Since the force is zero, the boat does not move. Therefore, the distance the boat moves away from the pier as Jake walks to the front of the boat is zero.
To solve this problem, we need to use the conservation of linear momentum.
The total mass of the boat and the two brothers is given by:
M = m_boat + m_brother_1 + m_brother_2
= 83.0 kg + 59.5 kg + 50.0 kg
= 192.5 kg
The total momentum of the system before Jake starts walking is given by:
P_total = m_boat * v_boat + m_brother_1 * v_brother_1 + m_brother_2 * v_brother_2
= (83.0 kg) * (v_boat) + (59.5 kg) * (0) + (50.0 kg) * (0)
= 83.0 kg * v_boat + 297.5 kg * 0
= 210.5 kg * v_boat
v_boat is the velocity of the boat, measured in the same direction as the displacement of the boat.
Since the boat is stationary initially, v_boat = 0.
Now, we can apply Newton's second law to the system. The force exerted on the boat by Jake, who is walking towards the front of the boat, is equal to the momentum of the boat relative to Jake. Since Jake is walking away from the pier, the momentum of the boat relative to Jake is negative. Therefore, we have:
F = P_relative - P_initial
= -210.5 kg * v_boat - 297.5 kg * 0
= -408.0 kg * 0
= 0 N
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Which diagram shows the effect of cutting the
acceleration in Part A in half and not changing
the value of the initial velocity?
Acceleration is the rate of change of velocity over time. The diagram that shows the effect of cutting acceleration by half without changing initial velocity is graph (c)
The equation is given as:
\(v = 2t + 4\)
The first equation of motion is:
\(v = u + at\)
By comparing both equations, we have:
\(u = 4\) --- initial velocity
\(a = 2\) --- acceleration
When the acceleration is cut in half, the new acceleration is:
\(a_{new} = \frac a2\)
\(a_{new} = \frac 22\)
\(a_{new} = 1\)
So, the equation of velocity is:
\(v = u + at\)
\(v = 4 + 1 \times t\)
\(v = 4 + t\)
When \(t = 0\)
\(v = 4 + 0 = 4\)
When \(t = 1\)
\(v = 4 + 1 = 5\)
The graph of velocity that satisfies \(v = 4 + t\) and the values of time (t) and velocity (v) tested above is (c).
See attachment for the diagram (graph)
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What is occurring in the umbra?
A. a total solar eclipse
B. a total lunar eclipse
C. a partial lunar eclipse
D. a partial solar eclipse
Answer:
A. a total solar eclipse
Explanation:
During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth
what is the formula of kinetic and potential energy
hey its haris
Answer:
Explanation:
potential energy = mgh
kinetic energy = 1/2mv²
A 2kg mass is suspended on a rope that wraps around a frictionless pulley attached to the ceiling with a mass of 0.01kg and a radius of 0.25 m. The other end of the rope is attached to a massless suspended platform, upon which 0.5 kg weights may be placed. While the system is initially in equilibrium, the rope is later cut above the weight, and the platform subsequently raised by pulling the rope. What is the torque on the pulley when the system is motionless?
Answer:
The torque on the pulley, when the system is motionless is approximately 9.81 N·m
Explanation:
The given parameters are;
The mass of the object = 2 kg
The friction between the rope and the pulley = 0
The mass of the rope, \(m_r\) = 0.5 kg
The mass of the pulley, \(m_p\) = 0.01 kg
The radius of the pulley, r = 0.25 m
The torque on the pulley, τ = I·α = F × D
The torque on the pulley, when the system is motionless, τ = F × D
Where;
F = The force acting on the pulley rope = The weight of the mass ≈ 2 kg × 9.81 m/s² = 19.62 N
D = The diameter of the pulley = 2×r = 2 × 0.25 m = 0.5 m
Therefore;
τ = 19.62 N × 0.5 m = 9.81 N·m
The torque on the pulley, when the system is motionless, τ ≈ 9.81 N·m.
If a body gains 360 electrons, what is its electric charge?
Answer:
5.76×10⁻¹⁷ C
Explanation:
An electron has a charge of 1.6×10⁻¹⁹ C.
360 × (1.6×10⁻¹⁹ C) = 5.76×10⁻¹⁷ C
pdf a ball thrown vertically upward continues upward until it reaches a certain position, and then falls downward. the ball's velocity is instantaneously zero at that highest point. is the ball accelerating at that point. describe an experiment to prove or disprove your answer.
When the ball is thrown upward, gravity takes control as soon as it is removed from the hand. The ball will only be under its control.
The ball is moving downward at a rate of 9.8 meters per second squared as it approaches the dot-com point. Using a second camera and the gadget, you can perform an experiment where you can observe that the velocity is 0.0 at the top, but varies somewhat before and after it moves.
The ball is accelerating, as can be shown if you take the difference in velocities and calculate acceleration of the ball.
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When a 5 kg rock is dropped from a height of 6 m on Planet X, it loses 24 J of GPE. What is the acceleration due to gravity on Planet X?
Answer:
g = 1.25m/s²
Explanation:
Given the following data;
Mass = 5kg
Height = 6m
Gravitational potential energy = 24J
To find the acceleration due to gravity;
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
\( P.E = mgh\)
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
GPE = mgh
Substituting into the equation, we have;
24 = 5*6*g
24 = 30g
g = 30/24
g = 1.25m/s²
Therefore, the acceleration due to gravity on Planet X is 1.25m/s².
Answer:
g=0.8m/s^2
Explanation:
M=5kg
h=6m
GPE=24J
GPE=Mgh
g=GPE/Mh
g=24J/(5kg)(6m)=0.8
g=0.8m/s^2
Which of the following most correctly describes end-diastolic volume?
A. the volume of the ventricle when it is least full
B. the volume of the ventricle at the end of atrial diastole
C. the increase in ventricular volume during atrial systole
D. the volume of the ventricle when it is most full
The correct option is D. the volume of the ventricle when it is most full.
The volume of the ventricle when it is most full is the most correct description of end-diastolic volume.
It can be defined as the amount of blood in the ventricle immediately before a cardiac contraction or systole occurs. End-diastolic volume is the volume of blood in the ventricles at the end of diastole, after filling with blood from the atria, before the ventricles contract to begin systole.
ventricles are hollow chambers or cavities found in the heart and brain. In the heart, there are two ventricles responsible for pumping blood, while in the brain, there are four interconnected ventricles that produce and circulate cerebrospinal fluid.
Therefore, the correct option is D. the volume of the ventricle when it is most full.
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A solid cylinder of mass 3.6 kg and radius 25 cm is rotating counterclockwise around a vertical axis running through the centers of its circular faces at 580 rev/min. A second solid cylinder of the same mass and radius is rotating clockwise around the same vertical axis running through the centers of its circular faces at 890 rev/min. If the cylinders couple so that they rotate about the same vertical axis, what is the angular velocity (in rev/min) of the combination?
A solid cylinder of mass (M=1 kg) and radius R=0.5 m is pivoted at its center The axis of rotation of the cylinder is horizontal. Three small particles of mass (m=0.1 kg) are mounted along its surface as shown in the figure. The system is initially at rest.
Solid cylinders need to be cut or split into small thin rings.
Each ring consists of a thickness dr of length L.
The moments of these thin cylindrical shells should be summed to infinitesimal.
Follow the instructions given.
1st place Use the general moment of inertia equation.
dI = r2 dm
Next, proceed to the dm determination. It is usually given as follows: To get
dm = ρdV
dm, you first need to calculate DV. It is given as follows:
dV = dA L
where dA is the area of the large ring (radius: r + dr) minus the small ring (radius: r). as a result;
Please check the attached file for ta detailed answer.
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a 0.350 kg block at -27.5 °C is added to 0.217 kg of water at 25.0 °C. they come to equilibrium at 16.4 °C. what is the specific heat of the block?
Answer:
\(C_{pb}=0.501\ kJ/kg.K\)
Explanation:
Given that
\(m_1=0.35 kg\)
\(T_1=-27.5^oC\)
\(m_2=0.214 kg\)
\(T_2=25^oC\)
\(T=16.4^oC\)
We know that
\(C_{pw}=4.187 kJ/kg.K\)
By using energy conservation
Heat lost by water = Heat gain by block
\(m_2\times C_{pw}\times (T_2-T)=m_1\times C_{pb}\times (T-T_1)\)
\(0.214\times 4.187\times (25-16.4)=0.35\times C_{pb}\times (16.4+27.5)\)
\(C_{pb}=0.501\ kJ/kg.K\)
Therefore the specific heat of the block will be 0.501 kJ/kg.K
Homeostasis is most closely associated with which motivation theory? A. Instintict theory B. Incentive theory C. Hierarchy of needs D. Arousal theory E. Drive reduction theory
Homeostasis is most closely associated with the drive reduction theory. The drive reduction theory explains how homeostasis is maintained by the satisfaction of biological needs that reduce the drive state.
What is meant by homeostasis?Homeostasis is the ability of an organism or a cell to regulate its internal environment to maintain a stable, relatively constant condition. It helps ensure the stability of the internal environment in response to changes in external conditions.
What is the importance of homeostasis?Homeostasis helps the organism to survive and function optimally. Examples include regulation of body temperature, blood glucose levels, and water balance.
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Which of the following is an advantage of recorded presentations? A. Start-times and time zones are not a factor. B. Speakers can adapt topic coverage if necessary. C. Audience members have the opportunity to provide feedback D. More visual aids can be used.
The statement describes an advantage of recorded presentations is that the audience members have the opportunity to provide feedback. Thus, the correct option for this question is C.
What do you mean by Recorded presentations?A recorded presentation may be defined as a popular format of multimedia content with a duration of several seconds or minutes that significantly expresses the advantages of a product, service, or any idea with the support of interesting graphic images, concise text, and appropriate narration.
According to the context of this question, a recorded presentation delivers an advantage to the audience to provide feedback. This is because the process of recorded PowerPoint presentation gives the actual sense and understanding to the audience similar to the real event.
Therefore, the correct option for this question is C.
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A wave with a frequency of 56 Hz has a wavelength of 27 meters. At what speed will this wave travel?
A constant property, highly viscous, hot liquid having the far upstream temperature To and velocity u flows slowly through an infinitely long tube of cross-sectional area A and perimeter P. The wall thickness of the tube is negligible. The upstream half of the tube is insulated and the downstream half is subjected to convective heat transfer with the ambient at T. The heat transfer coefficient is h. Since the fluid flow is slow, axial heat conduction cannot be neglected. u a) Derive the differential equation describing the temperature distribution of the liquid in the downstream region based on a plug flow assumption. State all other assumptions. b) Write the appropriate boundary conditions and solve the differential equation.
a) The derivation of the differential equation is ΔT' = (1 - h/(ρcPu))ΔT + T' - T and is explained in the explanation part below. b) The appropriate boundary conditions are: At the tube entrance (x = 0), T = To. At the tube exit (x = L), the convective heat transfer condition is applied: -kA(dT/dx) = hA(T - T∞).
a) The following assumptions are made to develop the differential equation characterising the temperature distribution of the liquid in the downstream region:
Steady-state flow: The system achieves thermal equilibrium with no temperature fluctuation over time.Heat transport happens solely in the axial direction in one-dimensional heat conduction.Heat transfer occurs primarily within the fluid, and the influence of the tube walls on heat transfer is insignificant.The fluid flows uniformly in the tube with a consistent velocity profile across the cross-section, as assumed by the plug flow assumption.ρc(uA)∂T/∂x + ρc(uA)(T - To)∂u/∂x = kA∂²T/∂x² - hA(T - T∞)
Dividing the above equation by ρcPAu and rearranging, we obtain:
ΔT' = (1 - h/(ρcPu))ΔT + T' - T
b) The boundary conditions are:
At the tube entrance (x = 0), T = To.At the tube exit (x = L), the convective heat transfer condition is given: -kA(dT/dx) = hA(T - T∞).Thus, this can be concluded regarding the given scenario.
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Which of the following does NOT describe a structural feature of a volcano? A. vent. B. vesicle. C. fissure. D. magma chamber.
B. Vesicle does NOT describe a structural feature of a volcano.
A vent, fissure, and magma chamber are all structural features, while a vesicle refers to a small cavity in volcanic rock, formed by trapped gas bubbles during the solidification of lava. A vent is an opening in the Earth's surface that allows volcanic material to escape. A fissure is a large crack in the Earth's surface that allows lava to flow. A magma chamber is a large underground reservoir containing molten rock. A vesicle is an air pocket inside rocks formed by the expansion of gases during volcanic eruptions.
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18. Compare the momentum of a 5450 kg truck moving at 8.00 m/s to the momentum of a 2725 kg car moving at 16.0 m/s.
Answer:
They are equal
Explanation:
Multiply the mass by the velocity.
A student lifts a basketball to a height of 6 feet and lets the ball drop to the ground. Which statement accurately compares the ball's energy at a height of 6 feet (at rest) and at a height of 2 feet (falling)?
A.
The ball's kinetic energy is the same at both heights, but its potential energy is different.
B.
The ball has less potential energy and more kinetic energy at 6 feet than at 2 feet.
C.
The ball's potential energy is the same at both heights, but its kinetic energy is different.
D.
The ball has more potential energy and less kinetic energy at 6 feet than at 2 feet.
Answer:C
Explanation:
If you are holding the ball that would be the ball would have potential energy since it it not moving. Once you drop the ball it will have kinetic energy since it’s moving. If you drop the ball from 6ft it will have more kinetic since it will have more time to accelerate. If you drop the ball from 2ft then it will have less kinetic energy since it is closer to the ground and won’t have beeping time to accelerate and get rid of the potential energy.
Answer:
c
Explanation:
Phys-1A Horizontal Practice 2
Ground-to-Ground Equations
Horizontal Equations
Vicos
Vertical Equations
sin
ay earth).-9.8 m/s
Horizontal Launch Equations
Horizontal Equations
Vertical Equational
Velocity-as-Hits:
wv * , te
Use. Pythagorean Range
and tan (9)
Show work/use units !!
1. For each problem, solve for "?" and "?", and Velocity-as-it-Mits. Circle your final answers with units.
2.26, 226, 24.3 65.7
Vf, V+ay.t
wh25
V4.0
(Pythag. +
7+17,
tan
Velocity-as-Hits -
2. For each problem, solve for "7" and "?", and Velocity-as-it-Hits Circle your final answers with units.
2.02,742, 21.1 69.5
W.77
VF, VI+ ayt
VF,
Mercede
(Pythag.+ v
tan
Velocity-as-Hits -
An electric wall clock has a second hand 15 cm long. What is the radial acceleration of the tip of this hand?
4.25* 10^-4 m/s^2
5.32* 10^-2 m/s^2
1.64* 10^-3 m/s^2
3.16* 10^-3 m/s^2
300kg times 4m/s^(2)
I'm guessing that you need the force, since the question doesn't specify I'll just use the force equation. If this is not what you wanted let me know in the comments section of this answer.
m = 300 kg (kilograms)a = 4 (m/(s^2)) (meters per second square)F = ma- F = 300 x 4
- F = 1200 N (newtons)
1. S1 shows a change as a result of price. Is this a change in supply or change in quantity
supplied? Change in quantity supplied
2. D1 to D2 shows a change. Is this a change in demand or change in quantity demanded?
Change in demand
3. What is the D1 equilibrium price? $2500
4. What is the D2 market clearing price? $4000
5. What is the quantity supplied and demanded at the D1 and D2 equilibrium price?
6. What is the quantity demanded (D1 & D2) and supplied (S1) at $10,000? 13,000
7. What is the quantity supplied and demanded at $1000?
8. What could have caused the shift from D2 to D3 (non-price factors)
Answer: yes
Explanation:
so basically i need points
A cube measures 3cm on each side has a mass of 25 grams. what it its density and relative density.
Answer:
Density= 2.78 g/cm³
Relative density=2.8
Explanation:
To calculate the density of the cube we have to use the formula ρ=mass/volume
ρ stands for density.
So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³
3³= 9 cm³
Now plug in the values. ρ= 25 g/9 cm³
ρ= 2.78 g/cm³
To find the relative density, we have to use the formula ρsample/ρH20
The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.
Now we have to make the units same so you change the unit of the density of cube to kg/m³
So, 25/1000= 0.025 kg
9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)
=0.000009 m³
The new density= 0.025 kg/ 0.000009 m³
= 2777.78 kg/m³
Now plug the values into the formula:
relative density= 2.777.78 kg/m³ / 997 kg/m³
=2.8
There is no unit since kg/m³ and kg/m³ cancels
GIVING EASY BRAINLIEST PLEASE HELP!!
-if you answer correctly ill give you brainliest which will give you 26pts-
Answer:
A
Explanation:
because the first law of thermodynamics is heat brings energy, but don't get confused with C, because bicyle pumps is the thing itself getting warm, though its not providing any energy unlike the stove, which uses it energy to heat something.
hope this helps :)
. A 1.00 kg rock is thrown up into the air from ground level at a speed of 8.00 m/s. The ball travels up
to a maximum height, then returns to the ground. Calculate the rock's momentum as it strikes the
ground.
Answer:
p = -8 kg-m/s
Explanation:
Given that,
Initial speed of the rock, u = 8 m/s
Mass of the rock, m = 1 kg
The ball travels up to a maximum height, then returns to the ground.
We need to find the rock's momentum as it strikes the ground. Let v be the final speed of the rock. Its final speed is as same as initial speed i.e. 8 m/s but in negative direction. So
p = mv
p = 1 kg × (-8 m/s)
= -8 kg-m/s
So, the rock's momentum as it strikes the ground is (-8 kg-m/s).
How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 22.0 cmcm in diameter to produce an electric field of 1340 N/CN/C just outside the surface of the sphere?
Answer:
1.125x10^-10 electrons
Explanation:
Pls see attached file
Suppose you inflate your car tires to 38 psi on a 25 ∘C day.
Later, the temperature drops to 0∘C. What is the pressure in your tires now?
The pressure in your tires would decrease due to the decrease in temperature. The relationship between temperature and pressure is known as the ideal gas law.
which states that pressure and temperature are directly proportional to each other. As the temperature drops, so does the pressure in the tires. The ideal gas law formula is P1/T1 = P2/T2, where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure, and T2 is the final temperature.
Using this formula and assuming that the volume of the tires remains constant, we can calculate the final pressure in the tires. P1 is 38 psi, T1 is 25°C + 273.15 (to convert to Kelvin) = 298.15 K, T2 is 0°C + 273.15 = 273.15 K. Plugging in the values, we get P2 = (38 psi * 273.15 K) / 298.15 K = 34.9 psi. Therefore, the pressure in your tires would be approximately 34.9 psi when the temperature drops to 0°C.
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Which of the following is the process of making a new product to be sold by a business or enterprise to its customers? a.product analysis
b.product conceptualization
c.product development
d.product implementation
Answer: option (c)
Explanation:
Product development is also known as new product operation.
The main ideal is to satisfy the consumer demand.
There are some stages of product development process. They're idea generation, webbing, conception development and testing, request strategy, developing the new product, request testing, request commercialization.
The process of developing a product is managed by product inventor.
Product development can be done in two ways, the new product is introduced or the being products can be bettered according to the client satisfaction.
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the law of conservation of energy cannot be created nor destroyed, it can only change form. if this is the case, why are we worried about energy sources in our world?
Energy cannot be generated or destroyed; it can only be changed from one form of energy to another, according to the rule of conservation of energy. This implies that a system always possesses the same amount of energy, barring external energy addition.
In the event that energy cannot be generated or destroyed, why is there a crisis?According to the rule of conservation of energy, energy cannot be generated or destroyed. It can only be changed from one form to another, though. It is simply changed from a form that we can use to one that is less useful. Energy problem as a result of this
Energy efficiency is necessary to save expenses and extend the life of the resources.
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Write the dimension of a / b in the x = at + bt2. Where x is the distance and t is the time?
The dimension of a/b where x is the distance and t is the time is T
Given the expression
x = at + bt²
where
x is the distance
t is the time
Based on the homogeneity principle, the expression on the left-hand side must be equal to that on the right. Hence;
x = at
\(a = \frac{x}{t}\)
Since x is the distance and distance is measured in metres, the dimension equivalent will be the length 'L'
Since t is the time and time is measured in seconds, the dimension equivalent will be the seconds 'T'
\(a=\frac{L}{T}\)
Similarly;
x = bt²
\(b=\frac{x}{t^2}\\b=\frac{L}{T^2}\)
Next is to get a/b;
\(\frac{a}{b} = \frac{L}{T} \div \frac{L}{T^2}\\\frac{a}{b} = \frac{L}{T}*\frac{T^2}{L} \\\frac{a}{b} =\frac{T^2}{T}\\\frac{a}{b} =T\)
Hence the dimension of a/b is T
10 Waves Question 2 of 10 A wave travels at a speed of 74 m/s. If the distance between crests is 12 m, what is the frequency of the wave? Use j A. 0.16 Hz B. 6.2 Hz C. 890 Hz D. 62 Hz SUBMIT
Answer: B 6.2 Hz
Explanation: Equation for waves v = λf.
Frequency = speed / wavelength f = v/λ
f = 74 m/s / 12 m = 6.166... Hz
Answer:
Rounding is necessary: the answer is 6.2 Hz
Explanation: