Retrograde motion was a major source of difficulty in designing a theoretical model of the solar system. what is the explanation for retrograde motion?
Answers
Retrograde motion refers to the apparent backward or opposite motion of a planet in its orbit as observed from Earth. It was a major challenge in early attempts to develop theoretical models of the solar system.
The explanation for retrograde motion lies in the relative motion and orbits of the Earth and other planets. As Earth orbits the Sun, it occasionally catches up with and overtakes other planets in their orbits. When this occurs, the motion of the overtaken planet appears to change direction relative to the background stars, creating the illusion of retrograde motion.
To understand this, it is essential to recognize that planets closer to the Sun than Earth (such as Mercury and Venus) have smaller orbits, while those farther away (such as Mars, Jupiter, and Saturn) have larger orbits. As Earth orbits the Sun, planets closer to the Sun can be overtaken, resulting in their apparent retrograde motion.
This phenomenon occurs due to a combination of the planets' varying orbital speeds and the differences in their orbital distances from the Sun. When Earth overtakes an inner planet, it passes it at a higher speed, causing the inner planet to appear to move backward (retrograde) against the backdrop of the more distant stars. Once Earth moves ahead of the inner planet, it resumes its normal forward motion.
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Related Questions
Vi VE
5. A train accelerates from 60 km/h to 150 km/h and travels 600 m. How long does
this motion take?
2.0.6
600 m.
Answers
Answer:
50%.......
Explanation:
is the correct check it then send feedback
Oxygen makes up more than 90 percent of the volume of the Earth's crust. Is oxygen found as a solid, liquid, or gas?
Answers
Answer:
Oxygen is an element that can be a solid, liquid or gas depending on its temperature and pressure. In the atmosphere it is found as a gas, more specifically, a diatomic gas. This means that two oxygen atoms are connected together in a covalent double bond.
A plane lands and comes to a complete stop through 180 m of runway with a deceleration of 6.25 m/s2 [N]. Determine the plane’s velocity when it first touched the landing strip.
Answers
Answer:
47.43 m/s
Explanation:
Given that,
Final speed of a plane, v = 0
Distance, d = 180 m
Acceleration of the plane, a = -6.25 m/s² (deceleration )
We need to find the plane's velocity. Let it was u. So, using the third equation of kinematics as :
\(v^2-u^2=2ad\\\\u^2=0^2-2\times (-6.25)\times 180\\\\u=\sqrt{2250} \\\\u=15\sqrt{10}\ m/s\\ \\\text{or}\\\\u=47.43\ m/s\)
So, the plane's velocity when it first touched the landing strip is 47.43 m/s.
A 2uF capacitor, in series with a 2kohm resistance is joined to 100Vd. C supply. Calculate:
i. The current flowing and
ii. The energy stored in the capacitor at the end of 4 seconds from the start.
Answers
i) The current flowing is 0.05A.
ii) The energy stored in the capacitor at the end of 4 seconds from the start is 0.001J.
i)To calculate the current flowing, we can use Ohm's Law which states that current (I) is equal to voltage (V) divided by resistance (R):
I = V/R
In this case, V is 100V and R is 2kohm. So,
I = 100V / 2kohm
I = 0.05A
Therefore, the current flowing is 0.05A.
ii)To calculate the energy stored in the capacitor, we can use the formula:
E = (1/2) * C * V^2
Where E is energy, C is capacitance and V is voltage.
In this case, C is 2uF (which is equivalent to 0.000002F) and V is also 100V. So,
E = (1/2) * 0.000002F * (100V)^2
E = 0.001J
Therefore, the energy stored in the capacitor at the end of 4 seconds from the start is 0.001J.
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Which skateboarder has greater momentum?
a) Skateboarder A: mass = 60 kg; velocity = 1.5 m/s
b) Skateboarder B: mass = 50 kg; velocity = 2.0 m/s
Answers
Answer:
skateboard b
Explanation:
p=mv
skateboard a
p=(60kg)(1.5m/s)=90kg*m/s
skateboard b
p=(50kg)(2m/s)=100kg*m/s
Skateboarder B has the greater momentum because the momentum of A is 90 kg m/s and the momentum of B is 100 kg m/s so B has the greater momentum.
What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum. Check out Newton's laws of motion.
According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum. On the other hand, a particle's momentum represents the length of time needed for a consistent force to bring it to rest.
According to the question,
For Skateboarder A :
momentum = 60 × 1.5
momentum = 90 kg m/s
For Skateboarder B :
momentum = 50 × 2
momentum = 100 kg m/s.
Hence, B has greater momentum than A.
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after turning on the light switch, at what level do you set the rheostat?
Answers
We can see here that after turning on the light switch the level that you set the rheostat is to the lowest level.
What is a rheostat?A rheostat is a variable resistor that is used to control the amount of current flowing through a circuit. In a lighting circuit, the rheostat is used to control the brightness of the light.
When the rheostat is set to the lowest level, the most resistance is present in the circuit, which reduces the amount of current flowing through the light bulb. This results in a dimmer light.
As the rheostat is turned up, the resistance in the circuit decreases, which allows more current to flow through the light bulb. This results in a brighter light.
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How does the 3rd Newtons Law apply to kicking a soccer ball?
Answers
The soccer ball will exert an equal amount of force but in the opposite direction, which is on your foot. This is felt as ‘recoil’
Calculate the minimum frequency of ultrasound that will allow you to see details as small as 0.802 mm in human tissue. (Assume the speed of sound through human tissue is 1540 m/s.)
Answers
Answer:
the minimum frequency of ultrasound that will allow you to see the details is 1.92 x 10⁶ Hz.
Explanation:
Given;
wavelength, λ = 0.802 mm = 0.802 x 10⁻³ m
speed of sound in human tissue, v = 1540 m/s
The minimum frequency of ultrasound that will allow you to see the details is calculated as;
\(f = \frac{v}{\lambda} \\\\f = \frac{1540}{0.802 \times 10^{-3}} \\\\f = 1.92 \ \times \ 10^6 \ Hz\)
Therefore, the minimum frequency of ultrasound that will allow you to see the details is 1.92 x 10⁶ Hz.
This armed
rover weighs 1900 N
and has a mass of
340 kg. What is the
acceleration due to gravity
on its current planet?
Please help
Answers
Answer:
5.59 m/s2
Explanation:
F = 1900 N
m = 340 kg
F = ma
Therefore, a = 1900/340 = 5.59
What type of number is 3π + 1?
Choose all answers that apply:
A. whole number
B. integer
C. rational
D. Irrational
Answers
Answer: It's D
Explanation:
True or false, anything can turn into a black hole.
Answers
Answer:
False. Not everything can turn into a black hole. The formation of a black hole requires a massive object, typically a star, to collapse under its own gravity. This collapse causes the object to become so dense that it creates a singularity, a point of infinite density at the center of the black hole, which is surrounded by an event horizon, the point of no return beyond which nothing, not even light, can escape. So, only objects with sufficient mass and gravity can become black holes.
Explanation:
For the following questions, please provide a complete step by step solution. You do notneed interaction, but you are required force diagrams.
Answers
Tennsion 1= horizontal = 484.94 N
Tension 2 = slanted string = 560 N
Explanation
Step 1
Free body diagram
Newton's first law says that if the net force on an object is zero, like in this case the mass is in rest,then that object will have zero acceleration
so
Step 1
set the equations:
a) for x-axis
\(\begin{gathered} \sum ^{}_{}F_x=0 \\ so \\ T_{2x}-T_1=0 \\ T_2\cos 30-T_1=0\rightarrow equation(1) \end{gathered}\)b) for y -axis
\(\begin{gathered} \sum ^{}_{}F_y=0 \\ so \\ T_{2y}-w=0 \\ T_2\sin 30-280N=0\rightarrow equation(2) \end{gathered}\)Step 2
Solve the equations
\(\begin{gathered} T_2\cos 30-T_1=0\rightarrow equation(1) \\ T_2\sin 30-280N=0\rightarrow equation(2) \end{gathered}\)a) solve for T2in equation (2)
\(\begin{gathered} T_2\sin 30-280N=0\rightarrow equation(2 \\ \text{add 280 N in both sides} \\ T_2\sin 30-280N+280N=0+280\text{ N} \\ T_2\sin 30=280\text{ N} \\ \text{divide both sides by sin 30} \\ \frac{T_2\sin30}{\sin30}=\frac{280\text{ N}}{\sin30} \\ T_2=560\text{ N} \end{gathered}\)b) replace the T2 value in equation (1) to find T1
\(\begin{gathered} T_2\cos 30-T_1=0\rightarrow equation(1) \\ 560\cos 30-T_1=0\rightarrow equation(1) \\ 484.97-T_1=0 \\ 484.97=T_1 \end{gathered}\)therefore
Tennsion 1= horizontal = 484.94 N
Tension 2 = slanted string = 560 N
I hope this helps you
I have no clue on how to do this
Answers
a)5m/s b)5
the 5 is because you add the seconds to get 8 seconds and then do the same with the distance to get 40. 40/8 = 5. speed = 5
Velocity = displacement/change in time
V = 40/8
I just realized how unorganised my math looks but I hope this is helpfull
Why is thunder so d*mn loud. Like that s*it always the scares the living hell out of my dog.
Answers
Answer:
Տᗩᗰᗴ ᵐᵃᵗᵉ Տᗩᗰᗴ
\( \infty \infty \)
Answer:
The thunder I know it is to loud
It scares me sooooo much :O
I hope you are having a great day :3❤️
briefly explain why the magnitude of the absorption coefficient a depends on the radiationwavelength.
Answers
It is important to understand what the absorption coefficient (a) represents.
This coefficient is a measure of the amount of energy that is absorbed by a material per unit of distance traveled by the radiation through the material. In other words, it represents the ability of a material to absorb electromagnetic radiation. The magnitude of this coefficient can vary depending on a number of different factors, one of which is the wavelength of the radiation.
Lastly, it is important to note that the magnitude of the absorption coefficient is not the only factor that determines how much radiation is absorbed by a material. Other factors such as the thickness of the material, the temperature of the material, and the intensity of the radiation all play a role in determining the amount of energy that is absorbed.
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Given that on Earth, gravity causes an acceleration of 9.8 m/s2, what is an acceleration of 7 g?
Answers
Answer:
68.6 m/s^2
Explanation:
1 g = 9.8 m/s^2
so
7 g × 9.8m/s^2 = 68.6
A skateboarder starts at point A on the ramp and rises to point B, a maximum height of h = 3.01 m above the top of the ramp.If the amount of work done against friction is insignificant, determine his initial speed (in m/s) at point A
Answers
Answer:
7.68m/s
Explanation:
At point A, height h= 0m where v=?
At point B, height of h = 3.01 m above the top of the ramp v= 0 m/s
The conservation of energy here will be energy at Point A equals energy at point B
g= acceleration due to gravity= 9.81m/s^2
(mgh + 1/2 mv^2)A = (mgh + 1/2 mv^2)B
✓But height h at point A= 0 m then energy at point A= 1/2 mv^2
✓At point B , the velocity v= 0 m/s, then Energy at point B= mgh
✓ if we equate both energy at point A and B we have
mgh=1/2 mv^2
Let us make v the subject of formula, and cancel out the "m"
v=√2gh
Then substitute the values
V= √2×9.81×3.01
V=7.68m/s
Hence, his initial speed (in m/s) at point A is 7.68m/s
For the circuit shown, which of the following statements is true?
Answers
Answer:
ΔV1 = ΔV2 = I1 R1 = I2 R2
The first answer is correct - the voltage drop is the same across either resistor
I = I1 + I2 because the current splits on entering the resistors
which statements about the moon’s phases are true? check all that apply.
Answers
The moon has eight phases in its cycle.
The following are the statements that are true regarding the moon’s phases:
The moon's phase cycle lasts about 29.5 days long. The length of the moon's phase cycle is 29.5 days and not exactly 28 days. This discrepancy is caused by the moon's elliptical orbit around the Earth, as well as the Earth's own elliptical orbit around the sun.
The Moon’s phases are due to the alignment of the Sun, Earth, and the Moon. The moon's phases are determined by the positioning of the Sun, Earth, and Moon. Depending on where these celestial objects are in relation to one another, the Moon appears to be different shapes at different times. The moon's phases are a result of light from the sun reflecting off the moon's surface.
During a new moon, the Moon is located between the Earth and the Sun. When the Moon is in this position, it appears dark since the side that is lit by the sun faces away from Earth.
During a full moon, the Earth is located between the Sun and the Moon. During this time, the entire sunlit side of the moon faces Earth, causing the Moon to appear as a perfect circle in the sky. These statements are true about the moon’s phases.
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An upward electric force of 10 N is exerted on a 3 C charge. Find the magnitude and direction of the electric field at the position of this charge. Group of answer choices Cannot be determined 30 N/C, upward 30 N/C, downward 3.33 N/C, downward 3.33 N/C, upward
Answers
The magnitude and direction of the electric field at the position of this charge.3.33 N/C upward
An electric field is the electric force per unit of charge. It is assumed that the field's direction corresponds to the direction in which a positive test charge would experience force. The electric field is directed radially inward toward a negative point charge and radially outward from a positive charge.
Value of force F given = 10N
value of charge Q = 3 C
We know that E = F/Q
E = 10/3
= 3.33N
where charge is scalar quantity so the direction of force is the direction of electric field
Hence the magnitude and direction of the electric field at the position of this charge.3.33 N/C upward
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Which of the following represents a possible magnitude for the force of static friction when Xavier applied 72.1 Newtons of force on the cart?
Answers
The possible magnitude for the force of static friction on the stationary cart is 72.1 N.
The given parameters:
Applied force on the cart, F = 72.1 NBased on Newton's second law of motion, the force applied to object is directly proportional to the product of mass and acceleration of the object.
F = ma
Static frictional force is the force resisting the motion of an object at rest.
\(\Sigma F = 0\\\\F -F_f = 0\)
where;
\(F_f\) is the frictional force
\(F= F_f \\\\72.1 = F_f\\\\F_f = 72.1\ N\)
Thus, the possible magnitude for the force of static friction on the stationary cart is 72.1 N.
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x=3+4t+6t^2+4^2 what is the velocity and acceleration?what is the acceleration when the velocity is 1om/s?
Answers
Answer:
Velocity= 12t + 12t^2
Acceleration= 12 + 24t^2
When the velocity is 10m/s, the acceleration is 20.
Branch of physics which deals with properties of light
Answers
Answer:
Branch of physics which deals with properties of light is called Optics
Explanation:
A ball of mass of 0.5kg is dropped from a height of 2m.
Assuming that all of the GPE is transferred to KE, what
will be the velocity of the ball when it hits the ground?
Answers
Answer:
6.3m/s
Explanation:
Given parameters:
Mass of the ball = 0.5kg
Height = 2m
Unknown:
Velocity when the ball hits the ground = ?
Solution:
Since the potential energy is transformed into kinetic energy;
P.E = K.E
mgh = \(\frac{1}{2}\) m v²
cancelling m;
gh = \(\frac{1}{2}\) v²
v² = 2gh
v = √2gh
Insert the parameters and solve;
v = √2gh = √ 2 x 9.8 x 2 = 6.3m/s
Native people are
in films.
Select the best answer from the choices provided.
O A. almost always cast in supporting roles
OB. rarely allowed to speak
OC. rarely allowed to display a real personality
OD. All of the answers are correct.
Answers
Answer:
D.
Explanation:
all of the options are true.
Two identical clocks are set to 12 noon time when on the ground at rest relative to the ground. One clock is placed in a spacecraft, sent into space and accelerated to a speed of v = 0.93 x 108 m/s. What will the moving clock read if the first clock reads 6 p.m.? Express your answer as the number of minutes from 6 pm.
Answers
First, for this problem, we will need to know the formula for time dilation
\(t=\frac{t_0}{\sqrt{1-\frac{v^2}{c^2}}}\)Where t is the time in the reference frame on earth
t0 is the time on the ship
v is the velocity relative to lightspeed
and c is light speed in a vacuum
For this problem, we will need to convert .93x10^8 to a fraction of light speed.
.93x10^8 = .31c
Now, we can plug in the numbers we get from the given
t0 = 6 hours since the ship has been in the air for 6 hours
\(t=\frac{6}{\sqrt{1-\frac{(.31c)^2}{c^2}}}\)t = 6.31089
For the answer to be valid, we will convert .31089 to minutes by multiplying it by 60 (60 minutes in a hour)
18.654 minutes
A car travels 500 km from home at 35 m/s, then travels back at 43 m/s. Find its average speed.
Answers
The average speed of the car is 35.6m/s
What is average speed?The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction. It is measured in meter per second
Therefore average speed = total distance / total time taken
The total distance here is 500+ 500= 1000km = 1×10⁶m
the time taken for the first journey = 500×1000/35= 14285.71 seconds
the time taken for traveling back = 500000/43= 11627.91 seconds
total time taken = 14285.71 + 11627.91 = 25913.62seconds
therefore average speed = 1000000/25913.62
= 35.6m/s
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a uniformly charged rod with length and line charge density is bent to form one quadrant of a circle. what is the magntiude of the electric field at the center of the circle?
Answers
Let's consider a uniformly charged rod with length "l" and line charge density "λ." A quadrant of a circle with radius "R" is formed by bending the rod. We have to find out the magnitude of the electric field at the center of the circle. Let's assume that the arc is made up of n sections.
For small segments of the arc, we can assume the electric field is constant and perpendicular to the segments. Hence, we can treat each segment as a point charge with the amount of charge given by dq = λ × ds. Here, "ds" is the small length of the arc segment, and "λ" is the line charge density. The distance from each segment to the center of the arc is equal to R.
Let's find out the magnitude of the electric field at the center of the circle by using the formula;
E = ∫ dE
The formula for the electric field due to a point charge q at a distance r is:
E = k × (q / r²)
Here, k is Coulomb's constant, which is equal to 9 × 10⁹ Nm²/C².So, we can write the equation for dE as;d
E = k × dq / r² Now, let's substitute the value of "dq" into the above equation;
dE = k × λ × ds / R² For a quadrant of a circle, we have a total length of πR/2. If we divide the arc into n sections, each section will have a length of (πR/2) / n. Hence, we can write the total electric field at the center as;
E = ∑ dE
= k × λ × (∑ ds / R²)
= k × λ × (∑ (πR/2) / n × R²)
= (kλπR) / (2n)
As we know, the line charge density (λ) = q/l. So, we can rewrite the above equation as:
E = (kqπR) / (2nl)
Therefore, the magnitude of the electric field at the center of the circle is given by; E = (kqπR) / (2nl)
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A 25.0 kg door is 0.925 m wide. A customer
pushes it perpendicular to its face with a 19.2
N force, and creates an angular acceleration
of 1.84 rad/s2. At what distance from the axis
was the force applied?
[?] m
Hint: Remember, the moment of inertia for a panel
rotating about its end is I = mr².
Answers
The distance from the axis of the force applied is 2.05 m.
What is the distance from the axis of the force applied?The distance from the axis of the force applied is calculated as follows;
The formula for torque;
τ = Fr
where;
F is the applied forcer is the distance from the axis of the force appliedAnother formula for torque is given as;
τ = Iα
where;
I is the moment of inertia of the doorα is the angular acceleration;τ = (mr²)α
τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)
τ = 39.36 Nm
The distance is calculated as;
r = τ/F
r = ( 39.36 Nm ) / (19.2 N)
r = 2.05 m
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what is a positive lachman maneuver/test
Answers
A positive Lachman maneuver or test refers to the presence of increased anterior translation of the tibia in relation to the femur when performing a manual examination of the knee joint.
This finding suggests a possible anterior cruciate ligament (ACL) injury, as the ACL provides stability to prevent this type of movement. A positive Lachman test is often used as part of the clinical evaluation of a knee injury, along with other tests and imaging studies, to determine the extent of the damage and guide treatment. Place the patient's knee in about 20-30 degrees flexion. According to Bates' Guide to Physical Examination, the leg should also be externally rotated slightly. The examiner should place one hand behind the tibia and the other on the patient's thigh. It is important that the examiner's thumb be on the tibial tuberosity. On pulling the tibia anteriorly, an intact ACL should prevent forward translational movement of the tibia on the femur ("firm end-feel"). So, a positive Lachman maneuver or test refers to the presence of increased anterior translation of the tibia in relation to the femur when performing a manual examination of the knee joint.
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