range, variance, and standard deviation are measurements of: a. gradations of quality. b. sampling error. c. intensity. d. dispersion. e. quantity

ANSWER:

a. AB

STEP-BY-STEP EXPLANATION:

The greatest distance occurs when the speed is increasing and also takes less time to reach that speed.

According to the graph, the highest speed is 8 m/s and it reaches it in 3 seconds, therefore, it is where the greatest distance is given.

Therefore, the segment of greater distance is the segment AB

Answer:

Fnet = 16.98204316 N will point right

Explanation:

q₁ and q₂ both positive ⇒ F₁₂ will point right, repel

q₂ pos and q₃ neg        ⇒ F₂₃ will point right, attract

Fnet = F₁₂ + F₂₃

Fnet = k.q₁.q₂/r₁₂² + k.q₂.q₃/r₂₃²

Fnet = 9x10⁹x 9.33x10⁻⁶x4.22x10⁻⁶/(0.18)² +  9x10⁹x 4.22x10⁻⁶x8.42x10⁻⁶/(0.23)²

Fnet = 0.3543534/(0.18)² +  0.3197916/(0.23)²

Fnet = 10.93683333 + 6.04520983

Fnet = 16.98204316 N

(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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Answer:

From spectral lines astronomers can determine not only the element, but the temperature and density of that element in the star. The spectral line also can tell us about any magnetic field of the star. ... The light from the stuff between the stars allows astronomers to study the interstellar medium (ISM).

Answer:

A - 4.5 m/s

Explanation:

31,500/7,000= 4.5

Answer:

the speed is 3m/s

Explanation:

below is the working

Explanation:

KE = 0.5mv² = 0.5(50kg)(8.97m/s)² = 2,009.5J.

PE = mgh = (50kg)(9.81N/kg)(1m) = 490.5J.

You can see that the total mechanical energy (ME) is the sum

Answer:

Air temperature and air pressure both decreases

Answer: A

Explanation:

there will be no east-west displacement, in meters, relative to your starting location. The explanation is as The question implies that the boat crosses the river from the southern bank, aiming due north at all times until it reaches the northern bank.

This scenario indicates that the boat doesn't drift left or right during the crossing; hence there is no east-west displacement.In conclusion,

the boat's starting point and its endpoint are directly opposite, and there will be no east-west displacement, in meters, relative to your starting location.

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Answer:

The answer is "\(\bold{3.8\ \frac{m}{s}}\)"

Explanation:

\(0 = \int_{cs} \overrightarrow{V} \overrightarrow{dn} \\\\= \int_{h_1} \overrightarrow{V_1} \overrightarrow{dA_1} + V_2A_2 +V_3A_3V_3A_3 \\\\ = -\int_{h_1} V_1dA_1 + V_2 dA_2 \\\\\to \int^{h_1}_{0} V_1 max \frac{y}{h_1} w dy -V_2 wh_2 \ \ \ \ \ \ \ \_{where} \ \ \ v_1=\frac{y}{h_1}\\\\\)

\(\to V_3A_3= V_1 max [\frac{y^2}{2h_1}]^{h_1}_{0} -V_2wh_2 \\\\= \frac{V_1 max}{2} \times wh_1 -V_2wh_2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ A_3 =w_3h_3\\\\\to \frac{V_3A_3}{w}= \frac{V_1 max}{2} \times h_1 -V_2wh_2 \\\\ \to V_3h_3= \frac{V_1 max}{2} \times h_1 -V_2wh_2 \\\\\to 5 \times 0.15 = \frac{V_1}{2} \times 0.5 - 1 \times 0.2 \\\\V_1 = 3.8 \ \frac{m}{s}\)

Julia has to increase the no of loops in the coil in order to increase the generation of current.

A solenoid is an electromagnet formed by a helical coil of wire. which generates a magnetic field when an electric current is passed through the coil.

According to  Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the vof the amount of current.

magnetic flux is defined as

Ф=NBA

\(EMF = \frac{d\phi}{dt} \\\\EMF = \frac{d(NBA)}{dt} \\\\\)

\(EMF =NA \frac{d(B)}{dt} \\\\\)

EMF is directly proportional to the amount of current. so that in order to increase the amount of current emf should be increasing and Emf is increased by the increasing no of the loop in the coil.

Hence Julia has to increase the no of loops in the coil in order to increase the generation of current.

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Answer:

BBBBBBBBB

Explanation:

The beginning of solar system development is most likely indicated by the big bang theory. An explanation for how the universe grew from a high density starting state is provided by the Big Bang theory.

And temperature. The evolution of the observable universe from the earliest known times through its later large-scale form is explained by a variety of cosmological models of the Big Bang theory. The Sun and the things that circle it make up the solar system, which is gravitationally bound. The gravitational collapse of a massive interstellar molecular cloud gave it birth 4.6 billion years ago. 99.86% of the system's mass is in the Sun, with the planet holding the majority of the remaining mass.

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The nebular hypothesis is the most widely recognized cosmogony theory to explain how the Solar System started and evolved (as well as other planetary systems). It implies that gas and dust orbiting the Sun are what created the Solar System.

Over 70 different types of meteorites have undergone radiometric dating to ascertain their ages. The findings suggest that between 4.53 and 4.58 billion years ago, the Solar System and meteorites both began to develop.

Scientists believe that the formation of terrestrial planets like Earth several billion years ago resulted from the coalescence of hot blobs of molten rock and metal from dust and gas. Before they developed into separate planets, they went through four stages of development: differentiation, cratering, flooding, and surface evolution.

The solar nebula

4.6 billion years ago, the solar nebula, a cloud of gas and dust, gave rise to the Sun and the planets.

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Explanation:

The force between two charges is given by :

\(F=\dfrac{kq_1q_2}{r^2}\)

k is electrostatic constant

r is distance between charges

The force between charges is directly proportional to the product of charges and inversely proportional to the square of the distance between them.  

a)The runner's kinetic energy at the given  instant is  814.11Joules b)net work required to triple his speed is 6653.361Jolues

Mechanical energy is divided into two parts- one kinetic energy and second one is potential energy.

a) The kinetic energy is given by the following expression =(1/2)mv² where m is the mass of the body and v is the velocity of the body.

Now, we have runner mass as 62.5kg and speed as 5.10m/sec

So, after putting in the formula we get,

K.E=(1/2)×62.6×(5.10)²

=>K.E.=31.3×(26.01)

=>K.E=814.11Joules.

b)According to the definition of work energy theorem, work done on the body is equal to change in kinetic energy of the body

W=ΔK.E

When velocity is tripled, final kinetic energy(KE₂)=(1/2)×62.6×(3×5.10)²

=>KE₂=31.3×9×26.01

=>KE₂=7467.471Jolues.

Initial kinetic energy(KE₁)=814.11Joules.

So, net work required=KE₂-(KE₁)

                           =>W=7467.471-814.11

                           =>W=6653.361Jolues

Hence, a)kinetic energy is 814.11Joules and b)net work required is 6653.361Jolues.

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Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alone a horizontal roadway. Therefore,

(a) Cable work: 6,750,000 J horizontally.

(b) Cable work: 6,308,250 J at 35.0° above horizontal.

(c) No work by gravity.

To calculate the work done by the cable in each scenario, we need to consider the angle between the direction of the force applied and the displacement.

(a) If the cable pulls horizontally (0° above the horizontal):

In this case, the angle between the force and the displacement is 0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(0°)

Work = 1350 N * 5000 m * 1

Work = 6,750,000 J

The cable does 6,750,000 Joules of work on the car when it pulls horizontally.

(b) If the cable pulls at 35.0 degrees above the horizontal:

In this case, the angle between the force and the displacement is 35.0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(35.0°)

Work = 1350 N * 5000 m * 0.819

Work = 6,308,250 J

The cable does approximately 6,308,250 Joules of work on the car when it pulls at 35.0 degrees above the horizontal.

(c) The work done by gravity on the car is zero because gravity acts vertically downward, perpendicular to the displacement along the horizontal roadway. Therefore, the gravitational force does not contribute to the work done on the car in this scenario.

In both cases (a) and (b), the cable does the same amount of work on the tow truck as on the car since they are connected by the cable. So the work done by the cable on the tow truck would be equal to the values calculated above: 6,750,000 J in case (a) and 6,308,250 J in case (b).

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a) The shoppers who walked from the car to the door in 20 minutes walked for 1200 seconds.

b) The shoppers' walking speed in meters per second is 0.67m/s.

A) In the question, we are already given how long it took for the shoppers to walk from their car to the entrance of the shopping mall, although it's in minutes. We are told that it took them 20 minutes to walk from their car to the entrance. In order to know how long they were walking in seconds, we would have to multiply by 60. This is because there are 60 seconds in one minute. Hence, to find the number of seconds in 20 minutes, we multiply 20 minutes by 60 seconds, thus;

                     20 minutes × 60 seconds = 1200 seconds.

B) Now that we know how long the shoppers were walking in seconds, we can use it to get their walking speed. To find the speed of any moving object, we divide the distance the object travelled by the time taken for the object to cross that distance in seconds. In the question, we are told that the shoppers parked their car 800 meters away from the entrance. This means that the distance they walked to get to the entrance is also 800 meters. Thus to find their walking speed;

                               Speed = distance ÷ time

                               Speed = 800 meters ÷ 1200 seconds

                              Speed = 0.67 m/s.

Therefore, the shoppers walked for 1200 seconds at 0.67m/s.

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The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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The energy required to warm one gram of water by one celsius degree is called a specific heat

The specific heat also known as specific heat capacity, is an intensive property specific, and representative of each substance. It is defined as the energy or amount of heat required to raise the temperature of 1 kilogram (kg) of mass by one degree Celsius (°C).  

In the International units system of measurement the specific heat is expressed  in Joules per kilogram per degree Kelvin.

It is the physical magnitude that allows us to know the degree of heat that a body or an environment has. The higher the temperature, the greater the degree of heat.

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Groundwater is a part of the geosphere realm, which refers to the solid Earth.

The geosphere includes all of the land, rocks, and minerals that make up the Earth's crust, mantle, and core. Groundwater is water that is stored beneath the Earth's surface in rock formations called aquifers, which are part of the geosphere.

Groundwater is an important resource for drinking water, irrigation, and industrial use, and it plays a critical role in many natural systems, such as the water cycle and the formation of landscapes such as caves, sinkholes, and canyons.

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Answer:

Explanation:

The formula for the magnitude of this resultant vector, which is in Q1, btw, is:

\(B_{mag}=\sqrt{6.18^2+4.43^2}\) which gives us, to 3 sig fig's:

7.60 m. Since the resultant vector is in Q1, we don't need to add anything to the angle once we find it to 3 sig fig:

\(tan^{-1}(\frac{4.43}{6.18})\) gives us an angle of 35.6 degrees

The producer of refrigerator compressors needs to determine the number of kanbans required for implementing a just-in-time production line to meet the demand for 150 compressors per day from a neighboring appliance manufacturer.

To calculate the number of kanbans required, we need to consider the production lead time, safety stock factor, and optimal production quantity. The production lead time is 5 days, which means that it takes 5 days to produce a batch of compressors once the production process starts.

The safety stock factor is 17%, indicating that the producer wants to maintain an additional 17% of the daily demand as safety stock to mitigate any unforeseen fluctuations. The optimal production quantity is 95 units, which is the batch size that minimizes setup costs.

To determine the number of kanbans, we first need to calculate the total demand during the production lead time. Since the demand is 150 compressors per day and the lead time is 5 days, the total demand during the lead time is 150 compressors/day * 5 days = 750 compressors. Adding the safety stock, the total demand becomes 750 compressors + (17% * 150 compressors) = 750 compressors + 25.5 compressors = 775.5 compressors.

Next, we divide the total demand by the optimal production quantity to get the number of kanbans required. The number of kanbans is calculated as 775.5 compressors / 95 compressors per kanban = 8.16 kanbans. Since we cannot have a fraction of a kanban, we round up to the nearest whole number. Therefore, the producer of compressors requires 9 kanbans to meet the demand of 150 compressors per day from the neighboring appliance manufacturer.

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The complete question is:

A producer of refrigerator compressors wants to implement a just-in-time production line to support demand from a neighboring appliance manufacturer. Demand from the appliance manufacturer is for 150 compressors a day. The production lead time is 5 days and the producer wants to have a 17% safety stock factor. This producer has also cut setup costs such that the optimal production quantity is 95 units. How many kanbans does this producer of compressors require?

Answer:

the acceleration of the car is 1.167 m/s²

Explanation:

Given;

initial velocity of the race car, u = 5 m/s

final velocity of the race car, v = 12 m/s

time to finish the race, t = 6 s

The acceleration of the car is calculated as;

a = (v - u) / t

a = (12 - 5) / (6)

a = 1.167 m/s²

Therefore, the acceleration of the car is 1.167 m/s²

Answer:

1.167 m/s^2

Explanation:

Given that a race car is accelerating at 5m/s and then speeds up to a final velocity of 12 m/s if the race car driver finished this let of the race in 6 seconds what was the car's acceleration ?

From the question, the following parameters are given

Initial velocity U = 5 m/s

Final velocity V = 12 m/s

Time t = 6 s

According to the definition of acceleration:

Acceleration = change in velocity per time taken.

I.e

Acceleration =( V - U)/ t

Acceleration =( 12 - 5 )/6

Acceleration = 7/6

Acceleration = 1.167 m/s^2

Therefore, acceleration is 1.167 m/s^2

Answer:

give brainliest please

Explanation:

T- lymphocytes or T cells

The Sun appears bigger and brighter than other stars in the sky because it is much closer to the Earth than any other star.

While the Sun is only an average-sized star, it is still much closer to us than any other star, so it appears larger and brighter in the sky.

Additionally, the Sun is also the closest star to the Earth that undergoes nuclear fusion, which is the process that produces its energy and makes it shine.

Other stars in the sky may be much larger or brighter than the Sun, but their distance from us makes them appear much smaller and dimmer.

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An optical device is an instrument that uses light for a purpose. The device that can focus light to a point through reflection is mirror.

The reflection is the phenomenon of a light ray going back to the same medium after striking a surface.

The mirror is a one sided polished surface which reflects all the light falling on it. The reflected light after striking the mirror meets at a point forming the image of an object place in front of mirror. A mirror is an optical device that uses reflection phenomenon to focus light.

Thus, the device that can focus light to a point through reflection is mirror.

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Given data:

1) Runner jogged 40 m at a slow pace for 40 sec.

2) Stopped for 40 sec.

3) Again funs for 60 m in 20 sec.

Friction affects the work done by machines by reducing the mechanical advantage of that machine.

MA = \(F_{o}\) / \(F_{i}\)

MA = Mechanical advantage

\(F_{o}\) = Output force

\(F_{i}\) = Input force

Mechanical advantage is the ratio of output force to input force in a system.

According to law of conservation of energy, input energy is equal to output energy. It is true in the machines also but some of the output energy is not necessarily asked of the machine. That energy which is not useful is heat produced due to friction.

Therefore, friction affects the work done by machines by reducing the mechanical advantage of that machine.

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Answer:

Speed and velocity are related in much the same way that distance and displacement are related. Speed is a scalar and velocity is a vector.