishable organisms such as mold and yeast. Proper cooking water canning processes are important to prevent the growth of acid-tolerant molds and yeasts that can lead to elevated pH levels. The pH of borderline foods such as figs and tomatoes can easily exceed 4.6, so lemon juice or citric acid should be added before canning with boiling water. Low-acid foods such as vegetables and meat should be processed in a pressure preserver for safety.

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The term used for the space between two metal pieces at the bottom of the joint to be welded is "root opening."

The root opening in welding plays a crucial role in achieving a successful and strong weld joint. It refers to the gap or space intentionally created between the two metal pieces that are to be joined together. This gap is typically located at the root of the joint, which is the junction between the two base metals.

The root opening is the gap or space intentionally left between the metal pieces to allow for proper fusion and penetration of the weld bead. It is an important parameter in welding as it affects the strength and quality of the weld joint. The size of the root opening is typically specified in welding procedures to ensure appropriate weld penetration and sound weld formation.

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no  ls eb vb vj lfn  nbf,   l mgñ rlr  o

Answer:

4365.54 moles

Explanation:

Take the scientific notation and multiply it by the molar mass of 59.76.

The Fahrenheit temperatures corresponding to Celsius 31°C, 21°C, -9°C, and -15°C are approximately 88°F, 70°F, 16° F, 5°F.

To find the equation relating Fahrenheit temperature (F) to Celsius temperature (C), we can use the given freezing and boiling points of water on both scales.

We know that at the freezing point of water:

Fahrenheit temperature = 32°F

Celsius temperature = 0°C

And at the boiling point of water:

Fahrenheit temperature = 212°F

Celsius temperature = 100°C

We can use these two points to find the equation of the line relating F and C.

First, we find the slope of the line:

Slope = (Change in Fahrenheit temperature) / (Change in Celsius temperature)

= (212°F - 32°F) / (100°C - 0°C)

= 180°F / 100°C

Next, we find the y-intercept of the line:

Using the freezing point of water (0°C, 32°F):

32°F = Slope * 0°C + y-intercept

32°F = 0.18 * 0°C + y-intercept

y-intercept = 32°F

Therefore, the equation relating Fahrenheit temperature (F) to Celsius temperature (C) is:

F = 1.8C + 32

Now, we can use this equation to find the Fahrenheit temperatures corresponding to the given Celsius temperatures:

For 31°C:

F = 1.8 * 31 + 32 = 87.8 ≈ 88°F

For 21°C:

F = 1.8 * 21 + 32 = 69.8 ≈ 70°F

For -9°C:

F = 1.8 * -9 + 32 = 15.8 ≈ 16°F

For -15°C:

F = 1.8 * -15 + 32 = 5 ≈ 5°F

Therefore, the Fahrenheit temperatures corresponding to 31°C, 21°C, -9°C, and -15°C are approximately 88°F, 70°F, 16° F, 5°F.

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You would need roughly 202 ml of water to dissolve 72 grams of salt at 25 degrees Celsius.

The solubility of the compound, salt in water at 25 degrees Celsius is stated to be 357 grams per liter (g/L).

Then we can say that 357 grams of salt can be dissolved in 1 liter (1000 milliliters) of water.

To find out how much water you need to dissolve 72 grams of salt, solve the ratio as

357 g : 1000 mL = 72 g : x mL

Solving for x gives:

x = (72 g × 1000 mL) / 357 g

x = 201.681 mL

If we approximate this value it becomes 202ml

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Answer:

220g of CO2

Explanation:

Step 1:

The balanced equation for the reaction.

2C5H11OH + 15O2 —> 10CO2 + 12H2O

Step 2:

Determination of the number of mole of CO2 produced by burning 1 mole of C5H11OH.

From the balanced equation above,

2 moles of C5H11OH produced 10 moles CO2.

Therefore, 1 mole of C5H11OH will produce = (1 x 10)/2 = 5 moles of CO2.

Therefore, 5 moles of CO2 is produced from the reaction.

Step 3:

Conversion of 5 moles of CO2 to grams.

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Number of mole of CO2 = 5 moles

Mass of CO2 =...?

Mass = mole x molar mass

Mass of CO2 = 5 x 44

Mass of CO2 = 220g.

Therefore, 220g of CO2 were obtained from the reaction.

The term mole concept is used here to determine the moles of copper. It is the convenient method for expressing the amount of the substance. The number of moles of copper in 564 grams is  8.87 moles.

One mole of a substance is defined as that quantity of it which contains as many entities as there are atoms exactly in 12 g of carbon - 12. The formula used to calculate the number of moles is:

Number of moles = Given mass / Molar mass

Molar mass of copper = 63.55 g / mol

Number of moles = 564 / 63.55 = 8.87 moles

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The pair of aqueous solutions that will form a precipitate when mixed is option d: HCl and Pb(NO3)2.

When HCl (hydrochloric acid) is mixed with Pb(NO3)2 (lead(II) nitrate), a double displacement reaction occurs. The chloride ions (Cl-) from HCl and the nitrate ions (NO3-) from Pb(NO3)2 will switch places, forming HNO3 (nitric acid) and PbCl2 (lead(II) chloride) as the products.

Lead(II) chloride (PbCl2) is insoluble in water and forms a white precipitate. Therefore, when HCl and Pb(NO3)2 are mixed, a precipitate of PbCl2 will be formed.

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The mass percent of a molecule shows the amount each element contributes to the total molecular mass. So, acetamide is 40.7% Carbon, 23.7% Nitrogen, 27.1% Oxygen, and 8.5% Hydrogen.

the balanced equation of the reaction :NaBr + C4H9OH → C4H9Br + Na OH Sodium Bromide (NaBr) is the limiting reagent in the experiment, not 1-butanol.

The limiting reagent in the experiment between sodium bromide and 1-butanol is sodium bromide.What is a limiting reagent ?A limiting reagent is a reactant in a chemical reaction that restricts the yield of the product. It means the reaction can't go on forever because the reagents are consumed up. In general, the limiting reagent determines the amount of products that can be produced during a reaction .In the given chemical reaction between sodium bromide and 1-butanol, it is essential to know which reactant is the limiting reagent.  the balanced equation of the reaction :NaBr + C4H9OH → C4H9Br + Na OH Sodium Bromide (NaBr) is the limiting reagent in the experiment, not 1-butanol.To identify the limiting reagent, you need to know the balanced chemical equation, the amounts or concentrations of the reactants, and their stoichiometric ratios. With that information, we can compare the actual amounts of each reactant to their stoichiometric ratios to determine which one will be completely consumed and thereby limit the reaction.

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If the extracellular concentration of potassium was suddenly decreased, repolarization would be slowed down.

Potassium ions play a key role in repolarization. When an action potential is generated, sodium ions rush into the cell, causing the inside of the cell to become more positive. This positive charge triggers the opening of potassium channels, which allows potassium ions to flow out of the cell. This outward flow of potassium ions helps to restore the negative charge inside the cell and repolarize the membrane.

If the extracellular concentration of potassium is decreased, there will be fewer potassium ions available to flow out of the cell. This will slow down the repolarization process and make it more difficult for the cell to return to its resting state.

This can lead to a number of problems, including:

Here are some additional details about the role of potassium in repolarization:

Thus, if the extracellular concentration of potassium was suddenly decreased, repolarization would be slowed down.

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the concentration (moles per liter) of calcium ions present in local water is determined by the molarity of EDTA, volume of EDTA titrated, volume of water in the sample, molarity of EDTA and the volume of water in the sample

A substance's molarity (M) is the volume of solution in which it is present. The amount of a solute in moles per litre of a solution is known as molarity. A solution's molar concentration is another name for molarity. In terms of the amount of material per unit volume of solution, molar concentration is a measurement of the concentration of a chemical species, specifically a solute in a solution. The most frequent measure of molarity in chemistry is the number of moles per litre, denoted by the unit symbol mol/L or mol/dm3 in SI units.

the concentration (moles per liter) of calcium ions present in local water is determined by the _____.

1.molarity of EDTA

2.volume of EDTA titrated

3.volume of water in the sample

4.molarity of EDTA and the volume of water in the sample

5.All of the above

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The question gives us the reaction to produce sodium sulfide (Na2S) from sodium sulfate (Na2SO4) and carbon (C) and provides the amount of reactants used (15.0 g of Na2SO4 and 7.50 g of C), asking the limiting reactant, the excess reactant and the amount of Na2S produced.

I) The first step for this type of question is checking if the given equation is balanced. For this case, we don't need to adjust the coefficients as the equation is already balanced.

II) Next, we need to calculate the molar mass of the compounds we'll be using. To calculate the molar mass, I'll be using the following atomic masses and considering the number of each atom in the molecules:

Na: 22.99 u

S: 32.07 u

O: 15.99 u

C: 12.01 u

Now, we can calculate the molar mass of Na2SO4, C and Na2S:

Na2SO4: molar mass = (2 * 22.99) + (1 * 32.07) + (4 * 15.99) = 142.01 g/mol

C: molar mass = (1 * 12.01) = 12.01 g/mol

Na2S: molar mass = (2 * 22.99) + (1 * 32.07) = 78.05 g/mol

iii) The third step is to convert the masses given for Na2SO4 and C into the correspondent number of moles using the molar mass of these compounds:

IV) On the forth step, we must define the limiting reactant for this reaction considering the amounts used of each one and the stoichiometric coefficients:

1 mol Na2SO4 reacts with 1 mol C

0.106 mol Na2SO4 reacts with...?

Solving this calculation, we have that we would need 0.106 mol of C to react with 15.0 g of Na2SO4. Since we there are 0.624 mol of C available to react, we can conclude that carbon is the reactant in excess (there is an excess of 0.518 mol) and sodium sulfate is the limiting reactant.

V) At last, we can calculate the amount of Na2S produced from the limiting reactant amount used (0.106 mol of Na2SO4) and the stoichiometric coefficients:

1 mol Na2SO4 ----------1 mol Na2S

0.106 mol Na2SO4 ---- y

Solving for y, we have that 0.106 mol of Na2S will be produced.

vWe can convert this amount into mass of Na2S using its molar mass:

In summary:

Na2SO4 is the limiting reactant and there is an excess of 0.518 mol or 6.22 g of C;

8.27 g of Na2S will be produced from 15.0 g of Na2SO4.

Answer:

It the acid easier to handel

Answer:

im on this question i need help with it as well lol

Explanation:

Answer:

It weighs about 0.819 kg.

Answer: Cow fart unhealthy because

they spent there days for people can

make milk.

During translation, the process by which the genetic code in RNA is used to synthesize a polypeptide (protein), the amino acid that always begins the polypeptide is a methionine (abbreviated as Met).

This is because the start codon in RNA, which marks the beginning of the protein sequence, codes for the amino acid methionine. The genetic code is a set of rules that dictate how the sequence of nucleotides in RNA corresponds to the sequence of amino acids in a protein. Each three-nucleotide sequence in RNA is called a codon, and each codon codes for a specific amino acid. The start codon in RNA is the codon AUG, which codes for the amino acid methionine.

Once the methionine residue is added to the growing polypeptide chain, the rest of the amino acids are added in order according to the genetic code. The methionine residue is essential for the proper folding and function of the protein, as it is involved in the formation of the protein's first protein-protein interaction.

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In this instance, the equilibrium concentration of Cu⁺ with 0.10 M Br⁻ is similarly 0.10 M.

To determine the concentration of Cu⁺ in equilibrium with CuBr(s) and 0.10 M Br⁻, we need to consider the solubility equilibrium of CuBr.

The solubility equilibrium for CuBr can be represented as follows:

CuBr(s) ⇌ Cu⁺(aq) + Br⁻(aq)

The solubility product constant (Ksp) expression for this equilibrium is:

Ksp = [Cu⁺][Br⁻]

Since the stoichiometry of the reaction is 1:1 between Cu⁺ and Br⁻, the concentration of Cu⁺ in equilibrium will be equal to the concentration of Br⁻.

Therefore, in this case, the concentration of Cu⁺ in equilibrium with 0.10 M Br⁻ is also 0.10 M.

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The concentration of Cu+ in equilibrium with solid CuBr and 0.10M Br- is 7.9 x 10-5 M. This happens due to the common ion effect, which is the presence of extra Br- ions in solution that suppress the dissolution of CuBr.

You are asked to find the concentration of Cu+ in equilibrium with solid CuBr and 0.10M Br-. The solubility product constant (Ksp) defines the equilibrium between a solid and its constituent ions in a solution. The balanced equation for this dissolution process is:

CuBr(s) <==> Cu+ (aq) + Br- (aq)

For CuBr, the Ksp value is 7.9 x 10-5 M. This represents product of concentrations of its ions in the solution. However, we already have 0.10M Br-, which is much higher than that provided by the dissolution of CuBr. Therefore, the Cu+ concentration in equilibrium is essentially equal to the Ksp, i.e. 7.9 x 10-5 M.

Here, the concept of the common ion effect comes into play. The presence of extra Br- ions from the solution suppresses the dissolution of CuBr, thereby controlling the Cu+ concentration in the solution.

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Answer:

D

Explanation:

not all atoms would be the same size. As for they vary scaleing from left to right in the periodic table.

Answer:

Explanation:

Titration: titrate twice, the first time with an indicator to determine how much sodium hydroxide is needed to completely react with hydrochloric acid, and the second time without an indicator to prevent the contamination of the sodium chloride salt produced

Answer: Emily can measure the density of the piece of metal to find out what it is. Density is a physical property.

Explanation:

The density of a substance can be found by dividing its mass by its volume. No chemical reaction is involved in measuring the mass nor the volume; therefore, density is a physical property.

Answer:

7.08 moles

Explanation:

To find the number of moles of copper in 450 grams, we need to divide the given mass by the molar mass of copper.

The molar mass of copper can be found on the periodic table, and it is approximately 63.55 grams per mole.

So, the number of moles of copper in 450 grams is:

450 grams / 63.55 grams per mole = 7.08 moles

Answer: hydrogen + oxygen Right arrow .water

Explanation:

The exact equation for this reaction is;

2H2  +  O2 ------------->   2H2O

hydrogen + oxygen Right arrow. water is the correct option.

The equation shows hydrogen reacting with oxygen to form water is as follows:-

\(2H_2+O_2\rightarrow2H_2O\)

The above reaction in word form is written as follows:-

\(hydrogen+Oxygen \rightarrow water\)

So, hydrogen + oxygen Right arrow. water is the correct option.

Hydrogen-H

Oxyden-O

Water-\(H_2O\)

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Answer:

200

Explanation:

23 rounds down to 20

7 rounds up to 10

20 times 10 equals 200