roller coaster car drops a maximum vertical distance of 35.4 m . part a determine the maximum speed of the car at the bottom of that drop. ignore work done by friction. express your answer with the appropriate units. activate to select the appropriates template from the following choices. operate up and down arrow for selection and press enter to choose the input value typeactivate to select the appropriates symbol from the following choices. operate up and down arrow for selection and press enter to choose the input value type vf

Answer:

salt w nulas...........

Answer:

The quantities which do not depend on other quantities is called fundamental qiantity. For eg; time,current,lwngth etc...

The melting point of ice is 0°C because at this temperature, the Gibbs free energy of water and ice are equal. This means that the system is at equilibrium and there is no net change in the amount of water or ice.

The Gibbs free energy equation is ΔG = ΔH - TΔS, where ΔG is the change in Gibbs free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.

At the melting point of ice, ΔH is the enthalpy of fusion, which is the amount of energy needed to convert ice to water at a constant temperature. ΔS is the change in entropy, which is the measure of the disorder of the system. As ice melts, the disorder of the system increases, so ΔS is positive.

At 0°C, the Gibbs free energy of water and ice are equal, so ΔG = 0. This means that ΔH - TΔS = 0, or ΔH = TΔS. Since ΔH and ΔS are both positive, this equation is satisfied at 0°C, which is why the melting point of ice is 0°C. Above 0°C, the Gib  water will freeze.

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Out of 150 approved mortgage applications, a random sample may have variable or interest-only mortgages.

we are given that a random sample of 150 approved mortgage applications is either variable or interest-only mortgages. A variable mortgage, also known as an adjustable-rate mortgage (ARM), is a type of mortgage in which the interest rate fluctuates based on market conditions. An interest-only mortgage is a type of mortgage in which the borrower only pays interest on the loan for a certain period of time before beginning to make principal payments.To determine what percentage of the sample is variable or interest-only mortgages, we would need more information on the breakdown of the sample. However, we know that these are two different types of mortgages that borrowers can choose from when applying for a mortgage.

A home loan application is a report submitted to a bank when you apply for a home loan to buy land. The application is extensive and includes information about the borrower's employment history, financial situation, and the property being considered for purchase, among other things.

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Answer:

Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.

In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.

The density of the liquid can be determined from the mass of the sphere, the volume of the sphere, the distance the spring is stretched, and the acceleration due to gravity.

To determine the spring constant of the elastic spring, we need to use Hooke's law, which states that the force F required to extend or compress a spring by a distance x is directly proportional to that distance. Mathematically, this can be expressed as:

F = -kx

where k is the spring constant, x is the distance the spring is stretched or compressed, and the negative sign indicates that the force is in the opposite direction to the displacement.

Since the sphere is suspended from the spring, its weight will stretch the spring downwards by a distance X, until the spring force balances the gravitational force on the sphere. The gravitational force on the sphere is given by:

F_gravity = mg

where m is the mass of the sphere and g is the acceleration due to gravity.

The upward force exerted by the spring on the sphere is given by:

F_spring = -kX

where X is the distance the spring is stretched downwards.

At equilibrium, these two forces balance each other out:

F_gravity = F_spring

mg = -kX

Solving for k, we get:

k = -mg/X

Now, to determine the density of the liquid in which the sphere is submerged, we need to consider the buoyant force acting on the sphere. According to Archimedes' principle, the buoyant force F_buoyant acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. Mathematically, this can be expressed as:

\(F_buoyant\) = pVg

where p is the density of the fluid, V is the volume of the sphere, and g is the acceleration due to gravity.

Since the sphere is completely submerged in the fluid, its weight is equal to the sum of the gravitational force and the buoyant force:

F_total = mg + F_buoyant

At equilibrium, this force is balanced by the upward force exerted by the spring:

F_total = F_spring

mg + pVg = -kX

Solving for p, we get:

p = (-kX - mg)/(Vg)

Substituting the value of k we obtained earlier, we get:

p = (mg/X - mg)/(Vg)

Simplifying this expression, we get:

p = m/(VgX)

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the period of the signal \(\(x(t) = \cos(2t) \cos(5t)\)\) is 10. This means that the signal completes one full cycle every 10 units of time.

The period of a signal refers to the time it takes for the signal to complete one full cycle. In this case, the signal \(x(t) = \(\cos(2t) \cos(5t)\)\) is a product of two cosine functions. To find the period of this signal, we need to determine the smallest time\(\(T\)\)such that\(\(x(t + T) = x(t)\)\)for all values of\(\(t\)\).
To find the period of a product of two cosine functions, we can use the concept of the least common multiple (LCM) of their frequencies. The frequency of the first cosine function is 2, and the frequency of the second cosine function is 5.
To find the LCM of 2 and 5, we list their multiples:
Multiples of 2: 2, 4, 6, 8, 10, ...
Multiples of 5: 5, 10, 15, 20, 25, ...
We can see that the LCM of 2 and 5 is 10, as it is the smallest common multiple of the two frequencies.

Therefore, the period of the signal \(\(x(t) = \cos(2t) \cos(5t)\)\) is 10. This means that the signal repeats itself every 10 units of time.

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Answer:

D

Explanation:

Mgo is ionic and N2 has covalent bonds

Hurricane propagation is the process through which a hurricane moves from one location to another.

Winds from throughout the world direct hurricanes. The environmental wind field, commonly referred to as the dominant winds, is what directs a cyclone along its course. The hurricane moves in the direction of this wind field, which affects the hurricane's speed of movement.

The northeast trade winds move these hurricanes toward the United States.

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Answer:

a 15.6voltz

i Hope this helps

Answer:

The impulse transferred to the nail is 0.01 kg*m/s.

Explanation:

The impulse (J) transferred to the nail can be found using the following equation:

\( J = \Delta p = p_{f} - p_{i} \)

Where:                                                                

\(p_{f}\): is the final momentum

\(p_{i}\): is the initial momentum

The initial momentum is given by:

\( p_{i} = m_{1}v_{1_{i}} + m_{2}v_{2_{i}} \)

Where 1 is for the hammer and 2 is for the nail.

Since the hammer is moving down (in the negative direction):

\(v_{1_{i}} = -10 m/s \)

And because the nail is not moving:

\(v_{2_{i}}= 0\)                      

\( p_{i} = m_{1}v_{1_{i}} = 0.25 kg*(-10 m/s) = -2.5 kg*m/s \)

Now, the final momentum can be found taking into account that the hammer remains in contact with the nail during and after the blow:

\( p_{f} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}} \)

Since the hammer and the nail are moving in the negative direction:

\(v_{1_{f}}\) = \(v_{2_{f}}\) = -9.7 m/s

\( p_{f} = -9.7 m/s(7 \cdot 10^{-3} kg + 0.25 kg) = -2.49 kg*m/s \)

Finally, the impulse is:

\( J = p_{f} - p_{i} = - 2.49 kg*m/s + 2.50 kg*m/s = 0.01 kg*m/s \)

Therefore, the impulse transferred to the nail is 0.01 kg*m/s.

I hope it helps you!                                                                                                                                                                                                                                                                                                                                                                                                                    

The moment of inertia of a spherical shell can be calculated using the formula:
I = (2/3) * M * (r2^5 - r1^5)

Where:
- I is the moment of inertia
- M is the mass of the shell
- r2 is the outer radius of the shell
- r1 is the inner radius of the shell
To derive this formula, we consider the moment of inertia as the sum of infinitesimally small mass elements multiplied by their respective distances squared from the axis of rotation.
By integrating this equation over the entire volume of the spherical shell, we can obtain the main answer. The integral accounts for the varying radii of the shell and the density of mass.
After the integration and simplification steps, the formula mentioned above is derived.
The moment of inertia of a spherical shell with inner radius r1 and outer radius r2 is given by (2/3) * M * (r2^5 - r1^5), where M is the mass of the shell.

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Answer:

1. He feels worse off.

2. His awareness of the grim situation.

Explanation:

Elie Weisel's memoir "Night" is about the persecution of the jews by the Germans during the worst genocide in world history. The events leading up to the Holocaust and the resulting after-effects through his personal experience provides one of the most prominent witness accounts of the crime.

When Weisel states that "lying down wasn't an option", he reveals how congested space was in the cabin. The "lucky ones" were able to breathe in the fresh air from the window, while the rest have to be satisfied with wherever they are. This reveals his realization of the grim situation inside the over-packed cabin, where there is hardly any space to move.

And when he said that they "never ate enough to satisfy our hunger", he presents the realization and understanding of the grim situation in the train's cabin where eating is not a luxury, but a necessity to stay alive. And for that, they know they have to "economize, to save for tomorrow" rather than just stay full once.  

Answer:

1. He feels worse off.

2. His awareness of the grim situation.

Explanation:

Answer:

\(\dfrac{-1}{2}\)

Explanation:

We need to divide the second number by the first number and the numbers are 3/4,-3/8​.

First number = 3/4

Second number = -3/8

Dividing the second number by the first number.

So,

\(\dfrac{\dfrac{-3}{8}}{\dfrac{3}{4}}\)

We know that,

\(\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}\)

So,

\(\dfrac{\dfrac{-3}{8}}{\dfrac{3}{4}}=\dfrac{-3}{8}\times \dfrac{4}{3}\\\\=\dfrac{-1}{2}\)

So, the answer is (-1/2)

Answer:

The net force is positive

Explanation:

This would mean that altogether, the force would cause the object to always be going the same way, and if it is not gaining or losing speed, we can say the force has not changed and that the object has reached terminal velocity. It is not correct to say that the positive is greater than the negative as friction also causes some type of effect and it is neither positive nor negative

When you turn while moving, your speed zeros out before rising.

What is instantaneous speed?

The speed of an object can change as it moves. The speed of an object at a certain instant of time is known as the instantaneous speed. If the position is a function of time, then the speed depends on the change in the position as time changes.

Turning around while moving causes your speed to drop to zero before rising in the opposite direction at the same location.

While you might maintain a steady pace if you made a semicircle turn, you wouldn't be traveling along the same road in the other direction.

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The density of SO₃ gas at 25 °C and 715 Torr is 3.08 g/L.

We want to calculate the density of SO₃ gas at 25 °C and 715 Torr.

Density (ρ) is the ratio of the mass to the volume of a substance.

If we assume ideal behavior, we can calculate the density of SO₃ using the following expression.

ρ = P × M / R × T

where,

To apply this formula, we need to convert 25 °C to Kelvin using the following expression.

K = °C + 273.15 = 25 °C + 273.15 = 298 K

The density of SO₃ is:

ρ = P × M / R × T

ρ = 715 Torr × (80.06 g/mol) / (62.4 mmHg.L/mol.K) × 298 K = 3.08 g/L

The density of SO₃ gas at 25 °C and 715 Torr is 3.08 g/L.

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The maximum height reached is 99.6.

The velocity of the ball at the highest point. When the ball reaches the highest point, its velocity is zero. Therefore, we can use the following formula to find the velocity at the highest point: v = u - gt

where:v is the final velocity (which is zero)u is the initial velocity. g is the acceleration due to gravityt is the time taken to reach the highest pointWe know that the ball takes 2.80 seconds to reach the thrower.

Therefore, it takes half of that time, or 1.40 seconds, to reach the highest point. We also know that the ball was thrown vertically upward, which means that the initial velocity was positive (upward).

Therefore, 0 = u - g(1.40)Solving for u, we get:u = g(1.40) = 9.8(1.40) = 13.72 m/s.

The maximum height: h = ut - ½gt²

where:h is the maximum height. u is the initial velocity (which is 13.72 m/s)t is the time taken to reach the highest point (which is 1.40 seconds)g is the acceleration due to gravity (which is 9.8 m/s²)

h = (13.72)(1.40) - ½(9.8)(1.40)² = 9.60 m.Therefore, the maximum height the ball reaches from the point of release is 9.60 m.

An alternative approach that can also be used is to use the formula:v² = u² + 2ghwhere:v is the final velocity (which is zero)u is the initial velocity. g is the acceleration due to gravityh is the maximum height.

0² = (13.72)² + 2(-9.8)hh = (13.72)²/2(9.8) = 9.60 m.

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(a) The moment of inertia of the wheel is 22.8 kg·m².

(b) The magnitude of the frictional torque is 3.67 N·m.

(c) The total number of revolutions of the wheel during the entire interval of 67.1 s is approximately 4.83 revolutions.

(a) To find the moment of inertia of the wheel, we can use the formula for torque:

Torque = Moment of inertia * Angular acceleration

The total torque is 36.1 N·m and the angular acceleration is the change in angular speed divided by the time, we have:

36.1 N·m = Moment of inertia * (9.8 rad/s - 0 rad/s) / 6.20 s

Simplifying the equation:

Moment of inertia = (36.1 N·m * 6.20 s) / 9.8 rad/s

Moment of inertia = 22.8 kg·m²

Therefore, the moment of inertia of the wheel is 22.8 kg·m².

(b) After the applied force is removed, the wheel comes to rest, indicating that the torque due to friction is acting in the opposite direction to oppose the wheel's motion. We need to find the magnitude of this frictional torque.

The frictional torque can be found using the equation:

Torque = Moment of inertia * Angular acceleration

Since the wheel comes to rest, its final angular speed is 0 rad/s, and the time taken for it to come to rest is 60.9 s. Therefore, the angular acceleration can be calculated as:

Angular acceleration = (0 rad/s - 9.8 rad/s) / 60.9 s

Plugging in the values:

Angular acceleration = -0.161 rad/s²

Now we can find the frictional torque:

Torque = 22.8 kg·m² * (-0.161 rad/s²)

The magnitude of the frictional torque is 3.67 N·m.

(c) The total number of revolutions can be calculated by finding the total angle rotated by the wheel in radians and converting it to revolutions.

During the first 6.20 s, the wheel rotates from 0 rad/s to 9.8 rad/s. The total angle rotated can be found using the equation:

θ = 0.5 * (initial angular speed + final angular speed) * time

θ = 0.5 * (0 rad/s + 9.8 rad/s) * 6.20 s

θ = 30.38 rad

During the next 60.9 s, the wheel comes to rest, so the total angle rotated is 0 rad.

Therefore, the total angle rotated by the wheel in 67.1 s is 30.38 rad.

To convert this to revolutions, we divide by 2π radians, since there are 2π radians in one revolution:

Number of revolutions = 30.38 rad / (2π rad/rev)

Number of revolutions ≈ 4.83 revolutions

Therefore, the total number of revolutions of the wheel during the entire interval of 67.1 s is approximately 4.83 revolutions.

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Answer:

The answer is . A 46.2g

Answer:

Total Voltage V=36*2Ω = 72Ω

We can use the formula V=IR

V=voltage

I=current

R=resistance

V=IR

I= 52/72

I=13/18

The pressure drop along the section is 5.344Pa.

This refers to the difference in total pressure between two points of any fluid-carrying network. A pressure drop happens due to frictional forces, caused by the resistance to flow, acting on a fluid as it flows through the tube.

Formular for calculating Pressure drop ΔP:

ΔP = 0.0668 μv ÷ D²

Where,

ΔP = Pressure drop (pressure loss )

S = Distance along the pipe

μ = viscosity

v = flow velocity

D =  Inside Diameter of the pipe

Form the question:

T = 200 °C

μ = viscosity

v = velocity

r =1.0cm

S = 4m

D = 2r

D = 2 * 1.0cm

D = 2cm

converting cm to m:

100cm =1m

2cm   = xm

cross multiplying and making xm subject of the formular:

100 cm * xm = 1m * 2cm

xm = 1m * 2cm

         100 cm

xm = 0.002m

ΔP = 0.0668 *1.6x10⁻³NSM⁻² * 0.2m/s

                         (0.002m)²

ΔP = 5.344Pa

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The answer is 118 J :)

Explanation:

38 +80 = 118.

The speedboat momentum is 19,500 kg.m/s.

We need to know about momentum to solve this problem. Momentum can be defined as the degree of difficulty to stop a moving object. It can be determined by

P = m . v

where P is momentum (kgm/s), m is mass (kg) and v is velocity (m/s).

From the question above, we know that:

m = 1500 kg

v = 13 m / s

By substituting the given parameters, we can calculate the momentum

P = m . v

P = 1500 . 13

P = 19,500 kg . m / s

Hence, the speedboat momentum is 19,500 kg.m/s.

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Answer:19,500 kg

Explanation:your welcome!:)

The magnitude of the magnetic field surrounding the rod is \(3.92*10^{-6} T\).

To find the magnitude of the magnetic field surrounding the rod, we need to substitute the numerical values into the given equation. Here, we are given that b = kmg iℓ = kg 9.80 m/s2 a m = t. We can substitute the values of k (which is the magnetic constant), m (mass of the rod), g (acceleration due to gravity), i (current in the rod), and ℓ (length of the rod) to get the value of the magnetic field. We are also given the value of a (acceleration of the rod) and t (time), but these values are not required to find the magnetic field.
So, the magnitude of the magnetic field surrounding the rod can be calculated as:
b = kmg iℓ
Substituting the values, we get:
b = \((4\pi *10^{-7} Tm/A) (0.1 kg) (9.80 m/s^2) (2 A) (0.2 m)\)
b = \(3.92*10^{-6} T\)

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Answer:

c.15mls

Explanation:

speed is the total distance cover by body .i

speed:total c covered distance(d)/time taken(t)

The distance the springs need to bring the car to a stop can be calculated using the equation for the potential energy of an object at a height, which is:

PE = mgh

where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), and h is the height.

In this case, the car has a mass of 1,836 kg and is at a height of 88.6 meters. So the potential energy of the car at the top of the roller coaster is:

PE = 1,836 kg * 9.8 m/s^2 * 88.6 m = 1.5*10^5 J

Next, we need to find the work done by the spring. Work can be calculated using the equation

W = 1/2 * kx^2

where k is the spring constant (100,000 N/m) and x is the compression distance of the spring.

Since the work done by the spring is equal to the potential energy of the car, we can set the two equations equal to each other and solve for x (the compression distance of the spring):

1/2 * kx^2 = 1.510^5 J

x = sqrt(2 * 1.510^5 J / 100,000 N/m)

x = sqrt(30000/100000)

x = 0.173 m

Therefore, the spring needs a distance of 0.173 m to bring the car to a stop.