round 314,759 to the number of the underlined digit

The vectors v = 6i - 3j and w = i + 2j are orthogonal.

To determine if the vectors v and w are orthogonal, we need to find their dot product. If the dot product is 0, the vectors are orthogonal.

Here are the steps to find the dot product of v = 6i - 3j and w = i + 2j,

1. Identify the components of the vectors: v = (6, -3) and w = (1, 2)

2. Multiply the corresponding components of the vectors:

\((6 \times 1) + (-3 \times 2) = 6 - 6 \)

3. Add the products: 6 - 6 = 0 Since the dot product is 0, the vectors v = 6i - 3j and w = i + 2j are orthogonal.

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Correct question is " Are these vectors orthogonal? v = 6i - 3j and w = i+2j"

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Answer:

1. Substitute 9 for y..............................3 x y

2.  Substitute 3 for X .......................................3x 9

3.   multiply ................................... 27                                        

Step-by-step explanation:

Answer:

195 students are left-handed

Step-by-step explanation:

Here, we want to calculate the total number of students who are left-handed

Let the total number of students in the school be x

The total ratio is 8 + 3 = 11

8/11 * x = 520

8x = 11 * 520

x = (11 * 520)/8

x = 715 students

So the number of students who are left handed will be;

Total - number of right-handed students

That would be;

715-520 = 195

The properties of an open set:

The properties of a closed set:

An open set is a set in which every point is surrounded by a neighborhood that lies entirely within the set. Therefore, an open set cannot have any boundary points. This is why the empty set and the whole space are considered open sets. Additionally, any union of open sets must also be open because any point within the union must be in at least one of the open sets, and hence not on the boundary.

On the other hand, a closed set is a set that includes all its boundary points, which means it can contain its limit points as well. This is why the empty set and the whole space are considered closed sets. Moreover, the intersection of any collection of closed sets must also be closed because any point within the intersection must be in every closed set, and hence on the boundary of each set.

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Answer:

A 6.930

Step-by-step explanation:

The expression at the upper and lower limits and the difference is

∫[0,1]√(4-3\(x^2\)) dx \(=(2 - (3/2)(1)^2) - (2 - (3/2)(0)^2) = (2 - 3/2) - (2 - 0) = (4/2 - 3/2) = 1/2.\)

To evaluate the integral ∫√(4-3\(x^2\)) dx, where the interval of integration is 0≤x≤1, we can use various techniques such as substitution or integration by parts. Let's proceed with the method of substitution to simplify the integral and find its value.

First, let's identify a suitable substitution for the integral. Since the expression inside the square root contains a quadratic term, it is beneficial to let u be equal to the square root of the quadratic expression. Therefore, we set u = √(4-3\(x^2\)).

Next, we need to find the differential of u with respect to x. Taking the derivative of both sides with respect to x, we have du/dx = (-6x)/(2√(4-3\(x^2\))) = -3x/√(4-3\(x^2\)).

Now, we can rewrite the integral in terms of the new variable u. Substituting u = √(4-3\(x^2\)) and du = (-3x/√(4-3\(x^2\))) dx into the integral, we have:

∫√(4-3\(x^2\)) dx = ∫u du

Our new integral is now much simpler, as it reduces to the integral of u with respect to u. Integrating u, we get:

∫u du = (1/2)\(u^2\) + C,

where C is the constant of integration.

Now, we can substitute back for u in terms of x. Recall that we set u = √(4-3x^2). Therefore, the final result becomes:

∫√(4-3x^2) dx = (1/2)(√\((4-3x^2))^2 + C = (1/2)(4-3x^2) + C = 2 - (3/2)x^2 + C.\)

To find the definite integral over the interval [0, 1], we need to evaluate the expression at the upper and lower limits and find the difference:

∫[0,1]√(4-3\(x^2\)) dx\(= (2 - (3/2)(1)^2) - (2 - (3/2)(0)^2) = (2 - 3/2) - (2 - 0) = (4/2 - 3/2) = 1/2.\)

Therefore, the value of the definite integral ∫√(4-3\(x^2\)) dx over the interval [0, 1] is 1/2.

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we have the next information

48 ft in 24 hours

x ft in 15 hours

x is the height of the drill after 15 hours

x can be calculated if we multiply 15 by 48 and then we divide the result between 24

the height that was drill after 15 hours was 30 ft

(i) Assumptions of classical linear regression: linearity, independence, homoscedasticity, no perfect multicollinearity, zero conditional mean, and normality. Violation: perfect multicollinearity between X2, X3, and X4.

(ii) Omitted variable bias occurs when X4 is omitted from the model, leading to a biased estimate of β2 compared to α2 if X2 and X4 are correlated.

In the given model, the assumption of no perfect multicollinearity is violated when the regressors X2, X3, and X4 are defined as the log of per capita GDP, the log of the square of per capita GDP, and the proportion of population with graduation, respectively. X3 is a function of X2, and X4 may be correlated with both X2 and X3. This violates the assumption that the independent variables are not perfectly correlated with each other.

Omitted variable bias in β2 compared to α2 occurs when X4 is omitted from the model. This bias arises because X4 is a relevant explanatory variable that affects the dependent variable (Y), and its omission leads to an incomplete model. The bias in β2 arises from the correlation between X2 and X4. If X2 and X4 are not correlated, β2 will equal α2, and there will be no omitted variable bias. However, if X2 and X4 are correlated, omitting X4 from the model will result in a biased estimate of β2 because the omitted variable (X4) affects both Y and X2, leading to a bias in the estimation of the relationship between Y and X2.

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The value of b that satisfies the equation is 7/2. To solve the given equation without using LaTeX, let's rewrite it in a different form.

We have the equation:

b/7 + b^2/7^2 + b^3/7^3 + ... = 7.

Notice that the left-hand side is an infinite geometric series with the first term (a) equal to b/7 and the common ratio (r) equal to b/7.

The sum (S) of an infinite geometric series is given by the formula:

S = a / (1 - r),

where |r| < 1.

Applying this formula to our equation, we get:

7 = (b/7) / (1 - b/7).

To simplify, let's multiply both sides of the equation by (1 - b/7) to get rid of the denominator:

7(1 - b/7) = b.

Expanding the left side, we have:

7 - b = b.

Moving the b term to the left side:

7 = 2b.

Finally, divide both sides by 2:

b = 7/2.

Therefore, the value of b that satisfies the equation is 7/2.

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Answer:

-25

Step-by-step explanation:

-30+5 = -25

cube roots of -1 lies in the region given in the best options are  A. on real axis, B. quadrant 1, F. quadrant 4.

Cube roots of -1 mean "finding solution of the equation z³ = -1 since the equation is of order 3, the equation has 3 roots in complex field."

According to the question,

Cube roots of -1 can written as \((-1)^\frac{1}{3}\)

First, write the given number in polar form

\(x = ( cos 0 - i sin 0)^\frac{1}{3}\)

Add 2kπ to the argument

\(x = (cos2k\pi - i sin 2k\pi )^\frac{1}{3}\)

Apply De Moivre's  theorem

\((cos\alpha - i sin\alpha) = cosn\alpha + i sin\alpha\)

x = \(\frac{2k\pi }{3} - i sin\frac{2k\pi }{3}\)

Put k = 0,1,2..., (n-1)                   [sin (-θ) = -sin θ, cos(-θ) = cos θ]

The three roots are

cos 0 -  sin 0, cos \(\frac{2\pi }{3}\), \(i sin\frac{2\pi }{3}\) , cos \(\frac{4\pi }{3}\),  \(i\)sin\(\frac{4\pi }{3}\)

-1, \(-\frac{1}{2} ,- i \frac{\sqrt{3} }{2}, -\frac{1}{2} , +\frac{\sqrt{3} }{2}\) ,  are the three roots of cube roots of -1

It can be seen that the three roots lies in the regions of real axis, quadrant 1 and quadrant 4.

Hence, cube roots of -1 lies in the region given in the best options are  A. on real axis, B. quadrant 1, F. quadrant 4.

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Answer:

y = \(\frac{36}{25}\)

Step-by-step explanation:

y ∝ \(\frac{1}{x^2}\)

=> y = \(\frac{k}{x^2}\) --------------(1)

Now, y = 4 and x = 3.

Putting in (1)

=> 4 = \(\frac{k}{9}\)

=> k = 4*9

=> k = 36

Now, y = ?, when x = 5

Putting in (1)

=> y = \(\frac{36}{5^2}\)

=> y = \(\frac{36}{25}\)

Answer:

y = x - 1 (third answer choice)

Step-by-step explanation:

From the given we see immediately that the slope of this line is -1.  The slope of a line perpendicular to this one is +1, which is the negative reciprocal of -1.  The slope-intercept form is y = mx + b.  To find b, the y-intercept, we make the following substitutions:  m = -1, y = -2, x = -2:

-2 = +1(-2) + b, or +1 = 2 + b, or b = -1

and so the desired equation is y = x - 1 (third answer choice)

The perimeter of the rectangle is approximately √29 + √37 + √29 + √41.

To find the perimeter of a rectangle, we need to calculate the lengths of all four sides and then sum them up.

Given the coordinates of the rectangle's vertices as (-3, 4), (2, 2), (-4, 1), and (1, -1), we can determine the lengths of the sides.

Side AB:

Using the distance formula, we calculate the distance between points A(-3, 4) and B(2, 2):

AB = √((2 - (-3))^2 + (2 - 4)^2) = √(5^2 + (-2)^2) = √(25 + 4) = √29

Side BC:

Using the distance formula, we calculate the distance between points B(2, 2) and C(-4, 1):

BC = √((-4 - 2)^2 + (1 - 2)^2) = √((-6)^2 + (-1)^2) = √(36 + 1) = √37

Side CD:

Using the distance formula, we calculate the distance between points C(-4, 1) and D(1, -1):

CD = √((1 - (-4))^2 + (-1 - 1)^2) = √(5^2 + (-2)^2) = √(25 + 4) = √29

Side DA:

Using the distance formula, we calculate the distance between points D(1, -1) and A(-3, 4):

DA = √((-3 - 1)^2 + (4 - (-1))^2) = √((-4)^2 + 5^2) = √(16 + 25) = √41

Now, we can sum up the lengths of all four sides to find the perimeter:

Perimeter = AB + BC + CD + DA

Perimeter = √29 + √37 + √29 + √41

So, the perimeter of the rectangle is approximately √29 + √37 + √29 + √41.

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Answer:

2/5

Step-by-step explanation:

Total water birds=10

ducks=6

geese=4

fraction of geese=4/10

=2/5

Answer:

The slope will be m=-3

Step-by-step explanation:

Answer:

The standard form of a circle's equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius.

Step-by-step explanation:

The missing side of the right triangle is as follows:

a = 22.7 units

b = 10.6 units

A right angle triangle is a triangle that has one of its angles as 90 degrees. The sum of angles in a triangle is 180 degrees.

The sides a and b can be found using trigonometric ratios as follows:

Hence,

sin 25 = opposite / hypotenuse

sin 25° = b / 25

cross multiply

b = 25 sin 25

b = 25 × 0.42261826174

b = 10.5654565435

b = 10.6 units

cos 25 = adjacent / hypotenuse

cos 25 = a / 25

cross multiply

a = 25 cos 25

a = 22.6576946759

a = 22.7 units

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Answer:

D

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

a trinomial is a math equation that has three terms which are connected by plus or minus notations. An example of trinomial is 6x squared + 3x + 5.

Answer:

104.5 is the volume

Step-by-step explanation:

you do length x width x height but but sense theres no length you do

(1.5+9.5) x (9.5)

*simplify*

11 x 9.5 = 104.5

Answer:

ima tae simp to :)

Step-by-step explanation:

Answer:

The graph is a Box graph

The push operation is called 9 times to evaluate the given postfix expression. The correct option is C) 9.

Postfix expression refers to an expression in which the operator follows the operands. It is also known as the Reverse Polish Notation (RPN). A stack data structure is used to evaluate postfix expressions.

The given postfix expression is 6 4 + 3 10 * + 2 2 - +.

To evaluate the expression, the stack data structure is used:

Step 1: Push 6 into the stack.

Step 2: Push 4 into the stack.

Step 3: Pop 4 and 6 from the stack and add them. Then push the sum (10) into the stack.

Step 4: Push 3 into the stack.

Step 5: Push 10 into the stack.

Step 6: Pop 10 and 3 from the stack and multiply them. Then push the product (30) into the stack.

Step 7: Pop 30 and 10 from the stack and add them. Then push the sum (40) into the stack.

Step 8: Push 2 into the stack.

Step 9: Push 2 into the stack.

Step 10: Pop 2 and 2 from the stack and subtract them. Then push the difference (0) into the stack.

Step 11: Pop 0 and 40 from the stack and add them. Then push the sum (40) into the stack.

Therefore, the push operation is called 9 times to evaluate the given postfix expression. The correct option is C) 9.

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There exists a sequence of points zn in the unit disk with |zn| → 1 such that f(z) is bounded.

Let's assume the contrary, that f(z) is unbounded in the unit disk. Then, for each positive integer n, there exists a point zn in the unit disk such that |f(zn)| > n. Consider the sequence zn in the unit disk. Since the unit disk is bounded, this sequence must have a limit point z ∈ ¯D (closure of the unit disk).By the maximum modulus principle, f(z) cannot attain its maximum within ¯D unless f is a constant function. But f is holomorphic, so it must have a maximum on the boundary of the unit disk, i.e., |f(zn)| ≤ M for some positive constant M and all n. This contradicts our initial assumption that |f(zn)| > n for all n. Therefore, the assumption that f(z) is unbounded must be false.

Hence, there exists a sequence of points zn in the unit disk with |zn| → 1 such that f(z) is bounded.

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Answer:She will need to work for 22 hours in other other job.

Step-by-step explanation:

12x16=192

357-192=165

165/7.50=22 hours

The values of `eax` and `edx` after the division takes place will depend on the specific architecture and the values of `eax` and `edx` before the division.

1. In the given code snippet, `eax` is set to 0x00007530 and `ecx` is set to 0x00002710. Since the `div` instruction performs unsigned division, it divides the double-word value formed by concatenating `edx` and `eax` by the value in the `ecx` register.

After the division, the quotient will be stored in `eax`, and the remainder will be stored in `edx`. However, note that dividing by zero will cause an exception, so the result will depend on whether `ecx` is zero or not.

2. The roles of `eax` and `edx` concerning the result of the `div` instruction are as follows:

  - `eax`: It holds the high-order 32 bits of the dividend. After the division, it will contain the quotient.

  - `edx`: It holds the low-order 32 bits of the dividend. After the division, it will contain the remainder.

3. In the given code, the `test edx, edx` instruction checks whether `edx` is zero or not. If `edx` is zero (the zero flag is set), the `jz` instruction will jump to the address `loc_00401044`.

If the `test` instruction was replaced with `test eax, eax`, it would check whether `eax` is zero or not. The jump will be taken (to `loc_00401044`) only if `eax` is zero, i.e., the zero flag is set.

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Answer:

I needed thisssss ! Thanks for the points and you too<3

Step-by-step explanation:

Answer:

Yes! You get it, fellow human!

Step-by-step explanation:

Thank you so much! You made my day :))))) <3<3<3